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  • SIMPLE BASH Programming.

    - by atif089
    I am a newbie to BASH so please dont mind my stupid questions because I am not able to get any good sources to learn that. I want to create a script to display filename and its size. This is what the code is like filename=$1 if [ -f $filename ]; then filesize=`du -b $1` echo "The name of file is $1" echo "Its size is $filesize" else echo "The file specified doesnot exists" fi The output is like this $ ./filesize.sh aa The name of file is aa Its size is 88 aa But in the last line I dont want to show the name of the file. How do I do that ? I want to do the same thing using wc as well.

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  • Custom installation directories

    - by Alex Farber
    Let's say I am writing installation script for the program which contains executable file and shared library. By default, this script places executable to /usr/local/bin, and shared library to /usr/local/lib. In this case my program may be executed by any user by typing its name in the command line. Suppose that user selects custom installation directory, like ~/myprogram/. Is it user's responsibility to ensure that my program may be executed, or my installation script must do this?

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  • Regex for capturing number in brackets

    - by neversaint
    I have a lines like this NF419andZNF773 (e=10^-92,). ZNF571 (e=2 10^-14,) What's the regex for extracting the results above so that it gives NF419andZNF773 - 10^-92 ZNF571 - 2 10^-14 I tried this but fail. $line =~ /(\w+)\s\(e=\s(.*),\)/; print "$1 - $2\n";

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  • Invoking external shell application through RubyCocoa

    - by Shyam
    Hi, How would I invoke an external application through the RubyCocoa bridge? I read something about NSTask, yet I have no idea how this should be translated in RubyCocoa. My goal is to have an IB_action to trigger a method which will run a terminal application with some parameters, i.e. ls -p $mydir, where mydir comes from an IB_outlet such as an Textfield. Any directions or help would be greatly appreciated!

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  • Redirect PHP-Shell-Script output

    - by Corelgott
    Hi Folks, i have got a php-script foo.php #!/usr/bin/php -c /etc/php5/cli/php.ini -q <?php echo 'hello'; // & do some stuff ?> I call this script not wrapped by a sh-script but using it directly in a cron job. To get rid of it's output i normally would just create a sh-file which calls /usr/bin/php -c /etc/php5/cli/php.ini -q foo.php > /dev/null 2 > /dev/null now i'd like to do this in the interpreter-declaration of the php file it self... so i am looking for the syntax for: #!/usr/bin/php -args [file's content] > /redirect 2 > /redirect i have kind of a hard time googleing for it... so if anybody could point me into the right direction i would really appreciate it! Thx in advance Corelgott

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  • Can I use POSIX signals in my Perl program to create event-driven programming?

    - by Shiftbit
    Is there any POSIX signals that I could utilize in my Perl program to create event-driven programming? Currently, I have multi-process program that is able to cross communicate but my parent thread is only able to listen to listen at one child at a time. foreach (@proc) { sysread(${$_}{'read'}, my $line, 100); #problem here chomp($line); print "Parent hears: $line\n"; } The problem is that the parent sits in a continual wait state until it receives it a signal from the first child before it can continue on. I am relying on 'pipe' for my intercommunication. My current solution is very similar to: http://stackoverflow.com/questions/2558098/how-can-i-use-pipe-to-facilitate-interprocess-communication-in-perl If possible I would like to rely on a $SIG{...} event or any non-CPAN solution. Update: As Jonathan Leffler mentioned, kill can be used to send a signal: kill USR1 = $$; # send myself a SIGUSR1 My solution will be to send a USR1 signal to my child process. This event tells the parent to listen to the particular child. child: kill USR1 => $parentPID if($customEvent); syswrite($parentPipe, $msg, $buffer); #select $parentPipe; print $parentPipe $msg; parent: $SIG{USR1} = { #get child pid? sysread($array[$pid]{'childPipe'}, $msg, $buffer); }; But how do I get my the source/child pid that signaled the parent? Have the child Identify itself in its message. What happens if two children signal USR1 at the same time?

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  • Viewing an EXE File

    - by Steve
    I was attempting to install an exe that requires a serial number before the install, which the vendor has not provided to us yet. This got my wheels turning about whether there is any information that can be gained from viewing an exe using a hex editor/VI/etc? Using VI to view an exe, I can see some sections of plain text, but it is difficult to determine what it refers to without any context around it. Is it possible to determine any information by reading an exe? Thanks

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  • Logging from multiple apps/processes to a single log file

    - by Andrew
    Our app servers (weblogic) all use log4j to log to the same file on a network share. On top of this we have all web apps in a managed server logging errors to a common error.log. I can't imagine this is a good idea but wanted to hear from some pros. I know that each web app has its own classloader, so any thread synchronization only occurs within the app. So what happens when multiple processes start converging on a single log file? Can we expect interspersed log statements? Performance problems? What about multiple web apps logging to a common log file? The environment is Solaris.

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  • awk output to a file

    - by Harish
    I need help in moving the contents printed by awk to a text file. THis is a continuation of previous quesion I have to move all the contents into the same file so it is appending. To be specific nawk -v file="$FILE" 'BEGIN{RS=";"} /select/{ gsub(/.*select/,"select");gsub(/\n+/,"");print file,$0;} /update/{ gsub(/.*update/,"update");gsub(/\n+/,"");print file,$0;} /insert/{ gsub(/.*insert/,"insert");gsub(/\n+/,"");print file,$0;} ' "$FILE" How to get the print results to a text file appended one after the other in the same file?

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  • Unknown error in Producer/Consumer program, believe it to be an infinite loop.

    - by ray2k
    Hello, I am writing a program that is solving the producer/consumer problem, specifically the bounded-buffer version(i believe they mean the same thing). The producer will be generating x number of random numbers, where x is a command line parameter to my program. At the current moment, I believe my program is entering an infinite loop, but I'm not sure why it is occurring. I believe I am executing the semaphores correctly. You compile it like this: gcc -o prodcon prodcon.cpp -lpthread -lrt Then to run, ./prodcon 100(the number of randum nums to produce) This is my code. typedef int buffer_item; #include <stdlib.h> #include <stdio.h> #include <pthread.h> #include <semaphore.h> #include <unistd.h> #define BUFF_SIZE 10 #define RAND_DIVISOR 100000000 #define TRUE 1 //two threads void *Producer(void *param); void *Consumer(void *param); int insert_item(buffer_item item); int remove_item(buffer_item *item); int returnRandom(); //the global semaphores sem_t empty, full, mutex; //the buffer buffer_item buf[BUFF_SIZE]; //buffer counter int counter; //number of random numbers to produce int numRand; int main(int argc, char** argv) { /* thread ids and attributes */ pthread_t pid, cid; pthread_attr_t attr; pthread_attr_init(&attr); pthread_attr_setscope(&attr, PTHREAD_SCOPE_SYSTEM); numRand = atoi(argv[1]); sem_init(&empty,0,BUFF_SIZE); sem_init(&full,0,0); sem_init(&mutex,0,0); printf("main started\n"); pthread_create(&pid, &attr, Producer, NULL); pthread_create(&cid, &attr, Consumer, NULL); printf("main gets here"); pthread_join(pid, NULL); pthread_join(cid, NULL); printf("main done\n"); return 0; } //generates a randum number between 1 and 100 int returnRandom() { int num; srand(time(NULL)); num = rand() % 100 + 1; return num; } //begin producing items void *Producer(void *param) { buffer_item item; int i; for(i = 0; i < numRand; i++) { //sleep for a random period of time int rNum = rand() / RAND_DIVISOR; sleep(rNum); //generate a random number item = returnRandom(); //acquire the empty lock sem_wait(&empty); //acquire the mutex lock sem_wait(&mutex); if(insert_item(item)) { fprintf(stderr, " Producer report error condition\n"); } else { printf("producer produced %d\n", item); } /* release the mutex lock */ sem_post(&mutex); /* signal full */ sem_post(&full); } return NULL; } /* Consumer Thread */ void *Consumer(void *param) { buffer_item item; int i; for(i = 0; i < numRand; i++) { /* sleep for a random period of time */ int rNum = rand() / RAND_DIVISOR; sleep(rNum); /* aquire the full lock */ sem_wait(&full); /* aquire the mutex lock */ sem_wait(&mutex); if(remove_item(&item)) { fprintf(stderr, "Consumer report error condition\n"); } else { printf("consumer consumed %d\n", item); } /* release the mutex lock */ sem_post(&mutex); /* signal empty */ sem_post(&empty); } return NULL; } /* Add an item to the buffer */ int insert_item(buffer_item item) { /* When the buffer is not full add the item and increment the counter*/ if(counter < BUFF_SIZE) { buf[counter] = item; counter++; return 0; } else { /* Error the buffer is full */ return -1; } } /* Remove an item from the buffer */ int remove_item(buffer_item *item) { /* When the buffer is not empty remove the item and decrement the counter */ if(counter > 0) { *item = buf[(counter-1)]; counter--; return 0; } else { /* Error buffer empty */ return -1; } }

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  • Too many open files in one of my java routine.

    - by Irfan Zulfiqar
    I have a multithreaded code that has to generated a set of objects and write them to a file. When I run it I sometime get "Too many open files" message in Exception. I have checked the code to make sure that all the file streams are being closed properly. Here is the stack trace. When I do ulimit -a, open files allowed is set to 1024. We think increasing this number is not a viable option / solution. [java] java.io.FileNotFoundException: /export/event_1_0.dtd (Too many open files) [java] at java.io.FileInputStream.open(Native Method) [java] at java.io.FileInputStream.<init>(FileInputStream.java:106) [java] at java.io.FileInputStream.<init>(FileInputStream.java:66) [java] at sun.net.www.protocol.file.FileURLConnection.connect(FileURLConnection.java:70) [java] at sun.net.www.protocol.file.FileURLConnection.getInputStream(FileURLConnection.java:161) [java] at java.net.URL.openStream(URL.java:1010) Now what we have identified so far by looking closely at the list of open files is that the VM is opening same class file multiple times. /export/BaseEvent.class 236 /export/EventType1BaseEvent.class 60 /export/EventType2BaseEvent.class 48 /export/EventType2.class 30 /export/EventType1.class 14 Where BaseEvent is partent of all the classes and EventType1 ant EventType2 inherits EventType1BaseEvent and EventType2BaseEvent respectively. Why would a class loader load the same class file 200+ times. It seems it is opening up the base class as many time it create any child instance. Is this normal? Can it be handler any other way apart from increasing the number of open files?

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  • Using Regex groups in bash

    - by AlexeyMK
    Greetings, I've got a directory with a list of pdfs in it: file1.pdf, file2.pdf, morestuff.pdf ... etc. I want to convert these pdfs to pngs, ie file1.png, file2.png, morestuff.png ... etc. The basic command is, convert from to, But I'm having trouble getting convert to rename to the same file name. The obvious 'I wish it worked this way' is convert *.pdf *.png But clearly that doesn't work. My thought process is that I should utilize regular expression grouping here, to say somethink like convert (*).pdf %1.png but that clearly isn't the right syntax. I'm wondering what the correct syntax is, and whether there's a better approach (that doesn't require jumping into perl or python) that I'm ignoring. Thanks!

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  • Socket read() hangs for a while when there is no data to read.

    - by janesconference
    Hi' I'm writing a simple http port forwarder. I read data from port 80, and pass the data to my lighttpd server, on port 8080. As long as I write() data on the socket on port 8080 (forwarding the request) there's no problem, but when I read() data from that socket (forwarding the response), the last read() hangs a lot (about 1 or 2 seconds) before realizing there's no more data and returning 0. I tried to set the socket to non-blocking, but this doesn't work, as sometimes it returns EWOULDBLOCKING even if there's some data left (lighttpd + cgi can be quite slow). I tried to set a timeout with select(), but, as above, a slow cgi could timeout the socket when there's actually some data to transmit. How would you do?

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  • In terminal, merging multiple folders into one.

    - by Josh Pinter
    I have a backup directory created by WDBackup (western digital external HD backup util) that contains a directory for each day that it backed up and the incremental contents of just what was backed up. So the hierarchy looks like this: 20100101 My Documents Letter1.doc My Music Best Songs Every First Songs.mp3 My song.mp3 # modified 20100101 20100102 My Documents Important Docs Taxes.doc My Music My Song.mp3 # modified 20100102 ...etc... Only what has changed is backed up and the first backup that was ever made contains all the files selected for backup. What I'm trying to do now is incrementally copy, while keeping the folder structure, from oldest to newest, each of these dated folders into a 'merged' folder so that it overrides the older content and keeps the new stuff. As an example, if just using these two example folders, the final merged folder would look like this: Merged My Documents Important Docs Taxes.doc Letter1.doc My Music Best Songs Every First Songs.mp3 My Song.mp3 # modified 20100102 Hope that makes sense. Thanks, Josh

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  • git crlf configuration in mixed environment

    - by Jonas Byström
    I'm running a mixed environment, and keep a central, bare repository where I pull and push most of my stuff. This centralized repository runs on Linux, and I check out to Windows XP/7, Mac and Linux. In all repositories I put the following line in my .git/config: [core] autocrlf = true I don't have the flag safecrlf=true anywhere. First time when I modify stuff on my one Windows machine (XP) there is no problem and when I look at the diff, it looks fine. But when I do the same on the other Windows machine (7), all lines are shown as changed but local line endings are \r\n as expected (when checked in a hex editor). The same applies to a MacOSX can. Sometimes I get the feeling that the different systems wrestle on line endings, but I can't be sure (I'm loosing track of all the times I change specific files). I didn't use to have the autocrlf set, but set the flag many months back. Could that be causing my current problems? Do I need to clone everything again to loose some old baggage? Or are there other things that needs configuring too? I tried git checkout -- . about a million times, but with no success.

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  • aumix problem- how can I make the changes permenantly

    - by thillai-selvan
    Hai every one. How can I make the changes in the aumix permanently? I am running the aumix application using the following command thinapplaunch aumix. I am increasing the volume manually. I saved and quit. I am again launching that application using the same command. thinapplaunch aumix Now all the changes I made is still there. All the volumes are full. But when I logged out and login again the changes is not exists. All the volumes are not full. How can I make the changes permanently? Any help much appreciated. Thanks in Advance!!!

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  • Catching / blocking SIGINT during system call

    - by danben
    I've written a web crawler that I'd like to be able to stop via the keyboard. I don't want the program to die when I interrupt it; it needs to flush its data to disk first. I also don't want to catch KeyboardInterruptedException, because the persistent data could be in an inconsistent state. My current solution is to define a signal handler that catches SIGINT and sets a flag; each iteration of the main loop checks this flag before processing the next url. However, I've found that if the system happens to be executing socket.recv() when I send the interrupt, I get this: ^C Interrupted; stopping... // indicates my interrupt handler ran Traceback (most recent call last): File "crawler_test.py", line 154, in <module> main() ... File "/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/socket.py", line 397, in readline data = recv(1) socket.error: [Errno 4] Interrupted system call and the process exits completely. Why does this happen? Is there a way I can prevent the interrupt from affecting the system call?

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  • Bash: using commands as parameters (specifically cd, dirname and find)

    - by sixtyfootersdude
    This command and output: % find . -name file.xml 2> /dev/null ./a/d/file.xml % So this command and output: % dirname `find . -name file.xml 2> /dev/null` ./a/d % So you would expect that this command: % cd `dirname `find . -name file.xml 2> /dev/null`` Would change the current directory to ./a/d. Strangely this does not work. When I type cd ./a/d. The directory change works. However I cannot find out why the above does not work...

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  • Search and replace

    - by zx
    Hi, I have a really large SQL dump around 400MB. It's in the following format, "INSERT INTO user VALUES('USERID', 'USERNAME', 'PASSWORD', '0', '0', 'EMAIL', 'GENDER', 'BIRTHDAY', '182', '13', '640', 'Married', 'Straight', '', 'Yes', 'Yes', '1146411153', '1216452123', '1149440844', '0', picture', '1', '0', '0', 'zip', '0', '', '0', '', '', '0')" Is there anyway I can just get the email and password out from that, I want to import the users into another table. Anyone know how I can do this and just get email-password stripped out from that content? Thank you in advance

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