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  • Protect all XML-RPC calls with HTTP basic auth but one

    - by bodom_lx
    I set up a Django project for smartphone serving XML-RPC methods over HTTPS and using basic auth. All XML-RPC methods require username and password. I would like to implement a XML-RPC method to provide registration to the system. Obviously, this method should not require username and password. The following is the Apache conf section responsible for basic auth: <Location /RPC2> AuthType Basic AuthName "Login Required" Require valid-user AuthBasicProvider wsgi WSGIAuthUserScript /path/to/auth.wsgi </Location> This is my auth.wsgi: import os import sys sys.stdout = sys.stderr sys.path.append('/path/to/project') os.environ['DJANGO_SETTINGS_MODULE'] = 'project.settings' from django.contrib.auth.models import User from django import db def check_password(environ, user, password): """ Authenticates apache/mod_wsgi against Django's auth database. """ db.reset_queries() kwargs = {'username': user, 'is_active': True} try: # checks that the username is valid try: user = User.objects.get(**kwargs) except User.DoesNotExist: return None # verifies that the password is valid for the user if user.check_password(password): return True else: return False finally: db.connection.close() There are two dirty ways to achieve my aim with current situation: Have a dummy username/password to be used when trying to register to the system Have a separate Django/XML-RPC application on another URL (ie: /register) that is not protected by basic auth Both of them are very ugly, as I would also like to define a standard protocol to be used for services like mine (it's an open Dynamic Ridesharing Architecture) Is there a way to unprotect a single XML-RPC call (ie. a defined POST request) even if all XML-RPC calls over /RPC2 are protected?

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  • How do you pass or share variables between django views?

    - by Hugh
    Hi, I'm kind of lost as to how to do this: I have some chained select boxes, with one select box per view. Each choice should be saved so that a query is built up. At the end, the query should be run. But how do you share state in django? I can pass from view to template, but not template to view and not view to view. Or I'm truly not sure how to do this. Please help!

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  • Can a python view template be made to be 'safe/secure' if I make it user editable?

    - by Blankman
    Say I need to have a templating system where a user can edit it online using an online editor. So they can put if tags, looping tags etc., but ONLY for specific objects that I want to inject into the template. Can this be made to be safe from security issues? i.e. them somehow outputing sql connection string information or scripting things outside of the allowable tags and injected objects.

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  • What javascript templating engine do you recommend?

    - by flybywire
    Do you have experience with a Javascript templating engine, one that is stable, easy to use and has good performance? I need to do apply the same template many times for different data. I prefer to download the template itself once (and have it cached) rather than processing the template on the server. Also, this way the template itself would be a static resource more easily cached in the server side too.

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  • Best practice: How to persist simple data without a database in django?

    - by Infinity
    I'm building a website that doesn't require a database because a REST API "is the database". (Except you don't want to be putting site-specific things in there, since the API is used by mostly mobile clients) However there's a few things that normally would be put in a database, for example the "jobs" page. You have master list view, and the detail views for each job, and it should be easy to add new job entries. (not necessarily via a CMS, but that would be awesome) e.g. example.com/careers/ and example.com/careers/77/ I could just hardcode this stuff in templates, but that's no DRY- you have to update the master template and the detail template every time. What do you guys think? Maybe a YAML file? Or any better ideas? Thx

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  • Unexplained Django error. Diagnosis anyone?

    - by colorfulgrayscale
    I have a django project I keep on github. It worked perfectly fine on my laptop. I downloaded it on my desktop and tried to "python manage.py runserver" or even "python manage.py shell" I get a Error: No module named messages No other messages, no stack trace, nothing..Anyone have any idea whats going on? Thanks.

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  • Why is mod_wsgi not able to write data? IOError: failed to write data

    - by BryanWheelock
    What could be causing this error: $ sudo tail -n 100 /var/log/apache2/error.log' [Wed Dec 29 15:20:03 2010] [error] [client 220.181.108.181] mod_wsgi (pid=20343): Exception occurred processing WSGI script '/home/username/public_html/idm.wsgi'. [Wed Dec 29 15:20:03 2010] [error] [client 220.181.108.181] IOError: failed to write data Here is the WSGI script: $ cat public_html/idm.wsgi import os import sys sys.path.append('/home/username/public_html/IDM_app/') os.environ['DJANGO_SETTINGS_MODULE'] = 'settings' import django.core.handlers.wsgi application = django.core.handlers.wsgi.WSGIHandler() Why would Django not be able to write data? I'm running Django 1.2.4

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  • running python script with cron

    - by paulo
    hey guys, im trying to run a python script after every 5 minutes using cron, inside the script is a django import import django when running the crontab i get mailed the following error ImportError: No module named django this is what the crontab file looks like: [email protected] */5 * * * * /usr/bin/python /Users/paulo/Desktop/ashtanga/ping/sender.py do anyone of you know whats causing this ? btw i do have django insalled version 1.2, python 2.6, and MacOX 10.6

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  • why my code error,about serve the static file using django..

    - by zjm1126
    my settings.py: DIRNAME = os.path.dirname(__file__) STATIC_DOC_ROOT = os.path.join(DIRNAME, 'media') MEDIA_URL = '/media/' my urls.py: def google(request): return render_to_response('a.html',context_instance=RequestContext(request)) urlpatterns = patterns('', (r'^$',google), (r'^media/(?P<path>.*)$', 'django.views.static.serve',{'document_root':settings.STATIC_DOC_ROOT,'show_indexes': True}), ) and my a.html is: <script type="text/javascript" src="/media/jquery-1.4.2.js"></script> <script type="text/javascript"> alert($) </script> but,it can't defiend the '$' why ? thanks

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  • Django-imagekit: how to reduce image quality with a preprocessor_spec ?

    - by pierre-guillaume-degans
    Hi, please excuse me for my ugly english :p I've created this simple model class, with a Preprocessor to reduce my photos'quality (the photos'extension is .JPG): from django.db import models from imagekit.models import ImageModel from imagekit.specs import ImageSpec from imagekit import processors class Preprocessor(ImageSpec): quality = 50 processors = [processors.Format] class Picture(ImageModel): image = models.ImageField(upload_to='pictures') class IKOptions: preprocessor_spec = Preprocessor The problem : pictures'quality are not reduced. :( Any idea to fix it ? Thank you very much ;)

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  • How can I write this query in Django? (datetime)

    - by alex
    | time_before | datetime | YES | MUL | NULL | | | time_after | datetime | YES | MUL | NULL | | the_tag = Tag.objects.get(id=tag_id) Log.objects.filter(blah).extra(where=['last_updated >'+the_tag.time_before, 'last_updated' < the_tag.time_after]) Ok. Basically, I have an object that's called "the_tag". I want to select from Log where log.last_updated (which is a datetime field) is between the tag's time. But, I don't know how to write the last part of this Django query.

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  • What should a Django user know when moving from MySQL to PostgreSQL?

    - by tmitchell
    Most of my experience with Django thus far has been with MySQL and mysqldb. For a new app I'm writing, I'm dipping my toe in the PostgreSQL water, now that I have seen the light. While writing a data import script, I stumbled upon an issue with the default autocommit behavior. I would guess there are other "gotchas" that might crop up. What else should I be on the lookout for?

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  • How to share memory buffer across sessions in Django?

    - by afriza
    I want to have one party (or more) sends a stream of data via HTTP request(s). Other parties will be able to receive the same stream of data in almost real-time. The data stream should be accessible across sessions (according to access control list). How can I do this in Django? If possible I would like to avoid database access and use in memory buffer (along with some synchronization mechanism)

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  • how to count all distinct records in many-to-many relations in django ORM?

    - by marduk-pl
    hi, i have two models: class Project(models.Model): categories = models.ManyToManyField(Category) class Category(models.Model): name = models.CharField() now, i make some queryset: query = Project.objects.filter(id__in=[1,2,3,4]) and i like to get list of all distinct categories in this queryset with count of projects with refering to these categories - exactly i would like to get that results: category1 - 10 projects category2 - 5 projects that is opposite to this query: query2 = query.annotate(Count('categories')) what return me: project1 - 2categories project2 - 7categories how can i make it in django ORM?

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  • Are there any generic shipping calculators out there for DJango?

    - by Jon Cage
    I'm in the process of settings up a website (I'm using DJango) to begin selling some toys I build and need a way of calculating shipping costs for my customers. Are there any (preferably free) shipping calculators which accept a customers address and return the cost for different delivery companies / delivery options? It would be nice if the API could indicate cost vs delivery time. We'll be shipping world-wide if that makes a difference?

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  • How to update the filename of a Django's FileField instance ?

    - by pierre-guillaume-degans
    Hello, Here a simple django model: class SomeModel(models.Model): title = models.CharField(max_length=100) video = models.FileField(upload_to='video') I would like to save any instance so that the video's file name would be a valid file name of the title. For example, in the admin interface, I load a new instance with title "Lorem ipsum" and a video called "video.avi". The copy of the file on the server should be "Lorem Ipsum.avi" (or "Lorem_Ipsum.avi"). Thank you :)

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  • Eclipse + Django: How to get bytecode output when python source files change?

    - by Sean Ochoa
    Whenever I change my python source files in my Django project, the .pyc files become out of date. Of course that's because I need to recompile them in order to test them through my local Apache web server. I would like to get around this manual process by employing some automatic means of compiling them on save, or on build through Eclipse, or something like that. What's the best and proper way to do this?

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