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  • Access PHP var from external javascript file

    - by FFish
    I can access a PHP var with Javascript like this: <?php $fruit = "apple"; $color = "red"; ?> <script type="text/javascript"> alert("fruit: " + "<?php echo $fruit; ?>"); // or shortcut "<?= $fruit ?>" </script> But what if I want to use an external JS file: <script type="text/javascript" src="externaljs.js"></script> externaljs.js: alert("color: " + "<?php echo $color; ?>");

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  • Access control of page in php

    - by garcon1986
    Hello, I want to control the access in php website. I have a solution right now with switch case. <?php $obj = $_GET['obj']; switch ($obj) { case a: include ('a.php'); break; default: include ('f.php'); } ?> But when i have so many pages, it becomes difficult to manage them. Do you have better solutions? Right now, i develop the application using php4. And i want to use php5. Do you have any suggestions when i develop it using php5? Thanks

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  • iPhone: Try to send html code to a php script (but fail)

    - by Marc-André Weibezahn
    Hello all, I am trying this for an iPhone app in Xcode: create html code for a website on the fly sending it to a php-script and getting the response with this code: NSError * error = [[[NSError alloc]init]autorelease]; NSURL * phpURL = [NSURL URLWithString: @"http://www.mydomain.com/myscript.php?mywebsite= (...websitestring...) ];NSString * myResponse = [NSString stringWithContentsOfURL:phpURL encoding:NSUTF8StringEncoding error:&error]; It does not work. It should not be a problem of the php code because when I replace the websitestring which contains the html code with "hello" or something, this is accepted. (the script then creates a file "test.html" with the content I sent.) But when I put html code in it, I always get the error: Error Domain=NSCocoaErrorDomain Code=256 "The operation couldn’t be completed. (Cocoa error 256.)" UserInfo=0x322ec10 {} It seems that there are some things to consider when sending code to php? Thanks in advance!

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  • got undefined variable in php code

    - by Newbie New
    I got a error message when I run my php however the result is come out this is my code function cart() { foreach($_SESSION as $name => $value) { if ($value>0) { if (substr($name, 0, 5) == 'cart_'){ $id = substr($name, 5, (strlen($name)-5)); $get = mysql_query('SELECT id, name, price FROM products WHERE id=' .mysql_real_escape_string((int)$id)); while ($get_row = mysql_fetch_assoc($get)){ $sub = $get_row['price'] * $value; echo $get_row['name'].' x '.$value.' @ &pound'.number_format($get_row['price'], 2).' = &pound'.number_format($sub, 2).' <a href="cart.php?remove='.$id.'">[-]</a> <a href="cart.php?add='.$id.'">[+]</a> <a href="cart.php?delete='.$id.'">[Delete]</a><br />' ; } } $total += $sub; } } echo $total; } ?> I got a error message Notice: Undefined variable: total in C:\xampp\htdocs\shoppingcart\cart.php on line 54 which line 54 is echo $total; what's wrong with my code?? I think I have defined the code in $total += $sub; thanks for helping me :)

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  • 3 small PHP errors I cannot decipher

    - by Dave
    *Notice: Use of undefined constant _ - assumed '_' in /.../uploader.php on line 45* Line 45 $newname = str_replace(array(' ', '&'), array('_', 'and'), trim( strip_tags( $_POST['name'] ) ) ) . _ . $formKey->generateKey() . '_' . time() . '.jpg'; Notice: Undefined index: approve in /.../uploader.php on line 81 Line 81 - the second last line here $query = sprintf("INSERT INTO `$db_name`.`the_table` (`id` , `name` , `photo` , `email` , `date` , `code` , `subscribe` , `approve` , `created` ) VALUES ( NULL , '%s', '%s', '%s', '%s', '%s', '%s', '1', CURRENT_TIMESTAMP );", mysql_real_escape_string($_POST['name']), mysql_real_escape_string($newname), mysql_real_escape_string($_POST['email']), mysql_real_escape_string($date), mysql_real_escape_string($_POST['code']), mysql_real_escape_string($subscribe), mysql_real_escape_string($_POST['approve']) ); Warning: Cannot modify header information - headers already sent by (output started at /.../uploader.php:45) in/.../uploader.php on line 102 Line 45 $newname = str_replace(array(' ', '&'), array('_', 'and'), trim( strip_tags( $_POST['name'] ) ) ) . _ . $formKey->generateKey() . '_' . time() . '.jpg'; Line 102 - the third line here if ($success == 'Done') { $page = 'uploader'; header('Location: ./thanks.php'); } else { echo "error"; }

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  • How to use the php fopen() correctly

    - by Jacksta
    I am learning php, trying to use the fopen() function. The php file I am coding is in this directory /domains/xxxxx.com.au/public_html/phpfile.php What path do I specify for the file to be opened, the example I am looking at is based on a server on a pc where this is the file path $filename = "c:/newfile.txt"; not an online server.

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  • PHP Echo current filename without extension

    - by Christian Nikkanen
    I'm working on a very simple homemade CMS that simply uses a rich text editor and database to save the website contents and displays them to visitors. Heres the save.php that saves it: <?php include 'mysqlconnection.php'; mysql_query("UPDATE Content SET Content='$_POST[edit]' WHERE PageName='$_POST[PageName]'"); mysql_close($con); ?> <?php header('Location:http://xxx.com/Kayttoliittyma'); ?> It just saves it to the database. The pagename part is the part where I need to echo the filename without the extension. It would echo to the forms hidden field. But how?

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  • Pass a variable from javascript to php in the same session OnClickFunction

    - by MickyScion
    I was seeing through stackoverflow the solutions for this kind of problems but any of them are executing the code of javascript in the same session...please i want some help with this...i have this in my session <script> function show_alert() { var ProdAntes = document.getElementById("productoseleccionado").value; var CantAntes = document.getElementById("cantidadantes").value; var PrecAntes = document.getElementById("precioantes").value; var FecAntes = document.getElementById("fechaantes").value; var ProdAhora = document.getElementById("SoyaProductorProduccionProducto").value; var CantAhora = document.getElementById("SoyaProductorProduccionCantidadtm").value; var PrecAhora = document.getElementById("SoyaProductorProduccionPreciodolar").value; var FecAhora = document.getElementById("select_date").value; } </script> and in my html stuff i have this <?php echo $this->Form->create('SoyaProductorProduccion');?> <fieldset> <?php echo $this->Form->hidden('id', array('value' => $this->data['SoyaProductorProduccion']['id'])); echo $this->Form->input('operacion', array('type' => 'hidden', 'value'=>'Produccion')); //-------------------------------------------------------------- $productoseleccionado = $this->data['SoyaProductorProduccion']['producto']; echo $this->Form->input('productoseleccionado', array('type' => 'hidden','style'=>'width:500px; height:30px;','id' => 'productoseleccionado' , 'value' => $productoseleccionado)); echo $this->Form->input('producto', array( 'options' => array( $productoseleccionado => $productoseleccionado, 'Torta solvente de soya' => 'Torta solvente de soya', 'Torta solvente de girasol' => 'Torta solvente de girasol', 'Harina integral de soya' => 'Harina integral de soya', 'Harina de girasol' => 'Harina de girasol', 'Cascarilla de soya' => 'Cascarilla de soya', 'Cascarilla de girasol' => 'Cascarilla de girasol', 'Aceite de soya refinado' => 'Aceite de soya refinado', 'Aceite de soya crudo' => 'Aceite de soya crudo', 'Aceite de girasol refinado' => 'Aceite de girasol refinado', 'Aceite de girasol crudo' => 'Aceite de girasol crudo', ),'label'=>'Tipo de Producto' )); foreach ($soyacambiodolares as $soyacambiodolar): $dolar=$soyacambiodolar['SoyaCambioDolar']['cambio']; endforeach; echo $this->Form->input('cambio', array('type' => 'hidden','value' => $dolar)); //----------------------------------------------------------------------------- $cantidadantes = $this->data['SoyaProductorProduccion']['cantidadtm']; echo $this->Form->input('cantidadantes', array('type' => 'hidden','style'=>'width:500px; height:30px;', 'value' => $cantidadantes,'id' => 'cantidadantes')); echo $this->Form->input('cantidadtm', array('label' => 'Cantidad en tonelada(s) métrica(s) del producto (TM)','style'=>'width:500px; height:30px;')); //----------------------------------------------------------------------------- $precioantes = $this->data['SoyaProductorProduccion']['preciodolar']; echo $this->Form->input('precioantes', array('type' => 'hidden','style'=>'width:500px; height:30px;', 'value' => $precioantes,'id' => 'precioantes')); echo $this->Form->input('preciodolar', array('label' => 'Precio en Dolares Americanos por tonelada métrica (TM / $us)','style'=>'width:500px; height:30px;')); //----------------------------------------------------------------------------- ?> <table style="width: 600px"> <tr> <td > <?php //---------------------------------------------------------------- $fechaantes = $this->data['SoyaProductorProduccion']['fecharegistro']; echo $this->Form->input('fechaantes', array('type' => 'hidden','style'=>'width:500px; height:30px;', 'value' => $fechaantes, 'id' => 'fechaantes')); //---------------------------------------------------------------- echo $this->Form->input("fecharegistro", array( 'label' => '<strong>Periodo al que corresponde la declaración</strong>', 'type' => 'text', 'style' => 'width: 110px', 'class' => 'fl tal vat w300p', 'error' => false , 'id' => 'select_date')); ?> <?php echo $this->Html->div('datepicker_img w100p fl pl460p pa', $this->Html->image('datepicker_calendar_icon.gif'),array('id' => 'datepicker_img')); ?> <?php echo $this->Html->div('datepicker fl pl460p pa', ' ' ,array('id' => 'datepicker')); ?> </td> </tr> </table> <?php echo $this->Form->submit('Modificar Existencia', array('class' => 'form-submit', 'title' => 'Presione aqui para agregar datos', 'onclick' => 'return show_alert();')); ?> </fieldset> <?php echo $this->Form->end(); ?> my function is ok but i want these: when i click the submit button i want to compare wich field had been changed, and i want to create a chain of detailed changes like "change in the field 1, change in the fiel 2.--" and so on...and this has to be saved in my database so i have to pass to a variable in my php before saving...thanks!

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  • Visual PHP GUI IDE

    - by Joshua
    Does anybody know of a reliable, well-made tool for creating standalone desktop applications complete with GUI, using just PHP, or primarily PHP? I enjoy the R.A.D. and many other aspects of PHP and would like to use it for some non server/client projects.

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  • PHP Dropdown menu [closed]

    - by rShetty
    <br><h2>Select a Tag</h2></br> <?php $con = mysql_connect("localhost","root",""); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("portal", $con); $query = "SELECT tag_name FROM tags"; $result = mysql_query($query); ?> <select name="tag_name" id="abc"> <option size=30 selected>Select</option> <?php while($array = mysql_fetch_assoc($result)){ ?> <option value ="<?php echo $array['tag_name'];?>"><?php echo $array['tag_name'];?> </option> <?php } ?> </select> <br><br> This is a snippet of code for getting the dropdown menu in the page. I have a database named portal and table named tags with tag_name as the attribute. Do help me to find the error in the program. I am not getting the tag_names in the dropdown menu

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  • What is wrong with this php loop?

    - by Mark R
    I made a loop but it doesn't work. here's what I did: <?php if(is_tree('4')) { ?> <?php $show_after_p = 2; $content = apply_filters('the_content', $post->post_content); if(substr_count($content, '<p>') > $show_after_p) { $contents = explode("</p>", $content); $p_count = 1; foreach($contents as $content) { echo $content; if($p_count == $show_after_p) { ?> YOUR AD CODE GOES HERE < ? } echo "</p>"; $p_count++; } } ?> <?php else : ?> <?php the_content('<p class="serif">Read the rest of this page &raquo;</p>'); ?> <?php endif; } ?> I need to make it work but don't know how. I'm guessing it's a simple syntax error I'm not seeing?

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  • Easiest way to submit data via PHP?

    - by Abijah
    I'm new to PHP, and have spent 10 hours trying to figure this problem out. The goal is to take all data entered into this order form, and send it to my email via PHP. I have 2 questions: 1. I can get PHP to send data from a single menu item (example: Mexican Tortas), but how do I get PHP to send data from multiple items (example: Mexican Tortas, Fish Sandwich and Hamburger)? 2. How do I tell PHP to not send data from menu items that don't have the "How Many?" or "Customize It?" text fields filled out? If you could provide a super simple example (or a link to a learning resource) I would really appreciate it. Thank you, Abijah PHP <?php if(isset($_POST['submit'])) { $to = "[email protected]"; $subject = "New Order"; $name_field = $_POST['name']; $phone_field = $_POST['phone']; $item = $_POST['item']; $quantity = $_POST['quantity']; $customize = $_POST['customize']; } $body = "Name: $name_field\nPhone: $phone_field\n\nItem: $item\nQuantity: $quantity\nCustomize: $customize"; echo "Data has been submitted to $to!"; mail($to, $subject, $body); ?> HTML <form action="neworder.php" method="POST"> <div class ="item"> <img style="float:left; margin-right:15px; border:1px Solid #000; width:200px; height:155px;" src="images/mexicantortas.jpg"> <h1>Mexican Torta - $8.50</h1> <input name="item" type="hidden" value="Mexican Torta"/> <h2>How Many? <font color="#999999">Ex: 1, 2, 3...?</font></h2> <input name="quantity" type="text"/> <h3>Customize It? <font color="#999999">Ex: No Lettuce, Extra Cheese...</font></h3> <textarea name="customize"/></textarea> </div><!-- ITEM_LEFT --> <div class ="item"> <img style="float:left; margin-right:15px; border:1px Solid #000; width:200px; height:155px;" src="images/fishsandwich.jpg"> <h1>Fish Sandwich - $8.50</h1> <input name="item" type="hidden" value="Fish Sandwich"/> <h2>How Many? <font color="#999999">Ex: 1, 2, 3...?</font></h2> <input name="quantity" type="text"/> <h3>Customize It? <font color="#999999">Ex: No Lettuce, Extra Cheese...</font></h3> <textarea name="customize"/></textarea> </div><!-- ITEM_LEFT --> <div class ="item"> <img style="float:left; margin-right:15px; border:1px Solid #000; width:200px; height:155px;" src="images/hamburgers.jpg"> <h1>Hamburger w/ Fries - $7.00</h1> <input name="item" type="hidden" value="Fish Sandwich"/> <h2>How Many? <font color="#999999">Ex: 1, 2, 3...?</font></h2> <input name="quantity" type="text"/> <h3>Customize It? <font color="#999999">Ex: No Lettuce, Extra Cheese...</font></h3> <textarea name="customize"/></textarea> </div><!-- ITEM_LEFT --> <div class="horizontal_form"> <div class="form"> <h2>Place Your Order Now: <font size="3"><font color="#037B41">Fill in the form below, and we'll call you when your food is ready to be picked up...</font></font></h2> <p class="name"> <input type="text" name="name" id="name" style="text-align:center;" onClick="this.value='';" value="Enter your name"/> </p> <p class="phone"> <input type="text" name="phone" id="phone" style="text-align:center;" onClick="this.value='';" value="Enter your phone #"/> </p> <p class="submit"> <input type="submit" value="Place Order" name="submit"/> </p> </div><!-- FORM --> </div><!-- HORIZONTAL_FORM --> </form>

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  • What is PHP like as a programming language?

    - by seanlinmt
    I am not really familiar with PHP, but I get the impression that it is like JavaScript (syntax-wise). What are the benefits of a dynamically typed language, when compared to a strongly typed language like C# or Java, and how would this help in the context of web development? What would make a dynamically typed language so attractive? Or, does the popularity of PHP have more to do with it being free? Okay, I think I better give a little more background to get more meaningful answers, because I am not wanting a flame war. I come from a C background, and when I moved into C# and Visual Studio. Having code completion, integration with an SQL database, huge existing class libraries and easy to access documentation, as well as new tools such as LINQ and ReSharper was like heaven. I didn't enjoy JavaScript before JQuery, but now I love it as well. Recently, I ported a PHP project over to C# and I used Zend to help me debug and understand more while porting - instead of maintaining two code streams. That also cut down on the cost of the server and maintenance. Getting into PHP would be nice. I think that Visual Studio has spoiled me - but again Eclipse is also equally spoiling. It would be nice to have an answer from someone who has experience developing both under PHP and .NET.

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  • how to execute a .exe program by php script

    - by user347262
    hello I want to execute a .exe file on my Apache server using a php script. the procedure is as follow: 1- user comes, fills a html form 2- it goses to a php script 3- php script executes the name.exe file 4- php prints the output of the name.exe file on the page. I execute the name.exe normally from windows like this: run--> cmd--> D:\name [command] the name.exe needs to communicate with other files like libraries in the same directory. the complete comand in cmd at windows is like this: D:\name library.dll [input from user] then program executes and prints some results in cmd window. I actually want to run this program on my server form my clients. I dont know how, but I now there is a way to do this. another related questoin is that, is there any shell that i can install on Linux server and execute name.exe in it? thanks in advanced, John.

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  • memcache, wamp, php 5.4, win8

    - by user1406269
    I am using wamp, PHP 5.4 running on win 8, I can't seem to get PHP to acknowledge the memcache dll. I download php_memcache-3.0.8-5.4-ts-vc9-x86.zip (the only one I could find). I copied the dll to C:\wamp\bin\php\php5.4.12\ext I added extension=php_memcache.dll restart the server. but still I cannot use memcache, and it is missing from Loaded Extensions list. Please supply a step-by-step instruction on how to set this up, Thanks.

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  • Fake Template Engine php

    - by user1464822
    i got an idea for making php template engine fast and user friendly but i'm not sure if it's good or bad. the idea is to create a fake template engine: creating a template editor in control panel that let user see something like this: <html> <head> <title>{title}</title> </head> <body> {content} </body> </html> what the editor actually does is to replace all php code like <?php echo $this->title; ?> to user friendly {title} but it's not really replacing it just in the view when the user save the template the template actually saved as fast pure php template. the question is this a good idea or bad ? your answers is highly appreciated.

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  • How to manually create Friendly URLs? (PHP)

    - by Ole Jak
    How to manually create Friendly URLs? (PHP) So I have created simple php file which echos requested string. Now it has form echo.php?string=bla+bla+bla&font=times I want to see it like echo/bla+bla+bla/times How to do such thing (not using external libs)?

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  • PHP Error Form - Leave Contents of Form on Redirect

    - by user1371500
    I have a simple login form in which if an error occurs such as wrong password, I need it to be able to remember the username which was entered. Would I Go about doing this PHP or Javascript as I am not allowed to use JQuery. My current PHP - (Not Including the HTML Form) <?php //MySQl Connection mysql_connect("localhost", "root", "") or die(mysql_error()); mysql_select_db("clubresults") or die(mysql_error()); //Initiates New Session - Cookie session_start(); // Start a new session // Get the data passed from the form $username = $_POST['username']; $password = md5($_POST['pass']); // Do some basic sanitizing $username = mysql_real_escape_string($username); $password = mysql_real_escape_string($password); //Performs SQL Query to retrieve Login Details from DB $sql = "select * from admin_passwords where username = '$username' and password = '$password'"; $result = mysql_query($sql) or die ( mysql_error() ); //Assigns a Variable Count to 0 $count = 0; //Exectues a loop to increment on Successful Login while ($line = mysql_fetch_assoc($result)) { $count++; } //If count is equal to 1 Redirect user to the Members Page and Set Cookie if ($count == 1) { $_SESSION['loggedIn'] = "true"; header("Location: members.php"); // This is wherever you want to redirect the user to } else { //Else Echo that login was a failure. die('Login Failed. <a href=login.php>Click Here to Try Again</a>'); } ?> Any help would be appreciated. Cheers

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  • open url through header in php

    - by sumit
    I have a .php file in which i have a added a simple code: <?php header("Location:http//www.google.com"); ?> when i run this code, then instead of opening google.com it opens a download file, which is the same as my php file.

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  • PHP shell_exec() - Run directly, or perform a cron (bash/php) and include MySQL layer?

    - by Jimbo
    Sorry if the title is vague - I wasn't quite sure how to word it! What I'm Doing I'm running a Linux command to output data into a variable, parse the data, and output it as an array. Array values will be displayed on a page using PHP, and this PHP page output is requested via AJAX every 10 seconds so, in effect, the data will be retrieved and displayed/updated every 10 seconds. There could be as many as 10,000 characters being parsed on every request, although this is usually much lower. Alternative Idea I want to know if there is a better* alternative method of retrieving this data every 10 seconds, as multiple users (<10) will be having this command executed automatically for them. A cronjob running on the server could execute either bash or php (which is faster?) to grab the data and store it in a MySQL database. Then, any AJAX calls to the PHP output would return values in the MySQL database rather than making a direct call to execute server code every 10 seconds. Why? I know there are security concerns with running execs directly from PHP, and (I hope this isn't micro-optimisation) I'm worried about CPU usage on the server. The server is running a sempron processor. Yes, they do still exist. Having this only execute when the user is on the page (idea #1) means that the server isn't running code that doesn't need to be run. However, is this slow and insecure? Just in case the type of linux command may be of assistance in determining it's efficiency: shell_exec("transmission-remote $host:$port --auth $username:$password -l"); I'm hoping that there are differences in efficiency and level of security with the two methods I have outlined above, and that this isn't just micro-micro-optimisation. If there are alternative methods that are better*, I'd love to learn about these! :)

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  • Pass PHP variables without being seen when working with a database generated list

    - by Wilcoholic
    Looking for any help regarding the problem. Here's the deal: I have a database that has a teams table and it contains team_id. On one of my pages, I generate a list of links that contain the team_id of the creator in their get URL. I need the team_id on the next page but can't figure out how to pass it through any other way. Using a form and POST isn't an option because this method would only pass through the last links data on the list. Storing in a session isn't an option either because there is no way to discretely pass the the variables I need to a function to set the session variables. I have tried and it can pretty easily be viewed from viewing the source code. So here's some sample code to see exactly what I'm dealing with. <? if(mysql_num_rows($result2)>0){ ?> <a class="fltrt btn btn-danger btn-small" onclick="test()" href="acceptmatch-exec.php?match_id=<?php echo $match_id; ?>&team_id=<?php echo $team_id;?>&action=cancel">Cancel Match</a> <?}else{?> <a class="fltrt btn btn-success btn-small" href="acceptmatch-exec.php?match_id=<?php echo $match_id; ?>&team_id=<?php echo $team_id;?>&action=accept">Accept Match</a> <?} ?> The code above is generated multiple times on a page via a while loop that was excluded. I want to pass the match_id and team_id variables without being seen anywhere. If I made this a form, it wouldn't pass the correct variables unless there is only one result at the time (not likely). I'm sure there has to be an easy method that is eluding me, so please share thoughts on how to solve this. I feel as though I am not explaining it well enough, but it's not really easy to explain. I basically want something that works like GET but acts like POST and can be hidden from people viewing source code or link locations. Thanks

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  • PHP display progress messages on the fly

    - by XaviEsteve
    Hi everyone, I am working in a tool in PHP that processes a lot of data and takes a while to finish. I would like to keep the user updated with what is going on and the current task processed. What is in your opinion the best way to do it? I've got some ideas but can't decide for the most effective one: The old way: execute a small part of the script and display a page to the user with a Meta Redirect or a JavaScript timer to send a request to continue the script (like /script.php?step=2). Sending AJAX requests constantly to read a server file that PHP keeps updating through fwrite(). Same as above but PHP updates a field in the database instead of saving a file. Does any of those sound good? Any ideas? Thanks!

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