Search Results

Search found 53 results on 3 pages for 'inlines'.

Page 1/3 | 1 2 3  | Next Page >

  • group inlines in django admin

    - by pablo
    Hi I have a two models, Model1 and Model2. Model2 has a FK to Model1 and FK to iteself. In the admin I show Model2 as inlines in Model1 change_form. I want to modify the way the inlines are shown in the admin. I need to group all the instances that have the same parent_model2 and display them as a readonly field with a string of 'childs' in the parent Model2 instance. I know how to use itertools.groupby (or the django version) but don't know how to do it in the admin. What should I override to be able to iterate over all the Model2 instances, group them by parent, add children to the parent and remove children from the inlines? class Model1(models.Model): name = models.CharField() class Model2(models.Model): name = models.CharField() fk_model1 = models.ForeignKey('self', blank=True, null=True) parent_model2 = models.ForeignKey('self', blank=True, null=True) Thanks

    Read the article

  • Inlines in Django Admin

    - by Oli
    I have two models, Order and UserProfile. Each Order has a ForeignKey to UserProfile, to associate it with that user. On the django admin page for each Order, I'd like to display the UserProfile associated with it, for easy processing of information. I have tried inlines: class UserInline(admin.TabularInline): model = UserProfile class ValuationRequestAdmin(admin.ModelAdmin): list_display = ('address1', 'address2', 'town', 'date_added') list_filter = ('town', 'date_added') ordering = ('-date_updated',) inlines = [ UserInline, ] But it complains that UserProfile "has no ForeignKey to" Order - which it doesn't, it's the other way around. Is there a way to do what I want?

    Read the article

  • Not quite nested inlines?

    - by Lynden Shields
    Not quite sure what to call this, it's not quite nested inlines, but is probably related. I have a 3 level hierarchy of objects, A one-to-many B one-to-many C. Therefore, every C implicitly also belongs to an A. class A(models.Model): stuff = models.CharField("Stuff", max_length=50) class B(models.Model): a = models.ForeignKey(A) class C(models.Model): b = models.ForeignKey(B) I would like all C's that belong to an A to be listed on the admin page for A in an in-line. They do not have to show which B they belong to on the same page. Is this possible or is it the same problem as nested inlines anyway? If it's possible, how do I do it? I'm using django 1.3

    Read the article

  • Prepopulating inlines based on the parent model in the Django Admin

    - by Alasdair
    I have two models, Event and Series, where each Event belongs to a Series. Most of the time, an Event's start_time is the same as its Series' default_time. Here's a stripped down version of the models. #models.py class Series(models.Model): name = models.CharField(max_length=50) default_time = models.TimeField() class Event(models.Model): name = models.CharField(max_length=50) date = models.DateField() start_time = models.TimeField() series = models.ForeignKey(Series) I use inlines in the admin application, so that I can edit all the Events for a Series at once. If a series has already been created, I want to prepopulate the start_time for each inline Event with the Series' default_time. So far, I have created a model admin form for Event, and used the initial option to prepopulate the time field with a fixed time. #admin.py ... import datetime class OEventInlineAdminForm(forms.ModelForm): start_time = forms.TimeField(initial=datetime.time(18,30,00)) class Meta: model = OEvent class EventInline(admin.TabularInline): form = EventInlineAdminForm model = Event class SeriesAdmin(admin.ModelAdmin): inlines = [EventInline,] I am not sure how to proceed from here. Is it possible to extend the code, so that the initial value for the start_time field is the Series' default_time?

    Read the article

  • How to deal with multiple sub-type of one super-type in Django admin

    - by Henri
    What would be the best solution for adding/editing multiple sub-types. E.g a super-type class Contact with sub-type class Client and sub-type class Supplier. The way shown here works, but when you edit a Contact you get both inlines i.e. sub-type Client AND sub-type Supplier. So even if you only want to add a Client you also get the fields for Supplier of vice versa. If you add a third sub-type , you get three sub-type field groups, while you actually only want one sub-type group, in the mentioned example: Client. E.g.: class Contact(models.Model): contact_name = models.CharField(max_length=128) class Client(models.Model): contact = models.OneToOneField(Contact, primary_key=True) user_name = models.CharField(max_length=128) class Supplier(models.Model): contact.OneToOneField(Contact, primary_key=True) company_name = models.CharField(max_length=128) and in admin.py class ClientInline(admin.StackedInline): model = Client class SupplierInline(admin.StackedInline): model = Supplier class ContactAdmin(admin.ModelAdmin): inlines = (ClientInline, SupplierInline,) class ClientAdmin(admin.ModelAdmin): ... class SupplierAdmin(admin.ModelAdmin): ... Now when I want to add a Client, i.e. only a Client I edit Contact and I get the inlines for both Client and Supplier. And of course the same for Supplier. Is there a way to avoid this? When I want to add/edit a Client that I only see the Inline for Client and when I want to add/edit a Supplier that I only see the Inline for Supplier, when adding/editing a Contact? Or perhaps there is a different approach. Any help or suggestion will be greatly appreciated.

    Read the article

  • WPF Multiline TextBlock LineBreak issues

    - by KMC
    I have the following code txtBlock1.Inlines.Add("This is first paragraph \n This is second paragraph"); then TextBlock would display: This is first paragraph This is second paragraph But, if I have the following (which I though is equivalent); txtBlock1.Inlines.Add("This is first paragraph"); txtBlock1.Inlines.Add("\n"); txtBlock1.Inlines.Add("This is second paragraph"); TextBlock display: This is first paragraph // but second paragraph missing If I separate out the linebreak then the rest of text after the linebreak doesn't show. Why? I have to use run: Run run1 = new Run(); run1.Text = "First Paragraph"; run1.Text += "\n"; run1.Text += "Second Paragraph"; txtBlock1.Inlines.Add(run1); Then it produce the result correctly. Why I cannot add inline text to Textblock and require me to use Run?

    Read the article

  • Raising event in custom control.

    - by SeSSiZ
    Hi all, I'm writing a custom textblock control thats populate hyperlinks and raises event when clicked to hyperlink. I wrote this code but I got stucked. My code is : Imports System.Text.RegularExpressions Public Class CustomTextBlock Inherits TextBlock Public Event Klik As EventHandler(Of EventArgs) Public ReadOnly InlineCollectionProperty As DependencyProperty = DependencyProperty.Register("InlineCollection", GetType(String), GetType(CustomTextBlock), New PropertyMetadata(New PropertyChangedCallback(AddressOf CustomTextBlock.InlineChanged))) Private Shared Sub InlineChanged(ByVal sender As DependencyObject, ByVal e As DependencyPropertyChangedEventArgs) DirectCast(sender, CustomTextBlock).Inlines.Clear() Dim kelimeler = Split(e.NewValue, " ") For i = 0 To kelimeler.Length - 1 If Regex.Match(kelimeler(i), "(http|ftp|https):\/\/[\w\-_]+(\.[\w\-_]+)+([\w\-\.,@?^=%&:/~\+#]*[\w\-\@?^=%&/~\+#])?").Success Then Dim x = New Hyperlink(New Run(kelimeler(i))) x.AddHandler(Hyperlink.ClickEvent, New RoutedEventHandler(AddressOf t_Click)) x.ToolTip = kelimeler(i) x.Tag = kelimeler(i) DirectCast(sender, CustomTextBlock).Inlines.Add(x) If Not i = kelimeler.Length Then DirectCast(sender, CustomTextBlock).Inlines.Add(" ") Else DirectCast(sender, CustomTextBlock).Inlines.Add(kelimeler(i)) If Not i = kelimeler.Length Then DirectCast(sender, CustomTextBlock).Inlines.Add(" ") End If ''//Console.WriteLine(kelime(i).ToString.StartsWith("@")) Next kelimeler = Nothing End Sub Public Property InlineCollection As String Get Return DirectCast(GetValue(InlineCollectionProperty), String) End Get Set(ByVal value As String) SetValue(InlineCollectionProperty, value) End Set End Property Private Shared Sub t_Click(ByVal sender As Hyperlink, ByVal e As System.Windows.RoutedEventArgs) e.Handled = True RaiseEvent Klik(sender, EventArgs.Empty) End Sub End Class This code gives error at RaiseEvent Klik(sender, EventArgs.Empty) Error is : Cannot refer to an instance member of a class from within a shared method or shared member initializer without an expliticit instance of the class. Thanks for your answers, Alper

    Read the article

  • WPF Repeater (like) control for collection source??

    - by Sonic Soul
    I have a WPF DataGrid bound to ObservableCollection. Each item in my collection has Property which is a List. In my row details pane, i would like to write out formatted textblocks for each item in this collection. The end result would be something equivalent to: <TextBlock Style="{StaticResource NBBOTextBlockStyle}" HorizontalAlignment="Right"> <TextBlock.Inlines> <Run FontWeight="Bold" Text="{Binding Path=Exchanges[0].Name}" /> <Run FontWeight="Bold" Text="{Binding Path=Exchanges[0].Price}" /> <LineBreak /> <Run Foreground="LightGray" Text="{Binding Path=Exchanges[0].Quantity}" /> </TextBlock.Inlines> </TextBlock> <TextBlock Style="{StaticResource NBBOTextBlockStyle}"> <TextBlock.Inlines> <Run FontWeight="Bold" Text="{Binding Path=Exchanges[1].Name}" /> <Run FontWeight="Bold" Text="{Binding Path=Exchanges[1].Price}" /> <LineBreak /> <Run Foreground="LightGray" Text="{Binding Path=Exchanges[1].Quantity}" /> </TextBlock.Inlines> </TextBlock> and so on 0-n times. I've tried using ItemsControl for this: <ItemsControl ItemsSource="{Binding Path=Exchanges}"> <DataTemplate> <Label>test</Label> </DataTemplate> </ItemsControl> however, this appears to be only meant for more static sources, as it throws the following exception (collection is not altered after creation): ItemsControl Operation is not valid while ItemsSource is in use. Access and modify elements with ItemsControl.ItemsSource instead Is there another way to achieve this?

    Read the article

  • Generic relations missing with grappelli

    - by diegueus9
    I'm using the last svn revision of grappelli and rev 11840 of django (before multidatabases and stuff), and i'm trying to use generic relations in the admin, but doesn't work, The model: class AutorProyectoLey(DatedModel): tipo_autor = models.ForeignKey(ContentType) autor_id = models.PositiveIntegerField() content_object = generic.GenericForeignKey('tipo_autor', 'autor_id') proyecto_ley = models.ForeignKey(ProyectoLey) The admin: class AutorInline(GenericInlineModelAdmin): model = AutorProyectoLey allow_add = True ct_field = 'tipo_autor' ct_fk_field = 'autor_id' classes = ('collapse-open',) And i put this model of var inlines in another adminmodel, but the html render is : <!-- Inlines --> <!-- Submit-Row -->

    Read the article

  • WPF: LineBreak enable/disable dynamically

    - by Sonic Soul
    i would like to make the LineBreak element inside of that TextBlock controllable by the user in preferences to Enable/Disable it being there <TextBlock Style="{StaticResource TextBlockStyle}" Width="130"> <TextBlock.Inlines> <Run Text="{Binding Path=Name}" FontWeight="Bold" Foreground="#FF2A4D9E" /> <Run Text="{Binding Path=Price}" FontWeight="Bold" /> <LineBreak /> <Run Text="{Binding Path=Quantity}" Foreground="#99000000" /> </TextBlock.Inlines> </TextBlock>

    Read the article

  • Item 2, Scott Myers Effective C++ question

    - by user619818
    In Item2 on page 16, (Prefer consts, enums, and inlines to #defines), Scott says: 'Also, though good compilers won't set aside storage for const objects of integer types'. I don't understand this. If I define a const object, eg const int myval = 5; then surely the compiler must set aside some memory (of int size) to store the value 5? Or is const data stored in some special way? This is more a question of computer storage I suppose. Basically, how does the computer store const objects so that no storage is set aside?

    Read the article

  • How do .so files avoid problems associated with passing header-only templates like MS dll files have?

    - by Doug T.
    Based on the discussion around this question. I'd like to know how .so files/the ELF format/the gcc toolchain avoid problems passing classes defined purely in header files (like the std library). According to Jan in that answer, the dynamic linker/loader only picks one version of such a class to load if its defined in two .so files. So if two .so files have two definitions, perhaps with different compiler options/etc, the dynamic linker can pick one to use. Is this correct? How does this work with inlining? For example, MSVC inlines templates aggressively. This makes the solution I describe above untenable for dlls. Does Gcc never inline header-only templates like the std library as MSVC does? If so wouldn't that make the functionality of ELF described above ineffective in these cases?

    Read the article

  • HTML5 Boilerplate : 4ème version de l'outil de prototypage de designs, documentation embarquée et de nouvelles @media queries

    HTML5 Boilerplate atteint sa quatrième version Code réorganisé, documentation embarquée, licence MIT et nouvelles @media queries La nouvelle version de HTML5 Boilerplate vient d'être distribuée. C'est le quatrième opus du fameux outil de prototypage de designs HTML5, à partir de templates HTML, CSS et JavaScript. Quoi de neuf dans cette version ? D'abord un nouveau site élégant, une nouvelle licence MIT (au lieu d'être simplement dans le domaine public), une documentation embarquée et un code réorganisé et épuré. Les commentaires « inlines » superflus ont été enlevés et les fichiers CSS, JS et les sous répertoires renommés. On remarque aussi une meilleure uniformisation du formatag...

    Read the article

  • Django disable editing (but allow adding) in TabularInline view

    - by VoteyDisciple
    I want to disable editing ALL objects within a particular TabularInline instance, while still allowing additions and while still allowing editing of the parent model. I have this trivial setup: class SuperviseeAdmin(admin.TabularInline): model = Supervisee class SupervisorAdmin(admin.ModelAdmin): inlines = [SuperviseeAdmin] admin.site.register(Supervisor, SupervisorAdmin) I have tried adding a has_change_permission function to SuperviseeAdmin that returns False unconditionally, but it had no effect. I have tried setting actions = None in SuperviseeAdmin but it had no effect. What might I be overlooking that could get this to work?

    Read the article

  • Page specific CSS styling, but where to put the code?

    - by wretrOvian
    Hi. :) Apart from the global.css i'm including in my header.php, i would also like to load certain page-content specific styles. But since my <head></head> is already covered by my header file, and i don't wish to resort to inlines, what is the best way to place the styles on the specific page? Thanks ! :D

    Read the article

  • Is QtQuick.Controls available on Ubuntu 13.10

    - by javascript is future
    I was looking to do UI development in QML, and I really want it to look native. I found the QtQuick.Controls (http://qt-project.org/doc/qt-5.1/qtquickcontrols/qtquickcontrols-index.html), but when I try make a simple application, it tells me that QtQuick.Controls isn't installed. main.qml: import QtQuick 2.1 import QtQuick.Controls 1.0 Rectangle { height: 200 width: 200 } terminal: $ qmlscene main.qml file:///tmp/main.qml:2 module "QtQuick.Controls" is not installed Also, I downloaded the source from https://qt.gitorious.org/qt/qtquickcontrols/source/stable, ran qmake && make, but this returned the following output: cd src/ && ( test -e Makefile || /usr/lib/i386-linux-gnu/qt5/bin/qmake /tmp/qtquickcontrols/src/src.pro -o Makefile ) && make -f Makefile make[1]: Går til katalog '/tmp/qtquickcontrols/src' cd controls/ && ( test -e Makefile || /usr/lib/i386-linux-gnu/qt5/bin/qmake /tmp/qtquickcontrols/src/controls/controls.pro -o Makefile ) && make -f Makefile make[2]: Går til katalog '/tmp/qtquickcontrols/src/controls' g++ -c -g -O2 -fstack-protector --param=ssp-buffer-size=4 -Wformat -Werror=format-security -D_FORTIFY_SOURCE=2 -O2 -fvisibility=hidden -fvisibility-inlines-hidden -std=c++0x -fno-exceptions -Wall -W -D_REENTRANT -fPIC -DQT_NO_XKB -DQT_NO_EXCEPTIONS -D_LARGEFILE64_SOURCE -D_LARGEFILE_SOURCE -DQT_NO_DEBUG -DQT_PLUGIN -DQT_QUICK_LIB -DQT_QML_LIB -DQT_WIDGETS_LIB -DQT_NETWORK_LIB -DQT_GUI_LIB -DQT_CORE_LIB -I/usr/share/qt5/mkspecs/linux-g++ -I. -I/usr/include/qt5 -I/usr/include/qt5/QtQuick -I/usr/include/qt5/QtQml -I/usr/include/qt5/QtWidgets -I/usr/include/qt5/QtNetwork -I/usr/include/qt5/QtGui -I/usr/include/qt5/QtGui/5.1.1 -I/usr/include/qt5/QtGui/5.1.1/QtGui -I/usr/include/qt5/QtCore -I/usr/include/qt5/QtCore/5.1.1 -I/usr/include/qt5/QtCore/5.1.1/QtCore -I.moc/release-shared -o .obj/release-shared/qquickaction.o qquickaction.cpp qquickaction.cpp:49:39: fatal error: private/qguiapplication_p.h: No such file or directory #include <private/qguiapplication_p.h> ^ Is there some PPA I could use, or do I have to wait for Trusty to get out, before I can use native controls from Qt? Regards

    Read the article

  • WPF TextBlock highlight certan parts based on search condition

    - by Daniil Harik
    Hello, I have TextBlock that has Inlines dynamicly added to it (basically bunch of Run objects that are either italic or bold). In my application I have search function. I want to be able to highlight TextBlock's text that is in being searched for. By highlighting I mean changing certain parts of TextBlock text's color (keeping in mind that it may highlight several different Run objects at a time). I have tried this example http://blogs.microsoft.co.il/blogs/tamir/archive/2008/05/12/search-and-highlight-any-text-on-wpf-rendered-page.aspx But it seams very unstable :( Is there easy way to solve this problem?

    Read the article

  • Django: Adding inline formset rows without javascript

    - by Brant
    This post relates to this: http://stackoverflow.com/questions/520421/add-row-to-inlines-dynamically-in-django-admin Is there a way to achive adding inline formsets WITHOUT using javascript? Obviously, there would be a page-refresh involved. So, if the form had a button called 'add'... I figured I could do it like this: if request.method=='POST': if 'add' in request.POST: PrimaryFunctionFormSet = inlineformset_factory(Position,Function,extra=1) prims = PrimaryFunctionFormSet(request.POST) Which I thought would add 1 each time, then populate the form with the post data. However, it seems that the extra=1 does not add 1 to the post data.

    Read the article

  • How to customize a many-to-many inline model in django admin

    - by Jonathan
    I'm using the admin interface to view invoices and products. To make things easy, I've set the products as inline to invoices, so I will see the related products in the invoice's form. As you can see I'm using a many-to-many relationship. In models.py: class Product(models.Model): name = models.TextField() price = models.DecimalField(max_digits=10,decimal_places=2) class Invoice(models.Model): company = models.ForeignKey(Company) customer = models.ForeignKey(Customer) products = models.ManyToManyField(Product) In admin.py: class ProductInline(admin.StackedInline): model = Invoice.products.through class InvoiceAdmin(admin.ModelAdmin): inlines = [FilteredApartmentInline,] admin.site.register(Product, ProductAdmin) The problem is that django presents the products as a table of drop down menus (one per associated product). Each drop down contains all the products listed. So if I have 5000 products and 300 are associated with a certain invoice, django actually loads 300x5000 product names. Also the table is not aesthetic. How can I change it so that it'll just display the product's name in the inline table? Which form should I override, and how?

    Read the article

  • Adding links to full change forms for inline items in django admin?

    - by David Eyk
    I have a standard admin change form for an object, with the usual StackedInline forms for a ForeignKey relationship. I would like to be able to link each inline item to its corresponding full-sized change form, as the inline item has inlined items of its own, and I can't nest them. I've tried everything from custom widgets to custom templates, and can't make anything work. So far, the "solutions" I've seen in the form of snippets just plain don't seem to work for inlines. I'm getting ready to try some DOM hacking with jQuery just to get it working and move on. I hope I must be missing something very simple, as this seems like such a simple task! Using Django 1.2.

    Read the article

  • django admin gives warning "Field 'X' doesn't have a default value"

    - by noam
    I have created two models out of an existing legacy DB , one for articles and one for tags that one can associate with articles: class Article(models.Model): article_id = models.AutoField(primary_key=True) text = models.CharField(max_length=400) class Meta: db_table = u'articles' class Tag(models.Model): tag_id = models.AutoField(primary_key=True) tag = models.CharField(max_length=20) article=models.ForeignKey(Article) class Meta: db_table = u'article_tags' I want to enable adding tags for an article from the admin interface, so my admin.py file looks like this: from models import Article,Tag from django.contrib import admin class TagInline(admin.StackedInline): model = Tag class ArticleAdmin(admin.ModelAdmin): inlines = [TagInline] admin.site.register(Article,ArticleAdmin) The interface looks fine, but when I try to save, I get: Warning at /admin/webserver/article/382/ Field 'tag_id' doesn't have a default value

    Read the article

1 2 3  | Next Page >