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• sql query --need some suggestions

  - by benjamin button

  I have a table with list of cycle codes.CYCLE_DEFINITION. each and every cycle_code has 12 months entries in another table(PM1_CYCLE_STATE). Each and every month has a cycle_start_date and a cycle_close_date. i will check with a particular date(lets say sysdate) and check what is the current month of every cycle.additionally i will also get the list of future 3 more months of that particular cycle. the query i have written is as below: SELECT cycd,cm,sd,ed,ld FROM (SELECT pcs.cycle_code CYCD,LTRIM(pcs.cycle_month,'0')+0 CM, pcs.cycle_start_date SD,pcs.cycle_close_date ED,ld.logical_date LD FROM pm1_cycle_state pcs,logical_date ld WHERE ld.logical_date BETWEEN pcs.cycle_start_date AND pcs.cycle_close_date and ld.logical_date_type='B') UNION SELECT cycd,cm,sd,ed,ld FROM (SELECT pcs.cycle_code CYCD,DECODE(LTRIM(pcs.cycle_month,'0')+1,13,1,14,2,15,3,LTRIM(pcs.cycle_month,'0')+1) CM ,pcs.cycle_start_date SD,pcs.cycle_close_date ED,ld.logical_date LD FROM pm1_cycle_state pcs,logical_date ld WHERE ld.logical_date BETWEEN pcs.cycle_start_date AND pcs.cycle_close_date and ld.logical_date_type='B') UNION SELECT cycd,cm,sd,ed,ld FROM (SELECT pcs.cycle_code CYCD,DECODE(LTRIM(pcs.cycle_month,'0')+2,13,1,14,2,15,3,LTRIM(pcs.cycle_month,'0')+2) CM ,pcs.cycle_start_date SD,pcs.cycle_close_date ED,ld.logical_date LD FROM pm1_cycle_state pcs,logical_date ld WHERE ld.logical_date BETWEEN pcs.cycle_start_date AND pcs.cycle_close_date and ld.logical_date_type='B') UNION SELECT cycd,cm,sd,ed,ld FROM (SELECT pcs.cycle_code CYCD,DECODE(LTRIM(pcs.cycle_month,'0')+3,13,1,14,2,15,3,LTRIM(pcs.cycle_month,'0')+3) CM ,pcs.cycle_start_date SD,pcs.cycle_close_date ED,ld.logical_date LD FROM pm1_cycle_state pcs,logical_date ld WHERE ld.logical_date BETWEEN pcs.cycle_start_date AND pcs.cycle_close_date and ld.logical_date_type='B') This query is running perfectly fine. This will result in all the cycle_codes with exactly 4 rows for current month and future 3 months. Now the requirement is if any of the month is missing.how could i show it? for eg: the output of the above query is cycd cm 102 1 102 10 102 11 102 12 103 1 103 10 103 11 103 12 104 1 104 10 104 11 104 12 Now lets say the row with cycd=104 and cm=11 is not present in the table,then the above query will not get the row 104 11. I want to display only those rows. how could i do it?

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• Excessive httpd processes to stack up on my Rails + Apache2 + Passenger production setup?

  - by LeoAlmighty

  I have a Rails + Apache2 + Postgres + Passenger application running in production mode in OSX Snow Leopard. The application serves as a data warehouse for another application in the cloud so I'm constantly getting API calls to my OSX production build. After a recent reboot, I'm finding a ton of httpd processes stacking up and eventually requiring an apache reboot. I haven't changed any settings, everything was running fine before. Any ideas on the best way to troubleshoot this? $ ps -ef|grep httpd 0 6203 1 0 0:00.20 ?? 0:00.47 /usr/sbin/httpd -D FOREGROUND 70 6222 6203 0 0:00.05 ?? 0:00.11 /usr/sbin/httpd -D FOREGROUND 70 6224 6203 0 0:00.31 ?? 0:00.50 /usr/sbin/httpd -D FOREGROUND 70 6233 6203 0 0:00.05 ?? 0:00.10 /usr/sbin/httpd -D FOREGROUND 70 6234 6203 0 0:00.43 ?? 0:00.64 /usr/sbin/httpd -D FOREGROUND 70 6243 6203 0 0:00.02 ?? 0:00.03 /usr/sbin/httpd -D FOREGROUND 70 6319 6203 0 0:00.08 ?? 0:00.16 /usr/sbin/httpd -D FOREGROUND 70 6334 6203 0 0:00.02 ?? 0:00.05 /usr/sbin/httpd -D FOREGROUND 70 6469 6203 0 0:00.04 ?? 0:00.08 /usr/sbin/httpd -D FOREGROUND 70 6487 6203 0 0:00.36 ?? 0:00.48 /usr/sbin/httpd -D FOREGROUND 70 6593 6203 0 0:00.36 ?? 0:00.48 /usr/sbin/httpd -D FOREGROUND 70 6709 6203 0 0:00.04 ?? 0:00.08 /usr/sbin/httpd -D FOREGROUND 70 6718 6203 0 0:00.04 ?? 0:00.10 /usr/sbin/httpd -D FOREGROUND 70 6834 6203 0 0:00.01 ?? 0:00.03 /usr/sbin/httpd -D FOREGROUND 70 6852 6203 0 0:00.00 ?? 0:00.00 /usr/sbin/httpd -D FOREGROUND 70 6853 6203 0 0:00.01 ?? 0:00.02 /usr/sbin/httpd -D FOREGROUND

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• Why does iOS 5 fail to connect to a server running JDK 1.6, but not JDK 1.5

  - by KC Baltz

  We have a Java Socket Server listening on an SSLSocket (port 443) and an iOS application that connects with it. When running on iOS 5.1, the application stopped working when we upgraded the Java version of the server from JDK 1.5 to 1.6 (or 1.7). The app connects just fine to JDK 5 and 6 when running on iOS 6. The iOS app is reporting an error: -9809 = errSSLCrypto. On the Java side, we get javax.net.ssl.SSLException: Received fatal alert: close_notify. On the Java server side, we have enabled all the available cipher suites. On the client side we have tested enabling several different suites, although we have yet to complete a test involving each one individually enabled. Right now, it is failing when we use TLS_DH_anon_WITH_AES_128_CBC_SHA although it has failed with others and we are starting to think it's not the suite. Here is the debug output. It makes it all the way to ServerHelloDone and then fails shortly thereafter: Is secure renegotiation: false [Raw read]: length = 5 0000: 16 03 03 00 41 ....A [Raw read]: length = 65 0000: 01 00 00 3D 03 03 50 83 1E 0B 56 19 25 65 C8 F2 ...=..P...V.%e.. 0010: AF 02 AD 48 FE E2 92 CF B8 D7 A6 A3 EA C5 FF 5D ...H...........] 0020: 74 0F 1B C1 99 18 00 00 08 00 FF 00 34 00 1B 00 t...........4... 0030: 18 01 00 00 0C 00 0D 00 08 00 06 05 01 04 01 02 ................ 0040: 01 . URT-, READ: Unknown-3.3 Handshake, length = 65 *** ClientHello, Unknown-3.3 RandomCookie: GMT: 1333992971 bytes = { 86, 25, 37, 101, 200, 242, 175, 2, 173, 72, 254, 226, 146, 207, 184, 215, 166, 163, 234, 197, 255, 93, 116, 15, 27, 193, 153, 24 } Session ID: {} Cipher Suites: [TLS_EMPTY_RENEGOTIATION_INFO_SCSV, TLS_DH_anon_WITH_AES_128_CBC_SHA, SSL_DH_anon_WITH_3DES_EDE_CBC_SHA, SSL_DH_anon_WITH_RC4_128_MD5] Compression Methods: { 0 } Unsupported extension signature_algorithms, data: 00:06:05:01:04:01:02:01 *** [read] MD5 and SHA1 hashes: len = 65 0000: 01 00 00 3D 03 03 50 83 1E 0B 56 19 25 65 C8 F2 ...=..P...V.%e.. 0010: AF 02 AD 48 FE E2 92 CF B8 D7 A6 A3 EA C5 FF 5D ...H...........] 0020: 74 0F 1B C1 99 18 00 00 08 00 FF 00 34 00 1B 00 t...........4... 0030: 18 01 00 00 0C 00 0D 00 08 00 06 05 01 04 01 02 ................ 0040: 01 . %% Created: [Session-1, TLS_DH_anon_WITH_AES_128_CBC_SHA] *** ServerHello, TLSv1 RandomCookie: GMT: 1333992972 bytes = { 100, 3, 56, 153, 7, 2, 251, 64, 41, 32, 66, 240, 227, 181, 55, 190, 2, 237, 146, 0, 73, 119, 70, 0, 160, 9, 28, 207 } Session ID: {80, 131, 30, 12, 241, 73, 52, 38, 46, 41, 237, 226, 199, 246, 156, 45, 3, 247, 182, 43, 223, 8, 49, 169, 188, 63, 160, 41, 102, 199, 50, 190} Cipher Suite: TLS_DH_anon_WITH_AES_128_CBC_SHA Compression Method: 0 Extension renegotiation_info, renegotiated_connection: <empty> *** Cipher suite: TLS_DH_anon_WITH_AES_128_CBC_SHA *** Diffie-Hellman ServerKeyExchange DH Modulus: { 233, 230, 66, 89, 157, 53, 95, 55, 201, 127, 253, 53, 103, 18, 11, 142, 37, 201, 205, 67, 233, 39, 179, 169, 103, 15, 190, 197, 216, 144, 20, 25, 34, 210, 195, 179, 173, 36, 128, 9, 55, 153, 134, 157, 30, 132, 106, 171, 73, 250, 176, 173, 38, 210, 206, 106, 34, 33, 157, 71, 11, 206, 125, 119, 125, 74, 33, 251, 233, 194, 112, 181, 127, 96, 112, 2, 243, 206, 248, 57, 54, 148, 207, 69, 238, 54, 136, 193, 26, 140, 86, 171, 18, 122, 61, 175 } DH Base: { 48, 71, 10, 213, 160, 5, 251, 20, 206, 45, 157, 205, 135, 227, 139, 199, 209, 177, 197, 250, 203, 174, 203, 233, 95, 25, 10, 167, 163, 29, 35, 196, 219, 188, 190, 6, 23, 69, 68, 64, 26, 91, 44, 2, 9, 101, 216, 194, 189, 33, 113, 211, 102, 132, 69, 119, 31, 116, 186, 8, 77, 32, 41, 216, 60, 28, 21, 133, 71, 243, 169, 241, 162, 113, 91, 226, 61, 81, 174, 77, 62, 90, 31, 106, 112, 100, 243, 22, 147, 58, 52, 109, 63, 82, 146, 82 } Server DH Public Key: { 8, 60, 59, 13, 224, 110, 32, 168, 116, 139, 246, 146, 15, 12, 216, 107, 82, 182, 140, 80, 193, 237, 159, 189, 87, 34, 18, 197, 181, 252, 26, 27, 94, 160, 188, 162, 30, 29, 165, 165, 68, 152, 11, 204, 251, 187, 14, 233, 239, 103, 134, 168, 181, 173, 206, 151, 197, 128, 65, 239, 233, 191, 29, 196, 93, 80, 217, 55, 81, 240, 101, 31, 119, 98, 188, 211, 52, 146, 168, 127, 127, 66, 63, 111, 198, 134, 70, 213, 31, 162, 146, 25, 178, 79, 56, 116 } Anonymous *** ServerHelloDone [write] MD5 and SHA1 hashes: len = 383 0000: 02 00 00 4D 03 01 50 83 1E 0C 64 03 38 99 07 02 ...M..P...d.8... 0010: FB 40 29 20 42 F0 E3 B5 37 BE 02 ED 92 00 49 77 .@) B...7.....Iw 0020: 46 00 A0 09 1C CF 20 50 83 1E 0C F1 49 34 26 2E F..... P....I4&. 0030: 29 ED E2 C7 F6 9C 2D 03 F7 B6 2B DF 08 31 A9 BC ).....-...+..1.. 0040: 3F A0 29 66 C7 32 BE 00 34 00 00 05 FF 01 00 01 ?.)f.2..4....... 0050: 00 0C 00 01 26 00 60 E9 E6 42 59 9D 35 5F 37 C9 ....&.`..BY.5_7. 0060: 7F FD 35 67 12 0B 8E 25 C9 CD 43 E9 27 B3 A9 67 ..5g...%..C.'..g 0070: 0F BE C5 D8 90 14 19 22 D2 C3 B3 AD 24 80 09 37 ......."....$..7 0080: 99 86 9D 1E 84 6A AB 49 FA B0 AD 26 D2 CE 6A 22 .....j.I...&..j" 0090: 21 9D 47 0B CE 7D 77 7D 4A 21 FB E9 C2 70 B5 7F !.G...w.J!...p.. 00A0: 60 70 02 F3 CE F8 39 36 94 CF 45 EE 36 88 C1 1A `p....96..E.6... 00B0: 8C 56 AB 12 7A 3D AF 00 60 30 47 0A D5 A0 05 FB .V..z=..`0G..... 00C0: 14 CE 2D 9D CD 87 E3 8B C7 D1 B1 C5 FA CB AE CB ..-............. 00D0: E9 5F 19 0A A7 A3 1D 23 C4 DB BC BE 06 17 45 44 ._.....#......ED 00E0: 40 1A 5B 2C 02 09 65 D8 C2 BD 21 71 D3 66 84 45 @.[,..e...!q.f.E 00F0: 77 1F 74 BA 08 4D 20 29 D8 3C 1C 15 85 47 F3 A9 w.t..M ).<...G.. 0100: F1 A2 71 5B E2 3D 51 AE 4D 3E 5A 1F 6A 70 64 F3 ..q[.=Q.M>Z.jpd. 0110: 16 93 3A 34 6D 3F 52 92 52 00 60 08 3C 3B 0D E0 ..:4m?R.R.`.<;.. 0120: 6E 20 A8 74 8B F6 92 0F 0C D8 6B 52 B6 8C 50 C1 n .t......kR..P. 0130: ED 9F BD 57 22 12 C5 B5 FC 1A 1B 5E A0 BC A2 1E ...W"......^.... 0140: 1D A5 A5 44 98 0B CC FB BB 0E E9 EF 67 86 A8 B5 ...D........g... 0150: AD CE 97 C5 80 41 EF E9 BF 1D C4 5D 50 D9 37 51 .....A.....]P.7Q 0160: F0 65 1F 77 62 BC D3 34 92 A8 7F 7F 42 3F 6F C6 .e.wb..4....B?o. 0170: 86 46 D5 1F A2 92 19 B2 4F 38 74 0E 00 00 00 .F......O8t.... URT-, WRITE: TLSv1 Handshake, length = 383 [Raw write]: length = 388 0000: 16 03 01 01 7F 02 00 00 4D 03 01 50 83 1E 0C 64 ........M..P...d 0010: 03 38 99 07 02 FB 40 29 20 42 F0 E3 B5 37 BE 02 .8....@) B...7.. 0020: ED 92 00 49 77 46 00 A0 09 1C CF 20 50 83 1E 0C ...IwF..... P... 0030: F1 49 34 26 2E 29 ED E2 C7 F6 9C 2D 03 F7 B6 2B .I4&.).....-...+ 0040: DF 08 31 A9 BC 3F A0 29 66 C7 32 BE 00 34 00 00 ..1..?.)f.2..4.. 0050: 05 FF 01 00 01 00 0C 00 01 26 00 60 E9 E6 42 59 .........&.`..BY 0060: 9D 35 5F 37 C9 7F FD 35 67 12 0B 8E 25 C9 CD 43 .5_7...5g...%..C 0070: E9 27 B3 A9 67 0F BE C5 D8 90 14 19 22 D2 C3 B3 .'..g......."... 0080: AD 24 80 09 37 99 86 9D 1E 84 6A AB 49 FA B0 AD .$..7.....j.I... 0090: 26 D2 CE 6A 22 21 9D 47 0B CE 7D 77 7D 4A 21 FB &..j"!.G...w.J!. 00A0: E9 C2 70 B5 7F 60 70 02 F3 CE F8 39 36 94 CF 45 ..p..`p....96..E 00B0: EE 36 88 C1 1A 8C 56 AB 12 7A 3D AF 00 60 30 47 .6....V..z=..`0G 00C0: 0A D5 A0 05 FB 14 CE 2D 9D CD 87 E3 8B C7 D1 B1 .......-........ 00D0: C5 FA CB AE CB E9 5F 19 0A A7 A3 1D 23 C4 DB BC ......_.....#... 00E0: BE 06 17 45 44 40 1A 5B 2C 02 09 65 D8 C2 BD 21 ...ED@.[,..e...! 00F0: 71 D3 66 84 45 77 1F 74 BA 08 4D 20 29 D8 3C 1C q.f.Ew.t..M ).<. 0100: 15 85 47 F3 A9 F1 A2 71 5B E2 3D 51 AE 4D 3E 5A ..G....q[.=Q.M>Z 0110: 1F 6A 70 64 F3 16 93 3A 34 6D 3F 52 92 52 00 60 .jpd...:4m?R.R.` 0120: 08 3C 3B 0D E0 6E 20 A8 74 8B F6 92 0F 0C D8 6B .<;..n .t......k 0130: 52 B6 8C 50 C1 ED 9F BD 57 22 12 C5 B5 FC 1A 1B R..P....W"...... 0140: 5E A0 BC A2 1E 1D A5 A5 44 98 0B CC FB BB 0E E9 ^.......D....... 0150: EF 67 86 A8 B5 AD CE 97 C5 80 41 EF E9 BF 1D C4 .g........A..... 0160: 5D 50 D9 37 51 F0 65 1F 77 62 BC D3 34 92 A8 7F ]P.7Q.e.wb..4... 0170: 7F 42 3F 6F C6 86 46 D5 1F A2 92 19 B2 4F 38 74 .B?o..F......O8t 0180: 0E 00 00 00 .... [Raw read]: length = 5 0000: 15 03 01 00 02 ..... [Raw read]: length = 2 0000: 02 00 .. URT-, READ: TLSv1 Alert, length = 2 URT-, RECV TLSv1 ALERT: fatal, close_notify URT-, called closeSocket() URT-, handling exception: javax.net.ssl.SSLException: Received fatal alert: close_notify FYI, this works in iOS 6.0

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• Android AES and init vector

  - by Donald_W

  I have an issue with AES encryptio and decryption: I can change my IV entirely and still I'm able to decode my data. public static final byte[] IV = { 65, 1, 2, 23, 4, 5, 6, 7, 32, 21, 10, 11, 12, 13, 84, 45 }; public static final byte[] IV2 = { 65, 1, 2, 23, 45, 54, 61, 81, 32, 21, 10, 121, 12, 13, 84, 45 }; public static final byte[] KEY = { 0, 42, 2, 54, 4, 45, 6, 7, 65, 9, 54, 11, 12, 13, 60, 15 }; public static final byte[] KEY2 = { 0, 42, 2, 54, 43, 45, 16, 17, 65, 9, 54, 11, 12, 13, 60, 15 }; //public static final int BITS = 256; public static void test() { try { // encryption Cipher c = Cipher.getInstance("AES"); SecretKeySpec keySpec = new SecretKeySpec(KEY, "AES"); c.init(Cipher.ENCRYPT_MODE, keySpec, new IvParameterSpec(IV)); String s = "Secret message"; byte[] data = s.getBytes(); byte[] encrypted = c.doFinal(data); String encryptedStr = ""; for (int i = 0; i < encrypted.length; i++) encryptedStr += (char) encrypted[i]; //decryoption Cipher d_c = Cipher.getInstance("AES"); SecretKeySpec d_keySpec = new SecretKeySpec(KEY, "AES"); d_c.init(Cipher.DECRYPT_MODE, d_keySpec, new IvParameterSpec(IV2)); byte[] decrypted = d_c.doFinal(encrypted); String decryptedStr = ""; for (int i = 0; i < decrypted.length; i++) decryptedStr += (char) decrypted[i]; Log.d("", decryptedStr); } catch (Exception ex) { Log.d("", ex.getMessage()); } } Any ideas what I'm doing wrong? How can I get 256 bit AES encryption (only change key to 32-byte long array?) Encryption is a new topic for me so please for newbie friendly answers.

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• Creating one row of information in excel using a unique value

  - by user1426513

  This is my first post. I am currently working on a project at work which requires that I work with several different worksheets in order to create one mail master worksheet, as it were, in order to do a mail merge. The worksheet contains information regarding different purchases, and each purchaser is identified with their own ID number. Below is an example of what my spreadsheet looks like now (however I do have more columns): ID Salutation Address ID Name Donation ID Name Tickets 9 Mr. John Doe 123 12 Ms. Jane Smith 100.00 12 Ms.Jane Smith 300.00 12 Ms. Jane Smith 456 22 Mr. Mike Man 500.00 84 Ms. Jo Smith 300.00 What I would like to do is somehow sort my data so that everythign with the same unique identifier (ID) lines up on the same row. For example ID 12 Jane Smith - all the information for her will show up under her name matched by her ID number, and ID 22 will match up with 22 etc... When I merged all of my spreadsheets together, I sorted them all by ID number, however my problem is, not everyone who made a donation bought a ticket or some people just bought tickets and nothing us, so sorting doesn't work. Hopefully this makes sense. Thanks in advance.

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• myXmlDataDoc.DataSet.ReadXml problem

  - by alex

  Hi: I am using myXmlDataDoc.DataSet.ReadXml(xml_file_name, XmlReadMode.InferSchema); to populate the tables within the dataset created by reading in a xml schema using: myStreamReader = new StreamReader(xsd_file_name); myXmlDataDoc.DataSet.ReadXmlSchema(myStreamReader); The problems I am facing is when it comes to read the xml tag: The readXml function puts the element in a different table and everything in the tables are 0s. Here is the print out of the datatable: TableName: test_data 100 2 1 TableName: parameters 1 0 2 0 3 0 4 0 5 0 6 0 7 0 8 0 9 0 10 0 11 0 12 0 In my xsd file, I represent an array using this: <xs:element name="test_data"> <xs:complexType> <xs:complexContent> <xs:extension base="test_base"> <xs:sequence> <xs:element name="a" type="xs:unsignedShort"/> <xs:element name="b" type="xs:unsignedShort"/> <xs:element name="c" type="xs:unsignedInt"/> <xs:element name="parameters" minOccurs="0" maxOccurs="12" type="xs:unsignedInt"/> </xs:sequence> </xs:extension> </xs:complexContent> </xs:complexType> And here is my xml file: 100 2 1 1 2 3 4 5 6 7 8 9 10 11 12 I am expecting after the readXml function call, the "parameters" is part of the test_data table. TableName: test_data 100 2 1 1 2 3 4 5 6 7 8 9 10 11 12 Does anyone knows what's wrong? Thanks

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• Jquery grid overlay in wordpress

  - by Anders Kitson

  I am adding this simple plugin that I have working in a static html site, and am trying to add it to a wordpress development site based off of 960 gs. The jquery code links are correct but the console gives me this error "Uncaught TypeError: Cannot call method 'addGrid' of null" I got the code from this turtorial http://www.badlydrawntoy.com/2009/04/21/960gs-grid-overlay-a-jquery-plugin/ Here is the code I am using /*<![CDATA[*/ // onload $(function() { $("body").addGrid(12, {img_path: 'img/'}); }); /*]]>*/ Here is the code for the plugin /* * @ description: Plugin to display 960.gs gridlines See http://960.gs/ * @author: badlyDrawnToy sharp / http://www.badlydrawntoy.com * @license: Creative Commons License - ShareAlike http://creativecommons.org/licenses/by-sa/3.0/ * @version: 1.0 20th April 2009 */ (function($){$.fn.addGrid=function(cols,options){var defaults={default_cols:12,z_index:999,img_path:'/images/',opacity:.6};var opts=$.extend(defaults,options);var cols=cols!=null&&(cols===12||cols===16)?cols:12;var cols=cols===opts.default_cols?'12_col':'16_col';return this.each(function(){var $el=$(this);var height=$el.height();var wrapper=$('<div id="'+opts.grid_id+'"/>').appendTo($el).css({'display':'none','position':'absolute','top':0,'z-index':(opts.z_index-1),'height':height,'opacity':opts.opacity,'width':'100%'});$('<div/>').addClass('container_12').css({'margin':'0 auto','width':'960px','height':height,'background-image':'url('+opts.img_path+cols+'.png)','background-repeat':'repeat-y'}).appendTo(wrapper);$('<div>grid on</div>').appendTo($el).css({'position':'absolute','top':0,'left':0,'z-index':opts.z_index,'background':'#222','color':'#fff','padding':'3px 6px','width':'40px','text-align':'center'}).hover(function(){$(this).css("cursor","pointer");},function(){$(this).css("cursor","default");}).toggle(function(){$(this).text("grid off");$('#'+opts.grid_id).slideDown();},function(){$(this).text("grid on");$('#'+opts.grid_id).slideUp();});});};})(jQuery);

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• Algorithm Question

  - by Ravi

  Hi, I am trying to find a O (n) algorithm for this problem but unable to do so even after spending 3 - 4 hours. The brute force method times out (O (n^2)). I am confused as to how to do it ? Does the solution requires dynamic programming solution ? http://acm.timus.ru/problem.aspx?space=1&num=1794 In short the problem is this: There are some students sitting in circle and each one of them has its own choice as to when he wants to be asked a question from a teacher. The teacher will ask the questions in clockwise order only. For example: 5 3 3 1 5 5 This means that there are 5 students and : 1st student wants to go third 2nd student wants to go third 3rd student wants to go first 4th student wants to go fifth 5th student wants to go fifth. The question is as to where should teacher start asking questions so that maximum number of students will get the turn as they want. For this particular example, the answer is 5 because 3 3 1 5 5 2 3 4 5 1 You can see that by starting at fifth student as 1st, 2 students (3 and 5) are getting the choices as they wanted. For this example the answer is 12th student : 12 5 1 2 3 6 3 8 4 10 3 12 7 because 5 1 2 3 6 3 8 4 10 3 12 7 2 3 4 5 6 7 8 9 10 11 12 1 four students get their choices fulfilled. Thanks Ravi

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• Arduino variable going blank after the first pass

  - by user541597

  I have an Arduino sketch that takes a timet and when that timet is equal to the current time it sets the new timet to timet + 2. For example: char* convert(char* x, String y) { int hour; int minute; sscanf(x, "%d:%d", &hour, &minute); char buf[6]; if (y == "6") { if (hour > 17) { hour = (hour+6)%24; snprintf(buf, 10, "%d:%d", hour, minute ); } else if (hour < 18) { //hour = hour + 6; minute = (minute + 2); snprintf(buf, 10, "%d:%d", hour, minute); } } if (y == "12") { if (hour > 11) { hour = (hour+12)%24; snprintf(buf, 10, "%d:%d", hour, minute ); } else if (hour < 12) { hour = hour + 12; snprintf(buf, 10, "%d:%d", hour, minute); } } if (y == "24") { hour = (hour+24)%24; snprintf(buf, 10, "%d:%d", hour, minute ); } return buf; } The sketch starts for example at 1:00am. timet is set to 1:02, at system time 1:02 timet is equal to the system time. My loops looks like this: if (timet == currenttime) { timet = convert(timet) } Whenever I check the value of timet it should equal 1:04, however I get the correct value at the first run after the execution of convert, however every time after that my timet value is blank. I tried changing the code instead of using the if loop. I only run the convert function when I send for example t through the serial monitor. This works fine and outputs the correct timet after the execution of the convert function, So I figured the problem is in the if loop... Any ideas?

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• How do I count how many arrays have the same name within a multidimensional array with php?

  - by zeckdude

  I have a multidimensional array, and I would have multiple arrays within it. Some of those arrays contain multiple arrays within them as well, and I would like to count how many arrays are within the second array(the date). This is an example of the structure of the multidimensional array: $_SESSION['final_shipping'][04/03/2010][book] $_SESSION['final_shipping'][04/12/2010][magazine] $_SESSION['final_shipping'][04/12/2010][cd] This is the foreach statement I am currently using to count how many of the second array(the one with the dates) exists. foreach($_SESSION['final_shipping'] as $date_key => $date_value) { foreach ($date_value as $product_key => $product_value) { echo 'There are ' . count($date_key) . ' of the ' . $date_key . ' selection.<br/>'; } } It is currently outputting this: There are 1 of the 04/03/2010 selection. There are 1 of the 04/12/2010 selection. There are 1 of the 04/12/2010 selection. I would like it to output this: There are 1 of the 04/03/2010 selection. There are 2 of the 04/12/2010 selection.

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• Factorial function - design and test.

  - by lukas

  I'm trying to nail down some interview questions, so I stared with a simple one. Design the factorial function. This function is a leaf (no dependencies - easly testable), so I made it static inside the helper class. public static class MathHelper { public static int Factorial(int n) { Debug.Assert(n >= 0); if (n < 0) { throw new ArgumentException("n cannot be lower that 0"); } Debug.Assert(n <= 12); if (n > 12) { throw new OverflowException("Overflow occurs above 12 factorial"); } //by definition if (n == 0) { return 1; } int factorialOfN = 1; for (int i = 1; i <= n; ++i) { //checked //{ factorialOfN *= i; //} } return factorialOfN; } } Testing: [TestMethod] [ExpectedException(typeof(OverflowException))] public void Overflow() { int temp = FactorialHelper.MathHelper.Factorial(40); } [TestMethod] public void ZeroTest() { int factorialOfZero = FactorialHelper.MathHelper.Factorial(0); Assert.AreEqual(1, factorialOfZero); } [TestMethod] public void FactorialOf5() { int factOf5 = FactorialHelper.MathHelper.Factorial(5); Assert.AreEqual(120,factOf5); } [TestMethod] [ExpectedException(typeof(ArgumentException))] public void NegativeTest() { int factOfMinus5 = FactorialHelper.MathHelper.Factorial(-5); } I have a few questions: Is it correct? (I hope so ;) ) Does it throw right exceptions? Should I use checked context or this trick ( n 12 ) is ok? Is it better to use uint istead of checking for negative values? Future improving: Overload for long, decimal, BigInteger or maybe generic method? Thank you

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• MySQL: SELECT highest column value when WHERE finds similar entries

  - by Ike

  My question is comparable to this one, but not quite the same. I have a database with a huge amount of books, with different editions of some of the same book titles. I'm looking for an SQL statement giving me the highest edition number of each of the titles I'm selecting with a WHERE clause (to find specific book series). Here's what the table looks like: |id|title |edition|year| |--|-------------------------|-------|----| |01|Serie One Title One |1 |2007| |02|Serie One Title One |2 |2008| |03|Serie One Title One |3 |2009| |04|Serie One Title Two |1 |2001| |05|Serie One Title Three |1 |2008| |06|Serie One Title Three |2 |2009| |07|Serie One Title Three |3 |2010| |08|Serie One Title Three |4 |2011| |--|-------------------------|-------|----| The result I'm looking for is this: |id|title |edition|year| |--|-------------------------|-------|----| |03|Serie One Title One |3 |2009| |04|Serie One Title Two |1 |2001| |08|Serie One Title Three |4 |2011| |--|-------------------------|-------|----| The closest I got was using this statement: select id, title, max(edition), max(year) from books where title like "serie one%" group by name; but it returns the highest edition and year and includes the first id it finds: |--|-----------------------|-------|----| |01|Serie One Title One |3 |2009| |04|Serie One Title Two |1 |2001| |05|Serie One Title Three |4 |2011| |--|-----------------------|-------|----| This fancy join also comes close, but doesn't give the right result: select b.id, b.title, b.edition, b.year from books b inner join (select name, max(edition) as maxedition from books group by title) g on b.edition = g.maxedition where b.title like "serie one%" group by title; Using this I'm getting unique titles, but mostly old editions.

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• novice needing help on shuffeling an array

  - by steffen Myklebust

  Please help a TOTAL beginner.! I found this post: http://stackoverflow.com/questions/56648/whats-the-best-way-to-shuffle-an-nsmutablearray And as i try to deploy this in my own code, I cant get it working... :-( Can anyone help me to resolve this code? To me it looks like the shuffle function is not called..? here is my code: // // shuffle2ViewController.h // shuffle2 #import @interface shuffle2ViewController : UIViewController { NSMutableArray *puzzles; int *randomSort; } - (void)shuffle; @end //============================= // shuffle2ViewController.m ´#import "shuffle2ViewController.h" @implementation shuffle2ViewController (void)viewDidLoad { [super viewDidLoad]; NSMutableArray *puzzles = [NSMutableArray arrayWithObjects:@"1",@"2",@"3", @"4",@"5",@"6",@"7",@"8",@"9", @"10",@"11",@"12", nil]; // Call the shuffle function [self shuffle]; // print to log int i; NSLog(@"NEW OLD"); NSLog(@"================="); for (i = 0; i < 12; ++i) NSLog(@" %2i %@", i + 1, [puzzles objectAtIndex:i]); } int randomSort(id obj1, id obj2, void *context ) { // returns random number -1 0 1 return (random()%3 - 1); } (void)shuffle { // call custom sort function [puzzles sortUsingFunction:randomSort context:nil]; } Giving this result: NEW OLD ================= 1 1 2 2 3 3 4 4 5 5 6 6 7 7 8 8 9 9 10 10 11 11 12 12

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• Arduino variable going blank after first pass.

  - by user541597

  I have an arduino sketch that takes a timet and when that timet is equal to the current time it sets the new timet to timet + 2. For example: char* convert(char* x, String y){ int hour; int minute; sscanf(x, "%d:%d", &hour, &minute); char buf[6]; if (y == "6"){ if (hour > 17){ hour = (hour+6)%24; snprintf(buf, 10, "%d:%d", hour, minute ); }else if (hour < 18){ //hour = hour + 6; minute = (minute + 2); snprintf(buf, 10, "%d:%d", hour, minute); } } if (y == "12"){ if (hour > 11){ hour = (hour+12)%24; snprintf(buf, 10, "%d:%d", hour, minute ); } else if (hour < 12){ hour = hour + 12; snprintf(buf, 10, "%d:%d", hour, minute); } } if (y == "24"){ hour = (hour+24)%24; snprintf(buf, 10, "%d:%d", hour, minute ); } return buf; } sketch starts for example at 1:00am timet is set to 1:02, at system time 1:02 timet == system time my loops looks like this: if (timet == currenttime){ timet = convert(timet) } From this now when ever I check the value of timet it should equal 1:04, however I am getting the correct value at the first run after the execution of convert however everytime after that my timet value is blank. I tried changing the code instead of using the if loop I only run the convert function when I send for example t through the serial monitor, this works fine and outputs the correct timet after the execution of the convert function, So I figured the problem is in the if loop... Any ideas?

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• PHP / Zend custom date input formats

  - by mld

  Hi, I'm creating a library component for other developers on my team using PHP and Zend. This component needs to be able to take as input a date (string) and another string telling it the format of that date. Looking through the Zend documentation and examples, I thought I found the solution - $dateObject = Zend_Date('13.04.2006', array('date_format' => 'dd.MM.yyyy')); this line, however, throws an error - call to undefined function. So instead I tried this - $dt = Zend_Locale_Format::getDate('13.04.2006', array('date_format' => 'dd.MM.yyyy')); This gets the job done, but throws an error if a date that is entered isn't valid. The docs make it look like you can use the isDate() function to check validity - Zend_Date::isDate('13.04.2006', array('date_format' => 'dd.MM.yyyy')) but this line always returns false. So my questions - Am I going about this the right way? If not, is there a better way to handle this via Zend or straight PHP? If I do use Zend_Locale_Format::getDate(), do I need to worry about a locale being set elsewhere and changing the results of the call? I'm locked into PHP 5.2.6 on windows, btw... so 5.3+ functions & strptime() are out.

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• Firefox not honoring must-revalidate cache headers returned by jQuery.ajax() request

  - by Oliver Weichhold

  UPDATE 1: Judging by this thread I am not the only one having this problem in FF 12 and only in 12. UPDATE 2: The problem does not seem to be limited to Ajax requests. From the looks of it everything that makes it into Firefox 12's cache will be fetched from there. No matter what. The server can specify cache control headers all day long. Bummer! What I'm trying to achieve is the following behavior: Browser may cache the response without revalidating for up to 5 minutes I don't care if the browser revalidates on every request (Both Chrome and IE9 do for example) When the expiration is up the browser MUST revalidate (which in my case will result in fresh data) Chrome and IE9 exhibit the desired behavior when issuing a jquery.ajax() request with ifModified: true and cache: true while Firefox 12 never revalidates, which poses a serious problem. These are the actual response headers: HTTP/1.1 200 OK Server: nginx Date: Sun, 03 Jun 2012 07:13:43 GMT Content-Type: text/javascript; charset=UTF-8 Transfer-Encoding: chunked Connection: keep-alive Vary: Accept-Encoding Cache-Control: private, must-revalidate, max-age=300 Last-Modified: Sun, 03 Jun 2012 07:07:13 GMT Content-Encoding: gzip Any suggestions?

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• How to sort a Pandas DataFrame according to multiple criteria?

  - by user1715271

  I have the following DataFrame containing song names, their peak chart positions and the number of weeks they spent at position no 1: Song Peak Weeks 76 Paperback Writer 1 16 117 Lady Madonna 1 9 118 Hey Jude 1 27 22 Can't Buy Me Love 1 17 29 A Hard Day's Night 1 14 48 Ticket To Ride 1 14 56 Help! 1 17 109 All You Need Is Love 1 16 173 The Ballad Of John And Yoko 1 13 85 Eleanor Rigby 1 14 87 Yellow Submarine 1 14 20 I Want To Hold Your Hand 1 24 45 I Feel Fine 1 15 60 Day Tripper 1 12 61 We Can Work It Out 1 12 10 She Loves You 1 36 155 Get Back 1 6 8 From Me To You 1 7 115 Hello Goodbye 1 7 2 Please Please Me 2 20 92 Strawberry Fields Forever 2 12 93 Penny Lane 2 13 107 Magical Mystery Tour 2 16 176 Let It Be 2 14 0 Love Me Do 4 26 157 Something 4 9 166 Come Together 4 10 58 Yesterday 8 21 135 Back In The U.S.S.R. 19 3 164 Here Comes The Sun 58 19 96 Sgt. Pepper's Lonely Hearts Club Band 63 12 105 With A Little Help From My Friends 63 7 I'd like to rank these songs in order of popularity, so I'd like to sort them according to the following criteria: songs that reached the highest position come first, but if there is a tie, the songs that remained in the charts for the longest come first. I can't seem to figure out how to do this in Pandas.

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• Tweaking rendering of thumbnail images in galleria

  - by saket

  I am working on the classic theme of Galleria to display a gallery. Here the requirement is to display the thumbnails in two row with the images in following order with a horizontal scroller if the thumbnails list div width increases more than 24. 1 3 5 7 9 11 13 15 17 19 21 23 .. 2 4 6 8 10 12 14 16 18 20 22 24 .. For if the images are less than 24 and more than 12 then the order should be rendered in two rows as :- 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 .. For if the images is less than 12 the images should be rendered in a single row as :- 1 2 3 4 5 6 7... Presently what I have done is I am using css3 column property to do this using different classes on the basis of image counts. This is working in all browsers but in IE8. So, is there any substitute for css3 column property for IE8 or less. Or some better way to implement the stuff that works fine in IE as well.

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• Creating a timesheet for work using PHP MySQL

  - by Justin

  I am trying to create a time-sheet for my work. I don't know if getting myself into a lot of work by doing this as I am quiet new to PHP and MYSQL but I do have a good understanding/knowledge of the two. I want the below fields in my database. Job weekPeriod ------A list of weeks Monday Sunday dateWorked ------List Of dates in the form coming from a database e.g. 1/1/2011 startTime ------List of times from 12:00am11:00pm 30 min intervals e.g. 11:30-12:30 endTime ------List of times from 12:00am11:00pm 30 min intervals e.g. 11:30-12:30 totalHours ------Automated amount ------Automated based on dayWorked comments ------Any messages here I want to be able to fill in some drop down boxes through a form that will then submit all information to my database. I want the script to know that if the date worked is on a Weekday Mon-Fri e.g. my rate of pay is 30.00ph On a sat it is 35.00ph and on a Sunday it is 40ph I then want to create a page where i select a particular week and see how many hours i worked and how much i earn and so on. Please let me know if there is such a program already established or if this is something that requires a bit of time and if I could do it being new to PHP and MYSQL

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• txt file read/overwrite/append. Is this feasible? (Visual C#)

  - by Arcadian

  Hi, I'm writing a program for some data entry I have to periodically do. I have begun testing a few things that the program will have to do but i'm not sure about this part. What i need this part to do is: read a .txt file of data take the first 12 characters from each line take the first 12 characters from each line of the data that has been entered in a multi-line text box compare the two lists line by line if one of the 12 character blocks from the multi-line text box match one of the blocks in the .txt file then overwrite that entire line (only 17 characters in total) if one of the 12 character blocks from the multi-line text box DO NOT match any of the blocks in the.txt file then append that entire line to the file thats all it has to do. i'll do an example: TXT FILE: G01:78:08:32 JG05 G08:80:93:10 JG02 G28:58:29:28 JG04 MULTI-LINE TEXT BOX: G01:78:08:32 JG06 G28:58:29:28 JG03 G32:10:18:14 JG01 G32:18:50:78 JG07 RESULTING TXT FILE: G01:78:08:32 JG06 G08:80:93:10 JG02 G28:58:29:28 JG03 G32:10:18:14 JG01 G32:18:50:78 JG07 as you can see lines 1 and 3 were overwriten, line 2 was left alone as it did not match any blocks in the text box, lines 4 and 5 were appended to the file. thats all i want it to do. How do i go about this? Thanks in advance

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• how to count multiples of numbers in an input file?

  - by user292489

  i was trying to count the number of multiples of 2, 3, and 6 respectielly from the users input file. but for some reason, my counter is not working. can any bosy hep me please. my code: #include <stdio.h> int main (void) { int num[12]; int i; int counttwo; int countthree; int countsix; int total=0; printf("enter 12 integer numbers:\n"); for(i=0;i<12;i++){ scanf("%d", &num[i]); } for(i=0;i<12;i++){ counttwo=0; if(num[i]%2==0){ counttwo++; } countthree=0; if(num[i]%3==0) { countthree++; } countsix=0; if(num[i]%6==0) { countsix++; } printf("There are %d multiples of 2:\n", counttwo); printf("There are %d multiples of 3:\n", countthree); printf("There are %d multiples of 6:\n", countsix); } return 0; }

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• How can I make my code work in a GUI using Swing in Java?

  - by Razor Shadow

  I'm making a tool that does multiple things, and I'm onto the last feature for now: You type in a date and it tells you what day of the week it would be on that date. So I have two problems here: I can't use I can't use arguments, it doesn't like them On the last line, I can't use jTextArea2.setText(d0); because it doesn't like that either... My code is here: public static void main(String[] args) { int d = Integer.parseInt(args[0]); int m = Integer.parseInt(args[1]); int y = Integer.parseInt(args[2]); int y0 = y - (14 - m) / 12; int x = y0 + y0/4 - y0/100 + y0/400; int m0 = m + 12 * ((14 - m) / 12) - 2; int d0 = (d + x + (31*m0)/12) % 7; System.out.println("Sunday = 0\nMonday = 1\nTuesday = 2\nWednesday = 3\nThursday = 4\nFriday = 5\nSaturday = 6\nThis date is on a:"); System.out.println(d0); Basically, this code was at first for use with the console, and now I want to implement it into a Swing GUI app. I'm only a week into learning Java, so excuse me if the problem is obvious or easy to fix... But can anyone figure out how to work it? Thanks!

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• MySQL datetime fields and daylight savings time -- how do I reference the "extra" hour?

  - by Aaron

  I'm using the America/New York timezone. In the Fall we "fall back" an hour -- effectively "gaining" one hour at 2am. At the transition point the following happens: it's 01:59:00 -04:00 then 1 minute later it becomes: 01:00:00 -05:00 So if you simply say "1:30am" it's ambiguous as to whether or not you're referring to the first time 1:30 rolls around or the second. I'm trying to save scheduling data to a MySQL database and can't determine how to save the times properly. Here's the problem: "2009-11-01 00:30:00" is stored internally as 2009-11-01 00:30:00 -04:00 "2009-11-01 01:30:00" is stored internally as 2009-11-01 01:30:00 -05:00 This is fine and fairly expected. But how do I save anything to 01:30:00 -04:00? The documentation does not show any support for specifying the offset and, accordingly, when I've tried specifying the offset it's been duly ignored. The only solutions I've thought of involve setting the server to a timezone that doesn't use daylight savings time and doing the necessary transformations in my scripts (I'm using PHP for this). But that doesn't seem like it should be necessary. Many thanks for any suggestions.

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• mysql report sql help

  - by sfgroups

  I have mysql table with data like this. record will have server with total cpu and virtual server with cpu assinged type, cpu srv1, 10 vsrv11, 2 vsrv12, 3 srv2, 15 vsrv21, 6 vsrv22, 7 vsrv23, 1 from the above data, I want to create output like this. server, total cpu, assigned cpu, free cpu srv1, 10, 5, 5 srv2, 15, 14, 1 Can you help me on creating sql query for this report? I have changed my table and data like this. CREATE TABLE `cpuallocation` ( `servertype` varchar(10) DEFAULT NULL, `servername` varchar(20) DEFAULT NULL, `hostname` varchar(20) DEFAULT NULL, `cpu_count` float DEFAULT NULL, UNIQUE KEY `server_uniq_idx` (`servertype`,`servername`,`hostname`) insert into cpuallocation values('srv', 'server1', '',16); insert into cpuallocation values('vir', 'server1', 'host1',5); insert into cpuallocation values('vir', 'server1', 'host2',2.5); insert into cpuallocation values('vir', 'server1', 'host3',4.5); insert into cpuallocation values('srv', 'server2', '',8); insert into cpuallocation values('vir', 'server2', 'host1',5); insert into cpuallocation values('vir', 'server2', 'host2',2.5); insert into cpuallocation values('srv', 'server3', '',24); insert into cpuallocation values('vir', 'server3', 'host1',12); insert into cpuallocation values('vir', 'server3', 'host2',2); insert into cpuallocation values('srv', 'server4', '',12); Update: I created two view, now I getting the result I want. create view v1 as select servername, sum(cpu_count) as cpu_allocated from cpuallocation where servertype='vir' group by servername; create view v2 as select servername, cpu_count as total_cpu from cpuallocation where servertype='srv'; select a.servername, a.total_cpu, b.cpu_allocated from v2 as a left join v1 as b on a.servername=b.servername; +------------+-----------+---------------+ | servername | total_cpu | cpu_allocated | +------------+-----------+---------------+ | server1 | 16 | 12 | | server2 | 8 | 7.5 | | server3 | 24 | 14 | | server4 | 12 | NULL | +------------+-----------+---------------+ 4 rows in set (0.00 sec) Is it possible to create a query with-out creating views?

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• How to make smooth movements in OpenGL?

  - by thyrgle

  So this kind of on topic to my other OpenGL question (not my OpenGL ES question but OpenGL the desktop version). If you have someone press a key to move a square how do you make the square movement naturally and less jumpy but also at the same speed I have it now? This is my code for the glutKeyboardFunc() function: void handleKeypress(unsigned char key, int x, int y) { if (key == 'w') { for (int i = 0; i < 12; i++) { if (i == 1 || i == 7 || i == 10 || i == 4) { square[i] = square[i] + 1; } } glutPostRedisplay(); } if (key == 'd') { for (int i = 0; i < 12; i++) { if (i == 0 || i % 3 == 0) { square[i] = square[i] + 1; } } glutPostRedisplay(); } if (key == 's') { for (int i = 0; i < 12; i++) { if (i == 1 || i == 7 || i == 10 || i == 4) { square[i] = square[i] - 1; } } glutPostRedisplay(); } if (key == 'a') { for (int i = 0; i < 12; i++) { if (i == 0 || i % 3 == 0) { square[i] = square[i] - 1; } } glutPostRedisplay(); } } I'm sorry if this doesn't quite make sense I'll try to rephrase it in a better way if it doesn't make sense.

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