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  • Flex - Increase timeout on a PHP service function call

    - by Travesty3
    I'm using Flash Builder 4 Beta 2. I have it connecting to a PHP service. The way I set this up was using the wizard, so I didn't actually write the code to connect to it. The service looks like this: package services.flash { import mx.rpc.AsyncToken; import com.adobe.fiber.core.model_internal; import mx.rpc.AbstractOperation; import valueObjects.CustomDatatype8; import valueObjects.NewUsageData; import mx.collections.ItemResponder; import mx.rpc.remoting.RemoteObject; import mx.rpc.remoting.Operation; import com.adobe.fiber.services.wrapper.RemoteObjectServiceWrapper; import com.adobe.fiber.valueobjects.AvailablePropertyIterator; import com.adobe.serializers.utility.TypeUtility; [ExcludeClass] internal class _Super_FLASH extends RemoteObjectServiceWrapper { // Constructor public function _Super_FLASH() { // initialize service control _serviceControl = new RemoteObject(); var operations:Object = new Object(); var operation:Operation; operation = new Operation(null, "sendCommand"); operation.resultType = Object; operations["sendCommand"] = operation; ... } } One of the functions that I'm calling fetches users from a MySQL database. There are about 30,000 users right now. The service seems to timeout when fetching more than around 22,000 rows, I get the "Channel Disconnected before an acknowledgement was received" error. If I call the PHP script from a browser, it fetches them all with no problems at all, however. I have tried increasing the timeout in the PHP script (which didn't work), but obviously this isn't the problem since the browser is able to pull them up with no problems. Is there a way to increase the timeout of the PHP service in Flash Builder? I'm a bit of a noob when it comes to Flash, so please be descriptive. Thanks in advance!

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  • Using PHP to display button with hyperlink or greyed out button if no URL in database

    - by Diane
    I've got a webpage that I'm working on where you click on a letter or category and it displays records matching that query from a database. One of the things I want to display is a hyperlinked button that says "Website" if the database record contains a URL in the 'URL' field, and if there is no value in that field, it will display a greyed out version of that button. I tried using an if...else statement, but was absolutely unable to get the syntax correct trying to get php to call up the 'URL' value in the middle of an "echo " So here's what I did: <?php if($row_rsmemalpha['URL'] != NULL) ?><a href="http://<?php echo ($row_rsmemalpha['URL']);?>"><target ="_blank"><img src="web_button_on.gif" alt="Website" border="0" height="18" width="103" /></target></a> <?php if($row_rsmemalpha['URL'] == NULL) echo "<img src=\"web_button_off.gif\" alt=\"No Website Available\" height=\"18\" width=\"103\" />"; ?> If there is a URL available it shows the button properly. But if there isn't a URL in the database it shows both buttons. I have spent a few days studying examples and tutorials on the web, but haven't found too much that helps. The buttons were completely non-functional when I started, so I'm pretty proud of getting this far with it! I've just run out of time and patience for more trial-and-error experimenting. Any help is appreciated... Diane

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  • Nusphere PHPEd: PHP Function Hints Lost Arguments?

    - by Eli
    Hi All, My PHPEd suddenly stopped showing arguments and arg order in the hints, and now just shows a basic description of the function. Before I go digging around in the config files, has anyone else had this problem? Thanks! Edit: Sorry, I may not have been entirely clear on this. There is no problem with my own classes, only with the actual php functions. Example: How it used to work: I type a PHP function, say strpos. As soon as I type the '(' at the end of it, I get the little yellow box, showing something like this: int strpos ( string $haystack , mixed $needle [, int $offset=0 ] ) with the first argument bold. If I type it, and then a comma, it bolds the second arg, and so on. This is really nice, since PHP functions are a bit scrambled as far as argument order, and I don't have to look them up every time. How it works now: I type a php function, say strpos. As soon as I type the '(' at the end of it, I get the little yellow box. It says something like "strpos - Returns the numeric position of the first occurrence of needle in the haystack string." There are no arguments shown, which makes the little box basically worthless - I know what strpos does, I just want a reminder of the argument order. I think this may be a problem with the included PHPDoc, which I never use, but may be the source of the data for the hint box. I did recently upgrade to 5.6, but ended up removing it and restoring 5.2. I installed to a different folder, and uninstalled from there, but it may have overwritten something in the original folder? I'm using v5.2 (5220). Thanks!

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  • Checking parameter classes in PHP

    - by Professor Elm
    At the moment, I have the following: <?php if ($custom != ""): ?> <div class="head-row5" id="custom"> <?php print $custom?> </div><?php //head-row5 ?> <?php endif; ?> What is returned is something like.... <div class="block block-block" id="block-block-15"> <div class="title"> <h3></h3> </div> <div class="content"><p style="text-align: center;"><a href="website linkage" id="T2roll"><span class="alt">Name of the linked page</span></a></p> </div> What I'm trying to do is find a way to print this out ONLY if the is true. How would I go about doing this? I believe that I'm going to have to check the elements by class of this $custom parameter. However, I have no idea how to go about doing this.

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  • php file path of server

    - by Jacksta
    I am trying to get this script to work. it opens up a directry and lists the files in the directory. I have copied this code from somewhere else and the problem is that this php file is hosted on an apache server not my localhost. what is the correct $dir_name = "c:/"; to use? The file is in this directory /domains/domainxxxx.com.au/public_html/lsitfiles.php so would I use domainxxxx.com.au/public_html/lsitfiles.php ? <?php $dir_name = "c:/"; $dir = opendir($dir_name); $file_list = "<ul>"; while ($file_name = readdir($dir)) { if(($file_name != ".") && (file_name != "..")) { $file_list .= "<li>$file_name"; } } $file_list.= "<ul>"; closedir($dir); ?> <HTML> <BODY> <p>Files in: <? echo "$dir_name"; ?></p> <? echo "$file_list"; ?> </BODY> </HTML>

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  • Run a PHP script every second using CLI

    - by Saif Bechan
    Hello, I have a dedicated server running Cent OS with a Parallel PLESK panel. I need to run a php script every second, that updates my database. These is no alternative way timewise, i have checked every method, it needs to be updated every second. I can find my script using the url: http://www.mysite.com/phpfile.php?key=123, and this has to be executed every second. Does anyone have any knowledge at all on doing this, i can not seem to find the answer. I heard about doing it with CLI and putty, but i have no knowledge of this at all. Or can this be done using the PLESK Panel? And can the file be executed locally every second. Like \phpfile.php If someone helps me on answering these question i would really appreciate it. Regards EDIT It has been a few months since i added this question. I ended up using the following code: #!/user/bin/php $start = microtime(true); set_time_limit(60); for (i = 0; i < 59; ++$i) { doMyThings(); time_sleep_until($start + $i + 1); } Thank you for this code guys! My cronjob is set to every minute. I have been running this for some time now in a test environment, and this works out great. It works really supperfast, and i see no increase in CPU nor Memory usage.

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  • sending email in php unable to use HTML tags

    - by JPro
    I am trying to send an email through the result sets generated in MySQL in PHP This is the code. <?php $txtMsg = '<table><th>Name</th>'; $txtMsg = ''; mysql_connect("localhost", "root", "pop") or die(mysql_error()); mysql_select_db("jpd") or die(mysql_error()); $oustanding = mysql_query("select Name from results") or die(mysql_error()); $num=mysql_num_rows($oustanding); while($row1 = mysql_fetch_array( $oustanding )) { ?> <tr> <td><h3><?php echo $row1['Name']; ?></h3></td> </tr> <?php $txtMsg .= "<tr><td>".$row1['Name']."</td></tr>"; } ini_set ( "SMTP", "xy.domain.com" ); $mail_to= '[email protected]'; $mail_from='[email protected]'; $mail_sub='OutStanding Results'; $mail_mesg=$txtMsg; //Check for success/failure of delivery if(mail($mail_to,$mail_sub,$mail_mesg,"From: $mail_from")) echo "<br><br>Email Successfully Sent!"; else echo "<br><br>Error Sending Email!"; } ?> The problem is , I want the results to be displayed in table format. But instead of processing the html tags, they are getting printed as well. How to get the email with table format? Thanks.

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  • Send POSTs to a PHP script on a server

    - by Sam Jarman
    I have a PHP script on a server <?php // retrieve POST vars $comment = $_POST['comment']; $email = $_POST['email']; // remove trailing whitespace etc $comment = trim($comment); $email = trim($email); // format date accoring to http://www.w3schools.com/php/func_date_date.asp $date_time = date("Y-m-d-H-i-s"); // i.e. 2010-04-15-09-45-23 // prepare message $to = "(removed my email addy)"; //who to send the mail to $subject = "Feedback from iPhone app"; //what to put in the subject line $message = "Name/Email: $email \r\n Comment: $comment"; mail($to, $subject,$message) or "bad"; echo "ok"; ?> How do I now send a POST request from my iPhone app... ive tried this sort of thing... NSURL *url = [NSURL URLWithString:@"mysite.com/script.php"]; NSMutableURLRequest *request = [NSMutableURLRequest requestWithURL:url]; [request setHTTPMethod:@"POST"]; NSString *message = boxForSuggestion.text; NSString *userEmailString = usersEmail.text; NSString *requestBodyString = [NSString stringWithFormat:@"comment:%@&email%@", message , userEmailString]; NSData *requestBody = [requestBodyString dataUsingEncoding:NSUTF8StringEncoding]; [request setHTTPMethod:@"POST" [request setHTTPBody:requestBody]; NSURLResponse *response = NULL; NSError *requestError = NULL; NSData *responseData = [NSURLConnection sendSynchronousRequest:request returningResponse:&response error:&requestError]; NSString *responseString = [[[NSString alloc] initWithData:responseData encoding:NSUTF8StringEncoding] autorelease]; NSLog(@"%@", responseString); Any ideas? Thanks guys Sam

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  • PHP - Best practice to retain form values across postback

    - by Adam
    Hello, Complete PHP novice here, almost all my previous work was in ASP.NET. I am now working on a PHP project, and the first rock I have stumbled upon is retaining values across postback. For the most simple yet still realistic example, i have 10 dropdowns. They are not even databound yet, as that is my next step. They are simple dropdowns. I have my entire page inclosed in a tag. the onclick() event for each dropdown, calls a javascript function that will populate the corrosponding dropdowns hidden element, with the dropdowns selected value. Then, upon page reload, if that hidden value is not empty, i set the selected option = that of my hidden. This works great for a single postback. However, when another dropdown is changed, the original 1'st dropdown loses its value, due to its corrosponding hidden value losing its value as well! This draws me to look into using querystring, or sessions, or... some other idea. Could someone point me in the right direction, as to which option is the best in my situation? I am a PHP novice, however I am being required to do some pretty intense stuff for my skill level, so I need something flexable and preferribly somewhat easy to use. Thanks! -----edit----- A little more clarification on my question :) When i say 'PostBack' I am referring to the page/form being submitted. The control is passed back to the server, and the HTML/PHP code is executed again. As for the dropdowns & hiddens, the reason I used hidden variables to retain the "selected value" or "selected index", is so that when the page is submitted, I am able to redraw the dropdown with the previous selection, instead of defaulting back to the first index. When I use the $_POST[] command, I am unable to retrieve the dropdown by name, but I am able to retrieve the hidden value by name. This is why upon dropdown-changed event, I call javascript which sets the selected value from the dropdown into its corrosponding hidden.

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  • ajax to php to curl and back..

    - by pfunc
    I am trying to make an ajax call to a php script. The php script calls an rss feed using curl, gets the data, and returns the data to the funciton. I keep getting an error "Warning: Wrong parameter count for curl_error() in" .... Here is my php code:1 $ch = curl_init() or die(curl_error()); curl_setopt($ch, CURLOPT_URL, $feed); curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1); $data1 = curl_exec($ch) or die(curl_error()); echo $data1; and the ajax call: $.ajax({ url: "getSingleFeed.php", type: "POST", data: "feedURL=" + window.feedURL, success: function(feed){ alert(feed); }}); I tested all the variables, they are being passed correctly, I can echo them out. But this line: $data1 = curl_exec($ch) or die(curl_error()); is what is giving me the error. I am doing the same thing with curl on other pages, just without ajax, and it is working fine. Is there anything special I need to do with ajax to do this?

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  • how to put links in php

    - by user225269
    <?php> while($row = mysql_fetch_array($result2)) { echo "<tr>"; echo "<td>" . $row['IDNO'] . "</td>"; echo "<td>" . $row['ADDRESS'] . "</td>"; echo "<td>" . $row['LASTNAME'] . "</td>"; echo "<td>" . $row['FIRSTNAME'] . "</td>"; echo "<td>" . <a href='update.php'>view</a> . "</td>"; echo "</tr>"; } echo "</table>"; } ?> That's my code, I really don't know the correct format of putting links inside the php tags: echo "<td>" . <a href='update.php'>view</a> . "</td>"; Please help

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  • Facebook Application with PHP running loosing session

    - by ArneRie
    Iam trying to build an Facebook Application based on PHP. The Application is running under php on my own Webhost inside an Canvas as iFrame. I have included the newest Client Library for PHP from Facebook: facebook-php-sdk-94fcb13 To Authorize the user inside my application iam trying to use Facebook Connect, like the example shipped with the Client. Everything works fine the 1st Login, but when i hit the F5 Key to reload the page, the session is lost and i have to login again. When i call my application outside of the Facebook Canvas everything is fine. Iam not sure, but i think my Browser (Chrome/FireFox - Ubuntu) is not allowing to store an cookie inside an iFrame. Does someone knows an solution for this Problem? Here are some Parts of the Sourcecode: $facebook = new Facebook(array( 'appId' => 'x', 'secret' => 'x', 'cookie' => 'true', )); $session = $facebook->getSession(); $facebook->setSession($session); $me = null; // Session based API call. if ($session) { try { $uid = $facebook->getUser(); $me = $facebook->api('/me'); } catch (FacebookApiException $e) { error_log($e); } } // login or logout url will be needed depending on current user state. if ($me) { $logoutUrl = $facebook->getLogoutUrl(); } else { $loginUrl = $facebook->getLoginUrl(); }

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  • PHP: Profiling code and strict environment ~ Improving my coding

    - by DavidYell
    I would like to update my local working environment to be stricter in an effort to improve my code. I know that my code is okay, but as with most things there is always room for improvement. I use XAMPP on my local machine, for simplicities sake Apache Friends XAMPP (Basic Package) version 1.7.2 So I've updated my php.ini : error_reporting to be E_ALL | E_STRICT to help with the code standard. I've also enabled the XDebug extension zend_extension = "C:\xampp\php\ext\php_xdebug.dll" which seems to be working, having tested some broken code and got the nice standard orange error notice. However, having read this question, http://stackoverflow.com/questions/133686/what-is-the-best-way-to-profile-php-code and enabled the profiler, I cannot seem to create a cachegrind file. Many of the guides that I've looked at seem to think you need to install XDebug in XAMPP which leads me to think they are out of date, as XDebug is bundled with XAMPP these days. So I would appreciate it if anyone can help point me in the right direction with both configuring XDebug to output grind files, and or just a great set of default settings for the XDebug config in XAMPP. Seems there is very little documentation to go on. If people have tips on integrating these tools with Netbeans, that would be awesomesauce. I'm happy to get suggestions on other things that I can do to help tighten up my php code, both syntactically and performance wise Thanks, and apologies for the rambling question(s)! Ninja edit I should menion that I'm using named vhosts as my Apache configuration, which I think is why running XDebug on port 9000 isn't working for me. I guess I'd need to edit my vhost to include port 9000

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  • Downloading attachments to directory with IMAP in PHP, randomly works

    - by Nick
    I found PHP code online to download attachments to a directory using IMAP from here. http://www.nerdydork.com/download-pop3imap-email-attachments-with-php.html I modified it slightly changing $structure = imap_fetchstructure($mbox, $jk); $parts = ($structure->parts); to $structure = imap_fetchstructure($mbox, $jk); $parts = ($structure); to get it to run properly, as otherwise I got an error about how stdClass doesn't define a property called $parts. Doing that, I was able to download all the attachments. I tested it again recently though, and it didn't work. Well, it didn't work 6 times, worked the 7th, and then hasn't worked since. I'm thinking it has something to do with me screwing up the parts handling, since count($parts) keeps returning 1 for each message, so it's not finding any attachments I think. Since it downloaded the attachments at one point with no issues, I feel confident that the area things are getting screwed up is right here. Before this block of code is a for loop that goes through each message in the box, and after it is loop that just goes through $parts for each imap structure. Thanks for any help you can provide. I looked at the imap_fetchstructure page on php.net and can't figure out what I'm doing wrong. Edit: I just double-checked the folder after typing up my question and it all popped up. I feel like I'm going nuts. I hadn't run the code since a few minutes before I started typing this, and it doesn't make sense to me that it would take this long to trigger. I have some 800 messages in the mailbox, but I figured since it printed my statement at the very end of the PHP that all of the file creation work was done.

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  • PHP Serialize Function - Adding serialized data to mysql and then fetch and display

    - by Abhilash Shukla
    I want to know whether the PHP serialize function is 100% secure, also if we store serialized data into a database and want to do something after fetching it, will it be a nice way. For example:- I have a website with different user privileges, now i want to store the permissions settings for a particular privilege to my database (This data i want to store is to be done through php serialize function), now when a user logs in i want to fetch this data and set the privilege for the customer. Now i am ok to do this thing, what i want to know is, whether it is the best way to do or something more efficient can be done. Also, i was going through php manual and found this code, can anybody explain me a bit what's happening in this code:- [Specially why base64_encode is used?] <?php mySerialize( $obj ) { return base64_encode(gzcompress(serialize($obj))); } myUnserialize( $txt ) { return unserialize(gzuncompress(base64_decode($txt))); } ?> Also if somebody can provide me their own code to show me to do this thing in the most efficient manner. Thanks.

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  • php insert doesnot take place

    - by reggie
    my code is as follows <?php include("config.php"); $ip=$_SERVER['REMOTE_ADDR']; if($_POST['id']) { $id=$_POST['id']; $id = mysql_escape_String($id); $ip_sql=mysql_query("select ip_add from Voting_IP where mes_id_fk='$id' and ip_add='$ip'"); $count=mysql_num_rows($ip_sql); if($count==0) { $sql = "update Messages set up=up+1 where mes_id='$id'"; mysql_query($sql); $sql_in = "insert into Voting_IP (mes_id_fk,ip_add) values ('$id','$ip')"; mysql_query($sql_in) or die(mysql_error()); echo "<script>alert('Thanks for the vote');</script>"; } else { echo "<script>alert('You have already voted');</script>"; } $result=mysql_query("select up from Messages where mes_id='$id'"); $row=mysql_fetch_array($result); $up_value=$row['up']; echo "<img src='button.png' width='110' height='90'>"; echo $up_value; } ?> My problem is that the insert process doesnot take place at all. the script tags echos an alert box. even the img tag is echoed to the web page. but the insert process doesnot take place. the config file is fine.. note: this code works on my local machine which has php 5.3 but it doesnot work on the server which has php 5.2.. any advice..???

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  • Generating dynamic css using php and javascript

    - by Onkar Deshpande
    I want to generate tooltip based on a dynamically changing background image in css. This is my my_css.php file. <?php header('content-type: text/css'); $i = $_GET['index']; if($i == 0) $bg_image_path = "../bg_red.jpg"; elseif ($i == 1) $bg_image_path = "../bg_yellow.jpg"; elseif ($i == 2) $bg_image_path = "../bg_green.jpg"; elseif ($i == 3) $bg_image_path = "../bg_blue.jpg"; ?> .tooltip { white-space: nowrap; color:green; font-weight:bold; border:1px solid black;; font-size:14px; background-color: white; margin: 0; padding: 7px 4px; border: 1px solid black; background-image: url(<?php echo $bg_image_path; ?>); background-repeat:repeat-x; font-family: Helvetica,Arial,Sans-Serif; font-family: Times New Roman,Georgia,Serif; filter:alpha(opacity=85); opacity:0.85; zoom: 1; } In order to use this css I added <link rel="stylesheet" href="css/my_css.php" type="text/css" media="screen" /> in my html <head> tag of javascript code. I am thinking of passing different values of 'index' so that it would generate the background image dynamically. Can anyone tell me how should I pass such values from a javascript ? I am creating the tooltip using var tooltip = document.createElement("div"); document.getElementById("map").appendChild(tooltip); tooltip.style.visibility="hidden"; and I think before calling this createElement, I should set background image.

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  • share the same cookie between two website using PHP cURL extension

    - by powerboy
    I want to get the contents of some emails in my gmail account. I would like to use the PHP cURL extension to do this. I followed these steps in my first try: In the PHP code, output the contents of https://www.google.com/accounts/ServiceLoginAuth. In the browser, the user input username and password to login. In the PHP code, save cookies in a file named cookie.txt. In the PHP code, send request to https://mail.google.com/ along with cookies retrieved from cookie.txt and output the contents. The following code does not work: $login_url = 'https://www.google.com/accounts/ServiceLoginAuth'; $gmail_url = 'https://mail.google.com/'; $cookie_file = dirname(__FILE__) . '/cookie.txt'; $ch = curl_init(); curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, false); curl_setopt($ch, CURLOPT_HEADER, false); curl_setopt($ch, CURLOPT_POST, true); curl_setopt($ch, CURLOPT_RETURNTRANSFER, true); curl_setopt($ch, CURLOPT_FOLLOWLOCATION, true); curl_setopt($ch, CURLOPT_COOKIEJAR, $cookie_file); curl_setopt($ch, CURLOPT_URL, $login_url); $output = curl_exec($ch); echo $output; curl_setopt($ch, CURLOPT_URL, $gmail_url); curl_setopt($ch, CURLOPT_COOKIEFILE, $cookie_file); $output = curl_exec($ch); echo $output; curl_close($ch);

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  • how can we store php variables in jquery variables in jquery part

    - by surya
    $('#b').bind('click',function(){ alert('hii'); var slide_start=slider_content.indexOf(0); if(slide_start==2) { $('#reg_rem_form').hide(); } var show=1+slide_start; var show_first='#'+show; **var value_to_insert=<?php echo $value;? >=$(show_first).val();** <?php /* 1. Date of birth 2. gender 3. Unvi1 4. Unvi2 5. highest degree unvi1 6. highest degree unvi2 7. Year of passing unvi1 8. Year of passing unvi2 9. Current working 10. Work experience */ ?> Just as we store php variables in jquery variables , same thing but in reverse i want to store jquery variables in php variables ??? The highlighted part is the main line. how to do that , above code giving me the error === missing ";" before statement. Is this right way to do this =$('#bold').val();

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  • Need help with a PHP proxy script

    - by blabus
    I’m currently working on a small web app that allows people to search for music album covers. However, I’m having a problem getting my PHP proxy to work. Right now I’m using a simple PHP proxy script to grab the HTML from Google’s image result page, and parse it to find the first image result (I can’t use the image search API because it doesn’t offer the parameters that I need to use). I know that the PHP script works in some way, because I’ve used it to grab XML data across domains, so I also assume that since I’m trying to grab HTML that’s what’s causing the error. So anyway, here is the site where you can see it: http://www.5byfive.net/beta/index.html Just type something into the textbox, and it will come up with the error that’s returned (I’ve placed the HTML into a file so you can see what it actually looks like here: http://www.5byfive.net/beta/error.html ). Now, I’ve tried searching for info on the web, but unfortunately I basically know nothing about PHP, so I really don’t know how to fix it, and was wondering if anyone here could lend any info or help. Thanks!

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  • Javascript Confirm Delete in One PHP File (on href)

    - by gamerzfuse
    <p><span class="linky"><a href="deletephone.php?id=' . $row['id'] . '">Delete Phone</a></span></p><br /> I have the above code that I am using to link to a delete script. I want to somehow incorporate Javascript with a simple onclick confirmation. This way if they choose OK, I can run the code to delete the item from the database, but if they choose Cancel then I can cancel the operation and do nothing. I have tried a whole variety of functions with changing the window.location to the delete file, and trying to cancel the href= if they choose Cancel, but it always goes to the link regardless of what the user clicks. I would like to be able to keep the delete functions inside the same PHP file if possible, but this is not necessary at all. Thanks in advance! ASIDE: If there is a simple PHP way to check IF the alert was confirmed or denied, that could work also. Any way to check what the user chooses and then run my simple delete PHP command.

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  • PHP: Best solution for links breaking in a mod_rewrite app

    - by psil
    I'm using mod rewrite to redirect all requests targeting non-existent files/directories to index.php?url=* This is surely the most common thing you do with mod_rewrite yet I have a problem: Naturally, if the page url is "mydomain.com/blog/view/1", the browser will look for images, stylesheets and relative links in the "virtual" directory "mydomain.com/blog/view/". Problem 1: Is using the base tag the best solution? I see that none of the PHP frameworks out there use the base tag, though. I'm currently having a regex replace all the relative links to point to the right path before output. Is that "okay"? Problem 2: It is possible that the server doesn't support mod_rewrite. However, all public files like images, stylesheets and the requests collector index.php are located in the directory /myapp/public. Normally mod_rewrite points all request to /public so it seems as if public was actually the root directory too all users. However if there is no mod_rewrite, I then have to point the users to /public from the root directory with a header() call. That means, however that all links are broken again because suddenly all images, etc. have to be called via /public/myimage.jpg Additional info: When there is no mod_rewrite the above request would look like this: mydomain.com/public/index.php/blog/view/1 What would be the best solutions for both problems?

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  • PHP's openssl_sign generates different signature than SSCrypto's sign

    - by pascalj
    I'm writing an OS X client for a software that is written in PHP. This software uses a simple RPC interface to receive and execute commands. The RPC client has to sign the commands he sends to ensure that no MITM can modify any of them. However, as the server was not accepting the signatures I sent from my OS X client, I started investigating and found out that PHP's openssl_sign function generates a different signature for a given private key/data combination than the Objective-C SSCrypto framework (which is only a wrapper for the openssl lib): SSCrypto *crypto = [[SSCrypto alloc] initWithPrivateKey:self.localPrivKey]; NSData *shaed = [self sha1:@"hello"]; [crypto setClearTextWithData:shaed]; NSData *data = [crypto sign]; generates a signature like CtbkSxvqNZ+mAN... The PHP code openssl_sign("hello", $signature, $privateKey); generates a signature like 6u0d2qjFiMbZ+... (For my certain key, of course. base64 encoded) I'm not quite shure why this is happening and I unsuccessfully experimented with different hash-algorithms. As the PHP documentation states SHA1 is used by default. So why do these two functions generate different signatures and how can I get my Objective-C part to generate a signature that PHPs openssl_verify will accept? Note: I double checked that the keys and the data is correct!

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  • Help with PHP simplehtmldom - Modifiying a form.

    - by onemyndseye
    Ive gotten some great help here and I am so close to solving my problem that I can taste it. But I seem to be stuck. I need to scrape a simple form from a local webserver and only return the lines that match a users local email (i.e. onemyndseye@localhost). simplehtmldom makes easy work of extracting the correct form element: foreach($html->find('form[action*="delete"]') as $form) echo $form; Returns: <form action="/delete" method="post"> <input type="checkbox" id="D1" name="D1" /><a href="http://www.linux.com/rss/feeds.php"> http://www.linux.com/rss/feeds.php </a> [email: onemyndseye@localhost (Default) ]<br /> <input type="checkbox" id="D2" name="D2" /><a href="http://www.ubuntu.com/rss.xml"> http://www.ubuntu.com/rss.xml </a> [email: onemyndseye@localhost (Default) ]<br /> However I am having trouble making the next step. Which is returning lines that contain 'onemyndseye@localhost' and removing it so that only the following is returned: <input type="checkbox" id="D1" name="D1" /><a href="http://www.linux.com/rss/feeds.php">http://www.linux.com/rss/feeds.php</a> <br /> <input type="checkbox" id="D2" name="D2" /><a href="http://www.ubuntu.com/rss.xml">http://www.ubuntu.com/rss.xml</a> <br /> Thanks to the wonderful users of this site Ive gotten this far and can even return just the links but I am having trouble getting the rest... Its important that the complete <input> tags are returned EXACTLY as shown above as the id and name values will need to be passed back to the original form in post data later on. Thanks in advance!

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  • PHP File Upload using url parameters

    - by Arthur
    Is there a way to upload a file to server using php and the filename in a parameter (instead using a submit form), something like this: myserver/upload.php?file=c:\example.txt Im using a local server, so i dont have problems with filesize limit or upload function, and i have a code to upload file using a form <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "DTD/xhtml1-transitional.dtd"> <html> <body> <form action="<?php echo $_SERVER['PHP_SELF']; ?>" method="post" name="fileForm" enctype="multipart/form-data"> File to upload: <table> <tr><td><input name="upfile" type="file"></td></tr> <tr><td><input type="submit" name="submitBtn" value="Upload"></td></tr> </table> </form> <?php if (isset($_POST['submitBtn'])){ // Define the upload location $target_path = "c:\\"; // Create the file name with path $target_path = $target_path . basename( $_FILES['upfile']['name']); // Try to move the file from the temporay directory to the defined. if(move_uploaded_file($_FILES['upfile']['tmp_name'], $target_path)) { echo "The file ". basename( $_FILES['upfile']['name']). " has been uploaded"; } else{ echo "There was an error uploading the file, please try again!"; } } ?> </body> Thanks for the help

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