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  • iPhone - sorting the results of a core data entity

    - by Digital Robot
    I have a core data entity that represents the attributes of a product, as number, price, etc. The product number is a NSString property and follows the form X.y where X is a number variable of digits and Y is one digit. For example. 132.2, 99.4, etc. I am querying the database to obtain the list of product numbers in order: The code is like this: + (NSArray*)todosOsItens:(NSString *)pName inManagedObjectContext:(NSManagedObjectContext *)context { Product *aProduct = [Product productWithName:pName inManagedObjectContext:context]; NSArray *all = nil; NSFetchRequest *request = [[NSFetchRequest alloc] init]; request.entity = [NSEntityDescription entityForName:@"Attributes" inManagedObjectContext:context]; request.predicate = [NSPredicate predicateWithFormat: @"(belongsTo == %@)", aProduct]; [request setResultType:NSDictionaryResultType]; [request setReturnsDistinctResults:YES]; [request setPropertiesToFetch:[NSArray arrayWithObject:item]]; NSSortDescriptor *sortByItem = [NSSortDescriptor sortDescriptorWithKey:@"ProductNumber" ascending:YES]; NSArray *sortDescriptors = [NSArray arrayWithObject:sortByItem]; [request setSortDescriptors:sortDescriptors]; NSError *error = nil; all = [[context executeFetchRequest:request error:&error] mutableCopy]; [request release]; return all; } but this query is not returning the sorted results. The results are coming on their natural order on the database. How do I do that? thanks.

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  • Things to take care while sending the username and password using Ajax request ?

    - by Anil Namde
    Normally we have login page with username, password filed and signin button. Using the normal form based approach we send the data on and page gets post back. Now i would like to change this using the Ajax. As Ajax too using the normal HTTP so i guess nothing in different from the existing workflow barring postback right ? Now my question is is what all securities issues can be there? and what care should be taken for doing so ? Should we encode data using say base64 or so before sending using Ajax?

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  • Is this the best way to make an API request using PHP CURL?

    - by Abs
    Hello all, I have a site that has a simple API which can be used via http. I wish to make use of the API and submit data about 1000-1500 times at one time. Here is their API: http://api.jum.name/ I have constructed the URL to make a submission but now I am wondering what is the best way to make these 1000-1500 API GET requests? Here is the PHP CURL implementation I was thinking of: $add = 'http://www.mysite.com/3rdparty/API/api.php?fn=post&username=test&password=tester&url=http://google.com&category=21&title=story a&content=content text&tags=Season,news'; curl_setopt ($ch, CURLOPT_URL, "$add"); curl_setopt ($ch, CURLOPT_POST, 0); curl_setopt ($ch, CURLOPT_COOKIEFILE, 'files/cookie.txt'); curl_setopt ($ch, CURLOPT_FOLLOWLOCATION, 0); curl_setopt ($ch, CURLOPT_RETURNTRANSFER, TRUE); $postdata = curl_exec ($ch); Shall I close the CURL connection every time I make a submission? Can I re-write the above in a better way that will make these 1000-1500 submissions quicker? Thanks all

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  • using ftpWebRequest with an error: the remote server returned error 530 not loged in

    - by user1361207
    I am trying to use the ftpWebRequest in c# my code is // Get the object used to communicate with the server. FtpWebRequest request = (FtpWebRequest)WebRequest.Create("ftp://192.168.20.10/file.txt"); request.Method = WebRequestMethods.Ftp.UploadFile; // This example assumes the FTP site uses anonymous logon. request.Credentials = new NetworkCredential("dev\ftp", "devftp"); // Copy the contents of the file to the request stream. StreamReader sourceStream = new StreamReader(@"\file.txt"); byte[] fileContents = Encoding.UTF8.GetBytes(sourceStream.ReadToEnd()); sourceStream.Close(); request.ContentLength = fileContents.Length; request.UsePassive = true; Stream requestStream = request.GetRequestStream(); requestStream.Write(fileContents, 0, fileContents.Length); requestStream.Close(); FtpWebResponse response = (FtpWebResponse)request.GetResponse(); Console.WriteLine("Upload File Complete, status {0}", response.StatusDescription); response.Close(); and I get an Error in request.GetRequestStream(); the error is: the remote server returned error 530 not loged in if I try to go in to a browser page and in the url I write ftp://192.168.20.10/ the brows page is asking me for a name and password, I put the same name and password and I see all the files and folders in the ftp folder. can any one help me with this problem?

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  • Access is denied. Javascript error on request to secured page

    - by ihorko
    On SomePage.aspx page by javascript (XMLHttpRequest) I call SecuredPage.aspx used next code: var httpRequest = GetXmlHttp(); var url = "https://myhost.com/SecuredPage.aspx"; var params = "param1=" + document.getElementById('param1').value + "&param2=" + document.getElementById('param2').value; httpRequest.open("POST", url, true); httpRequest.setRequestHeader("Content-Type", "application/x-www-form-urlencoded"); httpRequest.onreadystatechange = function() { //Call a function when the state changes. if (httpRequest.readyState == 4 && httpRequest.status == 200) { alert(httpRequest.responseText); } } httpRequest.send(params); // HERE ACCESS IS DENIED //--------------------------------------------- function GetXmlHttp() { var xmlhttp = false; if (window.XMLHttpRequest) { xmlhttp = new XMLHttpRequest(); } else if (window.ActiveXObject) // code for IE { try { xmlhttp = new ActiveXObject("Msxml2.XMLHTTP"); } catch (e) { try { xmlhttp = new ActiveXObject("Microsoft.XMLHTTP"); } catch (E) { xmlhttp = false; } } } return xmlhttp; } It throws Access is denied error. if send to http (http://myhost.com/SecuredPage.aspx), it works fine. How is it possible to resolve that problem. Thanks!

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  • Dealloc'd Predicate crashing iPhone App!

    - by DVG
    To preface, this is a follow up to an inquiry made a few days ago: http://stackoverflow.com/questions/2981803/iphone-app-crashes-when-merging-managed-object-contexts Short Version: EXC_BAD_ACCESS is crashing my app, and zombie-mode revealed the culprit to be my predicate embedded within the fetch request embedded in my Fetched Results Controller. How does an object within an object get released without an explicit command to do so? Long Version: Application Structure Platforms View Controller - Games View Controller (Predicated upon platform selection) - Add Game View Controller When a row gets clicked on the Platforms view, it sets an instance variable in Games View for that platform, then the Games Fetched Results Controller builds a fetch request in the normal way: - (NSFetchedResultsController *)fetchedResultsController{ if (fetchedResultsController != nil) { return fetchedResultsController; } //build the fetch request for Games NSFetchRequest *request = [[NSFetchRequest alloc] init]; NSEntityDescription *entity = [NSEntityDescription entityForName:@"Game" inManagedObjectContext:context]; [request setEntity:entity]; //predicate NSPredicate *predicate = [NSPredicate predicateWithFormat:@"platform == %@", selectedPlatform]; [request setPredicate:predicate]; //sort based on name NSSortDescriptor *sortDescriptor = [[NSSortDescriptor alloc] initWithKey:@"name" ascending:YES]; NSArray *sortDescriptors = [[NSArray alloc] initWithObjects:sortDescriptor, nil]; [request setSortDescriptors:sortDescriptors]; //fetch and build fetched results controller NSFetchedResultsController *aFetchedResultsController = [[NSFetchedResultsController alloc] initWithFetchRequest:request managedObjectContext:context sectionNameKeyPath:nil cacheName:@"Root"]; aFetchedResultsController.delegate = self; self.fetchedResultsController = aFetchedResultsController; [sortDescriptor release]; [sortDescriptors release]; [predicate release]; [request release]; [aFetchedResultsController release]; return fetchedResultsController; } At the end of this method, the fetchedResultsController's _fetch_request - _predicate member is set to an NSComparisonPredicate object. All is well in the world. By the time - (NSInteger)tableView:(UITableView *)tableView numberOfRowsInSection:(NSInteger)section gets called, the _predicate is now a Zombie, which will eventually crash the application when the table attempts to update itself. I'm more or less flummoxed. I'm not releasing the fetched results controller or any of it's parts, and the only part getting dealloc'd is the predicate. Any ideas?

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  • Request URL in Javascript, Fetch URL Content using Java Applet, return to Javascript?

    - by Sam G
    I'm in the process of making a little experiment, it grabs a YouTube page, and returns the highest quality MP4 link, then plays this in a HTML 5 Video element. Now I was using PHP with cURL to get the URL content (YouTube), but that only works on my local server (MP4 link is locked to IP address). I can't think of any other way to get the page content due to cross domain rules except a Java applet. So I've built a Java applet that should return the content of a URL. Java import java.applet.Applet; import java.awt.*; import java.io.ByteArrayOutputStream; import java.io.InputStream; import java.net.HttpURLConnection; import java.net.URL; public class URLFetcherabc extends Applet { public void init() { } public void paint(Graphics g) { g.drawString("Java loaded. Waiting for URL", 0, 10); } public String getURL(String url, String httpMethod) { try { URL u = new URL(url); HttpURLConnection conn = (HttpURLConnection)u.openConnection(); conn.setRequestMethod(httpMethod); InputStream is = conn.getInputStream(); ByteArrayOutputStream output = new ByteArrayOutputStream(); byte[] buffer = new byte[1024]; for (int bytesRead = 0; (bytesRead = is.read(buffer)) != -1; ) { output.write(buffer, 0, bytesRead); } return output.toString(); } catch (Exception e) { }return null; } } Now I've got the applet on the page, but every-time I call the function it returns nothing. Heres my HTML for including the applet. HTML <applet id="URLFetcher" name="URLFetcher" code="URLFetcherabc.class" archive="URLFetcher.jar" height="200" width="200" mayscript=""></applet> Java-Script function fetchurl(urltofetch) { var URLFetcher = document.getElementById("URLFetcher"); var result = URLFetcher.getURL(urltofetch); //Result = URL Content return result; } The function always returns null, in Java the function does work when passed a variable via other means (parameter etc). I've tried running other functions through Javascript and the Java applet does respond. I'm new to Java applets and communicating with them via Javascript, so I'm probably making either a small mistake somewhere or its completely wrong. Any ideas? Thanks

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  • Why did I get a 400 Bad Request when getting a page with PHP Curl?

    - by user307272
    Hi, I was trying to access a page using curl. I could access it perfectly using the browser and using "static" strings as the URL, like: $url = "http://www.example.com/?q=1234" But when I tried to access the page using a variable in the URL string like: $url = "http://www.example.com/?q=$param" I got a 400 error code. I checked out on the web and found some comments here in this stackoverflow thread: Then, just for curiosity I did the following: $url = "http://www.example.com/?q=" . trim($param); and it worked! And no, $param did NOT contain any spaces. To me, it seems that it can be some encoding error, but I really can't find an explanation for it. Does anyone here in stackoverflow know what it can possibly be? Thanks in advance :)

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  • How i finding Internate network error using Try..........Catch in iphone?

    - by Rajendra Bhole
    Hi, I developing an application in which i calling web services on iphone. I want to implement Try.......Catch in that code for catching internet and GPRS connection error.The code is as follow, NSMutableURLRequest *request = [[[NSMutableURLRequest alloc] init] autorelease]; [request setURL:[NSURL URLWithString:mainURL5]]; [request setHTTPMethod:@"POST"]; NSHTTPURLResponse* urlResponse = nil; NSError *error = [[[NSError alloc] init] autorelease]; NSData *responseData = [NSURLConnection sendSynchronousRequest:request returningResponse:&urlResponse error:&error]; result5 = [[NSMutableString alloc] initWithData:responseData encoding:NSUTF8StringEncoding]; I was using Try......catch but it didn't work that code as follows, @try { //prepar request NSMutableURLRequest *request = [[[NSMutableURLRequest alloc] init] autorelease]; [request setURL:[NSURL URLWithString:mainURL5]]; [request setHTTPMethod:@"POST"]; NSHTTPURLResponse* urlResponse = nil; NSError *error = [[[NSError alloc] init] autorelease]; NSData *responseData = [NSURLConnection sendSynchronousRequest:request returningResponse:&urlResponse error:&error]; result5 = [[NSMutableString alloc] initWithData:responseData encoding:NSUTF8StringEncoding]; } @catch(NSException * e) { [clsMessageBox ShowMessageOK:@"some text" :[e reason]]; }

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  • jquery ajax request is Forbidden in IE. How to fix (any workaround)?

    - by 1gn1ter
    <script type="text/javascript"> $(function () { $("select#oblast").change(function () { var oblast_id = $("#oblast > option:selected").attr("value"); $("#Rayondiv").hide(); $.ajax({ type: "GET", contentType: "application/json", url: "http://site.com/Regions.aspx/FindGorodByOblastID/", data: 'oblast_id=' + oblast_id, dataType: "json", success: function (data) { if (data.length > 0) { var options = ''; for (p in data) { var gorod = data[p]; options += "<option value='" + gorod.Id + "'>" + gorod.Name + "</option>"; } $("#gorod").removeAttr('disabled').html(options); } else { $("#gorod").attr('disabled', false).html(''); } } }); }); }); </script>

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  • Using routing (?) to make GET request in Rails so ID doesn't show

    - by ale
    I have a link in one view myapp/locations that goes to myapp/statistics?id=1 (statistics for location with ID 1) which works fine but it doesn't look pretty. I think I've seen people do this sort of thing without needing the ?id=1? I could use a POST but this is not RESTful. Is there a way I can use routing to allow the user to go to myapp/statistics?id=1 but have the user see myapp/statistics? Many thanks.

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  • How do I rewrite a request by hostname unless it is a specified value?

    - by Tim
    My app will have a regular domain - let's say example.com - which will have information about logging in, signing up, etc. It will also host numerous other domains dynamically. My app serves the webpage for these at http://example.com/site/foobar.com/ So, I need to redirect all requests where the hostname is not example.com to /site/[hostname]/ I'm writing this in Django and hosting with Apache. How do I set up a rewrite rule to do this? The user must not know they are on any other site but foobar.com and if the user browses to foobar.com/something - the URL must be rewritten to /site/foobar.com/something

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  • Has anyone properly interpreted HTTP request based on this demo of winpcap?

    - by httpinterpret
    The example is here, and I tried it by changing the filter to tcp and dst port 80 and the following: void packet_handler(u_char *param, const struct pcap_pkthdr *header, const u_char *pkt_data) { .... ip_len = (ih->ver_ihl & 0xf) * 4; tcp_len = (((u_char*)ih)[ip_len + 12] >> 4) * 4; tcpPayload = (u_char*)ih + ip_len + tcp_len; /* start of url - skip "GET " */ url = tcpPayload + 4; end_url = strchr((char*)url, ' '); url_length = end_url - url; final_url = (u_char*)malloc(url_length + 1); strncpy((char*)final_url, (char*)url, url_length); final_url[url_length] = '\0'; printf("%s\n", final_url); .... } But through debug, I see tcpPayload is full of messy code,not supposed "GET ..." stuff. What's wrong with my implement?

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  • problems piping in node.js

    - by alvaizq
    We have the following example in node.js var http = require('http'); http.createServer(function(request, response) { var proxy = http.createClient(8083, '127.0.0.1') var proxy_request = proxy.request(request.method, request.url, request.headers); proxy_request.on('response', function (proxy_response) { proxy_response.pipe(response); response.writeHead(proxy_response.statusCode, proxy_response.headers); }); setTimeout(function(){ request.pipe(proxy_request); },3000); }).listen(8081, '127.0.0.1'); The example listen to a request in 127.0.0.1:8081 and sends it to a dummy server (always return 200 OK status code) in 127.0.0.1:8083. The problem is in the pipe among the input stream (readable) and output stream (writable) when we have a async module before (in this case the setTimeOut timing). The pipe doesn't work and nothing is sent to dummy server in 8083 port. Maybe, when we have a async call (in this case the setTimeOut) before the pipe call, the inputstream change to a state "not readable", and after the async call the pipe doesn't send anything. This is just an example...we test it with more async modules from node.js community with the same result (ldapjs, etc)... We try to fix it with: - request.readable =true; //before pipe call - request.pipe(proxy_request, {end : false}); with the same result (the pipe doesn't work). Can anybody help us? Many thanks in advanced and best regards,

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  • How do you make the script wait for the status of an Ajax get request before continuing?

    - by codeninja
    Basically what I'm doing is checking for the existence of an object, if it's not found, the script will try to load the source file using getScript. I only want to check this once though then return true or false to the function that calls fetch() fetch:function(obj){ ... isReady = false; $.getScript(obj.srcFile,function(){ isReady=true; warn("was able to load object "+key); }); return isReady; } but return kicks in before the script loads =/ later the script is loaded but the function returned false. This is the beauty of asynchronous I suppose... What's the best way to handle this... Maybe I could check again at some other point if the object exists? Or maybe there's a better way to do this where I dont have to potentially lock the browser?

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  • noob: how to show login error message on the same page after php server processes request.

    - by funbar
    Hi, I have a login page. User first enters information and submits the form. And I have a php script that will see if the user exists. If( authenticated == true) { // I do a redirect } else { // I want to popup an error message on the same page. } 1) I'm not sure how to show the popup message, I would like to make my div element visible with an error message returned from the server, I would have to use Ajax, right? But how? Or are there alternatives which are just as good.

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  • Using Javascript to detect the bottom of the window and ignoring all events when a request is loading

    - by Aaron Reba
    I have an anonymous function to detect the user has scrolled to the bottom of the window. Inside of the anonymous function, I have a call to a database that takes a while to complete. var allowing_more = 1; $(window).scroll(function() { if (allowing_more == 1){ if ($(window).scrollTop() + $(window).height() == $(document).height()) { allowing_more = 0; //query allowing_more = 1; } } }); In this time, if the user scrolls to the bottom of the window again, it seems a queue is made holding the occurences the user scrolled to the bottom of the window while the query was loading. Upon completing of the query, these occurences are then executed. I have a boolean statement to detect if the anonymous function is accepting more query requests but this seems to be ignored. Is there some sort of way to ignore an anonymous function temporarily and re-enable it?

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  • Are all "GET" requests to JSF "Initial Request"s?

    - by Pradyumna
    Hi, In JSF 1.1, I am assuming that GET requests are treated as initial requests (resulting in the creation of a new view), and POST requests are treated as Postbacks (resulting in the restoration of the old view). However, my application is behaving differently - it restores the same old view even for GET requests. Why does this happen? Is there a way to force the creation of a new view for GET requests? (My state-saving method is 'server'. I'm using MyFaces with JSP, and I have a t:saveState on a managed bean in the view) Regards, Pradyumna

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  • Why each request with activerecord is doing SHOW TABLE?

    - by dynback.com
    My test page is processed if believe to trace in 46 ms, while 11 of them I am doing this 20:53:06.111597 system.db.CDbConnection Opening DB connection 20:53:06.118046 system.db.CDbCommand Querying SQL: SHOW COLUMNS FROM `questions` 20:53:06.122476 system.db.CDbCommand Querying SQL: SHOW CREATE TABLE `questions` Is this obligatory?

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  • How to write UIWebView with default request address is like (192.168.1.1)..

    - by user323503
    i have implemented UIWebView in my application but i default address is "192.168.1.1" but it is not open default it and i have tried with "http://www.google.com" it is working fine. [iview loadRequest:[NSURLRequest requestWithURL:[NSURL URLWithString:@"192.168.1.1"]]]; it doesn't working and it is working with [iview loadRequest:[NSURLRequest requestWithURL:[NSURL URLWithString:@"http://www.google.com"]]];

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  • How to send data many times to web browser in response to one request?

    - by robert_d
    I have a form on my web page, it allows to submit many queries to my website, every query is on a separate line in TextArea. Because waiting for all queries to complete is too long I would like to update the web page after every query completes - send result of one query to a web browser, new result should be appended to old results that are already on the web page. How to do this in ASP.NET MVC 2? I will be grateful for helpful responses.

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  • Access database Need to prevent from approving overlapping OT.Second Try with modified request Not a programmer [on hold]

    - by user2512764
    Employees Signups on company Website for advance overtime line. Access table already has overtime signups which does not require user to add the time but it requires only to add location as approved. Since this table has field Employee name, Date, start time and End time and location, All the fields has the data except for location. In the data base I have created a form based on this table. Since the table already have most of the information User only has to add location in the form field in order to approve overtime. Once user approves an overtime line for example: User approves overtime for employee name 'John' which starts on 7/1/2013 at 0400-0800, location is successfully added. When user tries to add location for John again which might has the start time for 7/1/2013 at 0600=0900. Again we are not entering Start time, End time and date it is already in the table. we are only entering location as approval. Soon user enters the location for John in the form field, since there is a conflict with previously overtime line which has already been approved. program needs to check employee name, date and time in previously approved (Added location) overtime line and The location in current record needs to be deleted and go to next record. I hope I have explained it in understandable format. Thank You,

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