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  • Sort std::vector by an element inside?

    - by user146780
    I currently have a std::vector which holds std::vector of double. I'd want to sort it by the second element of the double vectore. ex: instead of sorting by MyVec[0] or myvec[1] I wat it to sort myVec[0] and myvec[1] based on myvec[0][1] myvec[1][1]. Basically sort by a contained value, not the objects in it. so if myvec[0][1] is less than myvec[1][1] then myvec[0] and myvec[1] will swap. Thanks

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  • Speeding up Math calculations in Java

    - by Simon
    I have a neural network written in Java which uses a sigmoid transfer function defined as follows: private static double sigmoid(double x) { return 1 / (1 + Math.exp(-x)); } and this is called many times during training and computation using the network. Is there any way of speeding this up? It's not that it's slow, it's just that it is used a lot, so a small optimisation here would be a big overall gain.

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  • Floating point arithmetics restricted to integers

    - by user396672
    I use doubles for a uniform implementation of some arithmetic calculations. These calculations may be actually applied to integers too, but there are no C++-like templates in Java and I don't want to duplicate the implementation code, so I simply use "double" version for ints. Does JVM spec guarantees the correctness of integer operations such a <=,=, +, -, *, and / (in case of remainder==0) when the operations are emulated as corresponding floating point ops? (Any integer, of course, has reasonable size to be represented in double's mantissa)

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  • Parsing command line options in Perl

    - by Jay Gridley
    Hi guys, I am parsing command line options in Perl using Getopt::Long. I am forced to use prefix - (one dash) for short commands (-s) and -- (double dash) for long commands (ex. --input=file), but problem is, that there is one special option (-r=) so it is long option for its requirement for argument, but it has to have one dash (-) prefix not double dash (--) like other long options. Is possible to setup Getopt::Long to accept these?

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  • GC generation 3 appearing in windbg

    - by Johnv2020
    I've a dump file of a process I'm running (trying to find a memory leak) One thing I've noticed is that when I dump the bigger objects via !do windbg tells me that they are GC generation 3 ?? All of these are byte arrays so when I look at all the byte arrays in the dump I can see GC generations 0, 1, 2 & 3. Could someone explain whats going on here as I thought there was only 3 generations of GC.

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  • Comparator interface

    - by 1ace1
    ok I was going to edit my previous question but i wasnt sure if it was the right way to do it so i'll just give another question about Comparator, now i want to be able to sort with different ways. I have a bank checks and i want to sort with checkNumber then checkAmount i managed to do it with checkNumber but couldnt figure out how with checkAmount here is how i did it for checkNumber: import java.util.Comparator; public class Check implements Comparator { private int checkNumber; private String description; private double checkAmount; public Check() { } public Check(int newCheckNumber, double newAmountNumber) { setCheckNumber(newCheckNumber); setAmountNumber(newAmountNumber); } public String toString() { return checkNumber + "\t\t" + checkAmount; } public void setCheckNumber(int checkNumber) { this.checkNumber = checkNumber; } public int getCheckNumber() { return checkNumber; } public void setAmountNumber(double amountNumber) { this.checkAmount = amountNumber; } public double getAmountNumber() { return checkAmount; } @Override public int compare(Object obj1, Object obj2) { int value1 = ((Check) obj1).getCheckNumber(); int value2 = ((Check) obj2).getCheckNumber(); int result = 0; if (value1 > value2){ result = 1; } else if(value1 < value2){ result = -1; } return result; } } import java.util.ArrayList; import java.util.Collections; import test.CheckValue; public class TestCheck { public static void main(String[] args) { ArrayList List = new ArrayList(); List.add(new Check(445, 55.0)); List.add(new Check(101,43.12)); List.add(new Check(110,101.0)); List.add(new Check(553,300.21)); List.add(new Check(123,32.1)); Collections.sort(List, new Check()); System.out.println("Check Number - Check Amount"); for (int i = 0; i < List.size(); i++){ System.out.println(List.get(i)); } } } thank you very much in advance and please tell me if im submiting things in the wrong way.

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  • UnicodeDecodeError in pyton 2.7

    - by user2913962
    i try to write this code to process Arabic language by python import codecs file = codecs.open("C:\Python27\CCA_raw_utf8.txt","r","utf-8") text= file.read() #################################### print "\n "," --------------------------------------------" text=text[1:] words=text.split() for w in words: if w == unicode ("?????","utf-8"): print w but it doesn't and take error " if w == unicode ("?????","utf-8"): UnicodeDecodeError: 'utf8' codec can't decode byte 0xc7 in position 0: invalid continuation byte " why program gives this result and how we can correct that??

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  • Why can't your switch statement data type be long Java?

    - by Fostah
    Here's an excerpt from Sun's Java tutorials: A switch works with the byte, short, char, and int primitive data types. It also works with enumerated types (discussed in Classes and Inheritance) and a few special classes that "wrap" certain primitive types: Character, Byte, Short, and Integer (discussed in Simple Data Objects ). There must be a good reason why the long primitive data type is not allowed. Anyone know what it is?

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  • round() for float in C++

    - by Roddy
    I need a simple floating point rounding function, thus: double round(double); round(0.1) = 0 round(-0.1) = 0 round(-0.9) = -1 I can find ceil() and floor() in the math.h - but not round(). Is it present in the standard C++ library under another name, or is it missing??

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  • Python : Convert from C-Char to Int

    - by cuband
    I have a string read in from a binary file that is unpacked using struct.unpack as a string of length n. Each byte in the string is a single integer (1-byte) representing 0-255. So for each character in the string I want to convert it to an integer. I can't figure out how to do this. Using ord doesn't seem to be on the right track...

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  • Detecting if two png images are different

    - by Benjol
    (Context: running autohotkey scripts to try and automate some tests. The plan is to take screenshots and then compare them to 'standard' screenshots to detect if output has changed). Is there a 'clever' way to check if two png images are different? By clever I mean other than comparing them byte by byte? (after having compared their size, obviously)

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  • Unzip a memorystream (Contains the zip file) and get the files

    - by user1621791
    I have a memory stream that contains a zip file in byte[] format . Is there any way I can unzip this memory stream, without any need of writing the file to disk ? In general I am using ICSharpCode.SharpZipLib.Zip.FastZip to unzip a file , But any way to unzip a memory stream ? and store the files in another memorystream or in byte[] format according to the files/folders present in the zip ? Any way I can use the Memorymapped files feature in this scenario ?

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  • Constructors from extended class in Java

    - by Crystal
    I'm having some trouble with a hw assignment. In one assignment, we had to create a Person class. Mine was: public class Person { String firstName; String lastName; String telephone; String email; public Person() { firstName = ""; lastName = ""; telephone = ""; email = ""; } public Person(String firstName) { this.firstName = firstName; } public Person(String firstName, String lastName, String telephone, String email) { this.firstName = firstName; this.lastName = lastName; this.telephone = telephone; this.email = email; } public String getFirstName() { return firstName; } public void setFirstName(String firstName) { this.firstName = firstName; } public String getLastName() { return lastName; } public void setLastName(String lastName) { this.lastName = lastName; } public String getTelephone() { return telephone; } public void setTelephone(String telephone) { this.telephone = telephone; } public String getEmail() { return email; } public void setEmail(String email) { this.email = email; } public boolean equals(Object otherObject) { // a quick test to see if the objects are identical if (this == otherObject) { return true; } // must return false if the explicit parameter is null if (otherObject == null) { return false; } if (!(otherObject instanceof Person)) { return false; } Person other = (Person) otherObject; return firstName.equals(other.firstName) && lastName.equals(other.lastName) && telephone.equals(other.telephone) && email.equals(other.email); } public int hashCode() { return 7 * firstName.hashCode() + 11 * lastName.hashCode() + 13 * telephone.hashCode() + 15 * email.hashCode(); } public String toString() { return getClass().getName() + "[firstName = " + firstName + '\n' + "lastName = " + lastName + '\n' + "telephone = " + telephone + '\n' + "email = " + email + "]"; } } Now we have to extend that class and use that class in our constructor. The function protoype is: public CarLoan(Person client, double vehiclePrice, double downPayment, double salesTax, double interestRate, CAR_LOAN_TERMS length) I'm confused on how I use the Person constructor from the superclass. I cannot necessarily do super(client); in my constructor which is what the book did with some primitive types in their example. Not sure what the correct thing to do is... Any thoughts? Thanks!

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  • Optimizing division/exponential calculation

    - by Saltheart
    I've inherited a Visual Studio/VB.Net numerical simulation project that has a likely inefficient calculation. Profiling indicates that the function is called a lot (1 million times plus) and spends about 50% of the overall calculation within this function. Here is the problematic portion Result = (A * (E ^ C)) / (D ^ C * B) (where A-C are local double variables and D & E global double variables) Result is then compared to a threshold which might have additional improvements as well, but I'll leave them another day any thoughts or help would be appreciated Steve

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  • C# How can i remove newline characters from binary?

    - by Tom
    Basically i have binary data, i dont mind if it's unreadable but im writing it to a file which is parsed and so it's importance newline characters are taken out. I thought i had done the right thing when i converted to string.... byte[] b = (byte[])SubKey.GetValue(v[i]); s = System.Text.ASCIIEncoding.ASCII.GetString(b); and then removed the newlines String t = s.replace("\n","") but its not working ?

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  • saving an image object in sql server database from action method

    - by user3532152
    [HttpPost] public void Test(HttpPostedFileBase file) { UsersContext db = new UsersContext(); byte[] image = new byte[file.ContentLength]; file.InputStream.Read(image, 0, image.Length); CrimeReport i = new CrimeReport { ImageId=1, ImageName="Anjli",ImageContent = image, Active=true }; db.CrimeReports.Add(i); db.SaveChanges(); } I am getting an exception on db.CrimeReports.Add(i);

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  • C++, strange behavior reusing variable name

    - by aaa
    hello. I have following snippet: { double scale = 3; // not used? { double scale = 4*scale; // what is RHS scale? for (...) { // scale is 0 here, using g++ } } } moreover, g++ reports first scale is not used. how is second scale initialize? What should be correct behavior? thanks

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  • What does @@variable mean in Ruby?

    - by Andrew
    What are Ruby variables preceded with double at signs (@@)? My understanding of a variable preceded with an at sign is that it is an instance variable, like this in PHP: PHP version class Person { public $name; public function setName($name) { $this->name = $name; } public function getName() { return $this->name; } } Ruby equivalent class Person def set_name(name) @name = name end def get_name() @name end end What does the double at sign @@ mean, and how does it differ from a single at sign?

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  • Xen kernel can't see 2 disks of 6 of 1TB, does it have a limitation?

    - by PartySoft
    Linux gentoo-xen 2.6.18-xen-r12 #3 SMP Tue Oct 5 09:28:53 PDT 2010 x86_64 Intel(R) Xeon(R) CPU E5506 @ 2.13GHz GenuineIntel GNU/Linux I have 6 disks of 1 TB and i can't see all of them only 4, can anyone give me an ideea what can i do ? Filesystem Size Used Avail Use% Mounted on rootfs 886G 4.4G 836G 1% / /dev/sda3 886G 4.4G 836G 1% / rc-svcdir 1.0M 44K 980K 5% /lib64/rc/init.d shm 7.9G 0 7.9G 0% /dev/shm /dev/sdb1 917G 200M 871G 1% /home2 /dev/sdc1 917G 200M 871G 1% /home3 /dev/sdd1 917G 200M 871G 1% /home4 The hardware is Dual xeon E5506 processors on a supermicro X8DTL mobo 4.346585] ata3.00: ATA-8, max UDMA/133, 1953525168 sectors: LBA48 NCQ (depth 0/32) [ 4.346588] ata3.00: ata3: dev 0 multi count 16 [ 4.352861] ata3.00: configured for UDMA/133 [ 4.352867] scsi3 : ata_piix [ 4.352875] PM: Adding info for No Bus:host3 [ 4.510584] ata4.00: ATA-8, max UDMA/133, 1953525168 sectors: LBA48 NCQ (depth 0/32) [ 4.510587] ata4.00: ata4: dev 0 multi count 16 [ 4.516848] ata4.00: configured for UDMA/133 [ 4.516861] PM: Adding info for No Bus:target2:0:0 [ 4.516905] Vendor: ATA Model: SAMSUNG HD103SJ Rev: 1AJ1 [ 4.516910] Type: Direct-Access ANSI SCSI revision: 05 [ 4.516920] PM: Adding info for scsi:2:0:0:0 [ 4.517452] SCSI device sde: 1953525168 512-byte hdwr sectors (1000205 MB) [ 4.517460] sde: Write Protect is off [ 4.517461] sde: Mode Sense: 00 3a 00 00 [ 4.517478] SCSI device sde: drive cache: write back [ 4.517514] SCSI device sde: 1953525168 512-byte hdwr sectors (1000205 MB) [ 4.517521] sde: Write Protect is off [ 4.517522] sde: Mode Sense: 00 3a 00 00 [ 4.517532] SCSI device sde: drive cache: write back [ 4.517534] sde: sde1 [ 4.524551] sd 2:0:0:0: Attached scsi disk sde [ 4.524855] sd 2:0:0:0: Attached scsi generic sg4 type 0 [ 4.524874] PM: Adding info for No Bus:target3:0:0 [ 4.524928] Vendor: ATA Model: SAMSUNG HD103SJ Rev: 1AJ1 [ 4.524933] Type: Direct-Access ANSI SCSI revision: 05 [ 4.524946] PM: Adding info for scsi:3:0:0:0 [ 4.525216] SCSI device sdf: 1953525168 512-byte hdwr sectors (1000205 MB) [ 4.525227] sdf: Write Protect is off [ 4.525228] sdf: Mode Sense: 00 3a 00 00 [ 4.525242] SCSI device sdf: drive cache: write back [ 4.525280] SCSI device sdf: 1953525168 512-byte hdwr sectors (1000205 MB) [ 4.525286] sdf: Write Protect is off [ 4.525289] sdf: Mode Sense: 00 3a 00 00 [ 4.525301] SCSI device sdf: drive cache: write back [ 4.525302] sdf: sdf1 [ 4.532691] sd 3:0:0:0: Attached scsi disk sdf [ 4.533010] sd 3:0:0:0: Attached scsi generic sg5 type 0 [ 4.977669] scsi: <fdomain> Detection failed (no card) [ 5.030479] GDT-HA: Storage RAID Controller Driver. Version: 3.05 [ 5.030635] GDT-HA: Found 0 PCI Storage RAID Controllers [ 5.372350] Fusion MPT base driver 3.04.01 [ 5.372358] Copyright (c) 1999-2005 LSI Logic Corporation [ 5.579176] Fusion MPT SPI Host driver 3.04.01 [ 5.881777] ieee1394: Initialized config rom entry `ip1394' [ 6.166745] ieee1394: sbp2: Driver forced to serialize I/O (serialize_io=1) [ 6.166748] ieee1394: sbp2: Try serialize_io=0 for better performance [ 6.428866] md: md driver 0.90.3 MAX_MD_DEVS=256, MD_SB_DISKS=27 [ 6.428872] md: bitmap version 4.39 [ 6.431518] md: raid0 personality registered for level 0 [ 6.495979] md: raid1 personality registered for level 1 [ 6.570270] raid5: automatically using best checksumming function: generic_sse [ 6.575523] generic_sse: 6608.000 MB/sec [ 6.575526] raid5: using function: generic_sse (6608.000 MB/sec) [ 6.596226] raid6: int64x1 1835 MB/s [ 6.613231] raid6: int64x2 1773 MB/s [ 6.630256] raid6: int64x4 1675 MB/s [ 6.647296] raid6: int64x8 1027 MB/s [ 6.664267] raid6: sse2x1 3578 MB/s [ 6.681268] raid6: sse2x2 4207 MB/s [ 6.698280] raid6: sse2x4 4625 MB/s [ 6.698281] raid6: using algorithm sse2x4 (4625 MB/s) [ 6.698285] md: raid6 personality registered for level 6 [ 6.698286] md: raid5 personality registered for level 5 [ 6.698288] md: raid4 personality registered for level 4 [ 6.781090] md: raid10 personality registered for level 10 [ 7.007043] Intel(R) PRO/1000 Network Driver - version 7.1.9-k4 [ 7.007046] Copyright (c) 1999-2006 Intel Corporation. [ 9.229465] kjournald starting. Commit interval 5 seconds [ 9.229476] EXT3-fs: mounted filesystem with ordered data mode.

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  • Openldap/Sasl/GSSAPI on Debian: Key table entry not found

    - by badbishop
    The goal: to make an OpenLDAP server to authenticate using Kerberos V via GSSAPI Setup: several virtual machines running on freshly installed/updated Debian Squeeze A master KDC server kdc.example.com A LDAP server, running OpenLDAP ldap.example.com The problem: tom@ldap:~$ ldapsearch -b 'dc=example,dc=com' SASL/GSSAPI authentication started ldap_sasl_interactive_bind_s: Other (e.g., implementation specific) error (80) additional info: SASL(-1): generic failure: GSSAPI Error: Unspecified GSS failure. Minor code may provide more information (Key table entry not found) One might suggest to add that bloody keytab entry, but here's the real problem: ktutil: rkt /etc/ldap/ldap.keytab ktutil: list slot KVNO Principal ---- ---- --------------------------------------------------------------------- 1 2 ldap/[email protected] 2 2 ldap/[email protected] 3 2 ldap/[email protected] 4 2 ldap/[email protected] So, the entry as suggested by the OpenLDAP manual is there allright. Deleting and re-creating both service principal and the keytab on ldap.example.com didn't help, I get the same error. And before I make the keytab file readable by openldap, I get "Permission denied" error instead of the one in the subject. Which implies, that the right keytab file is being accessed, as set in /etc/default/slapd. I have my doubts about the following part of slapd config: root@ldap:~# cat /etc/ldap/slapd.d/cn\=config.ldif | grep -v "^#" dn: cn=config objectClass: olcGlobal cn: config olcArgsFile: /var/run/slapd/slapd.args olcLogLevel: 256 olcPidFile: /var/run/slapd/slapd.pid olcToolThreads: 1 structuralObjectClass: olcGlobal entryUUID: d6737f5c-d321-1030-9dbe-27d2a7751e11 olcSaslHost: kdc.example.com olcSaslRealm: EXAMPLE.COM olcSaslSecProps: noplain,noactive,noanonymous,minssf=56 olcAuthzRegexp: {0}"uid=([^/]*),cn=EXAMPLE.COM,cn=GSSAPI,cn=auth" "uid=$1,ou=People,dc=example,dc=com" olcAuthzRegexp: {1}"uid=host/([^/]*).example.com,cn=example.com,cn=gssapi,cn=auth" "cn=$1,ou=hosts,dc=example,dc=com" A HOWTO at https://help.ubuntu.com/community/OpenLDAPServer#Kerberos_Authentication mentiones vaguely: Also, it is frequently necessary to map the Distinguished Name (DN) of an authorized Kerberos client to an existing entry in the DIT. I fail to understand where in the tree this should be defined, what schema should be used, etc. After hours of googling, it's official: I'm stuck! Please, help. Other things checked: Kerberos as such works fine (I can ssh without using a password to any machine in this setup). That means there should be no DNS-related problems. ldapsearch -b 'dc=example,dc=com' -x works OK. SASL/GSSAPI has been tested using sasl-sample-server -m GSSAPI -s ldap and sasl-sample-client -s ldap -n ldap.example.com -u tom without errors: root@ldap:~# sasl-sample-server -m GSSAPI -s ldap Forcing use of mechanism GSSAPI Sending list of 1 mechanism(s) S: R1NTQVBJ Waiting for client mechanism... C: R1NTQVBJAGCCAmUGCSqGSIb3EgECAgEAboICVDCCAlCgAwIBBaEDAgEOogcDBQAgAAAAo4IBamGCAWYwggFioAMCAQWhDRsLRVhBTVBMRS5DT02iIzAhoAMCAQOhGjAYGwRsZGFwGxBsZGFwLmV4YW1wbGUuY29to4IBJTCCASGgAwIBEqEDAgECooIBEwSCAQ8Re8XUnscB8dx6V/cXL+uzSF2/olZvcrVAJHZBZrfRKUFEQmU1Li46bUGK3GZwsn6qUVwmW6lyqVctOIYwGvBpz81Rw/5mj4V5iQudZbIRa+5Ew6W1oBB7ALi2cnPsbUroqzGmEh8/Vw8zSFk7W1gND4DLuWrPXD2xhLDUMMekBn5nXEPTnNAnV4w81Sj3ZlyLZz5OSitGVUEnQweV53z1spWsASHHWod/tSuxb19YeWmY5QHXPLG+lL5+w+Cykr0EhYVj8f8MDWFB8qoN1cr85xDfn18r8JldSw+i18nFKOo8usG+37hZTWynHYvBfMONtG9mLJv82KGPZMydWK7pzyTZDcnSsIjo2AftMZd5pIHMMIHJoAMCARKigcEEgb5aG1k4xgxmUXX7RKfvAbVBVJ12dWOgFFjMYceKjziXwrrOkv8ZwIvef9Yn2KsWznb5L55SXt2c/zlPa5mLKIktvw77hsK1h/GYc7p//BGOsmr47aCqVWsGuTqVT129uo5LNQDeSFwl2jXCkCZJZavOVrqYsM6flrPYE4n5lASTcPitX+/WNsf6WrvZoaexiv1JqyM/MWqS/vMBRMMc5xlurj6OARFvP9aFZoK/BLmfkSyAJj6MLbLVXZtkHiIPgot 'GSSAPI' Sending response... S: YIGZBgkqhkiG9xIBAgICAG+BiTCBhqADAgEFoQMCAQ+iejB4oAMCARKicQRvkxggi9pW+yJ1ExbTwLDclqw/VQ98aPq8mt39hkO6PPfcO2cB+t6vJ01xRKBrT9D2qF2XK0SWD4PQNb5UFbH4RM/bKAxDuCfZ1MHKgIWTLu4bK7VGZTbYydcckU2d910jIdvkkHhaRqUEM4cqp/cR Waiting for client reply... C: got '' Sending response... S: BQQF/wAMAAAAAAAAMBOWqQcACAAlCodrXW66ZObsEd4= Waiting for client reply... C: BQQE/wAMAAAAAAAAFUYbXQQACAB0b20VynB4uGH/iIzoRhw=got '?' Negotiation complete Username: tom Realm: (NULL) SSF: 56 sending encrypted message 'srv message 1' S: AAAASgUEB/8AAAAAAAAAADATlqrqrBW0NRfPMXMdMz+zqY32YakrHqFps3o/vO6yDeyPSaSqprrhI+t7owk7iOsbrZ/idJRxCBm8Wazx Waiting for encrypted message... C: AAAATQUEBv8AAAAAAAAAABVGG17WC1+/kIV9xTMUdq6Y4qYmmTahHVCjidgGchTOOOrBLEwA9IqiTCdRFPVbK1EgJ34P/vxMQpV1v4WZpcztgot '' recieved decoded message 'client message 1' root@ldap:~# sasl-sample-client -s ldap -n ldap.example.com -u tom service=ldap Waiting for mechanism list from server... S: R1NTQVBJrecieved 6 byte message Choosing best mechanism from: GSSAPI returning OK: tom Using mechanism GSSAPI Preparing initial. Sending initial response... C: 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 Waiting for server reply... S: YIGZBgkqhkiG9xIBAgICAG+BiTCBhqADAgEFoQMCAQ+iejB4oAMCARKicQRvkxggi9pW+yJ1ExbTwLDclqw/VQ98aPq8mt39hkO6PPfcO2cB+t6vJ01xRKBrT9D2qF2XK0SWD4PQNb5UFbH4RM/bKAxDuCfZ1MHKgIWTLu4bK7VGZTbYydcckU2d910jIdvkkHhaRqUEM4cqp/cRrecieved 156 byte message C: Waiting for server reply... S: BQQF/wAMAAAAAAAAMBOWqQcACAAlCodrXW66ZObsEd4=recieved 32 byte message Sending response... C: BQQE/wAMAAAAAAAAFUYbXQQACAB0b20VynB4uGH/iIzoRhw= Negotiation complete Username: tom SSF: 56 Waiting for encoded message... S: AAAASgUEB/8AAAAAAAAAADATlqrqrBW0NRfPMXMdMz+zqY32YakrHqFps3o/vO6yDeyPSaSqprrhI+t7owk7iOsbrZ/idJRxCBm8Wazxrecieved 78 byte message recieved decoded message 'srv message 1' sending encrypted message 'client message 1' C: AAAATQUEBv8AAAAAAAAAABVGG17WC1+/kIV9xTMUdq6Y4qYmmTahHVCjidgGchTOOOrBLEwA9IqiTCdRFPVbK1EgJ34P/vxMQpV1v4WZpczt

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