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  • How do I do a cross domain GET of an XML feed in a WordPress plugin?

    - by MM.
    I would like to use AJAX to display dynamic content via my wordpress plugin. The data source is an xml feed from a remote domain (not owned by me). I have tried using JQuery plugins that use YQL to do cross domain Ajax calls; however, they are geared towards json and tend to return the data to me in a mangled state. My question is, is there a way of obtaining an xml feed using ajax from a remote domain?

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  • Redirect in codeigniter after login

    - by edelweiss
    Trying to do a redirect after a successful login. The login info is sent using ajax to the controller. My controller code as below public function login_controller_function() { $this->load->model('login_model'); if ($this->input->is_ajax_request()) { $user_name=$this->input->post('username'); $user_password = $this->input->post('password'); $this->load->helper('url'); $result = $this->login_model->verify_user($user_name,$user_password); // echo 'user_logged_in'; if(strcmp($result,'user_logged_in')==0) { redirect('welcome'); } } } But it is not working at all. Anyone knows whats wrong? Hi my html as requested. i am using twitter bootstrap as well <li class="divider-vertical"></li> <li><a href="#" id="login_btn">Login</a></li> <li><a href="<?php echo base_url('register'); ?>">Register</a></li> for the buttons so when i click the login button, a modal window will appear and ask for login info. so when i click on the login button, my js code will send an ajax request my js code as below /*Attempt register user jquery ajax*/ $('#login').click(function(){ var user_name = $('#loginHere').find('#user_name').val(); var user_password = $('#loginHere').find('#login_pwd').val(); if(user_name==""||user_password=="") return; var login_data = { username:user_name, password:user_password}; $.ajax({ type: "POST", dataType: "json", async: false, url:"login_register/login_controller_function", data: login_data, success: function(data) { if(data.login) { alert(data.redirect); window.location.replace(data.redirect); } else if(!data.login) { alert('data login not true'); } }, error:function(data){ alert('ajax error'); } }); }); });

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  • With Google's #! mess, what effect would a redirect on the converted URL have?

    - by Ne0nx3r0
    So Google takes: http://www.mysite.com/mypage/#!pageState and converts it to: http://www.mysite.com/mypage/?_escaped_fragment_=pageState ...So... Would be it fair game to redirect that with a 301 status to something like: http://www.mysite.com/mypage/pagestate/ and then return an HTML snapshot? My thought is if you have an existing html structure, and you just want to add ajax as a progressive enhancement, this would be a fair way to do it, if Google just skipped over _escaped_fragment_ and indexed the redirected URL. Then your ajax links are configured by javascript, and underneath them are the regular links that go to your regular site structure. So then when a user comes in on a static url (ie http://www.mysite.com/mypage/pagestate/ ), the first link he clicks takes him to the ajax interface if he has javascript, then it's all ajax. On a side note does anyone know if Yahoo/MSN onboard with this 'spec' (loosely used)? I can't seem to find anything that says for sure.

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  • Uploadify Not Working

    - by azz0r
    Hello, I'll re-edit this to tackle the uploadify issue. Its very strange, essentially the script isn't uploading and isn't triggering onAllComplete. Also if I try to upload an image that's to large, and click Upload files, it skips from 0 to 100%. But does not trigger onAllComplete. It does not upload either. Whats strange, is I have an earlier revision of this and the codes no different and it works, ive tried switched back to the same jquery/uploadify/layout and it still doesnt work. However due to the nature of uploadify not being very forthcoming about errors or whats going on, I can't figure out where its going wrong! Controller: public function manageImagesAction() { $id = $this->_getParam('id'); $object = Eurocreme_Gallery::load_by_fields(array('id' => $id), 1); $images = Eurocreme_Image::load_by_type(array('type' => 'gallery_id', 'values' => $id, 'from' => 0, 'to' => COUNT_HIGH, 'order' => 'gi.position ASC')); $this->view->object = $object; $this->view->images = $images; $this->view->headScript()->appendFile('/library/jquery/uploadify/swfobject.js'); $this->view->headScript()->appendFile('/library/jquery/uploadify/jquery.uploadify.v2.1.0.js'); $this->view->headScript()->appendFile('/library/jquery/ui.js'); } View: <div class="content-area"> <h1>Adding Images To "<?php echo $this->object->name; ?>" Gallery</h1> <p><input id="fileInput2" name="fileInput2" type="file" /></p> <p><a href="javascript:$('#fileInput2').uploadifyUpload();">Upload Files</a> | <a href="javascript:$('#fileInput2').uploadifyClearQueue();">Clear Queue</a></p> </div> <?php if (!empty($this->images)) { ?> <div class="content-area"> <h1>Order Images For <?php echo $this->object->name; ?></h1> <p id="status_update">Drop And Drag Images to re-order them, I will automatically save it for you!</p> <ul id="sort_list"> <?php foreach ($this->images as $image) { ?> <li class="removable" id="recordsArray_<?php echo $image->id; ?>"><img src="/images/Image/thumb/<?php echo $image->image_url; ?>" alt="<?php echo $image->name_url; ?>" title="<?php echo $image->name; ?>" /><p><a class="removable" id="<?php echo $image->id; ?>">Delete</a></p></li> <?php } ?> </ul> <p class="clear"></p> </div> <?php } ?> <?php $this->headScript()->captureStart(); ?> $('document').ready(function() { $("#fileInput2").uploadify({ 'uploader' : '/library/jquery/uploadify/uploadify.swf', 'script' : '/<?php echo $this->object->name_url; ?>/upload.php', 'cancelImg' : '/library/jquery/uploadify/cancel.png', 'folder' : '/images/Image/', 'multi' : true, 'onAllComplete' : function(e, queueId, file, response, data) { window.location.reload(); }, }) //sortable $(function() { $("#sort_list").sortable({ opacity: 0.6, cursor: 'move', update: function() { $("#status_update").html('Processing'); var order = $(this).sortable("serialize"); $.post("/administration/gallery/save-image-order/id/<?php echo $this->object->id; ?>", order, function(theResponse){ $("#status_update").html(theResponse); }); } }); //delete $('a.removable').click(function(){ var id = this.id; $.post("/administration/gallery/delete-image/gallery_id/<?php echo $this->object->id; ?>/image_id/"+id+"", '', function(theResponse) { $("#recordsArray_"+id+"").remove(); }); }); }); }); <?php $this->headScript()->captureEnd(); ?>

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  • Handling file upload in a non-blocking manner

    - by Kaliyug Antagonist
    The background thread is here Just to make objective clear - the user will upload a large file and must be redirected immediately to another page for proceeding different operations. But the file being large, will take time to be read from the controller's InputStream. So I unwillingly decided to fork a new Thread to handle this I/O. The code is as follows : The controller servlet /** * @see HttpServlet#doPost(HttpServletRequest request, HttpServletResponse * response) */ protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { // TODO Auto-generated method stub System.out.println("In Controller.doPost(...)"); TempModel tempModel = new TempModel(); tempModel.uploadSegYFile(request, response); System.out.println("Forwarding to Accepted.jsp"); /*try { Thread.sleep(1000 * 60); } catch (InterruptedException e) { // TODO Auto-generated catch block e.printStackTrace(); }*/ request.getRequestDispatcher("/jsp/Accepted.jsp").forward(request, response); } The model class package com.model; import java.io.IOException; import java.util.concurrent.ExecutionException; import java.util.concurrent.Future; import javax.servlet.http.HttpServletRequest; import javax.servlet.http.HttpServletResponse; import com.utils.ProcessUtils; public class TempModel { public void uploadSegYFile(HttpServletRequest request, HttpServletResponse response) { // TODO Auto-generated method stub System.out.println("In TempModel.uploadSegYFile(...)"); /* * Trigger the upload/processing code in a thread, return immediately * and notify when the thread completes */ try { FileUploaderRunnable fileUploadRunnable = new FileUploaderRunnable( request.getInputStream()); /* * Future<FileUploaderRunnable> future = ProcessUtils.submitTask( * fileUploadRunnable, fileUploadRunnable); * * FileUploaderRunnable processed = future.get(); * * System.out.println("Is file uploaded : " + * processed.isFileUploaded()); */ Thread uploadThread = new Thread(fileUploadRunnable); uploadThread.start(); } catch (IOException e) { // TODO Auto-generated catch block e.printStackTrace(); } /* * catch (InterruptedException e) { // TODO Auto-generated catch block * e.printStackTrace(); } catch (ExecutionException e) { // TODO * Auto-generated catch block e.printStackTrace(); } */ System.out.println("Returning from TempModel.uploadSegYFile(...)"); } } The Runnable package com.model; import java.io.File; import java.io.FileInputStream; import java.io.FileNotFoundException; import java.io.FileOutputStream; import java.io.IOException; import java.io.InputStream; import java.nio.ByteBuffer; import java.nio.channels.Channels; import java.nio.channels.ReadableByteChannel; public class FileUploaderRunnable implements Runnable { private boolean isFileUploaded = false; private InputStream inputStream = null; public FileUploaderRunnable(InputStream inputStream) { // TODO Auto-generated constructor stub this.inputStream = inputStream; } public void run() { // TODO Auto-generated method stub /* Read from InputStream. If success, set isFileUploaded = true */ System.out.println("Starting upload in a thread"); File outputFile = new File("D:/06c01_output.seg");/* * This will be changed * later */ FileOutputStream fos; ReadableByteChannel readable = Channels.newChannel(inputStream); ByteBuffer buffer = ByteBuffer.allocate(1000000); try { fos = new FileOutputStream(outputFile); while (readable.read(buffer) != -1) { fos.write(buffer.array()); buffer.clear(); } fos.flush(); fos.close(); readable.close(); } catch (FileNotFoundException e) { // TODO Auto-generated catch block e.printStackTrace(); } catch (IOException e) { // TODO Auto-generated catch block e.printStackTrace(); } System.out.println("File upload thread completed"); } public boolean isFileUploaded() { return isFileUploaded; } } My queries/doubts : Spawning threads manually from the Servlet makes sense to me logically but scares me coding wise - the container isn't aware of these threads after all(I think so!) The current code is giving an Exception which is quite obvious - the stream is inaccessible as the doPost(...) method returns before the run() method completes : In Controller.doPost(...) In TempModel.uploadSegYFile(...) Returning from TempModel.uploadSegYFile(...) Forwarding to Accepted.jsp Starting upload in a thread Exception in thread "Thread-4" java.lang.NullPointerException at org.apache.coyote.http11.InternalInputBuffer.fill(InternalInputBuffer.java:512) at org.apache.coyote.http11.InternalInputBuffer.fill(InternalInputBuffer.java:497) at org.apache.coyote.http11.InternalInputBuffer$InputStreamInputBuffer.doRead(InternalInputBuffer.java:559) at org.apache.coyote.http11.AbstractInputBuffer.doRead(AbstractInputBuffer.java:324) at org.apache.coyote.Request.doRead(Request.java:422) at org.apache.catalina.connector.InputBuffer.realReadBytes(InputBuffer.java:287) at org.apache.tomcat.util.buf.ByteChunk.substract(ByteChunk.java:407) at org.apache.catalina.connector.InputBuffer.read(InputBuffer.java:310) at org.apache.catalina.connector.CoyoteInputStream.read(CoyoteInputStream.java:202) at java.nio.channels.Channels$ReadableByteChannelImpl.read(Unknown Source) at com.model.FileUploaderRunnable.run(FileUploaderRunnable.java:39) at java.lang.Thread.run(Unknown Source) Keeping in mind the point 1., does the use of Executor framework help me in anyway ? package com.utils; import java.util.concurrent.Future; import java.util.concurrent.ScheduledThreadPoolExecutor; public final class ProcessUtils { /* Ensure that no more than 2 uploads,processing req. are allowed */ private static final ScheduledThreadPoolExecutor threadPoolExec = new ScheduledThreadPoolExecutor( 2); public static <T> Future<T> submitTask(Runnable task, T result) { return threadPoolExec.submit(task, result); } } So how should I ensure that the user doesn't block and the stream remains accessible so that the (uploaded)file can be read from it?

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  • ajax.googleapis.com stopping my Firefox

    - by Oscar Reyes
    Today for some strange reason, Firefox stops working properly because it is trying to fetch something from ajax.googleapis.com. Is there something I can do to avoid this? Safari and Chrome work just fine. I tried uninstalling Firebug and clearing the cache. The only thing that worked was disabling the JavaScript altogether. This seems to be the culprit link: http://ajax.googleapis.com/ajax/libs/jquery/1.3.2/jquery.min.js What can I do? EDIT I think I have found where the problem is. My proxy is serving one byte at a time the file, so firefox consume it at that peace. What I don't understand is why Safari and Chrome takes it right away. What I did last night was, leave the FF open all the night to give him change to load the file, my hope was that I got cached and the next time there was no need to go for it. Today in the morning, the page load successfully but the page was not cached, because the next request failed the same. Here's a video showing the problem:

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  • ajax.googleapis.com stopping my Firefox

    - by Oscar Reyes
    Today for some strange reason, Firefox stops working properly because it is trying to fetch something from ajax.googleapis.com. Is there something I can do to avoid this? Safari and Chrome work just fine. I tried uninstalling Firebug and clearing the cache. The only thing that worked was disabling the JavaScript altogether. This seems to be the culprit link: http://ajax.googleapis.com/ajax/libs/jquery/1.3.2/jquery.min.js What can I do? EDIT I think I have found where the problem is. My proxy is serving one byte at a time the file, so firefox consume it at that peace. What I don't understand is why Safari and Chrome takes it right away. What I did last night was, leave the FF open all the night to give him change to load the file, my hope was that I got cached and the next time there was no need to go for it. Today in the morning, the page load successfully but the page was not cached, because the next request failed the same. Here's a video showing the problem:

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  • Anytime I upload something, my internet slows down extremely. What can I do?

    - by Earlz
    Title says it all. For a bit more info though: Basically, I have Time Warner cable internet. My speeds maintain a stable 2Mbit/s upload and 20Mbit/s download with average ping times around 30ms. This crazy thing happens though when I upload anything. I went to upload a 200M file to my server today through sftp and my internet completely choked up. I speed tested it during this upload and my ping time was around 800ms, download speeds of 0.2Mbit/s and Upload speeds of 0.3Mbit/s. Note, I wasn't downloading anything during this time either. It is just straight upload. What is it that causes this phenomenon? My router is OpenBSD. Is there anything I could set up to fix this problem(by queues or some such), or is this a problem with cable internet?

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  • Upload file in Android webview

    - by Sunny
    I have a html form like this <form data-ajax="false" action='UserPhoto.php' class="settings" method='POST' enctype='multipart/form-data' > <input type='file' style="height:25px" name='photo' /> <input type='hidden' name='task' value='upload'> <input type='hidden' name='file_size' value='5000000'> and I want to upload it by using webView posturl function, is it possible? as I know posturl can send String data by this way String value1 = "persistent=1"; String value2 = "&email="+ 2nd_value; String value3 = "&password="+ 3rd_value; String postData = value1+value2+value3; webView.postUrl("http://www.abc.php",EncodingUtils.getBytes(postData, "BASE64")); but is it possible for me to post .png together with some string values? and I know another method using this way to upload photo conn.setRequestProperty("Connection", "Keep-Alive"); conn.setRequestProperty("ENCTYPE", "multipart/form-data"); conn.setRequestProperty("Content-Type", "multipart/form-data;boundary=" + boundary); conn.setRequestProperty("photo", fileName); but this way doesn't communicate with webview, I need to post the photo using webview as user session is kept with it. Thanks for helping.

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  • Zend form and dynamic file upload

    - by DoomStone
    Hello there i'm trying to create a form with Zend_Form that will enable my user to upload a unlited number of files to my site, witch is done by javascript. Something like <script type="text/javascript"> $(document).ready(function(){ var image_uploade_i = 0; $('#upload_more').click(function() { image_uploade_i++; $('#upload_list').append('<div id="image_uploade_id_'+image_uploade_i+'" style="display: none;"><input type="file" name="image[]" /><br /></a>'); $('#image_uploade_id_'+image_uploade_i).slideDown('slow'); }); }); </script> <?=$this->translate('Add images')?> <form action="" method="post" enctype="multipart/form-data"> <div id="upload_list"> <input type="file" name="image[]" /><br /> <input type="file" name="image[]" /><br /> <input type="file" name="image[]" /><br /> </div> <a href="#" id="upload_more"><?=$this->translate('Upload another image')?></a><br /> <input type="submit" name="image_uploade" value="<?=$this->translate('Upload images')?>" /> </form> But i'm am unable to find out how i can create something like this with Zend_From, the only reason i want to use Zend_Form on this thoug is for validation of the uploadet files. $element = new Zend_Form_Element_File('image'); $element->setRequired(true) ->setLabel('Profile image') ->setDestination($store) ->setValueDisabled(true) ->addValidator(new Zend_Validate_File_ImageSize(array( 'minheight' => 100, 'minwidth' => 150, 'maxheight' => 1920, 'maxwidth' => 1200))) // File must be below 1.5 Mb ->addValidator(new Zend_Validate_File_FilesSize(array('max' => 1572864))) ->addValidator(new Zend_Validate_File_IsImage()); If any 1 can help me set this up would i be verry great full :D

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  • WCF Streaming not working at server

    - by Radhi
    hi, i have used WCF service to transfer large files in chunks to the server for that i have reference this article http://kjellsj.blogspot.com/2007/02/wcf-streaming-upload-files-over-http.html i have configured my application on IIS on my machine. its work fine here. it allows upto 64mb file upload but when we have published the site. it allows only maximum 30Mb file if i try to upload more than that i got error 404 - resource not found. here is the binding config i have used. <basicHttpBinding> <!-- buffer: 64KB; max size: 64MB --> <binding name="FileTransferServicesBinding" closeTimeout="00:01:00" openTimeout="00:01:00" receiveTimeout="00:10:00" sendTimeout="00:01:00" transferMode="Streamed" messageEncoding="Mtom" maxBufferSize="65536" maxReceivedMessageSize="67108864"> <security mode="None"> <transport clientCredentialType="None"/> </security> </binding> </basicHttpBinding> please suggest me where i am missing anything. and if required more code please let me know -thanks in advance

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  • Uploading to TwitVid using x_verify_credentials_authorization

    - by deepa
    Hi, I am developing an iPhone application that uploads videos to TwitVid using the library TwitVid-iPhone-OAuth3. I have selected this library since Twitter is shifting to OAuth mechanism of authentication. 1) Does this new library allows to upload without user-name and password parameters? 2) I am using the following steps for uploading videos (assumed that new library allows to upload without user-name and password parameters). But, I am getting the error 'Incorrect Signature'. I am not able to identify the mistake that I am doing here. Could you please help me out to solve this problem. Authenticate the app using OAuth (MGTwitterEngine etc) which redirects the user to the web-page asking for log-in and app authentication. If the user authenticates the app, access token will obtained as final step. Upload the video to TwitVid using the following code snippet: OAuth *authorizer = [[OAuth alloc] initWithConsumerKey: @"my_consumer_key" andConsumerSecret: @"my_consumer_secret"]; authorizer.oauth_token = //The key-part of the access token obtained in step 2 authorizer.oauth_token_secret = //The secret-part of the access token obtained in step 2 authorizer.oauth_token_authorized = YES; //Since authenticated in steps 1 and 2 NSString *authHeader = [authorizer oAuthHeaderForMethod: @"POST" andUrl: @"https://api.twitter.com/1/account/verify_credentials.xml" andParams: nil]; twitVid = [[TwitVid alloc] init]; [mTwitVid setDelegate: self]; [mTwitVid authenticateWithXVerifyCredentialsAuthorization: authHeader xAuthServiceProvider: nil]; Thanks and Regards, Deepa

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  • Basic File upload in GWT

    - by Maksim
    I'm trying to figure out how to upload one file using GWTs FileUpload widget. I'm using GWT and Google AppEngine with Java but I would like to upload file to my own Linux server. I have the following code already but now I can't figure out how to submit my file to the Google AppServer server and save it to another server: public class FileUploader{ private ControlPanel cp; private FormPanel form = new FormPanel(); private FileUpload fu = new FileUpload(); public FileUploader(ControlPanel cp) { this.cp = cp; this.cp.setPrimaryArea(getFileUploaderWidget()); } @SuppressWarnings("deprecation") public Widget getFileUploaderWidget() { form.setEncoding(FormPanel.ENCODING_MULTIPART); form.setMethod(FormPanel.METHOD_POST); // form.setAction(/* WHAT SHOULD I PUT HERE */); VerticalPanel holder = new VerticalPanel(); fu.setName("upload"); holder.add(fu); holder.add(new Button("Submit", new ClickHandler() { public void onClick(ClickEvent event) { GWT.log("You selected: " + fu.getFilename(), null); form.submit(); } })); form.addSubmitHandler(new FormPanel.SubmitHandler() { public void onSubmit(SubmitEvent event) { if (!"".equalsIgnoreCase(fu.getFilename())) { GWT.log("UPLOADING FILE????", null); // NOW WHAT???? } else{ event.cancel(); // cancel the event } } }); form.addSubmitCompleteHandler(new FormPanel.SubmitCompleteHandler() { public void onSubmitComplete(SubmitCompleteEvent event) { Window.alert(event.getResults()); } }); form.add(holder); return form; } } Now, what do I need to do next? What do i need to put in web.xml and how do I write my servlet so i can store file and return url of that object (if possible)

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  • GoDaddy Subdomain Hosting Issue/Question with Disk Access (C#/ASP.NET 3.5)

    - by Vogel
    This isn't a very complicated scenario really, but as I start to type out the problem I'm realizing how convoluted it can become textually. Let me try and be very clear: First, the set up... I have a C#/ASP.NET web application that is publicly facing on my main domain (www), let's call it www.mysite.com. Nothing fancy, just a front-end that connects to SQL to display records. Then, I have a second C#/ASP.NET web application that is secured using forms authentication running on a subdomain, let's call it admin.mysite.com. This is a very light-weight CMS system to administer the public site. Now, the problem... Both of these sites run fine for basic tasks, however, my problem arises when I try to gain access to the file system for uploading. GoDaddy requires subdomains to run as a virtual directories under the main application in IIS (so the subdomains actually resolve/re-direct to www.mysite.com/admin when you type in admin.mysite.com), but because of this I am unable to write to my website root from the subfolder. Let me explain a little more... The CMS system (running as a virtual directory) gives the admin the ability to upload photos for display on the main site, the target folder of which is www.mysite.com/images - when attempting disk access from the root app, I am able to write to the virtual directory, but cannot do the opposite -- that is, write to the root from the virtual directory, getting security violations. If I can only upload to the /admin/ virtual directory, the entire point is moot because it's a secured folder that the public can't see! The only solution I can think of is to upload the files to the /admin/ virtual directory, then call a URL in the root that moves files from /admin/ back to the root, but that is entirely ghetto. I hope this post makes sense. Anyone else experience anything like this? The bottom line is that it seems virtual directories ONLY have access to themselves, and not their parent directories, no matter what credentials are used. Thanks!

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  • How to upload files?

    - by Brian Roisentul
    I just wanted to know how to configure FCKEditor to upload files and images to the server where the website is hosted. The relevant part for it's config file(i think) looks like this: FCKConfig.LinkUpload = true ; FCKConfig.LinkUploadURL = FCKConfig.BasePath + 'filemanager/connectors/' + _QuickUploadLanguage + '/upload.' + _QuickUploadExtension ; FCKConfig.LinkUploadAllowedExtensions = ".(7z|aiff|asf|avi|bmp|csv|doc|fla|flv|gif|gz|gzip|jpeg|jpg|mid|mov|mp3|mp4|mpc|mpeg|mpg|ods|odt|pdf|png|ppt|pxd|qt|ram|rar|rm|rmi|rmvb|rtf|sdc|sitd|swf|sxc|sxw|tar|tgz|tif|tiff|txt|vsd|wav|wma|wmv|xls|xml|zip)$" ; // empty for all FCKConfig.LinkUploadDeniedExtensions = "" ; // empty for no one FCKConfig.ImageUpload = true ; FCKConfig.ImageUploadURL = FCKConfig.BasePath + 'filemanager/connectors/' + _QuickUploadLanguage + '/upload.' + _QuickUploadExtension + '?Type=Image' ; FCKConfig.ImageUploadAllowedExtensions = ".(jpg|gif|jpeg|png|bmp)$" ; // empty for all FCKConfig.ImageUploadDeniedExtensions = "" ; // empty for no one Could it be a folder permission problem? Is this part of the config.js alright?

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  • Image upload - Latin chars problem

    - by Holian
    Dear Gods! I use this script to upload images to serveR: <?php if (($_FILES["image_upload_box"]["type"] == "image/jpeg" || $_FILES["image_upload_box"]["type"] == "image/pjpeg" && ($_FILES["image_upload_box"]["size"] < 2000000)) { $max_upload_width = 450; $max_upload_height = 450; if(isset($_REQUEST['max_width_box']) and $_REQUEST['max_width_box']!='' and $_REQUEST['max_width_box']<=$max_upload_width){ $max_upload_width = $_REQUEST['max_width_box']; } if(isset($_REQUEST['max_height_box']) and $_REQUEST['max_height_box']!='' and $_REQUEST['max_height_box']<=$max_upload_height){ $max_upload_height = $_REQUEST['max_height_box']; } if($_FILES["image_upload_box"]["type"] == "image/jpeg" || $_FILES["image_upload_box"]["type"] == "image/pjpeg"){ $image_source = imagecreatefromjpeg($_FILES["image_upload_box"]["tmp_name"]); } $remote_file =$directory."/".$_FILES["image_upload_box"]["name"]; imagejpeg($image_source,$remote_file,100); chmod($remote_file,0644); list($image_width, $image_height) = getimagesize($remote_file); if($image_width>$max_upload_width || $image_height >$max_upload_height){ $proportions = $image_width/$image_height; if($image_width>$image_height){ $new_width = $max_upload_width; $new_height = round($max_upload_width/$proportions); } else{ $new_height = $max_upload_height; $new_width = round($max_upload_height*$proportions); } $new_image = imagecreatetruecolor($new_width , $new_height); $image_source = imagecreatefromjpeg($remote_file); imagecopyresampled($new_image, $image_source, 0, 0, 0, 0, $new_width, $new_height, $image_width, $image_height); imagejpeg($new_image,$remote_file,100); imagedestroy($new_image); } imagedestroy($image_source); }else{ something.... } ?> This is works well, till i upload a photo with latin chars in filename. For example the filename: kék hegyek.jpg. After upload file name will be: KA©k hegyek.jpg How can i solve this? Thank you

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  • Still don't understand file upload-folder permissions

    - by Camran
    I have checked out articles and tutorials. I don't know what to do about the security of my picture upload-folder. It is pictures for classifieds which should be uploaded to the folder. This is what I want: Anybody may upload images to the folder. The images will be moved to another folder, by another php-code later on (automatic). Only I may manually remove them, as well as another php file on the server which automatically empties the folder after x-days. What should I do here? The images are uploaded via a php-upload script. This script checks to see if the extension of the file is actually a valid image-file. When I try this: chmod 755 images the images wont be uploaded. But like this it works: chmod 777 images But 777 is a security risk right? Please give me detailed information... The Q is, what to do to solve this problem, not info about what permissions there are etc etc... Thanks If you need more info let me know...

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  • My C# UploadFile method successfully uploads a file, but then my UI hangs...

    - by kyrathaba
    I have a simple WinForms test application in C#. Using the following method, I'm able to upload a file when I invoke the method from my button's Click event handler. The only problem is: my Windows Form "freezes". I can't close it using the Close button. I have to end execution from within the IDE (Visual C# 2010 Express edition). Here are the two methods: public void UploadFile(string FullPathFilename) { string filename = Path.GetFileName(FullPathFilename); try { FtpWebRequest request = (FtpWebRequest)WebRequest.Create(_remoteHost + filename); request.Method = WebRequestMethods.Ftp.UploadFile; request.Credentials = new NetworkCredential(_remoteUser, _remotePass); StreamReader sourceStream = new StreamReader(FullPathFilename); byte[] fileContents = Encoding.UTF8.GetBytes(sourceStream.ReadToEnd()); request.ContentLength = fileContents.Length; Stream requestStream = request.GetRequestStream(); requestStream.Write(fileContents, 0, fileContents.Length); FtpWebResponse response = (FtpWebResponse)request.GetResponse(); response.Close(); requestStream.Close(); sourceStream.Close(); } catch (Exception ex) { MessageBox.Show(ex.Message, "Upload error"); } finally { } } which gets called here: private void btnUploadTxtFile_Click(object sender, EventArgs e) { string username = "my_username"; string password = "my_password"; string host = "ftp://mywebsite.com"; try { clsFTPclient client = new clsFTPclient(host + "/httpdocs/non_church/", username, password); client.UploadFile(Path.GetDirectoryName(Application.ExecutablePath) + "\\myTextFile.txt"); } catch (Exception ex) { MessageBox.Show(ex.Message, "Upload problem"); } }

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  • How to use cURL to FTPS upload to SecureTransport (hint: SITE AUTH and client certificates)

    - by Seamus Abshere
    I'm trying to connect to SecureTransport 4.5.1 via FTPS using curl compiled with gnutls. You need to use --ftp-alternative-to-user "SITE AUTH" per http://curl.haxx.se/mail/lib-2006-07/0068.html Do you see anything wrong with my client certificates? I try with # mycert.crt -----BEGIN CERTIFICATE----- ... -----END CERTIFICATE----- # mykey.pem -----BEGIN RSA PRIVATE KEY----- ... -----END RSA PRIVATE KEY----- And it says "530 No client certificate presented": myuser@myserver ~ $ curl -v --ftp-ssl --cert mycert.crt --key mykey.pem --ftp-alternative-to-user "SITE AUTH" -T helloworld.txt ftp://ftp.example.com:9876/upload/ * About to connect() to ftp.example.com port 9876 (#0) * Trying 1.2.3.4... connected * Connected to ftp.example.com (1.2.3.4) port 9876 (#0) < 220 msn1 FTP server (SecureTransport 4.5.1) ready. > AUTH SSL < 334 SSLv23/TLSv1 * found 142 certificates in /etc/ssl/certs/ca-certificates.crt > USER anonymous < 331 Password required for anonymous. > PASS [email protected] < 530 Login incorrect. > SITE AUTH < 530 No client certificate presented. * Access denied: 530 * Closing connection #0 curl: (67) Access denied: 530 I also tried with a pk8 version... # openssl pkcs8 -in mykey.pem -topk8 -nocrypt > mykey.pk8 -----BEGIN CERTIFICATE----- ... -----END CERTIFICATE----- ...but got exactly the same result. What's the trick to sending a client certificate to SecureTransport?

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  • VSFTPD does not allow upload with virtual users

    - by Mr. Squig
    I am attempting to setup VSFTPD with virtual users on a server running Ubuntu 12.04. I have configured the server to allow for virtual users to login, but I am having trouble getting it to allow uploads. My vsftpd.conf is as follows: listen=YES anonymous_enable=NO local_enable=YES write_enable=YES local_umask=022 anon_upload_enable=YES dirmessage_enable=YES use_localtime=YES xferlog_enable=YES connect_from_port_20=YES chroot_local_user=YES virtual_use_local_privs=YES guest_enable=YES guest_username=virtual user_sub_token=$USER local_root=/var/www/$USER hide_ids=YES secure_chroot_dir=/var/run/vsftpd/empty pam_service_name=vsftpd rsa_cert_file=/etc/ssl/private/vsftpd.pem /etc/pam.d/vsftpd contains: auth required pam_pwdfile.so pwdfile /etc/vsftpd.passwd crypt=hash account required pam_permit.so crypt=hash I have two virtual users set up, one of which has the same name as a local user. They each have a directory in /var/www/ owned by 'virtual'. As I understand it, when a virtual user logs in this way they will appear to the system as the user virtual. Using this configuration user can log on, but cannot upload files. The error given in /var/log/vsftpd.log is: Tue Nov 20 19:49:00 2012 [pid 2] CONNECT: Client "96.233.116.53" Tue Nov 20 19:49:07 2012 [pid 1] [zac] OK LOGIN: Client "96.233.116.53" Tue Nov 20 19:49:11 2012 [pid 2] CONNECT: Client "96.233.116.53" Tue Nov 20 19:49:11 2012 [pid 1] [zac] OK LOGIN: Client "96.233.116.53" Tue Nov 20 19:49:11 2012 [pid 3] [zac] FAIL CHMOD: Client "96.233.116.53", "/test.ppm 644" I have tried changing the permissions of these directories in all sorts of ways, but nothing seem to work. I have a feeling that it is something simple related to permissions. Any ideas?

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  • Server not accepting uploads

    - by Tatu Ulmanen
    I'm having a strange problem with my VPS: I can download files from it, I can use PuTTy to connect to it and all behaves normally. But sometimes, when I try to upload a file to the server or save a file via SFTP, the connection inexplicably fails. I am using jEdit to edit files remotely via SFTP. When it works, it works fine. When it doesn't, I get an error message: Cannot save: java.io.IOException: inputstream is closed Cannot save: java.io.IOException: 4: I can see that a temporary save file (#file.php#save#) is created on the server with a filesize of 0. So the connection works, but when it comes to sending the actual data, something fails. The same thing with WinSCP, but the error is different: Copying file fatally failed. Copying files to remote side failed. And I can always browse the server with PuTTy without a problem. I see nothing abnormal in any log files. Auth.log shows this when I try to save: sshd[32638]: Accepted password for - from - port 62272 ssh2 sshd[32638]: pam_unix(sshd:session): session opened for user - by (uid=0) sshd[32640]: subsystem request for sftp sshd[32638]: pam_unix(sshd:session): session closed for user - When I wait for a while (say, an hour), everything works fine again. It can't be a temporary ban, as I am still allowed to connect to the server, right? I know this may not be enough info to solve the problem, but I am grateful for any clues or bits of information that might help me. What are the possible causes for this kind of behaviour, what log files can I check for clues etc.. I'm running out of ideas!

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  • different user group can not upload file in the server

    - by Dallal
    I have a CentOS server running in Thailand, and I'm in Canada. The guy at the computer center who set up the server for me doesn't really understand much about linux and left me off an issue to solve myself. I just moved from Mac Server to Linux server, and the first thing I'm facing a problem now is `file name` has failed to upload due to an error The uploaded file could not be moved to `location name` So what happen is that I knew from my experiences of these problem is all about permissions. So I go ahead and checked on my whole folder and found that everything in the folder permission is like myusername mygroupname then I checked the httpd file in the server and it is default to apache apache. My question is that how can I make my user to be in the same group with apache group so that I don't have to have any problem about uploading, changing data in my file....? But without having to affect other user in the same server. I'm holding Administrator account, but not root account, but I can change stuff on the server root no problem. When I was with godaddy.com there never been any problem about the permission and I wish I know how they configure that :(

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  • ASP.NET MVC File Upload Error - "The input is not a valid Base-64 string"

    - by Justin
    Hey all, I'm trying to add a file upload control to my ASP.NET MVC 2 form but after I select a jpg and click Save, it gives the following error: The input is not a valid Base-64 string as it contains a non-base 64 character, more than two padding characters, or a non-white space character among the padding characters. Here's the view: <% using (Html.BeginForm("Save", "Developers", FormMethod.Post, new {enctype = "multipart/form-data"})) { %> <%: Html.ValidationSummary(true) %> <fieldset> <legend>Fields</legend> <div class="editor-label"> Login Name </div> <div class="editor-field"> <%: Html.TextBoxFor(model => model.LoginName) %> <%: Html.ValidationMessageFor(model => model.LoginName) %> </div> <div class="editor-label"> Password </div> <div class="editor-field"> <%: Html.Password("Password") %> <%: Html.ValidationMessageFor(model => model.Password) %> </div> <div class="editor-label"> First Name </div> <div class="editor-field"> <%: Html.TextBoxFor(model => model.FirstName) %> <%: Html.ValidationMessageFor(model => model.FirstName) %> </div> <div class="editor-label"> Last Name </div> <div class="editor-field"> <%: Html.TextBoxFor(model => model.LastName) %> <%: Html.ValidationMessageFor(model => model.LastName) %> </div> <div class="editor-label"> Photo </div> <div class="editor-field"> <input id="Photo" name="Photo" type="file" /> </div> <p> <%: Html.Hidden("DeveloperID") %> <%: Html.Hidden("CreateDate") %> <input type="submit" value="Save" /> </p> </fieldset> <% } %> And the controller: //POST: /Secure/Developers/Save/ [AcceptVerbs(HttpVerbs.Post)] public ActionResult Save(Developer developer) { //get profile photo. var upload = Request.Files["Photo"]; if (upload.ContentLength > 0) { string savedFileName = Path.Combine( ConfigurationManager.AppSettings["FileUploadDirectory"], "Developer_" + developer.FirstName + "_" + developer.LastName + ".jpg"); upload.SaveAs(savedFileName); } developer.UpdateDate = DateTime.Now; if (developer.DeveloperID == 0) {//inserting new developer. DataContext.DeveloperData.Insert(developer); } else {//attaching existing developer. DataContext.DeveloperData.Attach(developer); } //save changes. DataContext.SaveChanges(); //redirect to developer list. return RedirectToAction("Index"); } Thanks, Justin

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