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  • VIM Replace word with contents of paste buffer?

    - by plong
    I need to do a bunch of word replacements in a file and want to do it with a vi command, not an EX command such as :%s///g. I know that this is the typical way one replaces the word at the current cursor position: cw<text><esc> but is there a way to do this with the contents of the unnamed register as the replacement text and without overwriting the register?

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  • Replace a whole line in a txt file

    - by user302935
    I'am new to Python 3 and could really use a little help. I have a txt file containing: InstallPrompt= DisplayLicense= FinishMessage= TargetName=D:\somewhere FriendlyName=something I have a python script that in the end, should change just two lines to: TargetName=D:\new FriendlyName=Big Could anyone help me, please? I have tried to search for it, but I didnt find something I could use. The text that should be replaced could have different length.

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  • Replace non-html links with <A> tags

    - by tombazza
    I have a block of code that will take a block of text like the following: Sample text sample text http://www.google.com sample text Using the preg_replace_callback method and the following regular expression: preg_replace_callback('/http:\/\/([,\%\w.\-_\/\?\=\+\&\~\#\$]+)/', create_function( '$matches', '$url = $matches[1]; $anchorText = ( strlen($url) > 35 ? substr($url, 0, 35).\'...\' : $url); return \'<a href="http://\'. $url .\'">\'. $anchorText .\'</a>\';'), $str); Will convert the sample text to look like: Sample text sample text < a href="http://www.google.com"http://www.google.com< /a sample text My problem now is that we have introduced a rich text editor that can create links before being sent to the script. I need to update this piece of code so that it will ignore any URLs that are already inside an tag.

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  • Get div and the correct close tag preg

    - by Barkermn01
    hi all, Now preg has always been a tool to me that i like but i cant figure out for the life if me if what i want to do is possible let and how to do it is going over my head What i want is preg_match to be able to return me a div's innerHTML the problem is the div im tring to read has more divs in it and my preg keeps closing on the first tag it find Here is my Actual code $scrape_address = "http://isohunt.com/torrent_details/133831593/98e034bd6382e0f4ecaa9fe2b5eac01614edc3c6?tab=summary"; $ch = curl_init($scrape_address); curl_setopt ($ch, CURLOPT_RETURNTRANSFER, '1'); curl_setopt($ch, CURLOPT_HEADER, 0); curl_setopt($ch, CURLOPT_ENCODING, ""); $data = curl_exec($ch); preg_match('% <div id="torrent_details">(.*)</div> %six', $data, $match); print_r($match); This has been updated for TomcatExodus's help Live at :: http://megatorrentz.com/beta/details.php?hash=98e034bd6382e0f4ecaa9fe2b5eac01614edc3c6

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  • C# Regex - Replace multiple characters at once without overwriting?

    - by Everaldo Aguiar
    Hello guys, I'm implementing a c# program that should automatize a Mono-alphabetic substitution cipher. The functionality i'm working on at the moment is the simplest one: The user will provide a plain text and a cipher alphabet, for example: Plain text(input): THIS IS A TEST Cipher alphabet: A - Y, H - Z, I - K, S - L, E - J, T - Q Cipher Text(output): QZKL KL QJLQ I thought of using regular expressions since I've been programming in perl for a while, but I'm encountering some problems on c#. First I would like to know if someone would have a suggestion for a regular expression that would replace all occurrence of each letter by its corresponding cipher letter (provided by user) at once and without overwriting anything. Example: In this case, user provides plaintext "TEST", and on his cipher alphabet, he wishes to have all his T's replaced with E's, E's replaced with Y and S replaced with J. My first thought was to substitute each occurrence of a letter with an individual character and then replace that character by the cipherletter corresponding to the plaintext letter provided. Using the same example word "TEST", the steps taken by the program to provide an answer would be: 1 - replace T's with (lets say) @ 2 - replace E's with # 3 - replace S's with & 4 - Replace @ with E, # with Y, & with j 5 - Output = EYJE This solution doesn't seem to work for large texts. I would like to know if anyone can think of a single regular expression that would allow me to replace each letter in a given text by its corresponding letter in a 26-letter cipher alphabet without the need of splitting the task in an intermediate step as I mentioned. If it helps visualize the process, this is a print screen of my GUI for the program: http://img43.imageshack.us/img43/2118/11618743.jpg

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  • .NET Regex - Replace multiple characters at once without overwriting?

    - by Everaldo Aguiar
    I'm implementing a c# program that should automatize a Mono-alphabetic substitution cipher. The functionality i'm working on at the moment is the simplest one: The user will provide a plain text and a cipher alphabet, for example: Plain text(input): THIS IS A TEST Cipher alphabet: A - Y, H - Z, I - K, S - L, E - J, T - Q Cipher Text(output): QZKL KL QJLQ I thought of using regular expressions since I've been programming in perl for a while, but I'm encountering some problems on c#. First I would like to know if someone would have a suggestion for a regular expression that would replace all occurrence of each letter by its corresponding cipher letter (provided by user) at once and without overwriting anything. Example: In this case, user provides plaintext "TEST", and on his cipher alphabet, he wishes to have all his T's replaced with E's, E's replaced with Y and S replaced with J. My first thought was to substitute each occurrence of a letter with an individual character and then replace that character by the cipherletter corresponding to the plaintext letter provided. Using the same example word "TEST", the steps taken by the program to provide an answer would be: 1 - replace T's with (lets say) @ 2 - replace E's with # 3 - replace S's with & 4 - Replace @ with E, # with Y, & with j 5 - Output = EYJE This solution doesn't seem to work for large texts. I would like to know if anyone can think of a single regular expression that would allow me to replace each letter in a given text by its corresponding letter in a 26-letter cipher alphabet without the need of splitting the task in an intermediate step as I mentioned. If it helps visualize the process, this is a print screen of my GUI for the program:

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  • C# Find and Replace a section of a string with wildcard type search using RegEx (while retaining som

    - by fraXis
    Hello, I am trying to replace some text in a string with different text while retaining some of the text and I am having trouble doing it. My code is: StreamReader reader = new StreamReader(fDialog.FileName.ToString()); string content = reader.ReadToEnd(); reader.Close(); /Replace M2 with M3 (this works fine) content = Regex.Replace(content, "M2", "M3"); I want to replace a string that contains this: Z0.1G0H1E1 and turn it into: G54G43Z.1H1M08 (Note the Z value and the H value contain the same numeric value before the text change) The trouble I am having is that when I replace the values, I need to retain the H value and the Z value from the first set of text. For example, Z0.5G0H5E1 I need to add the new text, but also add the H5 and Z0.5 back into the text such as: G54G43Z0.5H5M08 But the Z values and H values will be different every time, so I need to capture those values and reinsert them back into the string when add the new G54G43 values. Can someone please show me how to do this using Regex.Replace? Thanks so much, Shawn

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  • Is there a find and replace application with multiple rules?

    - by Joe
    I'm looking for a search and replace tool that takes a list of rules and either a file (or directory) and runs those rules on the files. I have a bunch of different things that need to be changed in many files, and I'd like to be able to run all the rules in one shot. I was hoping I could put the rules separate file, and use the same set of rules over and over again. Does such a tool exist?

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  • ereg to preg conversion

    - by musoNic80
    I'm a complete novice when it comes to regex. Could someone help me convert the following expression to preg? ereg('[a-zA-Z0-9]+[[:punct:]]+', $password) An explanation to accompany any solution would be especially useful!!!!

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  • preg match count matches

    - by Scarface
    Hey guys quick question, I have a preg match statement, and it checks for matches, but I was wondering how you can count the matches. Any advice appreciated. $message='[tag] [tag]'; preg_match('/\[tag]\b/i',$message); for example a count of this message string should lead to 2 matches

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  • in tcl, how do I replace a line in a file?

    - by n00b programmer
    let's say I opened a file, then parsed it into lines. Then I use a loop: foreach line $lines {} inside the loop, for some lines, I want to replace them inside the file with different lines. Is it possible? Or do I have to write to another temporary file, then replace the files when I'm done? e.g., if the file contained AA BB and then I replace capital letters with lower case letters, I want the original file to contain aa bb Thanks!

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  • How to replace part of an input value in jquery?

    - by WonderBugger
    I've been trying to figure out a way to replace part of a string in an input value, but haven't been able to get it working. the input field looks like this: <input type="text" value="20,54,26,99" name="ids" /> I've tried: $('input[name=ids]').val().replace("54,",""); and var replit = $('input[name=ids]').val(); replit.replace("54,",""); $('input[name=ids]').val(replit); but neither worked?

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  • R: How to replace elements of a data.frame?

    - by John
    I'm trying to replace elements of a data.frame containing "#N/A" with "NULL", and I'm running into problems: foo <- data.frame("day"= c(1, 3, 5, 7), "od" = c(0.1, "#N/A", 0.4, 0.8)) indices_of_NAs <- which(foo == "#N/A") replace(foo, indices_of_NAs, "NULL") Error in [<-.data.frame(*tmp*, list, value = "NULL") : new columns would leave holes after existing columns I think that the problem is that my index is treating the data.frame as a vector, but that the replace function is treating it differently somehow, but I'm not sure what the issue is?

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  • Visual Studio 2010 Find and Replace With Regular Expressions

    - by Lance Robinson
    Here is a quick notes about using regular expressions in the VS2010 Find Replace dialog.  1.  To create a backreference, use curly braces (“{“ and “}” ) instead of regular parentheses. 2.  To use the captured backreference, use \1\2 etc, where \1 is the first captured value, \2 is the second captured value, etc. Example: I want to find*: info.setFieldValue(param1, param2); and replace it with: SetFieldValue(info, param1, param2); To do this, I can use the following find/replace values: Find what: {[a-zA-Z0-9]+}.setFieldValue\({[a-zA-Z0-9., ]+}\); Replace with: SetFieldValue(\1, \2); Use Regular Expressions is checked, of course. *If you’re wondering why I’d want to do this – because I don’t have control over the setFieldValue function – its in a third party library that doesn’t behave in a very friendly manner. Technorati Tags: Visual Studio,Regular Expressions

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  • I want to replace a number with successive numbers, starting at 1 and going up.

    - by Pär-Magnus Green
    I'm aware that this is something people can easily program, but I'm not familiar with those things, so I was hoping there was an easier solution. I've edited a large database of questions, including sorting, and ended up getting all the question ID's mixed up. I'm trying to do this in Notepad++, but any other suggestions are welcome. I'm wondering if there's a way to search for a string (ex. "Question[any number]") and replace the numbers with first 1, then 2, et.c. For clarification, this is how one question looks like: TriviaBot_Questions[3]['Question'][63] = "Acronyms: What does WTT stand for?"; TriviaBot_Questions[3]['Answers'][63] = {"Want To Trade"}; TriviaBot_Questions[3]['Category'][63] = 7; TriviaBot_Questions[3]['Points'][63] = 1; TriviaBot_Questions[3]['Hints'][63] = {}; and the next question, as is now, is not followed by 64. It might be 245 or 1029, and regardless of which number it is, I want it replaced with "previous number + 1", basically.

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  • Mysql replace() function, help with query (what chars do I escape?)

    - by jyoseph
    I am trying to update an old cms where images were stored in /images/editor/, they are now stored in a bucket on amazon s3. I'm trying to update the database using mysql replace. I've done this in the past with replacing simple words, but now Mysql is reporting an error, I suspect because this is more than a simple word: UPDATE contents SET desc = replace(desc, '/images/editor/', 'http://s3.amazonaws.com/my_bucket/editor/') Do I need to escape the : or slashes? I've tried escaping it with a '\' to no avail. Can someone get me pointed in the right direction? Thanks! Edit Here's the error I am getting, nothing too telling error : You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'desc = replace(desc, '/images/editor', 'http://s3.amazonaws.com/app_navigator/ed' at line 1

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  • Regular expressions in a Python find-and-replace script?

    - by Haidon
    I'm new to Python scripting, so please forgive me in advance if the answer to this question seems inherently obvious. I'm trying to put together a large-scale find-and-replace script using Python. I'm using code similar to the following: findreplace = [ ('term1', 'term2'), ] inF = open(infile,'rb') s=unicode(inF.read(),charenc) inF.close() for couple in findreplace: outtext=s.replace(couple[0],couple[1]) s=outtext outF = open(outFile,'wb') outF.write(outtext.encode('utf-8')) outF.close() How would I go about having the script do a find and replace for regular expressions? Specifically, I want it to find some information (metadata) specified at the top of a text file. Eg: Title: This is the title Author: This is the author Date: This is the date and convert it into LaTeX format. Eg: \title{This is the title} \author{This is the author} \date{This is the date} Maybe I'm tackling this the wrong way. If there's a better way than regular expressions please let me know! Thanks!

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  • Helper method to Replace/Remove characters that do not match the Regular Expression

    - by Michael Freidgeim
    I have a few fields, that use regEx for validation. In case if provided field has unaccepted characters, I don't want to reject the whole field, as most of validators do, but just remove invalid characters. I am expecting to keep only Character Classes for allowed characters and created a helper method to strip unaccepted characters. The allowed pattern should be in Regex format, expect them wrapped in square brackets. function will insert a tilde after opening squere bracket , according to http://stackoverflow.com/questions/4460290/replace-chars-if-not-match.  [^ ] at the start of a character class negates it - it matches characters not in the class.I anticipate that it could work not for all RegEx describing valid characters sets,but it works for relatively simple sets, that we are using.         /// <summary>               /// Replaces  not expected characters.               /// </summary>               /// <param name="text"> The text.</param>               /// <param name="allowedPattern"> The allowed pattern in Regex format, expect them wrapped in brackets</param>               /// <param name="replacement"> The replacement.</param>               /// <returns></returns>               /// //        http://stackoverflow.com/questions/4460290/replace-chars-if-not-match.               //http://stackoverflow.com/questions/6154426/replace-remove-characters-that-do-not-match-the-regular-expression-net               //[^ ] at the start of a character class negates it - it matches characters not in the class.               //Replace/Remove characters that do not match the Regular Expression               static public string ReplaceNotExpectedCharacters( this string text, string allowedPattern,string replacement )              {                     allowedPattern = allowedPattern.StripBrackets( "[", "]" );                      //[^ ] at the start of a character class negates it - it matches characters not in the class.                      var result = Regex .Replace(text, @"[^" + allowedPattern + "]", replacement);                      return result;              }static public string RemoveNonAlphanumericCharacters( this string text)              {                      var result = text.ReplaceNotExpectedCharacters(NonAlphaNumericCharacters, "" );                      return result;              }        public const string NonAlphaNumericCharacters = "[a-zA-Z0-9]";There are a couple of functions from my StringHelper class  http://geekswithblogs.net/mnf/archive/2006/07/13/84942.aspx , that are used here.    //                           /// <summary>               /// 'StripBrackets checks that starts from sStart and ends with sEnd (case sensitive).               ///           'If yes, than removes sStart and sEnd.               ///           'Otherwise returns full string unchanges               ///           'See also MidBetween               /// </summary>               /// <param name="str"></param>               /// <param name="sStart"></param>               /// <param name="sEnd"></param>               /// <returns></returns>               public static string StripBrackets( this string str, string sStart, string sEnd)              {                      if (CheckBrackets(str, sStart, sEnd))                     {                           str = str.Substring(sStart.Length, (str.Length - sStart.Length) - sEnd.Length);                     }                      return str;              }               public static bool CheckBrackets( string str, string sStart, string sEnd)              {                      bool flag1 = (str != null ) && (str.StartsWith(sStart) && str.EndsWith(sEnd));                      return flag1;              }               public static string WrapBrackets( string str, string sStartBracket, string sEndBracket)              {                      StringBuilder builder1 = new StringBuilder(sStartBracket);                     builder1.Append(str);                     builder1.Append(sEndBracket);                      return builder1.ToString();              }v

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  • Warning: preg_match() [function.preg-match]: Unknown modifier '/' problem

    - by SonOfOmer
    I am building custom implementation of php MVC routing engine, and I have custom routes like one in $routes array below. Each time when I send asynchronous GET request like xmlhttp.open("GET","someurl"); I get following message Warning: preg_match() [function.preg-match]: Unknown modifier '/' problem but with synchronous (normal) request it all works fine <?php $routes = array( array('url' => '/^someurl$/', 'controller' => 'somecontroller', 'view' => 'someview') ); $url = $_SERVER['REQUEST_URI']; $url = substr( $url, 1 ); $params = array(); $route_match = false; foreach($routes as $urls => $route) { if(preg_match($route['url'], $url, $matches)) { $params = array_merge($params, $matches); $route_match = true; break; } } require_once(CONTROLLER_PATH.$route['controller'].'.php'); ?> string(11) "/^someurl$/" is the result of var_dump($route['url']); Thanks.

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