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  • SQL Max Group By Query Help

    - by Hcabnettek
    Hi All, I have a quick question. How do I select the two values I need in one query? Currently I'm doing this, which works fine, but it's obviously running two queries when one should do the trick. I tried MAX(columnA) and GROUP BY ColumnB, but that returns multiple row. I only want one row returned. DECLARE @biID bigint , @dtThreshold DateTime SELECT @biID = MAX(biID) FROM tbPricingCalculationCount WITH (NOLOCK) SELECT @dtThreshold = dtDateTime FROM tbPricingCalculationCount WITH (NOLOCK) WHERE biID = @biID I would like both those variables to be set correctly in one query. How can I do that? Thanks, ~ck

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  • To store images in SQL or not?

    - by Brett
    Generally, I had thought it was always better to store images in the filesystem and link to it via the database entry. However, I am trying to optimize my db design and am having a few questions. My images are all really small thumbmails in black and white (not greyscale, but true B&W) and are 70x70 in size. If we take the images (which is basically a 2D array of 1 and 0), it can be stored as binary data that would be approximately 600 bytes each. So my question is whether querying the 600 bytes stored in a db would be faster than querying a link followed by accessing the filesystem; assuming there are a lot of "image" queries being made. Does anyone have any experience with this area? If it matters, I am using MySQL, and MonetDB (separately, but have the same question for both). Many thanks, Brett

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  • SQL Query problem: How to merge two lists.

    - by ProfK
    I have a base table of Participants and Answers, with the following structure: ParticipantId, BusUnitId, QuestionNum, Answer. In this table, QuestionNum ranges, say, from 1 to 6. I also have two other tables that sort of link QuestionNum to the actual question table, BusUnitQuestions, and ParticipantQuestions. For each QuestionNum, I must get the actual question text, based on QuestionId. BusUnitId, QuestionId ParticipantId, QuestionId Now assuming records with QuestionNum from 1 to 6. BusUnitQuestions has 3 records, so QuestionNum 1 to 3 must join to Question on the QuestionId's from BusUnitQuestions, and QuestionNum 4 to 6 must join to Question on the QuestionId's from ParticipantQuestions. I assume I need to use ROW_NUMBER() in the subquery from BusUnitQuestions to join to my answer table, but I'm lost after that. If anyone at all understands me, do you have any suggestions?

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  • Query Optimizing Request

    - by mithilatw
    I am very sorry if this question is structured in not a very helpful manner or the question itself is not a very good one! I need to update a MSSQL table call component every 10 minutes based on information from another table call materials_progress I have nearly 60000 records in component and more than 10000 records in materials_progress I wrote an update query to do the job, but it takes longer than 4 minutes to complete execution! Here is the query : UPDATE component SET stage_id = CASE WHEN t.required_quantity <= t.total_received THEN 27 WHEN t.total_ordered < t.total_received THEN 18 ELSE 18 END FROM ( SELECT mp.job_id, mp.line_no, mp.component, l.quantity AS line_quantity, CASE WHEN mp.component_name_id = 2 THEN l.quantity*2 ELSE l.quantity END AS required_quantity, SUM(ordered) AS total_ordered, SUM(received) AS total_received , c.component_id FROM line l LEFT JOIN component c ON c.line_id = l.line_id LEFT JOIN materials_progress mp ON l.job_id = mp.job_id AND l.line_no = mp.line_no AND c.component_name_id = mp.component_name_id WHERE mp.job_id IS NOT NULL AND (mp.cancelled IS NULL OR mp.cancelled = 0) AND (mp.manual_override IS NULL OR mp.manual_override = 0) AND c.stage_id = 18 GROUP BY mp.job_id, mp.line_no, mp.component, l.quantity, mp.component_name_id, component_id ) AS t WHERE component.component_id = t.component_id I am not going to explain the scenario as it too complex.. could somebody please please tell me what makes this query this much expensive and a way to get around it? Thank you very very much in advance!!!

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  • SQL Server 2005 user permissions

    - by karl
    I have created a database and some dbo.tables. Now I want to create a user that are can read and write to these tables, but not modify or drop. However I want this user to be able to create own tables and let him do what he want with these. Is this possible? Could someone explain how this can be done?

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  • Cannot render images locally with Sql Server 2005 Report Services SOAP service calls

    - by user289146
    I am trying to render images from SSRS 2005 via the SOAP call. When the reports service is installed on the same server as my website, the images generated do not render in the page. However, when I connect to the reporting service URL from the same web code on a separate machine the images render just fine. Is there a dependency that I am missing to allow me to run the web and SSRS on the same box?

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  • Question about SQL Server HierarchyID depth-first performance

    - by AndalusianCat
    I am trying to implement hierarchyID in a table (dbo.[Message]) containing roughly 50,000 rows (will grow substantially in the future). However it takes 30-40 seconds to retrieve about 25 results. The root node is a filler in order to provide uniqueness, therefor every subsequent row is a child of that dummy row. I need to be able to traverse the table depth-first and have made the hierarchyID column (dbo.[Message].MessageID) the clustering primary key, have also added a computed smallint (dbo.[Message].Hierarchy) which stores the level of the node. Usage: A .Net application passes through a hierarchyID value into the database and I want to be able to retrieve all (if any) children AND parents of that node (besides the root, as it is filler). A simplified version of the query I am using: @MessageID hierarchyID /* passed in from application */ SELECT m.MessageID, m.MessageComment FROM dbo.[Message] as m WHERE m.Messageid.IsDescendantOf(@MessageID.GetAncestor((@MessageID.GetLevel()-1))) = 1 ORDER BY m.MessageID From what I understand, the index should be detected automatically without a hint. From searching forums I have seen people utilizing index hints, at least in the case of breadth-first indexes, as apparently CLR calls may be opaque to the query optimizer. I have spent the past few days trying to find a solution for this issue, but to no avail. I would greatly appreciate any assistance, and as this is my first post, I apologize in advance if this would be considered a 'noobish' question, I have read the MS documentation and searched countless forums, but have not came across a succinct description of the specific issue.

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  • Storing a set of criteria in another table

    - by bendataclear
    I have a large table with sales data, useful data below: RowID Date Customer Salesperson Product_Type Manufacturer Quantity Value 1 01-06-2004 James Ian Taps Tap Ltd 200 £850 2 02-06-2004 Apple Fran Hats Hats Inc 30 £350 3 04-06-2004 James Lawrence Pencils ABC Ltd 2000 £980 ... Many rows later... ... 185352 03-09-2012 Apple Ian Washers Tap Ltd 600 £80 I need to calculate a large set of targets from table containing values different types, target table is under my control and so far is like: TargetID Year Month Salesperson Target_Type Quantity 1 2012 7 Ian 1 6000 2 2012 8 James 2 2000 3 2012 9 Ian 2 6500 At present I am working out target types using a view of the first table which has a lot of extra columns: SELECT YEAR(Date) , MONTH(Date) , Salesperson , Quantity , CASE WHEN Manufacturer IN ('Tap Ltd','Hats Inc') AND Product_Type = 'Hats' THEN True ELSE False END AS IsType1 , CASE WHEN Manufacturer = 'Hats Inc' AND Product_Type IN ('Hats','Coats') THEN True ELSE False END AS IsType2 ... ... , CASE WHEN Manufacturer IN ('Tap Ltd','Hats Inc') AND Product_Type = 'Hats' THEN True ELSE False END AS IsType24 , CASE WHEN Manufacturer IN ('Tap Ltd','Hats Inc') AND Product_Type = 'Hats' THEN True ELSE False END AS IsType25 FROM SalesTable WHERE [some stuff here] This is horrible to read/debug and I hate it!! I've tried a few different ways of simplifying this but have been unable to get it to work. The closest I have come is to have a third table holding the definition of the types with the values for each field and the type number, this can be joined to the tables to give me the full values but I can't work out a way to cope with multiple values for each field. Finally the question: Is there a standard way this can be done or an easier/neater method other than one column for each type of target? I know this is a complex problem so if anything is unclear please let me know. Edit - What I need to get: At the very end of the process I need to have targets displayed with actual sales: Type Year Month Salesperson TargetQty ActualQty 2 2012 8 James 2000 2809 2 2012 9 Ian 6500 6251 Each row of the sales table could potentially satisfy 8 of the types. Some more points: I have 5 different columns that need to be defined against the targets (or set to NULL to include any value) I have between 30 and 40 different types that need to be defined, several of the columns could contain as many as 10 different values For point 2, if I am using a row for each permutation of values, 2 columns with 10 values each would give me 100 rows for each sales person for each month which is a lot but if this is the only way to define multiple values I will have to do this. Sorry if this makes no sense!

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  • SQL Server JDBC Exception

    - by user267581
    When using ANT to build my Java application I keep getting this error. I have tried multiple times to use SQLJDBC.JAR and SQLJDBC4.JAR but continually receive this error message. I am completely stumpped why this error is received even after upgrading to sqljdbc4.jar. [javadoc] java.lang.UnsupportedOperationException: Java Runtime Environment (JRE) version 1.6 is not supported by this driver. Use the sqljdbc4.jar class library, which provides support for JDBC 4.0.

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  • Counting number of children in hierarchical SQL data

    - by moontear
    Hello, for a simple data structure such as so: ID parentID Text Price 1 Root 2 1 Flowers 3 1 Electro 4 2 Rose 10 5 2 Violet 5 6 4 Red Rose 12 7 3 Television 100 8 3 Radio 70 9 8 Webradio 90 For reference, the hierarchy tree looks like this: ID Text Price 1 Root |2 Flowers |-4 Rose 10 | |-6 Red Rose 12 |-5 Violet 5 |3 Electro |-7 Television 100 |-8 Radio 70 |-9 Webradio 90 I'd like to count the number of children per level. So I would get a new column "NoOfChildren" like so: ID parentID Text Price NoOfChildren 1 Root 8 2 1 Flowers 3 3 1 Electro 3 4 2 Rose 10 1 5 2 Violet 5 0 6 4 Red Rose 12 0 7 3 Television 100 0 8 3 Radio 70 1 9 8 Webradio 90 0 I read a few things about hierarchical data, but I somehow get stuck on the multiple inner joins on the parentIDs. Maybe someone could help me out here. moon

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  • Multi-base conversion - using all combinations for URL shortener

    - by Guffa
    I am making an URL shortener, and I am struggling with the optimal way of encoding a number (id) into a character string. I am using the characters 0-9,A-Z,a-z so it will basically be a base-62 encoding. That is pretty basic, but it doesn't make use of all possible codes. The codes that it would produce would be: 0, 1, ... y, z, 10, 11, ... zy, zz, 100, 101, ... Notice that the codes 00 to 0z is not used, the same for 000 to 0zz, and so on. I would like to use all the codes, like this: 0, 1, ... y, z, 00, 01, ... zy, zz, 000, 001, ... It would be some combination of base-62 and base-63, with different bases depending on the position... Using base-62 is easy, for example: create procedure tiny_GetCode @UrlId int as set nocount on declare @Code varchar(10) set @Code = '' while (@UrlId > 0 or len(@Code) = 0) begin set @Code = substring('0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz', @UrlId % 62 + 1, 1) + @Code set @UrlId = @UrlId / 62 end select @Code But I haven't yet managed to make a multi-base conversion out of it, to make use of all the codes.

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  • optimizing an sql query using inner join and order by

    - by Sergio B
    I'm trying to optimize the following query without success. Any idea where it could be indexed to prevent the temporary table and the filesort? EXPLAIN SELECT SQL_NO_CACHE `groups`.* FROM `groups` INNER JOIN `memberships` ON `groups`.id = `memberships`.group_id WHERE ((`memberships`.user_id = 1) AND (`memberships`.`status_code` = 1 AND `memberships`.`manager` = 0)) ORDER BY groups.created_at DESC LIMIT 5;` +----+-------------+-------------+--------+--------------------------+---------+---------+---------------------------------------------+------+----------------------------------------------+ | id | select_type | table | type | possible_keys | key | key_len | ref | rows | Extra | +----+-------------+-------------+--------+--------------------------+---------+---------+---------------------------------------------+------+----------------------------------------------+ | 1 | SIMPLE | memberships | ref | grp_usr,grp,usr,grp_mngr | usr | 5 | const | 5 | Using where; Using temporary; Using filesort | | 1 | SIMPLE | groups | eq_ref | PRIMARY | PRIMARY | 4 | sportspool_development.memberships.group_id | 1 | | +----+-------------+-------------+--------+--------------------------+---------+---------+---------------------------------------------+------+----------------------------------------------+ 2 rows in set (0.00 sec) +--------+------------+-----------------------------------+--------------+-----------------+-----------+-------------+----------+--------+------+------------+---------+ | Table | Non_unique | Key_name | Seq_in_index | Column_name | Collation | Cardinality | Sub_part | Packed | Null | Index_type | Comment | +--------+------------+-----------------------------------+--------------+-----------------+-----------+-------------+----------+--------+------+------------+---------+ | groups | 0 | PRIMARY | 1 | id | A | 6 | NULL | NULL | | BTREE | | | groups | 1 | index_groups_on_name | 1 | name | A | 6 | NULL | NULL | YES | BTREE | | | groups | 1 | index_groups_on_privacy_setting | 1 | privacy_setting | A | 6 | NULL | NULL | YES | BTREE | | | groups | 1 | index_groups_on_created_at | 1 | created_at | A | 6 | NULL | NULL | YES | BTREE | | | groups | 1 | index_groups_on_id_and_created_at | 1 | id | A | 6 | NULL | NULL | | BTREE | | | groups | 1 | index_groups_on_id_and_created_at | 2 | created_at | A | 6 | NULL | NULL | YES | BTREE | | +--------+------------+-----------------------------------+--------------+-----------------+-----------+-------------+----------+--------+------+------------+---------+ +-------------+------------+----------------------------------------------------------+--------------+-------------+-----------+-------------+----------+--------+------+------------+---------+ | Table | Non_unique | Key_name | Seq_in_index | Column_name | Collation | Cardinality | Sub_part | Packed | Null | Index_type | Comment | +-------------+------------+----------------------------------------------------------+--------------+-------------+-----------+-------------+----------+--------+------+------------+---------+ | memberships | 0 | PRIMARY | 1 | id | A | 2 | NULL | NULL | | BTREE | | | memberships | 0 | grp_usr | 1 | group_id | A | 2 | NULL | NULL | YES | BTREE | | | memberships | 0 | grp_usr | 2 | user_id | A | 2 | NULL | NULL | YES | BTREE | | | memberships | 1 | grp | 1 | group_id | A | 2 | NULL | NULL | YES | BTREE | | | memberships | 1 | usr | 1 | user_id | A | 2 | NULL | NULL | YES | BTREE | | | memberships | 1 | grp_mngr | 1 | group_id | A | 2 | NULL | NULL | YES | BTREE | | | memberships | 1 | grp_mngr | 2 | manager | A | 2 | NULL | NULL | YES | BTREE | | | memberships | 1 | complex_index | 1 | group_id | A | 2 | NULL | NULL | YES | BTREE | | | memberships | 1 | complex_index | 2 | user_id | A | 2 | NULL | NULL | YES | BTREE | | | memberships | 1 | complex_index | 3 | status_code | A | 2 | NULL | NULL | YES | BTREE | | | memberships | 1 | complex_index | 4 | manager | A | 2 | NULL | NULL | YES | BTREE | | | memberships | 1 | index_memberships_on_user_id_and_status_code_and_manager | 1 | user_id | A | 2 | NULL | NULL | YES | BTREE | | | memberships | 1 | index_memberships_on_user_id_and_status_code_and_manager | 2 | status_code | A | 2 | NULL | NULL | YES | BTREE | | | memberships | 1 | index_memberships_on_user_id_and_status_code_and_manager | 3 | manager | A | 2 | NULL | NULL | YES | BTREE | | +-------------+------------+----------------------------------------------------------+--------------+-------------+-----------+-------------+----------+--------+------+------------+---------+

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  • Error: An aggregate may not appear in the WHERE clause unless it is in a subquery contained in a HAV

    - by brz dot net
    I have to find the indentid from the status table based on below two conditions: 1. If there are more than one record having same indentid in status table and the same indentID has count1 in feasibilitystatus table then I don't want to display the record. 2. If there is only one record of indentid in status table and the same indentID has count0 in feasibilitystatus table then I don't want to display the record. Query: select distinct s.indentid from status s where s.status='true' and s.indentid not in( select case when count(s.indentid)>1 then (select indentid from feasibilitystatus group by indentid having count(indentid)>1) else (select indentid from feasibilitystatus group by indentid having count(indentid)>0) end as indentid from status) Error: An aggregate may not appear in the WHERE clause unless it is in a subquery contained in a HAVING clause or a select list, and the column being aggregated is an outer reference.

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  • How can I fill SQL Server table from excel only using sql query?

    - by Phsika
    How can I do that with Microsoft.ACE.OLEDB.12.0? CREATE TABLE [dbo].[Addresses_Temp] ( [FirstName] VARCHAR(20), [LastName] VARCHAR(20), [Address] VARCHAR(50), [City] VARCHAR(30), [State] VARCHAR(2), [ZIP] VARCHAR(10) ) GO INSERT INTO [dbo].[Address_Temp] ( [FirstName], [LastName], [Address], [City], [State], [ZIP] ) SELECT [FirstName], [LastName], [Address], [City], [State], [ZIP] FROM OPENROWSET('Microsoft.ACE.OLEDB.12.0', 'Excel 12.0;Database=C:\Source\Addresses.xlsx;IMEX=1', 'SELECT * FROM [Sayfa1$]') How can I do that?

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  • Just installed Sql Server 2008 and cannot access it

    - by Mendy
    I just install Sql Server 2008 on a new server and I cannot connect to it. I'm trying to connect using Windows Authentication to the localhost but I get the following error: A network-related or instance-specific error occurred while establishing a connection to SQL Server. The server was not found or was not accessible. Verify that the instance name is correct and that SQL Server is configured to allow remote connections. (provider: Named Pipes Provider, error: 40 - Could not open a connection to SQL Server) (Microsoft SQL Server, Error: 2) For help, click: http://go.microsoft.com/fwlink?ProdName=Microsoft+SQL+Server&EvtSrc=MSSQLServer&EvtID=2&LinkId=20476

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  • Recursive Query Help

    - by Josh
    I have two tables in my database schema that represent an entity having a many-to-many relationship with itself. Role --------------------- +RoleID +Name RoleHasChildRole --------------------- +ParentRoleID +ChildRoleID Essentially, I need to to be able to write a query such that: Given a set of roles, return the unique set of all related roles recursively. This is an MSSQL 2008 Database.

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  • Filestream in Sql Server 2008 Express

    - by Xaitec
    i tried to get it to work but i never seem to have to luck, i go a code snippet for a blog and still no dice. This is the code. EXEC sp_configure filestream_access_level, 1 GO RECONFIGURE GO CREATE DATABASE NorthPole ON PRIMARY ( NAME = NorthPoleDB, FILENAME = 'C:\Temp\NP\NorthPoleDB.mdf' ), FILEGROUP NorthPoleFS CONTAINS FILESTREAM( NAME = NorthPoleFS, FILENAME = 'C:\Temp\NP\NorthPoleFS') LOG ON ( NAME = NorthPoleLOG, FILENAME = 'C:\Temp\NP\NorthPoleLOG.ldf') GO

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  • SQL help on a name dilemma

    - by Ardman
    I have a column which has surname and firstname plus salutation in. e.g. Bloggs,Joe,Mr I need to break this out into Bloggs Joe Mr as 3 seperate columns. Any ideas appreciated. How, the other thing is I won't know how many commas are in the initial column.

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