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  • PHP class to C# class?

    - by LordSauron
    I work for a company that makes application's in C#. recently we got a customer asking us to look in to rebuilding an application written in PHP. This application receives GPS data from car mounted boxes and processes that into workable information. The manufacturer for the GPS device has a PHP class that parses the received information and extracts coordinates. We were looking in to rewriting the PHP class to a C# class so we can use it and adapt it. And here it comes, on the manufacturers website there is a singel line of text that got my skin krawling: "The encoding format and contents of the transmitted data are subject to constant changes. This is caused by implementations of additional features by new module firmware versions which makes it virtually impossible to document it and for you to properly decode it yourself." So i am now looking for a option to use the "constantly changing" PHP class and access it in C#. Some thing link a shell only exposing some function's i need. Except i have no idea how i can do this. Can any one help me find a solution for this.

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  • how to pass session_id() throught out the php pages?

    - by Piyush
    when user clicks on login button(index.php) I am calling chechlogin.php where I am checking loginId an password as- if($count==1) { // Register $myusername, $mypassword and redirect to file "login_success.php" session_register("myusername"); session_register("mypassword"); $_SESSION['UserId'] = $myusername; $_session['SessionId'] = session_id(); header("location:LoggedUser.php"); } in LiggedUser.php <?php session_start(); //starting session if (!isset($_SESSION['SessionId']) || $_SESSION['SessionId'] == '') { header("location:index.php"); } ? Problem: It is always going back to index.php page although I am entering right userid and password.I think session_id() is not working properly or ??

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  • php lampp permissions of fopen function

    - by marmoushismail
    hi i'm programming php using: netbeans 6.8 lampp for ubuntu (xampp) apache which came with xampp $fh = fopen("testfile2.txt", 'w') or die("Failed to create file"); $text ="hello man cool good"; fwrite($fh, $text) or die("Could not write to file"); fclose($fh); echo "File 'testfile.txt' written successfully"; //i get the next error: Warning: fopen(testfile2.txt) [function.fopen]: failed to open stream: Permission denied in /home/marmoush/allprojects/phpprojects/myindex.php on line 91 Failed to create file anyway i know what this error is; it's about folder and files permissions; i looked into the folder permission tab made access available for "others" group ( to read and write) the program worked result was a file (test.txt) so i looked at the created file permission it appears to be that (php , xampp or whoever) creates file with (nobody permission) I have 2 QUESTIONS: 1- what if i need the file created by (php code and xampp ) to have the "root or user or myname" permissions ?? where to set this setting 2-also my concern (what if i send this files to actual web server will it make nobody permissions also nobody ? when they create files

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  • Connection to mysql works through php but not through a form submission?

    - by Legend
    I have a download.php file that connects to a remote mysql database. If I run it using php download.php it works fine. But if I create another php file form.php and then submit the form to this download.php, it complains the following: Can't connect to MySQL server on '<IP_ADDRESS>' (13) Does anyone know why this might be happening? I can't see a reason why this works directly but fails to work upon form submission...

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  • Upload to a PHP Server, using Ajax ( XMLHttp POST)

    - by Krishnanunni
    Right now i'm using the below method to Upload a file to PHP <form enctype="multipart/form-data" action="http://sserver.com/fileupload.php" method="POST"> <input type="hidden" name="MAX_FILE_SIZE" value="30000000" /> <input type="hidden" name="filename" value="file_uploaded.gif" /> <input type="hidden" name="username" value="foobar"/> Please choose a file: <input name="uploaded" type="file" /><br /> <input type="submit" value="Upload" /> </form> I read the $_POST and $_FILE in php to complete upload like this. $target = $_SERVER['DOCUMENT_ROOT']."/test/upload/"; $target = $target . basename( $_FILES['uploaded']['name']) ; echo $target; $ok=1; if(move_uploaded_file($_FILES['uploaded']['tmp_name'], $target)) { echo "The file ". basename( $_FILES['uploaded']['name']). " has been uploaded"; } else { echo "Sorry, there was a problem uploading your file."; } My questions is , can i change the above said code (HTML) to an Ajax XMLHttpRequest without changes in PHP.

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  • PHP Foreach statement issue. Multiple rows are returned

    - by Daniel Patilea
    I'm a PHP beginner and lately i've been having a problem with my source code. Here it is: <html> <head> <title> Bot </title> <link type="text/css" rel="stylesheet" href="main.css" /> </head> <body> <form action="bot.php "method="post"> <lable>You:<input type="text" name="intrebare"></lable> <input type="submit" name="introdu" value="Send"> </form> </body> </html> <?php //error_reporting(E_ALL & ~E_NOTICE); mysql_connect("localhost", "root", "") or die(mysql_error()); mysql_select_db("robo") or die(mysql_error()); $intrebare=$_POST['intrebare']; $query = "SELECT * FROM dialog where intrebare like '%$intrebare%'"; $result = mysql_query($query) or die(mysql_error()); $row = mysql_fetch_array($result) or die(mysql_error()); ?> <div id="history"> <?php foreach($row as $rows){ echo "<b>The robot says: </b><br />"; echo $row['raspuns']; } ?> </div> It returns me the result x6 times. This problem appeared when I've made that foreach because I wanted the results to stuck on the page one by one after every sql querry. Can you please tell me what seems to be the problem? Thanks!

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  • using a href (html)tag along with PHP

    - by dexter
    i have tried: <?php include("delete.php") ?> <?php .... .... .... if($result=mysql_query($sql)) { echo "<table><th>Id</th><th>Name</th><th>Description</th><th>Unit Price</th>"; while($row = mysql_fetch_array($result)) { echo "<tr><td>".$row['Id']."</td><td>".$row['Name']."</td><td>".$row['Description']."</td><td>".$row['UnitPrice']."</td> <td><a href='delproduct($row[Id])' onclick = 'return MsgOkCancel()'>Delete</a></td></tr>"; echo "<br/>"; } } ?> following javascript is in the same page: <script type="text/javascript" language="javascript"> function MsgOkCancel() { if (confirm("Are You Sure You Want to Delete?")) { return true } else {return false} } </script> where delproduct is a javascript function in delete.php written like: <script type="javascript"> function delproduct(Id) { alert('Id '+ Id); } <script> ** after ** clicking Delete a okcancel message-box appear asking conformation ** but ** after clicking 'ok' it should execute statements inside delproduct function but it doesn't it gives error like: Object Not Found :The requested URL was not found on this server. what would be the problem? pls help, thanks

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  • Write to PDF using PHP from android device

    - by Brent Mitchell
    I am trying to write to a pdf file on php server. I have sent variables to the server, create the pdf document, then have my phone download the document to view on device. The variables seem not to write on the php file. I have my code below public void postData() { try { Calculate calc = new Calculate(); HttpClient mClient = new DefaultHttpClient(); StringBuilder sb=new StringBuilder("myurl.com/pdf.php"); HttpPost mpost = new HttpPost(sb.toString()); String value = "1234"; List nameValuepairs = new ArrayList(1); nameValuepairs.add(new BasicNameValuePair("id",value)); mpost.setEntity(new UrlEncodedFormEntity(nameValuepairs)); } catch (UnsupportedEncodingException e) { Log.w(" error ", e.toString()); } catch (Exception e) { Log.w(" error ", e.toString()); } } And my php code to write the variable "value" onto the pdf document: //code to reverse the string if($_POST[] != null) { $reversed = strrev($_POST["value"]); $this->SetFont('Arial','u',50); $this->Text(52,68,$reversed); } I am just trying to write the variable in a random spot, but the variable the if statement is always null and I do not know why. Thanks. Sorry if it is a little sloppy.

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  • Increasing understanding of validating a string with PHP string functions

    - by user1554264
    I've just started attempts to validate data in PHP and I'm trying to understand this concept better. I was expecting the string passed as an argument to the $data parameter for the test_input() function to be formatted by the following PHP functions. trim() to remove white space from the end of the string stripslashes() to return a string with backslashes stripped off htmlspecialchars() to convert special characters to HTML entities The issue is that the string that I am echoing at the end of the function is not being formatted in the way I desire at all. In fact it looks exactly the same when I run this code on my server - no white space removed, the backslash is not stripped and no special characters converted to HTML entities. My question is have I gone about this in the wrong approach? Should I be creating the variable called $santised_input on 3 separate lines with each of the functions trim(), stripslashes() and htmlspecialchars()? By my understanding surely I am overwriting the value of the $santised_input variable each time I recreate it on a new line of code. Therefore the trim() and stripslashes() string functions will never be executed. What I am trying to achieve is using the "$santised_input" variable to run all of these PHP string functions when the $data argument is passed to my test_input() function. In other words can these string functions be chained together so that I only need to create $santised_input once? <?php function test_input($data) { $santised_input = trim($data); $santised_input = stripslashes($data); $santised_input = htmlspecialchars($data); echo $santised_input; } test_input("%22%3E%3Cscript%3Ealert('hacked')%3C/script%3E\ "); //Does not output desired result "&quot;&gt;&lt;script&gt;alert('hacked')&lt;/script&gt;" ?>

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  • Why is my php script freezing?

    - by William
    What is causing my php code to freeze? I know it's cause of the while loop, but I have $max_threads--; at the end so it shouldn't do that. <html> <head> <?php $db = mysql_connect("host","name","pass") or die("Can't connect to host"); mysql_select_db("dbname",$db) or die("Can't connect to DB"); $sql_result = mysql_query("SELECT MAX(Thread) FROM test_posts", $db); $rs = mysql_fetch_row($sql_result); $max_threads = $rs[0]; $board = $_GET['board']; ?> </head> <body> <?php While($max_threads >= 0) { $sql_result = mysql_query("SELECT MIN(ID) FROM test_posts WHERE Thread=".$max_threads."", $db); $rs = mysql_fetch_row($sql_result); $sql_result = mysql_query("SELECT post FROM test_posts WHERE ID=".$rs[0]."", $db); $post = mysql_fetch_row($sql_result); $sql_result = mysql_query("SELECT name FROM test_posts WHERE ID=".$rs[0]."", $db); $name = mysql_fetch_row($sql_result); $sql_result = mysql_query("SELECT trip FROM test_posts WHERE ID=".$rs[0]."", $db); $trip = mysql_fetch_row($sql_result); if(!empty($post)) echo'<div class="postbox"><h4>'.$name[0].'['.$trip[0].']</h4><hr />' . $post[0] . '<br /><hr />[<a href="http://prime.programming-designs.com/test_forum/viewthread.php?thread='.$max_threads.'">Reply</a>]</div>'; $max_threads--; } ?> </body> </html>

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  • PHP classes, parse syntax errors when using 'var' to declare variables

    - by jon
    I am a C# guy trying to translate some of my OOP understanding over to php. I'm trying to make my first class object, and are hitting a few hitches. Here is the beginning of the class: <?php require("Database/UserDB.php"); class User { private var $uid; private var $username; private var $password; private var $realname; private var $email; private var $address; private var $phone; private var $projectArray; public function _construct($username) { $userArray = UserDB::GetUserArray($username); $uid = $userArray['uid']; $username = $userArray['username']; $realname = $userArray['realname']; $email = $userArray['email']; $phone = $userArray['phone']; $i = 1; $projectArray = UserDB::GetUserProjects($this->GetID()); while($projectArray[$i] != null) { $projectArray[$i] = new Project($projectArray[$i]); } UserDB.php is where I have all my static functions interacting with the Database for this User Class. I am getting errors using when I use var, and I'm getting confused. I know I don't HAVE to use var, or declare the variables at all, but I feel it is a better practice to do so. the error is "unexpected T_VAR, expecting T_VARIABLE" When I simply remove var from the declarations it works. Why is this?

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  • Redirecting Pages with PHP causing problems

    - by psp
    I have a page which has a link to a php page which takes data from $_GET and updates a database. After that it returns the user to the homepage with: header("Location: http://localhost/"); The thing is that this seems to "interrupt" the mysql part of the code. If I remove this redirect, everything in the database is updated, but when I put it back, nothing gets updated... This is the database update code, I am using a class of mine as a mysql wrapper: $conn->where('hash',$data1['hash']); $conn->update(TABLE_ITEMS,$newData1); $conn->where('hash',$data2['hash']); $conn->update(TABLE_ITEMS,$newData2); Notes: -There is no text or echo()'s on the page and no space before the <?php tag Order of Code: Data received from $_SESSION and $_GET Data processed and placed into arrays Data placed into mysql database header(); used to redirect page Code <?php require_once('config.php'); import(); if ( isset ( $_GET['g'] ) && isset ( $_SESSION['itemA'] ) && isset ( $_SESSION['itemB'] ) ) { $itemA = $_SESSION['gameA']; $itemB = $_SESSION['gameB']; $newData1 = processData($itemA); $newData2 = processData($itemB); $conn->update(TABLE_ITEMS,$newData1); $conn->update(TABLE_ITEMS,$newData2); header('Location: http://localhost/'); } else { header('Location: http://localhost/'); }

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  • I want to store a php $_SESSION variable and retrieve it on another page.

    - by CDeanMartin
    <?php session_start(); // store session data $_SESSION['count']=0; ?> <html><head></head> <body> <?php include ("getElement.php"); echo getLinkButton("myscript.php", "myscript.php"); echo $_SESSION['count']++; ?> </body> </html> The code above works, but when I click the link to navigate to myscript.php: <?php echo $_SESSION['count']; ?> I get this error: Undefined variable: _SESSION in /home/ubuntu/public_html/myscript.php on line 2

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  • post values to external page explicitly PHP

    - by JPro
    Hi, I want to post values to a page through a hyperlink in another page. Is it possible to do that? Let's say I have a page results.php which has the starting line, <?php if(isset($_POST['posted_value'])) { echo "expected value"; // do something with the data } else { echo "no the value expected"; } If from another page say link.php I place a hyperlink like this: <a href="results.php?posted_value=1"> , will this be accepetd by the results page? If instead if I replace the above starting line with if(isset($_REQUEST['posted_value'])), will this work? I believe the above hyperlink evaluates to GET, but since the only visibility difference between GET and POST that is you can see parameters in the address bar with GET But, is there any other way to place a hyperlink which can post values to a page? or can we use jquery in the place of hyperlink to POST the values? Can anyone please suggest me something on this please? Thanks.

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  • What is good about php/what is php good for?

    - by Roman A. Taycher
    I have often seen php bashed around the webs as a loosely typed(loose typing as in a lot of type coercion and/or easy(and perhaps common) to cast object all over not dynamic typing) language without a great compiler/interpreter/vm, with even the standard library using a number of different naming conventions. A lot of people complain about perl but many (including a lot of the complainers) also give it a lot of credit for its regexes and general flexibility and power. Other then legacy code , giant web frameworks that can do tons(drupal,ect.), and easy cheap hosting what is good about php (,also what criticism are unfair, and how is the language evolving to overcome its problems). Why would i want to learn it? why would I want to do an independent project in it? The main thing I have heard is that its php codes simplicity is sometimes easier then the over-engineered complexity you find in certain Java frameworks and applications. I'm not just trolling, i'm genuinly curious what makes php programmers use it. try to convince me to put it on my languages to dabble in and languages to learn more in depth lists.

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  • PHP & MySQL storing multiple values in a database.

    - by R.I.P.coalMINERS
    I'm basically a front end designer and new to PHP and MySQL but I want a user to be able to store multiple names and there meanings in a MySQL database table named names using PHP I will dynamically create form fields with JQuery every time a user clicks on a link so a user can enter 1 to 1,000,000 different names and there meanings which will be stored in a table called names. All I want to know is how can I store multiple names and there meanings in a database and then display them back to the user for them to edit or delete using PHP MySQL? I created the MySQL table already. CREATE TABLE names ( id INT UNSIGNED NOT NULL AUTO_INCREMENT, userID INT NOT NULL, name VARCHAR(255) NOT NULL, meaning VARCHAR(255) NOT NULL, PRIMARY KEY (id) ); Here is the HTML. <form method="post" action="index.php"> <ul> <li><label for="name">Name: </label><input type="text" name="name" id="name" /></li> <li><label for="meaning">Meaning: </label><input type="text" name="meaning" id="meaning" /></li> <li><input type="submit" name="submit" value="Save" /> <input type="hidden" name="submit" value="true" /></li> </ul> </form>

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  • Passing Javascript value to PHP Variable using ajax

    - by shels
    I am trying to use a Flash detection script to assess whether Flash Plugin is enabled in the user browser so that a different page loads. The Flash detection script is as follows, using jquery 1.8.2 and jquery.jqplugin 1.0.2 <script type="text/javascript" src="jquery-1.8.2.min.js"></script> <script type="text/javascript" src="jquery.jqplugin.1.0.2.min.js"></script> <script type="text/javascript"> $(document).ready(function() { $("#withflash").hide(); $("#noflash").hide(); if ($.browser.flash == true) $("#withflash").show (); else $("#noflash").show (); }); </script> <div id="withflash">Flash Supported</div> <div id="noflash">Flash Not Supported</div> I get the display that "Flash Supported" if Flash Plugin is present.. I need to capture the value whether flash plugin value is true in a php variable $hasFlashSupport as below: <?php echo " $hasFlashSupport"; exit; ?> I am aware that PHP is server based and Javascript is client based.. Hence Ajax would be a nice option to capture the javascript variable to my php variable. I am totally ignorant about Ajax syntax and how to achieve it. Request the experts here to help me out with the code on how this can be achieved... Thanking all of you in advance..

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  • Write transparent HTTP Proxy script in PHP

    - by Leo Izen
    Is there an easy forwarding/transparent php proxy script that I can host on my web server? These are my conditions: I'm using free web hosting, so I have pretty much no control over my machine. Otherwise I could use Perl's HTTP::Proxy module. This means no root password. It does run php though. I already have a server running on port 80. What I mean is I would like to put a php script as index.php on my server that will forward all requests. I don't want a script like PHProxy or Glype where I go to the site, then enter a URL. I want a server so I can enter proxy.example.com:80 in Firefox's or IE's or whatever's proxy settings and it will forward all requests to the server. Preferably (though not fatal if not possible) I would like for it to pass on the USER_AGENT environmental variable (That's the browser) instead of setting itself to be the USER_AGENT I can't start a new Daemon. My server won't allow it. Is there a script that will do this? If so, which?

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  • PHP site scheduling Java execution?

    - by obfuscation
    I'm trying to get started on combining my (slightly limited) PHP experience with my (better) Java experience, in a project where I need to allow uploads of Java source files to the server, which the server then executes Javac on to compile it. Then, at a set time (e.g. specified on upload) I need to run that once on the server, which will generate some database info for the PHP site to display. To describe my current programming abilities- I have made many desktop Java programs, and am confident in 'pure' Java, but so far have only undertaken a couple of PHP projects (including using the CodeIgniter framework). My motivation for using PHP as the frontend is because I know it is very fast, lightweight and I will be able to display the results I need very easily with it (simple DB readout). Ideally, the technology used should be able to be developed on a localhost (e.g. WAMP, Tomcat etc..) Is there any advice which you could give on what technology I should consider to use to bridge this gap, and what resources could help in using that technology? I have looked at a few, but have struggled to find documentation helping in achieving what I need.

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  • Pi help with Php (mass looping)

    - by Pieman
    My primary question is: Is this alot of loops? while ($decimals < 50000 and $remainder != "0") { $number = floor($remainder/$currentdivider); //Always round down! 10/3 =3, 10/7 = 1 $remainder = $remainder%$currentdivider; // 10%3 =1, 10%1 $thisnumber = $thisnumber . $number; $remainder = $remainder . 0; //10 $decimals += 1; } Or could I fit more into it? -without the server crashing/lagging. I'm just wondering, Also is there a more effiecent way of doing the above? (e.g. finidng out that 1/3 = 0.3 to 50,000 decimals.) Finally: I'm doing this for a pi formulae the (1 - 1/3 + 1/5 - 1/7 etc.) one, And i'm wondering if there is a better one. (In php) I have found one that finds pi to 2000 in 4 seconds. But thats not what I want. I want an infinite series that converges closer to Pi so every refresh, users can view it getting closer... see: http://zombiewrath.com/pi.php (Old one) and 'zombiewrath.com/superpi.php' (Newer one) But obv. converging using the above formulae takes ALONG time. Is there any other 'loop' like Pi formulaes (workable in php) that converge faster? Thanks alot...

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  • PHP Fix Warning: Cannot modify header information - headers already sent...

    - by Storm Kiernan
    Warning: Cannot modify header information - headers already sent by (output started at /home/blocexco/public_html/homepage.php:73) in /home/blocexco/public_html/classes/mysql/mysql.security.php on line 99 This error is repeated a second time for mysql.security.php on line 100. homepage:73 <div class="login"> <?php require_once 'login.php'; ?> </div> mysql.security.php: 99-100 setcookie('username', "", time() - (60 * 60 * 24 * 365)); setcookie('password', "", time() - (60 * 60 * 24 * 365)); I know this isn't a "BOM" issue as I've read about. There is output before and after my calls to header() and setcookie() functions - this is necessary since the homepage includes a php file which then injects the right login or logout form. I've heard about using ob_start() at the beginning of content, but that's not a very specific instruction...I tried placing it at the beginning of homepage.php (just before the html tag) and that didn't fix anything. I'm new to PHP (a few days in, and new to web-app dev in general). To be honest, it blows my mind that I can't just change which page I am on, via php without bending over backwards...

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  • Error while saving csv file generated by PHP

    - by user1667374
    I have created below script which is saving the csv file in the same path of this script but when I am saving it to different directory, it gives me error. Can somebody please help me on this? This is the error: Warning: fopen(/store/secure/mas/) [function.fopen]: failed to open stream: No such file or directory in /getdetails.php on line 15 Warning: fputs(): supplied argument is not a valid stream resource in /getdetails.php on line 36 Warning: fclose(): supplied argument is not a valid stream resource in /getdetails.php on line 39 This is the script: <?php $MYSQL_HOST="localhost"; $MYSQL_USERNAME="***"; $MYSQL_PASSWORD="***"; $MYSQL_DATABASE="shop"; $MYSQL_TABLE="ds_orders"; mysql_connect( "$MYSQL_HOST", "$MYSQL_USERNAME", "$MYSQL_PASSWORD" ) or die( mysql_error( ) ); mysql_select_db( "$MYSQL_DATABASE") or die( mysql_error( $conn ) ); $filename="Order_Details"; $directory = "/store/secure/mas/"; $csv_filename = $filename.".csv"; $fd = fopen ( "$directory" . $cvs_filename, "w"); $today="2009-03-17"; $disp_date="05122008"; $sql = "SELECT * FROM $MYSQL_TABLE where cDate='$today'"; $result=mysql_query($sql); $rows=mysql_num_rows($result); echo $rows; if(mysql_num_rows($result)>0){ $fileContent="Record ID,Discount Percent\n"; while($data=mysql_fetch_array($result)) { $fileContent.= "".$data['oID'].",".$data['discount']."\n"; } $fileContent=str_replace("\n\n","\n",$fileContent); fputs($fd, $fileContent); } fclose($fd); ?>

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  • Ajax Code to run PHP query After Facebook Like Button is Clicked

    - by John
    I have the PHP below on a file called fblike.php. On another file, I have the Facebook Like button. The Like button functions. I would like to run the code below when the Facebook Like button is clicked. I know that FB.Event.subscribe('edge.create', function(response) {} is supposed to run whenever the Like button is clicked. I know that I am probably supposed to use Javascript and maybe Ajax to cause the PHP on fblike.php to run. But after multiple tries, I can't get it to work. What is the specific Ajax code that I could include within the Facebook Event? Do I need to do anything to the Like button code to allow the Facebook Event to work? $submissionid = $_POST['submissionid']; $uid = $_POST['uid']; mysql_connect("server", "username", "password") or die(mysql_error()); mysql_select_db("database") or die(mysql_error()); $q = "INSERT INTO fblikes VALUES (NULL, '$submissionid', '$uid', NULL)"; $r = mysql_query($q); if($r) { echo "Success!"; } elseif(!$r) { echo "Failed!"; }

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  • How would one dynamically load Javascript that has been parsed as PHP?

    - by beatsforthemind
    I am looking to dynamically load javascript that has been parsed as PHP so that I will be able to pass PHP variables to javascript, and then load this file into the primary PHP document. I have a document called myscript.js.php that includes the javascript and PHP. I attempted to load it into the primary document using jQuery's getScript like this: $.getScript("myscript.js.php", function() { alert('loaded script.'); }); This attempt failed - I am assuming because of the .php extension on the file. Is there anyway to dynamically load javascript that includes PHP? I have a few session variables that I am looking to pass through javascript that will be updated frequently, creating a need for the javascript to be reloaded.

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  • Is ASP.NET MVC completely (and exclusively) based on conventions?

    - by Mike Valeriano
    --TL;DR Is there a "Hello World!" ASP.NET MVC tutorial out there that doesn't rely on conventions and "stock" projects? Is it even possible to take advantage of the technology without reusing the default file structure, and start from a single "hello_world.asp" file or something (like in PHP)? Am I completely mistaken and I should be looking somewhere else, maybe this? I'm interested in the MVC framework, not Web Forms --Background I've played a bit with PHP in the past, just for fun, and now I'm back to it since web development became relevant for me once again. I'm no professional, but I try to gain as much knowledge and control over the technology I'm working with as possible. I'm using Visual Studio 2012 for C# - my "desktop" language of choice - and since I got the Professional Edition from Dreamspark, the Web Development Tools are available, including ASP.NET MVC 4. I won't touch Web Forms, but the MVC Framework got my attention because the MVC pattern is something I can really relate to, since it provides the control I want but... not quite. Learning PHP was easy - and right form the start I could just create a "hello_world.php" file and just do something like this for immediate results: <!-- file: hello_world.php --> <?php> echo "Hello World!"; <?> But I couldn't find a single ASP.NET (MVC) tutorial out there (I'll be sure to buy one of the upcoming MVC 4 books, only a month away or so) that would start like that. They all start with a sample project, building up knowledge from the basics and heavily using conventions as they go along. Which is fine, I suppose, but it's now the best way for me to learn things. Even the "Empty" project template for a new ASP.NET MVC 4 Application in VS2012 is not empty at all: several files and folders are created for you - much like a new C# desktop application project, but with C# I can in fact start from scratch, creating the project structure myself. It is not the case with PHP: I can choose from a plethora of different MVC frameworks I can just create my own framework I can just skip frameworks altogether, and toss random PHP along with my HTML on a single file and make it work I understand the framework needs to establish some rules, but what if I just want to create a single page website with some C# logic behind it? Do I really need to create a whole bloat of files and folders for the sake of convention? Also, please understand that I haven't gotten far on any of those tutorials mainly because of this reason, but, if that's the only way to do it, I'll go for it using one of the books I've mentioned before. This is my first contact with ASP.NET but from the few comparisons I've read, I believe I should stay the hell away from Web Forms. Thank you. (Please forgive the broken English - it is not my primary language.)

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