Search Results

Search found 10169 results on 407 pages for 'port'.

Page 115/407 | < Previous Page | 111 112 113 114 115 116 117 118 119 120 121 122  | Next Page >

• How do you interface with a USB to Parallel adapter?

  - by Hans

  I'm currently doing a project where I have to interact with a circuit I made through the parallel port of a computer. However, my computer doesn't have a parallel port so I borrowed a Parallel to USB adapter cable. The cable didn't come with any drivers, but it's recognized by the device manager as a "USB Printing Support" controller, under the USB section. It seems that old parallel printers can be plugged in and work properly without any problems. So my question is, if I write a program in Java that tries to interact with a parallel port directly, will it work? And if not, can anyone give me some pointers as to what I need to do to interact with it? Thanks.

  Read the article

• Windows.Networking.EndpointPair constructor parameters

  - by ComFreek

  I want to create a new EndpointPair object: // hostname is a string // port is an integer var endpointPair = new Windows.Networking.EndpointPair(null, null, hostname, port); But I always get this error: 0x800a000d - JavaScript runtime error: Type mismatch I've already tried the following: converting port to a string passing "" instead of null for the first two Parameters. (null should be okay if the documentation here, under the section Remarks, is right) passing no Parameters, but that ends up in an "too few parameters" error message Above all, the documentation about the constructor has been removed (as of September 4, 2012): http://msdn.microsoft.com/en-us/library/windows/apps/windows.networking.endpointpair.endpointpair.aspx

  Read the article

• How to make socket.listen(1) work for some time and then continue rest of code???

  - by Rami Jarrar

  I'm making server that make a tcp socket and work over port range, with each port it will listen on that port for some time, then continue the rest of the code. like this:: import socket sck = socket.socket(socket.AF_INET, socket.SOCK_STREAM) sck.setsockopt(socket.SOL_SOCKET, socket.SO_REUSEADDR, 1) msg ='' ports = [x for x in xrange(4000)] while True: try: for i in ports: sck.bind(('',i)) ## sck.listen(1) ## make it just for some time and then continue this ## if there a connection do this conn, addr = sck.accept() msg = conn.recv(2048) ## do something ##if no connection continue the for loop conn.close() except KeyboardInterrupt: exit() so how i could make sck.listen(1) work just for some time ??

  Read the article

• How could I get informations about the SIM card on Windows CE

  - by jeleb

  Hello, I am using a device running on WindowsCE 5.00. I cannot connect the GPRS, there is an error message telling that the port cannot be opened and may be in use by another application. I am not sure but I think the port it is talking about is a comp port to the SIM card that cannot be opened because the SIM doesn't work anymore. To tell the truth, it is likely that one of my coworker did lock the SIM and kept his mouth shut ... How could I get any information about the SIM on Windows CE ? I am new at this and Windows CE is not really user friendly ... I have been strongly searching this on internet but didn't find anything. Any kind of information will be welcomed. Thanks,

  Read the article

• How do you set rate limit access to your API using Iptables?

  - by Cory

  How can you set rate limit access to API using Iptables. Tried to set limit using port 80, but I don't want to set limit to the web access entirely. Is there a way to specified a subdomain rather than port. Example: set rate limit to api.example.com not example.com? If there is no way to set rate limit by subdomain, what is the suggested rate limit access to port 80 without risking blocking a legitimate web user? One connection per second would be enough?

  Read the article

• python and paramiko: how to check if end of ssh tunnel is still alive and reestablish if not?

  - by Christian

  Hello all, I'm trying to achieve the following: I have two hosts A and B. A establishes a remote port forwarding tunnel on B, i.e. B is the one a port is forwarded on to some where else and A is the one that sets up the tunnel. I tried the script rforward.py that ships with paramiko and it works very well so far. (I'm running rforward.py on A, which connects to B and forwards a port of B to somewhere else) However, when B is shutting down, A doesn't seem to recognize it. I'd rather like A to recognize that B is down and to try to reestablish the connection periodically in case B comes up again. Is there a way to do this? Thanks.

  Read the article

• CakePHP 'Cake is NOT able to connect to the database'

  - by kand

  I've looked at this post about a similar issue: CakePHP: Can't access MySQL database and I've tried everything they mentioned in there including: Changing my database.php so that the 'port' attribute for both $default and $test are the location of my mysqld.sock file Changing the 'port' attribute to the actual integer that represents the port in my my.cnf mysql config Changing the mysql socket locations in php.ini to the location of my mysqld.sock file I'm using ubuntu 11.04, apache 2.2.17, mysql 5.1.54, and CakePHP 1.3.10. My install of mysql and apache don't seem to match any conventions, as in, all the config files are there, they are all just in really weird places--I'm not sure why that is, but I've tried reinstalling both programs multiple times with the same results... At any rate, I can log into mysql from the terminal and use it normally, and apache is working because I can see the CakePHP default homepage. I just can't get it to change the message 'Cake is NOT able to connect to the database'. SOLVED: Figured it out, had to change php.ini so that extension_dir pointed to the correct directory and had to add a line extension=mysql.so.

  Read the article

• libcurl - unable to download a file

  - by marmistrz

  I'm working on a program which will download lyrics from sites like AZLyrics. I'm using libcurl. It's my code lyricsDownloader.cpp #include "lyricsDownloader.h" #include <curl/curl.h> #include <cstring> #include <iostream> #define DEBUG 1 ///////////////////////////////////////////////////////////////////////////// size_t lyricsDownloader::write_data_to_var(char *ptr, size_t size, size_t nmemb, void *userdata) // this function is a static member function { ostringstream * stream = (ostringstream*) userdata; size_t count = size * nmemb; stream->write(ptr, count); return count; } string AZLyricsDownloader::toProviderCode() const { /*this creates an url*/ } CURLcode AZLyricsDownloader::download() { CURL * handle; CURLcode err; ostringstream buff; handle = curl_easy_init(); if (! handle) return static_cast<CURLcode>(-1); // set verbose if debug on curl_easy_setopt( handle, CURLOPT_VERBOSE, DEBUG ); curl_easy_setopt( handle, CURLOPT_URL, toProviderCode().c_str() ); // set the download url to the generated one curl_easy_setopt(handle, CURLOPT_WRITEDATA, &buff); curl_easy_setopt(handle, CURLOPT_WRITEFUNCTION, &AZLyricsDownloader::write_data_to_var); err = curl_easy_perform(handle); // The segfault should be somewhere here - after calling the function but before it ends cerr << "cleanup\n"; curl_easy_cleanup(handle); // copy the contents to text variable lyrics = buff.str(); return err; } main.cpp #include <QString> #include <QTextEdit> #include <iostream> #include "lyricsDownloader.h" int main(int argc, char *argv[]) { AZLyricsDownloader dl(argv[1], argv[2]); dl.perform(); QTextEdit qtexted(QString::fromStdString(dl.lyrics)); cout << qPrintable(qtexted.toPlainText()); return 0; } When running ./maelyrica Anthrax Madhouse I'm getting this logged from curl * About to connect() to azlyrics.com port 80 (#0) * Trying 174.142.163.250... * connected * Connected to azlyrics.com (174.142.163.250) port 80 (#0) > GET /lyrics/anthrax/madhouse.html HTTP/1.1 Host: azlyrics.com Accept: */* < HTTP/1.1 301 Moved Permanently < Server: nginx/1.0.12 < Date: Thu, 05 Jul 2012 16:59:21 GMT < Content-Type: text/html < Content-Length: 185 < Connection: keep-alive < Location: http://www.azlyrics.com/lyrics/anthrax/madhouse.html < Segmentation fault Strangely, the file is there. The same error is displayed when there's no such page (redirect to azlyrics.com mainpage) What am I doing wrong? Thanks in advance EDIT: I made the function for writing data static, but this changes nothing. Even wget seems to have problems $ wget http://www.azlyrics.com/lyrics/anthrax/madhouse.html --2012-07-06 10:36:05-- http://www.azlyrics.com/lyrics/anthrax/madhouse.html Resolving www.azlyrics.com... 174.142.163.250 Connecting to www.azlyrics.com|174.142.163.250|:80... connected. HTTP request sent, awaiting response... No data received. Retrying. Why does opening the page in a browser work and wget/curl not? EDIT2: After adding this: curl_easy_setopt(handle, CURLOPT_FOLLOWLOCATION, 1); The log is: * About to connect() to azlyrics.com port 80 (#0) * Trying 174.142.163.250... * connected * Connected to azlyrics.com (174.142.163.250) port 80 (#0) > GET /lyrics/anthrax/madhouse.html HTTP/1.1 Host: azlyrics.com Accept: */* < HTTP/1.1 301 Moved Permanently < Server: nginx/1.0.12 < Date: Fri, 06 Jul 2012 09:09:47 GMT < Content-Type: text/html < Content-Length: 185 < Connection: keep-alive < Location: http://www.azlyrics.com/lyrics/anthrax/madhouse.html < * Ignoring the response-body * Connection #0 to host azlyrics.com left intact * Issue another request to this URL: 'http://www.azlyrics.com/lyrics/anthrax/madhouse.html' * About to connect() to www.azlyrics.com port 80 (#1) * Trying 174.142.163.250... * connected * Connected to www.azlyrics.com (174.142.163.250) port 80 (#1) > GET /lyrics/anthrax/madhouse.html HTTP/1.1 Host: www.azlyrics.com Accept: */* < HTTP/1.1 200 OK < Server: nginx/1.0.12 < Date: Fri, 06 Jul 2012 09:09:47 GMT < Content-Type: text/html < Transfer-Encoding: chunked < Connection: keep-alive < Segmentation fault

  Read the article

• php open_socket

  - by sea_1987

  Hello, I am trying to open a socket to use with secure tradings xpay api, however when I check to see if the socket is open I get error returned, Can't assign requested address I need to open up 127.0.0.1:5000 is there something wring with my code that means I cannot do this? if (isset($xpay_port) and ($socket=socket_create(AF_INET, SOCK_STREAM, SOL_TCP)) and (socket_connect($socket, $address, $port))) { $text="Connection successful on IP $address, port $port"; socket_close($socket); } else $text="Unable to connect<pre>".socket_strerror(socket_last_error())."</pre>"; echo "<html><head></head><body>". $text. "</body></html>";

  Read the article

• socket.error: [Errno 10054]

  - by C0d3r

  import socket, sys if len(sys.argv) !=3 : print "Usage: ./supabot.py <host> <port>" sys.exit(1) irc = sys.argv[1] port = int(sys.argv[2]) sck = socket.socket(socket.AF_INET, socket.SOCK_STREAM) sck.connect((irc, port)) sck.send('NICK supaBOT\r\n') sck.send('USER supaBOT supaBOT supaBOT :supaBOT Script\r\n') sck.send('JOIN #darkunderground' + '\r\n') data = '' while True: data = sck.recv(1024) if data.find('PING') != -1: sck.send('PONG ' + data.split() [1] + '\r\n') print data elif data.find('!info') != -1: sck.send('PRIVMSG #darkunderground supaBOT v1.0 by sourD' + '\r\n') print sck.recv(1024) when I run this code I get this error.. socket.error: [Errno 10054] An existing connection was forcibly closed by the remote host it says that the error is in line 16, in data = sck.recv(1024)

  Read the article

• Communication via internet in Java

  - by Stuart

  What I mean is like servers on video games. You can run an application and it will set up a server on your computer with an IP and a port. For example, how would you make an application where one host application sets up a thing where it has an IP and a port, and another computer that has access to the internet as well can type in the IP and port and it would be able to communicate with the host? I mean simple communication, like sending a boolean or String. And would there be any security problems that would be needed to fix?

  Read the article

• Android Source code download error

  - by user351850

  Hi all I have followed the instructions on the Android website on how to download the latest android source code files but it gives errors when i run this command: repo init -u git://android2.git.kernel.org/platform/manifest.git It gives the following error: Getting repo ... from git://android.git.kernel.org/tools/repo.git android.git.kernel.org[0: 199.6.1.176]: errno=Connection refused android.git.kernel.org[0: 130.239.17.12]: errno=Connection refused fatal: unable to connect a socket (Connection refused) On checking forums for its resolution, i was told that port 9418 was being blocked. I use Ubuntu 10.04 and ensured that the firewall wasnt blocking the port and also enabled the port and the above IP addresses. I also spoke to the networking peeps who ensured that no traffic from the internet is being blocked. I would be glad if i could get directions on how to proceed next. Many thanks as you respond. Saheed.

  Read the article

• Verizon Fivespot firewall exceptions

  - by Patrick

  I have a Verizon Fivespot Wi-Fi router and am having issues connecting to the computer that uses it to get on the internet. I am able to connect to the Fivespot admin pages remotely and I am able to connect to the internet from the computer behind the Fivespot. I've tried asking this on superuser but have gotten nothing, I figure this is pertinent to programmers working on remote computers as well. There are two sections pertinent to this issue, Port Filtering And, Port Forwarding I've tried each individually and both together but cannot access anything through the router except for the admin page. I am trying to connect through SSH on Port 22 to an Ubuntu 10.04 box over wifi. I have called Verizon Tech Support but they were unhelpful, the person essentially read what it says on each screen without any elaboration. Any help is greatly appreciated!

  Read the article

• Giving proper credit to a projects contributors

  - by Greg B

  I've recently been working with an opensource library for a commercial product. The opensource code is distributed from the website of the company who sells the proprietary product as a zip file. The library is a (direct) port to C# of the original library which is in Java. As such, it uses methods instead of getter/setter properties. The code contains copyright notices to the supplier of the product. The C# port was originally provided to the company by a 3rd party individual. I have modified the source to be more C# like and added a couple of small features. I want to put my version of the code out there (Google code or where ever) so that C# users of the software can benefit from a more native feeling library. How can I and/or how should I amend the copyright notice to give proper credit to The comercial owner of the original source The guy who provided the original C# port Myself and anyone else who contributes to the project in the future The source is provided under the LGPL V2.1,

  Read the article

• Strange IP addresses in tomcat

  - by mdev

  Some where I have this in some generic class. public static String getRequestIp (HttpServletRequest request){ String ipaddr = request.getHeader("X-FORWARDED-FOR"); if (ipaddr == null)ipaddr = request.getRemoteAddr(); return ipaddr; } For every request i call that method and in a certain moment i insert a record in a mysql database. In most cases it works normally and i can see a record for every request with a valid ip address in the right field. But sometimes where the IP should be there is something like this. "unknown, 93.186.30.120" or "10.0.1.169, 186.38.84.3" Apache is at the front listening at port 80 and used as proxy to Tomcat that listens at port 8081. My router config would not allow to pass any conection that come by any port other than 80. Any Help? Thanks in advance.

  Read the article

• Is this safe on a production server?

  - by Camran

  I have a database application (or search engine) which is called Solr. I connect to it via port 8983. I do this from php code, so I add and remove records from it via php. On my server I have a firewall. I have set this firewall to only allow connections to and from this port (8983) from the ip adress of my own server. In other words, only allow servers IP to access this port. Is that safe? Or am I thinking all wrong here? Will others be able to "simulate" my ip adress and act as the server? This is because otherwise others may add/remove records as they want from their own ip adresses... Thanks

  Read the article

• Writing a filter for incoming connections

  - by Kornel Kisielewicz

  I'm using C++/boost::asio under Win7. I'm trying to "sniff" trafic over a given TCP/IP port. Hence, I'd like to listen on that port, receive messages, analyze them, but also immidately allow them to flow further, as if I never intercepted them. I want them to sink into the program that normally listens and connects on that port. Imagine a transparent proxy, but not for HTTP. I'd rather find a code-based solution, but barring that, maybe you would suggest a tool?

  Read the article

• How to write an Android SocketServer to listen on wifi

  - by xioxox

  I've written a thread using java.net.SocketServer to listen on a particular port. It works fine in the android simulator (using port forwarding). I'm planning to connect over wifi to this port when the app is being used. However, the SocketServer documentation says that if you don't supply an InetAddress, the server listens on localhost. Am I correct that if I do not supply the address, I will not be able to get a connection over wifi? How can I get the InetAddress of the wifi connection to pass to the SocketServer?

  Read the article

• How to run Rails 3 application on localhost/<my_port> ?

  - by Misha Moroshko

  To run Rails application on Windows I do: cd < app_dir rails server I see the following: => Booting WEBrick => Rails 3.0.1 application starting in development on http://0.0.0.0:3000 => Call with -d to detach => Ctrl-C to shutdown server [2011-01-12 20:32:07] INFO WEBrick 1.3.1 [2011-01-12 20:32:07] INFO ruby 1.9.2 (2010-08-18) [i386-mingw32] [2011-01-12 20:32:07] INFO WEBrick::HTTPServer#start: pid=5812 port=3000 Question 1 Why port 3000 is selected ? Where is it configured ? Question 2 How could I run 2 applications in parallel ? I guess I need to configure one of them to be on other port (like 3001). How should I do this ?

  Read the article

• How to implement bridging/NAT on linux? [closed]

  - by mikepurvis

  What I have is a network topology which looks like this: ------ PC --- IP Camera The PC has two ethernet interfaces, and is hosting a small webserver providing some auxiliary data. The issue is that the server on the PC runs on port 80, and the IP Camera is also running on port 80. Currently, we are bridging them, so that the PC's server is accessible at 192.168.0.2 and the camera at 192.168.0.3. However, what I'm trying to explore is the feasibility of using the PC to expose them both on the PC's IP, ideally both on port 80. Can this be done with regular sockets, or will it be necessary to use raw sockets?

  Read the article

• How to find out on which internet addresses a java program can listen.

  - by tzador

  My program needs to listen incoming socket connections (lets agree on port 8765), but it doesn't know which addresses it can bind on a particular machine. Of, course, it could simply to listen to all of them, but it need to send to the client program over a different(slower) channel the addresses which it should try in order to rich me on port 8765. So the flow is like this: My program lisens on all available interfaces on port 8765 Finds out a list of inet4 adresses by which it can be possibly reached (this step is the actual question) Posts that address on a whiteboard (blogpost or something) Interested clients try out all of them, to see using which one they can reach my program. This is all is to be done in java ofcourse :)

  Read the article

• How do I make a TCP server work behind a router (NAT) without any redirection configuration needed.

  - by Chetane

  The scenario is the following. I have two machines A and B: A: Client (behind NAT) B: Server (behind NAT) I want B to be able to listen on any given port, so that A can send packets to B through that specific TCP port and receive any response. If both machines are not behind a NAT it is pretty straight foward process. However how do I make it work so that it works even when B is behind a router, without him having to go change the router configuration enable some port forwarding etc... For example, how do p2p program like torrent clients work without the user having anything to configure? Thanks and I hope my question is clear enough.

  Read the article

• Find mininum unused value in mysql table

  - by splattru

  I have a MySQL table like this: +--------+-------+ + Server + Port + +--------+-------+ + 1 + 27001 + +--------+-------+ + 2 + 27002 + +--------+-------+ + 4 + 27004 + +--------+-------+ How you can see - here was 27003 port - but it was deleted some time ago (just for example). Is there some way to know the minimum value that is not used (higher than 27000 for example) in mysql table? Or there is no way and I need to make an separate table with all ports and column with "used" or "not used" ? Situation explanation: I am creating game hosting website, and I can use auto-increment for ports, but I will have a lot of deleted/unused ports after some time, and I want to use all of them before increasing port range. Thanks for your answers!

  Read the article

• PHP memcache - check if any server is available in pool?

  - by Industrial

  Hi everyone, I have the following code: $cluster['local'] = array('host' => '192.168.1.1', 'port' => '11211', 'weight' => 50); $cluster['local2'] = array('host' => '192.168.1.2', 'port' => '11211', 'weight' => 50); $this->memcache = new Memcache; foreach ($this->cluster() as $cluster) { $this->memcache->addServer($cluster['host'], $cluster['port'], $this->persistent, $cluster['weight'], 10, 10, TRUE , 'failure' ); } I would like to make a function that checks if any of my servers in my memcache Pool is available. How could this be done?

  Read the article

• What host do I have to bind a listening socket to?

  - by herrturtur

  I used python's socket module and tried to open a listening socket using import socket import sys def getServerSocket(host, port): for r in socket.getaddrinfo(host, port, socket.AF_UNSPEC, socket.SOCK_STREAM, 0, socket.AI_PASSIVE): af, socktype, proto, canonname, sa = r try: s = socket.socket(af, socktype, proto) except socket.error, msg: s = None continue try: s.bind(sa) s.listen(1) except socket.error, msg: s.close() s = None continue break if s is None: print 'could not open socket' sys.exit(1) return s Where host was None and port was 15000. The program would then accept connections, but only from connections on the same machine. What do I have to do to accept connections from the internet?

  Read the article

< Previous Page | 111 112 113 114 115 116 117 118 119 120 121 122  | Next Page >