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  • Unit testing ASP.NET Web API controllers that rely on the UrlHelper

    - by cibrax
    UrlHelper is the class you can use in ASP.NET Web API to automatically infer links from the routing table without hardcoding anything. For example, the following code uses the helper to infer the location url for a new resource,public HttpResponseMessage Post(User model) { var response = Request.CreateResponse(HttpStatusCode.Created, user); var link = Url.Link("DefaultApi", new { id = id, controller = "Users" }); response.Headers.Location = new Uri(link); return response; } That code uses a previously defined route “DefaultApi”, which you might configure in the HttpConfiguration object (This is the route generated by default when you create a new Web API project). The problem with UrlHelper is that it requires from some initialization code before you can invoking it from a unit test (for testing the Post method in this example). If you don’t initialize the HttpConfiguration and Request instances associated to the controller from the unit test, it will fail miserably. After digging into the ASP.NET Web API source code a little bit, I could figure out what the requirements for using the UrlHelper are. It relies on the routing table configuration, and a few properties you need to add to the HttpRequestMessage. The following code illustrates what’s needed,var controller = new UserController(); controller.Configuration = new HttpConfiguration(); var route = controller.Configuration.Routes.MapHttpRoute( name: "DefaultApi", routeTemplate: "api/{controller}/{id}", defaults: new { id = RouteParameter.Optional } ); var routeData = new HttpRouteData(route, new HttpRouteValueDictionary { { "id", "1" }, { "controller", "Users" } } ); controller.Request = new HttpRequestMessage(HttpMethod.Post, "http://localhost:9091/"); controller.Request.Properties.Add(HttpPropertyKeys.HttpConfigurationKey, controller.Configuration); controller.Request.Properties.Add(HttpPropertyKeys.HttpRouteDataKey, routeData);  The HttpRouteData instance should be initialized with the route values you will use in the controller method (“id” and “controller” in this example). Once you have correctly setup all those properties, you shouldn’t have any problem to use the UrlHelper. There is no need to mock anything else. Enjoy!!.

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  • Youtube API - How to limit results for pagination?

    - by worchyld
    I want to grab a user's uploads (ie: BBC) and limit the output to 10 per page. Whilst I can use the following URL: http://gdata.youtube.com/feeds/api/users/bbc/uploads/?start-index=1&max-results=10 The above works okay. I want to use the query method instead: The Zend Framework docs: http://framework.zend.com/manual/en/zend.gdata.youtube.html State that I can retrieve videos uploaded by a user, but ideally I want to use the query method to limit the results for a pagination. The query method is on the Zend framework docs (same page as before under the title 'Searching for videos by metadata') and is similar to this: [code] $yt = new Zend_Gdata_YouTube(); $query = $yt-newVideoQuery(); $query-setTime('today'); $query-setMaxResults(10); $videoFeed = $yt-getUserUploads( NULL, $query ); // Output print ''; foreach($videoFeed as $video): print '' . $video-title . ''; endforeach; print ''; [/code] The problem is I can't do $query-setUser('bbc'). I tried setAuthor but this returns a totally different result. Ideally, I want to use the query method to grab the results in a paginated fashion. How do I use the $query method to set my limits for pagination? Thanks.

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  • Apache - "dynamic" rewrite rule

    - by Christian A. Rasmussen
    Hi there. I'm working on a Zend Framework project where I've stumbled across a bit of a problem. The problem originates from the fact that modules are 2nd class citizens in Zend Framework. In my project, I'd like for each module to have a folder containing files which are to be accessed from the outside - files such as stylesheets, javascripts and images. Now, how is this to be done. With a Zend Framework project I have a folder structure which looks like this: application/ modules/ moduleOne/ public/ stylesheet.css moduleTwo/ moduleThree/ public/ index.php The standard .htaccess file located in the public/ folder holds this: SetEnv APPLICATION_ENV development RewriteEngine On RewriteCond %{REQUEST_FILENAME} -s [OR] RewriteCond %{REQUEST_FILENAME} -l [OR] RewriteCond %{REQUEST_FILENAME} -d RewriteRule ^.*$ - [NC,L] RewriteRule ^.*$ index.php [NC,L] The way it works, is that the project's apache DocumentRoot is the public/ folder. All requests gets redirected through the index.php file where Zend Framework's router component takes over. Now, I'm by no means an expert with Apache nor mod_rewrite so pardon me if this is just silly. I imagine that I implement an extra step in the existing rewrite rule so that if I request http://project/public/moduleOne/stylesheet.css it will for instance resolve to /var/www/project/application/modules/moduleOne/public/stylesheet.css. So the steps which need to be done is to check if the first element in the URI is public/ if it is, we take the next segment as the modules name and use that in the path we're trying to resolve to and attempt to serve the file. Is this at all possible or does anyone have a better suggestion? Thank you for your time Christian Rasmussen

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  • How to install Eclipse + PHP Development Tools (PDT) + Debugger on Mac in The Year 2010

    - by aphex5
    I had a lot of trouble installing Eclipse and PDT on my system. It took two days, largely because all the tutorials I could find were out of date (written in 2008, it's 2010 now) and various steps they included were no longer necessary, broken, or irrelevant. I wanted to write my process here so it could be improved upon (via wiki) as time goes on. Install Eclipse without PHP plugin ("Eclipse Classic"). This will give you a complete Eclipse, which I find preferable, as the UI is more fleshed out (e.g. you get a default list of Perspectives, which helps you understand what Perspectives are.) Install PDT SDK with the Help Install New Software menu item. You'd think you'd be done here, but if you try to run something, it'll fail complaining of not having a debugger. Install the Zend Debugger. It'll fail if you try to use the Install New Software option, as many tutorials suggest ("No repository found containing osgi.bundle.org.zend.php.debug.debugger.5.3.7.v20091116".) Instead, download it from http://www.zend.com/en/community/pdt, and manually copy the features/ and plugins/ directory into your Eclipse install (these instructions are not written anywhere). Restart Eclipse Monkey with preferences for a while -- if you followed a previous tutorial and tried to manually add your php executable to Eclipse prefs (/usr/bin/php), remove it (PHP PHP Executables). Set one of the Zend Debugger executables to the default. If you've already tried to execute a .php file, remove the existing "Run" profile you (maybe weren't aware that you) created (Run Debug Configurations...). Eclipse works! You should be able to run a .php file as a script just fine.

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  • ZF2 namespace and file system

    - by user1918648
    I have standard Application module in ZF2. It's configured by default, I didn't change anything. I just added some stuff: module/ Application/ src/ Application/ Entity/ Product/ **Product.php** Controller/ **IndexController.php** Product.php namespace Application\Entity; class Product { } IndexController.php namespace Application\Controller; use Zend\Mvc\Controller\AbstractActionController; use Zend\View\Model\ViewModel; use Application\Entity\Product; class IndexController extends AbstractActionController { public function indexAction() { $product = new Product(); } } and I get following error: Fatal error: Class 'Application\Entity\Product' not found in \module\Application\src\Application\Controller\IndexController.php on line 20 I use the same namespace, but it doesn't see it. Why? P.S: If I will change Product.php to be the following: namespace Application\Entity\Product; class Product { } then in the IndexController.php the following code will be working: namespace Application\Controller; use Zend\Mvc\Controller\AbstractActionController; use Zend\View\Model\ViewModel; use Application\Entity\Product\Product; class IndexController extends AbstractActionController { public function indexAction() { $product = new Product(); } }

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  • ASP.NET MVC2: Getting textbox data from a view to a controller

    - by mr_plumley
    Hi, I'm having difficulty getting data from a textbox into a Controller. I've read about a few ways to accomplish this in Sanderson's book, Pro ASP.NET MVC Framework, but haven't had any success. Also, I've ran across a few similiar questions online, but haven't had any success there either. Seems like I'm missing something rather fundamental. Currently, I'm trying to use the action method parameters approach. Can someone point out where I'm going wrong or provide a simple example? Thanks in advance! Using Visual Studio 2008, ASP.NET MVC2 and C#: What I would like to do is take the data entered in the "Investigator" textbox and use it to filter investigators in the controller. I plan on doing this in the List method (which is already functional), however, I'm using the SearchResults method for debugging. Here's the textbox code from my view, SearchDetails: <h2>Search Details</h2> <% using (Html.BeginForm()) { %> <fieldset> <%= Html.ValidationSummary() %> <h4>Investigator</h4> <p> <%=Html.TextBox("Investigator")%> <%= Html.ActionLink("Search", "SearchResults")%> </p> </fieldset> <% } %> Here is the code from my controller, InvestigatorsController: private IInvestigatorsRepository investigatorsRepository; public InvestigatorsController(IInvestigatorsRepository investigatorsRepository) { //IoC: this.investigatorsRepository = investigatorsRepository; } public ActionResult List() { return View(investigatorsRepository.Investigators.ToList()); } public ActionResult SearchDetails() { return View(); } public ActionResult SearchResults(SearchCriteria search) { string test = search.Investigator; return View(); } I have an Investigator class: [Table(Name = "INVESTIGATOR")] public class Investigator { [Column(IsPrimaryKey = true, IsDbGenerated = false, AutoSync=AutoSync.OnInsert)] public string INVESTID { get; set; } [Column] public string INVEST_FNAME { get; set; } [Column] public string INVEST_MNAME { get; set; } [Column] public string INVEST_LNAME { get; set; } } and created a SearchCriteria class to see if I could get MVC to push the search criteria data to it and grab it in the controller: public class SearchCriteria { public string Investigator { get; set; } } } I'm not sure if project layout has anything to do with this either, but I'm using the 3 project approach suggested by Sanderson: DomainModel, Tests, and WebUI. The Investigator and SearcCriteria classes are in the DomainModel project and the other items mentioned here are in the WebUI project. Thanks again for any hints, tips, or simple examples! Mike

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  • IPHONE - Flip animation when controller pushed

    - by chacha
    Hi, I had a look around and didn't find what I was exactly looking for ... Is there a way to get a flip animation when pushing a view controller ? I read that you can change the animation by using a modal view controller but AFAIK the animation for a modal view is from bottom to top and that's not what i am looking for ;) Is there a way to get a flip animation somehow ? Cheers, Chacha

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  • [CakePHP] Can not Bake table model, controller and view

    - by user198003
    I developed small CakePHP application, and now I want to add one more table (in fact, model/controller/view) into system, named notes. I had already created a table of course. But when I run command cake bake model, I do not get table Notes on the list. I can add it manually, but after that I get some errors when running cake bake controller and cake bake view. Can you give me some clue why I have those problems, and how to add that new model?

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  • Transfer VLAN tagged packets over WLAN?

    - by stefan.at.wpf
    I have the following composition of devices: [selfmade router] - ethernet - [WLAN router 1] ----- wlan ------ [WLAN router 2] WLAN router 2 has 5 ethernet ports, each as an own VLAN, so 5 VLANs. I want to manage the routing and firewalling between those VLANs at selfmade router. What technique would I use to pass the tagged vlan packets from WLAN router 2 to selfmade router? Could I use a bridge from WLAN router 2 to WLAN router 1 which itself has a bridge from WLAN router 1 to selfmade router or do I have a wrong understanding of a bridge? Thanks for any hint on this :-)

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  • TDD a controller with ASP.NET MVC 2, NUnit and Rhino Mocks

    - by Nissan Fan
    What would a simple unit test look like to confirm that a certain controller exists if I am using Rhino Mocks, NUnit and ASP.NET MVC 2? I'm trying to wrap my head around the concept of TDD, but I can't see to figure out how a simple test like "Controller XYZ Exists" would look. In addition, what would the unit test look like to test an Action Result off a view?

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  • Pecl install ssh2, make failed

    - by user28259
    Hi! I'm trying really hard since two hours to install ssh2 with pecl... But all I get is: /bin/sh /root/ssh2-0.11.0/libtool --mode=compile cc -I. -I/root/ssh2-0.11.0 -DPHP_ATOM_INC -I/root/ssh2-0.11.0/include -I/root/ssh2-0.11.0/main -I/root/ssh2-0.11.0 -I/usr/include/php -I/usr/include/php/main -I/usr/include/php/TSRM -I/usr/include/php/Zend -I/usr/include/php/ext -I/usr/include/php/ext/date/lib -DHAVE_CONFIG_H -g -O2 -c /root/ssh2-0.11.0/ssh2.c -o ssh2.lo mkdir .libs cc -I. -I/root/ssh2-0.11.0 -DPHP_ATOM_INC -I/root/ssh2-0.11.0/include -I/root/ssh2-0.11.0/main -I/root/ssh2-0.11.0 -I/usr/include/php -I/usr/include/php/main -I/usr/include/php/TSRM -I/usr/include/php/Zend -I/usr/include/php/ext -I/usr/include/php/ext/date/lib -DHAVE_CONFIG_H -g -O2 -c /root/ssh2-0.11.0/ssh2.c -fPIC -DPIC -o .libs/ssh2.o /root/ssh2-0.11.0/ssh2.c:52: error: duplicate 'static' /root/ssh2-0.11.0/ssh2.c: In function 'zif_ssh2_methods_negotiated': /root/ssh2-0.11.0/ssh2.c:503: warning: passing argument 4 of 'add_assoc_string_ex' discards qualifiers from pointer target type /usr/include/php/Zend/zend_API.h:360: note: expected 'char *' but argument is of type 'const char *' /root/ssh2-0.11.0/ssh2.c:504: warning: passing argument 4 of 'add_assoc_string_ex' discards qualifiers from pointer target type /usr/include/php/Zend/zend_API.h:360: note: expected 'char *' but argument is of type 'const char *' /root/ssh2-0.11.0/ssh2.c:508: warning: passing argument 4 of 'add_assoc_string_ex' discards qualifiers from pointer target type /usr/include/php/Zend/zend_API.h:360: note: expected 'char *' but argument is of type 'const char *' /root/ssh2-0.11.0/ssh2.c:509: warning: passing argument 4 of 'add_assoc_string_ex' discards qualifiers from pointer target type /usr/include/php/Zend/zend_API.h:360: note: expected 'char *' but argument is of type 'const char *' /root/ssh2-0.11.0/ssh2.c:510: warning: passing argument 4 of 'add_assoc_string_ex' discards qualifiers from pointer target type /usr/include/php/Zend/zend_API.h:360: note: expected 'char *' but argument is of type 'const char *' /root/ssh2-0.11.0/ssh2.c:511: warning: passing argument 4 of 'add_assoc_string_ex' discards qualifiers from pointer target type /usr/include/php/Zend/zend_API.h:360: note: expected 'char *' but argument is of type 'const char *' /root/ssh2-0.11.0/ssh2.c:516: warning: passing argument 4 of 'add_assoc_string_ex' discards qualifiers from pointer target type /usr/include/php/Zend/zend_API.h:360: note: expected 'char *' but argument is of type 'const char *' /root/ssh2-0.11.0/ssh2.c:517: warning: passing argument 4 of 'add_assoc_string_ex' discards qualifiers from pointer target type /usr/include/php/Zend/zend_API.h:360: note: expected 'char *' but argument is of type 'const char *' /root/ssh2-0.11.0/ssh2.c:518: warning: passing argument 4 of 'add_assoc_string_ex' discards qualifiers from pointer target type /usr/include/php/Zend/zend_API.h:360: note: expected 'char *' but argument is of type 'const char *' /root/ssh2-0.11.0/ssh2.c:519: warning: passing argument 4 of 'add_assoc_string_ex' discards qualifiers from pointer target type /usr/include/php/Zend/zend_API.h:360: note: expected 'char *' but argument is of type 'const char *' /root/ssh2-0.11.0/ssh2.c: In function 'zif_ssh2_publickey_add': /root/ssh2-0.11.0/ssh2.c:1045: warning: passing argument 1 of '_efree' discards qualifiers from pointer target type /usr/include/php/Zend/zend_alloc.h:46: note: expected 'void *' but argument is of type 'const char *' /root/ssh2-0.11.0/ssh2.c: In function 'zif_ssh2_publickey_list': /root/ssh2-0.11.0/ssh2.c:1104: warning: passing argument 4 of 'add_assoc_stringl_ex' discards qualifiers from pointer target type /usr/include/php/Zend/zend_API.h:361: note: expected 'char *' but argument is of type 'const unsigned char *' /root/ssh2-0.11.0/ssh2.c:1105: warning: passing argument 4 of 'add_assoc_stringl_ex' discards qualifiers from pointer target type /usr/include/php/Zend/zend_API.h:361: note: expected 'char *' but argument is of type 'const unsigned char *' make: *** [ssh2.lo] Error 1 I looked on google a lot, I found some patches which didn't worked at all. So if you think you could help me, go ahead! Thanks!

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  • ErrorException [ Fatal Error ]: Class 'Controller' not found - Kohana 3.0.3 Error

    - by Asif
    Hi, I am (newbie) using Kohana V 3.0.3 and my directory structure is: pojectsys (kohana's system directory) parallel to htdocs directory C:\xampp\pojectsys and my application directory is in htdocs C:\xampp\htdocs\examples Inside C:\xampp\htdocs\examples\index.php, following variables have been set: $application = 'C:\xampp\htdocs\examples\application'; $system = 'C:\xampp\pojectsys'; Now when I am trying to execute http://lc.examples.com/ then Kohana returns error: ErrorException [ Fatal Error ]: Class 'Controller' not found for line 3 class Controller_Welcome extends Controller { Please help me to resolve this issue.

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  • how a view controller know when it is dismissed or poped out of the navigation controller stack?

    - by Thanh-Cong Vo
    Hi all, My view controller needs to know when it is poped out of the navigation controller stack, so that it can retain itself, wait and release itself later with another notification. I intend to do like that when the view is sent dealloc message: - (void)dealloc { if (self.isPerformingSomeTask) { self.isPopedOut = YES; [self retain]; return; } [super dealloc]; } But I think this is not a good solution? Any idea?

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  • Non blocking IO call from Django controller from a Windows service

    - by Anders
    Hi all, I have a CherryPy server with a Django application running as a Windows service, inside a controller I need to make a call to wmic, the problem is, so far I have only been able to implement a blocking operation. Does anyone have any recommendation for a non blocking operation so, at least more then one person at a time can access this controller and extract information from wmic? Thanks in advance, Anders

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  • iPhone - Reset UINavigation Controller

    - by Ward
    Hey there, I have a UINavigationController inside a UITabBarController. When a user presses the first tab, I want to reset the navigation controller back to the first screen instead of displaying whichever view they last selected in the navigation controller. Is there an easy way to reset the stack? Thanks, Howie

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  • Invoke modal view controller from UIWebView weblink

    - by JD
    Hey folks I was wondering if anyone can tip me on a painless way of invoking a modal view controller from a web link in a UIWebView. Is it possible to do this? I want the modal view controller to still be a part of the app as opposed to closing the main app and using a helper application instead. Any help would be greatly appreciated.

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  • One class instance throw all controller

    - by Falcon
    Hello i i have different class and controller. and i need that one instance of model will be available in controller/ now i'm doing something like this: def method1 inst = @MyClass.new(params) inst.action .... def method2 inst = @MyClass.new(params) inst.action .... but i want something like this def method1 @inst.action .... def method2 @inst.action or self.inst i't doesn't matter how i can do it? def self.inst MyClass.new(params) end doesn't work...

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  • [CakePHP] Can not Bake table model, controller and view

    - by user198003
    I developed small CakePHP application, and now I want to add one more table (in fact, model/controller/view) into system, named notes. I had already created a table of course. But when I run command cake bake model, I do not get table Notes on the list. I can add it manually, but after that I get some errors when running cake bake controller and cake bake view. Can you give me some clue why I have those problems, and how to add that new model?

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  • Rails Controller

    - by Steve
    Hi...In Rails, is it ok to define logic in a controller with a model. For example, take there is an User Model, which is good design. 1)Leaving the UserModel with the CRUD models and moving all the other User Specific actions to a separate controller or 2)Add the user specific actions to the same UserModels Thanks :)

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