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• Rails link from one model to another based on db field?

  - by Danny McClelland

  Hi Everyone, I have a company model and a person model with the following relationships: class Company < ActiveRecord::Base has_many :kases has_many :people def to_s; companyname; end end class Person < ActiveRecord::Base has_many :kases # foreign key in join table belongs_to :company end In the create action for the person, I have a select box with a list of the companies, which assigns a company_id to that person's record: <%= f.select :company_id, Company.all.collect {|m| [m.companyname, m.id]} %> In the show view for the person I can list the company name as follows: <%=h @person.company.companyname %> What I am trying to work out, is how do I make that a link to the company record? I have tried: <%= link_to @person.company.companyname %> but that just outputs the company name inside a href tag but links to the current page. Thanks, Danny

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• How can I modify input before model binding in asp.net mvc?

  - by David G

  How can I intercept submitted form input and modify it before it is bound to my model? For example, if I wanted to trim the whitespace from all text. I have tried creating a custom model binder like so: public class CustomBinder : DefaultModelBinder { protected override void SetProperty(ControllerContext controllerContext, ModelBindingContext bindingContext, PropertyDescriptor propertyDescriptor, object value) { string newValue = ((string)value).Trim(); //example code to create new value but could be anything base.SetProperty(controllerContext, bindingContext, propertyDescriptor, newValue); } } but this doesn't seem to be invoked. Is there a better place to modify the input value? Note: I need to modify the value before it is bound and validated.

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• What is the proper way to access datastore in custom Model Binders?

  - by mare

  How should I properly implement data access in my custom model binders? Like in controllers I use IContentRepository and then have it create an instance of its implementing class in constructor. So I have everything ready for incorporating IoC (DI) at a later stage. Now I need something similar in model binder. I need to make some DB lookups in the binder. I'm thinking of doing it the same way I do it in controllers but I am open to suggestion. This is a snippet from one of my controllers so you can imagine how I'm doing it in them: public class WidgetZoneController : BaseController { // BaseController has IContentRepository ContentRepository field public WidgetZoneController() : this(new XmlWidgetZoneRepository()) { } public WidgetZoneController(IContentRepository repository) { ContentRepository = repository; } ...

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• Translate model fields' attributes from a Database with Django?

  - by Luiz C.

  I'm trying to create a Model that has fields that have the following attributes translatable: verbose_name and choices. I can easily do this by tagging the strings and using the i18l middleware. The problem is that I don't want to define the translation in po/mo files. Is there a way to pull this data from a database table? If so, any examples? There are some options out there that offer model content translation. That is not my case. I need to translate the verbose_name, choices and error_messages from database.

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• Ruby on Rails: building a model with an attribute not in the database?

  - by randombits

  I have a model that sets one of its attributes based off of a form parameter that a user submits. The model is a child resource to a parent resource Home. A hypothetical example is the following: A class Person has an age attribute. The user submits a birthdate as an HTTP POST parameter and from that, I need to derive the age of the user. So I'd do something like this: @home.people.build(:name => params[:name], :birthdate => params[:birthdate]) Rails would barf on that for obvious reasons, complaining it doesn't know what the attribute birthdate is. What's the proper way of going about this? Is it possible to use the build constructor with the supplied solution so that my foreign key relations are also setup properly? If not, what's a better way to work around this problem?

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• Can I use Pub/Sub model with Many Publishers and Only One Subscriber?

  - by rauch

  I need to send some files from different machines to only one Server. As I understand, I can use JMS api + (for example) ActiveMQ as broker. There are two models: p2p and pub/sub. I would like to use pub/sub model, but the problem is that I haven`t few subscribers, I have only one Subscriber(Server) and many Publishers. The question is the following: can I use pub/sub model for my situation and How can I send files from different machines to Only One Topic, on that Server sibscribed? May be any other ideas, thanks a lot.

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• What's the best way to share one Entity Framework 4 data model among multiple applications (meant to

  - by Ivan

  A project (a "solution" to say in VS terms) of mine consists of an ASP.Net 4 Dynamic Data Entities web application, some WinForms applications, some WPF applications, some services. All they are intended to work with one SQL Server database, generated from an Entity Framework 4 model as table-per-type, with lots of inheritance and multiple self-referencing relations. Where do I best put my model? In a separate class library, a copy in every project, in one project, etc. What naming should I best use? Is it good idea to name it MySolution.MyClassLibrary.MySolutionEntities, or just MySolutionEntities or just MySolution? Can you share any useful experience on this subject?

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• Where could I get the information about the in-memory layout info of .NET Object Model?

  - by smwikipedia

  I want to know the in-memory representation of .NET constructs such as "interface", "class", "struct", etc. There's an excellent book for C++ object model - <Inside the C++ Object Model by Stanley. Lippman, I want a similar book for .NET and C#. Could someone provide some hints about books and articles? I have read about the "Drill Into .NET Framework Internals to See How the CLR Creates Runtime Objects" Anything more? If this info is not publicly avaialble. Shared source one like Mono or Shared Source CLI could be an option. Many thanks.

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• How do I dynamically assign the Model for a .find in Ruby on Rails?

  - by Angela

  I am trying to create a Single Table Inheritance. However, the Controller must be able to know which class to find or create. These are based on another class. For example, ContactEvent with type = Letter needs to grab attributes from a corresponding Model called Letter. Here's what I've tried to do and hit a snag, labelled below. I need to be able to dynamically call assign a value of EventClass so that it can be Letter.find(:conditions =) or Calls.find(:conditions =) depending on which type the controller is acting on. def new @contact_event = ContactEvent.new @contact_event.type = params[:event_type] # can be letter, call, postcard, email @contact_event.event_id = params[:event_id] # that ID to the corresponding Model @contact_event.contact_id = params[:contact] @EventClass = case when @contact_event.type == 'letter' then 'Letter' when @contact_event.type == 'call' then 'Call' when @contact_event.type == 'email' then 'Email' SNAG BELOW: @event = @EventClass.find(@contact_letter.letter_id) #how do I make @EventClass actually the Class?SNAG # substitution of variables into the body of the contact_event @event.body.gsub!("{FirstName}", @contact.first_name) @event.body.gsub!("{Company}", @contact.company_name) @evebt.body.gsub!("{Colleagues}", @colleagues.to_sentence) @contact_event.body = @event.body @contact_event.status = "sent" end

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• How do I construct a Django form with model objects in a Select widget?

  - by Thierry Lam

  Let's say I'm using the Django Site model: class Site(models.Model): name = models.CharField(max_length=50) My Site values are (key, value): 1. Stackoverflow 2. Serverfault 3. Superuser I want to construct a form with an html select widget with the above values: <select> <option value="1">Stackoverflow</option> <option value="2">Serverfault</option> <option value="3">Superuser</option> </select> I'm thinking of starting with the following code but it's incomplete: class SiteForm(forms.Form): site = forms.IntegerField(widget=forms.Select()) Any ideas how I can achieve that with Django form?

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• Showing custom model validation exceptions in the Django admin site.

  - by Guy Bowden

  I have a booking model that needs to check if the item being booked out is available. I would like to have the logic behind figuring out if the item is available centralised so that no matter where I save the instance this code validates that it can be saved. At the moment I have this code in a custom save function of my model class: def save(self): if self.is_available(): # my custom check availability function super(MyObj, self).save() else: # this is the bit I'm stuck with.. raise forms.ValidationError('Item already booked for those dates') This works fine - the error is raised if the item is unavailable, and my item is not saved. I can capture the exception from my front end form code, but what about the Django admin site? How can I get my exception to be displayed like any other validation error in the admin site?

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• Where is the best place to call the .tolist(); inside my controller classes or inside my model repository classes

  - by john G

  I have the following action method, inside my asp.net mvc web application:- public JsonResult LoadZoneByDataCenter(string id) { var zonelist = repository.getrealtedzone(Convert.ToInt32(id)).ToList(); //code goes here Which calls the following model repository method:- public IQueryable<Zone> getrealtedzone(int? dcid) { return tms.Zones.Where(a=> a.DataCenterID == dcid || dcid == null); } Currently I am calling the .tolist() which will interpret the Database from my action method, but my question is where is the best place to call the .tolist() inside the controller or inside the model classes and why ? thanks

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• how to model editing of multiple related resources on the same webpage?

  - by amikazmi

  Lets say we have a Company model, that has many Employees And has many Projects If we want to show the projects, we'll go to "/company/1/projects/index" If we want to edit 1 project, we'll go to "/company/1/projects/1/edit" What if we want to edit all the projects at once on the same webpage? We can go to "/company/1/edit" and put a nested forms for all the projects But what if we need a different webpage to edit all the employees at once too? We can't use "/company/1/edit" again.. Right now we do "/company/1/projects/multiedit", "/company/1/projects/multupdate"- but as you can see, it's not rest. How can we model this restfully?

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• In Entity framework, we can use Model first, DB first, Code first but how can we create table programmatically

  - by AukI

  In entity framework we can use 3 approaches model first , code first , database first but each one of them needs manual hand touch(means creating database or create model or write the POCO class codes or entity class codes) before proceeding to the next step ( using EF in context ). What if I want to create database and tables and table relationships programatically and still want to have to features of EntityFramework 4.3. To be more specific , from this example http://support.microsoft.com/kb/307283 we can create database , tables and everything using SQL command but we can't have the advantages of entity framework. So if we want to have that what should we do?

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• Any tips of how to handle hierarchial trees in relational model?

  - by George

  Hello all. I have a tree structure that can be n-levels deep, without restriction. That means that each node can have another n nodes. What is the best way to retrieve a tree like that without issuing thousands of queries to the database? I looked at a few other models, like flat table model, Preorder Tree Traversal Algorithm, and so. Do you guys have any tips or suggestions of how to implement a efficient tree model? My objective in the real end is to have one or two queries that would spit the whole tree for me. With enough processing i can display the tree in dot net, but that would be in client machine, so, not much of a big deal. Thanks for the attention

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• asp.net mvc. Inserting string data from model into javascript. best-practice

  - by Andrew Florko

  Hello everybody, I have to populate javascript code in html layout (hidden fields, method params) with string data from model. Html.Encode is not appropriate for my task because it encodes ' symbol, bypass : (that ruines object attributes declaration) and so on. I wrote static helper class that is used from View like this: alert('<%=ViewHelper.MakeJavaScriptSafe(Model.Message)%>'); I hope there is asp.net in-built function I don't know about for this task. Does it exist really? Thank you in advance.

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• What do you name the "other" kind of view-model in an MVVM project?

  - by DanM

  With MVVM, I think of a view-model as a class that provides all the data and commands that a view needs to bind to. But what happens when I have a database entity object, say a Customer, and I want to build a class that shapes or flattens the Customer class for use in a data grid. For example, maybe this special Customer object would have a property TotalOrders, which is actually calculated using a join with a collection of Order entities. My question is, what do I call this special Customer class? In other situations, I'd be tempted to call it a CustomerViewModel, but I feel like "overloading" the notion of a view-model like this would be confusing in an MVVM project. What would you suggest?

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• How to read a complex view model on POST?

  - by Interfector

  Hello, I have an user view model that has the following properties: public User user; public List<Language> Languages; I send the above model to the view and use html helpers to build the form, so I end up with something like: <form action="/Users/Edit/5" method="post"><input id="user_UserId" name="user.UserId" type="hidden" value="5" /> First Name Last Name Email Language - en en Now, I try to read the POST in something that initially was something like : [AcceptVerbs( HttpVerbs.Post )] public ActionResult Edit( int UserId, FormCollection form ) { and cannot get the user.UserId variable, user.FirstName variable etc. Any idea what needs to be done to be able to read this kind of POST request. I'm kind of reluctant to modifying my ViewModel as it is very simple and easy to maintain as it is. Thank you.

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• MVC 3 Nested EditorFor Templates

  - by Gordon Hickley

  I am working with MVC 3, Razor views and EditorFor templates. I have three simple nested models:- public class BillingMatrixViewModel { public ICollection<BillingRateRowViewModel> BillingRateRows { get; set; } public BillingMatrixViewModel() { BillingRateRows = new Collection<BillingRateRowViewModel>(); } } public class BillingRateRowViewModel { public ICollection<BillingRate> BillingRates { get; set; } public BillingRateRowViewModel() { BillingRates = new Collection<BillingRate>(); } } public class BillingRate { public int Id { get; set; } public int Rate { get; set; } } The BillingMatrixViewModel has a view:- @using System.Collections @using WIP_Data_Migration.Models.ViewModels @model WIP_Data_Migration.Models.ViewModels.BillingMatrixViewModel <table class="matrix" id="matrix"> <tbody> <tr> @Html.EditorFor(model => Model.BillingRateRows, "BillingRateRow") </tr> </tbody> </table> The BillingRateRow has an Editor Template called BillingRateRow:- @using System.Collections @model IEnumerable<WIP_Data_Migration.Models.ViewModels.BillingRateRowViewModel> @foreach (var item in Model) { <tr> <td> @item.BillingRates.First().LabourClass.Name </td> @Html.EditorFor(m => item.BillingRates) </tr> } The BillingRate has an Editor Template:- @model WIP_Data_Migration.Models.BillingRate <td> @Html.TextBoxFor(model => model.Rate, new {style = "width: 20px"}) </td> The markup produced for each input is:- <input name="BillingMatrix.BillingRateRows.item.BillingRates[0].Rate" id="BillingMatrix_BillingRateRows_item_BillingRates_0__Rate" style="width: 20px;" type="text" value="0"/> Notice the name and ID attributes the BillingRate indexes are handled nicely but the BillingRateRows has no index instead '.item.'. From my reasearch this is because the context has been pulled out due to the foreach loop, the loop shouldn't be necessary. I want to achieve:- <input name="BillingMatrix.BillingRateRows[0].BillingRates[0].Rate" id="BillingMatrix_BillingRateRows_0_BillingRates_0__Rate" style="width: 20px;" type="text" value="0"/> If I change the BillingRateRow View to:- @model WIP_Data_Migration.Models.ViewModels.BillingRateRowViewModel <tr> @Html.EditorFor(m => Model.BillingRates) </tr> It will throw an InvalidOperationException, 'model item passed into the dictionary is of type System.Collections.ObjectModel.Collection [BillingRateRowViewModel] but this dictionary required a type of BillingRateRowViewModel. Can anyone shed any light on this?

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• How to pass Model from a view to a partial view?

  - by chobo2

  Hi I have a view that is not strongly typed. However I have in this view a partial view that is strongly typed. How do I do I pass the model to this strongly typed view? I tried something like public ActionResult Test() { MyData = new Data(); MyData.One = 1; return View("Test",MyData) } In my TestView <% Html.RenderPartial("PartialView",Model); %> This give me a stackoverflow exception. So I am not sure how to pass it on. Of course I don't want to make the test view strongly typed if possible as what happens if I had like 10 strongly typed partial views in that view I would need like some sort of wrapper.

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• What is Agile Modeling and why do I need it?

  What is Agile Modeling and why do I need it? Agile Modeling is an add-on to existing agile methodologies like Extreme programming (XP) and Rational Unified Process (RUP). Agile Modeling enables developers to develop a customized software development process that actually meets their current development needs and is flexible enough to adjust in the future. According to Scott Ambler, Agile Modeling consists of five core values that enable this methodology to be effective and light weight Agile Modeling Core Values: Communication Simplicity Feedback Courage Humility Communication is a key component to any successful project. Open communication between stakeholder and the development team is essential when developing new applications or maintaining legacy systems. Agile models promote communication amongst software development teams and stakeholders. Furthermore, Agile Models provide a common understanding of an application for members of a software development team allowing them to have a universal common point of reference. The use of simplicity in Agile Models enables the exploration of new ideas and concepts through the use of basic diagrams instead of investing the time in writing tens or hundreds of lines of code. Feedback in regards to application development is essential. Feedback allows a development team to confirm that the development path is on track. Agile Models allow for quick feedback from shareholders because minimal to no technical expertise is required to understand basic models. Courage is important because you need to make important decisions and be able to change direction by either discarding or refactoring your work when some of your decisions prove inadequate, according to Scott Ambler. As a member of a development team, we must admit that we do not know everything even though some of us think we do. This is where humility comes in to play. Everyone is a knowledge expert in their own specific domain. If you need help with your finances then you would consult an accountant. If you have a problem or are in need of help with a topic why would someone not consult with a subject expert? An effective approach is to assume that everyone involved with your project has equal value and therefore should be treated with respect. Agile Model Characteristics: Purposeful Understandable Sufficiently Accurate Sufficiently Consistent Sufficiently Detailed Provide Positive Value Simple as Possible Just Fulfill Basic Requirements According to Scott Ambler, Agile models are the most effective possible because the time that is invested in the model is just enough effort to complete the job. Furthermore, if a model isn’t good enough yet then additional effort can be invested to get more value out of the model. However if a model is good enough, for the current needs, or surpass the current needs, then any additional work done on the model would be a waste. It is important to remember that good enough is in the eye of the beholder, so this can be tough. In order for Agile Models to work effectively Active Stakeholder need to participation in the modeling process. Finally it is also very important to model with others, this allows for additionally input ensuring that all the shareholders needs are reflected in the models. How can Agile Models be incorporated in to our projects? Agile Models can be incorporated in to our project during the requirement gathering and design phases. As requirements are gathered the models should be updated to incorporate the new project details as they are defined and updated. Additionally, the Agile Models created during the requirement phase can be the bases for the models created during the design phase.  It is important to only add to the model when the changes fit within the agile model characteristics and they do not over complicate the design.

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• How to Create Views for All Tables with Oracle SQL Developer

  - by thatjeffsmith

  Got this question over the weekend via a friend and Oracle ACE Director, so I thought I would share the answer here. If you want to quickly generate DDL to create VIEWs for all the tables in your system, the easiest way to do that with SQL Developer is to create a data model. Wait, why would I want to do this? StackOverflow has a few things to say on this subject… So, start with importing a data dictionary. Step One: Open of Create a Model In SQL Developer, go to View – Data Modeler – Browser. Then in the browser panel, expand your design and create a new Relational Model. Step Two: Import your Data Dictionary This is a fancy way of saying, ‘suck objects out of the database into my model’ This will open a wizard to connect, select your schema(s), objects, etc. Once they’re in your model, you’re ready to cook with gas I’m using HR (Human Resources) for this example. You should end up with something that looks like this. Our favorite HR model Now we’re ready to generate the views! Step Three: Auto-generate the Views Go to Tools – Data Modeler – Table to View Wizard. I don’t want all my tables included, and I want to change the naming standard Decide if you want to change the default generated view names By default the views will be created as ‘V_TABLE_NAME.’ If you don’t like the ‘V_’ you can enter your own. You also can reference the object and model name with variables as shown in the screenshot above. I’m going to go with something a little more personal. The views are the little green boxes in the diagram Can’t find your views? They should be grouped together in your diagram. Don’t forget to use the Navigator to easily find and navigate to those model diagram objects! Step Four: Generate the DDL Ok, let’s use the Generate DDL button on the toolbar. Un-check everything but your views If you used a prefix, take advantage of that to create a filter. You might have existing views in your model that you don’t want to include, right? Once you click ‘OK’ the DDL will be generated. -- Generated by Oracle SQL Developer Data Modeler 4.0.0.825 -- at: 2013-11-04 10:26:39 EST -- site: Oracle Database 11g -- type: Oracle Database 11g CREATE OR REPLACE VIEW HR.TJS_BLOG_COUNTRIES ( COUNTRY_ID , COUNTRY_NAME , REGION_ID ) AS SELECT COUNTRY_ID , COUNTRY_NAME , REGION_ID FROM HR.COUNTRIES ; CREATE OR REPLACE VIEW HR.TJS_BLOG_EMPLOYEES ( EMPLOYEE_ID , FIRST_NAME , LAST_NAME , EMAIL , PHONE_NUMBER , HIRE_DATE , JOB_ID , SALARY , COMMISSION_PCT , MANAGER_ID , DEPARTMENT_ID ) AS SELECT EMPLOYEE_ID , FIRST_NAME , LAST_NAME , EMAIL , PHONE_NUMBER , HIRE_DATE , JOB_ID , SALARY , COMMISSION_PCT , MANAGER_ID , DEPARTMENT_ID FROM HR.EMPLOYEES ; CREATE OR REPLACE VIEW HR.TJS_BLOG_JOBS ( JOB_ID , JOB_TITLE , MIN_SALARY , MAX_SALARY ) AS SELECT JOB_ID , JOB_TITLE , MIN_SALARY , MAX_SALARY FROM HR.JOBS ; CREATE OR REPLACE VIEW HR.TJS_BLOG_JOB_HISTORY ( EMPLOYEE_ID , START_DATE , END_DATE , JOB_ID , DEPARTMENT_ID ) AS SELECT EMPLOYEE_ID , START_DATE , END_DATE , JOB_ID , DEPARTMENT_ID FROM HR.JOB_HISTORY ; CREATE OR REPLACE VIEW HR.TJS_BLOG_LOCATIONS ( LOCATION_ID , STREET_ADDRESS , POSTAL_CODE , CITY , STATE_PROVINCE , COUNTRY_ID ) AS SELECT LOCATION_ID , STREET_ADDRESS , POSTAL_CODE , CITY , STATE_PROVINCE , COUNTRY_ID FROM HR.LOCATIONS ; CREATE OR REPLACE VIEW HR.TJS_BLOG_REGIONS ( REGION_ID , REGION_NAME ) AS SELECT REGION_ID , REGION_NAME FROM HR.REGIONS ; -- Oracle SQL Developer Data Modeler Summary Report: -- -- CREATE TABLE 0 -- CREATE INDEX 0 -- ALTER TABLE 0 -- CREATE VIEW 6 -- CREATE PACKAGE 0 -- CREATE PACKAGE BODY 0 -- CREATE PROCEDURE 0 -- CREATE FUNCTION 0 -- CREATE TRIGGER 0 -- ALTER TRIGGER 0 -- CREATE COLLECTION TYPE 0 -- CREATE STRUCTURED TYPE 0 -- CREATE STRUCTURED TYPE BODY 0 -- CREATE CLUSTER 0 -- CREATE CONTEXT 0 -- CREATE DATABASE 0 -- CREATE DIMENSION 0 -- CREATE DIRECTORY 0 -- CREATE DISK GROUP 0 -- CREATE ROLE 0 -- CREATE ROLLBACK SEGMENT 0 -- CREATE SEQUENCE 0 -- CREATE MATERIALIZED VIEW 0 -- CREATE SYNONYM 0 -- CREATE TABLESPACE 0 -- CREATE USER 0 -- -- DROP TABLESPACE 0 -- DROP DATABASE 0 -- -- REDACTION POLICY 0 -- -- ERRORS 0 -- WARNINGS 0 You can then choose to save this to a file or not. This has a few steps, but as the number of tables in your system increases, so does the amount of time this feature can save you!

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• SQL SERVER – Select the Most Optimal Backup Methods for Server

  - by pinaldave

  Backup and Restore are very interesting concepts and one should be very much with the concept if you are dealing with production database. One never knows when a natural disaster or user error will surface and the first thing everybody wants is to get back on point in time when things were all fine. Well, in this article I have attempted to answer a few of the common questions related to Backup methodology. How to Select a SQL Server Backup Type In order to select a proper SQL Server backup type, a SQL Server administrator needs to understand the difference between the major backup types clearly. Since a picture is worth a thousand words, let me offer it to you below. Select a Recovery Model First The very first question that you should ask yourself is: Can I afford to lose at least a little (15 min, 1 hour, 1 day) worth of data? Resist the temptation to save it all as it comes with the overhead – majority of businesses outside finances can actually afford to lose a bit of data. If your answer is YES, I can afford to lose some data – select a SIMPLE (default) recovery model in the properties of your database, otherwise you need to select a FULL recovery model. The additional advantage of the Full recovery model is that it allows you to restore the data to a specific point in time vs to only last backup time in the Simple recovery model, but it exceeds the scope of this article Backups in SIMPLE Recovery Model In SIMPLE recovery model you can select to do just Full backups or Full + Differential. Full Backup This is the simplest type of backup that contains all information needed to restore the database and should be your first choice. It is often sufficient for small databases, but note that it makes a big impact on the performance of your database Full + Differential Backup After Full, Differential backup picks up all of the changes since the last Full backup. This means if you made Full, Diff, Diff backup – the last Diff backup contains all of the changes and you don’t need the previous Differential backup. Differential backup is obviously smaller and carries less performance overhead Backups in FULL Recovery Model In FULL recovery model you can select Full + Transaction Log or Full + Differential + Transaction Log backup. You have to create Transaction Log backup, because at that time the log is being truncated. Otherwise your Transaction Log will grow uncontrollably. Full + Transaction Log Backup You would always need to perform a Full backup first. Then a series of Transaction log backup. Note that (in contrast to Differential) you need ALL transactions to log since the last Full of Diff backup to properly restore. Transaction log backups have the smallest performance overhead and can be performed often. Full + Differential + Transaction Log Backup If you want to ease the performance overhead on your server, you can replace some of the Full backup in the previous scenario with Differential. You restore scenario would start from Full, then the Last Differential, then all of the remaining transactions log backups Typical backup Scenarios You may say “Well, it is all nice – give me the examples now”. As you may already know, my favorite SQL backup software is SQLBackupAndFTP. If you go to Advanced Backup Schedule form in this program and click “Load a typical backup plan…” link, it will give you these scenarios that I think are quite common – see the image below. The Simplest Way to Schedule SQL Backups I hate to repeat myself, but backup scheduling in SQL agent leaves a lot to be desired. I do not know the simple way to schedule your SQL server backups than in SQLBackupAndFTP – see the image below. The whole backup scheduling with compression, encryption and upload to a Network Folder / HDD / NAS Drive / FTP / Dropbox / Google Drive / Amazon S3 takes just a few minutes – see my previous post for the review. Final Words This post offered an explanation for major backup types only. For more complicated scenarios or to research other options as usually go to MSDN. Reference: Pinal Dave (http://blog.sqlauthority.com) Filed under: PostADay, SQL, SQL Authority, SQL Backup and Restore, SQL Query, SQL Server, SQL Tips and Tricks, T SQL, Technology

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• Oracle Tutor: XPDL conversion (and why you should care)

  - by mary.keane

  You may have noticed that the Oracle Business Process Converter feature in Tutor 14 supports "XPDL" conversion to Oracle Business Process Analysis Suite (BPA), Oracle Business Process Management Suite (BPM), and Oracle Tutor, and you may have briefly wondered "what is XPDL?" before you moved on to the Visio import feature (a very popular feature in Tutor 14). This posting is for those who do not yet understand (or care) about XPDL and process modeling. Many of us (and I'm including myself) have spent years working in the process definition arena: we've written procedures, designed systems and software to help others write procedures, and have been responsible for embedding policies and procedures into training material for employees. We've worked with tools such as Oracle Tutor, Microsoft Visio, Microsoft Word, and UPK. Most of us have never worked with "modeling tools" before, and we certainly never had to understand BPMN. It's a brave new world in this arena, and companies desperately need people with policy and procedural system expertise to be able to work with system analysts so there is a seamless transfer of knowledge from IT to employees. When working with applications, a picture is worth a thousand words, so eventually you're going to need to understand and be able to work with business process models. XPDL is an acronym for XML Process Definition Language, and it is an interchange format for business process models. It allows you to take a BPMN model that was developed in one workflow application such as BizAgi and import it into another workflow application or a true BPMN management system such as Oracle BPM. Specifically, the XPDL format contains the graphical information of a model as well as any executable information. By using a common format, models can be moved from a basic modeling application used by business owners to applications used by system architects. Over 80 applications support the XPDL format, including MetaStorm ProVision, BEA ALBPM, BizAgi, and Tibco. I mention these applications because we have provided XSLT mapping files specifically for these vendors. Oracle Business Process Converter was designed with user extensibility in mind, and thus users can add their own XML files so that additional XPDL models from other vendors can be converted to BPM, BPA, and Oracle Tutor. Instructions on how to add your own files can be found in Appendix 4 of the Oracle Business Converter manual. Let's take a visual look at how this works. Here is an example of a model devloped in BizAgi: This model can be created by the average business user without a large learning curve, and it's a good start for the system analyst who will be adding web services as well as for the business manager who manages the process described in the model. By exporting this model as XPDL, the information can be converted into Oracle BPA and Oracle BPM as well as converted to Oracle Tutor to become the framework for a procedure. Through this conversion feature, one graphic illustration of a business process can be used by a system analyst, business analyst, business manager, and employee, as seen below. Model Converted to Tutor Procedure Below is the task section of the procedure after conversion from an XPDL file. Model converted to BPA Model converted to BPM End users still want step by step instructions on how to perform their jobs, so procedures (Oracle Tutor) and application simulations (UPK) are still a critical piece of the solution. But IT professionals need graphic descriptions of how the applications work, regardless of whether there are any tasks involving humans. Now there is a way to convert procedures (Oracle Tutor docx files) and basic models (XPDL files) so that business managers and system analysts can share process information. References Wikipedia XPDL. Workflow Management Coalition, XPDL Support and Resources Oracle Business Process Converter manual, Oracle Tutor 14 Oracle Business Process Management 11g If you have any XPDL conversion stories to share, we'd love to hear from you. Best wishes for the coming new year, Mary Keane, Senior Development Manager, Oracle Tutor and BPM

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• Hudson Mercurial checkout throws exception on Debian

  - by Jack

  I'm trying to configure Hudson to checkout my site's sources from Mercurial but it throws an exception. The /var/lib/hudson/jobs/jobname directory does exist, and I can create a workspace directory in there (even after su hudson), but as soon as I run the Hudson job again this directory disappears and the job ends with the same error: java.io.IOException: Cannot run program "hg" (in directory "/var/lib/hudson/jobs/jobname/workspace"): java.io.IOException: error=2, No such file or directory at java.lang.ProcessBuilder.start(ProcessBuilder.java:460) at hudson.Proc$LocalProc.<init>(Proc.java:192) at hudson.Proc$LocalProc.<init>(Proc.java:164) at hudson.Launcher$LocalLauncher.launch(Launcher.java:639) at hudson.Launcher$ProcStarter.start(Launcher.java:274) at hudson.Launcher$ProcStarter.join(Launcher.java:281) at hudson.plugins.mercurial.MercurialSCM.joinWithPossibleTimeout(MercurialSCM.java:298) at hudson.plugins.mercurial.HgExe.popen(HgExe.java:191) at hudson.plugins.mercurial.HgExe.tip(HgExe.java:171) at hudson.plugins.mercurial.MercurialSCM.calcRevisionsFromBuild(MercurialSCM.java:254) at hudson.scm.SCM._calcRevisionsFromBuild(SCM.java:304) at hudson.model.AbstractProject.calcPollingBaseline(AbstractProject.java:1183) at hudson.model.AbstractProject.checkout(AbstractProject.java:1172) at hudson.model.AbstractBuild$AbstractRunner.checkout(AbstractBuild.java:499) at hudson.model.AbstractBuild$AbstractRunner.run(AbstractBuild.java:415) at hudson.model.Run.run(Run.java:1362) at hudson.model.FreeStyleBuild.run(FreeStyleBuild.java:46) at hudson.model.ResourceController.execute(ResourceController.java:88) at hudson.model.Executor.run(Executor.java:145) Caused by: java.io.IOException: java.io.IOException: error=2, No such file or directory at java.lang.UNIXProcess.<init>(UNIXProcess.java:148) at java.lang.ProcessImpl.start(ProcessImpl.java:65) at java.lang.ProcessBuilder.start(ProcessBuilder.java:453) Running on Debian 6.0.1 I wonder if anyone has ran into this before, and hopefully solved it?

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