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  • XSLT transformation datetime to date format

    - by freggel
    I'm trying to transform a datetime to a date format yyyy-MM-dd, because I'm using the xsd.exe tool the xs:date datatypes are automatically changed into a datetime datatype, because there is no type in the .NET Framework that matches the type xs:date completely. But I can't get it to work <articles> <article> <articleid>48992</articleid> <deliverydateasked>2009-01-29T00:00:00+01:00</deliverydateasked> </article> <article> <articleid>48993</articleid> <deliverydateasked>2009-01-30T00:00:00+01:00</deliverydateasked> </article> </articles> trying to convert the xml to <articles> <article> <articleid>48992</articleid> <deliverydateasked>2009-01-29</deliverydateasked> </article> <article> <articleid>48993</articleid> <deliverydateasked>2009-01-30</deliverydateasked> </article> </articles> currently I'm using this XSLT <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0"> <xsl:template match="/"> <articles> <xsl:apply-templates select="article"> </xsl:apply-templates> </articles> </xsl:template> <xsl:template name="FormatDate"> <xsl:param name="DateTime" /> <xsl:variable name="date"> <xsl:value-of select="substring-before($DateTime,'T')" /> </xsl:variable> <xsl:if test="string-length($date) != 10"> <xsl:value-of select="$DateTime"/> </xsl:if> <xsl:if test="string-length($date) = 10"> <xsl:value-of select="$date"/> </xsl:if> </xsl:template> <xsl:template match="article"> <xsl:call-template name="FormatDate"> <xsl:with-param name="DateTime" select="deliverydateasked"/> </xsl:call-template> </xsl:template> Does anyone know a good xslt transformation. Thanks in advance The output result of my code is <articles />

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