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  • Setting LD_LIBRARY_PATH in Apache PassEnv/SetEnv still cant find library

    - by DoMoreASAP
    I am trying to test the Cybersource 3d party implementation. I was able to get the test files running fine from the command line, which requires that on Linux I export the path to the payment libraries to LD_LIBRARY_PATH. to try to test this on my server I have created the apache config below <VirtualHost 127.0.0.1:12345> AddHandler cgi-script .cgi AddHandler fcgid-script .php .fcgi FCGIWrapper /my/path/to/php_fcgi/bin/php-cgi .php AddType text/html .shtml AddOutputFilter INCLUDES .shtml DocumentRoot /my/path/to/cybersource/simapi-php-5.0.1/ ProxyPreserveHost on <Directory /my/path/to/cybersource/simapi-php-5.0.1> SetEnv LD_LIBRARY_PATH /my/path/to/cybersource/LinkedLibraries/lib/ AllowOverride all Options +Indexes IndexOptions Charset=UTF-8 </Directory> </VirtualHost> I have set the env variable there with SetEnv command, which seems to be working when i run a page that prints <?php phpinfo(); ?> however the test script when called through the browser still wont work, apache says: tail /my/apache/error_log [Tue Mar 30 23:11:46 2010] [notice] mod_fcgid: call /my/path/to/cybersource/index.php with wrapper /my/path/to/cybersource/php_fcgi/bin/php-cgi PHP Warning: PHP Startup: Unable to load dynamic library '/my/path/to/cybersource/extensionsdir/php5_cybersource.so' - libspapache.so: cannot open shared object file: No such file or directory in Unknown on line 0 so it cant find the linked file libspapache.so even though it is in the LD_LIBRARY_PATH that is supposedly defined i really appreciate the help. thanks so much.

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  • Why do I get completely different results when saving a BitmapSource to bmp, jpeg, and png in WPF

    - by DanM
    I wrote a little utility class that saves BitmapSource objects to image files. The image files can be either bmp, jpeg, or png. Here is the code: public class BitmapProcessor { public void SaveAsBmp(BitmapSource bitmapSource, string path) { Save(bitmapSource, path, new BmpBitmapEncoder()); } public void SaveAsJpg(BitmapSource bitmapSource, string path) { Save(bitmapSource, path, new JpegBitmapEncoder()); } public void SaveAsPng(BitmapSource bitmapSource, string path) { Save(bitmapSource, path, new PngBitmapEncoder()); } private void Save(BitmapSource bitmapSource, string path, BitmapEncoder encoder) { using (var stream = new FileStream(path, FileMode.Create)) { encoder.Frames.Add(BitmapFrame.Create(bitmapSource)); encoder.Save(stream); } } } Each of the three Save methods work, but I get unexpected results with bmp and jpeg. Png is the only format that produces an exact reproduction of what I see if I show the BitmapSource on screen using a WPF Image control. Here are the results: BMP - too dark JPEG - too saturated PNG - correct Why am I getting completely different results for different file types? I should note that the BitmapSource in my example uses an alpha value of 0.1 (which is why it appears very desaturated), but it should be possible to show the resulting colors in any image format. I know if I take a screen capture using something like HyperSnap, it will look correct regardless of what file type I save to. Here's a HyperSnap screen capture saved as a bmp: As you can see, this isn't a problem, so there's definitely something strange about WPF's image encoders. Do I have a setting wrong? Am I missing something?

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  • What is the most platform- and Python-version-independent way to make a fast loop for use in Python?

    - by Statto
    I'm writing a scientific application in Python with a very processor-intensive loop at its core. I would like to optimise this as far as possible, at minimum inconvenience to end users, who will probably use it as an uncompiled collection of Python scripts, and will be using Windows, Mac, and (mainly Ubuntu) Linux. It is currently written in Python with a dash of NumPy, and I've included the code below. Is there a solution which would be reasonably fast which would not require compilation? This would seem to be the easiest way to maintain platform-independence. If using something like Pyrex, which does require compilation, is there an easy way to bundle many modules and have Python choose between them depending on detected OS and Python version? Is there an easy way to build the collection of modules without needing access to every system with every version of Python? Does one method lend itself particularly to multi-processor optimisation? (If you're interested, the loop is to calculate the magnetic field at a given point inside a crystal by adding together the contributions of a large number of nearby magnetic ions, treated as tiny bar magnets. Basically, a massive sum of these.) # calculate_dipole # ------------------------- # calculate_dipole works out the dipole field at a given point within the crystal unit cell # --- # INPUT # mu = position at which to calculate the dipole field # r_i = array of atomic positions # mom_i = corresponding array of magnetic moments # --- # OUTPUT # B = the B-field at this point def calculate_dipole(mu, r_i, mom_i): relative = mu - r_i r_unit = unit_vectors(relative) #4pi / mu0 (at the front of the dipole eqn) A = 1e-7 #initalise dipole field B = zeros(3,float) for i in range(len(relative)): #work out the dipole field and add it to the estimate so far B += A*(3*dot(mom_i[i],r_unit[i])*r_unit[i] - mom_i[i]) / sqrt(dot(relative[i],relative[i]))**3 return B

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  • Trying to use a authlogic-connect as a plugin in place of gem - Server doesn't start

    - by Arkid
    I am trying to use Authlogic-connect as a plugin in Rails 3 in place of a gem. I have made an entry in the gemfile as gem "authlogic-connect", :require => "authlogic-connect", :path => "localgems" Now when I run the bundle install, it runs fine. When I try to start the server i get the error Could not find gem 'authlogic-connect (>= 0, runtime)' in source at localgems. Source does not contain any versions of 'authlogic-connect (>= 0, runtime)' Try running `bundle install`. I have placed the unzipped Gem renamed as authlogic-connect in the localgems folder. what is the problem? Here is what I get on using rails plugin install arkidmitra$ rails plugin install git://github.com/viatropos/authlogic-connect.git Usage: rails new APP_PATH [options] Options: [--skip-gemfile] # Don't create a Gemfile -d, [--database=DATABASE] # Preconfigure for selected database (options: mysql/oracle/postgresql/sqlite3/frontbase/ibm_db) # Default: sqlite3 -O, [--skip-active-record] # Skip Active Record files [--dev] # Setup the application with Gemfile pointing to your Rails checkout -J, [--skip-prototype] # Skip Prototype files -T, [--skip-test-unit] # Skip Test::Unit files -G, [--skip-git] # Skip Git ignores and keeps -r, [--ruby=PATH] # Path to the Ruby binary of your choice # Default: /System/Library/Frameworks/Ruby.framework/Versions/1.8/usr/bin/ruby -m, [--template=TEMPLATE] # Path to an application template (can be a filesystem path or URL) -b, [--builder=BUILDER] # Path to an application builder (can be a filesystem path or URL) [--edge] # Setup the application with Gemfile pointing to Rails repository Runtime options: -q, [--quiet] # Supress status output -s, [--skip] # Skip files that already exist -f, [--force] # Overwrite files that already exist -p, [--pretend] # Run but do not make any changes Rails options: -h, [--help] # Show this help message and quit -v, [--version] # Show Rails version number and quit Description: The 'rails new' command creates a new Rails application with a default directory structure and configuration at the path you specify. Example: rails new ~/Code/Ruby/weblog This generates a skeletal Rails installation in ~/Code/Ruby/weblog. See the README in the newly created application to get going.

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  • Use localeURL middleware with apache prefix

    - by Olivier R.
    Good morning everyone, I Got a question about localeURL usage. Everything works great for me with url like this : www.mysite.com/ If I type www.mysite.com/ in adress bar, it turns correctly in www.mysite.com/en/ for example. If I use the view change_locale, it's also all right (ie change www.mysite.com/en/ in www.mysite.com/fr/). But my application use apache as server, and use a prefix for the site, that gives url like this : www.mysite.com/prefix/ If I type www.mysite.com/prefix/ in the adress bar, the adress turns into www.mysite.com/en/ without prefix (so 404) I change code of view to manage our settings.SERVER_PREFIX value : def change_locale(request) : """ Redirect to a given url while changing the locale in the path The url and the locale code need to be specified in the request parameters. O. Rochaix; Taken from localeURL view, and tuned to manage : - SERVER_PREFIX from settings.py """ next = request.REQUEST.get('next', None) if not next: next = request.META.get('HTTP_REFERER', None) if not next: next = settings.SERVER_PREFIX + '/' next = urlsplit(next).path prefix = False if settings.SERVER_PREFIX!="" and next.startswith(settings.SERVER_PREFIX) : prefix = True next = "/" + next.lstrip(settings.SERVER_PREFIX) _, path = utils.strip_path (next) if request.method == 'POST': locale = request.POST.get('locale', None) if locale and check_for_language(locale): path = utils.locale_path(path, locale) if prefix : path = settings.SERVER_PREFIX + path response = http.HttpResponseRedirect(path) return response with this customized view, i'm able to correctly change language, but i'm not sure that's the right way of doing stuff. Is there any option on localeURL to manage prefix of apache ?

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  • Matching Regular Expression in Javascript and PHP problem...

    - by Frankie
    I can't figure out how to get the same result from my Javscript as I do from my PHP. In particular, Javascript always leaves out the backslashes. Please ignore the random forward and backslashes; I put them there so that I can cover my basis on a windows system or any other system. Output: Input String: "/root\wp-cont ent\@*%'i@$@%$&^(@#@''mage6.jpg:" /root\wp-content\image6.jpg (PHP Output) /rootwp-contentimage6.jpg (Javscript Output) I would appreciate any help! PHP: <?php $path ="/root\wp-cont ent\@*%'i@$@%$&^(@#@''mage6.jpg:"; $path = preg_replace("/[^a-zA-Z0-9\\\\\/\.-]/", "", $path); echo $path; ?> Javascript: <script type="text/javascript"> var path = "/root\wp-cont ent\@*%'i@$@%$&^(@#@''mage6.jpg:"; //exact same string as PHP var regx = /[^a-zA-Z0-9\.\/-]/g; path = path.replace(regx,""); document.write("<br>"+path); </script>

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  • django inner redirects

    - by Zayatzz
    Hello I have one project that in my own development computer (uses mod_wsgi to serve the project) caused no problems. In live server (uses mod_fastcgi) it generates 500 though. my url conf is like this: # -*- coding: utf-8 -*- from django.conf.urls.defaults import * # Uncomment the next two lines to enable the admin: from django.contrib import admin admin.autodiscover() urlpatterns = patterns('', url(r'^admin/', include(admin.site.urls)), url(r'^', include('jalka.game.urls')), ) and # -*- coding: utf-8 -*- from django.conf.urls.defaults import * from django.contrib.auth import views as auth_views urlpatterns = patterns('jalka.game.views', url(r'^$', view = 'front', name = 'front',), url(r'^ennusta/(?P<game_id>\d+)/$', view = 'ennusta', name = 'ennusta',), url(r'^login/$', auth_views.login, {'template_name': 'game/login.html'}, name='auth_login'), url(r'^logout/$', auth_views.logout, {'template_name': 'game/logout.html'}, name='auth_logout'), url(r'^arvuta/$', view = 'arvuta', name = 'arvuta',), ) and .htaccess is like that: Options +FollowSymLinks RewriteEngine on RewriteOptions MaxRedirects=10 # RewriteCond %{HTTP_HOST} . RewriteCond %{HTTP_HOST} ^www\.domain\.com RewriteRule (.*) http://domain.com/$1 [R=301,L] AddHandler fastcgi-script .fcgi RewriteCond %{HTTP_HOST} ^jalka\.domain\.com$ [NC] RewriteCond %{REQUEST_FILENAME} !-f RewriteRule ^(.*) cgi-bin/fifa2010.fcgi/$1 [QSA,L] RewriteCond %{HTTP_HOST} ^subdomain\.otherdomain\.eu$ [NC] RewriteCond %{REQUEST_FILENAME} !-f RewriteRule ^(.*) cgi-bin/django.fcgi/$1 [QSA,L] Notice, that i have also other project set up with same .htaccess and that one is running just fine with more complex urls and views fifa2010.fcgi: #!/usr/local/bin/python # -*- coding: utf-8 -*- import sys, os DOMAIN = "domain.com" APPNAME = "jalka" PREFIX = "/www/apache/domains/www.%s" % (DOMAIN,) # Add a custom Python path. sys.path.insert(0, os.path.join(PREFIX, "htdocs/django/Django-1.2.1")) sys.path.insert(0, os.path.join(PREFIX, "htdocs")) sys.path.insert(0, os.path.join(PREFIX, "htdocs/jalka")) # Switch to the directory of your project. (Optional.) os.chdir(os.path.join(PREFIX, "htdocs", APPNAME)) # Set the DJANGO_SETTINGS_MODULE environment variable. os.environ['DJANGO_SETTINGS_MODULE'] = "%s.settings" % (APPNAME,) from django.core.servers.fastcgi import runfastcgi runfastcgi(method="threaded", daemonize="false") Alan

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  • WCF done broke.

    - by SteveCav
    WCF is completely fouled up on my machine. I start a new sln in VS2008. Add a project (WCF Service Lib).Build the project (builds ok). debug the project -- it gets halfway through the progress bar and bombs out with the error below (real path changed to "my mex path" so codeproject doesn't think its spam). I'm assuming it's file permissions but don't know where to start. Any ideas?: Error: Cannot obtain Metadata from my mex path If this is a Windows (R) Communication Foundation service to which you have access, please check that you have enabled metadata publishing at the specified address. For help enabling metadata publishing, please refer to the MSDN documentation at somewhere unhelpful Exchange Error URI: my mex path Metadata contains a reference that cannot be resolved: 'my mex path'. Could not connect to my mex path. TCP error code 10061: No connection could be made because the target machine actively refused it 127.0.0.1:8731. Unable to connect to the remote server No connection could be made because the target machine actively refused it 127.0.0.1:8731HTTP GET Error URI: my mex path There was an error downloading 'my mex path'. Unable to connect to the remote server No connection could be made because the target machine actively refused it 127.0.0.1:8731

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  • Generate canonical / real URL based on base.href or location

    - by blueyed
    Is there a method/function to get the canonical / transformed URL, respecting any base.href setting of the page? I can get the base URL via (in jQuery) using $("base").attr("href") and I could use string methods to parse the URL meant to being made relative to this, but $("base").attr("href") has no host, path etc attributes (like window.location has) manually putting this together is rather tedious E.g., given a base.href of "http://example.com/foo/" and a relative URL "/bar.js", the result should be: "http://example.com/bar.js" If base.href is not present, the URL should be made relative to window.location. This should handle non-existing base.href (using location as base in this case). Is there a standard method available for this already? (I'm looking for this, since jQuery.getScript fails when using a relative URL like "/foo.js" and BASE tag is being used (FF3.6 makes an OPTIONS request, and nginx cannot handle this). When using the full URL (base.href.host + "/foo.js", it works).)

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  • django+mod_wsgi on virtualenv not working

    - by jwesonga
    I've just finished setting up a django app on virtualenv, deployment went smoothly using a fabric script, but now the .wsgi is not working, I've tried every variation on the internet but no luck. My .wsgi file is: import os import sys import django.core.handlers.wsgi # put the Django project on sys.path root_path = os.path.abspath(os.path.dirname(__file__) + '../') sys.path.insert(0, os.path.join(root_path, 'kcdf')) sys.path.insert(0, root_path) os.environ['DJANGO_SETTINGS_MODULE'] = 'kcdf.settings' application = django.core.handlers.wsgi.WSGIHandler() I keep getting the same error: [Sun Apr 18 12:44:30 2010] [error] [client 41.215.123.159] mod_wsgi (pid=16938): Exception occurred processing WSGI script '/home/kcdfweb/webapps/kcdf.web/releases/current/kcdf/apache/kcdf.wsgi'. [Sun Apr 18 12:44:30 2010] [error] [client 41.215.123.159] Traceback (most recent call last): [Sun Apr 18 12:44:30 2010] [error] [client 41.215.123.159] File "/usr/local/lib/python2.6/dist-packages/django/core/handlers/wsgi.py", line 230, in __call__ [Sun Apr 18 12:44:30 2010] [error] [client 41.215.123.159] self.load_middleware() [Sun Apr 18 12:44:30 2010] [error] [client 41.215.123.159] File "/usr/local/lib/python2.6/dist-packages/django/core/handlers/base.py", line 33, in load_middleware [Sun Apr 18 12:44:30 2010] [error] [client 41.215.123.159] for middleware_path in settings.MIDDLEWARE_CLASSES: [Sun Apr 18 12:44:30 2010] [error] [client 41.215.123.159] File "/usr/local/lib/python2.6/dist-packages/django/utils/functional.py", line 269, in __getattr__ [Sun Apr 18 12:44:30 2010] [error] [client 41.215.123.159] self._setup() [Sun Apr 18 12:44:30 2010] [error] [client 41.215.123.159] File "/usr/local/lib/python2.6/dist-packages/django/conf/__init__.py", line 40, in _setup [Sun Apr 18 12:44:30 2010] [error] [client 41.215.123.159] self._wrapped = Settings(settings_module) [Sun Apr 18 12:44:30 2010] [error] [client 41.215.123.159] File "/usr/local/lib/python2.6/dist-packages/django/conf/__init__.py", line 75, in __init__ [Sun Apr 18 12:44:30 2010] [error] [client 41.215.123.159] raise ImportError, "Could not import settings '%s' (Is it on sys.path? Does it have syntax errors?): %s" % (self.SETTINGS_MODULE, e) [Sun Apr 18 12:44:30 2010] [error] [client 41.215.123.159] ImportError: Could not import settings 'kcdf.settings' (Is it on sys.path? Does it have syntax errors?): No module named kcdf.settings my virtual environment is on /home/user/webapps/kcdfweb my app is /home/user/webapps/kcdf.web/releases/current/project_name my wsgi file home/user/webapps/kcdf.web/releases/current/project_name/apache/project_name.wsgi

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  • Have an unprivileged non-account user ssh into another box?

    - by Daniel Quinn
    I know how to get a user to ssh into another box with a key: ssh -l targetuser -i path/to/key targethost But what about non-account users like apache? As this user doesn't have a home directory to which it can write a .ssh directory, the whole thing keeps failing with: $ sudo -u apache ssh -o StrictHostKeyChecking=no -l targetuser -i path/to/key targethost Could not create directory '/var/www/.ssh'. Warning: Permanently added '<hostname>' (RSA) to the list of known hosts. Permission denied (publickey). I've tried variations using -o UserKnownHostsFile=/dev/null and setting $HOME to /dev/null and none of these have done the trick. I understand that sudo could probably fix this for me, but I'm trying to avoid having to require a manual server config since this code will be deployed on a number of different environments. Any ideas? Here's a few examples of what I've tried that don't work: $ sudo -u apache export HOME=path/to/apache/writable/dir/ ssh -o StrictHostKeyChecking=no -o UserKnownHostsFile=path/to/apache/writable/dir/.ssh/known_hosts -l deploy -i path/to/key targethost $ sudo -u apache ssh -o StrictHostKeyChecking=no -o UserKnownHostsFile=path/to/apache/writable/dir/.ssh/known_hosts -l deploy -i path/to/key targethost $ sudo -u apache ssh -o StrictHostKeyChecking=no -o UserKnownHostsFile=/dev/null -l deploy -i path/to/key targethost Eventually, I'll be using this solution to run rsync as the apache user.

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  • VBA: How go I get the total width from all controls in an MS-Access form?

    - by Stefan Åstrand
    Hi, This is probably very basic stuff, but please bear in mind I am completely new to these things. I am working on a procedure for my Access datasheet forms that will: Adjust the width of each column to fit content Sum the total width of all columns and subtract it from the size of the window's width Adjust the width of one of the columns to fit the remaining space This is the code that adjusts the width of each column to fit content (which works fine): Dim Ctrl As Control Dim Path As String Dim ClmWidth As Integer 'Adjust column width to fit content For Each Ctrl In Me.Controls If TypeOf Ctrl Is TextBox Then Path = Ctrl.Name Me(Path).ColumnWidth = -2 End If Next Ctrl How should I write the code so I get the total width of all columns? Thanks a lot! Stefan Solution This is the code that makes an Access datasheet go from this: To this: Sub AdjustColumnWidth(frm As Form, clm As String) On Error GoTo HandleError Dim intWindowWidth As Integer ' Window width property Dim ctrl As Control ' Control Dim intCtrlWidth As Integer ' Control width property Dim intCtrlSum As Integer ' Control width property sum Dim intCtrlAdj As Integer ' Control width property remaining after substracted intCtrSum 'Adjust column width to standard width For Each ctrl In frm.Controls If TypeOf ctrl Is TextBox Or TypeOf ctrl Is CheckBox Or TypeOf ctrl Is ComboBox Then Path = ctrl.Name frm(Path).ColumnWidth = 1500 End If Next ctrl 'Get total column width For Each ctrl In frm.Controls If TypeOf ctrl Is TextBox Or TypeOf ctrl Is CheckBox Or TypeOf ctrl Is ComboBox Then Path = ctrl.Name intCtrlWidth = frm(Path).ColumnWidth If Path <> clm Then intCtrlSum = intCtrlSum + intCtrlWidth End If End If Next ctrl 'Adjust column to fit window intWindowWidth = frm.WindowWidth - 270 intCtrlAdj = intWindowWidth - intCtrlSum frm.Width = intWindowWidth frm(clm).ColumnWidth = intCtrlAdj Debug.Print "Totalt (Ctrl): " & intCtrlSum Debug.Print "Totalt (Window): " & intWindowWidth Debug.Print "Totalt (Remaining): " & intCtrlAdj Debug.Print "clm : " & clm HandleError: GeneralErrorHandler Err.Number, Err.Description Exit Sub End Sub Code to call procedure: Private Sub Form_Load() Call AdjustColumnWidth(Me, "txtDescription") End Sub

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  • Background image help (Solved)

    - by J2
    thanks for help, ended up with this html{ position:relative; min-width:950px; height:100%; background:black url(images/GrassBG.png) repeat-y top center; font:13px "Lucida Grande",Helvetica,Arial,sans-serif; } body.main{ width:950px; margin:0 auto; position:relative; } is there any way when using a div for a background image- to limit the height to only the content displayed? im putting the background image in a div because i want it centered via position:relative but the image doesnt show up unless i put a height on the div, and thats not what i want because i dont want to be able to just scroll down to the bottom of the image where theres no content ive tried putting the background image on the body css but if the browser is less than the width of the image, it just throws it over to the left and you can only see half of it- is there no way to make the background position:relative on the body? sorry if that doesnt make sense < thanks why can you not use Position:relative; on the body?

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  • How to create a semi transparent window in WPF that allows mouse events to pass through

    - by RMK
    I am trying to create an effect similar to the Lights out /lights dim feature in Adobe Lightroom (http://www.youtube.com/watch?v=87hNd3vaENE) except in WPF. What I tried was to create another window over-top of my existing window, make it transparent and put a semi transparent Path geometry on it. But I want mouse events to be able to pass through this semi transparent window (on to windows below). This is a simplified version of what I have: <Window x:Class="LightsOut.MaskWindow" xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation" xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml" AllowsTransparency="True" WindowStyle="None" ShowInTaskbar="False" Topmost="True" Background="Transparent"> <Grid> <Button HorizontalAlignment="Left" Height="20" Width="60">click</Button> <Path IsHitTestVisible="False" Stroke="Black" Fill="Black" Opacity="0.3"> <Path.Data> <RectangleGeometry Rect="0,0,1000,1000 "/> </Path.Data> </Path> </Grid> The window is fully transparent, so on places where the Path doesn't cover, mouse events pass right through. So far so good. The IsHitTestvisible is set to false on the path object. So mouse events will pass through it to other controls on the same form (ie you can click on the Button, because it is on the same form). But mouse events wont pass through the Path object onto windows that are below it. Any ideas? Or better ways to solve this problem? Thanks.

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  • Baffled by differences between WPF BitmapEncoders

    - by DanM
    I wrote a little utility class that saves BitmapSource objects to image files. The image files can be either bmp, jpeg, or png. Here is the code: public class BitmapProcessor { public void SaveAsBmp(BitmapSource bitmapSource, string path) { Save(bitmapSource, path, new BmpBitmapEncoder()); } public void SaveAsJpg(BitmapSource bitmapSource, string path) { Save(bitmapSource, path, new JpegBitmapEncoder()); } public void SaveAsPng(BitmapSource bitmapSource, string path) { Save(bitmapSource, path, new PngBitmapEncoder()); } private void Save(BitmapSource bitmapSource, string path, BitmapEncoder encoder) { using (var stream = new FileStream(path, FileMode.Create)) { encoder.Frames.Add(BitmapFrame.Create(bitmapSource)); encoder.Save(stream); } } } Each of the three Save methods work, but I get unexpected results with bmp and jpeg. Png is the only format that produces an exact reproduction of what I see if I show the BitmapSource on screen using a WPF Image control. Here are the results: BMP - too dark JPEG - too saturated PNG - correct Why am I getting completely different results for different file types? I should note that the BitmapSource in my example uses an alpha value of 0.1 (which is why it appears very desaturated), but it should be possible to show the resulting colors in any image format. I know if I take a screen capture using something like HyperSnap, it will look correct regardless of what file type I save to. Here's a HyperSnap screen capture saved as a bmp: As you can see, this isn't a problem, so there's definitely something strange about WPF's image encoders. Do I have a setting wrong? Am I missing something?

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  • HttpPostedFile.SaveAs() throws UnauthorizedAccessException even though the file is saved?

    - by jrummell
    I have an aspx page with multiple FileUpload controls and one Upload button. In the click handler I save the files like this: string path = "..."; for (int i = 0; i < Request.Files.Count - 1; i++) { HttpPostedFile file = Request.Files[i]; string fileName = Path.GetFileName(file.FileName); string saveAsPath = Path.Combine(path, fileName); file.SaveAs(saveAsPath); } When file.SaveAs() is called, it throws: System.Web.HttpUnhandledException: Exception of type 'System.Web.HttpUnhandledException' was thrown. --- System.UnauthorizedAccessException: Access to the path '...' is denied. at System.IO.__Error.WinIOError(Int32 errorCode, String maybeFullPath) at System.IO.FileStream.Init(String path, FileMode mode, FileAccess access, Int32 rights, Boolean useRights, FileShare share, Int32 bufferSize, FileOptions options, SECURITY_ATTRIBUTES secAttrs, String msgPath, Boolean bFromProxy) at System.IO.FileStream..ctor(String path, FileMode mode, FileAccess access, FileShare share, Int32 bufferSize, FileOptions options, String msgPath, Boolean bFromProxy) at System.IO.FileStream..ctor(String path, FileMode mode) at System.Web.HttpPostedFile.SaveAs(String filename) at Belden.Web.Intranet.Iso.Complaints.AttachmentUploader.btnUpload_Click(Object sender, EventArgs e) at System.Web.UI.WebControls.Button.OnClick(EventArgs e) at System.Web.UI.WebControls.Button.RaisePostBackEvent(String eventArgument) at System.Web.UI.Page.RaisePostBackEvent(IPostBackEventHandler sourceControl, String eventArgument) at System.Web.UI.Page.ProcessRequestMain(Boolean includeStagesBeforeAsyncPoint, Boolean includeStagesAfterAsyncPoint) --- End of inner exception stack trace --- at System.Web.UI.Page.HandleError(Exception e) at System.Web.UI.Page.ProcessRequestMain(Boolean includeStagesBeforeAsyncPoint, Boolean includeStagesAfterAsyncPoint) at System.Web.UI.Page.ProcessRequest(Boolean includeStagesBeforeAsyncPoint, Boolean includeStagesAfterAsyncPoint) at System.Web.UI.Page.ProcessRequest() at System.Web.UI.Page.ProcessRequest(HttpContext context) at ASP.departments_iso_complaints_uploadfiles_aspx.ProcessRequest(HttpContext context) at System.Web.HttpApplication.CallHandlerExecutionStep.System.Web.HttpApplication.IExecutionStep.Execute() at System.Web.HttpApplication.ExecuteStep(IExecutionStep step, Boolean& completedSynchronously) Now here's the fun part. The file is saved correctly! So why is it throwing this exception?

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  • More efficient approach to XSLT for-each

    - by Paul
    I have an XSLT which takes a . delimted string and splits it into two fields for a SQL statement: <xsl:for-each select="tokenize(Path,'\.')"> <xsl:choose> <xsl:when test="position() = 1 and position() = last()">SITE = '<xsl:value-of select="."/>' AND PATH = ''</xsl:when> <xsl:when test="position() = 1 and position() != last()">SITE = '<xsl:value-of select="."/>' </xsl:when> <xsl:when test="position() = 2 and position() = last()">AND PATH = '<xsl:value-of select="."/>' </xsl:when> <xsl:when test="position() = 2">AND PATH = '<xsl:value-of select="."/></xsl:when> <xsl:when test="position() > 2 and position() != last()">.<xsl:value-of select="."/></xsl:when> <xsl:when test="position() > 2 and position() = last()">.<xsl:value-of select="."/>' </xsl:when> <xsl:otherwise>zxyarglfaux</xsl:otherwise> </xsl:choose> </xsl:for-each> The results are as follows: INPUT: North OUTPUT: SITE = 'North' AND PATH = '' INPUT: North.A OUTPUT: SITE = 'North' AND PATH = 'A' INPUT: North.A.B OUTPUT: SITE = 'North' AND PATH = 'A.B' INPUT: North.A.B.C OUTPUT: SITE = 'North' AND PATH = 'A.B.C' This works, but is very lengthy. Can anyone see a more efficient approach? Thanks!

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  • Segmentation fault

    - by darkie15
    #include<stdio.h> #include<zlib.h> #include<unistd.h> #include<string.h> int main(int argc, char *argv[]) { char *path=NULL; size_t size; int index ; printf("\nArgument count is = %d", argc); printf ("\nThe 0th argument to the file is %s", argv[0]); path = getcwd(path, size); printf("\nThe current working directory is = %s", path); if (argc <= 1) { printf("\nUsage: ./output filename1 filename2 ..."); } else if (argc > 1) { for (index = 1; index <= argc;index++) { printf("\n File name entered is = %s", argv[index]); strcat(path,argv[index]); printf("\n The complete path of the file name is = %s", path); } } return 0; } In the above code, here is the output that I get while running the code: $ ./output test.txt Argument count is = 2 The 0th argument to the file is ./output The current working directory is = /home/welcomeuser File name entered is = test.txt The complete path of the file name is = /home/welcomeusertest.txt Segmentation fault (core dumped) Can anyone please me understand why I am getting a core dumped error? Regards, darkie

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  • Failure to connect to admin share pops up dialog

    - by Jan
    I'm having an issue with a curious error message when accessing the administrative share on a remote machine. Specifically, the client is logged in as the domain administrator on the machine A, and runs some code that tries to access the admin share on B (a domain member). The access is done in .NET, along these lines (though I am not sure if the method of access makes a difference): string path = @"\\B\admin$"; if (Directory.Exists(path)) { try { path += @"\temp\"; if (!Directory.Exists(path)) { Directory.CreateDirectory(path); } path += "myfile_remote"; File.Copy("myfile", path); Now, on some machines this fails. That is not a big problem as we have a fallback. I'd like to know why but it is not the real issue. The problem is that running this piece of code causes a dialog box to pop up for the logged-in user on B, saying "network error trying to access \\B\admin$\temp\myfile_remote. Contact the network administrator and ask for the correct permissions". Unfortunately, it is a foreign language Windows so I'll spare you all posting a screenshot. It is skinned like a standard Windows dialog box. Why exactly is that dialog box popping up for the user and is there anything I can do about it? Edit to add: B is a Windows 7 Enterprise installation. The client is not aware of any GPO policies being installed. There is AV from Trend Micro installed.

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  • Open Select using Javascript/jQuery?

    - by Newbie
    Hello! Is there a way to open a select box using Javascript (and jQuery)? <select style="width:150px;"> <option value="1">1</option> <option value="2">Lorem ipsum dolor sit amet, consectetur adipiscing elit. Nunc arcu nunc, rhoncus ac dignissim at, rhoncus ac tellus.</option> <option value="3">3</option> </select> I have to open my select, cause of ie bug. All versions of IE (6,7,8) cut my options. As far as I know, there is no css bugfix for this. At the moment I try to do the following: var original_width = 0; var selected_val = false; if (jQuery.browser.msie) { $('select').click(function(){ if (selected_val == false){ if(original_width == 0) original_width = $(this).width(); $(this).css({ 'position' : 'absolute', 'width' : 'auto' }); }else{ $(this).css({ 'position' : 'relative', 'width' : original_width }); selected_val = false; } }); $('select').blur(function(){ $(this).css({ 'position' : 'relative', 'width' : original_width }); }); $('select').blur(function(){ $(this).css({ 'position' : 'relative', 'width' : original_width }); }); $('select').change(function(){ $(this).css({ 'position' : 'relative', 'width' : original_width }); }); $('select option').click(function(){ $(this).css({ 'position' : 'relative', 'width' : original_width }); selected_val = true; }); } But clicking on my select the first time will change the width of the select but I have to click again to open it.

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  • What is the space character for the browser?

    - by Hiro Protagonist
    echo "\n\s\s\s\s\s\s" . "<div id='data-load' data-load='" . $load . "'></div>"; \n works for adding a return in...I tried \s logically for space but this does not work. Keep mind, I don't want this rendered in the browser view...but in the source view ( when you click view-source )...I'm trying to put my html in to a readable form. echo "&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp\n" . "<div id='data-path' data-path='" . $path . "'></div>"; This does not work either. I am composing HTML from PHP... echo " \n" . "<div id='data-load' data-load='" . $load . "'></div>"; This does not work either. Actual Code: public static function setUniversals() { $shared_object = new Shared(); if ( $shared_object->getLoadOn() == 1 ) { $load = 'server'; } else { $load = 'client'; } if( getcwd() === '/home/foo/public_html/develop' ) { $path = 'development'; } else { $path = 'production'; } $shared_object = new Shared(); echo "\n"; echo "\n " . "<div id='data-path' data-path='" . $path . "'></div>"; echo "\n " . "<div id='data-load' data-load='" . $load . "'></div>"; }

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  • Python function correctly/incorrectly?

    - by Anthony Kernan
    I'm just starting too use python, learning experience. I know the basics logic of programming. I have a function in python that is running everytime, even when it's not supposed to. I use an if statement in the beginning of the function. I don't know why this if statement is not working, confused. I have another function that is similar and works correctly. Am I missing something simple? Here's the function that is not working... def check_artist_art(): if os.path.exists("/tmp/artistinfo") and open("/tmp/artistinfo").read() != title: #if artist == "": if os.path.exists(home + "/.artist"): os.remove(home + "/.artist") if os.path.exists("/tmp/artistinfo"): os.remove("/tmp/artistinfo") print artist return False else: os.path.exists("/tmp/artistinfo") and open("/tmp/artistinfo").read() == artist return False return True And this is the similar function that is working correctly.. def check_album(): if os.path.exists("/tmp/albuminfo") and open("/tmp/albuminfo").read() != album: if os.path.exists(home + "/.album"): os.remove(home + "/.album") if os.path.exists("/tmp/albuminfo"): os.remove("/tmp/albuminfo") return False elif os.path.exists("/tmp/trackinfo") and open("/tmp/trackinfo").read() == artist + album: return False return True Any help is greatly appreciated.

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  • How to compare two file structures in PHP?

    - by OM The Eternity
    I have a function which gives me the complete file structure upto n-level, function getDirectory($path = '.', $ignore = '') { $dirTree = array (); $dirTreeTemp = array (); $ignore[] = '.'; $ignore[] = '..'; $dh = @opendir($path); while (false !== ($file = readdir($dh))) { if (!in_array($file, $ignore)) { if (!is_dir("$path/$file")) { //display of file and directory name with their modification time $stat = stat("$path/$file"); $statdir = stat("$path"); $dirTree["$path"][] = $file. " === ". date('Y-m-d H:i:s', $stat['mtime']) . " Directory == ".$path."===". date('Y-m-d H:i:s', $statdir['mtime']) ; } else { $dirTreeTemp = getDirectory("$path/$file", $ignore); if (is_array($dirTreeTemp))$dirTree = array_merge($dirTree, $dirTreeTemp); } } } closedir($dh); return $dirTree; } $ignore = array('.htaccess', 'error_log', 'cgi-bin', 'php.ini', '.ftpquota'); //function call $dirTree = getDirectory('.', $ignore); //file structure array print print_r($dirTree); Now here my requirement is , I have two sites The Development/Test Site- where i do testing of all the changes The Production Site- where I finally post all the changes as per test in development site Now, for example, I have tested an image upload in the Development/test site, and i found it appropriate to publish on Production site then i will completely transfer the Development/Test DB detail to Production DB, but now I want to compare the files structure as well to transfer the corresponding image file to Production folder. There could be the situation when I update the image by editing the image and upload it with same name, now in this case the image file would be already present there, which will restrict the use of "file_exist" logic, so for these type of situations....HOW CAN I COMPARE THE TWO FILE STRUCTURE TO GET THE SYNCHRONIZATION DONE AS PER REQUIREMENT??

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  • script to list user's mapped drive not giving results or error

    - by user223631
    We are in the process of migrating two file servers to a new server. We have mapped drives via user group in group policy. Many users have manually mapped drives and we need to find these mappings. I have created a PowerShell script to run that remotely get the drive mappings. It works on most computers but there are many that are not returning results and I am not getting any error messages. Each workstation on the list creates a text file and the ones that are not returning results have no text in the files. I can ping these machines. If the machine is not turned on, it does come up error message that the RPC server is not available. My domain user account is in a group that is in the local admin account. I have no idea why some are not working. Here is the script. # Load list into variable, which will become an array of strings If( !(Test-Path C:\Scripts)) { New-Item C:\Scripts -ItemType directory } If( !(Test-Path C:\Scripts\Computers)) { New-Item C:\Scripts\Computers -ItemType directory } If( !(Test-Path C:\Scripts\Workstations.txt)) { "No Workstations found. Please enter a list of Workstations under Workstation.txt"; Return} If( !(Test-Path C:\Scripts\KnownMaps.txt)) { "No Mapping to check against. Please enter a list of Known Mappings under KnownMaps.txt"; Return} $computerlist = Get-Content C:\Scripts\Workstations.txt # Loop through each item in the array (each computer in the list of computers we loaded into the variable) ForEach ($computer in $computerlist) { $diskObject = Get-WmiObject Win32_MappedLogicalDisk -computerName $computer | Select Name,ProviderName | Out-File C:\Tester\Computers\$computer.txt -width 200 } Select-String -Path C:\Tester\Computers\*.txt -Pattern cmsfiles | Out-File C:\Tester\Drivemaps-all.txt $strings = Get-Content C:\Tester\KnownMaps.txt Select-String -Path C:\Tester\Drivemaps-all.txt -Pattern $strings -notmatch -simplematch | Out-File C:\Tester\Drivemaps-nonmatch.txt -Width 200 Select-String -Path C:\Tester\Drivemaps-all.txt -Pattern $strings -simplematch | Out-File C:\Tester\Drivemaps-match.txt -Width 200

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  • Accept All Cookies via HttpClient

    - by Vinay
    So this is currently how my app is set up: 1.) Login Activity. 2.) Once logged in, other activities may be fired up that use PHP scripts that require the cookies sent from logging in. I am using one HttpClient across my app to ensure that the same cookies are used, but my problem is that I am getting 2 of the 3 cookies rejected. I do not care about the validity of the cookies, but I do need them to be accepted. I tried setting the CookiePolicy, but that hasn't worked either. This is what logcat is saying: 11-26 10:33:57.613: WARN/ResponseProcessCookies(271): Cookie rejected: "[version: 0] [name: cookie_user_id][value: 1][domain: www.trackallthethings.com][path: trackallthethings][expiry: Sun Nov 25 11:33:00 CST 2012]". Illegal path attribute "trackallthethings". Path of origin: "/mobile-api/login.php" 11-26 10:33:57.593: WARN/ResponseProcessCookies(271): Cookie rejected: "[version: 0][name: cookie_session_id][value: 1985208971][domain: www.trackallthethings.com][path: trackallthethings][expiry: Sun Nov 25 11:33:00 CST 2012]". Illegal path attribute "trackallthethings". Path of origin: "/mobile-api/login.php" I am sure that my actual code is correct (my app still logs in correctly, just doesn't accept the aforementioned cookies), but here it is anyway: HttpGet httpget = new HttpGet(//MY URL); HttpResponse response; response = Main.httpclient.execute(httpget); HttpEntity entity = response.getEntity(); InputStream in = entity.getContent(); BufferedReader reader = new BufferedReader(new InputStreamReader(in)); StringBuilder sb = new StringBuilder(); From here I use the StringBuilder to simply get the String of the response. Nothing fancy. I understand that the reason my cookies are being rejected is because of an "Illegal path attribute" (I am running a script at /mobile-api/login.php whereas the cookie will return with a path of just "/" for trackallthethings), but I would like to accept the cookies anyhow. Is there a way to do this?

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