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  • DefaultHttpClient GET and POST commands Java Android

    - by RenegadeAndy
    Ok this is my application : An Android app to allow me to submit CokeZone codes into CokeZone.co.uk from a mobile app instead of from the website. So I wrote this section of code to do the post logon command and then check to see if im logged in after. Problem is - the html I get from the homepage after I send the post command is the default - as if im not logged in - so something is going wrong. Can anyone please help! Its probably the URL im sending the POST to, or the params within the POST command - I havent done much of this stuff so its probably something obvious. Below is my code so far: DefaultHttpClient httpclient = new DefaultHttpClient(); HttpGet httpget = new HttpGet(url); HttpResponse response = httpclient.execute(httpget); HttpEntity entity = response.getEntity(); thisResponse = printPage(entity.getContent()); Log.e("debug",thisResponse); System.out.println("Login form get: " + response.getStatusLine()); if (entity != null) { entity.consumeContent(); } System.out.println("Initial set of cookies:"); List<Cookie> cookies = httpclient.getCookieStore().getCookies(); if (cookies.isEmpty()) { System.out.println("None"); } else { for (int i = 0; i < cookies.size(); i++) { System.out.println("- " + cookies.get(i).toString()); } } HttpPost httpost = new HttpPost("https://secure.cokezone.co.uk/home/blank.jsp?_DARGS=/home/login/login.jsp"); List <NameValuePair> nvps = new ArrayList <NameValuePair>(); nvps.add(new BasicNameValuePair("_dyncharset", "ISO-8859-1")); nvps.add(new BasicNameValuePair("/grlp/login/LoginHandler.loginFormBean.name","renegadeandy%40gmail.com")); nvps.add(new BasicNameValuePair("_D:/grlp/login/LoginHandler.loginFormBean.name", "+")); nvps.add(new BasicNameValuePair("/grlp/login/LoginHandler.cookiedUser", "false")); nvps.add(new BasicNameValuePair("_D:/grlp/login/LoginHandler.cookiedUser", "+")); nvps.add(new BasicNameValuePair("/grlp/login/LoginHandler.loginFormBean.password", "passwordval")); nvps.add(new BasicNameValuePair("_D:/grlp/login/LoginHandler.loginFormBean.password", "+")); nvps.add(new BasicNameValuePair("/grlp/login/LoginHandler.rememberMe", "yes")); nvps.add(new BasicNameValuePair("_D:/grlp/login/LoginHandler.rememberMe", "false")); nvps.add(new BasicNameValuePair("/grlp/login/LoginHandler.aSuccessURL", "http://www.cokezone.co.uk/home/index.jsp")); nvps.add(new BasicNameValuePair("_D:/grlp/login/LoginHandler.aSuccessURL", "+")); nvps.add(new BasicNameValuePair("/grlp/login/LoginHandler.aErrorURL", "http://www.cokezone.co.uk/home/index.jsphttps://secure.cokezone.co.uk/home/index.jsp")); nvps.add(new BasicNameValuePair("/grlp/login/LoginHandler.aErrorURL", "+")); nvps.add(new BasicNameValuePair("/grlp/login/LoginHandler.explicitLogin", "true")); nvps.add(new BasicNameValuePair("_D:/grlp/login/LoginHandler.explicitLogin", "+")); nvps.add(new BasicNameValuePair("/grlp/login/LoginHandler.fICLogin", "login")); nvps.add(new BasicNameValuePair("_D:/grlp/login/LoginHandler.fICLogin", "+")); nvps.add(new BasicNameValuePair("/grlp/login/LoginHandler.fICLogin", "LOGIN")); nvps.add(new BasicNameValuePair("_D:/grlp/login/LoginHandler.fICLogin", "+")); nvps.add(new BasicNameValuePair("_DARGS", "/home/login/login.jsp")); httpost.setEntity(new UrlEncodedFormEntity(nvps, HTTP.UTF_8)); response = httpclient.execute(httpost); entity = response.getEntity(); System.out.println("Login form get: " + response.getStatusLine()); if (entity != null) { thisResponse = printPage(entity.getContent()); entity.consumeContent(); } Log.e("debug",thisResponse); Log.e("debug","done"); httpget = new HttpGet("http://www.cokezone.co.uk/home/index.jsp"); response = httpclient.execute(httpget); entity = response.getEntity(); TextView points = (TextView)findViewById(R.id.points); points.setText(getPoints(entity.getContent()).toString()); debug.setText(thisResponse); System.out.println("Post logon cookies:"); cookies = httpclient.getCookieStore().getCookies(); if (cookies.isEmpty()) { System.out.println("None"); } else { for (int i = 0; i < cookies.size(); i++) { System.out.println("- " + cookies.get(i).toString()); } }

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  • WCF Restful services getting error 400 (bad request) when post xml data

    - by Wayne Lo
    I am trying to self host a WCF services and calling the services via javascript. It works when I pass the request data via Json but not xml (400 bad request). Please help. Contract: public interface iSelfHostServices { [OperationContract] [WebInvoke(Method = "POST", UriTemplate = INFOMATO.RestTemplate.hello_post2,RequestFormat = WebMessageFormat.Xml, ResponseFormat = WebMessageFormat.Xml, BodyStyle = WebMessageBodyStyle.Wrapped)] Stream hello_post2(string helloString); } Server side code: public Stream hello_post2(string helloString) { if (helloString == null) { WebOperationContext.Current.OutgoingResponse.StatusCode = System.Net.HttpStatusCode.BadRequest; return null; } WebOperationContext.Current.OutgoingResponse.StatusCode = System.Net.HttpStatusCode.OK; return new MemoryStream(Encoding.UTF8.GetBytes(helloString)); } JavaScript: function testSelfHost_WCFService_post_Parameter() { var xmlString = "<helloString>'hello via Post'</helloString>"; Ajax_sendData("hello/post2", xmlString); } function Ajax_sendData(url, data) { var request = false; request = getHTTPObject(); if (request) { request.onreadystatechange = function() { parseResponse(request); }; request.open("post", url, true); request.setRequestHeader("Content-Type", "text/xml; charset=utf-8"); charset=utf-8"); request.send(data); return true; } } function getHTTPObject() { var xhr = false; if (window.XMLHttpRequest) { xhr = new XMLHttpRequest(); } else if (window.ActiveXObject) {...} }

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  • jQuery DataTables: Problems with POST Server Side JSON output

    - by Tim
    Hello Everyone, I am trying to get my datatable to take a POST JSON output from my server. This is my client side code <script> $(document).ready(function() { $('#example').dataTable( { "bProcessing": true, "bServerSide": true, "sAjaxSource": "http://localhost/staff/jobs/my_jobs", "fnServerData": function ( sSource, aoData, fnCallback ) { $.ajax( { "dataType": 'json', "type": "POST", "url": sSource, "data": aoData, "success": fnCallback } ); } } ); } ); </script> Now I have copied and pasted the server side code found in the DataTables examples found here. When I change my sAjaxSource to view this page the table doesn't move beyond 'processing'. When I view the JSON directly I see this output. {"sEcho": 1, "iTotalRecords": 1, "iTotalDisplayRecords": 1, "aaData": [ ["Trident","First Ever Job"]] } Just for fun I went to the POST server-side example and copied some of the JSON they are using for their example and just PHP echoed it straight out of another page. This is the output of that page. {"sEcho": 1, "iTotalRecords": 1, "iTotalDisplayRecords": 1, "aaData": [ ["Trident","Internet Explorer 4.0"]] } Here is where it gets interesting. The JSON that has been processed by the server fails to work yet the JSON simply echo'd by the same server on a different page does work... yet both are almost identical in outputs. I hope someone can shed some light on this because as the tree said to the lumberjack... I'm stumped. Thanks, Tim

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  • jQuery, PHP, AJAX, "tu" variable beeing posted for no reason, shows in var_dump()

    - by Mattis
    A jQuery AJAX request .post()s data to page.php, which creates $res and var_dump()s it. $res: $res = array(); foreach ($_REQUEST as $key => $value) { if($key){ $res[$key] = $value; } } var_dump($res): array(4) { ["text1"]=> string(6) "mattis" ["text2"]=> string(4) "test" ["tu"]=> string(32) "deb6adbbff4234b5711cc4368c153bc4" ["PHPSESSID"]=> string(32) "cda24363cb9d3226bd37b2577ed0bc0b" } My javascript only sends text1 and text2: $.post("page.php",{ text1:"mattis", text2:"test" } What is the "tu" variable beeing sent? Apparantly it's very similar to the session id, but I've never seen it before. EDIT: It is sent in IE but not in FF.

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  • Http Requests POST vs GET

    - by behrk2
    Hi everyone, I am using a lot of HTTP Requests in an application that I am writing which uses OAuth. Currently, I am sending my GET and POST requests the same way: HttpConnection connection = (HttpConnection) Connector.open(url + connectionParameters); connection.setRequestMethod(method); connection.setRequestProperty("WWW-Authenticate", "OAuth realm=api.netflix.com"); int responseCode = connection.getResponseCode(); And this is working fine. I am successfully POSTing and GETing. However, I am worried that I am not doing POST the right way. Do I need to include in the above code the following if-statement? if (method.equals("POST") && postData != null) { connection.setRequestProperty("Content-type", "application/x-www-form-urlencoded"); connection.setRequestProperty("Content-Length", Integer .toString(postData.length)); OutputStream requestOutput = connection.openOutputStream(); requestOutput.write(postData); requestOutput.close(); } If so, why? What's the difference? I would appreciate any feedback. Thanks!

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  • Java: Handling cookies when logging in with POST

    - by Cris Carter
    I'm having quite some trouble logging in to any site in Java. I'm using the default URLconnection POST request, but I'm unsure how to handle the cookies properly. I tried this guide: http://www.hccp.org/java-net-cookie-how-to.html But couldn't get it working. I've been trying basically for days now, and I really need help if anyone wants to help me. I'll probably be told that it's messy and that I should use a custom library meant for this stuff. I tried downloading one, but wasn't sure how to get it set up and working. I've been trying various things for hours now, and it just won't work. I'd rather do this with a standard URLconnection, but if anyone can help me get another library working that's better for this, that would be great, too. I would really appreciate if someone could post a working source that I could study. What I need is: POST login data to site - Get and store the cookie from the site - use cookie with next URLconnection requests to get logged-in version of the site. Can anyone help me with this? Would be EXTREMELY appreciated. It really does mean a lot. If anyone wants to actually help me out live, please leave an instant-messenger address. Thank you a lot for your time.

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  • Using PHP to store results of a post request

    - by Paul M
    Im currently working with an API which requires we send our collection details in xml to their server using a post request. Nothing major there but its not working, so I want to output the sent xml to a txt file so I can look at actually whats being sent!! Instead of posting to the API im posting to a document called target, but the xml its outputting its recording seems to be really wrong. Here is my target script, note that the posting script posts 3 items, so the file being written should have details of each post request one after the other. <?php error_reporting(E_ALL); ini_set('display_errors', 1); // get the request data... $payload = ''; $fp = fopen('php://input','r'); $output_file = fopen('output.txt', 'w'); while (!feof($fp)) { $payload .= fgets($fp); fwrite($output_file, $payload); } fclose($fp); fclose($output_file); ?> I also tried the following, but this just recorded the last post request so only 1 collection item was recorded in the txt file, instead of all 3 output_file = fopen('output.txt', 'w'); while (!feof($fp)) { $payload .= fgets($fp); } fwrite($output_file, $payload); fclose($fp); fclose($output_file); I know im missing something really obvious, but ive been looking at this all morning!

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  • Retrieve Flash file post in ASP.NET

    - by Quandary
    Question: In ASP.NET, I retrieve a JPEG-file as Flash post data like this Sub ProcessRequest(ByVal context As HttpContext) Implements IHttpHandler.ProcessRequest context.Response.ContentType = "text/plain" ' Retrieve a bytearray from the post buffer Dim myBuffer As Byte() = context.Request.BinaryRead(Convert.ToInt32(context.Request.InputStream.Length)) System.IO.File.WriteAllBytes("c:\temp\test.jpg", myBuffer) End Sub In Flash, I send it to an asp.net handler like this var jpgSource:BitmapData = cPrint.TakeSnapshot(MovieClip(cGlobals.ccPlanZoomView)); var bmpThisBitmap:Bitmap = new Bitmap(jpgSource); var nQuality:Number = 100; var jpgEncoder:JPGEncoder = new JPGEncoder(nQuality); var jpgStream:ByteArray = jpgEncoder.encode(jpgSource); var header:URLRequestHeader = new URLRequestHeader ("Content-type", "application/octet-stream"); // Make sure to use the correct path to jpg_encoder_download.php var strFileName:String="test.jpg"; var jpgURLRequest:URLRequest = new URLRequest("http://localhost/raumplaner_new/raumplaner_new/cgi-bin/SavePDF.ashx"); //var scriptVars:URLVariables = new URLVariables(); //scriptVars.fn = strFileName; //var myarr:Array= new Array(); //myarr.push(jpgStream); //scriptVars.Files = myarr; jpgURLRequest.requestHeaders.push(header); jpgURLRequest.method = URLRequestMethod.POST; //jpgURLRequest.data = scriptVars; jpgURLRequest.data = jpgStream; var loader:URLLoader = new URLLoader(); loader.dataFormat = URLLoaderDataFormat.BINARY; loader.load(jpgURLRequest); It works but I want to send a few additional variables along, via scriptVars (commented out here). How do I retrieve the JPEG file in that case ? Because if I use parameters, there is no more BinaryRead... Aspecially, how would I read an array of jpeg files (several files) ?

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  • delphi post 'illegal access' error

    - by paul
    hello all im making some delphi simple software which using Idhttp module in indy. i want to access ' http://mybuddy.buddybuddy.co.kr/userinfo/UserInfo.asp ' this page by use idhttp's post function. to open this webpage firstly have to login(http://user.buddybuddy.co.kr/Login/Login.asp), so i was logged in but problem is after logged in webpage i can see another login page but when try to login(http://user.buddybuddy.co.kr/usercheck/UserCheckPWExec.asp) , i encountered some error message 'illegal access'. if anyone help me much appreciate! begin sl.Clear; sl.Add('ID=ph896011'); sl.add('PWD=pk1089'); sl.add('SECCHK=0'); IdHTTP1.HandleRedirects := True; IdHTTP1.Request.ContentType := 'application/x-www-form-urlencoded'; memo1.Text:=idhttp1.Post('http://user.buddybuddy.co.kr/Login/Login.asp',sl); if pos('top.location =',Memo1.Text)> 0 then begin application.ProcessMessages; sleep(1000); Memo1.Text:= ''; sleep(300); sl2.Clear; sl2.Add('PASSWD=pk1089' ); Memo2.Text := IdHTTP1.Post('http://user.buddybuddy.co.kr/usercheck/UserCheckPWExec.asp', sl2); result.Caption := 'login success' ; sleep(300); Memo1.Text := ''; //memo1.Text := IdHTTP1.Get('https://user.buddybuddy.co.kr/Login/Logout.asp'); //Sleep(1000); end;

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  • JQuery Post-Request question - FF doesn't get the result of the referenced php page

    - by OlliD
    Dear community, I just want to have my question posted here but just from the beginning: For a personal web project I use PHP + JQuery. Now I got stuck when I try to use the ajax posting method to send data to another php-page. I planned to have some navigational elements like next + previous on the bottom of the page by saving the user input / user given data. The code looks as follows: <div id="bottom_nav"> <div id="prev" class="flt_l"><a href="?&step=<?= $pages[$step-1] ?>">next</a></div> <div id="next" class="flt_r"><a href="?&step=<?= $pages[$step+1] ?>">previous</a></div> </div> The functionality of the page works fine. Lateron, I use the following code to sent data over via POST: $("#bottom_nav a").click( function() { alert("POST-Link: Parameter=" + $("#Parameter").val()); $.ajax( { type:"post", url:"saveParameter.php", data:"Parameter=" + $("#Parameter").val(), success: function(result) { alert(result); //$("#test").text(result); } }); }); The request itself work perfectly on IE, but on FF I'm not able to get back any result. within the PHP page, there just written: <? echo $_POST['Parameter']; ?> As IE returns the correct value, FF just provide an empty message box. I assumed that the behaviour on the -Link is different. While IE seems to handle the click event after the JS-Code execution, FF will interpret it before. My question was whether you has a solution on this regarding restructuring the code itself or using another method to reach the intened behaviour. Thanks for your assistance and recommendations, Olli

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  • Java : HTTP POST Request

    - by SpunkerBaba
    I have to do a http post request to a web-service for authenticating the user with username and password. The Web-service guy gave me following information to construct HTTP Post request. POST /login/dologin HTTP/1.1 Host: webservice.companyname.com Content-Type: application/x-www-form-urlencoded Content-Length: 48 id=username&num=password&remember=on&output=xml The XML Response that i will be getting is <?xml version="1.0" encoding="ISO-8859-1"?> <login> <message><![CDATA[]]></message> <status><![CDATA[true]]></status> <Rlo><![CDATA[Username]]></Rlo> <Rsc><![CDATA[9L99PK1KGKSkfMbcsxvkF0S0UoldJ0SU]]></Rsc> <Rm><![CDATA[b59031b85bb127661105765722cd3531==AO1YjN5QDM5ITM]]></Rm> <Rl><![CDATA[[email protected]]]></Rl> <uid><![CDATA[3539145]]></uid> <Rmu><![CDATA[f8e8917f7964d4cc7c4c4226f060e3ea]]></Rmu> </login> This is what i am doing HttpPost postRequest = new HttpPost(urlString); How do i construct the rest of the parameters?

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  • Rails 3 get raw post data and write it to tmp file

    - by Andrew
    I'm working on implementing Ajax-Upload for uploading photos in my Rails 3 app. The documentation says: For IE6-8, Opera, older versions of other browsers you get the file as you normally do with regular form-base uploads. For browsers which upload file with progress bar, you will need to get the raw post data and write it to the file. So, how can I receive the raw post data in my controller and write it to a tmp file so my controller can then process it? (In my case the controller is doing some image manipulation and saving to S3.) Some additional info: As I'm configured right now the post is passing these parameters: Parameters: {"authenticity_token"=>"...", "qqfile"=>"IMG_0064.jpg"} ... and the CREATE action looks like this: def create @attachment = Attachment.new @attachment.user = current_user @attachment.file = params[:qqfile] if @attachment.save! respond_to do |format| format.js { render :text => '{"success":true}' } end end end ... but I get this error: ActiveRecord::RecordInvalid (Validation failed: File file name must be set.): app/controllers/attachments_controller.rb:7:in `create'

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  • security deleting a mysql row with jQuery $.post

    - by FFish
    I want to delete a row in my database and found an example on how to do this with jQuery's $.post() Now I am wondering about security though.. Can someone send a POST request to my delete-row.php script from another website? JS function deleterow(id) { // alert(typeof(id)); // number if (confirm('Are you sure want to delete?')) { $.post('delete-row.php', {album_id:+id, ajax:'true'}, function() { $("#row_"+id).fadeOut("slow"); }); } } PHP: delete-row.php <?php require_once("../db.php"); mysql_connect(DB_SERVER, DB_USER, DB_PASSWORD) or die("could not connect to database " . mysql_error()); mysql_select_db(DB_NAME) or die("could not select database " . mysql_error()); if (isset($_POST['album_id'])) { $query = "DELETE FROM albums WHERE album_id = " . $_POST['album_id']; $result = mysql_query($query); if (!$result) die('Invalid query: ' . mysql_error()); echo "album deleted!"; } ?>

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  • How to cache an HTTP POST response?

    - by KARASZI István
    I would like to create a cacheable HTTP response for a POST request. My actual implementation responses the following for the POST request: HTTP/1.1 201 Created Expires: Sat, 03 Oct 2020 15:33:00 GMT Cache-Control: private,max-age=315360000,no-transform Content-Type: application/x-www-form-urlencoded; charset=UTF-8 Content-Length: 9 ETag: 2120507660800737950 Last-Modified: Wed, 06 Oct 2010 15:33:00 GMT ......... But it looks like that the browsers (Safari, Firefox tested) are not cacheing the response. In the HTTP RFC the corresponding part says: Responses to this method are not cacheable, unless the response includes appropriate Cache-Control or Expires header fields. However, the 303 (See Other) response can be used to direct the user agent to retrieve a cacheable resource. So I think it should be cached. I know I could set a session variable and set a cookie and do a 303 redirect, but I want to cache the response of the POST request. Is there any way to do this? P.S.: I've started with a simple 200 OK, so it does not work. Thanks,

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  • Which CMS do I need? Needs to be easy to post a certain kind of post

    - by Vian Esterhuizen
    Hi, I'm creating a site for a video store and it needs to be CMS. I'm doing this for free so I need to use a free CMS like Wordpress, Drupal or Joomla. Do I need a new CMS, a plugin or some PHP of my own? What I need: User accounts Categories Custom post Here's the site as it stands with WP: http://sundancevideo.ca. Right now an experimental site to try to work this out. What I've done now, is created a "Draft" that includes a template table with images and text and so on. The user would then have to copy everything, past into a new post and replace necessary. This really isn't working well. As you may notice by the condition of the posts. What I would prefer is if it was integrated into the WP UI. Like a field for "Description" and field for "Image" where they can upload the images as necessary. This would then generate post, with a table including all the information and images, for as many movies that were added in the UI. Please ask if I'm not being clear. Please help, any suggestions are welcome. Thank you, Vian

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  • Why qry.post executed with asynchronous mode?

    - by Ryan
    Recently I met a strange problem, see code snips as below: var sqlCommand: string; connection: TADOConnection; qry: TADOQuery; begin connection := TADOConnection.Create(nil); try connection.ConnectionString := 'Provider=Microsoft.Jet.OLEDB.4.0;Data Source=Test.MDB;Persist Security Info=False'; connection.Open(); qry := TADOQuery.Create(nil); try qry.Connection := connection; qry.SQL.Text := 'Select * from aaa'; qry.Open; qry.Append; qry.FieldByName('TestField1').AsString := 'test'; qry.Post; beep; finally qry.Free; end; finally connection.Free; end; end; First, Create a new access database named test.mdb and put it under the directory of this test project, we can create a new table named aaa in it which has only one text type field named TestField1. We set a breakpoint at line of "beep", then lunch the test application under ide debug mode, when ide stops at the breakpoint line (qry.post has been executed), at this time we use microsoft access to open test.mdb and open table aaa you will find there are no any changes in table aaa, if you let the ide continue running after pressing f9 you can find a new record is inserted in to table aaa, but if you press ctrl+f2 to terminate the application at the breakpoint, you will find the table aaa has no record been inserted, but in normal circumstance, a new record should be inserted in to the table aaa after qry.post executed. who can explain this problem , it troubles me so long time. thanks !!! BTW, the ide is delphi 2010, and the access mdb file is created by microsoft access 2007 under windows 7

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  • How to post to a request using node.js

    - by Mr JSON
    I am trying to post some json to a URL. I saw various other questions about this on stackoverflow but none of them seemed to be clear or work. This is how far I got, I modified the example on the api docs: var http = require('http'); var google = http.createClient(80, 'server'); var request = google.request('POST', '/get_stuff', {'host': 'sever', 'content-type': 'application/json'}); request.write(JSON.stringify(some_json),encoding='utf8'); //possibly need to escape as well? request.end(); request.on('response', function (response) { console.log('STATUS: ' + response.statusCode); console.log('HEADERS: ' + JSON.stringify(response.headers)); response.setEncoding('utf8'); response.on('data', function (chunk) { console.log('BODY: ' + chunk); }); }); When I post this to the server I get an error telling me that it's not of the json format or that it's not utf8, which they should be. I tried to pull the request url but it is null. I am just starting with nodejs so please be nice.

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  • Submit form with POST data in Android app

    - by datguywhowanders
    I've been searching the web for a way to do this for about a week now, and I just can't seem to figure it out. I'm trying to implement an app that my college can use to allow users to log in to various services on the campus with ease. The way it works currently is they go to an online portal, select which service they want, fill in their user name and pwd, and click login. The form data is sent via post (it includes several hidden values as well as just the user name and pwd) to the corresponding login script which then signs them in and loads the service. I've been trying to come at the problem in two ways. I first tried a WebView, but it doesn't seem to want to support all of the html that normally makes this form work. I get all of the elements I need, fields for user and pwd as well as a login button, but clicking the button doesn't do anything. I wondered if I needed to add an onclick handler for it, but I can't see how as the button is implemented in the html of the webview not using a separate android element. The other possibility was using the xml widgets to create the form in a nice relative layout, which seems to load faster and looks better on the android screen. I used EditText fields for the input, a spinner widget for the service select, and the button widget for the login. I know how to make the onclick and item select handlers for the button and spinner, respectively, but I can't figure out how to send that data via POST in an intent that would then launch a browser. I can do an intent with the action url, but can't get the POST data to feed into it. Anyone have any suggestions?

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  • window.open on load page (asp.net) using Method=POST

    - by Raul
    i need open pop up in asp.net using post Method and window.open to rezise te new windows. my code: ---- open the pop up --- function mdpbch(URL) { child = window.open(URL, "passwd","dependent=1,toolbar=0,location=0,directories=0,status=0,menubar=0,scrollbars=1,resizable=1,width=600,height=475"); child.location.href = URL; if (child.opener == null) { child.opener = window; } child.opener.name = "opener"; } -------- URL --- function PagoEnLinea(Banco) { switch(x){ case "BCH": document.frmEnvia.action = SERV + "/llamacom.asp"; url = SERV + "lamacom.asp alert(url); mdpbch(url); document.frmEnvia.submit(); break; } } -------ASPX-------------------- <body> <form id="frmEnvia" runat="server" name="formulario" method="post" target="_blank"> <div style="visibility:hidden;"> <asp:TextBox ID="txtXml" runat="server" Visible="true"></asp:TextBox> </div> ..... </body> on page load (code behind) i create a xml string and put it in the textbox txtXml. i need use post method becose the server validate te method, and window.open becose need customize the pop up thanks

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  • send post data in jsf

    - by milostrivun
    I just cannot figure this out, it looks really simple but I'm relatively new at jsf. Here is the old stuff: Plain old html form tag like this: <form name="someForm" action="somewhere" method="post"> <input name="param1"/> <input name="param2" /> </form That is sending data by post to a location specified in the action attribute of the form. The new stuff: <h:form id="paymentForm"> <h:panelGroup> <h:inputText id="param1" value="#{facesView.param1}" ></h:inputText> <h:inputText id="param1" value="#{facesView.param2}" ></h:inputText> <h:panelGroup> <h:commandLink>Submit</h:commandLink> </h:panelGroup> </h:form> This other new stuff doesn't work. 1.How do I specify to this h:form where to go(like setting action in old html) because I need it to go to a totally new url. 2.how to pass params with POST? Any help is appreciated. Milos

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  • XMLHttpRequest POST Data Size

    - by usurper
    Hi, Is there a size limit to a XHR POST request? I am using the POST method for saving textdata into MySQL using PHP script and the data is cut off. Firebug sends me the following message: ... Firebug request size limit has been reached by Firebug. ... This is my code for sending the data: function makeXHR(recordData) { xmlhttp = createXHR(); var body = "q=" + encodeURIComponent(recordData); xmlhttp.open("POST", "insertRowData.php", true); xmlhttp.setRequestHeader("Content-Type", "application/x-www-form-urlencoded"); xmlhttp.setRequestHeader("Content-length", body.length); xmlhttp.setRequestHeader("Connection", "close"); xmlhttp.onreadystatechange = function() { if(xmlhttp.readyState == 4 && xmlhttp.status == 200) { //alert(xmlhttp.responseText); alert("Records were saved successfully!"); } } xmlhttp.send(body); } The only solution I can think of is splitting the data and making a queue of XHR requests but I don't like it. Is there another way?

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  • Change post categories while saving post

    - by fuunnews
    Hi everybody, I'm trying to change post categories inside a save_post action callback function, but I get endless recursion, because wp_update_post method fires save_post action itself. Maybe somebody did this before& Or there is a way to change post categories without using wp_update_post method?

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  • TortoiseSVN commit shortcut

    - by Patrick
    I find it tedious when everytime I need to commit a file.The process goto windows explorer window, right click directory, then click 'Commit'... and then the tortoisesvn commit window. Anyone know of any shortcut to do this? Maybe press a keyboard shortcut to commit instead of having to right click directory then click commit? Thank you for saving my productivity!

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  • Post data to aspx page from iphone application

    - by Dipen
    Hi, I am developing a application. In which i am posting a image to .aspx page.The HTML for the page is as below. <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd>"> <html xmlns="http://www.w3.org/1999/xhtml>"> <head><title> Untitled Page </title><link href="App_Themes/XXX/XXX.css" type="text/css" rel="stylesheet" /></head> <body> <form name="form1" method="post" action="Default16.aspx" id="form1" enctype="multipart/form-data"> <div> <input type="hidden" name="__VIEWSTATE" id="__VIEWSTATE" value="/wEPDwUKLTQwMjY2MDA0Mw9kFgICAw8WAh4HZW5jdHlwZQUTbXVsdGlwYXJ0L2Zvcm0tZGF0YWRktr+hG1VVXZsO01PCyj61d6Ulqy8=" /> </div> <div> <div style="float:left;margin:10px"> <input type="file" name="fuImage" id="fuImage" /> </div> <div style="float:right"> <input type="submit" name="btnPost" value="Post Image" id="btnPost" /> </div> </div> </form> </body> </html> Now i am sending a request from my application then i am getting " Error Domain=kCFErrorDomainCFNetwork Code=303 UserInfo=0xf541c0 "Operation could not be completed. (kCFErrorDomainCFNetwork error 303.)"" I have tried using SynchronousRequest and aSynchronousRequest but both are not working. I have also used apple sample code. Here is the code for iPhone app UIImage *image=[UIImage imageNamed:@"photo2.jpg"]; NSData *imageData = UIImageJPEGRepresentation(image, 90); NSString *urlString = @"http://XXXXXXXX.com/Post.aspx"; NSMutableURLRequest *request = [[[NSMutableURLRequest alloc] init] autorelease]; [request setURL:[NSURL URLWithString:urlString]]; [request setHTTPMethod:@"POST"]; NSString *boundary = [NSString stringWithString:@"----WebKitFormBoundarylU9pAl5wPrF+Tk52"]; NSString *contentType = [NSString stringWithFormat:@"multipart/form-data; boundary=%@", boundary]; [request addValue:contentType forHTTPHeaderField:@"Content-Type"]; NSMutableData *body = [NSMutableData data]; [body appendData:[[NSString stringWithFormat:@"\r\n--%@\r\n", boundary] dataUsingEncoding:NSUTF8StringEncoding]]; [body appendData:[[NSString stringWithString:@"Content-Disposition: form-data; name=\"fuimage\"; filename=\"asd.jpg\"\r\n"] dataUsingEncoding:NSUTF8StringEncoding]]; [body appendData:[[NSString stringWithString:@"Content-Type: image/jpeg\r\n\r\n"] dataUsingEncoding:NSUTF8StringEncoding]]; [body appendData:[NSData dataWithData:imageData]]; [body appendData:[[NSString stringWithFormat:@"\r\n--%@--\r\n", boundary] dataUsingEncoding:NSUTF8StringEncoding]]; [request setHTTPBody:body]; // NSData *returnData = [NSURLConnection sendSynchronousRequest:request returningResponse:nil error:nil]; // NSString *returnString = [[NSString alloc] initWithData:returnData encoding:NSUTF8StringEncoding]; // NSLog(returnString); NSURLConnection *theConnection = [[NSURLConnection alloc] initWithRequest:request delegate:self]; if( theConnection ) { webData = [[NSMutableData data] retain]; } else { NSLog(@"theConnection is NULL"); } Thanks in Advance.

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