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  • Move MySQL master

    - by Noodles
    I currently have a master db server (lets call it db1) and 6 slaves (slave1-6). I've setup a new server (db2) as a slave of db1 and it's in sync. I want to change all the slaves to use db2 instead of db1, but with minimal downtime/data loss. At the moment the only way I can think of doing it is shutting down our website (so data stops being written to db1), waiting until all the slaves are up to date, flush logs on db1, shut it down. Reset master on db2, change all slaves to point to db2 with log position = 0. Is this the right way to do it or is there a way to do it without taking the site offline?

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  • How do I mirror a MySQL database?

    - by user45745
    I'm running two load balanced servers for one website, and I'd like the databases to be synchronized. Queries may be run on either of the two servers because they are both production sites, so the replication can't just work one way. It doesn't have to be in real-time, just fairly accurate so people don't notice a difference when they get switched to a different server.

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  • Realtime website slowness (PHP/MYSQL)

    - by 3s2ng
    We got a website with realtime transactions. The past few days we experienced some slowness during a period of time. Usually the slowness last for 5 minutes. And also during the slowness we noticed that sometimes we can not connect to SSH and FTP or sometimes very slow to connect to those services. Currently we are trying to identify the issue. We already setup database monitoring tool. Now are about to signup with pingdom.com My question is. If the website is too slow due to the database (table or row lock) will it affect the other services like SSH and FTP? Does the ping correlates the page load and the connection between my PC and server? Thanks, Mark

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  • How to filter a mysql database with user input on a website and then spit the filtered table back to the website? [migrated]

    - by Luke
    I've been researching this on google for literally 3 weeks, racking my brain and still not quite finding anything. I can't believe this is so elusive. (I'm a complete beginner so if my terminology sounds stupid then that's why.) I have a database in mysql/phpmyadmin on my web host. I'm trying to create a front end that will allow a user to specify criteria for querying the database in a way that they don't have to know sql, basically just combo boxes and checkboxes on a form. Then have this form 'submit' a query to the database, and show the filtered tables. This is how the SQL looks in Microsoft Access: PARAMETERS TEXTINPUT1 Text ( 255 ), NUMBERINPUT1 IEEEDouble; // pops up a list of parameters for the user to input SELECT DISTINCT Table1.Column1, Table1.Column2, Table1.Column3,* // selects only the unique rows in these three columns FROM Table1 // the table where this query is happening WHERE (((Table1.Column1) Like TEXTINPUT1] AND ((Table1.Column2)<=[NUMBERINPUT1] AND ((Table1.Column3)>=[NUMBERINPUT1])); // the criteria for the filter, it's comparing the user input parameters to the data in the rows and only selecting matches according to the equal sign, or greater than + equal sign, or less than + equal sign What I don't get: WHAT IN THE WORLD AM I SUPPOSED TO USE (that isn't totally hard)!? I've tried google fusion tables - doesn't filter right with numerical data or empty cells in rows, can't relate tables I've tried DataTables.net, can't filter right with numerical data and can't use SQL without a bunch of indepth knowledge, not even sure it can if you have that.. I've looked into using jQuery with google spreadsheets, doesn't work at all either I have no idea how I'm supposed to build a front end with my database. Every place that looks promising (like zohocreator) is asking for money, and is far too simplified to be able to do the LIKE criteria or SELECT DISTINCT stuff.

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  • How do you setup Postfix/Dovecot/MySQL to not look for local accounts?

    - by thiesdiggity
    I am having an issue with one of my Postfix/Dovecot mail servers and I'm unsure how to fix the problem. I will try to explain it in detail, here it goes: I have an Ubuntu server setup using Virtual hosting with Postfix, Dovecot and MySQL. We have one domain setup as a virtual domain, for this example I am going to use mail.example.com. Under that domain we have one email address. I have another server (MS Exchange) setup using another one of my sub-domains, ex.example.com. The problem is that when I SMTP into the account on mail.example.com and try to send an email to an account on ex.example.com, I get the email returned back to us with an "unknown host" error. Now, I know that the mail.example.com server can resolve the ex.example.com domain because I can ping/dig while SSH'd into it. I can also log into Postfix via Telnet and send an email to an ex.example.com mailbox. I'm guessing that it has something to do with Postfix/Dovecot looking locally for the domain in the virtual domain list because of the tld domain (example.com)? If that's the case, how do I get Postfix/Dovecot to only look locally for the entire URL (mail.example.com) and if it doesn't find it, send it to the correct server by looking up the MX/A records (which I know exist and are setup correctly)? I have been working on this all day and any guidance would be GREATLY appreciated! Thanks for your time!

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  • PHP Code (modules) included via MySQL database, good idea?

    - by ionFish
    The main script includes "modules" which add functionality to it. Each module is set up like this: <?php //data collection stuff //(...) approx 80 lines of code //end data collection $var1 = 'some data'; $var2 = 'more data'; $var3 = 'other data'; ?> Each module has the same exact variables, just the data collection is different. I was wondering if it's a reasonable idea to store the module data in MySQL like this: [database] |_modules |_name |_function (the raw PHP data from above) |_description |_author |_update-url |_version |_enabled ...and then include the PHP-data from the database and execute it? Something like, a tab-navigation system at the top of the page for each module name, then inside each of those tabs the page content would function by parsing the database-stored code of the module from the function section. The purpose would be to save code space (fewer lines), allow for easy updates, and include/exclude modules based on the enabled option. This is how many other web-apps work, some of my own too. But never had I thought about this so deeply. Are there any drawbacks or security risks to this?

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  • Random Alpha numeric generator

    - by AAA
    Hi, I want to give our users in the database a unique alpha-numeric id. I am using the code below, will this always generate a unique id? Below is the old and updated version of the code: New php: // Generate Guid function NewGuid() { $s = strtoupper(md5(uniqid("something",true))); $guidText = substr($s,0,8) . '-' . substr($s,8,4) . '-' . substr($s,12,4). '-' . substr($s,16,4). '-' . substr($s,20); return $guidText; } // End Generate Guid $Guid = NewGuid(); echo $Guid; echo "<br><br><br>"; Old PHP: // Generate Guid function NewGuid() { $s = strtoupper(md5(uniqid("something",true))); $guidText = substr($s,0,8) . '-' . substr($s,8,4) . '-' . substr($s,12,4). '-' . substr($s,16,4). '-' . substr($s,20); return $guidText; } // End Generate Guid $Guid = NewGuid(); echo $Guid; echo "<br><br><br>"; Will this first code guarantee uniqueness?

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  • Multiple JOIN and SELECT Statements from eight tables

    - by user1486004
    I am trying to make an SQL statement that takes eight different numbers and searches eight different tables from one database for the corresponding value. I keep getting invalid syntax, but I can't figure out why. Here is my code: SELECT cable_length.ID, drawing.ID, optional.ID, output_type.ID, pressure_range.ID, pressure_type.ID, series.ID, termination.ID FROM ( SELECT value AS cable_length FROM A1 WHERE A1.id = %s JOIN SELECT value AS drawing FROM A2 WHERE A2.id = %s, JOIN SELECT value AS optional FROM A3 WHERE A3.id = %s, JOIN SELECT value AS output_type FROM A4 WHERE A4.id = %s, JOIN SELECT value AS pressure_range FROM A5 WHERE A5.id = %s, JOIN SELECT value AS pressure_type FROM A6 WHERE A6.id = %s, JOIN SELECT value AS series FROM A7 WHERE A7.id = %s, JOIN SELECT value AS termination FROM A8 WHERE A8.id = %s ); The %s will be changed to numbers only. The column name in each database is "ID" and "Value". I want to search by "ID" and return "Value". Any help is greatly appreciated.

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  • PHP MySQL Update query

    - by Jordan Pagaduan
    I have a website that has an update query. Example. Table name - myTable Table Content - id(AI) name -- myName age -- 13 image -- (no values) birthdate -- (no values) I only put values in name and age. In image and birthdate, I haven't put anything. If I edit it and update it and I don't put anything in name and in age, I only put values in image and in birthdate. The output is like this. (This ouput I wanted) Table name - myTable Table Content - id(AI) name -- myName age -- 13 image -- myImage.jpg birthdate -- Feb. 31, 2010 This is my code: <?php //mysql connect... //mysql select database... $sql = "UPDATE myTable SET name = '".$name."', age = '".$age."', image = '".$image."', birthdate"'$birthdate.."' WHERE id = $id"; mysql_query($sql); ?> I used this code but the output is: Table name - myTable Table Content - id(AI) name -- (no values) age -- (no values) image -- myImage.jpg birthdate -- Feb. 31, 2010 Feel free to ask if you don't understand my question Thank you

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  • What is wrong with my PHP/MySQL code?

    - by James
    I am building a navigation menu which lists all my categories and subcategories. The problem is it returns only one of these and not all. I have the categories echoed inside the while loop so I'm not sure why it's only showing one result and not all: <?php $query = mysql_query("SELECT * FROM categories_parent"); while ($row = mysql_fetch_assoc($query)) { $id = $row['id']; $name = $row['name']; $slug = $row['slug']; $childStatus = $row['child_status']; // if has child categories if ($childStatus == "1") { echo "<li class='dir'><a href='category.php?slug=$slug'>$name</a>"; echo "<ul id='dropdown'>"; $query = mysql_query("SELECT * FROM categories_child WHERE parent=$id"); while ($row = mysql_fetch_assoc($query)) { $id = $row['id']; $name = $row['name']; $slug = $row['slug']; echo "<li><a href='category.php?slug=$slug'>$name</a></li>"; } echo "</ul>"; echo "</li>"; } // if singular parent else { echo "<li><a href='category.php?slug=$slug'>$name</a></li>"; } } ?> My database tables: -- -- Table structure for table `categories_child` -- CREATE TABLE IF NOT EXISTS `categories_child` ( `id` int(11) NOT NULL AUTO_INCREMENT, `name` varchar(1000) NOT NULL, `slug` varchar(1000) NOT NULL, `parent` int(11) NOT NULL, PRIMARY KEY (`id`) ) ENGINE=MyISAM DEFAULT CHARSET=latin1 AUTO_INCREMENT=139 ; -- -- Dumping data for table `categories_child` -- INSERT INTO `categories_child` (`id`, `name`, `slug`, `parent`) VALUES (138, 'Britney Spears', 'category/celiberties/britney-spears/', 137), (136, 'Tigers', 'category/animals/tigers/', 136), (137, 'Horses', 'category/animals/horses/', 136), (135, 'Lions', 'category/animals/lions/', 136); -- -- Table structure for table `categories_parent` -- CREATE TABLE IF NOT EXISTS `categories_parent` ( `id` int(11) NOT NULL AUTO_INCREMENT, `name` varchar(1000) NOT NULL, `slug` varchar(1000) NOT NULL, `child_status` int(1) NOT NULL DEFAULT '0', PRIMARY KEY (`id`) ) ENGINE=MyISAM DEFAULT CHARSET=latin1 AUTO_INCREMENT=139 ; -- -- Dumping data for table `categories_parent` -- INSERT INTO `categories_parent` (`id`, `name`, `slug`, `child_status`) VALUES (137, 'Celiberties', 'category/celiberties/', 1), (138, 'TV Shows', 'category/tv-shows/', 0), (136, 'Animals', 'category/animals/', 1);

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  • What's wrong with my MySql query ?!

    - by Anytime
    This is a query I am doing with mysql using PHP This is the query line <?php $query = "SELECT * FROM node WHERE type = 'student_report' AND uid = '{$uid}' LIMIT 1 ORDER BY created DESC"; ?> I get the following error You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'ORDER BY created DESC' at line 1

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  • mysql error using Rails-- Please help

    - by Cypher
    Alright I am sry for the noob question but this has been driving me up a wall-especially because I got it to work yesterday and I can't remember what I did.... I am just trying to use mysql with rails with a mongrel server. I set up the server fine and can run rails applications that don't need mysql but when I create a project using (for example) rails -d mysql blog and then create some simple controller e.g. ruby script/generate Test then put this code in the controller... class TestController < ApplicationController def index render :text => 'WORK' end end then when I start the server up and open up localhost:3000/test I get the following error: = Booting Mongrel = Rails 2.3.5 application starting on http://0.0.0.0:3000 = Call with -d to detach = Ctrl-C to shutdown server /!\ FAILSAFE /!\ Mon May 10 20:15:06 -0500 2010 Status: 500 Internal Server Error Can't connect to MySQL server on 'localhost' (10061) C:/Ruby/lib/ruby/gems/1.8/gems/activerecord-2.3.5/lib/active_record/connection_adapter s/mysql_adapter.rb:589:in 'real_connect' C:/Ruby/lib/ruby/gems/1.8/gems/activerecord-2.3.5/lib/active_record/connection_adapter s/mysql_adapter.rb:589:in 'connect' C:/Ruby/lib/ruby/gems/1.8/gems/activerecord-2.3.5/lib/active_record/connection_adapter s/mysql_adapter.rb:203:in 'initialize' C:/Ruby/lib/ruby/gems/1.8/gems/activerecord-2.3.5/lib/active_record/connection_adapter s/mysql_adapter.rb:75:in 'new' C:/Ruby/lib/ruby/gems/1.8/gems/activerecord-2.3.5/lib/active_record/connection_adapter s/mysql_adapter.rb:75:in 'mysql_connection' C:/Ruby/lib/ruby/gems/1.8/gems/activerecord-2.3.5/lib/active_record/connection_adapter s/abstract/connection_pool.rb:223:in 'send' C:/Ruby/lib/ruby/gems/1.8/gems/activerecord-2.3.5/lib/active_record/connection_adapter s/abstract/connection_pool.rb:223:in 'new_connection' C:/Ruby/lib/ruby/gems/1.8/gems/activerecord-2.3.5/lib/active_record/connection_adapter s/abstract/connection_pool.rb:245:in 'checkout_new_connection' C:/Ruby/lib/ruby/gems/1.8/gems/activerecord-2.3.5/lib/active_record/connection_adapter s/abstract/connection_pool.rb:188:in 'checkout' C:/Ruby/lib/ruby/gems/1.8/gems/activerecord-2.3.5/lib/active_record/connection_adapter s/abstract/connection_pool.rb:184:in 'loop' C:/Ruby/lib/ruby/gems/1.8/gems/activerecord-2.3.5/lib/active_record/connection_adapter s/abstract/connection_pool.rb:184:in 'checkout' C:/Ruby/lib/ruby/1.8/monitor.rb:242:in 'synchronize' C:/Ruby/lib/ruby/gems/1.8/gems/activerecord-2.3.5/lib/active_record/connection_adapter s/abstract/connection_pool.rb:183:in 'checkout' C:/Ruby/lib/ruby/gems/1.8/gems/activerecord-2.3.5/lib/active_record/connection_adapter s/abstract/connection_pool.rb:98:in 'connection' C:/Ruby/lib/ruby/gems/1.8/gems/activerecord-2.3.5/lib/active_record/connection_adapter s/abstract/connection_pool.rb:326:in 'retrieve_connection' C:/Ruby/lib/ruby/gems/1.8/gems/activerecord-2.3.5/lib/active_record/connection_adapter s/abstract/connection_specification.rb:123:in 'retrieve_connection' C:/Ruby/lib/ruby/gems/1.8/gems/activerecord-2.3.5/lib/active_record/connection_adapter s/abstract/connection_specification.rb:115:in 'connection' etc... In the browser i get a 'We're sorry, but something went wrong' Does anyone know what I am doing wrong?

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  • Delphi - MySQL Best Data aware components to use

    - by Brad
    I need my applicaiton to connect to my web server's MySQL database, what is the best option for this. Perfered Data aware Component. I tried zeos 7, but I keep getting the error: SQL error: Client does not support authentication protocal requested by server; consider upgrading MySQL client and have not been able to fix it. Thanks -Brad

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  • Slug ID's with the same name?

    - by James Jeffery
    I want to create slug URL's from a users title in my system. If a user types "The best way's to get slim; period!", then I want the slug to be "the-best-ways-to-get-slim-period". Also, if someone has already created a page with that title I want the slug to be "the-best-ways-to-get-slim-period-1". My question is how can I check the database before a record is created? Ok, obviously I am going to have to perform a check in the database, and then a write. That's 2 queries. Is this the normal way to do it? Also, are there any conventional regular expressions for filtering non alpha/number characters and replacing spaces with hyphens? Any help is much appreciated. Thanks.

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  • Zend Server with xampp MySQL

    - by Vincent
    I am running Zend Server,Zend Studio (Trial versions) on Ubuntu 9.10. I am also using xampp to do most of my development. I plan to use Zend Server only to do URL profiling to know function level performance of my code. Is it possible to configure Zend Server to use XAMPP's MySQL database instead of installing a new mysql instance for Zend Server? Thanks

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  • Using preg_replace in mysql

    - by Roshan
    I have a CMS content in database. The content contains '<img src= .............../>' also. I want to retrieve this content using mysql query and show on frontend but with all '<img src='.........../>' removed from the content. How can it be done using query in mysql?

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  • Can we use JCR API over MySQL?

    - by n_mysql
    Apache Jackrabbit (or the JCR API) helps you separate the data store from the data management system. This would mean that every data store provider would have to implement the JCR API for his own data store. The question is JCR implemented for MySQL? Can we use the JCR API over MySQL? I want to truly abstract out where i store my content, so that tomorrow if i don't want to use a relational DB i can swap it out with the file system with ease.

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