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• tmux: Suddenly, cannot horizontally split

  - by A__A__0

  As root, using a reasonably default .profile and .shrc and an empty tmux.conf, I am unable to split the window horizontally. There are a number of cases to consider so I'll list them clearly. Using the keybinding + empty configuration: nothing happens Using the keybinding + my configuration: a bell is generated, nothing else; occasionally, the split will appear and disappear immediately (maybe it always does this, but I'm connecting over ssh so it may not make it through) Using tmux split-window -h with any config: tmux immediately exits I've posted here in order the server and client verbose logs generated by tmux -v during the third case: server started, pid 9523 socket path /tmp/tmux-0/default new client 7 got 100 from client 7 got 101 from client 7 got 102 from client 7 got 103 from client 7 got 104 from client 7 got 105 from client 7 got 105 from client 7 got 105 from client 7 got 105 from client 7 got 105 from client 7 got 105 from client 7 got 105 from client 7 got 105 from client 7 got 105 from client 7 got 105 from client 7 got 105 from client 7 got 105 from client 7 got 105 from client 7 got 105 from client 7 got 105 from client 7 got 105 from client 7 got 106 from client 7 got 200 from client 7 cmdq 0x801c6e080: new-session (client 7) new term: xterm xterm override: XT xterm override: Ms ]52;%p1%s;%p2%s xterm override: Cs ]12;%p1%s xterm override: Cr ]112 xterm override: Ss [%p1%d q xterm override: Se [2 q new key Oo: 0x1021 (KP/) new key Oj: 0x1022 (KP*) new key Om: 0x1023 (KP-) new key Ow: 0x1024 (KP7) new key Ox: 0x1025 (KP8) new key Oy: 0x1026 (KP9) new key Ok: 0x1027 (KP+) new key Ot: 0x1028 (KP4) new key Ou: 0x1029 (KP5) new key Ov: 0x102a (KP6) new key Oq: 0x102b (KP1) new key Or: 0x102c (KP2) new key Os: 0x102d (KP3) new key OM: 0x102e (KPEnter) new key Op: 0x102f (KP0) new key On: 0x1030 (KP.) new key OA: 0x101d (Up) new key OB: 0x101e (Down) new key OC: 0x1020 (Right) new key OD: 0x101f (Left) new key [A: 0x101d (Up) new key [B: 0x101e (Down) new key [C: 0x1020 (Right) new key [D: 0x101f (Left) new key OH: 0x1018 (Home) new key OF: 0x1019 (End) new key [H: 0x1018 (Home) new key [F: 0x1019 (End) new key Oa: 0x501d (C-Up) new key Ob: 0x501e (C-Down) new key Oc: 0x5020 (C-Right) new key Od: 0x501f (C-Left) new key [a: 0x901d (S-Up) new key [b: 0x901e (S-Down) new key [c: 0x9020 (S-Right) new key [d: 0x901f (S-Left) new key [11^: 0x5002 (C-F1) new key [12^: 0x5003 (C-F2) new key [13^: 0x5004 (C-F3) new key [14^: 0x5005 (C-F4) new key [15^: 0x5006 (C-F5) new key [17^: 0x5007 (C-F6) new key [18^: 0x5008 (C-F7) new key [19^: 0x5009 (C-F8) new key [20^: 0x500a (C-F9) new key [21^: 0x500b (C-F10) new key [23^: 0x500c (C-F11) new key [24^: 0x500d (C-F12) new key [25^: 0x500e (C-F13) new key [26^: 0x500f (C-F14) new key [28^: 0x5010 (C-F15) new key [29^: 0x5011 (C-F16) new key [31^: 0x5012 (C-F17) new key [32^: 0x5013 (C-F18) new key [33^: 0x5014 (C-F19) new key [34^: 0x5015 (C-F20) new key [2^: 0x5016 (C-IC) new key [3^: 0x5017 (C-DC) new key [7^: 0x5018 (C-Home) new key [8^: 0x5019 (C-End) new key [6^: 0x501a (C-NPage) new key [5^: 0x501b (C-PPage) new key [11$: 0x9002 (S-F1) new key [12$: 0x9003 (S-F2) new key [13$: 0x9004 (S-F3) new key [14$: 0x9005 (S-F4) new key [15$: 0x9006 (S-F5) new key [17$: 0x9007 (S-F6) new key [18$: 0x9008 (S-F7) new key [19$: 0x9009 (S-F8) new key [20$: 0x900a (S-F9) new key [21$: 0x900b (S-F10) new key [23$: 0x900c (S-F11) new key [24$: 0x900d (S-F12) new key [25$: 0x900e (S-F13) new key [26$: 0x900f (S-F14) new key [28$: 0x9010 (S-F15) new key [29$: 0x9011 (S-F16) new key [31$: 0x9012 (S-F17) new key [32$: 0x9013 (S-F18) new key [33$: 0x9014 (S-F19) new key [34$: 0x9015 (S-F20) new key [2$: 0x9016 (S-IC) new key [3$: 0x9017 (S-DC) new key [7$: 0x9018 (S-Home) new key [8$: 0x9019 (S-End) new key [6$: 0x901a (S-NPage) new key [5$: 0x901b (S-PPage) new key [11@: 0xd002 (C-S-F1) new key [12@: 0xd003 (C-S-F2) new key [13@: 0xd004 (C-S-F3) new key [14@: 0xd005 (C-S-F4) new key [15@: 0xd006 (C-S-F5) new key [17@: 0xd007 (C-S-F6) new key [18@: 0xd008 (C-S-F7) new key [19@: 0xd009 (C-S-F8) new key [20@: 0xd00a (C-S-F9) new key [21@: 0xd00b (C-S-F10) new key [23@: 0xd00c (C-S-F11) new key [24@: 0xd00d (C-S-F12) new key [25@: 0xd00e (C-S-F13) new key [26@: 0xd00f (C-S-F14) new key [28@: 0xd010 (C-S-F15) new key [29@: 0xd011 (C-S-F16) new key [31@: 0xd012 (C-S-F17) new key [32@: 0xd013 (C-S-F18) new key [33@: 0xd014 (C-S-F19) new key [34@: 0xd015 (C-S-F20) new key [2@: 0xd016 (C-S-IC) new key [3@: 0xd017 (C-S-DC) new key [7@: 0xd018 (C-S-Home) new key [8@: 0xd019 (C-S-End) new key [6@: 0xd01a (C-S-NPage) new key [5@: 0xd01b (C-S-PPage) new key [I: 0x1031 ((null)) new key [O: 0x1032 ((null)) new key OP: 0x1002 (F1) new key OQ: 0x1003 (F2) new key OR: 0x1004 (F3) new key OS: 0x1005 (F4) new key [15~: 0x1006 (F5) new key [17~: 0x1007 (F6) new key [18~: 0x1008 (F7) new key [19~: 0x1009 (F8) new key [20~: 0x100a (F9) new key [21~: 0x100b (F10) new key [23~: 0x100c (F11) new key [24~: 0x100d (F12) new key [2~: 0x1016 (IC) new key [3~: 0x1017 (DC) replacing key OH: 0x1018 (Home) replacing key OF: 0x1019 (End) new key [6~: 0x101a (NPage) new key [5~: 0x101b (PPage) new key [Z: 0x101c (BTab) replacing key OA: 0x101d (Up) replacing key OB: 0x101e (Down) replacing key OD: 0x101f (Left) replacing key OC: 0x1020 (Right) spawn: /bin/sh -- session 0 created writing 207 to client 7 got 208 from client 7 input_parse: '#' ground input_parse: ' ' ground keys are 7 ([?1;2c) received service class 1 complete key [?1;2c 0xfff keys are 1 (t) complete key t 0x74 input_parse: 't' ground keys are 1 (m) complete key m 0x6d input_parse: 'm' ground keys are 1 (u) complete key u 0x75 input_parse: 'u' ground keys are 1 (x) complete key x 0x78 input_parse: 'x' ground keys are 1 ( ) complete key 0x20 input_parse: ' ' ground keys are 1 (s) complete key s 0x73 input_parse: 's' ground keys are 1 (p) complete key p 0x70 input_parse: 'p' ground keys are 1 (l) complete key l 0x6c input_parse: 'l' ground keys are 1 (i) complete key i 0x69 input_parse: 'i' ground keys are 1 (t) complete key t 0x74 input_parse: 't' ground keys are 1 (-) complete key - 0x2d input_parse: '-' ground keys are 1 (d) complete key d 0x64 input_parse: 'd' ground keys are 1 () complete key 0x7f input_parse: '' ground input_c0_dispatch: ' input_parse: '' ground input_parse: '[' esc_enter input_parse: 'K' csi_enter input_csi_dispatch: 'K' "" "" keys are 1 (w) complete key w 0x77 input_parse: 'w' ground keys are 1 (i) complete key i 0x69 input_parse: 'i' ground keys are 1 (n) complete key n 0x6e input_parse: 'n' ground keys are 1 (d) complete key d 0x64 input_parse: 'd' ground keys are 1 (o) complete key o 0x6f input_parse: 'o' ground keys are 1 (w) complete key w 0x77 input_parse: 'w' ground keys are 1 ( ) complete key 0x20 input_parse: ' ' ground keys are 1 (-) complete key - 0x2d input_parse: '-' ground keys are 1 (h) complete key h 0x68 input_parse: 'h' ground keys are 1 ( ) complete key 0xd input_parse: ' ' ground input_c0_dispatch: ' input_parse: ' ' ground input_c0_dispatch: ' new client 13 got 100 from client 13 got 101 from client 13 got 102 from client 13 got 103 from client 13 got 104 from client 13 got 105 from client 13 got 105 from client 13 got 105 from client 13 got 105 from client 13 got 105 from client 13 got 105 from client 13 got 105 from client 13 got 105 from client 13 got 105 from client 13 got 105 from client 13 got 105 from client 13 got 105 from client 13 got 105 from client 13 got 105 from client 13 got 105 from client 13 got 105 from client 13 got 105 from client 13 got 105 from client 13 got 106 from client 13 got 200 from client 13 cmdq 0x801c6e160: split-window -h (client 13) spawn: /bin/sh -- writing 203 to client 13 input_parse: '#' ground input_parse: ' ' ground input_parse: '#' ground input_parse: ' ' ground lost client 13 session 0 destroyed writing 203 to client 7 got 205 from client 7 writing 204 to client 7 lost client 7 got 207 from server got 203 from server got 204 from server There are some other peculiarities: With a newly created user (from which I overwrote root's .profile and .shrc, tmux works perfectly. Occasionally (twice out of the 50 or so times I've tested it), the splitting will work fine once in a session. (This happened for example when I ran ktrace on tmux, which I can also post) To explain the 'suddenly' part of the title: when I started my newly updated mysql56-server, tmux immediately exited and lost the session. Recently I changed architectures, from FreeBSD 10.0 i386 to amd64, and I am still working through shared library incompatibilities. I suspect that this could be involved, but I can't imagine how an incompatibility of this sort could result in such a specific, isolated failure.

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• Force a Windows 7 user to change password when it has expired

  - by Joshua King

  Is it possible to force users (on Windows 7 PCs) to change their password once it has expired? Currently our users get notifications that their passwords will expire in 7, 3, 2 and 1 days but once the password has expired they are still able to log into their machines with the expired password. Most of our users ignore the warnings and don't change their password until we tell them they have to (when they ring Help Desk asking why their email and intranet isn't working). From memory, Windows XP machines would show a message at login that the password had expired and then offer the change password screen. Is it possible to do the same thing under Win7? Similar to how if you set a user's account to "must change password at next login" it gives the change password screen automatically.

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• Added key, but still getting "gpg: Can't check signature: public key not found"

  - by gertvdijk

  Trying to download Django source package using dget and the .dsc file from here. Then dget fails to verify the source, because it is missing a public key. $ dget https://launchpad.net/ubuntu... [...] dscverify: python-django_1.4.1-2.dsc failed signature check: gpg: Signature made Tue 21 Aug 2012 09:12:04 CEST using RSA key ID F2AC729A gpg: Can't check signature: public key not found Validation FAILED!! Fine, I added this key to my keyring, because I think I can trust this one: $ gpg --keyserver keyserver.ubuntu.com --recv-key 0xF2AC729A gpg: requesting key F2AC729A from hkp server keyserver.ubuntu.com gpg: key F2AC729A: "Raphaël Hertzog <[email protected]>" not changed gpg: Total number processed: 1 gpg: unchanged: 1 (well, this output is run afterwards, when it was already in my keyring) And it is really there: $ gpg --fingerprint F2AC729A pub 4096R/F2AC729A 2009-05-07 Key fingerprint = 3E4F B711 7877 F589 DBCF 06D6 E619 045D F2AC 729A uid Raphaël Hertzog <[email protected]> uid Raphaël Hertzog (Debian) <[email protected]> uid Raphaël Hertzog (Freexian SARL) <[email protected]> sub 2048R/71F23DEE 2009-05-07 But still fails for the same reason: gpg: Signature made Tue 21 Aug 2012 09:12:04 CEST using RSA key ID F2AC729A gpg: Can't check signature: public key not found I'm running all these commands as my regular user. I also tried adding this key to APT's keyring and root's keyring. Both to no avail. What am I missing here?

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• Cannot log into Oracle Enterprise Manager 11g: ORA-28001

  - by Álvaro G. Vicario

  I can no longer log into Oracle Enterprise Manager 11g. I get this error message: ORA-28001: the password has expired (DBD ERROR: OCISessionBegin) I could log into the server using SQL*Plus. I warned me that the password was going to expire in 7 days (which is not the same as being already expired). Following advice from several documents, I ran these commands from SQL*Plus: ALTER USER sys IDENTIFIED BY new_password; ALTER USER system IDENTIFIED BY new_password; SQL*Plus no longer warns about passwords, but I still cannot use the Enterprise Manager. Then I followed this to remove password expiration: ALTER PROFILE default LIMIT password_life_time UNLIMITED And I've also restarted the Oracle services. In case it was using cached credentials, I've tried to connect from several browsers in several computers. No way: I still get ORA-28001 in Enterprise Manager. What am I missing? Update: Some more info SQL> select username,ACCOUNT_STATUS,EXPIRY_DATE from dba_users; USERNAME ACCOUNT_STATUS EXPIRY_D ------------------------------ -------------------------------- -------- MGMT_VIEW OPEN SYS OPEN SYSTEM OPEN [...] DBSNMP EXPIRED 24/05/10 SYSMAN EXPIRED 24/05/10 OUTLN EXPIRED & LOCKED 16/11/09 FLOWS_FILES EXPIRED & LOCKED 16/11/09 USERNAME ACCOUNT_STATUS EXPIRY_D ------------------------------ -------------------------------- -------- MDSYS EXPIRED & LOCKED 16/11/09 ORDSYS EXPIRED & LOCKED 16/11/09 EXFSYS EXPIRED & LOCKED 16/11/09 WMSYS EXPIRED & LOCKED 16/11/09 WKSYS EXPIRED & LOCKED 16/11/09 WK_TEST EXPIRED & LOCKED 16/11/09 CTXSYS EXPIRED & LOCKED 16/11/09 ANONYMOUS EXPIRED & LOCKED 16/11/09 XDB EXPIRED & LOCKED 16/11/09 WKPROXY EXPIRED & LOCKED 16/11/09 ORDPLUGINS EXPIRED & LOCKED 16/11/09 USERNAME ACCOUNT_STATUS EXPIRY_D ------------------------------ -------------------------------- -------- FLOWS_030000 EXPIRED & LOCKED 16/11/09 OWBSYS EXPIRED & LOCKED 16/11/09 SI_INFORMTN_SCHEMA EXPIRED & LOCKED 16/11/09 OLAPSYS EXPIRED & LOCKED 16/11/09 SCOTT EXPIRED & LOCKED 16/11/09 ORACLE_OCM EXPIRED & LOCKED 16/11/09 TSMSYS EXPIRED & LOCKED 16/11/09 XS$NULL EXPIRED & LOCKED 16/11/09 BI EXPIRED & LOCKED 16/11/09 PM EXPIRED & LOCKED 16/11/09 MDDATA EXPIRED & LOCKED 16/11/09 USERNAME ACCOUNT_STATUS EXPIRY_D ------------------------------ -------------------------------- -------- IX EXPIRED & LOCKED 16/11/09 SH EXPIRED & LOCKED 16/11/09 DIP EXPIRED & LOCKED OE EXPIRED & LOCKED 16/11/09 APEX_PUBLIC_USER EXPIRED & LOCKED 16/11/09 HR EXPIRED & LOCKED 16/11/09 SPATIAL_CSW_ADMIN_USR EXPIRED & LOCKED 16/11/09 SPATIAL_WFS_ADMIN_USR EXPIRED & LOCKED 16/11/09

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• Simple SSH public/private key question

  - by James R.

  I am trying to learn this instead of just following guides so I can recommend proper actions when people do ask (and they do). Here is what I got down. First, generate both key with command such as this: ssh-keygen -b 2048 -t rsa -C comment -f ~/.ssh/id_rsa Then you push the public part of the key into authorized_keys2 file cat ~/.ssh/id_rsa.pub >> ~/.ssh/authorized_keys2 (and then chmod it to 600 or similar) And you download the private key to your computer (id_rsa) and feed that in to Putty to be read and authenticate. Are these the correct steps to setting this public/private key authentication for passwordless login to SSH?

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• Can a Compound key be set as a primary key to another table?

  - by Nikos

  Can a compound key be set as a primary key to another table? For instance i have the tables: Books -with Primary Key:Product_ID Client -with Primary key: Client_ID Clients_Books -with Compound Primary Key:Product_Id and Client_ID I want to set this compound Primary key from Clients_Books as a Primary Key to another table named: Order_Details. But I don't want to use the Product_ID and the Client_ID from the Books, Clients tables. Does this make sense? All opinions more than welcome.

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• Help with restoring expired domain as quick as possible

  - by Pasta

  My domain name expired today (owing to missing credit card info, etc) and it is really important as the company has about 50 users who cannot access emails, website unreachable, etc. I have requested UKReg to bring the domains backup and running but they will take about 24 hours to get it back up and running. Is there anything that I can do to return the service back to normal quicker?

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• Tell git which private key to use

  - by jrdioko

  ssh has the -i option to tell it which private key file to use when authenticating: -i identity_file Selects a file from which the identity (private key) for RSA or DSA authentication is read. The default is ~/.ssh/identity for protocol ver- sion 1, and ~/.ssh/id_rsa and ~/.ssh/id_dsa for protocol version 2. Iden- tity files may also be specified on a per-host basis in the configuration file. It is possible to have multiple -i options (and multiple identities specified in configuration files). Is there a similar way to tell git which private key file to use when on a system with multiple private keys in the .ssh directory?

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• How to revoke gnupg public key without private key?

  - by danijelc

  Long story short I have an key generated with seahorse and mistakenly deleted it from my system. I do remember passphrase but I don't have this key anywhere on my system. Scanned trough Ask Ubuntu but couldn't find any aplicabile solution on similar issue. However public key is still updated on keyring servers and I would like to revoke it. Since I have no revocation certificate and I can't get hold of private key (only public key is available from keyservers which I imported to seahorse) I have no idea how to accomplish it. Spent some time searching for solution acros net, various manuals and so on, but so far no luck. gpg --list-secret-keys - returns no output at all. gpg --list-keys - returns public key info gpg --gen-revoke *user-id* - returns - gpg: secret key *user-id* not found: eof gpg (GnuPG) version 1.4.11. Anyone able to suggest a solution?

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• BAD_UID error while exporting key in CryptoAPI

  - by mindthief

  Hi all, I am writing a test application for Microsoft CryptoAPI. I want to export the secret key of one party using the public key of the second party, and then import that secret key as the second party's secret key (this sets up a shared secret key for communication). Here is my code: if(!CryptExportKey(encryptT->hSymKey, decryptT->hPubKey, SIMPLEBLOB, 0, keyExBuf, &bufLen)) { FormattedDebugPrint(NULL, GetLastError(), "could not export secret key", TRUE); return -1; } if(!CryptImportKey(decryptT->hCryptProv, keyExBuf, bufLen, decryptT->hPubKey, 0, &(decryptT->hSymKey))) { FormattedDebugPrint(NULL, GetLastError(), "could not import secret key", TRUE); return -1; } And this gives the error: 80090001: Bad UID. The public keypair is being generated for both encryptT and decryptT (sender, receiver) by calling: CryptGenKey(encryptT->hCryptProv, CALG_RSA_KEYX, CRYPT_EXPORTABLE, &(encryptT->hPubKey)) Any idea what could be causing the error? Thanks,

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• Should foreign keys become table primary key?

  - by Carvell Fenton

  Hello again, I have a table (session_comments) with the following fields structure: student_id (foreign key to students table) session_id (foreign key to sessions table) session_subject_ID (foreign key to session_subjects table) user_id (foreign key to users table) comment_date_time comment Now, the combination of student_id, session_id, and session_subject_id will uniquely identify a comment about that student for that session subject. Given that combined they are unique, even though they are foreign keys, is there an advantage to me making them the combined primary key for that table? Thanks again.

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• Bind the windows key to Lubuntu start menu

  - by abel

  I am running Lubuntu 11.10. By default the main menu is bound to Alt+F1 (A-F1) which works. Here is the relevant code from ~/.config/openbox/lubuntu-rc.xml <keybind key="A-F1"> <action name="Execute"> <command>lxpanelctl menu</command> </action> </keybind> This works. When I hit Alt+F1, I can see the start menu. If I change the keys to "Windows key + M" (W-m), I can pull up the start menu using Win+M <keybind key="W-m"> <action name="Execute"> <command>lxpanelctl menu</command> </action> </keybind> However, I cannot bind the start menu to the Windows key alone. If I try replacing "W-m" by "W", the "W" alphabet key gets bound to the start menu. If I try "W-" nothing happens, I have tried the "Super" option too but to no avail. How can I bind the Lubuntu main menu to the windows Key? I have been through some relevant lubuntu questions, like this one, which tries to do the opposite. How do I unbind Super key from menu in Lubuntu

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• How to assign the array key a value, when the key name is itself a variable

  - by Matrym

  How do I identify an item in a hash array if the key of the array is only known within a variable? For example: var key = "myKey"; var array = {myKey: 1, anotherKey: 2}; alert(array.key); Also, how would I assign a value to that key, having identified it with the variable? This is, of course, assuming that I must use the variable key to identify which item in the array to alert. Thanks in advance!

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• mysql complex key or + auto increment key (guid)

  - by darko

  Hi, I have not very big db. I am using auto increment primary keys and in my case there is no problem with that. GUID is not necessary. I have a table containing this fields: from_destination to_testination shipper quantity Where the fields 1,2,3 needs to be unique. Also I have second table that for the fields 1,2,3 stores bought quantities per day One to many. from_destination to_destination shipper date reserved_quantity case 1 Is it better to make fields 1,2,3 as primary complex key in the first table and the same fields in the second table to be foreign key First table from_destination | to_destination | primary shipper | quaitity Second table second_id - autoincrement primary from_destination | to_destination | foreign key shipper | date reserved_quantity Case 2 or just to add auto increment filed in the first table and make fields 1,2,3 unique. In the second table there will be one ingeger foreign key pointing to the first table, and one auto increment key for the table. First table first_id - autoincrement primary from_destination | to_destination | unique shipper | quaitity Second table second_id - autoincrement primary first_id - forein date reserved_quantity If so why we need complex keys, when we can have one field auto increment or GUID and all other fields that are candidates for complex key to be unique. Regards

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• JUJU and ERROR environment has no access-key or secret-key

  - by Riccardo Magrini

  following the official guide: [1]https://juju.ubuntu.com/docs/config-maas.html and considered that I've generated the ssh key (added it to UI of MAAS) and the API key, my environments.yaml file presents in this way: environments: maas: type: maas maas-server: 'http://x.x.x.x/MAAS/' maas-oauth: 'NDPA86PsEzS7bFynSy:vqJLkyHUJbvYzbtY5Q:sXXXXXXXXXXXXXXXXXXXXXX admin-secret: 'nothing' default-series: precise authorized-keys-path: ~/.ssh/id_rsa.pub # or any file you want. when I try to run the command: juju bootstrap receive the following error: ERROR environment has no access-key or secret-key Someone can explain me where is the wrong? MAAS and JUJU are installed using their ppa stable on an Ubuntu 12.04.3 Server

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• Encryption Product Keys : Public and Private key encryption

  - by Aran Mulholland

  I need to generate and validate product keys and have been thinking about using a public/private key system. I generate our product keys based on a client name (which could be a variable length string) a 6 digit serial number. It would be good if the product key would be of a manageable length (16 characters or so) I need to encrypt them at the base and then distrubute the decryption/validation system. As our system is written in managed code (.NET) we dont want to distribute the encryption system, only the decryption. I need a public private key seems a good way to do this, encrypt with the one key that i keep and distribute the other key needed for decrpytion/verification. What is an appropriate mechanism to do this with the above requirements?

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• Foreign key reference to a two-column primary key

  - by Adam Ernst

  One of my tables has a two-column primary key: CREATE TABLE tournament ( state CHAR(2) NOT NULL, year INT NOT NULL, etc..., PRIMARY KEY(state, year) ); I want a reference to the tournament table from another table, but I want this reference to be nullable. Here's how I might do it, imagining that a winner doesn't necessarily have a tournament: CREATE TABLE winner ( name VARCHAR NOT NULL, state CHAR(2) NULL, year INT NULL ); If state is null but year is not, or vice-versa, the table would be inconsistent. I believe the following FOREIGN KEY constraint fixes it: ALTER TABLE winner ADD CONSTRAINT FOREIGN KEY fk (name, state) REFERENCES tournament (name, state); Is this the proper way of enforcing consistency? Is this schema properly normalized?

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• Primary Key Identity Value Increments On Unique Key Constraint Violation

  - by Jed

  I have a SqlServer 2008 table which has a Primary Key (IsIdentity=Yes) and three other fields that make up a Unique Key constraint. In addition I have a store procedure that inserts a record into the table and I call the sproc via C# using a SqlConnection object. The C# sproc call works fine, however I have noticed interesting results when the C# sproc call violates the Unique Key constraint.... When the sproc call violates the Unique Key constraint, a SqlException is thrown - which is no surprise and cool. However, I notice that the next record that is successfully added to the table has a PK value that is not exactly one more than the previous record - For example: Say the table has five records where the PK values are 1,2,3,4, and 5. The sproc attempts to insert a sixth record, but the Unique Key constraint is violated and, so, the sixth record is not inserted. Then the sproc attempts to insert another record and this time it is successful. - This new record is given a PK value of 7 instead of 6. Is this normal behavior? If so, can you give me a reason why this is so? (If a record fails to insert, why is the PK index incremented?) If this is not normal behavior, can you give me any hints as to why I am seeing these symptoms?

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• SSH Public Key - No supported authentication methods available (server sent public key)

  - by F21

  I have a 12.10 server setup in a virtual machine with its network set to bridged (essentially will be seen as a computer connected to my switch). I installed opensshd via apt-get and was able to connect to the server using putty with my username and password. I then set about trying to get it to use public/private key authentication. I did the following: Generated the keys using PuttyGen. Moved the public key to /etc/ssh/myusername/authorized_keys (I am using encrypted home directories). Set up sshd_config like so: PubkeyAuthentication yes AuthorizedKeysFile /etc/ssh/%u/authorized_keys StrictModes no PasswordAuthentication no UsePAM yes When I connect using putty or WinSCP, I get an error saying No supported authentication methods available (server sent public key). If I run sshd in debug mode, I see: PAM: initializing for "username" PAM: setting PAM_RHOST to "192.168.1.7" PAM: setting PAM_TTY to "ssh" userauth-request for user username service ssh-connection method publickey [preauth] attempt 1 failures 0 [preauth] test whether pkalg/pkblob are acceptable [preauth[ Checking blacklist file /usr/share/ssh/blacklist.RSA-1023 Checking blacklist file /etc/ssh/blacklist.RSA-1023 temporarily_use_uid: 1000/1000 (e=0/0) trying public key file /etc/ssh/username/authorized_keys fd4 clearing O_NONBLOCK restore_uid: 0/0 Failed publickey for username from 192.168.1.7 port 14343 ssh2 Received disconnect from 192.168.1.7: 14: No supported authentication methods available [preauth] do_cleanup [preauth] monitor_read_log: child log fd closed do_cleanup PAM: cleanup Why is this happening and how can I fix this?

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• Entity Framework with MySQL - Timeout Expired while Generating Model

  - by Nathan Taylor

  I've constructed a database in MySQL and I am attempting to map it out with Entity Framework, but I start running into "GenerateSSDLException"s whenever I try to add more than about 20 tables to the EF context. An exception of type 'Microsoft.Data.Entity.Design.VisualStudio.ModelWizard.Engine.ModelBuilderEngine+GenerateSSDLException' occurred while attempting to update from the database. The exception message is: 'An error occurred while executing the command definition. See the inner exception for details.' Fatal error encountered during command execution. Timeout expired. The timeout period elapsed prior to completion of the operation or the server is not responding. There's nothing special about the affected tables, and it's never the same table(s), it's just that after a certain (unspecific) number of tables have been added, the context can no longer be updated without the "Timeout expired" error. Sometimes it's only one table left over, and sometimes it's three; results are pretty unpredictable. Furthermore, the variance in the number of tables which can be added before the error indicates to me that perhaps the problem lies in the size of the query being generated to update the context which includes both the existing table definitions, and also the new tables that are being added to it. Essentially, the SQL query is getting too large and it's failing to execute for some reason. If I generate the model with EdmGen2 it works without any errors, but the generated EDMX file cannot be updated within Visual Studio without producing the aforementioned exception. In all likelihood the source of this problem lies in the tool within Visual Studio given that EdmGen2 works fine, but I'm hoping that perhaps others could offer some advice on how to approach this very unique issue, because it seems like I'm not the only person experiencing it. One suggestion a colleague offered was maintaining two separate EBMX files with some table crossover, but that seems like a pretty ugly fix in my opinion. I suppose this is what I get for trying to use "new technology". :(

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• Standard way to hash an RSA key?

  - by Adam J.R. Erickson

  What's the algorithm for creating hash (sha-1 or MD5) of an RSA public key? Is there a standard way to do this? Hash just the modulus, string addition of both and then take a hash? Is SHA-1 or MD5 usually used? I want to use it to ensure that I got the right key (have the sender send a hash, and I calculate it myself), and log said hash so I always know which exact key I used when I encrypt the payload.

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• violation of primary key constraint .Cannot insert duplicate key in object using ADO

  - by CREFLY

  Hi All we are working on a users apllication using Access2003(VBA) as software language and SQL Server 2005 as database. We are using ADO method and we encounter a problem. when users create new record in a ADO Screen and they want to save the record after implementing it they receive this error : error -2147217873 violation of primary key constraint 'PK_ '.Cannot insert duplicate key in object 'Pk_...' Any help will be appreciated Thanks in advance

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• workflow runtime ownership expired

  Hello all, I am facing a strange problem in windows workflow foundation, need help from you guys. I have creatd a State Machine Workflow ,it worked very fine in one build , but due to some requirements i altered workflow , build and reinstall application , but now when i am trying to access workflow instaces which i created in provious build , it give me runtime exception "This workflow is not owned by the WorkflowRuntime. The WorkflowRuntime's ownership has expired, or another WorkflowRuntime owns the workflow" please help me to resolve this problem

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• Using datetime float representation as primary key

  - by devanalyst

  From my experience I have learn that using an surrogate INT data type column as primary key esp. an IDENTITY key column offers better performance than using GUID or char/varchar data type column as primary key. I try to use IDENTITY key as primary key wherever possible. But recently I came across a schema where the tables were horizontally partitioned and were managed via a Partitioned view. So the tables could not have an IDENTITY column since that would make the Partitioned View non updatable. One work around for this was to create a dummy 'keygenerator' table with an identity column to generate IDs for primary key. But this would mean having a 'keygenerator' table for each of the Partitioned View. My next thought was to use float as a primary key. The reason is the following key algorithm that I devised DECLARE @KEY FLOAT SET @KEY = CONVERT(FLOAT,GETDATE())/100000.0 SET @KEY = @EMP_ID + @KEY Heres how it works. CONVERT(FLOAT,GETDATE()) gives float representation of current datetime since internally all datetime are represented by SQL as a float value. CONVERT(FLOAT,GETDATE())/100000.0 converts the float representation into complete decimal value i.e. all digits are pushed to right side of ".". @KEY = @EMP_ID + @KEY adds the Employee ID which is an integer to this decimal value. The logic is that the Employee ID is guaranteed to be unique across sessions since an employee cannot connect to an application more than once at the same time. And for the same employee each time a key will be generated the current datetime will be unique. In all an unique key across all employee sessions and across time. So for Emp Ids 11 and 12, I have key values like 12.40046693321566357, 11.40046693542361111 But my concern whether float data type as primary key offer benefits compared to choosing GUID or char/varchar as primary keys. Also important thing is because of partitioning the float column is going to be part of a composite key.

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• Varchar with trailing spaces as a Primary Key in SQL Server 2008

  - by cacaupt

  Is it possible to have a varchar column as a primary key with values like 'a ' and 'a', is gives always this error "Violation of PRIMARY KEY constraint" in MS SQL Server 2008. In Oracle dons't give any error. BTW I'm not implementing this way I'm only trying to migrate the data from oracle to sql server. Regards

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