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  • Rendering Views as String with Spring MVC and Apache Tiles

    - by lynxforest
    I am trying to reuse some of my tiles in a controller which is returning a json response to the client. I would like to return a json response similar to the following format: { 'success': <true or false>, 'response': <the contents of an apache tile> } In my controller I would like to perform logic similar to this pseudocode: boolean valid = validator.validate(modelObj) String response = "" if(valid){ response = successView.render() // im looking for a way to actually accomplish // this, where the successView is the apache tiles view. // I would also need to pass a model map to the view somehow. }else{ response = errorView.render() } writeJsonResponse(httpResponse, /* a Map whose json representation looks like the one I described above. */)

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  • Set Hibernate session's flush mode in Spring

    - by glaz666
    I am writing integration tests and in one test method I'd like to write some data to DB and then read it. @RunWith(SpringJUnit4ClassRunner.class) @ContextConfiguration(locations = {"classpath:applicationContext.xml"}) @TransactionConfiguration() @Transactional public class SimpleIntegrationTest { @Resource private DummyDAO dummyDAO; /** * Tries to store {@link com.example.server.entity.DummyEntity}. */ @Test public void testPersistTestEntity() { int countBefore = dummyDAO.findAll().size(); DummyEntity dummyEntity = new DummyEntity(); dummyDAO.makePersistent(dummyEntity); //HERE SHOULD COME SESSION.FLUSH() int countAfter = dummyDAO.findAll().size(); assertEquals(countBefore + 1, countAfter); } } As you can see between storing and reading data, the session should be flushed because the default FushMode is AUTO thus no data can be actually stored in DB. Question: Can I some how set FlushMode to ALWAYS in session factory or somewhere else to avoid repeating session.flush() call? All DB calls in DAO goes with HibernateTemplate instance. Thanks in advance.

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  • Return to the same view using ModelAndview in Spring MVC framework

    - by ria
    I have a page with a link. On clicking the link a page opens up in a separate window. This new page has a form. On submitting this form, some operation takes place at the server. The result of which needs to be redirected to the same page. However after the operation on using the following: return new ModelAndView("newUser"); //This view "newUser" actually maps to the popped up window. A similar new window again pops up and the message gets displayed on this new page. How to go about this?

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  • Spring MVC referencing params variable from RequestMapping

    - by NomNomNom
    Hi guys, I have the method below: @RequestMapping(value = "/path/to/{iconId}", params="size={iconSize}", method = RequestMethod.GET) public void webletIconData(@PathVariable String iconId, @PathVariable String iconSize, HttpServletResponse response) throws IOException { // Implementation here } I know how to pass the variable "webletId" from the RequestMapping using the @PathVariable, but how do I reference the variable "iconSize" from params? The same way? Thanks a lot.

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  • The penultimate audit trigger framework

    - by Piotr Rodak
    So, it’s time to see what I came up with after some time of playing with COLUMNS_UPDATED() and bitmasks. The first part of this miniseries describes the mechanics of the encoding which columns are updated within DML operation. The task I was faced with was to prepare an audit framework that will be fairly easy to use. The audited tables were to be the ones directly modified by user applications, not the ones heavily used by batch or ETL processes. The framework consists of several tables and procedures...(read more)

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  • Dependency injection with n-tier Entity Framework solution

    - by Matthew
    I am currently designing an n-tier solution which is using Entity Framework 5 (.net 4) as its data access strategy, but am concerned about how to incorporate dependency injection to make it testable / flexible. My current solution layout is as follows (my solution is called Alcatraz): Alcatraz.WebUI: An asp.net webform project, the front end user interface, references projects Alcatraz.Business and Alcatraz.Data.Models. Alcatraz.Business: A class library project, contains the business logic, references projects Alcatraz.Data.Access, Alcatraz.Data.Models Alcatraz.Data.Access: A class library project, houses AlcatrazModel.edmx and AlcatrazEntities DbContext, references projects Alcatraz.Data.Models. Alcatraz.Data.Models: A class library project, contains POCOs for the Alcatraz model, no references. My vision for how this solution would work is the web-ui would instantiate a repository within the business library, this repository would have a dependency (through the constructor) of a connection string (not an AlcatrazEntities instance). The web-ui would know the database connection strings, but not that it was an entity framework connection string. In the Business project: public class InmateRepository : IInmateRepository { private string _connectionString; public InmateRepository(string connectionString) { if (connectionString == null) { throw new ArgumentNullException("connectionString"); } EntityConnectionStringBuilder connectionBuilder = new EntityConnectionStringBuilder(); connectionBuilder.Metadata = "res://*/AlcatrazModel.csdl|res://*/AlcatrazModel.ssdl|res://*/AlcatrazModel.msl"; connectionBuilder.Provider = "System.Data.SqlClient"; connectionBuilder.ProviderConnectionString = connectionString; _connectionString = connectionBuilder.ToString(); } public IQueryable<Inmate> GetAllInmates() { AlcatrazEntities ents = new AlcatrazEntities(_connectionString); return ents.Inmates; } } In the Web UI: IInmateRepository inmateRepo = new InmateRepository(@"data source=MATTHEW-PC\SQLEXPRESS;initial catalog=Alcatraz;integrated security=True;"); List<Inmate> deathRowInmates = inmateRepo.GetAllInmates().Where(i => i.OnDeathRow).ToList(); I have a few related questions about this design. 1) Does this design even make sense in terms of Entity Frameworks capabilities? I heard that Entity framework uses the Unit-of-work pattern already, am I just adding another layer of abstract unnecessarily? 2) I don't want my web-ui to directly communicate with Entity Framework (or even reference it for that matter), I want all database access to go through the business layer as in the future I will have multiple projects using the same business layer (web service, windows application, etc.) and I want to have it easy to maintain / update by having the business logic in one central area. Is this an appropriate way to achieve this? 3) Should the Business layer even contain repositories, or should that be contained within the Access layer? If where they are is alright, is passing a connection string a good dependency to assume? Thanks for taking the time to read!

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  • Using multiple diagrams per model in Entity Framework 5.0

    - by nikolaosk
    I have downloaded .Net framework 4.5 and Visual Studio 2012 since it was released to MSDN subscribers on the 15th of August.For people that do not know about that yet please have a look at Jason Zander's excellent blog post .Since then I have been investigating the many new features that have been introduced in this release.In this post I will be looking into theIn order to follow along this post you must have Visual Studio 2012 and .Net Framework 4.5 installed in your machine.Download and install VS 20120 using this link.My machine runs on Windows 8 and Visual Studio 2012 works just fine. I have also installed in my machine SQL Server 2012 developer edition. I have also downloaded and installed AdventureWorksLT2012 database.You can download this database from the codeplex website.   Before I start showcasing the demo I want to say that I strongly believe that Entity Framework is maturing really fast and now at version 5.0 can be used as your data access layer in all your .Net projects.I have posted extensively about Entity Framework in my blog.Please find all the EF related posts here. In this demo I will show you how to split an entity model into multiple diagrams using the new enhanced EF designer. We will not build an application in this demo.Sometimes our model can become too large to edit or view.In earlier versions we could only have one diagram per EDMX file.In EF 5.0 we can split the model into more diagrams.1) Launch VS 2012. Express edition will work fine.2) Create a New Project. From the available templates choose a Web Forms application  3) Add a new item in your project, an ADO.Net Entity Data Model. I have named it AdventureWorksLT.edmx.Then we will create the model from the database and click Next.Create a new connection by specifying the SQL Server instance and the database name and click OK.Then click Next in the wizard.In the next screen of the wizard select all the tables from the database and hit Finish.4) It will take a while for our .edmx diagram to be created. When I select an Entity (e.g Customer) from my diagram and right click on it,a new option appears "Move to new Diagram".Make sure you have the Model Browser window open.Have a look at the picture below 5) When we do that a new diagram is created and our new Entity is moved there.Have a look at the picture below  6) We can also right-click and include the related entities. Have a look at the picture below. 7) When we do that the related entities are copied to the new diagram.Have a look at the picture below  8) Now we can cut (CTRL+X) the entities from Diagram2 and paste them back to Diagram1.9) Finally another great enhancement of the EF 5.0 designer is that you can change colors in the various entities that make up the model.Select the entities you want to change color, then in the Properties window choose the color of your choice. Have a look at the picture below. To recap we have demonstrated how to split your entity model in multiple diagrams which comes handy in EF models that have a large number of entities in them Hope it helps!!!!

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  • Entity Framework DateTime update extremely slow

    - by Phyxion
    I have this situation currently with Entity Framework: using (TestEntities dataContext = DataContext) { UserSession session = dataContext.UserSessions.FirstOrDefault(userSession => userSession.Id == SessionId); if (session != null) { session.LastAvailableDate = DateTime.Now; dataContext.SaveChanges(); } } This is all working perfect, except for the fact that it is terribly slow compared to what I expect (14 calls per second, tested with 100 iterations). When I update this record manually through this command: dataContext.Database.ExecuteSqlCommand(String.Format("update UserSession set LastAvailableDate = '{0}' where Id = '{1}'", DateTime.Now.ToString("yyyy-MM-dd HH:mm:ss.fffffff"), SessionId)); I get 55 calls per second, which is more than fast enough. However, when I don't update the session.LastAvailableDate but I update an integer (e.g. session.UserId) or string with Entity Framework, I get 50 calls per second, which is also more than fast enough. Only the datetime field is terrible slow. The difference of a factor 4 is unacceptable and I was wondering how I can improve this as I don't prefer using direct SQL when I can also use the Entity Framework. I'm using Entity Framework 4.3.1 (also tried 4.1).

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  • Looking into Enum Support in Entity Framework 5.0 Code First

    - by nikolaosk
    In this post I will show you with a hands-on demo the enum support that is available in Visual Studio 2012, .Net Framework 4.5 and Entity Framework 5.0. You can have a look at this post to learn about the support of multilple diagrams per model that exists in Entity Framework 5.0. We will demonstrate this with a step by step example. I will use Visual Studio 2012 Ultimate. You can also use Visual Studio 2012 Express Edition. Before I move on to the actual demo I must say that in EF 5.0 an enumeration can have the following types. Byte Int16 Int32 Int64 Sbyte Obviously I cannot go into much detail on what EF is and what it does. I will give again a short introduction.The .Net framework provides support for Object Relational Mapping through EF. So EF is a an ORM tool and it is now the main data access technology that microsoft works on. I use it quite extensively in my projects. Through EF we have many things out of the box provided for us. We have the automatic generation of SQL code.It maps relational data to strongly types objects.All the changes made to the objects in the memory are persisted in a transactional way back to the data store. You can find in this post an example on how to use the Entity Framework to retrieve data from an SQL Server Database using the "Database/Schema First" approach. In this approach we make all the changes at the database level and then we update the model with those changes. In this post you can see an example on how to use the "Model First" approach when working with ASP.Net and the Entity Framework. This model was firstly introduced in EF version 4.0 and we could start with a blank model and then create a database from that model.When we made changes to the model , we could recreate the database from the new model. You can search in my blog, because I have posted many posts regarding ASP.Net and EF. I assume you have a working knowledge of C# and know a few things about EF. The Code First approach is the more code-centric than the other two. Basically we write POCO classes and then we persist to a database using something called DBContext. Code First relies on DbContext. We create 2,3 classes (e.g Person,Product) with properties and then these classes interact with the DbContext class. We can create a new database based upon our POCOS classes and have tables generated from those classes.We do not have an .edmx file in this approach.By using this approach we can write much easier unit tests. DbContext is a new context class and is smaller,lightweight wrapper for the main context class which is ObjectContext (Schema First and Model First). Let's begin building our sample application. 1) Launch Visual Studio. Create an ASP.Net Empty Web application. Choose an appropriate name for your application. 2) Add a web form, default.aspx page to the application. 3) Now we need to make sure the Entity Framework is included in our project. Go to Solution Explorer, right-click on the project name.Then select Manage NuGet Packages...In the Manage NuGet Packages dialog, select the Online tab and choose the EntityFramework package.Finally click Install. Have a look at the picture below   4) Create a new folder. Name it CodeFirst . 5) Add a new item in your application, a class file. Name it Footballer.cs. This is going to be a simple POCO class.Place it in the CodeFirst folder. The code follows public class Footballer { public int FootballerID { get; set; } public string FirstName { get; set; } public string LastName { get; set; } public double Weight { get; set; } public double Height { get; set; } public DateTime JoinedTheClub { get; set; } public int Age { get; set; } public List<Training> Trainings { get; set; } public FootballPositions Positions { get; set; } }    Now I am going to define my enum values in the same class file, Footballer.cs    public enum FootballPositions    {        Defender,        Midfielder,        Striker    } 6) Now we need to create the Training class. Add a new class to your application and place it in the CodeFirst folder.The code for the class follows.     public class Training     {         public int TrainingID { get; set; }         public int TrainingDuration { get; set; }         public string TrainingLocation { get; set; }     }   7) Then we need to create a context class that inherits from DbContext.Add a new class to the CodeFirst folder.Name it FootballerDBContext.Now that we have the entity classes created, we must let the model know.I will have to use the DbSet<T> property.The code for this class follows       public class FootballerDBContext:DbContext     {         public DbSet<Footballer> Footballers { get; set; }         public DbSet<Training> Trainings { get; set; }     } Do not forget to add  (using System.Data.Entity;) in the beginning of the class file 8) We must take care of the connection string. It is very easy to create one in the web.config.It does not matter that we do not have a database yet.When we run the DbContext and query against it,it will use a connection string in the web.config and will create the database based on the classes. In my case the connection string inside the web.config, looks like this      <connectionStrings>    <add name="CodeFirstDBContext"  connectionString="server=.\SqlExpress;integrated security=true;"  providerName="System.Data.SqlClient"/>                       </connectionStrings>   9) Now it is time to create Linq to Entities queries to retrieve data from the database . Add a new class to your application in the CodeFirst folder.Name the file DALfootballer.cs We will create a simple public method to retrieve the footballers. The code for the class follows public class DALfootballer     {         FootballerDBContext ctx = new FootballerDBContext();         public List<Footballer> GetFootballers()         {             var query = from player in ctx.Footballers where player.FirstName=="Jamie" select player;             return query.ToList();         }     }   10) Place a GridView control on the Default.aspx page and leave the default name.Add an ObjectDataSource control on the Default.aspx page and leave the default name. Set the DatasourceID property of the GridView control to the ID of the ObjectDataSource control.(DataSourceID="ObjectDataSource1" ). Let's configure the ObjectDataSource control. Click on the smart tag item of the ObjectDataSource control and select Configure Data Source. In the Wizzard that pops up select the DALFootballer class and then in the next step choose the GetFootballers() method.Click Finish to complete the steps of the wizzard. Build your application.  11)  Let's create an Insert method in order to insert data into the tables. I will create an Insert() method and for simplicity reasons I will place it in the Default.aspx.cs file. private void Insert()        {            var footballers = new List<Footballer>            {                new Footballer {                                 FirstName = "Steven",LastName="Gerrard", Height=1.85, Weight=85,Age=32, JoinedTheClub=DateTime.Parse("12/12/1999"),Positions=FootballPositions.Midfielder,                Trainings = new List<Training>                             {                                     new Training {TrainingDuration = 3, TrainingLocation="MelWood"},                    new Training {TrainingDuration = 2, TrainingLocation="Anfield"},                    new Training {TrainingDuration = 2, TrainingLocation="MelWood"},                }                            },                            new Footballer {                                  FirstName = "Jamie",LastName="Garragher", Height=1.89, Weight=89,Age=34, JoinedTheClub=DateTime.Parse("12/02/2000"),Positions=FootballPositions.Defender,                Trainings = new List<Training>                                             {                                 new Training {TrainingDuration = 3, TrainingLocation="MelWood"},                new Training {TrainingDuration = 5, TrainingLocation="Anfield"},                new Training {TrainingDuration = 6, TrainingLocation="Anfield"},                }                           }                    };            footballers.ForEach(foot => ctx.Footballers.Add(foot));            ctx.SaveChanges();        }   12) In the Page_Load() event handling routine I called the Insert() method.        protected void Page_Load(object sender, EventArgs e)        {                   Insert();                }  13) Run your application and you will see that the following result,hopefully. You can see clearly that the data is returned along with the enum value.  14) You must have also a look at the database.Launch SSMS and see the database and its objects (data) created from EF Code First.Have a look at the picture below. Hopefully now you have seen the support that exists in EF 5.0 for enums.Hope it helps !!!

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  • Execute TSQL statement with ExecuteStoreQuery in entity framework 4.0

    - by Jalpesh P. Vadgama
    I was playing with entity framework in recent days and I was searching something that how we can execute TSQL statement in entity framework. And I have found one great way to do that with entity framework ‘ExecuteStoreQuery’ method. It’s executes a TSQL statement against data source given enity framework context and returns strongly typed result. You can find more information about ExcuteStoreQuery from following link. http://msdn.microsoft.com/en-us/library/dd487208.aspx So let’s examine how it works. So Let’s first create a table against which we are going to execute TSQL statement. So I have added a SQL Express database as following. Now once we are done with adding a database let’s add a table called Client like following. Here you can see above Client table is very simple. There are only two fields ClientId and ClientName where ClientId is primary key and ClientName is field where we are going to store client name. Now it’s time to add some data to the table. So I have added some test data like following. Now it’s time to add entity framework model class. So right click project->Add new item and select ADO.NET entity model as following. After clicking on add button a wizard will start it will ask whether we need to create model classes from database or not but we already have our client table ready so I have selected generate from database as following. Once you process further in wizard it will be presented a screen where we can select the our table like following. Now once you click finish it will create model classes with for us. Now we need a gridview control where we need to display those data. So in Default.aspx page I have added a grid control like following. <%@ Page Title="Home Page" Language="C#" MasterPageFile="~/Site.master" AutoEventWireup="true" CodeBehind="Default.aspx.cs" Inherits="EntityFramework._Default" %> <asp:Content ID="HeaderContent" runat="server" ContentPlaceHolderID="HeadContent"> </asp:Content> <asp:Content ID="BodyContent" runat="server" ContentPlaceHolderID="MainContent"> <h2> Welcome to ASP.NET! </h2> <p> To learn more about ASP.NET visit <a href="http://www.asp.net" title="ASP.NET Website">www.asp.net</a>. </p> <p> You can also find <a href="http://go.microsoft.com/fwlink/?LinkID=152368&amp;clcid=0x409" title="MSDN ASP.NET Docs">documentation on ASP.NET at MSDN</a>. <asp:GridView ID="grdClient" runat="server"> </asp:GridView> </p> </asp:Content> Now once we are done with adding Gridview its time to write code for server side. So I have written following code in Page_load event of default.aspx page. protected void Page_Load(object sender, EventArgs e) { if (!Page.IsPostBack) { using (var context = new EntityFramework.TestEntities()) { ObjectResult<Client> result = context.ExecuteStoreQuery<Client>("Select * from Client"); grdClient.DataSource = result; grdClient.DataBind(); } } } Here in the above code you can see that I have written create a object of our entity model and then with the help of the ExecuteStoreQuery method I have execute a simple select TSQL statement which will return a object result. I have bind that object result with gridview to display data. So now we are done with coding.So let’s run application in browser. Following is output as expected. That’s it. Hope you like it. Stay tuned for more..Till then happy programming.

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  • Where is .NET Framework 4.5 directory located?

    - by Evgeni Nabokov
    I installed .NET Framework 4.5 on Windows 7 Enterprise SP1 64 bit. When I looked in C:\Windows\Microsoft.NET\Framework (Framework64) directory, I did not see any directory containing files of .NET Framework 4.5, just those: v1.0.3705 v1.1.4322 v2.0.50727 v3.0 v3.5 v4.0.30319 Installing the .NET Framework 4.5 says: The .NET Framework 4.5 replaces the .NET Framework 4. When you install the .NET Framework 4.5 on a system that has the .NET Framework 4 installed, the assemblies are replaced. Thereby, 4.5's files are located in v4.0.30319 directory. Am I right?

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  • Spring, JPA, Hibernate, Jetty 7 Integration

    - by Jewel
    Have anyone successfully run any spring and JPA application in jetty 7? I am getting following exception. This application throws no error in jetty 6. INFO [main] org.eclipse.jetty.util.log - Logging to org.slf4j.impl.Log4jLoggerAdapter(org.eclipse.jetty.util.log) via org.eclipse.jetty.util.log.Slf4jLog INFO [main] org.eclipse.jetty.util.log - jetty-7.1.2.v20100523 INFO [main] org.eclipse.jetty.util.log - Deployment monitor G:\_Java\_Jetty\jetty-distribution-7.1.2.v20100523\contexts at interval 5 INFO [main] org.eclipse.jetty.util.log - Deployment monitor G:\_Java\_Jetty\jetty-distribution-7.1.2.v20100523\webapps at interval 5 INFO [main] org.eclipse.jetty.util.log - Deployable added: G:\_Java\_Jetty\jetty-distribution-7.1.2.v20100523\webapps\gwtrpc-spring.war INFO [main] org.eclipse.jetty.util.log - Copying WEB-INF/lib jar:file:/G:/_Java/_Jetty/jetty-distribution-7.1.2.v20100523/webapps/gwtrpc-spring.war!/WEB-INF/lib/ to C:\Documents and Settings\Jewel2\Local Settings\Temp\Jetty_0_0_0_0_8080_gwtrpc.spring.war__gwtrpc.spring__az1wdj\webinf\WEB-INF\lib INFO [main] org.eclipse.jetty.util.log - Copying WEB-INF/classes from jar:file:/G:/_Java/_Jetty/jetty-distribution-7.1.2.v20100523/webapps/gwtrpc-spring.war!/WEB-INF/classes/ to C:\Documents and Settings\Jewel2\Local Settings\Temp\Jetty_0_0_0_0_8080_gwtrpc.spring.war__gwtrpc.spring__az1wdj\webinf\WEB-INF\classes INFO [main] /gwtrpc-spring - Initializing Spring root WebApplicationContext INFO [main] org.springframework.web.context.ContextLoader - Root WebApplicationContext: initialization started INFO [main] org.springframework.web.context.support.XmlWebApplicationContext - Refreshing Root WebApplicationContext: startup date [Thu Jun 10 00:13:32 GMT+06:00 2010]; root of context hierarchy INFO [main] org.springframework.beans.factory.xml.XmlBeanDefinitionReader - Loading XML bean definitions from ServletContext resource [/WEB-INF/applicationContext.xml] INFO [main] org.springframework.beans.factory.support.DefaultListableBeanFactory - Pre-instantiating singletons in org.springframework.beans.factory.support.DefaultListableBeanFactory@467991: defining beans [org.springframework.context.annotation.internalConfigurationAnnotationProcessor,org.springframework.context.annotation.internalAutowiredAnnotationProcessor,org.springframework.context.annotation.internalRequiredAnnotationProcessor,org.springframework.context.annotation.internalCommonAnnotationProcessor,org.springframework.context.annotation.internalPersistenceAnnotationProcessor,greetingServiceImpl,testService,testService2,taskExecutor,dataSource,entityManagerFactory,org.springframework.aop.config.internalAutoProxyCreator,org.springframework.transaction.annotation.AnnotationTransactionAttributeSource#0,org.springframework.transaction.interceptor.TransactionInterceptor#0,org.springframework.transaction.config.internalTransactionAdvisor,transactionManager,org.springframework.orm.jpa.support.PersistenceAnnotationBeanPostProcessor#0]; root of factory hierarchy INFO [main] org.springframework.scheduling.concurrent.ThreadPoolTaskExecutor - Initializing ExecutorService 'taskExecutor' INFO [main] org.springframework.jdbc.datasource.DriverManagerDataSource - Loaded JDBC driver: com.mysql.jdbc.Driver INFO [main] org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean - Building JPA container EntityManagerFactory for persistence unit 'gwtrpc-spring-data-source' INFO [main] org.hibernate.cfg.annotations.Version - Hibernate Annotations 3.4.0.GA INFO [main] org.hibernate.cfg.Environment - Hibernate 3.3.1.GA INFO [main] org.hibernate.cfg.Environment - hibernate.properties not found INFO [main] org.hibernate.cfg.Environment - Bytecode provider name : javassist INFO [main] org.hibernate.cfg.Environment - using JDK 1.4 java.sql.Timestamp handling INFO [main] org.hibernate.annotations.common.Version - Hibernate Commons Annotations 3.1.0.GA INFO [main] org.hibernate.ejb.Version - Hibernate EntityManager 3.4.0.GA INFO [main] org.hibernate.ejb.Ejb3Configuration - Processing PersistenceUnitInfo [ name: gwtrpc-spring-data-source ...] INFO [main] org.springframework.beans.factory.support.DefaultListableBeanFactory - Destroying singletons in org.springframework.beans.factory.support.DefaultListableBeanFactory@467991: defining beans [org.springframework.context.annotation.internalConfigurationAnnotationProcessor,org.springframework.context.annotation.internalAutowiredAnnotationProcessor,org.springframework.context.annotation.internalRequiredAnnotationProcessor,org.springframework.context.annotation.internalCommonAnnotationProcessor,org.springframework.context.annotation.internalPersistenceAnnotationProcessor,greetingServiceImpl,testService,testService2,taskExecutor,dataSource,entityManagerFactory,org.springframework.aop.config.internalAutoProxyCreator,org.springframework.transaction.annotation.AnnotationTransactionAttributeSource#0,org.springframework.transaction.interceptor.TransactionInterceptor#0,org.springframework.transaction.config.internalTransactionAdvisor,transactionManager,org.springframework.orm.jpa.support.PersistenceAnnotationBeanPostProcessor#0]; root of factory hierarchy INFO [main] org.springframework.scheduling.concurrent.ThreadPoolTaskExecutor - Shutting down ExecutorService 'taskExecutor' ERROR [main] org.springframework.web.context.ContextLoader - Context initialization failed org.springframework.beans.factory.BeanCreationException: Error creating bean with name 'entityManagerFactory' defined in ServletContext resource [/WEB-INF/applicationContext.xml]: Invocation of init method failed; nested exception is javax.persistence.PersistenceException: [PersistenceUnit: gwtrpc-spring-data-source] class or package not found at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.initializeBean(AbstractAutowireCapableBeanFactory.java:1403) at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.doCreateBean(AbstractAutowireCapableBeanFactory.java:513) at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.createBean(AbstractAutowireCapableBeanFactory.java:450) at org.springframework.beans.factory.support.AbstractBeanFactory$1.getObject(AbstractBeanFactory.java:290) at org.springframework.beans.factory.support.DefaultSingletonBeanRegistry.getSingleton(DefaultSingletonBeanRegistry.java:222) at org.springframework.beans.factory.support.AbstractBeanFactory.doGetBean(AbstractBeanFactory.java:287) at org.springframework.beans.factory.support.AbstractBeanFactory.getBean(AbstractBeanFactory.java:189) at org.springframework.beans.factory.support.DefaultListableBeanFactory.preInstantiateSingletons(DefaultListableBeanFactory.java:545) at org.springframework.context.support.AbstractApplicationContext.finishBeanFactoryInitialization(AbstractApplicationContext.java:871) at org.springframework.context.support.AbstractApplicationContext.refresh(AbstractApplicationContext.java:423) at org.springframework.web.context.ContextLoader.createWebApplicationContext(ContextLoader.java:272) at org.springframework.web.context.ContextLoader.initWebApplicationContext(ContextLoader.java:196) at org.springframework.web.context.ContextLoaderListener.contextInitialized(ContextLoaderListener.java:47) at org.eclipse.jetty.server.handler.ContextHandler.startContext(ContextHandler.java:636) at org.eclipse.jetty.servlet.ServletContextHandler.startContext(ServletContextHandler.java:188) at org.eclipse.jetty.webapp.WebAppContext.startContext(WebAppContext.java:995) at org.eclipse.jetty.server.handler.ContextHandler.doStart(ContextHandler.java:579) at org.eclipse.jetty.webapp.WebAppContext.doStart(WebAppContext.java:381) at org.eclipse.jetty.util.component.AbstractLifeCycle.start(AbstractLifeCycle.java:55) at org.eclipse.jetty.deploy.bindings.StandardStarter.processBinding(StandardStarter.java:36) at org.eclipse.jetty.deploy.AppLifeCycle.runBindings(AppLifeCycle.java:182) at org.eclipse.jetty.deploy.DeploymentManager.requestAppGoal(DeploymentManager.java:497) at org.eclipse.jetty.deploy.DeploymentManager.addApp(DeploymentManager.java:135) at org.eclipse.jetty.deploy.providers.ScanningAppProvider$1.fileAdded(ScanningAppProvider.java:61) at org.eclipse.jetty.util.Scanner.reportAddition(Scanner.java:436) at org.eclipse.jetty.util.Scanner.reportDifferences(Scanner.java:349) at org.eclipse.jetty.util.Scanner.scan(Scanner.java:306) at org.eclipse.jetty.util.Scanner.start(Scanner.java:242) at org.eclipse.jetty.deploy.providers.ScanningAppProvider.doStart(ScanningAppProvider.java:136) at org.eclipse.jetty.util.component.AbstractLifeCycle.start(AbstractLifeCycle.java:55) at org.eclipse.jetty.deploy.DeploymentManager.startAppProvider(DeploymentManager.java:562) at org.eclipse.jetty.deploy.DeploymentManager.doStart(DeploymentManager.java:212) at org.eclipse.jetty.util.component.AbstractLifeCycle.start(AbstractLifeCycle.java:55) at org.eclipse.jetty.server.Server.doStart(Server.java:209) at org.eclipse.jetty.util.component.AbstractLifeCycle.start(AbstractLifeCycle.java:55) at org.eclipse.jetty.xml.XmlConfiguration$1.run(XmlConfiguration.java:1018) at java.security.AccessController.doPrivileged(Native Method) at org.eclipse.jetty.xml.XmlConfiguration.main(XmlConfiguration.java:983) at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method) at sun.reflect.NativeMethodAccessorImpl.invoke(Unknown Source) at sun.reflect.DelegatingMethodAccessorImpl.invoke(Unknown Source) at java.lang.reflect.Method.invoke(Unknown Source) at org.eclipse.jetty.start.Main.invokeMain(Main.java:447) at org.eclipse.jetty.start.Main.start(Main.java:605) at org.eclipse.jetty.start.Main.parseCommandLine(Main.java:238) at org.eclipse.jetty.start.Main.main(Main.java:77) Caused by: javax.persistence.PersistenceException: [PersistenceUnit: gwtrpc-spring-data-source] class or package not found at org.hibernate.ejb.Ejb3Configuration.addNamedAnnotatedClasses(Ejb3Configuration.java:1093) at org.hibernate.ejb.Ejb3Configuration.addClassesToSessionFactory(Ejb3Configuration.java:871) at org.hibernate.ejb.Ejb3Configuration.configure(Ejb3Configuration.java:758) at org.hibernate.ejb.Ejb3Configuration.configure(Ejb3Configuration.java:425) at org.hibernate.ejb.HibernatePersistence.createContainerEntityManagerFactory(HibernatePersistence.java:131) at org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean.createNativeEntityManagerFactory(LocalContainerEntityManagerFactoryBean.java:225) at org.springframework.orm.jpa.AbstractEntityManagerFactoryBean.afterPropertiesSet(AbstractEntityManagerFactoryBean.java:308) at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.invokeInitMethods(AbstractAutowireCapableBeanFactory.java:1460) at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.initializeBean(AbstractAutowireCapableBeanFactory.java:1400) ... 45 more Caused by: java.lang.ClassNotFoundException: WEB-INF.classes.org.gwtrpcspring.example.server.Person at java.net.URLClassLoader$1.run(Unknown Source) at java.security.AccessController.doPrivileged(Native Method) at java.net.URLClassLoader.findClass(Unknown Source) at java.lang.ClassLoader.loadClass(Unknown Source) at java.lang.ClassLoader.loadClass(Unknown Source) at java.lang.ClassLoader.loadClassInternal(Unknown Source) at java.lang.Class.forName0(Native Method) at java.lang.Class.forName(Unknown Source) at org.hibernate.util.ReflectHelper.classForName(ReflectHelper.java:135) at org.hibernate.ejb.Ejb3Configuration.classForName(Ejb3Configuration.java:1009) at org.hibernate.ejb.Ejb3Configuration.addNamedAnnotatedClasses(Ejb3Configuration.java:1081) ... 53 more WARN [main] org.eclipse.jetty.util.log - Failed startup of context WebAppContext@149f041@149f041/gwtrpc-spring,file:/C:/Documents and Settings/Jewel2/Local Settings/Temp/Jetty_0_0_0_0_8080_gwtrpc.spring.war__gwtrpc.spring__az1wdj/webinf/;jar:file:/G:/_Java/_Jetty/jetty-distribution-7.1.2.v20100523/webapps/gwtrpc-spring.war!/;,G:\_Java\_Jetty\jetty-distribution-7.1.2.v20100523\webapps\gwtrpc-spring.war org.springframework.beans.factory.BeanCreationException: Error creating bean with name 'entityManagerFactory' defined in ServletContext resource [/WEB-INF/applicationContext.xml]: Invocation of init method failed; nested exception is javax.persistence.PersistenceException: [PersistenceUnit: gwtrpc-spring-data-source] class or package not found at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.initializeBean(AbstractAutowireCapableBeanFactory.java:1403) at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.doCreateBean(AbstractAutowireCapableBeanFactory.java:513) at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.createBean(AbstractAutowireCapableBeanFactory.java:450) at org.springframework.beans.factory.support.AbstractBeanFactory$1.getObject(AbstractBeanFactory.java:290) at org.springframework.beans.factory.support.DefaultSingletonBeanRegistry.getSingleton(DefaultSingletonBeanRegistry.java:222) at org.springframework.beans.factory.support.AbstractBeanFactory.doGetBean(AbstractBeanFactory.java:287) at org.springframework.beans.factory.support.AbstractBeanFactory.getBean(AbstractBeanFactory.java:189) at org.springframework.beans.factory.support.DefaultListableBeanFactory.preInstantiateSingletons(DefaultListableBeanFactory.java:545) at org.springframework.context.support.AbstractApplicationContext.finishBeanFactoryInitialization(AbstractApplicationContext.java:871) at org.springframework.context.support.AbstractApplicationContext.refresh(AbstractApplicationContext.java:423) at org.springframework.web.context.ContextLoader.createWebApplicationContext(ContextLoader.java:272) at org.springframework.web.context.ContextLoader.initWebApplicationContext(ContextLoader.java:196) at org.springframework.web.context.ContextLoaderListener.contextInitialized(ContextLoaderListener.java:47) at org.eclipse.jetty.server.handler.ContextHandler.startContext(ContextHandler.java:636) at org.eclipse.jetty.servlet.ServletContextHandler.startContext(ServletContextHandler.java:188) at org.eclipse.jetty.webapp.WebAppContext.startContext(WebAppContext.java:995) at org.eclipse.jetty.server.handler.ContextHandler.doStart(ContextHandler.java:579) at org.eclipse.jetty.webapp.WebAppContext.doStart(WebAppContext.java:381) at org.eclipse.jetty.util.component.AbstractLifeCycle.start(AbstractLifeCycle.java:55) at org.eclipse.jetty.deploy.bindings.StandardStarter.processBinding(StandardStarter.java:36) at org.eclipse.jetty.deploy.AppLifeCycle.runBindings(AppLifeCycle.java:182) at org.eclipse.jetty.deploy.DeploymentManager.requestAppGoal(DeploymentManager.java:497) at org.eclipse.jetty.deploy.DeploymentManager.addApp(DeploymentManager.java:135) at org.eclipse.jetty.deploy.providers.ScanningAppProvider$1.fileAdded(ScanningAppProvider.java:61) at org.eclipse.jetty.util.Scanner.reportAddition(Scanner.java:436) at org.eclipse.jetty.util.Scanner.reportDifferences(Scanner.java:349) at org.eclipse.jetty.util.Scanner.scan(Scanner.java:306) at org.eclipse.jetty.util.Scanner.start(Scanner.java:242) at org.eclipse.jetty.deploy.providers.ScanningAppProvider.doStart(ScanningAppProvider.java:136) at org.eclipse.jetty.util.component.AbstractLifeCycle.start(AbstractLifeCycle.java:55) at org.eclipse.jetty.deploy.DeploymentManager.startAppProvider(DeploymentManager.java:562) at org.eclipse.jetty.deploy.DeploymentManager.doStart(DeploymentManager.java:212) at org.eclipse.jetty.util.component.AbstractLifeCycle.start(AbstractLifeCycle.java:55) at org.eclipse.jetty.server.Server.doStart(Server.java:209) at org.eclipse.jetty.util.component.AbstractLifeCycle.start(AbstractLifeCycle.java:55) at org.eclipse.jetty.xml.XmlConfiguration$1.run(XmlConfiguration.java:1018) at java.security.AccessController.doPrivileged(Native Method) at org.eclipse.jetty.xml.XmlConfiguration.main(XmlConfiguration.java:983) at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method) at sun.reflect.NativeMethodAccessorImpl.invoke(Unknown Source) at sun.reflect.DelegatingMethodAccessorImpl.invoke(Unknown Source) at java.lang.reflect.Method.invoke(Unknown Source) at org.eclipse.jetty.start.Main.invokeMain(Main.java:447) at org.eclipse.jetty.start.Main.start(Main.java:605) at org.eclipse.jetty.start.Main.parseCommandLine(Main.java:238) at org.eclipse.jetty.start.Main.main(Main.java:77) Caused by: javax.persistence.PersistenceException: [PersistenceUnit: gwtrpc-spring-data-source] class or package not found at org.hibernate.ejb.Ejb3Configuration.addNamedAnnotatedClasses(Ejb3Configuration.java:1093) at org.hibernate.ejb.Ejb3Configuration.addClassesToSessionFactory(Ejb3Configuration.java:871) at org.hibernate.ejb.Ejb3Configuration.configure(Ejb3Configuration.java:758) at org.hibernate.ejb.Ejb3Configuration.configure(Ejb3Configuration.java:425) at org.hibernate.ejb.HibernatePersistence.createContainerEntityManagerFactory(HibernatePersistence.java:131) at org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean.createNativeEntityManagerFactory(LocalContainerEntityManagerFactoryBean.java:225) at org.springframework.orm.jpa.AbstractEntityManagerFactoryBean.afterPropertiesSet(AbstractEntityManagerFactoryBean.java:308) at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.invokeInitMethods(AbstractAutowireCapableBeanFactory.java:1460) at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.initializeBean(AbstractAutowireCapableBeanFactory.java:1400) ... 45 more Caused by: java.lang.ClassNotFoundException: WEB-INF.classes.org.gwtrpcspring.example.server.Person at java.net.URLClassLoader$1.run(Unknown Source) at java.security.AccessController.doPrivileged(Native Method) at java.net.URLClassLoader.findClass(Unknown Source) at java.lang.ClassLoader.loadClass(Unknown Source) at java.lang.ClassLoader.loadClass(Unknown Source) at java.lang.ClassLoader.loadClassInternal(Unknown Source) at java.lang.Class.forName0(Native Method) at java.lang.Class.forName(Unknown Source) at org.hibernate.util.ReflectHelper.classForName(ReflectHelper.java:135) at org.hibernate.ejb.Ejb3Configuration.classForName(Ejb3Configuration.java:1009) at org.hibernate.ejb.Ejb3Configuration.addNamedAnnotatedClasses(Ejb3Configuration.java:1081) ... 53 more INFO [main] org.eclipse.jetty.util.log - Started [email protected]:8080 And this is my applicationContext.xml file <?xml version="1.0" encoding="UTF-8"?> <beans> <context:annotation-config /> <context:component-scan base-package="org.gwtrpcspring.example.server" /> <bean id="taskExecutor" class="org.springframework.scheduling.concurrent.ThreadPoolTaskExecutor"> <property name="corePoolSize" value="5" /> <property name="maxPoolSize" value="10" /> <property name="queueCapacity" value="25" /> </bean> <bean id="dataSource" class="org.springframework.jdbc.datasource.DriverManagerDataSource"> <property name="driverClassName" value="com.mysql.jdbc.Driver" /> <property name="url" value="jdbc:mysql://localhost:3306/test" /> <property name="username" value="jewel" /> <property name="password" value="jewel" /> </bean> <bean id="entityManagerFactory" class="org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean"> <property name="dataSource" ref="dataSource" /> <property name="jpaVendorAdapter"> <bean class="org.springframework.orm.jpa.vendor.HibernateJpaVendorAdapter"> <property name="databasePlatform" value="org.hibernate.dialect.MySQLDialect" /> <!-- <property name="databasePlatform" value="org.hibernate.dialect.HSQLDialect" /> --> <property name="showSql" value="false" /> <property name="generateDdl" value="true" /> </bean> </property> </bean> <tx:annotation-driven /> <bean id="transactionManager" class="org.springframework.orm.jpa.JpaTransactionManager"> <property name="entityManagerFactory" ref="entityManagerFactory" /> </bean> <bean class="org.springframework.orm.jpa.support.PersistenceAnnotationBeanPostProcessor" /> </beans>

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  • Spring 3.0 vs J2EE 6.0

    - by StudiousJoseph
    Hi everybody, I'm confronted with a situation... I've been asked to give an advise regarding which approach to take, in terms of J2EE development between Spring 3.0 and J2EE 6.0. I was, and still am, a promoter of Spring 2.5 over classic J2EE 5 development, specially with JBoss, I even migrated old apps to Spring and influenced the re-definition of the development policy here to include Spring specific APIs, and helped the development of a strategic plan to foster more lightweight solutions like Spring + Tomcat, instead of the heavier ones of JBoss, right now, we're using JBoss merely as a Web container, having what i call the "container inside the container paradox", that is, having Spring apps, with most of its APIs, running inside JBoss, So we're in the process of migrating to tomcat. However, with the coming of J2EE 6.0 many features, that made Spring attractive at that time, easy deployment, less-coupling, even some sort of D.I, etc, seems to have been mimicked, in one way or the other. JSF 2.0, JPA 2.0, WebBeans, WebProfiles, etc. So, the question goes... From your point of view, how save, and logical, it is to continue to invest in a non-standard J2EE development framework like Spring given the new perspectives offered by J2EE 6.0? Can we talk about maybe 3 or 4 more years of Spring development, or do you recommend early adoption of J2EE 6.0 APIs and it's practices? I'll appreciate any insights with this...

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  • Entity Framework Code-First to Provide Replacement for ASP.NET Profile Provider

    - by Ken Cox [MVP]
    A while back, I coordinated a project to add support for the SQL Table Profile Provider in ASP.NET 4 Web Applications.  We urged Microsoft to improve ASP.NET’s built-in Profile support so our workaround wouldn’t be necessary. Instead, Microsoft plans to provide a replacement for ASP.NET Profile in a forthcoming release. In response to my feature suggestion on Connect, Microsoft says we should look for something even better using Entity Framework: “When code-first is officially released the final piece of a full replacement of the ASP.NET Profile will have arrived. Once code-first for EF4 is released, developers will have a really easy and very approachable way to create any arbitrary class, and automatically have the .NET Framework create a table to provide storage for that class. Furthermore developer will also have full LINQ-query capabilities against code-first classes. “ The downside is that there won’t be a way to retrofit this Profile replacement to pre- ASP.NET 4 Web applications. At least there’ll still be the MVP workaround code. It looks like it’s time for me to dig into a CTP of EF Code-First to see what’s available.   Scott Guthrie has been blogging about Code-First Development with Entity Framework 4. It’s not clear when the EF Code-First is coming, but my guess is that it’ll be part of the VS 2010/.NET 4 service pack.

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  • Jump and run HTML5 Game Framework

    - by user1818924
    We're developing a jump and run game with HTML5 and JavaScript and have to build an own game framework for this. Here we have some difficulties and would like to ask you for some advice: we have a "Stage" object, which represents the root of our game and is a global div-wrapper. The stage can contain multiple "Scenes", which are also div-elements. We would implement a Scene for the playing task, for pause, etc. and switch between them. Each scene can therefore contain multiple "Layers", representing a canvas. These Layer contain "ObjectEntities", which represent images or other shapes like rectangles, etc. Each Objectentity has its own temporaryCanvas, to be able to draw images for one entity, whereas another contains a rectangle. We set an activeScene in our Stage, so when the game is played, just the active scene is drawn. Calling activeScene.draw(), calls all sublayers to draw, which draw their entities (calling drawImage(entity.canvas)). But is this some kind of good practive? Having multiple canvas to draw? Each gameloop every layer-context is cleared and drawn again. E.g. we just have a still Background-Layer, … wouldn't it be more useful to draw this once and not to clear it everytime and redraw it? Or should we use a global canvas for example in the Stage and just use this canvas to draw? But we thought this would be to expensive... Other question: Do you have any advice how we could dive into implementing an own framework? Most stuff we find online relies on existing frameworks or they just implement their game without building a framework.

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  • Mobile Web Framework that will only control rendering and page transitions

    - by rlemon
    I have been using jQueryMobile for a bit now, and there are some things I like about it and others I do not. First I will give a bit of background. I have a light weight mobile application that has a few configurations and 6 pages. Ideally I Would like to load all pages into the DOM (they interact with each other quite often and pages will be switched in the same frequency). The application will post for some JSON every n seconds and refresh the values on the page (yes it is primarily a information display app). with the jQuery Mobile framework the only real thing I like is how easy it is to have a standardized UI a crossed all devices and browsers, I'm really not using too much else out of the framework other than the basic page navigation (if you are familiar with the framework; a bare-bone multi-page design is all i need). Why I want to step away from jQueryMobile is how weighty it is. Not only do you need to include the mobile library, but also the base jQuery libraries. This I do not like because I'm not using jQuery anywhere else on the site. Any suggestions on light-weight mobile frameworks that have a similar rendering as jQueryMobile?

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  • Failed to load viewstate.The control tree into which viewstate is being loaded...etc

    - by alaa9jo
    Two days ago,a colleague of mine tried to publish an asp.net website (which is built in VS2008 using framework 3.5) to our server,he configured everything in IIS (he made sure that the selected asp.net version is 2.0) and launched the website..at first it was working great but when he tried to click on a specific treeview...BOOM..: "Failed to load viewstate. The control tree into which viewstate is being loaded must match the control tree that was used to save viewstate during the previous request. For example, when adding controls dynamically, the controls added during a post-back must match the type and position of the controls added during the initial request." In that page there were these control: a TreeView and a Placeholder,when the user selects any node then it's controls will be created dynamically into that placeholder..for the first time it's working fine but when (s)he select another node then that issue appears. He called me to help him with this issue,for me this is the first time I see such an issue,scratch my head then I decided to eliminate the possibilities of this issue one by one,at the development machine it's working perfectly,he published the website at the local IIS and again..it's working perfectly,I took a copy of the website and published it into my laptop but no issues at all,so this is means that it's not an issue in the code. So there is something missing/wrong in our server [it has Windows Server 2003],we went to the server and checked on the web-config and the configurations on IIS...nothing wrong so far,so I decided to check if the framework 3.5 is installed or not and the answer: it wasn't installed Of course he assumed that it was installed and there was nothing to tell if it wasn't from the "ASP.Net version" in IIS because frameworks 3.0 and 3.5 will not be listed there [2.0 will be listed there instead],the only way to check if it was installed or not is to search for the framework in this path:[WINDOWS Folder]\Microsoft.NET\Framework or check if it was installed in Add or remove programs. The obvious solution for his case: We installed Framework 3.5 SP1 into our server,did a restart to the machine and it worked ! If anyone faced the same issue and solved it using the same solution or with a different one please post it here to share experience.

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  • Spring Roo Database Reverse Engineer with Oracle

    - by kerry
    So you are trying to reverse engineer an Oracle database with roo? Unfortunately, due to licensing restrictions with the Oracle JDBC Drivers, this is a little difficult. There are a few blog posts and forum threads that address the problem but I figured I would post what worked for me here. First, you need to download the appropriate Oracle Drivers from Oracle. The required login, stringent password requirements, nosy registration form, and general system instability made this a pretty painful step for me. I’d also like to say that companies that have password requirements that don’t allow symbols (or any other non-standard requirement) have a special place in my heart. Having to recover my password every time I go to your site virtually guarantees I will only go there when I absolutely have to (not often). Anyways, once you have it downloaded you need to install is with maven: mvn install:install-file -Dfile=~/Downloads/ojdbc6.jar -DgroupId=com.oracle -DartifactId=ojdbc6 -Dversion=11.2.0.3 -Dpackaging=jar -DgeneratePom=true Here comes the fun part. You need to create an osgi wrapper for the driver to install it in roo. Otherwise, roo cannot see the driver. Create a new folder and put the contents of the oracle roo addon pom gist I created. Now build it with maven. You may want to change some of the artifact ids and dependencies for your particular situation. mvn package No open a roo shell and execute the following command: osgi install --url file:///Users/me/my-osgi-project/target/the-jar-it-built.jar Now run (in roo): jpa setup --provider HIBERNATE --database ORACLE dependency remove --groupId com.oracle --artifactId ojdbc14 --version 10.2.0.2 dependency add --groupId com.oracle --artifactId ojdbc6 --version 11.2.0.3 database properties set --key database.driverClassName --value oracle.jdbc.OracleDriver database properties set --key database.url --value jdbc:oracle:thin:@%YOUR_CONNECTION_INFO% database properties set --key database.username --value %YOUR_USERNAME% database properties set --key database.password --value %YOUR_PASSWORD% database reverse engineer --schema %YOUR_SCHEMA% --package ~.domain If you have any package loading exceptions when running the reverse engineer command you can uninstall the osgi bundle, set the package to optional in the osgi pom in the IncludedPackages tag (javax.some.package.*;resolution:=optional) rebuild, then reinstall in roo.

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  • Why can I not register a PropertyEditor for String in Spring MVC?

    - by Tom Tucker
    I'm using Spring 3.0.3. I've enabled the default ConversionService by adding this line to my Spring configuration XML. <mvc:annotation-driven/> I'm also using custom PropertyEditor's for certain data types, so I've registered them for corresponding data types like the following and they work fine. webDataBinder.registerCustomEditor(Date.class, new MyPropertyEditor()); I have a custom tag library that extends Spring's Form tag library, and I can acess these PropertyEditor's through getPropertyEditor() of AbstractDataBoundFormElementTag. What I don't understand is that I can't register a custom PropertyEditor for String for some reason. The following wouldn't work. webDataBinder.registerCustomEditor(String.class, new MyPropertyEditor()); When I do getPropertyEditor(), it always returns a ConvertingPropertyEditorAdapter, instead of MyPropertyEditor. Is this a bug? EDIT: I realized that I didn't do some stuff right. Spring works just fine.

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  • How to override the behavior of Spring @Autowired

    - by Mark
    Hi a little background: I am Using Spring 2.5, and specifically spring IOC and annotations. I am using @Autowired in my code (the Autowiring is done by type) and use @Component for exposing Classes to the Automatic wiring. The situation described bellow arose while i tried to test my code. now to the problem: Note: i use a different Spring Context for the Test environment. I have a class FOO which is @Autowired but in the test context i want to use a different class of the same type MockFoo (extends FOO) The Spring Setup of course fails do so automatically due to multiple options for the Dependency Injection of the FOO class (both FOO and MockFOO comply to the Type check) I am looking for a way to inject the test bean instead of the original bean. I expected Spring to allow using the Context configurion file to override a bean injection or to order Spring not to autowire a specific bean BUT All these option seem to exists only for the beans which were originally defined in the Spring Context Configuration file

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  • How can I map a spring controller to a url with .jsp extension?

    - by Matteo Caprari
    Hi. We are in the process of migrating a jsp-only application to Spring-MVC. For various reasons we can't change the extension of the current pages. (calls to login.jsp need to handled by a spring controller that will use a jsp file as view). We are doing this iteratively, so some pages need to stay jsp files (calls to welcome.jsp won't be handled by a controller). To do that I mapped both the DispatcherDervlet and the HandlerMapping to *.jsp, and configured the JstlView in the standard way. Unfortunately, if I browse to //login.jsp I get an error saying <No mapping found for HTTP request with URI [/<context>/WEB-INF/jsp/login.jsp] in DispatcherServlet with name 'spring'> It all works if I change .jsp to any other extension in DispatcherServlet and HandlerMapping. web.xml: <servlet> <servlet-name>spring</servlet-name> <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class> <load-on-startup>1</load-on-startup> </servlet> <servlet-mapping> <servlet-name>spring</servlet-name> <url-pattern>*.jsp</url-pattern> </servlet-mapping> spring-servlet.xml: <!-- View resolver --> <bean id="viewResolver" class="org.springframework.web.servlet.view.UrlBasedViewResolver"> <property name="viewClass" value="org.springframework.web.servlet.view.JstlView"/> <property name="prefix" value="/WEB-INF/jsp/"/> <property name="suffix" value=".jsp"/> </bean> <!-- URL Mapping --> <bean id="publicUrlMapping" class="org.springframework.web.servlet.handler.SimpleUrlHandlerMapping"> <property name="urlMap"> <map> <entry key="/login.jsp" value-ref="loginController"/> </map> </property> </bean> Thanks a lot.

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  • Data Access example using Entity Framework

    - by Dan
    Does anyone know of or having any good examples of how to use Entity Framework version 2 in the Data Access layer and put an interface on it so the business layer uses the interface rather than knowing about EF? I have found some examples but they are all from 2009 and I'm not sure how they relate to Entity Framework version 2.

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