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  • MySQL PHP SELECT throwing up an error?

    - by user1909695
    I am trying to make a comment section on my hand made site, using PHP and MySQL. I have got the comments stored in my database, but when I try to SELECT them my site throws up this error, mysql_result() [function.mysql-result]: Unable to jump to row 0 on MySQL result index 9 in /home/a9210109/public_html/comments.php on line 16 My code so far is below <?php $comment = $_POST['comment']; $mysql_host = ""; $mysql_database = ""; $mysql_user = ""; $mysql_password = ""; mysql_connect($mysql_host,$mysql_user,$mysql_password); @mysql_select_db($mysql_database) or die( "Unable to select database"); $CreateTable = "CREATE TABLE comments (comment VARCHAR(255), time VARCHAR(255));"; mysql_query($CreateTable); $UseComment = "INSERT INTO comments VALUES ('$comment')"; mysql_query($UseComment); $SelectComments = "SELECT * FROM comments"; $comments = mysql_query($SelectComments); $num=mysql_numrows($comments); $variable=mysql_result($comments,$i,"comment"); mysql_close(); ?> <a href="#" onclick="toggle_visibility('hidden');">Show/Hide Comments</a> <?php $i=0; while ($i < $num) { $comment=mysql_result($comments,$i,"comment"); echo "<div id='hidden' style='display:none'><h3>$comment</h3></div>"; $i++; } ?>

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  • Account activation PHP

    - by Wayne
    I created this account registration activation script of my own, I have checked it over again and again to find errors, I don't see a particular error... The domain would be like this: http://domain.com/include/register.php?key=true&p=AfRWDCOWF0BO6KSb6UmNMf7d333gaBOB Which comes from an email, when a user clicks it, they get redirected to this script: if($_GET['key'] == true) { $key = $_GET['p']; $sql = "SELECT * FROM users WHERE user_key = '" . $key . "'"; $result = mysql_query($sql) or die(mysql_error()); if(mysql_affected_rows($result) > 0) { $sql = "UPDATE users SET user_key = '', user_active = '1' WHERE user_key = '" . $key . "'"; $result = mysql_query(sql) or die(mysql_error()); if($result) { $_SESSION['PROCESS'] = $lang['Account_activated']; header("Location: ../index.php"); } else { $_SESSION['ERROR'] = $lang['Key_error']; header("Location: ../index.php"); } } else { $_SESSION['ERROR'] = $lang['Invalid_key']; header("Location: ../index.php"); } } It doesn't even work at all, I looked in the database with the user with that key, it matches but it keeps coming up as an error which is extremely annoying me. The database is right, the table and column is right, nothing wrong with the database, it's the script that isn't working. Help me out, guys. Thanks :)

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  • PHP Included files writing their own content from Importer values ...

    - by Adrian
    Hello, I have a index.php file that will include several external files: "content/templates/id1/template.php" "content/templates/id2/template.php" "content/templates/id3/template.php" etc. All these files are loaded dynamically into index.php (it reads all folders inside "templates" directory and then includes every "template.php" file). I want to make "template.php" to have the same code in all the "id1,id2,id3" folders, BUT to load values from index.php depending in which folder it stays.. How can I do that? Thank You!

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  • php insert doesnot take place _ URGENT HELP PLEASE

    - by reggie
    my code is as follows <?php include("config.php"); $ip=$_SERVER['REMOTE_ADDR']; if($_POST['id']) { $id=$_POST['id']; $id = mysql_escape_String($id); $ip_sql=mysql_query("select ip_add from Voting_IP where mes_id_fk='$id' and ip_add='$ip'"); $count=mysql_num_rows($ip_sql); if($count==0) { $sql = "update Messages set up=up+1 where mes_id='$id'"; mysql_query($sql); $sql_in = "insert into Voting_IP (mes_id_fk,ip_add) values ('$id','$ip')"; mysql_query($sql_in) or die(mysql_error()); echo "<script>alert('Thanks for the vote');</script>"; } else { echo "<script>alert('You have already voted');</script>"; } $result=mysql_query("select up from Messages where mes_id='$id'"); $row=mysql_fetch_array($result); $up_value=$row['up']; echo "<img src='button.png' width='110' height='90'>"; echo $up_value; } ?> My problem is that the insert process doesnot take place at all. the script tags echos an alert box. even the img tag is echoed to the web page. but the insert process doesnot take place. the config file is fine.. note: this code works on my local machine which has php 5.3 but it doesnot work on the server which has php 5.2.. any advice..???

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  • How to send XML and other post parameters via cURL in PHP

    - by tomaszs
    Hello. I've used code below to send XML to my REST API. $xml_string_data contains proper XML, and it is passed well to mypi.php: //set POST variables $url = 'http://www.server.cu/mypi.php'; $fields = array( 'data'=>urlencode($xml_string_data) ); //url-ify the data for the POST $fields_string = ""; foreach($fields as $key=>$value) { $fields_string .= $key.'='.$value.'&'; } rtrim($fields_string,'&'); echo $fields_string; //open connection $ch = curl_init(); curl_setopt($ch,CURLOPT_URL,$url); curl_setopt($ch, CURLOPT_RETURNTRANSFER, true); curl_setopt($ch,CURLOPT_POST,count($fields)); curl_setopt($ch,CURLOPT_POSTFIELDS,$fields_string); curl_setopt($ch,CURLOPT_HTTPHEADER,array ( "Expect: " )); //execute post $result = @curl_exec($ch); But when I've added other field: $fields = array( 'method' => "methodGoPay", 'data'=>urlencode($xml_string_data) ); It stopped to work. On the mypi.php I don't recieve any more POST parameters at all! Could you you please tell me what to do to send XML and other post parameters in one cURL request? Please don't suggest using any libraries, I wan't to acomplish it in plain PHP.

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  • jQuery Validate PHP Response

    - by Kurt
    Hello Everybody, my problem is, I want to validate an email adresse with jquery. Not only the syntax but rather if the email is already registrated. There are some tutorials but they are not working! At first the Jquery Code: <script id="demo" type="text/javascript"> $(document).ready(function() { // validate signup form on keyup and submit var validator = $("form#signupform").validate({ rules: { Vorname: { required: true, minlength: 3 }, Nachname:{ required: true, minlength: 4 }, password: { required: true, minlength: 5 }, password_confirm: { required: true, minlength: 5, equalTo: "#password" }, Email: { required: true, email: true, type: "POST", remote: "remotemail.php" }, dateformat: "required", ... </script> And now the PHP Code: <?php include('dbsettings.php'); $conn = mysql_connect($dbhost,$dbuser,$dbpw); mysql_select_db($dbdb,$conn); $auslesen1 = "SELECT Email FROM flo_user"; $auslesen2 = mysql_query($auslesen1,$conn); $registered_email = mysql_fetch_assoc($auslesen2); $requested_email = $_POST['Email']; if( in_array($requested_email, $registered_email) ){ echo "false"; } else{ echo "true"; } ?> I tried return TRUE/ return FALSE as well, but this displays "Email is registrated" all the time. json_encode didn't work as well. Thanks a lot!

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  • php request variables assigning $_GEt

    - by chris
    if you take a look at a previous question http://stackoverflow.com/questions/2690742/mod-rewrite-title-slugs-and-htaccess I am using the solution that Col. Shrapnel proposed- but when i assign values to $_GET in the actual file and not from a request the code doesnt work. It defaults away from the file as if the $_GET variables are not set The code I have come up with is- if(!empty($_GET['cat'])){ $_GET['target'] = "category"; if(isset($_GET['page'])){ $_GET['pageID'] = $_GET['page']; } $URL_query = "SELECT category_id FROM cats WHERE slug = '".$_GET['cat']."';"; $URL_result = mysql_query($URL_query); $URL_array = mysql_fetch_array($URL_result); $_GET['category_id'] = $URL_array['category_id']; }elseif($_GET['product']){ $_GET['target'] = "product"; $URL_query = "SELECT product_id FROM products WHERE slug = '".$_GET['product']."';"; $URL_result = mysql_query($URL_query); $URL_array = mysql_fetch_array($URL_result); print_r($URL_array); $_GET['product_id'] = $URL_array['product_id']; The original variable string that im trying to represent is /cart.php?Target=product&product_id=16142&category_id=249 And i'm trying to build the query string variables with code and including cart.php so i can use cleaner URL's So I have product/product-title-with-clean-url/ going to slug.php?product=slug Then the slug searches the db for a record with the matching slug and returns the product_id as in the code above.Then built the query string and include cart.php

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  • PHP static objects giving a fatal error

    - by Webbo
    I have the following PHP code; <?php component_customer_init(); component_customer_go(); function component_customer_init() { $customer = Customer::getInstance(); $customer->set(1); } function component_customer_go() { $customer = Customer::getInstance(); $customer->get(); } class Customer { public $id; static $class = false; static function getInstance() { if(self::$class == false) { self::$class = new Customer; } else { return self::$class; } } public function set($id) { $this->id = $id; } public function get() { print $this->id; } } ?> I get the following error; Fatal error: Call to a member function set() on a non-object in ....../classes/customer.php on line 9 Can anyone tell me why I get this error? I know this code might look strange, but it's based on a component system that I'm writing for a CMS. The aim is to be able to replace HTML tags in the template e.g.; <!-- component:customer-login --> with; <?php component_customer_login(); ?> I also need to call pre-render methods of the "Customer" class to validate forms before output is made etc. If anyone can think of a better way, please let me know but in the first instance, I'd like to know why I get the "Fatal error" mentioned above. Cheers

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  • bitly php url wont work???

    - by mathiregister
    Hi guys, <?php include('bitly.php'); $bitly = new bitly('myusername', 'myapikey'); print $bitly->shorten('http://www.google.com'); ?> WORKING!!! $currenturl = (!empty($_SERVER['HTTPS'])) ? "https://".$_SERVER['SERVER_NAME'].$_SERVER['REQUEST_URI'] : "http://".$_SERVER['SERVER_NAME'].$_SERVER['REQUEST_URI']; include('bitly.php'); $bitly = new bitly('myusername', 'myapikey'); print $bitly->shorten($currenturl); WORKING!!! include('bitly.php'); $currenturl = (!empty($_SERVER['HTTPS'])) ? "https://".$_SERVER['SERVER_NAME'].$_SERVER['REQUEST_URI'] : "http://".$_SERVER['SERVER_NAME'].$_SERVER['REQUEST_URI']; $url = "somehashtag" $shareurl = $currenturl . '#' . $url; $bitly = new bitly('myusername', 'myapikey'); print $bitly->shorten($shareurl); NOT WORKING!!! Any idea why? If i print out the $shareurl i can see that it's a completely normal url that i could paste onto the normal bit.ly website. I don't get it! Any ideas? Would be great if you could help me!

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  • HTML5 audio with PHP script does not work on iPad/Iphone

    - by saulob
    Ok, I'm trying to play an HTML audio code on iPad but does not work. I created one PHP script to send to the MP3 request to the HTML5 audio code mp3_file_player.php?n=mp3file.mp3 The player is here: http://www.avault.com/news/podcast-news/john-romero-podcast-episode-80/ You will see that works on every HTML5 supported browser even on my iPod Touch. But does not work on iPad/iPhone, even on Safari on Mac OSX (I tried on Safari/Windows, worked fine) This is my PHP code: header("X-Powered-By: "); header("Accept-Ranges: bytes"); header("Content-Length: ". (string)(filesize($episode_filename)) .""); header("Content-type: audio/mpeg"); readfile($episode_filename); exit(); Everything works fine, the MP3 has the same headers like reading the mp3 directly. HTTP Headers from direct file access: (Status-Line) HTTP/1.1 200 OK Date Mon, 31 May 2010 20:27:31 GMT Server Apache/2.2.9 Last-Modified Wed, 26 May 2010 13:39:19 GMT Etag "dac0039-41d91f8-4877f669cefc0" Accept-Ranges bytes Content-Length 50656162 Content-Range bytes 18390614-69046775/69046776 Keep-Alive timeout=15, max=100 Connection Keep-Alive Content-Type audio/mpeg HTTP Header from my PHP script: (Status-Line) HTTP/1.1 200 OK Date Mon, 31 May 2010 20:27:08 GMT Server Apache/2.2.9 Accept-Ranges bytes Content-Length 69046776 Keep-Alive timeout=15, max=100 Connection Keep-Alive Content-Type audio/mpeg The only thing different it's the Content-Range, I even tried to add it, but if I use it the player will not work on my Ipod Touch. So I removed. Thank you very much.

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  • Unserializing an API return object (PHP/Ebay API)

    - by DavidYell
    I have been working with the Ebay api for a project and have found it great. I have however found a problem now, more PHP related. When I read my items from Ebay, I store a bunch of details in the database. Currently, just for the sake of it really, I serialize the whole return object and store it in the database in a related table. The idea being, that when I display my information, I have all the details to hand should I need them. The problem arises in that the pricing information is always in a sub object. [ConvertedAdjustmentAmount] => __PHP_Incomplete_Class Object ( [__PHP_Incomplete_Class_Name] => eBayAmountType [_] => 0 [currencyID] => USD ) As you can see when I unserialize my object, my cunning plan falls foul of the Incomplete class problem. I have checked the following question, without success. http://stackoverflow.com/questions/965611/forcing-access-to-php-incomplete-class-object-properties The main issue lies, as far as I can see, in that the price class is stored in the Ebay api, so how do I recreate it? I have been reading this page, http://uk3.php.net/manual/en/function.unserialize.php and trying to figure out, unserialize_callback_func which I can't figure out either, so any help would be appreciated!

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  • accessing private variable from member function in PHP

    - by Carson Myers
    I have derived a class from Exception, basically like so: class MyException extends Exception { private $_type; public function type() { return $this->_type; //line 74 } public function __toString() { include "sometemplate.php"; return ""; } } Then, I derived from MyException like so: class SpecialException extends MyException { private $_type = "superspecial"; } If I throw new SpecialException("bla") from a function, catch it, and go echo $e, then the __toString function should load a template, display that, and then not actually return anything to echo. This is basically what's in the template file <div class="<?php echo $this->type(); ?>class"> <p> <?php echo $this->message; ?> </p> </div> in my mind, this should definitely work. However, I get the following error when an exception is thrown and I try to display it: Fatal error: Cannot access private property SpecialException::$_type in C:\path\to\exceptions.php on line 74 Can anyone explain why I am breaking the rules here? Am I doing something horribly witty with this code? Is there a much more idiomatic way to handle this situation? The point of the $_type variable is (as shown) that I want a different div class to be used depending on the type of exception caught.

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  • Problem with checkboxes, sql select statements & php

    - by smokey20
    I am trying to display some rows from a database table based on choices submitted by the user. Here is my form code <form action="choice.php" method="POST" > <input type="checkbox" name="variable[]" value="Apple">Apple <input type="checkbox" name="variable[]" value="Banana">Banana <input type="checkbox" name="variable[]" value="Orange">Orange <input type="checkbox" name="variable[]" value="Melon">Melon <input type="checkbox" name="variable[]" value="Blackberry">Blackberry From what I understand I am placing the values of these into an array called variable. Two of my columns are called receipe name and ingredients(each field under ingredients can store a number of fruits). What I would like to do is, if a number of checkboxes are selected then the receipe name/s is displayed. Here is my php code. <?php // Make a MySQL Connection mysql_connect("localhost", "*****", "*****") or die(mysql_error()); mysql_select_db("****") or die(mysql_error()); $variable=$_POST['variable']; foreach ($variable as $variablename) { echo "$variablename is checked"; } $query = "SELECT receipename FROM fruit WHERE $variable like ingredients"; $row = mysql_fetch_assoc($result); foreach ($_POST['variabble'] as $ingredients) echo $row[$ingredients] . '<br/>'; ?> I am very new to php and just wish to display the data, I do not need to perform any actions on it. I have tried many select statements but I cannot get any results to display. My db connection is fine and it does print out what variables are checked. Many thanks in advance.

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  • Problem with thumbnails after newly added - PHP on-the-fly method

    - by Wayne
    Hey again... to those that may have read my previous question that got solved a couple minutes ago .< The on-the-fly php script works perfectly, but when I went to upload new images into a gallery which I made myself, the images are resized to 150 x 150 for what I wanted... however, when it comes to new images being added it is all black... As you can see the three black images that were uploaded to the folder and the directory added to the database. What is causing this? If I view the source, the code is fine... the while loop in the PHP generates an output like this: <div class="view-wrap" id="photo-10"> <div class="view-icon"> <div class="img-label"> <a href="#" id="10" class="delete"><img src="img/small-delete.png" /> Delete</a> </div> <a href="img/events/Paintballing/24251_1395408043148_1170626626_1204038_5382765_n.jpg"> <img src="image.php?dir=img/events/Paintballing/24251_1395408043148_1170626626_1204038_5382765_n.jpg" alt="" width="110" height="110" /> </a> </div> </div> An example of one block. If I view the source (in Firefox) and click on the image.php?dir=img/events/Paintballing/24251_1395408043148_1170626626_1204038_5382765_n.jpg by exmaple, I can see the thumbnail at it's 150 x 150 size but in the layout, it shows a black thumbnail... Does anyone know why this is happening?

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  • Image generated with PHP dosn't show

    - by lolalola
    Hi, whats wrong with my code. image dosn't show in test2.php file File: test2.php: <img src = "test.php" /> File: test.php session_start(); $md5_hash = md5(rand(0,999)); $security_code = substr($md5_hash, 15, 5); $_SESSION["security_code"] = $security_code; $width = 100; $height = 20; header("Content-type: image/png"); $image = ImageCreate($width, $height); $white = ImageColorAllocate($image, 255, 255, 255); $black = ImageColorAllocate($image, 0, 0, 0); $grey = ImageColorAllocate($image, 204, 204, 204); ImageFill($image, 0, 0, $black); //Add randomly generated string in white to the image ImageString($image, 3, 30, 3, $security_code, $white); //Throw in some lines to make it a little bit harder for any bots to break imageRectangle($image,0,0,$width-1,$height-1,$grey); imageline($image, 0, $height/2, $width, $height/2, $grey); imageline($image, $width/2, 0, $width/2, $height, $grey); imagepng($image); imagedestroy($image);

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  • Creating an HTML file by combining multiple PHP files via the command line?

    - by FishOrDie
    Is it possible to combine multiple PHP files via the command line and create an HTML file? For example, this will save the rendered version of a single PHP file as HTML: php /path/to/my/file/filename.php > /path/to/my/file/test.html I need it to combine multiple files, but I can't seem to get it it to work. Ideally, it would be something like this: php /path/to/my/file/filename.php + /path/to/my/file/filename2.php + /path/to/my/file/filename3.php > /path/to/my/file/test.html Is this possible? If so, how?

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  • php, image dosn't show

    - by lolalola
    Hi, whats wrong with my code. image dosn't show in test2.php file File: test2.php: <img src = "test.php" /> File: test.php session_start(); $md5_hash = md5(rand(0,999)); $security_code = substr($md5_hash, 15, 5); $_SESSION["security_code"] = $security_code; $width = 100; $height = 20; header("Content-type: image/png"); $image = ImageCreate($width, $height); $white = ImageColorAllocate($image, 255, 255, 255); $black = ImageColorAllocate($image, 0, 0, 0); $grey = ImageColorAllocate($image, 204, 204, 204); ImageFill($image, 0, 0, $black); //Add randomly generated string in white to the image ImageString($image, 3, 30, 3, $security_code, $white); //Throw in some lines to make it a little bit harder for any bots to break imageRectangle($image,0,0,$width-1,$height-1,$grey); imageline($image, 0, $height/2, $width, $height/2, $grey); imageline($image, $width/2, 0, $width/2, $height, $grey); imagepng($image); imagedestroy($image);

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  • List of Big-O for PHP functions?

    - by Kendall Hopkins
    After using PHP for a while now, I've noticed that not all PHP built in functions as fast as expected. Consider the below two possible implementations of a function that finds if a number is prime using a cached array of primes. //very slow for large $prime_array $prime_array = array( 2, 3, 5, 7, 11, 13, .... 104729, ... ); $result_array = array(); foreach( $array_of_number => $number ) { $result_array[$number] = in_array( $number, $large_prime_array ); } //still decent performance for large $prime_array $prime_array => array( 2 => NULL, 3 => NULL, 5 => NULL, 7 => NULL, 11 => NULL, 13 => NULL, .... 104729 => NULL, ... ); foreach( $array_of_number => $number ) { $result_array[$number] = array_key_exists( $number, $large_prime_array ); } This is because in_array is implemented with a linear search O(n) which will linearly slow down as $prime_array grows. Where the array_key_exists function is implemented with a hash lookup O(1) which will not slow down unless the hash table gets extremely populated (in which case it's only O(logn)). So far I've had to discover the big-O's via trial and error, and occasionally looking at the source code. Now for the question... I was wondering if there was a list of the theoretical (or practical) big O times for all* the PHP built in functions. *or at least the interesting ones For example find it very hard to predict what the big O of functions listed because the possible implementation depends on unknown core data structures of PHP: array_merge, array_merge_recursive, array_reverse, array_intersect, array_combine, str_replace (with array inputs), etc.

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  • PHP IIS problems downloading file says it is corrupt

    - by Matt
    Hi, I am running PHP on IIS 6 with mssql. I have uploaded a file to my webserver through a php script. Upon checking the file on the server the file is ok and not corrupt. However, when i then have a link on my website to try and download the file, it says the file is corrupt. I know the file isnt corrupt as i can view it perfectly if i look at the file on the server. Is seems like this is a common problem as a similar problem was posted here: http://www.bigresource.com/Tracker/Track-php-1pAakBhT/ Any help would be much appreciated. Thanks, M My download code is as follows: $filesize = $rows->filesize; $filepath = $rows->filepath; header("Content-Disposition: attachment; filename=$filename"); header("Content-length: $filesize"); header("Content-type: application/pdf"); header("Cache-control: must-revalidate"); header("Content-Description: PHP Generated Data"); readfile($filepath);

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  • Adding with PHP to a MySQL database

    - by shinjuo
    I am pretty new to PHP and I am trying to make an inventory database. I have been trying to make it so that a user can enter a card ID and then amount the want to add to the inventory and have it update the inventory. For example someone could type in test and 2342 and it would update test. Here is what I have been trying with no success: add.html <body> <form action="add.php" method="post"> Card ID: <input type="text" name="CardID" /> Amount to Add: <input type="text" name="Add" /> <input type="submit" /> </form> </body> </html> add.php <?php $link = mysql_connect('tulsadir.ipowermysql.com', 'cbouwkamp', '!starman1'); if (!$link){ die('Could not connect: ' . mysql_error()); } mysql_select_db("tdm_inventory", $link); $add = $_POST[Add] mysql_query("UPDATE cardLists SET AmountLeft = '$add' WHERE cardID = 'Test'"); echo "test successful"; mysql_close($link); ?>

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  • Any PHP MVC framework planning to use 5.3 features?

    - by alexandrul
    I would like to get started with PHP, and 5.3 release seems to bring many nice features (namespaces, lambda functions, and many others). I have found some MVC frameworks, and some of them support only PHP 5: PHP Frameworks PHP MVC Frameworks Model–view–controller on Wikipedia but can anyone recommend one of those MVC frameworks that plans to actively use PHP 5.3 features, not just being compatible with PHP 5.3? Update Results so far: Zend Framework 2.0 (in development) Lithium (in development, based on CakePHP) Symfony (in development) FLOW3 (in development, alpha)

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  • PHP GET issue - it aint workin!

    - by benhowdle89
    I have a simple PHP form which displays inputs with values from a mysql DB and send the form results to another page which updates a db table based on the GET results: echo "<form method='get' action='updateprojects.php'>"; echo "<table>"; echo "<tr>"; echo " <th>Project No</th> <th>Customer Name</th> <th>Description</th> </tr>"; while($row = mysql_fetch_array($result)) { echo "<tr>"; echo "<td><input value=" . $row['project_no'] . "></input></td>"; echo "<td><input value='" . $row['cust_name'] . "'></input></td>"; echo "<td><input value='" . $row['description'] . "'></input></td>"; echo "</tr>"; } echo "</table>"; echo "<input type='submit' value='Update' />"; echo "</form>"; on updateprojects.php i have set up the GET variable and even echoed them to check but nothing comes through! Cannot see why!? This is the start of updateprojects.php: echo $_GET['project_no'].$_GET['cust_name'].$_GET['description'];

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  • PHP - How can I check if return() was called from an include()'d file?

    - by John Himmelman
    How can I tell if return() was called from within the included file. The problem is that include() returns 'int 1', even if return() wasn't called. Here is an example... included_file_1.php <?php return 1; included_file_2.php <?php echo 'no return here, meep'; main.php <?php $ret = include('included_file_1.php'); // This file DID return a value, int 1, but include() returns this value even if return() wasn't called in the included file. if ($ret === 1) { echo 'file did not return anything'; } var_dump($ret); $ret = include('included_file_2.php'); // The included file DID NOT return a value, but include() returns 'int 1' if ($ret === 1) { echo 'file did not return anything'; } var_dump($ret);

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  • Unzip .zip file uploaded from Android via PHP to IIS 7

    - by HaOx
    I'm sending compressed file in .zip extension from Android via PHP to IIS server. Almost is working everything, but I cannot achieve unzip files with php. I've this code: <?php $target_path1 = "C:/Windows/Temp/"; $target_path1 = $target_path1 . basename( $_FILES['uploaded_file']['name']); /* I'm making the folder */ $directorio = substr($target_path1, 0, 32); if (!is_dir($directorio)) { mkdir($directorio); } /* I declare a path */ $barra = "/"; $target_path1 = $directorio . $barra . basename( $_FILES['uploaded_file']['name']); $target_path2 = $directorio . $barra; if(move_uploaded_file($_FILES['uploaded_file']['tmp_name'], $target_path1)) { /* Here I want to unzip the uploaded file */ } else{ echo "There was an error uploading the file, please try again!"; echo "filename: " . basename( $_FILES['uploaded_file']['name']); echo "target_path: " .$target_path1; } ?> So, how can I unzip uploaded file? I tried so many methods but no one worked. I'd be appreciated if someone could tell what I have to do to unzip the uploaded file. And if I have to configure some parameters in php.ini or IIS server. Thanks in advance.

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  • php script randomly hangs up

    - by sergdev
    I install php 5 (more precisely 5.3.1) as apache module. After this one of my application becomes randomly hang up on mysql_connect - sometimes works, sometimes no, sometimes reload of page helps. How can this be fixed? I use Windows Vista, Apache/2.2.14 (Win32) PHP/5.3.1 with php module, MySql 5.0.67-community-nt. After a minute I obtain the error message: Fatal error: Maximum execution time of 60 seconds exceeded in path\to\mysqlcon.php on line 9 I run MySql locally and heavy load could not be a reason: SHOW PROCESSLIST shows about 3 process SHOW VARIABLES LIKE 'MAX_CONNECTIONS' is 100. UPDATE: At first I thought that this is connected with mysql_connect. But now I can't say for certain. More difficult thing is when I insert the line to debug: $fh = fopen("E://_debugLog", 'a'); fwrite($fh, __FILE__ . " : " . __LINE__ . "\n"); fclose($fh); script start working near that location as a rule.

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