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  • C# Regex - Replace multiple characters at once without overwriting?

    - by Everaldo Aguiar
    Hello guys, I'm implementing a c# program that should automatize a Mono-alphabetic substitution cipher. The functionality i'm working on at the moment is the simplest one: The user will provide a plain text and a cipher alphabet, for example: Plain text(input): THIS IS A TEST Cipher alphabet: A - Y, H - Z, I - K, S - L, E - J, T - Q Cipher Text(output): QZKL KL QJLQ I thought of using regular expressions since I've been programming in perl for a while, but I'm encountering some problems on c#. First I would like to know if someone would have a suggestion for a regular expression that would replace all occurrence of each letter by its corresponding cipher letter (provided by user) at once and without overwriting anything. Example: In this case, user provides plaintext "TEST", and on his cipher alphabet, he wishes to have all his T's replaced with E's, E's replaced with Y and S replaced with J. My first thought was to substitute each occurrence of a letter with an individual character and then replace that character by the cipherletter corresponding to the plaintext letter provided. Using the same example word "TEST", the steps taken by the program to provide an answer would be: 1 - replace T's with (lets say) @ 2 - replace E's with # 3 - replace S's with & 4 - Replace @ with E, # with Y, & with j 5 - Output = EYJE This solution doesn't seem to work for large texts. I would like to know if anyone can think of a single regular expression that would allow me to replace each letter in a given text by its corresponding letter in a 26-letter cipher alphabet without the need of splitting the task in an intermediate step as I mentioned. If it helps visualize the process, this is a print screen of my GUI for the program: http://img43.imageshack.us/img43/2118/11618743.jpg

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  • .NET Regex - Replace multiple characters at once without overwriting?

    - by Everaldo Aguiar
    I'm implementing a c# program that should automatize a Mono-alphabetic substitution cipher. The functionality i'm working on at the moment is the simplest one: The user will provide a plain text and a cipher alphabet, for example: Plain text(input): THIS IS A TEST Cipher alphabet: A - Y, H - Z, I - K, S - L, E - J, T - Q Cipher Text(output): QZKL KL QJLQ I thought of using regular expressions since I've been programming in perl for a while, but I'm encountering some problems on c#. First I would like to know if someone would have a suggestion for a regular expression that would replace all occurrence of each letter by its corresponding cipher letter (provided by user) at once and without overwriting anything. Example: In this case, user provides plaintext "TEST", and on his cipher alphabet, he wishes to have all his T's replaced with E's, E's replaced with Y and S replaced with J. My first thought was to substitute each occurrence of a letter with an individual character and then replace that character by the cipherletter corresponding to the plaintext letter provided. Using the same example word "TEST", the steps taken by the program to provide an answer would be: 1 - replace T's with (lets say) @ 2 - replace E's with # 3 - replace S's with & 4 - Replace @ with E, # with Y, & with j 5 - Output = EYJE This solution doesn't seem to work for large texts. I would like to know if anyone can think of a single regular expression that would allow me to replace each letter in a given text by its corresponding letter in a 26-letter cipher alphabet without the need of splitting the task in an intermediate step as I mentioned. If it helps visualize the process, this is a print screen of my GUI for the program:

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  • Python proper use of __str__ and __repr__

    - by Peter
    Hey, My current project requires extensive use of bit fields. I found a simple, functional recipe for bit a field class but it was lacking a few features I needed, so I decided to extend it. I've just got to implementing __str__ and __repr__ and I want to make sure I'm following convention. __str__ is supposed to be informal and concice, so I've made it return the bit field's decimal value (i.e. str(bit field 11) would be "3". __repr__ is supposed to be a official representation of the object, so I've made it return the actual bit string (i.e. repr(bit field 11) would be "11"). In your opinion would this implementation meet the conventions for str and repr? Additionally, I have used the bin() function to get the bit string of the value stored in the class. This isn't compatible with Python < 2.6, is there an alternative method? Cheers, Pete

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  • C# Find and Replace a section of a string with wildcard type search using RegEx (while retaining som

    - by fraXis
    Hello, I am trying to replace some text in a string with different text while retaining some of the text and I am having trouble doing it. My code is: StreamReader reader = new StreamReader(fDialog.FileName.ToString()); string content = reader.ReadToEnd(); reader.Close(); /Replace M2 with M3 (this works fine) content = Regex.Replace(content, "M2", "M3"); I want to replace a string that contains this: Z0.1G0H1E1 and turn it into: G54G43Z.1H1M08 (Note the Z value and the H value contain the same numeric value before the text change) The trouble I am having is that when I replace the values, I need to retain the H value and the Z value from the first set of text. For example, Z0.5G0H5E1 I need to add the new text, but also add the H5 and Z0.5 back into the text such as: G54G43Z0.5H5M08 But the Z values and H values will be different every time, so I need to capture those values and reinsert them back into the string when add the new G54G43 values. Can someone please show me how to do this using Regex.Replace? Thanks so much, Shawn

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  • Is there a find and replace application with multiple rules?

    - by Joe
    I'm looking for a search and replace tool that takes a list of rules and either a file (or directory) and runs those rules on the files. I have a bunch of different things that need to be changed in many files, and I'd like to be able to run all the rules in one shot. I was hoping I could put the rules separate file, and use the same set of rules over and over again. Does such a tool exist?

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  • str is not callable error in python .

    - by mekasperasky
    import sys import md5 from TOSSIM import * from RadioCountMsg import * t = Tossim([]) #The Tossim object is defined here m = t.mac()#The mac layer is defined here , in which the communication takes place r = t.radio()#The radio communication link object is defined here , as the communication needs Rf frequency to transfer t.addChannel("RadioCountToLedsC", sys.stdout)# The various channels through which communication will take place t.addChannel("LedsC", sys.stdout) #The no of nodes that would be required in the simulation has to be entered here print("enter the no of nodes you want ") n=input() for i in range(0, n): m = t.getNode(i) m.bootAtTime((31 + t.ticksPerSecond() / 10) * i + 1) #The booting time is defined so that the time at which the node would be booted is given f = open("topo.txt", "r") #The topography is defined in topo.txt so that the RF frequencies of the transmission between nodes are are set lines = f.readlines() for line in lines: s = line.split() if (len(s) > 0): if (s[0] == "gain"): r.add(int(s[1]), int(s[2]), float(s[3])) #The topogrography is added to the radio object noise = open("meyer-heavy.txt", "r") #The noise model is defined for the nodes lines = noise.readlines() for line in lines: str = line.strip() if (str != ""): val = int(str) for i in range(0, 4): t.getNode(i).addNoiseTraceReading(val) for i in range (0, n): t.getNode(i).createNoiseModel() #The noise model is created for each node for i in range(0,n): t.runNextEvent() fk=open("key.txt","w") for i in range(0,n): if i ==0 : key=raw_input() fk.write(key) ak=key key=md5.new() key.update(str(ak)) ak=key.digest() fk.write(ak) fk.close() fk=open("key.txt","w") plaint=open("pt.txt") for i in range(0,n): msg = RadioCountMsg() msg.set_counter(7) pkt = t.newPacket()#A packet is defined according to a certain format print("enter message to be transported") ms=raw_input()#The message to be transported is taken as input #The RC5 encryption has to be done here plaint.write(ms) pkt.setData(msg.data) pkt.setType(msg.get_amType()) pkt.setDestination(i+1)#The destination to which the packet will be sent is set print "Delivering " + " to" ,i+1 pkt.deliver(i+1, t.time() + 3) fk.close() print "the key to be displayed" ki=raw_input() fk=open("key.txt") for i in range(0,n): if i==ki: ms=fk.readline() for i in range(0,n): msg=RadioCountMsg() msg.set_counter(7) pkt=t.newPacket() msg.data=ms pkt.setData(msg.data) pkt.setType(msg.get_amType()) pkt.setDestination(i+1) pkt.deliver(i+1,t.time()+3) #The key has to be broadcasted here so that the decryption can take place for i in range(0, n): t.runNextEvent(); this code gives me error here key.update(str(ak)) . when i run a similar code on the python terminal there is no such error but this code pops up an error . why so?

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  • please help me to find Bug in my Code (segmentation fault)

    - by Vikramaditya Battina
    i am tring to solve this http://www.spoj.com/problems/LEXISORT/ question it working fine in visual studio compiler and IDEone also but when i running in SPOJ compiler it is getting SEGSIGV error Here my code goes #include<stdio.h> #include<stdlib.h> #include<string.h> char *getString(); void lexisort(char **str,int num); void countsort(char **str,int i,int num); int main() { int num_test; int num_strings; char **str; int i,j; scanf("%d",&num_test); for(i=0;i<num_test;i++) { scanf("%d",&num_strings); str=(char **)malloc(sizeof(char *)*num_strings); for(j=0;j<num_strings;j++) { str[j]=(char *)malloc(sizeof(char)*11); scanf("%s",str[j]); } lexisort(str,num_strings); for(j=0;j<num_strings;j++) { printf("%s\n",str[j]); free(str[j]); } free(str); } return 0; } void lexisort(char **str,int num) { int i; for(i=9;i>=0;i--) { countsort(str,i,num); } } void countsort(char **str,int i,int num) { int buff[52]={0,0},k,x; char **temp=(char **)malloc(sizeof(char *)*num); for(k=0;k<52;k++) { buff[k]=0; } for(k=0;k<num;k++) { if(str[k][i]>='A' && str[k][i]<='Z') { buff[(str[k][i]-'A')]++; } else { buff[26+(str[k][i]-'a')]++; } } for(k=1;k<52;k++) { buff[k]=buff[k]+buff[k-1]; } for(k=num-1;k>=0;k--) { if(str[k][i]>='A' && str[k][i]<='Z') { x=buff[(str[k][i]-'A')]; temp[x-1]=str[k]; buff[(str[k][i]-'A')]--; } else { x=buff[26+(str[k][i]-'a')]; temp[x-1]=str[k]; buff[26+(str[k][i]-'a')]--; } } for(k=0;k<num;k++) { str[k]=temp[k]; } free(temp); }

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  • in tcl, how do I replace a line in a file?

    - by n00b programmer
    let's say I opened a file, then parsed it into lines. Then I use a loop: foreach line $lines {} inside the loop, for some lines, I want to replace them inside the file with different lines. Is it possible? Or do I have to write to another temporary file, then replace the files when I'm done? e.g., if the file contained AA BB and then I replace capital letters with lower case letters, I want the original file to contain aa bb Thanks!

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  • How to replace part of an input value in jquery?

    - by WonderBugger
    I've been trying to figure out a way to replace part of a string in an input value, but haven't been able to get it working. the input field looks like this: <input type="text" value="20,54,26,99" name="ids" /> I've tried: $('input[name=ids]').val().replace("54,",""); and var replit = $('input[name=ids]').val(); replit.replace("54,",""); $('input[name=ids]').val(replit); but neither worked?

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  • R: How to replace elements of a data.frame?

    - by John
    I'm trying to replace elements of a data.frame containing "#N/A" with "NULL", and I'm running into problems: foo <- data.frame("day"= c(1, 3, 5, 7), "od" = c(0.1, "#N/A", 0.4, 0.8)) indices_of_NAs <- which(foo == "#N/A") replace(foo, indices_of_NAs, "NULL") Error in [<-.data.frame(*tmp*, list, value = "NULL") : new columns would leave holes after existing columns I think that the problem is that my index is treating the data.frame as a vector, but that the replace function is treating it differently somehow, but I'm not sure what the issue is?

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  • Visual Studio 2010 Find and Replace With Regular Expressions

    - by Lance Robinson
    Here is a quick notes about using regular expressions in the VS2010 Find Replace dialog.  1.  To create a backreference, use curly braces (“{“ and “}” ) instead of regular parentheses. 2.  To use the captured backreference, use \1\2 etc, where \1 is the first captured value, \2 is the second captured value, etc. Example: I want to find*: info.setFieldValue(param1, param2); and replace it with: SetFieldValue(info, param1, param2); To do this, I can use the following find/replace values: Find what: {[a-zA-Z0-9]+}.setFieldValue\({[a-zA-Z0-9., ]+}\); Replace with: SetFieldValue(\1, \2); Use Regular Expressions is checked, of course. *If you’re wondering why I’d want to do this – because I don’t have control over the setFieldValue function – its in a third party library that doesn’t behave in a very friendly manner. Technorati Tags: Visual Studio,Regular Expressions

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  • Given a string of letters from alphabet insert frequency of each character in the string.in O(n) time and O(1) space [on hold]

    - by learner
    Below is my attempt void str_freq(char *str, int len) { char c; int cnt=0; c=str[0]; int i,j=0; for(i=0;i<len;i++) { if(c==str[i]) { cnt++; } else { c = str[i]; // printf(" %d ",cnt); str[j] = str[i-1]; str[j+1] = (char)(((int)'0')+cnt); j++; cnt=0; } } str[j+1]='\0'; printf("%s",str); } int main() { char str[] = "aaabbccccdeffgggg"; int length=strlen(str); str_freq(str,length); } I am getting wrong answer abcdef1 instead of a3b2c4d1e1f2g4. Please let me know where I am going wrong.

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  • I want to replace a number with successive numbers, starting at 1 and going up.

    - by Pär-Magnus Green
    I'm aware that this is something people can easily program, but I'm not familiar with those things, so I was hoping there was an easier solution. I've edited a large database of questions, including sorting, and ended up getting all the question ID's mixed up. I'm trying to do this in Notepad++, but any other suggestions are welcome. I'm wondering if there's a way to search for a string (ex. "Question[any number]") and replace the numbers with first 1, then 2, et.c. For clarification, this is how one question looks like: TriviaBot_Questions[3]['Question'][63] = "Acronyms: What does WTT stand for?"; TriviaBot_Questions[3]['Answers'][63] = {"Want To Trade"}; TriviaBot_Questions[3]['Category'][63] = 7; TriviaBot_Questions[3]['Points'][63] = 1; TriviaBot_Questions[3]['Hints'][63] = {}; and the next question, as is now, is not followed by 64. It might be 245 or 1029, and regardless of which number it is, I want it replaced with "previous number + 1", basically.

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  • JS. How to replace html element with another element/text, represented in string?

    - by EL 2002
    I have a problem with replacing html elements. For example, there is a table <table><tr><td id="idTABLE">0</td><td>END</td></tr></table> (it can be div, span, anything) And string in JS script var str='<td>1</td><td>2</td>'; (it can be anything, '123 text', '<span123 element</span 456' or ' <tr<td123</td ' or anything) How can I replace element 'idTABLE' with str? I mean really replace, so <table><tr><td id="__TABLE__">0</td><td>END</td></tr></table> becomes <table><tr><td>1</td><td>2</td><td>END</td></tr></table> //str='<td>1</td><td>2</td>'; <table><tr>123 text<td>END</td></tr></table> //'123 text' <table><tr> tr><td>123</td> <td>END</td></tr></table> //' <tr><td>123</td> ' I tried with createElement, replaceChild, cloneNode, but with no result at all =(

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  • Mysql replace() function, help with query (what chars do I escape?)

    - by jyoseph
    I am trying to update an old cms where images were stored in /images/editor/, they are now stored in a bucket on amazon s3. I'm trying to update the database using mysql replace. I've done this in the past with replacing simple words, but now Mysql is reporting an error, I suspect because this is more than a simple word: UPDATE contents SET desc = replace(desc, '/images/editor/', 'http://s3.amazonaws.com/my_bucket/editor/') Do I need to escape the : or slashes? I've tried escaping it with a '\' to no avail. Can someone get me pointed in the right direction? Thanks! Edit Here's the error I am getting, nothing too telling error : You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'desc = replace(desc, '/images/editor', 'http://s3.amazonaws.com/app_navigator/ed' at line 1

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  • Regular expressions in a Python find-and-replace script?

    - by Haidon
    I'm new to Python scripting, so please forgive me in advance if the answer to this question seems inherently obvious. I'm trying to put together a large-scale find-and-replace script using Python. I'm using code similar to the following: findreplace = [ ('term1', 'term2'), ] inF = open(infile,'rb') s=unicode(inF.read(),charenc) inF.close() for couple in findreplace: outtext=s.replace(couple[0],couple[1]) s=outtext outF = open(outFile,'wb') outF.write(outtext.encode('utf-8')) outF.close() How would I go about having the script do a find and replace for regular expressions? Specifically, I want it to find some information (metadata) specified at the top of a text file. Eg: Title: This is the title Author: This is the author Date: This is the date and convert it into LaTeX format. Eg: \title{This is the title} \author{This is the author} \date{This is the date} Maybe I'm tackling this the wrong way. If there's a better way than regular expressions please let me know! Thanks!

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  • JSF, writeAttribute("value", str, null) fails with strings obtained through ValueExpression.getValue

    - by Roma
    Hello, I'm having a somewhat weird problem with custom JSF component. Here's my renderer code: public class Test extends Renderer { public void encodeBegin(final FacesContext context, final UIComponent component) throws IOException { ResponseWriter writer = context.getResponseWriter(); writer.startElement("textarea", component); String clientId = component.getClientId(context); if (clientId != null) writer.writeAttribute("name", clientId, null); ValueExpression exp = component.getValueExpression("value"); if (exp != null && exp.getValue(context.getELContext()) != null) { String val = (String) exp.getValue(context.getELContext()); System.out.println("Value: " + val); writer.writeAttribute("value", val, null); } writer.endElement("textarea"); writer.flush(); } } The code generates: <textarea name="j_id2:j_id12:j_id19" value=""></textarea> Property binding contains "test" and as it should be, "Value: test" is successfully printed to console. Now, if I change the code to: public void encodeBegin(final FacesContext context, final UIComponent component) throws IOException { ResponseWriter writer = context.getResponseWriter(); writer.startElement("textarea", component); String clientId = component.getClientId(context); if (clientId != null) writer.writeAttribute("name", clientId, null); ValueExpression exp = component.getValueExpression("value"); if (exp != null && exp.getValue(context.getELContext()) != null) { String val = (String) exp.getValue(context.getELContext()); String str = "new string"; System.out.println("Value1: " + val + ", Value2: " + str); writer.writeAttribute("value", str, null); } writer.endElement("textarea"); writer.flush(); } generated html is: <textarea name="j_id2:j_id12:j_id19" value="new string"></textarea> and console output is "Value1: test, Value2: new string" What's going on here? This doesn't make sense. Why would writeAttribute differentiate between the two strings? Additional info: The component extends UIComponentBase I am using it with facelets

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  • Replacing words in string

    - by abkai
    Okay, so I have the following little function: def swap(inp): inp = inp.split() out = "" for item in inp: ind = inp.index(item) item = item.replace("i am", "you are") item = item.replace("you are", "I am") item = item.replace("i'm", "you're") item = item.replace("you're", "I'm") item = item.replace("my", "your") item = item.replace("your", "my") item = item.replace("you", "I") item = item.replace("my", "your") item = item.replace("i", "you") inp[ind] = item for item in inp: ind = inp.index(item) item = item + " " inp[ind] = item return out.join(inp) Which, while it's not particularly efficient gets the job done for shorter sentences. Basically, all it does is swaps pronoun etc. perspectives. This is fine when I throw a string like "I love you" at it, it returns "you love me" but when I throw something like: you love your version of my couch because I love you, and you're a couch-lover. I get: I love your versyouon of your couch because I love I, and I'm a couch-lover. I'm confused as to why this is happening. I explicitly split the string into a list to avoid this. Why would it be able to detect it as being a part of a list item, rather than just an exact match? Also, slightly deviating to avoid having to post another question so similar; if a solution to this breaks this function, what will happen to commas, full stops, other punctuation? It made some very surprising mistakes. My expected output is: I love my version of your couch because you love I, and I'm a couch-lover. The reason I formatted it like this, is because I eventually hope to be able to replace the item.replace(x, y) variables with words in a database.

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  • MacBook says to replace battery. Should I?

    - by Palantir
    Hi! My MacBook says that battery is not charging, and the battery is completely empty (in fact, pressing the button on the battery illuminates no LEDs). If I plug the power adapter off the mac shuts off immediately. I tried with a spare adapter, and it won't charge it. System information says it has 380 cycles. The battery is 2.5 years old. System profiler says the battery has 0 mAh of capacity, and that it should be replaced. Should I just buy a new battery, or should I bring it to an apple point, and leave it there? They can take a look at it (it's on AppleCare), they told me that they will repair it is there is anything wrong with the charging circuit, but they won't give me a new battery. They will keep the laptop for 10 working days at least... I hate when this happens :P

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  • Regex Search and Replace in Eclipse: How do I fix dangling meta character 'x'?

    - by Roger
    I am trying to replace function calls written when methods were nonstatic to an updated version were they are. For example: TABLE_foo(table1, ...rest is the same with table1.foo(...rest is the same This is what I have come up with using my limited understanding of regex and this site. find: TABLE_(*)\((*), replace: $2.$1( The above yields a dangling meta character '*' error. Does anyone know what I am doing wrong?

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  • C# How do I replace an actual asterisk character (*) in a Regex expression?

    - by fraXis
    Hello, I have a statement: I have a string such as content = "* test *" I want to search and replace it with so when I am done the string contains this: content = "(*) test (*)" My code is: content = Regex.Replace(content, "*", "(*)"); But this causes an error in C# because it thinks that the * is part of the Regular Expressions Syntax. How can I modify this code so it changes all asterisks in my string to (*) instead without causing a runtime error? Thanks.

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