Search Results

Search found 73266 results on 2931 pages for 'django file upload'.

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

Page 102/2931 | < Previous Page | 98 99 100 101 102 103 104 105 106 107 108 109  | Next Page >

  • how to upload a audio file using REST webservice in Google App Engine for Java

    - by sathya
    Am using google app engine with eclipse IDE and trying to upload a audio file. I used the File Upload in Google App Engine For Java and can able to upload the file successfully. Now am planning to use REST web service for it. I had analyzed in developers.google but i failed. Can anyone suggest me how to implement REST Web services in google app engine using Eclipse. The code google provided is shown below, // file Upload.java public class Upload extends HttpServlet { private BlobstoreService blobstoreService = BlobstoreServiceFactory.getBlobstoreService(); public void doPost(HttpServletRequest req, HttpServletResponse res) throws ServletException, IOException { Map<String, BlobKey> blobs = blobstoreService.getUploadedBlobs(req); BlobKey blobKey = blobs.get("myFile"); if (blobKey == null) { res.sendRedirect("/"); } else { res.sendRedirect("/serve?blob-key=" + blobKey.getKeyString()); }}} // file Serve.java public class Serve extends HttpServlet { private BlobstoreService blobstoreService = BlobstoreServiceFactory.getBlobstoreService(); public void doGet(HttpServletRequest req, HttpServletResponse res) throws IOException { BlobKey blobKey = new BlobKey(req.getParameter("blob-key")); blobstoreService.serve(blobKey, res); }} // file index.jsp <%@ page import="com.google.appengine.api.blobstore.BlobstoreServiceFactory" %> <%@ page import="com.google.appengine.api.blobstore.BlobstoreService" %> <% BlobstoreService blobstoreService = BlobstoreServiceFactory.getBlobstoreService(); %> <form action="<%= blobstoreService.createUploadUrl("/upload") %>" method="post" enctype="multipart/form-data"> <input type="file" name="myFile"> <input type="submit" value="Submit"> </form> // web.xml <servlet> <servlet-name>Upload</servlet-name> <servlet-class>Upload</servlet-class> </servlet> <servlet> <servlet-name>Serve</servlet-name> <servlet-class>Serve</servlet-class> </servlet> <servlet-mapping> <servlet-name>Upload</servlet-name> <url-pattern>/upload</url-pattern> </servlet-mapping> <servlet-mapping> <servlet-name>Serve</servlet-name> <url-pattern>/serve</url-pattern> </servlet-mapping> Now how to provide a rest web service for the above code. Kindly suggest me an idea.

    Read the article

  • regular expression with special chars

    - by xRobot
    I need a regular expression to validate string with one or more of these characters: a-z A-Z ' àòèéùì simple white space FOR EXAMPLE these string are valide: D' argon calabrò maryòn l' Ancol these string are NOT valide: hello38239 my_house work [tab] with me I tryed this: re.match(r"^[a-zA-Z 'òàèéìù]+$", self.cleaned_data['title'].strip()) It seems to work in my python shell but in Django I get this error: SyntaxError at /home/ ("Non-ASCII character '\\xc3' ... Why ?

    Read the article

  • apache solr auto suggestions

    - by Pydev UA
    I use solr+django-haystack I set settings.HAYSTACK_INCLUDE_SPELLING = True and rebuild index I'm trying to get any suggestion using: SearchQuerySet().auto_query('tryng ani word her').spelling_suggestion() But I always get None What should I do to get at least one working suggestion ? may be I need add some configuration into solr config or have some specific data indexed ?

    Read the article

  • Overriding initial value in ModelForm

    - by schneck
    Hi, in my Django (1.2) project, I want to prepopulate a field in a modelform, but my new value is ignored. This is the snippet: class ArtefactForm(ModelForm): material = CharField(widget=AutoCompleteWidget('material', force_selection=False)) def __init__(self, *args, **kwargs): super(ArtefactForm, self).__init__(*args, **kwargs) self.fields['material'].initial = 'Test' I also tried with self.base_fields, but no effect: there is always the database-value displaying in the form. Any ideas?

    Read the article

  • call a Javascript function from controller more than once (in Rails)

    - by mm1
    hi. I have a multiple file upload form(html5) and want to update my view as soon one of the images is transfered to my image server. Currently I upload the files with ajax and use response_to_parent to update my upload view when all images are transfered to the image server. Is it possible to call a Javascript function from the controller more than once per action? def upload params[:images].each do |file| upload_to_image_server(file) #page << Update upload View end end Thanks, Michael

    Read the article

  • Three ways to upload/post/convert iMovie to YouTube

    - by user44251
    For Mac users, iMovie is probably a convenient tool for making, editing their own home movies so as to upload to YouTube for sharing with more people. However, uploading iMovie files to YouTube can't be always a smooth run, I did notice many people complaining about it. This article is delivered for guiding those who are haunted by the nightmare by providing three common ways to upload iMovie files to YouTube. YouTube and iMovie YouTube is the most popular video sharing website for users to upload, share and view videos. It empowers anyone with an Internet connection the ability to upload video clips and share them with friends, family and the world. Users are invited to leave comments, pick favourites, send messages to each other and watch videos sorted into subjects and channels. YouTube accepts videos uploaded in most container formats, including WMV (Windows Media Video), 3GP (Cell Phones), AVI (Windows), MOV (Mac), MP4 (iPod/PSP), FLV (Adobe Flash), MKV (H.264). These include video codecs such as MP4, MPEG and WMV. iMovie is a common video editing software application comes with every Mac for users to edit their own home movies. It imports video footage to the Mac using either the Firewire interface on most MiniDV format digital video cameras, the USB port, or by importing the files from a hard drive where users can edit the video clips, add titles, and add music. Since 1999, eight versions of iMovie have been released by Apple, each with its own functions and characteristic, and each of them deal with videos in a way more or less different. But the most common formats handled with iMovie if specialty discarded as far as to my research are MOV, DV, HDV, MPEG-4. Three ways for successful upload iMovie files to YouTube Solution one and solution two suitable for those who are 100 certainty with their iMovie files which are fully compatible with YouTube. For smooth uploading, you are required to get a YouTube account first. Solution 1: Directly upload iMovie to YouTube Step 1: Launch iMovie, select the project you want to upload in YouTube. Step 2: Go to the file menu, click Share, select Export Movie Step 3: Specify the output file name and directory and then type the video type and video size. Solution 2: Post iMovie to YouTube straightly Step 1: Launch iMovie, choose the project you want to post in YouTube Step 2: From the Share menu, choose YouTube Step 3: In the pop-up YouTube windows, specify the name of your YouTube account, the password, choose the Category and fill in the description and tags of the project. Tick Make this movie more private on the bottom of the window, if possible, to limit those who can view the project. Click Next, and then click Publish. iMovie will automatically export and upload the movie to YouTube. Step 4: Click Tell a Friend to email friends and your family about your film. You are also allowed to copy the URL from Tell a Friend window and paste it into an email you created in your favourite email application if you like. Anyone you send to email to will be able to follow the URL directly to your movie. Note: Videos uploaded to YouTube are limited to ten minutes in length and a file size of 2GB. Solution 3: Upload to iMovie after conversion If neither of the above mentioned method works, there is still a third way to turn to. Sometimes, your iMovie files may not be recognized by YouTube due to the versions of iMovie (settings and functions may varies among versions), video itself (video format difference because of file extension, resolution, video size and length), compatibility (videos that are completely incompatible with YouTube). In this circumstance, the best and reliable method is to convert your iMovie files to YouTube accepted files, iMovie to YouTube converter will be inevitably the ideal choice. iMovie to YouTube converter is an elaborately designed tool for convert iMovie files to YouTube workable WMV, 3GP, AVI, MOV, MP4, FLV, MKV for smooth uploading with hard-to-believe conversion speed and second to none output quality. It can also convert between almost all popular popular file formats like AVI, WMV, MPG, MOV, VOB, DV, MP4, FLV, 3GP, RM, ASF, SWF, MP3, AAC, AC3, AIFF, AMR, WAV, WMA etc so as to put on various portable devices, import to video editing software or play on vast amount video players. iMovie to YouTube converter can also served as an excellent video editing tool to meet your specific program requirements. For example, you can cut your video files to a certain length, or split your video files to smaller ones and select the proper resolution suitable for demands of YouTube by Clip or Settings separately. Crop allows you to cut off unwanted black edges from your videos. Besides, you can also have a good command of the whole process or snapshot your favourite pictures from the preview window. More can be expected if you have a try.

    Read the article

  • Three ways to upload/post/convert iMovie to YouTube [closed]

    - by alexyu2010
    For Mac users, iMovie is probably a convenient tool for making, editing their own home movies so as to upload to YouTube for sharing with more people. However, uploading iMovie files to YouTube can't be always a smooth run, I did notice many people complaining about it. This article is delivered for guiding those who are haunted by the nightmare by providing three common ways to upload iMovie files to YouTube. YouTube and iMovie YouTube is the most popular video sharing website for users to upload, share and view videos. It empowers anyone with an Internet connection the ability to upload video clips and share them with friends, family and the world. Users are invited to leave comments, pick favourites, send messages to each other and watch videos sorted into subjects and channels. YouTube accepts videos uploaded in most container formats, including WMV (Windows Media Video), 3GP (Cell Phones), AVI (Windows), MOV (Mac), MP4 (iPod/PSP), FLV (Adobe Flash), MKV (H.264). These include video codecs such as MP4, MPEG and WMV. iMovie is a common video editing software application comes with every Mac for users to edit their own home movies. It imports video footage to the Mac using either the Firewire interface on most MiniDV format digital video cameras, the USB port, or by importing the files from a hard drive where users can edit the video clips, add titles, and add music. Since 1999, eight versions of iMovie have been released by Apple, each with its own functions and characteristic, and each of them deal with videos in a way more or less different. But the most common formats handled with iMovie if specialty discarded as far as to my research are MOV, DV, HDV, MPEG-4. Three ways for successful upload iMovie files to YouTube Solution one and solution two suitable for those who are 100 certainty with their iMovie files which are fully compatible with YouTube. For smooth uploading, you are required to get a YouTube account first. Solution 1: Directly upload iMovie to YouTube Step 1: Launch iMovie, select the project you want to upload in YouTube. Step 2: Go to the file menu, click Share, select Export Movie Step 3: Specify the output file name and directory and then type the video type and video size. Solution 2: Post iMovie to YouTube straightly Step 1: Launch iMovie, choose the project you want to post in YouTube Step 2: From the Share menu, choose YouTube Step 3: In the pop-up YouTube windows, specify the name of your YouTube account, the password, choose the Category and fill in the description and tags of the project. Tick Make this movie more private on the bottom of the window, if possible, to limit those who can view the project. Click Next, and then click Publish. iMovie will automatically export and upload the movie to YouTube. Step 4: Click Tell a Friend to email friends and your family about your film. You are also allowed to copy the URL from Tell a Friend window and paste it into an email you created in your favourite email application if you like. Anyone you send to email to will be able to follow the URL directly to your movie. Note: Videos uploaded to YouTube are limited to ten minutes in length and a file size of 2GB. Solution 3: Upload to iMovie after conversion If neither of the above mentioned method works, there is still a third way to turn to. Sometimes, your iMovie files may not be recognized by YouTube due to the versions of iMovie (settings and functions may varies among versions), video itself (video format difference because of file extension, resolution, video size and length), compatibility (videos that are completely incompatible with YouTube). In this circumstance, the best and reliable method is to convert your iMovie files to YouTube accepted files, iMovie to YouTube converter will be inevitably the ideal choice. iMovie to YouTube converter is an elaborately designed tool for convert iMovie files to YouTube workable WMV, 3GP, AVI, MOV, MP4, FLV, MKV for smooth uploading with hard-to-believe conversion speed and second to none output quality. It can also convert between almost all popular popular file formats like AVI, WMV, MPG, MOV, VOB, DV, MP4, FLV, 3GP, RM, ASF, SWF, MP3, AAC, AC3, AIFF, AMR, WAV, WMA etc so as to put on various portable devices, import to video editing software or play on vast amount video players. iMovie to YouTube converter can also served as an excellent video editing tool to meet your specific program requirements. For example, you can cut your video files to a certain length, or split your video files to smaller ones and select the proper resolution suitable for demands of YouTube by Clip or Settings separately. Crop allows you to cut off unwanted black edges from your videos. Besides, you can also have a good command of the whole process or snapshot your favourite pictures from the preview window. More can be expected if you have a try.

    Read the article

  • PHP Frameworks (CodeIgnitor, Yii, CakePHP) vs. Django

    - by niting
    I have to develop a site which has to accomodate around 2000 users a day and speed is a criterion for it. Moreover, the site is a user oriented one where the user will be able to log in and check his profile, register for specific events he/she wants to participate in. The site is to be hosted on a VPS server.Although I have pretty good experience with python and PHP but I have no idea how to use either of the framework. We have plenty of time to experiment and learn one of the above frameworks.Could you please specify which one would be preferred for such a scenario considering speed, features, and security of the site. Thanks, niting

    Read the article

  • List display names from django models

    - by Ed
    I have an object: POP_CULTURE_TYPES = ( ('SG','Song'), ('MV', 'Movie'), ('GM', 'Game'), ('TV', 'TV'), ) class Pop_Culture(models.Model): name = models.CharField(max_length=30, unique=True) type = models.CharField(max_length=2, choices = POP_CULTURE_TYPES, blank=True, null=True) Then I have a function: def choice_list(request, modelname, field_name): mdlnm = get.model('mdb', modelname.lower()) mdlnm = mdlnm.objects.values_list(field_name, flat=True).distinct().order_by(field_name) return render_to_response("choice_list.html", { 'model' : modelname, 'field' : field_name, 'field_list' : mdlnm }) This gives me a distinct list of all the "type" entries in the database in the "field_list" variable passed in render_to_response. But I don't want a list that shows: SG MV I want a list that shows: Song Movie I can do this on an individual object basis if I was in the template object.get_type_display But how do I get a list of all of the unique "type" entries in the database as their full names for output into a template? I hope this question was clearly described. . .

    Read the article

  • Best way to re-use the same django models and admin for multiple apps

    - by kepioo
    Given a reference app ( called guide), how can I create additional apps that will reuse the same model/admin/views than guide - the motivation behind is to be able to individually control each subapp. guide guideApp1 exact same models/admin/views than guide guideApp2 exact same models/admin/views than guide in the Admin site, I should have : 1 section for guideApp1 with all the tables defined in guide, that applies to guideApp1 1 section for guideApp12 with all the tables defined in guide, that applies to guideApp2

    Read the article

  • Validating ModelChoiceField in Django forms

    - by Andrey
    I'm trying to validate a form containing a ModelChoiceField: state = forms.ModelChoiceField(queryset=State.objects.all(), empty_label=None) When it is used in normal circumstances, everything goes just fine. But I'd like to protect the form from the invalid input. It's pretty obvious that I must get forms.ValidationError when I put invalid value in this field, isn't it? But if I try to submit a form with a value 'invalid' in 'state' field, I get ValueError: invalid literal for int() with base 10: 'invalid' and not the expected forms.ValidationError. What should I do? I tried to place a def clean_state(self) to check this field but that didn't work plus I don't think this is a good solution, there must be something more simple but I just missed that.

    Read the article

  • Generate unique hashes for django models

    - by becomingGuru
    I want to use unique hashes for each model rather than ids. I implemented the following function to use it across the board easily. import random,hashlib from base64 import urlsafe_b64encode def set_unique_random_value(model_object,field_name='hash_uuid',length=5,use_sha=True,urlencode=False): while 1: uuid_number = str(random.random())[2:] uuid = hashlib.sha256(uuid_number).hexdigest() if use_sha else uuid_number uuid = uuid[:length] if urlencode: uuid = urlsafe_b64encode(uuid)[:-1] hash_id_dict = {field_name:uuid} try: model_object.__class__.objects.get(**hash_id_dict) except model_object.__class__.DoesNotExist: setattr(model_object,field_name,uuid) return I'm seeking feedback, how else could I do it? How can I improve it? What is good bad and ugly about it?

    Read the article

  • GAE/Django Templates (0.96) filters to get LENGTH of GqlQuery and filter it

    - by Halst
    I pass the query with comments to my template: COMM = CommentModel.gql("ORDER BY created") doRender(self,CP.template,{'CP':CP,'COMM':COMM, 'authorize':authorize()}) And I want to output the number of comments as a result, and I try to do things like that: <a href="...">{{ COMM|length }} comments</a> Thats does not work (yeah, since COMM is GqlQuery, not a list). What can I do with that? Is there a way to convert GqlQuery to list or is there another solution? (first question) Second question is, how to filter this list in template? Is there a construct like this: <a href="...">{{ COMM|where(reference=smth)|length }} comments</a> so that I can get not only the number of all comments, but only comments with certain db.ReferenceProperty() property, for example. Last question: is it weird to do such things using templates?

    Read the article

  • ContentType Issue -- Human is an idiot - Can't figure out how to tie the original model to a Content

    - by bmelton
    Originally started here: http://stackoverflow.com/questions/2650181/django-in-query-as-a-string-result-invalid-literal-for-int-with-base-10 I have a number of apps within my site, currently working with a simple "Blog" app. I have developed a 'Favorite' app, easily enough, that leverages the ContentType framework in Django to allow me to have a 'favorite' of any type... trying to go the other way, however, I don't know what I'm doing, and can't find any examples for. I'll start off with the favorite model: favorite/models.py from django.db import models from django.contrib.contenttypes.models import ContentType from django.contrib.contenttypes import generic from django.contrib.auth.models import User class Favorite(models.Model): content_type = models.ForeignKey(ContentType) object_id = models.PositiveIntegerField() user = models.ForeignKey(User) content_object = generic.GenericForeignKey() class Admin: list_display = ('key', 'id', 'user') class Meta: unique_together = ("content_type", "object_id", "user") Now, that allows me to loop through the favorites (on a user's "favorites" page, for example) and get the associated blog objects via {{ favorite.content_object.title }}. What I want now, and can't figure out, is what I need to do to the blog model to allow me to have some tether to the favorite (so when it is displayed in a list it can be highlighted, for example). Here is the blog model: blog/models.py from django.db import models from django.db.models import permalink from django.template.defaultfilters import slugify from category.models import Category from section.models import Section from favorite.models import Favorite from django.contrib.auth.models import User from django.contrib.contenttypes.models import ContentType from django.contrib.contenttypes import generic class Blog(models.Model): title = models.CharField(max_length=200, unique=True) slug = models.SlugField(max_length=140, editable=False) author = models.ForeignKey(User) homepage = models.URLField() feed = models.URLField() description = models.TextField() page_views = models.IntegerField(null=True, blank=True, default=0 ) created_on = models.DateTimeField(auto_now_add = True) updated_on = models.DateTimeField(auto_now = True) def __unicode__(self): return self.title @models.permalink def get_absolute_url(self): return ('blog.views.show', [str(self.slug)]) def save(self, *args, **kwargs): if not self.slug: slug = slugify(self.title) duplicate_count = Blog.objects.filter(slug__startswith = slug).count() if duplicate_count: slug = slug + str(duplicate_count) self.slug = slug super(Blog, self).save(*args, **kwargs) class Entry(models.Model): blog = models.ForeignKey('Blog') title = models.CharField(max_length=200) slug = models.SlugField(max_length=140, editable=False) description = models.TextField() url = models.URLField(unique=True) image = models.URLField(blank=True, null=True) created_on = models.DateTimeField(auto_now_add = True) def __unicode__(self): return self.title def save(self, *args, **kwargs): if not self.slug: slug = slugify(self.title) duplicate_count = Entry.objects.filter(slug__startswith = slug).count() if duplicate_count: slug = slug + str(duplicate_count) self.slug = slug super(Entry, self).save(*args, **kwargs) class Meta: verbose_name = "Entry" verbose_name_plural = "Entries" Any guidance?

    Read the article

  • Django exclude(**kwargs) help

    - by shawnjan
    Hey guys/gals! I had a question for you, something that I can't seem to find the solution for... Basically, I have a model called Environment, and I am passing all of them to a view, and there are particular environments that I would like to exclude. Now, I know there is a exclude function on a queryset, but I can't seem to figure out how to use it for multiple options... For example, I tried this but it didn't work: kwargs = {"name": "env1", "name": "env2"} envs = Environment.objects.exclude( kwards ) But the only thing that it will exclude is the last "name" value in the list of kwargs. I understand why it does that now, but I still can't seem to exclude multiple objects with one command. Any help is much appreciated! Shawn

    Read the article

  • Django ManyToMany join query

    - by Hanpan
    I'm sure this is really simple, but I can't for the life of me find any documentation explaining how to do this. How do I get the results of a ManyToMany field inside a join as opposed to doing this: {% for tag in article.tags.all %} Which results in an extra query? What I'd like to do is fetch all related tags when I retrieve the initial article, so I could then do something like: {% for tag in article.tags %} Without the .all and the extra query. Thanks!

    Read the article

  • Show choosen option in a notification Feed, Django

    - by apoo
    Hey I have a model where : LIST_OPTIONS = ( ('cheap','cheap'), ('expensive','expensive'), ('normal', 'normal'), ) then I have assigned the LIST_OPTIONS to nature variable. nature = models.CharField(max_length=15, choices=LIST_OPTIONS, null=False, blank=False). then I save it: if self.pk: new=False else: new=True super(Listing, self).save(force_insert, force_update) if new and notification: notification.send(User.objects.all().exclude(id=self.owner.id), "listing_new", {'listing':self, }, ) then in my management.py: def create_notice_types(app, created_models,verbosity, **kwargs): notification.create_notice_type("listing_new", _("New Listing"), _("someone has posted a new listing"), default=2) and now in my notice.html I want to show to users different sentences based on the options that they have choose so something like this: LINK href="{{ listing.owner.get_absolute_url }} {{listing.owner}} {% ifequal listing.nature "For Sale" %} created a {{ listing.nature }} listing, <a href="{{ listing.get_absolute_url }}">{{listing.title}}</a>. {% ifequals listing.equal "Give Away"%} is {{ listing.nature }} , LINK href="{{ listing.get_absolute_url }}" {{listing.title}}. {% ifequal listing.equal "Looking For"%} is {{ listing.nature }} , LINK href="{{ listing.get_absolute_url }}" {{listing.title}} {% endifequal %} {% endifequal %} {% endifequal %} Could you please help me out with this. Thank you

    Read the article

  • django ManyToMany through help

    - by dotty
    Hay I've got a question about relationships. I want to Users to have Friendships. So a User can be a friend with another User. I'm assuming i'll need to use the ManyToManyField, through a Friendship table. But i cannot get it to work. Any ideas? Here are my models. class User(models.Model): username = models.CharField(max_length=999) password = models.CharField(max_length=999) created_on = models.DateField(auto_now = False, auto_now_add = True) updated_on = models.DateField(auto_now = True, auto_now_add = False) friends = models.ManyToManyField('User', through='Friendship') class Friendship(models.Model): user = models.ForeignKey('User') friend = models.ForeignKey('User') Thanks

    Read the article

  • Django inlineformset validation and delete

    - by Andrew Gee
    Hi, Can someone tell me if a form in an inlineformset should go through validation if the DELETE field is checked. I have a form that uses an inlineformset and when I check the DELETE box it fails because the required fields are blank. If I put data in the fields it will pass validation and then be deleted. Is that how it is supposed to work, I would have thought that if it is marked for delete it would bypass the validation for that form. Regards Andrew Follow up - but I would still appreciate some others opinions/help What I have figured out is that for validation to work the a formset form must either be empty or complete(valid) otherwise it will have errors when it is created and will not be deleted. As I have a couple of hidden fields in my formset forms and they are pre-populated when the page loads via javascript the form fails validation on the other required fields which might still be blank. The way I have gotten around this by adding in a check in the add_fields that tests if the DELETE input is True and if it is it makes all fields on the form not required, which means it passes validation and will then delete. def add_fields(self, form, index) #add other fields that are required.... deleteValue = form.fields['DELETE'].widget.value_from datadict(form.data, form.files, form.add_prefix('DELETE')) if bool(deleteValue) or deleteValue == '': for name, field in form.fields.items(): form.fields[name].required= False This seems to be an odd way to do things but I cannot figure out another way. Is there a simpler way that I am missing? I have also noticed that when I add the new form to my page and check the Delete box, there is no value passed back via the request, however an existing form (one loaded from the database) has a value of on when the Delete box is checked. If the box is not checked then the input is not in the request at all. Thanks Andrew

    Read the article

  • django error:The model Tribe is already registered

    - by zjm1126
    when i python manage.py syncdb,it show this: The following content types are stale and need to be deleted: maps | tribe Any objects related to these content types by a foreign key will also be deleted. Are you sure you want to delete these content types? If you're unsure, answer 'no'. Type 'yes' to continue, or 'no' to cancel: no when i put 'no' ,and then python manage runserver: AlreadyRegistered at / The model Tribe is already registered what should i do ? thanks

    Read the article

  • onmouseover with django / imagekit

    - by Michael Moreno
    I'm using Imagekit. View.py includes: def pics(request): p = Photo.objects.all() return render_to_response('Shots.html', {'p': p}) The following simple code in the template will generate associated images: {% for p in p %} <img src = "{{ p.display.url }}"> <img src = "{{ p.thumbnail_image.url }}"> {% endfor %} I'm attempting to generate a series of thumbnails {{ p.thumbnail_image.url }} which, when mouseover'd, will generate the slightly larger version of the image, {{ p.display.url }} via Javascript. The following code in the template attempts to do so: <html> <head> <HEAD> <script language="Javascript"> { image1 = new Image image2 = new Image image1.src = {{ p.thumbnail_image.url }} image2.src = {{ p.display.url }} </script> </head> <body> {% for p in p %} <a href="" onMouseOver="document.rollover.src= image2.src onMouseOut="document.rollover.src= image1.src"> <img src="{{ p.thumbnail_image.url }}" border=0 name="rollover"></a> {% endfor %} </body> </html> This will display the series of thumbnails, but the larger image will not display when mouseover'd. I believe it has to do with how I'm specifying the variable {{ p.display.url }}.

    Read the article

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

< Previous Page | 98 99 100 101 102 103 104 105 106 107 108 109  | Next Page >