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  • Django Aggregation Across Reverse Relationship

    - by Tom
    Given these two models: class Profile(models.Model): user = models.ForeignKey(User, unique=True, verbose_name=_('user')) about = models.TextField(_('about'), blank=True) zip = models.CharField(max_length=10, verbose_name='zip code', blank=True) website = models.URLField(_('website'), blank=True, verify_exists=False) class ProfileView(models.Model): profile = models.ForeignKey(Profile) viewer = models.ForeignKey(User, blank=True, null=True) created = models.DateTimeField(auto_now_add=True) I want to get all profiles sorted by total views. I can get a list of profile ids sorted by total views with: ProfileView.objects.values('profile').annotate(Count('profile')).order_by('-profile__count') But that's just a dictionary of profile ids, which means I then have to loop over it and put together a list of profile objects. Which is a number of additional queries and still doesn't result in a QuerySet. At that point, I might as well drop to raw SQL. Before I do, is there a way to do this from the Profile model? ProfileViews are related via a ForeignKey field, but it's not as though the Profile model knows that, so I'm not sure how to tie the two together. As an aside, I realize I could just store views as a property on the Profile model and that may turn out to be what I do here, but I'm still interested in learning how to better use the Aggregation functions.

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  • optimizing the jquery in django

    - by sankar
    I have done the following code which actually dynamically generate the values in the third list box using ajax and jquery concepts. Thoug it works, i need to optimize it. Below is the code i am working on now. <html> <head> <title>Comparison based on ID Number</title> <script src="http://code.jquery.com/jquery-latest.js"></script> </head> <body> {% if form.errors %} <p style="color: red;"> Please correct the error{{ form.errors|pluralize }} below. </p> {% endif %} <form action="/idnumber/" method="post" align= "center">{% csrf_token %} <p>Select different id numbers and the name of the <b> Measurement Group </b>to start the comparison</p> <table align = "center"> <tr> <th><label for="id_criteria_1">Id Number 1:</label></th> <th> {{ form.idnumber_1 }} </th> </tr> <tr> <th><label for="id_criteria_2">Id Number 2:</label></th> <th> {{ form.idnumber_2 }} </th> </tr> <tr> <th><label for="group_name_list">Group Name:</label></th> <th><select name="group_name_list" id="id_group_name_list"> <option>Select</option> </select> </th> </tr> <script> $('#id_idnumber_2').change( function get_group_names() { var value1 = $('#id_idnumber_1').attr('value'); var value2 = $(this).attr('value'); alert(value1); alert(value2); var request = $.ajax({ url: "/getGroupnamesforIDnumber/", type: "GET", data: {idnumber_1 : value1,idnumber_2 : value2}, dataType: "json", success: function(data) { alert(data); var myselect = document.getElementById("group_name_list"); document.getElementById("group_name_list").options.length = 1; var length_of_data = data.length; alert(length_of_data); try{ for(var i = 0;i < length_of_data; i++) { myselect.add(new Option(data[i].group_name, "i"), myselect.options[i]) //add new option to beginning of "sample" } } catch(e){ //in IE, try the below version instead of add() for(var i = 0;i < length_of_data; i++) { myselect.add(new Option(data[i].group_name, data[i].group_name)) //add new option to end of "sample" } } } }); }); </script> <tr align = "center"><th><input type="submit" value="Submit"></th></tr> </table> </form> </body> </html> everything works fine but there is a little problem in my code. (ie) my ajax function calls only when there is a change in the select list 2 (ie) 'id_number_2'. I want to make it call in such a way that which ever select box, the third list box should be updated automatically. Can anyone please help me on this with a possible logical solution

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  • How to make django test framework read from live database?

    - by lfborjas
    I realize there's a similar question here, but this one has a different approach: I have a django app that does queries over data indexed with djapian ; I'd like to write unit tests for this app's search component, and, obviously, I'd need the django settings module and all connections with the database active, so the test runner that django provides seems ideal. however, the django testing framework creates a dummy database and I'd hate to dump all my data to a fixture and then index it (the tests would take forever!); My data isn't at risk because the tests would only read from the database, so, how could this be achieved? -I'm new at this whole unit testing thing, so the solution of writing a new test runner I read in that similar question doesn't enlighten me a bit, at least not without some details

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  • Putting links into text in Django

    - by Dane Larsen
    I have a notifications app that generates notifications for users. The notification class has to be really general, because notifications are generated by all sorts of different things. My question is this: How do I insert links into the text of the notifications? What I tried was this: note = Notification(..., notification="""%s %s has accepted the task: <a href="/tasks/%d/">%s</a>.""" % (request.user.first_name, request.user.last_name, task.id, task.name), ...) In retrospect, it's obvious this wouldn't work. How should I go about this? Thanks in advance!

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  • Passing list of values to django view via jQuery ajax call

    - by finspin
    I'm trying to pass a list of numeric values (ids) from one web page to another with jQuery ajax call. I can't figure out how to pass and read all the values in the list. I can successfully post and read 1 value but not multiple values. Here is what I have so far: jQuery: var postUrl = "http://localhost:8000/ingredients/"; $('li').click(function(){ values = [1, 2]; $.ajax({ url: postUrl, type: 'POST', data: {'terid': values}, traditional: true, dataType: 'html', success: function(result){ $('#ingredients').append(result); } }); }); /ingredients/ view: def ingredients(request): if request.is_ajax(): ourid = request.POST.get('terid', False) ingredients = Ingredience.objects.filter(food__id__in=ourid) t = get_template('ingredients.html') html = t.render(Context({'ingredients': ingredients,})) return HttpResponse(html) else: html = '<p>This is not ajax</p>' return HttpResponse(html) With Firebug I can see that POST contains both ids but probably in the wrong format (terid=1&terid=2). So my ingredients view picks up only terid=2. What am I doing wrong? EDIT: To clarify, I need the ourid variable pass values [1, 2] to the filter in the ingredients view.

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  • How to disable translations during unit tests in django?

    - by Denilson Sá
    I'm using Django Internationalization tools to translate some strings from my application. The code looks like this: from django.utils.translation import ugettext as _ def my_view(request): output = _("Welcome to my site.") return HttpResponse(output) Then, I'm writing unit tests using the Django test client. These tests make a request to the view and compare the returned contents. How can I disable the translations while running the unit tests? I'm aiming to do this: class FoobarTestCase(unittest.TestCase): def setUp(self): # Do something here to disable the string translation. But what? # I've already tried this, but it didn't work: django.utils.translation.deactivate_all() def testFoobar(self): c = Client() response = c.get("/foobar") # I want to compare to the original string without translations. self.assertEquals(response.content.strip(), "Welcome to my site.")

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  • Asynchronous database update in Django?

    - by Mark
    I have a big form on my site. When the users fill it out and submit it, most of the data just gets dumped to the database, and then they get redirected to a new page. However, I'd also like to use the data to query another site, and then parse the results. That might take a bit longer. It's not essential that the user sees these results right away, so I was wondering if it's possible to asynchronously call a function that will handle this, and then return an HttpResponse from my view like usual without making them wait? If so... how? Any particular libraries I should look at?

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  • Downloading a csv file in django

    - by spyder
    I am trying to download a CSV file using HttpResponse to make sure that the browser treats it as an attachment. I follow the instructions provided here but my browser does not prompt a "Save As" dialog. I cannot figure out what is wrong with my function. All help is appreciated. dev savefile(request): try: myfile = request.GET['filename'] filepath = settings.MEDIA_ROOT + 'results/' destpath = os.path.join(filepath, myfile) response = HttpResponse(FileWrapper(file(destpath)), mimetype='text/csv' ) response['Content-Disposition'] = 'attachment; filename="%s"' %(myfile) return response except Exception, err: errmsg = "%s"%(err) return HttpResponse(errmsg) Happy Pat's day!

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  • Django model help

    - by dotty
    Does anyone have any clue why this doesn't work as expected. If i use the python shell and do team.game_set or team.games It returns an error AttributeError: 'Team' object has no attribute 'game' If i create a Game object and call game.home_team it returns the correct team object Heres my model class Team(models.Model): name = models.CharField(blank=True, max_length=100) class Game(models.Model): home_team = models.ForeignKey(Team, related_name="home_team")

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  • django forms from two tables referencial integrity

    - by dana
    i have a class named cv,and a class named university, and each user that completes his cv, should choose a University he studyes at. My problem is: one student can study at one or 2 or three universities, or may be a user that is not student. I need to take this data into a form, and i use ModelForm. The data from the Cv class, and from the University class in the same form, and the user can add one or more universities, or no university. (in the same form) How should i do it? Should i use ModelForm? if i have a foreign key in the CV class, and the user is not a student (so he is at zero universities), i may get an referencial integrity error. thanks a lot

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  • Django forms I cannot save picture file

    - by dana
    i have the model: class OpenCv(models.Model): created_by = models.ForeignKey(User, blank=True) first_name = models.CharField(('first name'), max_length=30, blank=True) last_name = models.CharField(('last name'), max_length=30, blank=True) url = models.URLField(verify_exists=True) picture = models.ImageField(help_text=('Upload an image (max %s kilobytes)' %settings.MAX_PHOTO_UPLOAD_SIZE),upload_to='jakido/avatar',blank=True, null= True) bio = models.CharField(('bio'), max_length=180, blank=True) date_birth = models.DateField(blank=True,null=True) domain = models.CharField(('domain'), max_length=30, blank=True, choices = domain_choices) specialisation = models.CharField(('specialization'), max_length=30, blank=True) degree = models.CharField(('degree'), max_length=30, choices = degree_choices) year_last_degree = models.CharField(('year last degree'), max_length=30, blank=True,choices = year_last_degree_choices) lyceum = models.CharField(('lyceum'), max_length=30, blank=True) faculty = models.ForeignKey(Faculty, blank=True,null=True) references = models.CharField(('references'), max_length=30, blank=True) workplace = models.ForeignKey(Workplace, blank=True,null=True) the form: class OpencvForm(ModelForm): class Meta: model = OpenCv fields = ['first_name','last_name','url','picture','bio','domain','specialisation','degree','year_last_degree','lyceum','references'] and the view: def save_opencv(request): if request.method == 'POST': form = OpencvForm(request.POST, request.FILES) # if 'picture' in request.FILES: file = request.FILES['picture'] filename = file['filename'] fd = open('%s/%s' % (MEDIA_ROOT, filename), 'wb') fd.write(file['content']) fd.close() if form.is_valid(): new_obj = form.save(commit=False) new_obj.picture = form.cleaned_data['picture'] new_obj.created_by = request.user new_obj.save() return HttpResponseRedirect('.') else: form = OpencvForm() return render_to_response('opencv/opencv_form.html', { 'form': form, }, context_instance=RequestContext(request)) but i don't seem to save the picture in my database... something is wrong, and i can't figure out what :(

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  • Django i18n and SEO

    - by etam
    Hi, how do you prepare i18n in your websites? I mean what do you do avoid the situation when you search for i18ned websites in Polish you get English description cause English is the default one. Thanks in advance, Etam.

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  • Using a backwards relation (i.e FOO_set) for ModelChoiceField in Django

    - by Bwmat
    I have a model called Movie, which has a ManyToManyField called director to a model called Person, and I'm trying to create a form with ModelChoiceField like so: class MovieSearchForm(forms.Form): producer = forms.ModelChoiceField(label='Produced by', queryset=movies.models.Person.producer_set, required=False) but this seems to be failing to compile (I'm getting a ViewDoesNotExist exception for the view that uses the form, but it goes away if I just replace the queryset with all the person objects), I'm guessing because '.producer_set' is being evaluated too 'early'. How can I get this work? here are the relevant parts of the movie/person classes: class Person(models.Model): name = models.CharField(max_length=100) class Movie(models.Model): ... producer = models.ForeignKey(Person, related_name="producers") director = models.ForeignKey(Person, related_name="directors") What I'm trying to do is get ever Person who is used in the producer field of some Movie.

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  • django access to parent

    - by SledgehammerPL
    model: class Product(models.Model): name = models.CharField(max_length = 128) (...) def __unicode__(self): return self.name class Receipt(models.Model): name = models.CharField(max_length=128) (...) components = models.ManyToManyField(Product, through='ReceiptComponent') def __unicode__(self): return self.name class ReceiptComponent(models.Model): product = models.ForeignKey(Product) receipt = models.ForeignKey(Receipt) quantity = models.FloatField(max_length=9) unit = models.ForeignKey(Unit) def __unicode__(self): return unicode(self.quantity!=0 and self.quantity or '') + ' ' + unicode(self.unit) + ' ' + self.product.genitive And now I'd like to get list of the most often useable products: ReceiptComponent.objects.values('product').annotate(Count('product')).order_by('-product__count' the example result: [{'product': 3, 'product__count': 5}, {'product': 6, 'product__count': 4}, {'product': 5, 'product__count': 3}, {'product': 7, 'product__count': 2}, {'product': 1, 'product__count': 2}, {'product': 11, 'product__count': 1}, {'product': 8, 'product__count': 1}, {'product': 4, 'product__count': 1}, {'product': 9, 'product__count': 1}] It's almost what I need. But I'd prefer having Product object not product value, because I'd like to use this in views.py for generating list.

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  • Django forms I cannot save picture file

    - by dana
    i have the model: class OpenCv(models.Model): created_by = models.ForeignKey(User, blank=True) first_name = models.CharField(('first name'), max_length=30, blank=True) last_name = models.CharField(('last name'), max_length=30, blank=True) url = models.URLField(verify_exists=True) picture = models.ImageField(help_text=('Upload an image (max %s kilobytes)' %settings.MAX_PHOTO_UPLOAD_SIZE),upload_to='jakido/avatar',blank=True, null= True) bio = models.CharField(('bio'), max_length=180, blank=True) date_birth = models.DateField(blank=True,null=True) domain = models.CharField(('domain'), max_length=30, blank=True, choices = domain_choices) specialisation = models.CharField(('specialization'), max_length=30, blank=True) degree = models.CharField(('degree'), max_length=30, choices = degree_choices) year_last_degree = models.CharField(('year last degree'), max_length=30, blank=True,choices = year_last_degree_choices) lyceum = models.CharField(('lyceum'), max_length=30, blank=True) faculty = models.ForeignKey(Faculty, blank=True,null=True) references = models.CharField(('references'), max_length=30, blank=True) workplace = models.ForeignKey(Workplace, blank=True,null=True) objects = OpenCvManager() the form: class OpencvForm(ModelForm): class Meta: model = OpenCv fields = ['first_name','last_name','url','picture','bio','domain','specialisation','degree','year_last_degree','lyceum','references'] and the view: def save_opencv(request): if request.method == 'POST': form = OpencvForm(request.POST, request.FILES) # if 'picture' in request.FILES: file = request.FILES['picture'] filename = file['filename'] fd = open('%s/%s' % (MEDIA_ROOT, filename), 'wb') fd.write(file['content']) fd.close() if form.is_valid(): new_obj = form.save(commit=False) new_obj.picture = form.cleaned_data['picture'] new_obj.created_by = request.user new_obj.save() return HttpResponseRedirect('.') else: form = OpencvForm() return render_to_response('opencv/opencv_form.html', { 'form': form, }, context_instance=RequestContext(request)) but i don't seem to save the picture in my database... something is wrong, and i can't figure out what :(

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  • Structure for Django methods that span different models

    - by Duncan
    I have two models (say A and B) which are independent and have independent methods. I want to add some methods that operate on both models though. for example, addX() will create an object from both models A and B. What's the best way to structure code in this situation, since it doesnt make sense to have the method belong to either of the models methods. Is the standard to write a service for the kind of 'abstract' model?

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  • django forms overwrite data when saved

    - by dana
    If a have a form, with the data from a user, let's say a CV, and i save the data from the form into a database, but i don't want that a CV from the same user to be stored in the database more than once(when edited form instance) I want it to be overwritten every time it is saved by one same user. How can i do it? thanks a lot

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  • django modeling

    - by SledgehammerPL
    Concept: Drinks are made of components. E.g. 10ml of Vodka. In some receipt the component is very particular (10ml of Finlandia Vodka), some not (10 ml of ANY Vodka). I wonder how to model a component to solve this problem - on stock I have particular product, which can satisfy more requirements. The model for now is: class Receipt(models.Model): name = models.CharField(max_length=128) (...) components = models.ManyToManyField(Product, through='ReceiptComponent') def __unicode__(self): return self.name class ReceiptComponent(models.Model): product = models.ForeignKey(Product) receipt = models.ForeignKey(Receipt) quantity = models.FloatField(max_length=9) unit = models.ForeignKey(Unit) class Admin: pass def __unicode__(self): return unicode(self.quantity!=0 and self.quantity or '') + ' ' + unicode(self.unit) + ' ' + self.product.genitive class Product(models.Model): name = models.CharField(max_length = 128) (...) class Admin: pass def __unicode__(self): return self.name class Stock(Store): products = models.ManyToManyField(Product) class Admin: pass def __unicode__(self): return self.name I think about making some table which joins real product (on stock) with abstract product (receiptcomponent). But maybe there's easy solution?

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  • Can a python view template be made to be 'safe/secure' if I make it user editable?

    - by Blankman
    Say I need to have a templating system where a user can edit it online using an online editor. So they can put if tags, looping tags etc., but ONLY for specific objects that I want to inject into the template. Can this be made to be safe from security issues? i.e. them somehow outputing sql connection string information or scripting things outside of the allowable tags and injected objects.

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  • Image depending on the text in Python/Django

    - by PyOut
    Hello, How can I find an image, depending on the text? I have image model with keywords: class Post(models.Model): image = ImageField(_('Image'), blank=True, upload_to='folder') keywords = models.CharField(_('Keywords'), max_length=80) And model which will serve as the search for a suitable image class TextSearch(models.Model): body = models.TextField(_('Text'))

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  • Creating a db driven primary navigation in django?

    - by Fedor
    I find that it's pretty common most people hardcode the navigation into their templates, but I'm dealing with a pretty dynamic news site which might be better off if the primary nav was db driven. So I was thinking of having a Navigation model where each row would be a link. link_id INT primary key link_name varchar(255) url varchar(255) order INT active boolean If anyone's done something similar in the past, would you say this sort of schema is good enough? I also wanted for there to be an optional dropdown in the admin near the url field so that a user could choose a Category model's slug since category links would be common, but I'm not quite sure how that would be possible.

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  • After getting the 'It worked!' page with Djangoappengine, what do I do next?

    - by Jacques Bosch
    I followed the Djangoappengine instructions. I used their django-testapp and copied the following folders in the django-testapp folder according to what I understood the instructions to say: django djangoappengine djangotoolbox I then started the dev server by running: manage.py runserver Then navigated to http://localhost:8000/ and got the "It worked!" page, which is great, but it says the following at the bottom: You're seeing this message because you have DEBUG = True in your Django settings file and you haven't configured any URLs. Get to work! I am an absolute beginner with Django and App Engine and Djangoappengine and Django-nonrel, so I am pretty lost. How do I configure URLs? Or a link to the how to will help. I took a look at the Django tutorial, but am unsure how much of it is relevant to Djangoappengine and Django-nonrel as a lot of the starting steps have to do with SQL databases. Basically some direction on how to get my app running will be great. Thanx much.

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  • Django - Check users messages every request

    - by Hanpan
    Hi, I want to check if a user has any new messages each time they load the page. Up until now, I have been doing this inside of my views but it's getting fairly hard to maintain since I have a fair number of views now. I assume this is the kind of thing middleware is good for, a check that will happen every single page load. What I need it to do is so: Check if the user is logged in If they are, check if they have any messages Store the result so I can reference the information in my templates Has anyone ever had to write any middleware like this? I've never used middleware before so any help would be greatly appreciated.

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