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  • Control serialization of GWT

    - by Phuong Nguyen de ManCity fan
    I want GWT to not serialize some fields of my object (which implements Serializable interface). Normally, transient keyword would be enough. However, I also need to put the object on memcache. The use of transient keyword would make the field not being stored on memcache also. Is there any GWT-specific technique to tell the serializer to not serialize a field?

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  • Hibernate MappingException Unknown entity: $Proxy2

    - by slynn1324
    I'm using Hibernate annotations and have a VERY basic data object: import java.io.Serializable; import javax.persistence.Entity; import javax.persistence.Id; @Entity public class State implements Serializable { /** * */ private static final long serialVersionUID = 1L; @Id private String stateCode; private String stateFullName; public String getStateCode() { return stateCode; } public void setStateCode(String stateCode) { this.stateCode = stateCode; } public String getStateFullName() { return stateFullName; } public void setStateFullName(String stateFullName) { this.stateFullName = stateFullName; } } and am trying to run the following test case: public void testCreateState(){ Session s = HibernateUtil.getSessionFactory().getCurrentSession(); Transaction t = s.beginTransaction(); State state = new State(); state.setStateCode("NE"); state.setStateFullName("Nebraska"); s.save(s); t.commit(); } and get an org.hibernate.MappingException: Unknown entity: $Proxy2 at org.hibernate.impl.SessionFactoryImpl.getEntityPersister(SessionFactoryImpl.java:628) at org.hibernate.impl.SessionImpl.getEntityPersister(SessionImpl.java:1366) at org.hibernate.event.def.AbstractSaveEventListener.saveWithGeneratedId(AbstractSaveEventListener.java:121) .... I haven't been able to find anything referencing the $Proxy part of the error - and am at a loss.. Any pointers to what I'm missing would be greatly appreciated. hibernate.cfg.xml <property name="hibernate.connection.driver_class">org.hsqldb.jdbcDriver</property> <property name="connection.url">jdbc:hsqldb:hsql://localhost/xdb</property> <property name="connection.username">sa</property> <property name="connection.password"></property> <property name="current_session_context_class">thread</property> <property name="dialect">org.hibernate.dialect.HSQLDialect</property> <property name="show_sql">true</property> <property name="hbm2ddl.auto">update</property> <property name="hibernate.transaction.factory_class">org.hibernate.transaction.JDBCTransactionFactory</property> <mapping class="com.test.domain.State"/> in HibernateUtil.java public static SessionFactory getSessionFactory(boolean testing ) { if ( sessionFactory == null ){ try { String configPath = HIBERNATE_CFG; AnnotationConfiguration config = new AnnotationConfiguration(); config.configure(configPath); sessionFactory = config.buildSessionFactory(); } catch (Exception e){ e.printStackTrace(); throw new ExceptionInInitializerError(e); } } return sessionFactory; }

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  • INSERT and transaction searilization in PostreSQL

    - by Alexander
    Hello! I have a question. Transaction isolation level set to serializable. When the one user open transaction and INSERT or UPDATE data in "table1" and then another user open transaction and try to INSERT data to the same table is second user need to wait 'til the first user commits the transaction?

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  • Java serialization testing

    - by Jeff Storey
    Does anyone know if there is a library that exists to help test if an object graph is fully serializable? It would probably be as simple as writing it out and reading it back in, but I figured someone must have abstracted this already - I just can't find it.

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  • Use the serialVersionUID or suppress warnings?

    - by Okami
    Dear all, first thing to note is the serialVersionUID of a class implementing Interface Serializable is not in question. What if we create a class that for example extends HttpServlet? It also should have a serialVersionUID. If someone knows that this object will never be serialized should he define it or add an annotation to suppress those warnings? What would you do and why? Thanks for sharing your thoughts. Okami

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  • representing an XML config file with an IXmlSerializable class

    - by Sarah Vessels
    I'm writing in C# and trying to represent an XML config file through an IXmlSerializable class. I'm unsure how to represent the nested elements in my config file, though, such as logLevel: <?xml version="1.0" encoding="utf-8" ?> <configuration> <logging> <logLevel>Error</logLevel> </logging> <credentials> <user>user123</user> <host>localhost</host> <password>pass123</password> </credentials> <credentials> <user>user456</user> <host>my.other.domain.com</host> <password>pass456</password> </credentials> </configuration> There is an enum called LogLevel that represents all the possible values for the logLevel tag. The tags within credentials should all come out as strings. In my class, called DLLConfigFile, I had the following: [XmlElement(ElementName="logLevel", DataType="LogLevel")] public LogLevel LogLevel; However, this isn't going to work because <logLevel> isn't within the root node of the XML file, it's one node deeper in <logging>. How do I go about doing this? As for the <credentials> nodes, my guess is I will need a second class, say CredentialsSection, and have a property such as the following: [XmlElement(ElementName="credentials", DataType="CredentialsSection")] public CredentialsSection[] AllCredentials; Edit: okay, I tried Robert Love's suggestion and created a LoggingSection class. However, my test fails: var xs = new XmlSerializer(typeof(DLLConfigFile)); using (var stream = new FileStream(_configPath, FileMode.Open, FileAccess.Read, FileShare.Read)) { using (var streamReader = new StreamReader(stream)) { XmlReader reader = new XmlTextReader(streamReader); var file = (DLLConfigFile)xs.Deserialize(reader); Assert.IsNotNull(file); LoggingSection logging = file.Logging; Assert.IsNotNull(logging); // fails here LogLevel logLevel = logging.LogLevel; Assert.IsNotNull(logLevel); Assert.AreEqual(EXPECTED_LOG_LEVEL, logLevel); } } The config file I'm testing with definitely has <logging>. Here's what the classes look like: [Serializable] [XmlRoot("logging")] public class LoggingSection : IXmlSerializable { public XmlSchema GetSchema() { return null; } [XmlElement(ElementName="logLevel", DataType="LogLevel")] public LogLevel LogLevel; public void ReadXml(XmlReader reader) { LogLevel = (LogLevel)Enum.Parse(typeof(LogLevel), reader.ReadString()); } public void WriteXml(XmlWriter writer) { writer.WriteString(Enum.GetName(typeof(LogLevel), LogLevel)); } } [Serializable] [XmlRoot("configuration")] public class DLLConfigFile : IXmlSerializable { [XmlElement(ElementName="logging", DataType="LoggingSection")] public LoggingSection Logging; }

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  • Qt - serialize/deserialaize text plus picture

    - by Narek
    I want to use a field (kind of QTextEdit), which is capabale of storing picture and text (like MS Word is doing) and it serializes and deserialaizes picture+text data. Is there any Qt Widget that allows us to manipulate with picture and text simultaniously and it has set/get functions which operate with serializable type? In othger words, I want to know if there exsists any Qt widget that can store picture+text and has "get" types of function that returns the content of that widgets editable area, which is a Type that could be serialized with QDataStream.

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  • Help with XML SerializableDictionary in C#

    - by psilos
    Hi I am using the class public class SerializableDictionary : Dictionary, IXmlSerializable in order to serialize a dictionary. However it doesnt work when as values I have collelctions (eg List) or tyes other than the primitive types (eg. int, double, string....). My question is which types the TKey, TValue imply or can hold, and if there is way to have a serializable dictionary which collections as values.

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  • Prevent <xsi:nil="true"> on Nullable Value Types when Serializing to XML.

    - by Nat Ryall
    I have added some nullable value types to my serializable class. I perform a serialization using XmlSerializer but when the value is set to null, I get an empty node with xsi:nil="true". This is the correct behaviour as I have found here: http://msdn.microsoft.com/en-us/library/ybce7f69%28VS.80%29.aspx Is there a way to switch off this option so that nothing is output when the value type is null?

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  • DataContractJsonSerializer generating Ghost string to JSON keys?

    - by Anil Namde
    DataContractJsonSerializer this is nice class added in the .net framework which can be used to serialize/desirealize object into JSON. Now following is the example i am trying [Serializable] class User { public string name; public string userId; } Now following is the output generated Output : Notice structure where only "name" is expected instead of k__BackingField Now this is the problem after digging so much i am not sure from where < and _BackingField is coming ? { "<name>k__BackingField":"test user", "<userId>k__BackingField":100001}

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  • Attribute & Reflection libraries for C++?

    - by Fabian
    Most mature C++ projects seem to have an own reflection and attribute system, i.e for defining attributes which can be accessed by string and are automatically serializable. At least many C++ projects I participated in seemed to reinvent the wheel. Do you know any good open source libraries for C++ which support reflection and attribute containers, specifically: Defining RTTI and attributes via macros Accessing RTTI and attributes via code Automatic serialisation of attributes Listening to attribute modifications (e.g. OnValueChanged)

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  • Web Parts custom property not showing up

    - by Morri
    I'm trying to create a custom property for my web part, but can't get it to show up in Sharepoint. Here's my current code : [Serializable] [XmlRoot(Namespace = "MyWebPart")] [DefaultProperty("Text")] public class MyWebPart : WebPart { ... [Category("My Web Parts Properties")] [DefaultValue(defaultPropertyValue)] [WebPartStorage(Storage.Shared)] [FriendlyNameAttribute("Property name")] [Description("Longer desc for my property")] [Browsable(true)] [XmlElement(ElementName = "SomeProperty")] public string SomeProperty { get { return someProperty; } set { someProperty = value; } } Is there something else required to get custom properties working?

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  • Serialize boost array

    - by jules
    I would like to serialize a boost::array, containing something that is already serializable. If get this error: error C2039: 'serialize' : is not a member of 'boost::array<T,N>' I have tried to include the serialization/array.hpp header but it did not help. Is there another header to include ? According to the documentation I should be able to do that http://www.chuchusoft.com/serialization/doc/boost_types.html Thanks

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  • Problem persisting inheritance tree

    - by alaiseca
    I have a problem trying to map an inheritance tree. A simplified version of my model is like this: @MappedSuperclass @Embeddable public class BaseEmbedded implements Serializable { @Column(name="BE_FIELD") private String beField; // Getters and setters follow } @MappedSuperclass @Embeddable public class DerivedEmbedded extends BaseEmbedded { @Column(name="DE_FIELD") private String deField; // Getters and setters follow } @MappedSuperclass public abstract class BaseClass implements Serializable { @Embedded protected BaseEmbedded embedded; public BaseClass() { this.embedded = new BaseEmbedded(); } // Getters and setters follow } @Entity @Table(name="MYTABLE") @Inheritance(strategy=InheritanceType.SINGLE_TABLE) @DiscriminatorColumn(name="TYPE", discriminatorType=DiscriminatorType.STRING) public class DerivedClass extends BaseClass { @Id @Column(name="ID", nullable=false) private Long id; @Column(name="TYPE", nullable=false, insertable=false, updatable=false) private String type; public DerivedClass() { this.embedded = new DerivedClass(); } // Getters and setters follow } @Entity @DiscriminatorValue("A") public class DerivedClassA extends DerivedClass { @Embeddable public static NestedClassA extends DerivedEmbedded { @Column(name="FIELD_CLASS_A") private String fieldClassA; } public DerivedClassA() { this.embedded = new NestedClassA(); } // Getters and setters follow } @Entity @DiscriminatorValue("B") public class DerivedClassB extends DerivedClass { @Embeddable public static NestedClassB extends DerivedEmbedded { @Column(name="FIELD_CLASS_B") private String fieldClassB; } public DerivedClassB() { this.embedded = new NestedClassB(); } // Getters and setters follow } At Java level, this model is working fine, and I believe is the appropriate one. My problem comes up when it's time to persist an object. At runtime, I can create an object which could be an instance of DerivedClass, DerivedClassA or DerivedClassB. As you can see, each one of the derived classes introduces a new field which only makes sense for that specific derived class. All the classes share the same physical table in the database. If I persist an object of type DerivedClass, I expect fields BE_FIELD, DE_FIELD, ID and TYPE to be persisted with their values and the remaining fields to be null. If I persist an object of type DerivedClass A, I expect those same fields plus the FIELD_CLASS_A field to be persisted with their values and field FIELD_CLASS_B to be null. Something equivalent for an object of type DerivedClassB. Since the @Embedded annotation is at the BaseClass only, Hibernate is only persisting the fields up to that level in the tree. I don't know how to tell Hibernate that I want to persist up to the appropriate level in the tree, depending on the actual type of the embedded property. I cannot have another @Embedded property in the subclasses since this would duplicate data that is already present in the superclass and would also break the Java model. I cannot declare the embedded property to be of a more specific type either, since it's only at runtime when the actual object is created and I don't have a single branch in the hierarchy. Is it possible to solve my problem? Or should I resignate myself to accept that there is no way to persist the Java model as it is? Any help will be greatly appreciated.

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  • How can I link two Java serialised objects back together?

    - by Kidburla
    Sometimes (quite a lot, actually) we get a situation in Java where two objects are pointing to the same thing. Now if we serialise these separately it is quite appropriate that the serialised forms have separate copies of the object as it should be possible to open one without the other. However if we now deserialise them both, we find that they are still separated. Is there any way to link them back together? Example follows. public class Example { private static class ContainerClass implements java.io.Serializable { private ReferencedClass obj; public ReferencedClass get() { return obj; } public void set(ReferencedClass obj) { this.obj = obj; } } private static class ReferencedClass implements java.io.Serializable { private int i = 0; public int get() { return i; } public void set(int i) { this.i = i; } } public static void main(String[] args) throws Exception { //Initialise the classes ContainerClass test1 = new ContainerClass(); ContainerClass test2 = new ContainerClass(); ReferencedClass ref = new ReferencedClass(); //Make both container class point to the same reference test1.set(ref); test2.set(ref); //This does what we expect: setting the integer in one (way of accessing the) referenced class sets it in the other one test1.get().set(1234); System.out.println(Integer.toString(test2.get().get())); //Now serialise the container classes java.io.ObjectOutputStream os = new java.io.ObjectOutputStream(new java.io.FileOutputStream("C:\\Users\\Public\\test1.ser")); os.writeObject(test1); os.close(); os = new java.io.ObjectOutputStream(new java.io.FileOutputStream("C:\\Users\\Public\\test2.ser")); os.writeObject(test2); os.close(); //And deserialise them java.io.ObjectInputStream is = new java.io.ObjectInputStream(new java.io.FileInputStream("C:\\Users\\Public\\test1.ser")); ContainerClass test3 = (ContainerClass)is.readObject(); is.close(); is = new java.io.ObjectInputStream(new java.io.FileInputStream("C:\\Users\\Public\\test2.ser")); ContainerClass test4 = (ContainerClass)is.readObject(); is.close(); //We expect the same thing as before, and would expect a result of 4321, but this doesn't happen as the referenced objects are now separate instances test3.get().set(4321); System.out.println(Integer.toString(test4.get().get())); } }

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  • Where to store the session object in a Standalone application?

    - by HanuAthena
    I'm having a session object that does NOT implement the java.lang.Serializable. (its a legacy application, and now I can't go and change the code) Is there any way where I can store the session object some where and later GET BACK THE SAME STATE in a STANDALONE application. One thought is to use RMI. Is there any better way of achieving this. Thank you :)

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  • JPA 2?EJB 3.1?JSF 2????????! WebLogic Server 12c?????????Java EE 6??????|WebLogic Channel|??????

    - by ???02
    2012?2???????????????WebLogic Server 12c?????????Java EE 6?????????????????????????????????????????????????????????????Oracle Enterprise Pack for Eclipse 12c??WebLogic Server 12c(???)????Java EE 6??????3??????????????????????????????JPA 2.0??????????·?????????EJB 3.1???????·???????????????(???)???????O/R?????????????JPA 2.0 Java EE 6????????????????????Web?????????????3?????(3????)???????·????????????·????????????????????????????????JPA(Java Persistence API) 2.0???EJB(Enterprise JavaBeans) 3.1???JSF(JavaServer Faces) 2.0????3????????????????·???????????JPA??Java??????????????·?????????????O/R?????????????????????·???????????EJB?Session Bean??????????????????·??????????????????????JSF??????????????????????????????????????? ??????JPA????Oracle Database??EMPLOYEES?????Java??????????????????????Entity Bean??????XML?????????????????????????XML????????????????????????????????????????????????????·?????????????????????????????????????????????????????????????Java EE 6??????JPA 2.0??????????·???????????????????????????????????????????????????????????????????????????????????????? ?????????????????????????????????????????????????????????????Oracle Enterprise Pack for Eclipse(OEPE)??????File????????New?-?Other??????? ??????New??????????????????????????Web?-?Dynamic Web Project???????Next????????????????Dynamic Web Project?????????????Project name????OOW???????????Target Runtime????New Runtime????????? ???New Server Runtime Environment???????????????Oracle?-?Oracle WebLogic Server 12c(12.1.1)???????Next???????????????????????????WebLogic home????C:\Oracle\Middleware\wlserver_12.1???????Finish?????????????WebLogic Home????????????????????????Java home?????????????????????Finish??????????????????????Dynamic Web Project????????????????Finish??????????????????JPA 2.0??????????·?????? ???????????????JPA 2.0???????????????·??????????????????Eclipse??Project Explorer?(??????·???)?????????OOW?????????????????????????????·???????????????Properties?????????????????·???·????????????????????????????Project Facets?????????????JPA??????(?????????????Details?????JPA 2.0?????????????????????)???????????????????Further configuration available????????? ???Modify Faceted Project??????????????????????????????????Connection????????????????????????????Add Connection????????? ??????New Connection Profile????????????????Connection Profile Type????Oracle Database Connection??????Next???????????? ???Specify a Driver and Connection Details???????Drivers????Oracle Database 10g Driver Default???????????Properties?????????????????????SIDxeHostlocalhostPort number1521User nameHRPasswordhr ???????????Test Connection??????????????????Ping Succeeded!?????????????????????????????Finish???????????Modify Faceted Project????????OK????????????????Properties for OOW????????OK?????????????????? ?????????Eclipse????????????????OOW?????????????????·???????????????JPA Tools?-?Generate Entities from Tables...??????? ????Generate Custom Entities???????????????????????????????Schema????HR??????Tables????EMPLOYEES???????????Next???????????? ???????????Next???????????Customize Default Entity Generation??????Package????model???????Finish?????????????JPQL?????????? ?????????Oracle Database??EMPLOYEES??????????????????·????model.Employee.java?????????????????????????????????·?????OOW????Java Resources?-?src?-?model???????Employee.java????????????????????????????????·???Employee????(Employee.java)?package model; import java.io.Serializable; import java.math.BigDecimal; import java.util.Date; import java.util.Set; import javax.persistence.Column;<...?...>/**  * The persistent class for the EMPLOYEES database table.  *  */ @Entity  // ?@Table(name="EMPLOYEES")  // ?// Apublic class Employee implements Serializable {        private static final long serialVersionUID = 1L;       @Id  // ?       @Column(name="EMPLOYEE_ID")        private long employeeId;        @Column(name="COMMISSION_PCT")        private BigDecimal commissionPct;        @Column(name="DEPARTMENT_ID")        private BigDecimal departmentId;        private String email;        @Column(name="FIRST_NAME")        private String firstName;       @Temporal( TemporalType.DATE)  //?       @Column(name="HIRE_DATE")        private Date hireDate;        @Column(name="JOB_ID")        private String jobId;        @Column(name="LAST_NAME")        private String lastName;        @Column(name="PHONE_NUMBER")        private String phoneNumber;        private BigDecimal salary;        //bi-directional many-to-one association to Employee<...?...>}  ???????????????·???????????????????????????????????????????@Table(name="")??????@Table??????????????????????????????????????? ?????????????????????????????????????·???????????????? ?????????????????????????????SQL?Data?????????? ???????????????A?????JPA?????????JPQL(Java Persistence Query Language)?????????????JPQL?????SQL???????????????????????????????????????????????????????????????????????????????????Employee.selectByNameEmployee??firstName????????????????????employeeId????????? ?????????????????????import java.util.Date;import java.util.Set;import javax.persistence.Column;<...?...>/**  * The persistent class for the EMPLOYEES database table.  *  */ @Entity  // ?@Table(name="EMPLOYEES")  // ?@NamedQueries({       @NamedQuery(name="Employee.selectByName" , query="select e from Employee e where e.firstName like :name order by e.employeeId")})<...?...> ?????????·??????OOW?-?JPA Content?-?persistent.xml??????Connection???????????????Database????JTA data source:???jdbc/test????????????????????????Java EE 6??????JPA 2.0???????????????????????????????????·??????????????????????????????????????SQL????????????????????????·????????????·??????????????XML??????????????????1??????????????????????????????????????????????????????????????????EJB 3.1????????·???????????EJB 3.1????????·?????????????????EJB 3.1?Stateless Session Bean?????·????????????????·???????????????????·??????????????????? EJB3.1?????JPA 2.0???????????·???????????????????????XML???????????????????????????????EJB 3.1?????????·????EJB?????????????????????????????????????????????????????????????? ????????EJB 3.1?Session Bean?????·????????????????????????????????????????????????????public List<Employee> getEmp(String keyword)firstName????????????Employee?????? ????????????????????·???????????OOW????????????·???????????????New?-?Other???????????????????????????????????EJB?-?Session Bean(EJB 3.x)??????NEXT????????????????????Create EJB 3.x Session Bean?????????????Java Package????ejb???class name????EmpLogic???????????State Type????Stateless?????????No-interface???????????????????????Finish???????????? ?????????Stateless Session Bean??????·?????EmpLogic.java????????????????????EmpLogic????·????????EJB?????????????Stateless Session Bean?????????@Stateless?????????????????????????????????????EmpLogic????(EmpLogic.java)?package ejb;import javax.ejb.LocalBean;import javax.ejb.Stateless;<...?...>import model.Employee;@Stateless@LocalBeanpublic class EmpLogic {       public EmpLogic() {       }} ??????????????????????????????????????·???????????????????????import??????????????????EmpLogic??????????????????????????·???????????????????????import????????(EmpLogic.java)?package ejb;import javax.ejb.LocalBean;import javax.ejb.Stateless;import javax.persistence.EntityManager;  // ?import javax.persistence.PersistenceContext;  // ?<...?...>import model.Employee;@Stateless@LocalBeanpublic class EmpLogic {      @PersistenceContext(unitName = "OOW")  // ?      private EntityManager em;  // ?       public EmpLogic() {       }} ?????????·???????JPA???????????????????·????????????????????????????CRUD???????????????????·????????????EntityManager???????????????????????????1????????????????·???????????????????????@PersistenceContext?????unitName?????????????persistence.xml????persistence-unit???name?????????????? ???????EmpLogic?????·???????????????????????????????????????????????????????????????????????????????EmpLogic????????·???????(EmpLogic.java)?package ejb;import java.util.List;  // ? import javax.ejb.LocalBean;import javax.ejb.Stateless;import javax.persistence.EntityManager;  // ? import javax.persistence.PersistenceContext;  // ? <...?...>import model.Employee;@Stateless@LocalBeanpublic class EmpLogic {       @PersistenceContext(unitName = "OOW")  // ?        private EntityManager em;  // ?        public EmpLogic() {       }      @SuppressWarnings("unchecked")  // ?      public List<Employee> getEmp(String keyword) {  // ?             StringBuilder param = new StringBuilder();  // ?             param.append("%");  // ?             param.append(keyword);  // ?             param.append("%");  // ?             return em.createNamedQuery("Employee.selectByName")  // ?                    .setParameter("name", param.toString()).getResultList();  // ?      }} ???EJB 3.1???Stateless Session Bean?????????? ???JSF 2.0???????????????????????????????????????????????????JAX-RS????RESTful?Web??????????????????????

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  • Persisting model state in ASP.NET MVC using Serialize HTMLHelper

    - by shiju
    ASP.NET MVC 2 futures assembly provides a HTML helper method Serialize that can be use for persisting your model object. The Serialize  helper method will serialize the model object and will persist it in a hidden field in the HTML form. The Serialize  helper is very useful when situations like you are making multi-step wizard where a single model class is using for all steps in the wizard. For each step you want to retain the model object's whole state.The below is serializing our model object. The model object should be a Serializable class in order to work with Serialize helper method. <% using (Html.BeginForm("Register","User")) {%><%= Html.Serialize("User",Model) %> This will generate hidden field with name "user" and the value will the serialized format of our model object.In the controller action, you can place the DeserializeAttribute in the action method parameter. [HttpPost]               public ActionResult Register([DeserializeAttribute] User user, FormCollection userForm) {     TryUpdateModel(user, userForm.ToValueProvider());     //To Do } In the above action method you will get the same model object that you serialized in your view template. We are updating the User model object with the form field values.

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  • Persisting model state in ASP.NET MVC using Serialize HTMLHelper

    - by shiju
    ASP.NET MVC 2 futures assembly provides a HTML helper method Serialize that can be use for persisting your model object. The Serialize  helper method will serialize the model object and will persist it in a hidden field in the HTML form. The Serialize  helper is very useful when situations like you are making multi-step wizard where a single model class is using for all steps in the wizard. For each step you want to retain the model object's whole state.The below is serializing our model object. The model object should be a Serializable class in order to work with Serialize helper method. <% using (Html.BeginForm("Register","User")) {%><%= Html.Serialize("User",Model) %> This will generate hidden field with name "user" and the value will the serialized format of our model object.In the controller action, you can place the DeserializeAttribute in the action method parameter. [HttpPost]               public ActionResult Register([DeserializeAttribute] User user, FormCollection userForm) {     TryUpdateModel(user, userForm.ToValueProvider());     //To Do } In the above action method you will get the same model object that you serialized in your view template. We are updating the User model object with the form field values.

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  • What is ODBC?

    According to Microsoft, ODBC is a specification for a database API.  This API is database and operating system agnostic due to the fact that the primary goal of the ODBC API is to be language-independent. Additionally, the open functions of the API are created by the manufactures of DBMS-specific drivers. Developers can use these exposed functions from within their own custom applications so that they can communicate with DBMS through the language-independent drivers. ODBC Advantages Multiple ODBC drivers for each DBSM Example Oracle’s ODBC Driver Merant’s Oracle Driver Microsoft’s Oracle Driver ODBC Drivers are constantly updated for the latest data types ODBC allows for more control when querying ODBC allows for Isolation Levels ODBC Disadvantages ODBC Requires DSN ODBC is the proxy between an application and a database ODBC is dependent on third party drivers ODBC Transaction Isolation Levels are related to and limited by the transaction management capabilities of the data source. Transaction isolation levels:  READ UNCOMMITTED Data is allowed to be read prior to the committing of a transaction.  READ COMMITTED Data is only accessible after a transaction has completed  REPEATABLE READ The same data value is read during the entire transaction  SERIALIZABLE Transactions have no effect on other transactions

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  • LLBLGen Pro and JSON serialization

    - by FransBouma
    I accidentally removed a reply from my previous blogpost, and as this blog-engine here at weblogs.asp.net is apparently falling apart, I can't re-add it as it thought it would be wise to disable comment controls on all posts, except new ones. So I'll post the reply here as a quote and reply on it. 'Steven' asks: What would the future be for LLBLGen Pro to support JSON for serialization? Would it be worth the effort for a LLBLGenPro user to bother creating some code templates to produce additional JSON serializable classes? Or just create some basic POCO classes which could be used for exchange of client/server data and use DTO to map these back to LLBGenPro ones? If I understand the work around, it is at the expense of losing xml serialization. Well, as described in the previous post, to enable JSON serialization, you can do that with a couple of lines and some attribute assignments. However, indeed, the attributes might make the XML serialization not working, as described in the previous blogpost. This is the case if the service you're using serializes objects using the DataContract serializer: this serializer will give up to serialize the entity objects to XML as the entity objects implement IXmlSerializable and this is a no-go area for the DataContract serializer. However, if your service doesn't use a DataContract serializer, or you serialize the objects manually to Xml using an xml serializer, you're fine. When you want to switch to Xml serializing again, instead of JSON in WebApi, and you have decorated the entity classes with the data-contract attributes, you can switch off the DataContract serializer, by setting a global configuration setting: var xml = GlobalConfiguration.Configuration.Formatters.XmlFormatter; xml.UseXmlSerializer = true; This will make the WebApi use the XmlSerializer, and run the normal IXmlSerializable interface implementation.

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  • Advantages of Hudson and Sonar over manual process or homegrown scripts.

    - by Tom G
    My coworker and I recently got into a debate over a proposed plan at our workplace. We've more or less finished transitioning our Java codebase into one managed and built with Maven. Now, I'd like for us to integrate with Hudson and Sonar or something similar. My reasons for this are that it'll provide a 'zero-click' build step to provide testers with new experimental builds, that it will let us deploy applications to a server more easily, that tools such as Sonar will provide us with well-needed metrics on code coverage, Javadoc, package dependencies and the like. He thinks that the overhead of getting up to speed with two new frameworks is unacceptable, and that we should simply double down on documentation and create our own scripts for deployment. Since we plan on some aggressive rewrites to pay down the technical debt previous developers incurred (gratuitous use of Java's Serializable interface as a file storage mechanism that has predictably bit us in the ass) he argues that we can document as we go, and that we'll end up changing a large swath of code in the process anyways. I contend that having accurate metrics that Sonar (or fill in your favorite similar tool) provide gives us a good place to start for any refactoring efforts, not to mention general maintenance -- after all, knowing which classes are the most poorly documented, even if it's just a starting point, is better than seat-of-the-pants guessing. Am I wrong, and trying to introduce more overhead than we really need? Some more background: an alumni of our company is working at a Navy research lab now and suggested these two tools in particular as one they've had great success with using. My coworker and I have also had our share of friendly disagreements before -- he's more of the "CLI for all, compiles Gentoo in his spare time and uses Git" and I'm more of a "Give me an intuitive GUI, plays with XNA and is fine with SVN" type, so there's definitely some element of culture clash here.

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  • LibGdx efficient data saving/loading?

    - by grimrader22
    Currently, my LibGDX game consists of a 512 x 512 map of Tiles and entities such as players and monsters. I am wondering how to efficiently save and load the data of my levels. At the moment I am using JSON serialization for each class I want to save. I implement the Json.Serializable interface for all of these classes and write only the variables that are necessary. So my map consists of 512 x 512 tiles, that's 260,000 tiles. Each tile on the map consists of a Tile object, which points to some final Tile object like a GRASS_TILE or a STONE_TILE. When I serialize each level tile, the final Tile that it points to is re-serialized over and over again, so if I have 100 Tiles all pointing to GRASS_TILE, the data of GRASS_TILE is written 100 times over. When I go to load/deserialize my objects, 100 GrassTile objects are created, but they are each their own object. They no longer point to the final tile object. I feel like this reading/writing files very slow. If I were to abandon JSON serialization, to my knowledge my next best option would be saving the level data to a sql database. Unless there is a way to speed up serializing/deserializing 260,000 tiles I may have to do this. Is this a good idea? Could I really write that many tiles to the database efficiently? To sum all this up, I am trying to save my levels using JSON serialization, but it is VERY slow. What other options do I have for saving the data of so many tiles. I also must note that the JSON serialization is not slow on a PC, it is only VERY slow on a mobile device. Since file writing/reading is so slow on mobile devices, what can I do?

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  • PostgreSQL, Ubuntu, NetBeans IDE (Part 3)

    - by Geertjan
    To complete the picture, let's use the traditional (that is, old) Hibernate mechanism, i.e., via XML files, rather than via the annotations shown yesterday. It's definitely trickier, with many more places where typos can occur, but that's why it's the old mechanism. I do not recommend this approach. I recommend the approach shown yesterday. The other players in this scenario include PostgreSQL, as outlined in the previous blog entries in this series. Here's the structure of the module, replacing the code shown yesterday: Here's the Employee class, notice that it has no annotations: import java.io.Serializable; import java.util.Date; public class Employees implements Serializable {         private int employeeId;     private String firstName;     private String lastName;     private Date dateOfBirth;     private String phoneNumber;     private String junk;     public int getEmployeeId() {         return employeeId;     }     public void setEmployeeId(int employeeId) {         this.employeeId = employeeId;     }     public String getFirstName() {         return firstName;     }     public void setFirstName(String firstName) {         this.firstName = firstName;     }     public String getLastName() {         return lastName;     }     public void setLastName(String lastName) {         this.lastName = lastName;     }     public Date getDateOfBirth() {         return dateOfBirth;     }     public void setDateOfBirth(Date dateOfBirth) {         this.dateOfBirth = dateOfBirth;     }     public String getPhoneNumber() {         return phoneNumber;     }     public void setPhoneNumber(String phoneNumber) {         this.phoneNumber = phoneNumber;     }     public String getJunk() {         return junk;     }     public void setJunk(String junk) {         this.junk = junk;     } } And here's the Hibernate configuration file: <?xml version="1.0"?> <!DOCTYPE hibernate-configuration PUBLIC       "-//Hibernate/Hibernate Configuration DTD 3.0//EN"     "http://hibernate.sourceforge.net/hibernate-configuration-3.0.dtd"> <hibernate-configuration>     <session-factory>         <property name="hibernate.connection.driver_class">org.postgresql.Driver</property>         <property name="hibernate.connection.url">jdbc:postgresql://localhost:5432/smithdb</property>         <property name="hibernate.connection.username">smith</property>         <property name="hibernate.connection.password">smith</property>         <property name="hibernate.connection.pool_size">1</property>         <property name="hibernate.default_schema">public"</property>         <property name="hibernate.transaction.factory_class">org.hibernate.transaction.JDBCTransactionFactory</property>         <property name="hibernate.current_session_context_class">thread</property>         <property name="hibernate.dialect">org.hibernate.dialect.PostgreSQLDialect</property>         <property name="hibernate.show_sql">true</property>         <mapping resource="org/db/viewer/employees.hbm.xml"/>     </session-factory> </hibernate-configuration> Next, the Hibernate mapping file: <?xml version="1.0"?> <!DOCTYPE hibernate-mapping PUBLIC       "-//Hibernate/Hibernate Mapping DTD 3.0//EN"       "http://hibernate.sourceforge.net/hibernate-mapping-3.0.dtd"> <hibernate-mapping>     <class name="org.db.viewer.Employees"            table="employees"            schema="public"            catalog="smithdb">         <id name="employeeId" column="employee_id" type="int">             <generator class="increment"/>         </id>         <property name="firstName" column="first_name" type="string" />         <property name="lastName" column="last_name" type="string" />         <property name="dateOfBirth" column="date_of_birth" type="date" />         <property name="phoneNumber" column="phone_number" type="string" />         <property name="junk" column="junk" type="string" />             </class>     </hibernate-mapping> Then, the HibernateUtil file, for providing access to the Hibernate SessionFactory: import java.net.URL; import org.hibernate.cfg.AnnotationConfiguration; import org.hibernate.SessionFactory; public class HibernateUtil {     private static final SessionFactory sessionFactory;         static {         try {             // Create the SessionFactory from standard (hibernate.cfg.xml)             // config file.             String res = "org/db/viewer/employees.cfg.xml";             URL myURL = Thread.currentThread().getContextClassLoader().getResource(res);             sessionFactory = new AnnotationConfiguration().configure(myURL).buildSessionFactory();         } catch (Throwable ex) {             // Log the exception.             System.err.println("Initial SessionFactory creation failed." + ex);             throw new ExceptionInInitializerError(ex);         }     }         public static SessionFactory getSessionFactory() {         return sessionFactory;     }     } Finally, the "createKeys" in the ChildFactory: @Override protected boolean createKeys(List list) {     Session session = HibernateUtil.getSessionFactory().getCurrentSession();     Transaction transac = null;     try {         transac = session.beginTransaction();         Query query = session.createQuery("from Employees");         list.addAll(query.list());     } catch (HibernateException he) {         Exceptions.printStackTrace(he);         if (transac != null){             transac.rollback();         }     } finally {         session.close();     }     return true; } Note that Constantine Drabo has a similar article here. Run the application and the result should be the same as yesterday.

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