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  • C Static Function Confusion

    - by Lime
    I am trying to make the s_cord_print function visible in the cord_s.c file only. Currently the function is visible/runnable in main.c even when it is declared static. How do I make the s_cord_print function private to cord_s.c? Thanks! s_cord.c typedef struct s_cord{ int x; int y; struct s_cord (*print)(); } s_cord; void* VOID_THIS; #define $(EL) VOID_THIS=&EL;EL static s_cord s_cord_print(){ struct s_cord *THIS; THIS = VOID_THIS; printf("(%d,%d)\n",THIS->x,THIS->y); return *THIS; } const s_cord s_cord_default = {1,2,s_cord_print}; main.c #include <stdio.h> #include <stdlib.h> #include "s_cord.c" int main(){ s_cord mycord = s_cord_default; mycord.x = 2; mycord.y = 3; $(mycord).print().print(); //static didn't seem to hide the function s_cord_print(); return 0; } ~

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  • Managing a log stream in C++ in a cout-like notation

    - by Andry
    Hello! I have a class in c++ in order to write log files for an application of mine. I have already built the class and it works, it is something like this: class Logger { std::string _filename; public: void print(std::string tobeprinted); } Well, it is intuitive that, in order to print a line in the log file, for an object of Logger, it is simply necessary to do the following: Logger mylogger("myfile.log"); mylogger.print(std::string("This is a log line")); Well. Using a method approach is not the same as using a much better pattern like << is. I would like to do the following: Logger mylogger("myfile.log"); mylogger << "This is a log line"; That's all. I suppose I must overload the << operator... But overloading using this signature (the classic one): ostream& operator<<(ostream& output, const MyObj& o); But I do not have a ostream... So, should I do as follows? Logger& operator<<(Logger& output, const std::string& o); Is this the right way? Thanks

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  • lua metatable __lt __le __eq forced boolean conversion of return value

    - by chris g.
    Overloading __eq, __lt, and __le in a metatable always converts the returning value to a boolean. Is there a way to access the actual return value? This would be used in the following little lua script to create an expression tree for an argument usage: print(_.a + _.b - _.c * _.d + _.a) -> prints "(((a+b)-(c*d))+a)" which is perfectly what I would like to have but it doesn't work for print(_.a == _.b) since the return value gets converted to a boolean ps: print should be replaced later with a function processing the expression tree -- snip from lua script -- function binop(op1,op2, event) if op1[event] then return op1[event](op1, op2) end if op2[event] then return op2[event](op1, op2) end return nil end function eq(op1, op2)return binop(op1,op2, "eq") end ... function div(op1, op2)return binop(op1,op2, "div") end function exprObj(tostr) expr = { eq = binExpr("=="), lt = binExpr("<"), le = binExpr("<="), add = binExpr("+"), sub=binExpr("-"), mul = binExpr("*"), div= binExpr("/") } setmetatable(expr, { __eq = eq, __lt = lt, __le = le, __add = add, __sub = sub, __mul = mul, __div = div, __tostring = tostr }) return expr end function binExpr(exprType) function binExprBind(lhs, rhs) return exprObj(function(op) return "(" .. tostring(lhs) .. exprType .. tostring(rhs) .. ")" end) end return binExprBind end function varExpr(obj, name) return exprObj(function() return name end) end _ = {} setmetatable(_, { __index = varExpr }) -- snap -- Modifing the lua vm IS an option, however it would be nice if I could use an official release

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  • Is safe ( documented behaviour? ) to delete the domain of an iterator in execution

    - by PoorLuzer
    I wanted to know if is safe ( documented behaviour? ) to delete the domain space of an iterator in execution in Python. Consider the code: import os import sys sampleSpace = [ x*x for x in range( 7 ) ] print sampleSpace for dx in sampleSpace: print str( dx ) if dx == 1: del sampleSpace[ 1 ] del sampleSpace[ 3 ] elif dx == 25: del sampleSpace[ -1 ] print sampleSpace 'sampleSpace' is what I call 'the domain space of an iterator' ( if there is a more appropriate word/phrase, lemme know ). What I am doing is deleting values from it while the iterator 'dx' is running through it. Here is what I expect from the code : Iteration versus element being pointed to (*): 0: [*0, 1, 4, 9, 16, 25, 36] 1: [0, *1, 4, 9, 16, 25, 36] ( delete 2nd and 5th element after this iteration ) 2: [0, 4, *9, 25, 36] 3: [0, 4, 9, *25, 36] ( delete -1th element after this iteration ) 4: [0, 4, 9, 25*] ( as the iterator points to nothing/end of list, the loop terminates ) .. and here is what I get: [0, 1, 4, 9, 16, 25, 36] 0 1 9 25 [0, 4, 9, 25] As you can see - what I expect is what I get - which is contrary to the behaviour I have had from other languages in such a scenario. Hence - I wanted to ask you if there is some rule like "the iterator becomes invalid if you mutate its space during iteration" in Python? Is it safe ( documented behaviour? ) in Python to do stuff like this?

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  • Anything wrong with my cURL code (http status of 0)?

    - by Ilya
    Consistently getting a status of 0 even though if I copy and paste the url sent into my browser, I get a json object right back <?php $mainUrl = "https://api.xxxx.com/?"; $co = "xxxxx"; $pa = "xxxx"; $par = "xxxx"; $part= "xxxx"; $partn = "xxxx"; $us= "xxx"; $fields_string; $fields = array( 'co'=>urlencode($co), 'pa'=>urlencode($pa), 'par'=>urlencode($par), 'part'=>urlencode($part), 'partn'=>urlencode($partn), 'us'=>urlencode($us) ); foreach($fields as $key=>$value) { $fields_string .= $key . '=' . $value . '&' ;} $fields_string = rtrim($fields_string, "&"); $fields_string = "?" . $fields_string; $url = "https://api.xxxxx.com/" . $fields_string; $request = $url; $ch = curl_init(); curl_setopt($ch, CURLOPT_URL, $url); curl_setopt($ch, CURLOPT_RETURNTRANSFER,1); curl_setopt($ch, CURLOPT_TIMEOUT,'3'); $content = trim(curl_exec($ch)); $http_status = curl_getinfo($ch, CURLINFO_HTTP_CODE); curl_close($ch); print $url; print $http_status; print $content; ?>

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  • Java Detect Variable Change Using PropertyChangeSupport and PropertyChangeListener

    - by Sam
    I'm trying to print out debug statements when some third party code changes a variable. For example, consider the following: public final class MysteryClass { private int secretCounter; public synchronized int getCounter() { return secretCounter; } public synchronized void incrementCounter() { secretCounter++; } } public class MyClass { public static void main(String[] args) { MysteryClass mysteryClass = new MysteryClass(); // add code here to detect calls to incrementCounter and print a debug message } I don't have the ability to change the 3rd party MysteryClass, so I thought that I could use PropertyChangeSupport and PropertyChangeListener to detect changes to the secretCounter: public class MyClass implements PropertyChangeListener { private PropertyChangeSupport propertySupport = new PropertyChangeSupport(this); public MyClass() { propertySupport.addPropertyChangeListener(this); } public void propertyChange(PropertyChangeEvent evt) { System.out.println("property changing: " + evt.getPropertyName()); } public static void main(String[] args) { MysteryClass mysteryClass = new MysteryClass(); // do logic which involves increment and getting the value of MysteryClass } } Unfortunately, this did not work and I have no debug messages printed out. Does anyone see what is wrong with my implementation of the PropertyChangeSupport and Listener interfaces? I want to print a debug statement whenever incrementCounter is called or the value of secretCounter changes.

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  • I need to make a multithreading program (python)

    - by Andreawu98
    import multiprocessing import time from itertools import product out_file = open("test.txt", 'w') P = ['a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j', 'k', 'l', 'm', 'n', 'o', 'p','q', 'r', 's', 't', 'u', 'v', 'w', 'x', 'y', 'z',] N = [0, 1, 2, 3, 4, 5, 6, 7, 8, 9] M = ['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'] c = int(input("Insert the number of digits you want: ")) n = int(input("If you need number press 1: ")) m = int(input("If you need upper letters press 1: ")) i = [] if n == 1: P = P + N if m == 1: P = P + M then = time.time() def worker(): for i in product(P, repeat=c): #check every possibilities k = '' for z in range(0, c): # k = k + str(i[z]) # print each possibility in a txt without parentesis or comma out_file.write( k + '\n') # out_file.close() now = time.time() diff = str(now - then) # To see how long does it take print(diff) worker() time.sleep(10) # just to check console The code check every single possibility and print it out in a test.txt file. It works but I really can't understand how can I speed it up. I saw it use 1 core out of my quad core CPU so I thought Multi-threading might work even though I don't know how. Please help me. Sorry for my English, I am from Italy.

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  • How to check volume is mounted or not using python with a dynamic volume name

    - by SR query
    import subprocess def volumeCheck(volume_name): """This function will check volume name is mounted or not. """ volume_name = raw_input('Enter volume name:') volumeCheck(volume_name) print 'volume_name=',volume_name p = subprocess.Popen(['df', '-h'], stdout=subprocess.PIPE, stderr=subprocess.PIPE) p1, err = p.communicate() pattern = p1 if pattern.find(volume_name): print 'volume found' else: print 'volume not found' While running i always got wrong result "volume found". root@sr-query:/# df -h Filesystem Size Used Avail Use% Mounted on rootfs 938M 473M 418M 54% / /dev/md0 938M 473M 418M 54% / none 250M 4.9M 245M 2% /dev /dev/md2 9.7M 1.2M 8.0M 13% /usr/config /dev/md7 961M 18M 895M 2% /downloads tmpfs 250M 7.9M 242M 4% /var/volatile tmpfs 250M 0 250M 0% /dev/shm tmpfs 250M 0 250M 0% /media/ram **/dev/mapper/vg9-lv9 1016M 65M 901M 7% /VolumeData/sp /dev/mapper/vg10-lv10 1016M 65M 901M 7% /VolumeData/cp** root@sr-query:/# root@sr-query:/# root@sr-query:/# python volume_check.py Enter volume name:raid_10volume volume_name= raid_10volume **volume found** root@sr-query:/# I enterd raid_10volume its not listed here please check the df -h command out put(only 2 volume there sp and cp) , then how it reached else part. what is wrong in my code? Thanks in advance. is there any other way to do this work ! ?

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  • Celery Received unregistered task of type (run example)

    - by Echeg
    I'm trying to run example from Celery documentation. I run: celeryd --loglevel=INFO /usr/local/lib/python2.7/dist-packages/celery/loaders/default.py:64: NotConfigured: No 'celeryconfig' module found! Please make sure it exists and is available to Python. "is available to Python." % (configname, ))) [2012-03-19 04:26:34,899: WARNING/MainProcess] -------------- celery@ubuntu v2.5.1 ---- **** ----- --- * *** * -- [Configuration] -- * - **** --- . broker: amqp://guest@localhost:5672// - ** ---------- . loader: celery.loaders.default.Loader - ** ---------- . logfile: [stderr]@INFO - ** ---------- . concurrency: 4 - ** ---------- . events: OFF - *** --- * --- . beat: OFF -- ******* ---- --- ***** ----- [Queues] -------------- . celery: exchange:celery (direct) binding:celery tasks.py: # -*- coding: utf-8 -*- from celery.task import task @task def add(x, y): return x + y run_task.py: # -*- coding: utf-8 -*- from tasks import add result = add.delay(4, 4) print (result) print (result.ready()) print (result.get()) In same folder celeryconfig.py: CELERY_IMPORTS = ("tasks", ) CELERY_RESULT_BACKEND = "amqp" BROKER_URL = "amqp://guest:guest@localhost:5672//" CELERY_TASK_RESULT_EXPIRES = 300 When I run "run_task.py": on python console eb503f77-b5fc-44e2-ac0b-91ce6ddbf153 False errors on celeryd server [2012-03-19 04:34:14,913: ERROR/MainProcess] Received unregistered task of type 'tasks.add'. The message has been ignored and discarded. Did you remember to import the module containing this task? Or maybe you are using relative imports? Please see http://bit.ly/gLye1c for more information. The full contents of the message body was: {'retries': 0, 'task': 'tasks.add', 'utc': False, 'args': (4, 4), 'expires': None, 'eta': None, 'kwargs': {}, 'id': '841bc21f-8124-436b-92f1-e3b62cafdfe7'} Traceback (most recent call last): File "/usr/local/lib/python2.7/dist-packages/celery/worker/consumer.py", line 444, in receive_message self.strategies[name](message, body, message.ack_log_error) KeyError: 'tasks.add' Please explain what's the problem.

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  • Python Beautiful Soup .content Property

    - by Robert Birch
    What does BeautifulSoup's .content do? I am working through crummy.com's tutorial and I don't really understand what .content does. I have looked at the forums and I have not seen any answers. Looking at the code below.... from BeautifulSoup import BeautifulSoup import re doc = ['<html><head><title>Page title</title></head>', '<body><p id="firstpara" align="center">This is paragraph <b>one</b>.', '<p id="secondpara" align="blah">This is paragraph <b>two</b>.', '</html>'] soup = BeautifulSoup(''.join(doc)) print soup.contents[0].contents[0].contents[0].contents[0].name I would expect the last line of the code to print out 'body' instead of... File "pe_ratio.py", line 29, in <module> print soup.contents[0].contents[0].contents[0].contents[0].name File "C:\Python27\lib\BeautifulSoup.py", line 473, in __getattr__ raise AttributeError, "'%s' object has no attribute '%s'" % (self.__class__.__name__, attr) AttributeError: 'NavigableString' object has no attribute 'name' Is .content only concerned with html, head and title? If, so why is that? Thanks for the help in advance.

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  • SFTP in Python? (platform independent)

    - by Mark Wilbur
    I'm working on a simple tool that transfers files to a hard-coded location with the password also hard-coded. I'm a python novice, but thanks to ftplib, it was easy: import ftplib info= ('someuser', 'password') #hard-coded def putfile(file, site, dir, user=(), verbose=True): """ upload a file by ftp to a site/directory login hard-coded, binary transfer """ if verbose: print 'Uploading', file local = open(file, 'rb') remote = ftplib.FTP(site) remote.login(*user) remote.cwd(dir) remote.storbinary('STOR ' + file, local, 1024) remote.quit() local.close() if verbose: print 'Upload done.' if __name__ == '__main__': site = 'somewhere.com' #hard-coded dir = './uploads/' #hard-coded import sys, getpass putfile(sys.argv[1], site, dir, user=info) The problem is that I can't find any library that supports sFTP. What's the normal way to do something like this securely? Edit: Thanks to the answers here, I've gotten it working with Paramiko and this was the syntax. import paramiko host = "THEHOST.com" #hard-coded port = 22 transport = paramiko.Transport((host, port)) password = "THEPASSWORD" #hard-coded username = "THEUSERNAME" #hard-coded transport.connect(username = username, password = password) sftp = paramiko.SFTPClient.from_transport(transport) import sys path = './THETARGETDIRECTORY/' + sys.argv[1] #hard-coded localpath = sys.argv[1] sftp.put(localpath, path) sftp.close() transport.close() print 'Upload done.' Thanks again!

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  • Printing Images C# Overlapping Wrong

    - by Alen
    I have created a program much like Photoshop in the sense that you can place images (picture box) on a control, move them around, delete them, and so on... I have also managed to put together a method to print all the images on the control with no problems. But here is the weird part: When I click print, the program prints the image which was placed first, on top of the image which came second. On the screen the user can see the image which was placed second, on top of the first placed image (the way it should be) but when I print its opposite? I have no idea why it does this... I hope I've made my self as clear as possible, any help is appreciated! public void printToGraphics(Graphics graphics, Rectangle bounds) { graphics.TextRenderingHint = System.Drawing.Text.TextRenderingHint.ClearTypeGridFit; graphics.CompositingQuality = System.Drawing.Drawing2D.CompositingQuality.HighQuality; graphics.SmoothingMode = System.Drawing.Drawing2D.SmoothingMode.HighQuality; Bitmap bitmap = new Bitmap(newLabel.Width, newLabel.Height); newLabel.DrawToBitmap(bitmap, newLabel.DisplayRectangle); Rectangle target = new Rectangle(0, 0, bounds.Width, bounds.Height); target.Height = bitmap.Height; target.Width = bitmap.Width; graphics.PageUnit = GraphicsUnit.Display; graphics.DrawImage(bitmap,target); } void printDoc_PrintPage(object sender, PrintPageEventArgs e) { printToGraphics(e.Graphics, e.MarginBounds); }

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  • How do I pass three arrays from on method to another?

    - by user2966716
    I have a method studentSummary, that scans the input and creates three arrays examMark,courseworkMark and courseworkWeight. I need these arrays passing over to a different method, so I can use them to calculate moduleResult. heres my code: public static int[] studentSummary(int[] courseworkWeight2, int [] examMark2 , int [] courseworkMark2){ int examMark[] = { 0, 0, 0, 0, 0, 0 }; int courseworkMark[] = { 0, 0, 0, 0, 0, 0 }; Scanner resultInput = new Scanner(System.in); int courseworkWeight[] = { 0, 0, 0, 0, 0, 0 }; for (int k = 1; k < 7; k++) { System.out.print("Please enter exam marks for module " + k + ":"); examMark[k - 1] = resultInput.nextInt(); System.out.print("Please enter Coursework marks for module " + k + ":"); courseworkMark[k - 1] = resultInput.nextInt(); System.out.print("Please enter Coursework weighting for module " + k + ":"); courseworkWeight[k - 1] = resultInput.nextInt(); } Calculator method: public static int[] markCalculator() { int[] courseworkWeight = new int [6]; int[] courseworkMark = new int [6]; int[] examMark = new int [6]; for (int i = 0; i < 6; i++) { computedModuleMark = ((courseworkMark[i] * courseworkWeight[i]) + (examMark[i] * (100 - courseworkWeight[i]))) / 100; if ((computedModuleMark) < 35) { if (examMark[i]<35){ } } moduleMark[i] = computedModuleMark; } computeResult(moduleMark); StudentChart.draw(moduleMark); StudentChart.printSummary(moduleMark); return moduleMark; }

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  • parsing python to csv

    - by user185955
    I'm trying to download some game stats to do some analysis, only problem is each season the data their isn't 100% consistent. I grab the json file from the site, then wish to save it to a csv with the first line in the csv containing the heading for that column, so the heading would be essentially the key from the python data type. #!/usr/bin/env python import requests import json import csv base_url = 'http://www.afl.com.au/api/cfs/afl/' token_url = base_url + 'WMCTok' player_url = base_url + 'matchItems/round' def printPretty(data): print(json.dumps(data, sort_keys=True, indent=2, separators=(',', ': '))) session = requests.Session() # session makes it simple to use the token across the requests token = session.post(token_url).json()['token'] # get the token session.headers.update({'X-media-mis-token': token}) # set the token Season = 2014 Roundno = 4 if Roundno<10: strRoundno = '0'+str(Roundno) else: strRoundno = str(Roundno) # get some data (could easily be a for loop, might want to put in a delay using Sleep so that you don't get IP blocked) data = session.get(player_url + '/CD_R'+str(Season)+'014'+strRoundno) # print everything printPretty(data.json()) with open('stats_game_test.csv', 'w', newline='') as csvfile: spamwriter = csv.writer(csvfile, delimiter="'",quotechar='|', quoting=csv.QUOTE_ALL) for profile in data.json()['items']: spamwriter.writerow(['%s' %(profile)]) #for key in data.json().keys(): # print("key: %s , value: %s" % (key, data.json()[key])) The above code grabs the json and writes it to a csv, but it puts the key in each individual cell next to the value (eg 'venueId': 'CD_V190'), the key needs to be just across the first row as a heading. It gives me a csv file with data in the cells like this Column A B 'tempInCelsius': 17.0 'totalScore': 32 'tempInCelsius': 16.0 'totalScore': 28 What I want is the data like this tempInCelsius totalScore 17 32 16 28 As I mentioned up the top, the data isn't always consistent so if I define what fields to grab with spamwriter.writerow([profile['tempInCelsius'], profile['totalScore']]) then it will error out on certain data grabs. This is why I'm now trying the above method so it just grabs everything regardless of what data is there.

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  • For each loop not reading in the last item

    - by Gandalf StormCrow
    I'm trying to read in a multi line string then split it then print it .. here is the string : 1T1b5T!1T2b1T1b2T!1T1b1T2b2T!1T3b1T1b1T!3T3b1T!1T3b1T1b1T!5T1*1T 11X21b1X 4X1b1X When I split the string with ! I get this without the last line string : 1T1b5T 1T1b5T1T2b1T1b2T 1T2b1T1b2T1T1b1T2b2T 1T1b1T2b2T1T3b1T1b1T 1T3b1T1b1T3T3b1T 3T3b1T1T3b1T1b1T 1T3b1T1b1T5T1*1T 5T1*1T11X21b1X 11X21b1X Here is my code : import java.io.BufferedInputStream; import java.util.Scanner; public class Main { public static void main(String args[]) { Scanner stdin = new Scanner(new BufferedInputStream(System.in)); while (stdin.hasNext()) { for (String line : stdin.next().split("!")) { System.out.println(line); for (int i = 0; i < line.length(); i++) { System.out.print(line.charAt(i)); } } } } } Where did I make the mistake, why is not reading in the last line? After I read in all lines properly I should go trough each line if I encounter number I should print the next char the n times the number I just read, but that is long way ahead first I need help with this. Thank you

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  • Why does my perl script return a zero return code when I explicitly call exit with a non-zero parame

    - by Tom Duckering
    I have a perl script which calls another script. The perl script should be propagating the script's return code but seems to be returning zero to its caller (a Java application) desipte the explicit call to exit $scriptReturnCode. It's probably something dumb since I'm by no means a perl expert. Code and output as follows (I realise that <=> could/should be != but that's what I have): print "INFO: Calling ${scriptDirectory}/${script} ${args}" $scriptReturnCode = system("${scriptDirectory}/${script} ${args}"); if ( $scriptReturnCode <=> 0 ) { print "ERROR: The script returned $scriptReturnCode\n"; exit $scriptReturnCode; } else { print "INFO: The script returned $scriptReturnCode.\n"; exit 0; } The output I have from my Java is: 20/04/2010 14:40:01 - INFO: Calling /path/to/script/script.ksh arg1 arg2 20/04/2010 14:40:01 - Could not find installer files <= this is from the script.ksh 20/04/2010 14:40:01 - ERROR: The script returned 256 20/04/2010 14:40:01 - Command Finished. Exit Code: 0 <= this is the Java app.

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  • How can I read and parse chunks of data into a Perl hash of arrays?

    - by neversaint
    I have data that looks like this: #info #info2 1:SRX004541 Submitter: UT-MGS, UT-MGS Study: Glossina morsitans transcript sequencing project(SRP000741) Sample: Glossina morsitans(SRS002835) Instrument: Illumina Genome Analyzer Total: 1 run, 8.3M spots, 299.9M bases Run #1: SRR016086, 8330172 spots, 299886192 bases 2:SRX004540 Submitter: UT-MGS Study: Anopheles stephensi transcript sequencing project(SRP000747) Sample: Anopheles stephensi(SRS002864) Instrument: Solexa 1G Genome Analyzer Total: 1 run, 8.4M spots, 401M bases Run #1: SRR017875, 8354743 spots, 401027664 bases 3:SRX002521 Submitter: UT-MGS Study: Massive transcriptional start site mapping of human cells under hypoxic conditions.(SRP000403) Sample: Human DLD-1 tissue culture cell line(SRS001843) Instrument: Solexa 1G Genome Analyzer Total: 6 runs, 27.1M spots, 977M bases Run #1: SRR013356, 4801519 spots, 172854684 bases Run #2: SRR013357, 3603355 spots, 129720780 bases Run #3: SRR013358, 3459692 spots, 124548912 bases Run #4: SRR013360, 5219342 spots, 187896312 bases Run #5: SRR013361, 5140152 spots, 185045472 bases Run #6: SRR013370, 4916054 spots, 176977944 bases What I want to do is to create a hash of array with first line of each chunk as keys and SR## part of lines with "^Run" as its array member: $VAR = { 'SRX004541' => ['SRR016086'], # etc } But why my construct doesn't work. And it must be a better way to do it. use Data::Dumper; my %bighash; my $head = ""; my @temp = (); while ( <> ) { chomp; next if (/^\#/); if ( /^\d{1,2}:(\w+)/ ) { print "$1\n"; $head = $1; } elsif (/^Run \#\d+: (\w+),.*/){ print "\t$1\n"; push @temp, $1; } elsif (/^$/) { push @{$bighash{$head}}, [@temp]; @temp =(); } } print Dumper \%bighash ;

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  • Python script not working when run from browser directly

    - by splatterdash
    I'm trying to run this script: import re, os def build_pool(cwd): global xtn_pool, file_pool xtn, xtn_pool = re.compile('\\.[0-9a-zA-Z]{1,4}$'), [] file_pool = [files for files in os.listdir(cwd) if os.path.isfile(files) and xtn.search(files)] # Lists all the file extension in the folder for file in file_pool: if not xtn_pool.__contains__(xtn.search(file).group()): xtn_pool.append(xtn.search(file).group()) return xtn_pool.sort(), file_pool if __name__ == '__main__': import sys #if path is given, change working directory to path if len(sys.argv) >= 2: os.chdir(sys.argv[1]) build_pool(os.getcwd()) #if no path is given when running, do renaming in current folder else: build_pool(os.getcwd()) print('The folder contains the following extensions: ') for i in range(0, len(xtn_pool)): print(repr(i+1) + '. ' + xtn_pool[i][1:]) opt = int(input('Which one would you like to replace? ')) xtn_pick = xtn_pool[opt-1] # Lists all the file with the chosen extension xtn_file_pool = [file for file in file_pool if file.endswith(xtn_pick)] print('There are {0} files with the {1} extension.'.format(len(xtn_file_pool), xtn_pick)) xtn_new = input('Input replacement extension: ') # The actual renaming process for file in xtn_file_pool: os.rename(file, file[:-len(xtn_pick)+1] + xtn_new) directly from my file browser (Nautilus), but for some reason it's not working. When I run it from terminal (python3 scriptname.py) it works fine as intended. But when I just click the script file in Nautilus, choose 'Run in Terminal', it always stops after asking 'Input replacement extension: '. How can I make this script run without using the terminal?

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  • Handling text menu in Python

    - by PulpFiction
    Hi all. I am trying to create a text based menu in Python. Here is the code: #!/usr/bin/env python def testcaseOutput(): print '1. Add. 2. Subtract. 3. Divide. 4. Multiply' try: answer = int(raw_input('Enter a value (1 - 4) >. ')) except ValueError: print 'Invalid input. Enter a value between 1 -4 .' testcaseOutput() if answer in range(1, 5): return answer else: print 'Invalid input. Enter a value between 1 - 4.' testcaseOutput() My question: When the user enters an invalid input, i.e. not a number, I want this function to get called again. So I used the recursive approach which I think is bad design. I use that approach again in the if answer in range(1, 5). Is there any other way to handle this? I need the prompt called again when there is an invalid input. Also, is there any way I can club the two constraints: check whether input is a number and check whether the number is in the range(1,5) together? As you can see, I am checking that individually.

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  • Python client / server question

    - by AustinM
    I'm working on a bit of a project in python. I have a client and a server. The server listens for connections and once a connection is received it waits for input from the client. The idea is that the client can connect to the server and execute system commands such as ls and cat. This is my server code: import sys, os, socket host = '' port = 50105 s = socket.socket(socket.AF_INET, socket.SOCK_STREAM) s.bind((host, port)) print("Server started on port: ", port) s.listen(5) print("Server listening\n") conn, addr = s.accept() print 'New connection from ', addr while (1): rc = conn.recv(5) pipe = os.popen(rc) rl = pipe.readlines() file = conn.makefile('w', 0) file.writelines(rl[:-1]) file.close() conn.close() And this is my client code: import sys, socket s = socket.socket(socket.AF_INET, socket.SOCK_STREAM) host = 'localhost' port = input('Port: ') s.connect((host, port)) cmd = raw_input('$ ') s.send(cmd) file = s.makefile('r', 0) sys.stdout.writelines(file.readlines()) When I start the server I get the right output, saying the server is listening. But when I connect with my client and type a command the server exits with this error: Traceback (most recent call last): File "server.py", line 21, in <module> rc = conn.recv(2) File "/usr/lib/python2.6/socket.py", line 165, in _dummy raise error(EBADF, 'Bad file descriptor') socket.error: [Errno 9] Bad file descriptor On the client side, I get the output of ls but the server gets screwed up.

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  • How to implement the "System.out.println(ClassName::MethodName <then my message>)" of Eclipse in Netbeans?

    - by Sen
    I would like to know if there is the same feature as in eclipse to automatically generate and print the System.out.println(ClassName::MethodName <then my message>) functionality (which will print the class name and method name for debugging in the console) in Netbeans also. For example, in Eclipse Editor, Typing syst + Ctrl+ Space will auto generate a System.out.println(ClassName::MethodName ) type output in the console. Is such a method available in Netbeans? As of now, I have only two methods here in Netbeans: sout + Tab (System.out.println()) and soutv + Tab (System.out.println(prints the variable used just above the line)) automatically. Let me rephrase, instead of myMethod1, I want to get the enclosing method name. Eg. : public class X { public void myMethod1(int a) { System.out.println(X::myMethod1()); // This should be produced when I type the Code-Template abbreviation (example: syst) and press tab (or corresponding key). } } public class Y { public void myMethod2(int b) { System.out.println(Y::myMethod2()); // This should be produced when I type the Code-Template abbreviation (example: syst) and press tab (or corresponding key). } } Update: With the following code template: syst = System.out.println("${classVar editable="false" currClassName default="getClass()"}"); I am able to print the classname, but still no clue for the Method name.

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  • Interpretation of range(n) and boolean list, one-to-one map, simpler?

    - by HH
    #!/usr/bin/python # # Description: bitwise factorization and then trying to find # an elegant way to print numbers # Source: http://forums.xkcd.com/viewtopic.php?f=11&t=61300#p2195422 # bug with large numbers such as 99, but main point in simplifying it # def primes(n): # all even numbers greater than 2 are not prime. s = [False]*2 + [True]*2 + [False,True]*((n-4)//2) + [False]*(n%2) i = 3; while i*i < n: # get rid of ** and skip even numbers. s[i*i : n : i*2] = [False]*(1+(n-i*i)//(i*2)) i += 2 # skip non-primes while not s[i]: i += 2 return s # TRIAL: can you find a simpler way to print them? # feeling the overuse of assignments but cannot see a way to get it simpler # p = 49 boolPrimes = primes(p) numbs = range(len(boolPrimes)) mydict = dict(zip(numbs, boolPrimes)) print([numb for numb in numbs if mydict[numb]]) Something I am looking for, can you get TRIAL to be of the extreme simplicity below? Any such method? a=[True, False, True] b=[1,2,3] b_a # any such simple way to get it evaluated to [1,3] # above a crude way to do it in TRIAL

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  • Can I make a derived class inherit a derived member from its base class in Java?

    - by Eric
    I have code that looks like this: public class A { public void doStuff() { System.out.print("Stuff successfully done"); } } public class B extends A { public void doStuff() { System.out.print("Stuff successfully done, but in a different way"); } public void doMoreStuff() { System.out.print("More advanced stuff successully done"); } } public class AWrapper { public A member; public AWrapper(A member) { this.member = member; } public void doStuffWithMember() { a.doStuff(); } } public class BWrapper extends AWrapper { public B member; public BWrapper(B member) { super(member); //Pointer to member stored in two places: this.member = member; //Not great if one changes, but the other does not } public void doStuffWithMember() { member.doMoreStuff(); } } However, there is a problem with this code. I'm storing a reference to the member in two places, but if one changes and the other does not, there could be trouble. I know that in Java, an inherited method can narrow down its return type (and perhaps arguments, but I'm not certain) to a derived class. Is the same true of fields?

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  • need help with some basic java.

    - by Racket
    Hi, I'm doing the first chapter exercises on my Java book and I have been stuck for a problem for a while now. I'll print the question, prompt/read a double value representing a monetary amount. Then determine the fewest number of each bill and coin needed to represent that amount, starting with the highest (assume that a ten dollar bill is the maximum size needed). For example, if the value entered is 47,63 (forty-seven dollars and sixty-three cents), and the program should print the equivalent amount as: 4 ten dollar bills 1 five dollar bills 2 one dollar bills 2 quarters 1 dimes 0 nickels 3 pennies" etc. I'm doing an example exactly as they said in order to get an idea, as you will see in the code. Nevertheless, I managed to print 4 dollars, and I can't figure out how to get "1 five dollar", only 7 dollars (see code). Please, don't do the whole code for me. I just need some advice in regards to what I said. Thank you. import java.util.Scanner; public class PP29 { public static void main (String[] args) { Scanner sc = new Scanner (System.in); int amount; double value; double test1; double quarter; System.out.println("Enter \"double\" value: "); value = sc.nextDouble(); amount = (int) value / 10; // 47,63 / 10 = 4. int amount2 = (int) value % 10; // 47 - 40 = 7 quarter = value * 100; // 47,63 * 100 = 4736 int sum = (int) quarter % 100; // 4763 / 100 => 4763-4700 = 63. System.out.println(amount); System.out.println(amount2); } }

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  • How to match words as if in a dictionary, based on len-1 or len+1? Python

    - by pearbear
    If I have a word 'raqd', how would I use python to have a spellcheck, so to speak, to find the word 'rad' as an option in 'spellcheck'? What I've been trying to do is this: def isbettermatch(keysplit, searchword): i = 0 trues = 0 falses = 0 lensearchwords = len(searchword) keysplits = copy.deepcopy(keysplit) searchwords = copy.deepcopy(searchword) #print keysplit, searchwords if len(keysplits) == len(searchwords)-1: i = 0 while i < len(keysplits): j = 0 while j < lensearchwords: if keysplits[i] == searchwords[j]: trues +=1 searchwords.pop(j) lensearchwords = len(searchwords) elif keysplits[i] != searchwords[j]: falses +=1 j +=1 i +=1 if trues >= len(searchwords)-1: #print "-------------------------------------------------------", keysplits return True keysplit is a list like ['s', 'p', 'o', 'i', 'l'] for example, and the searchword would be a list ['r', 'a', 'q', 'd']. If the function returns True, then it would print the keyword that matches. Ex. 'rad', for the searchword 'raqd'. I need to find all possible matches for the searchword with a single letter addition or deletion. so ex. 'raqd' would have an option to be 'rad', and 'poted' could be 'posted' or 'potted'. Above is what I have tried, but it is not working well at all. Help much appreciated!

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