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  • PHP IF stops IE content from loading

    - by Rsmithy
    scenario I have a PHP if statement to test if a user is logging in for the first time ever. This then displays, a demo in a greybox popup box. Sadly when the box loads in IE, the content of the website doesn't. This means when I user closes the box, they are left the with background. Code - I'm now using PHP include. greybox.php <?php if ($fli == 0) {echo " <script type='text/javascript'> window.onload = function() { GB_showCenter('Your first login', '../video.php'); }; </script> ";} else echo "";?> <!-- GB scrip --> <script type="text/javascript"> var GB_ROOT_DIR = "greybox/"; </script> <script type="text/javascript" src="greybox/AJS.js"></script> <script type="text/javascript" src="greybox/AJS_fx.js"></script> <script type="text/javascript" src="greybox/gb_scripts.js"></script> <link href="greybox/gb_styles.css" rel="stylesheet" type="text/css" /> <!-- GB --> RELEVANT Script on main site <?php $fli = $_SESSION["USER"]["fli"]; ?> <?php include "greybox.php" ?> I would deeply appreicate any help at all please! :)

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  • PHP strtotime without leap-years

    - by Christian Sciberras
    With regards to this thread, I've developed a partial solution: function strtosecs($time,$now=null){ static $LEAPDIFF=86400; $time=strtotime($time,$now); return $time-((date('Y',$time)-1968)/4*$LEAPDIFF); } The function is supposed to get the number of seconds given a string without checking leap-years. It does this calculating the number of leap-years 1970 [(year-1986)/4], multiplying it by the difference in seconds between a leap-year and a normal year (which in the end, it's just the number of seconds in a day). Finally, I simply remove all those excess leap-year seconds from the calculated time. Here's some examples of the inputs/outputs: // test code echo strtosecs('+20 years',0).'=>'.(strtosecs('+20 years',0)/31536000); echo strtosecs('+1 years',0).'=>'.(strtosecs('+1 years',0)/31536000); // test output 630676800 => 19.998630136986 31471200 => 0.99794520547945 You will probably ask why am I doing a division on the output? It's to test it out; 31536000 is the number of seconds in a year, so that 19.99... should be 20 and 0.99... should be a 1. Sure, I could round it all and get "correct" answer, but I'm worried about the inaccuracies.

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  • mysql query using global variables

    - by Carlos
    I am trying run a query to active the users account. I am not sure if I am having problem with the query itself or if there's something else that I dont know about. here is the code: if($_SESSION['lastid']&&$_SESSION['random']) { $check= mysql_query('SELECT * FROM members WHERE id= "$_SESSION[lastid]" AND random = " $_SESSION[random]"'); $checknum = mysql_num_rows($check); //$checknum = mysql_query($check) or die("Error: ". mysql_error(). " with query ". $check); if($checknum != 0) // run query to activate the account { $acti= mysql_query('UPDATE members SET activation = "1" WHERE id= "$_SESSION[lastid]"'); die('Your account has been activated. You may now log in!'); }else{ echo('Invalid id or activation code.') . ' lastid: ' .$_SESSION['lastid'] . ' random: ' .$_SESSION['random'] ; // die ('Invalid id or activation code.'); } }else{ die('Could not either find id or random number!'); } this is the warning I am getting from mysql: Warning: mysql_num_rows(): supplied argument is not a valid MySQL result resource in /hermes/bosweb26b/b2501/servername/folder/file.php on line 30 but when I echo the variables out, I get the same values that are stored in the database.... Invalid id or activation code. lastid: 2 and random: 36308075 could someone please give me a hint? thank you.

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  • merge my code with Ajax code>>> problem

    - by sandy
    I want to help me In the following link i found nice code in Ajax http://www.w3schools.com/php/php_ajax_livesearch.asp I want to link my code with the code you see in the link above and replace dropdown list How can I do it for I could not where is it change in code even my code work as Ajax ?? I wish .... I wish .... I wish any somebody can help me <?php include ("connect.php"); print_r($_POST['sector_list']); $member_id = intval($_POST['sector_list']); if($member_id == 0) { // Default choice was selected } else { $res = mysql_query("SELECT * FROM members WHERE MemberID = $member_id LIMIT 1"); if(mysql_num_rows($res) == 0) { // Not a valid member } else { // The member is in the database } } ?> <form method="POST" action=<?php echo $_SERVER["PHP_SELF"]; ?> > <input type="hidden" name="sector" value="sector_list"> <select name="sector_list[]" class="inputstandard" multiple="multiple"> <option size ="40" value="default">send to </option> <?php $result = mysql_query('SELECT * from members') or die(mysql_error()); while ($row = mysql_fetch_assoc($result)) { echo '<option value="' . $row['MemberName'] . '">' . $row['MemberName']. '</option>'; } ?> <input type ="submit" name ="go" value = "go" > </select> </form>

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  • Preserving Tabs in POST Data

    - by byronh
    I need to preserve tab characters from a textarea through POST Data. It seems that there's no way to differentiate tabs from spaces in the $_POST array, and this is really frustrating me. I'm using a jQuery plugin from here to allow for tab and shift+tab usage within a textarea. http://teddevito.com/demos/textarea.html The JavaScript is using this as its TAB character: $.fn.tabby.defaults = {tabString : String.fromCharCode(9)}; For some reason, it shows an individual space instead of each tab character, so all my code formatting is lost: <textarea name="field0" rows="26" cols="123"><?php echo $_POST['field0']; ?></textarea> Neither does this. Apparently the tabs disappear before the data even reaches the str_replace function (the four spaces in the first double quotes is when I press TAB in my text editor). <textarea name="field0" rows="26" cols="123"><?php echo str_replace(" ", "\t", $_POST['field0']); ?></textarea> The reason I need tabs and not multiple spaces is because my application features and on-line code editor. Anyone have any ideas? I'm guessing the solution would involve modifying the data with javascript before it's sent through POST, but I haven't the slightest idea how to start.

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  • PHP mail() function not delivering mail

    - by Ryan Jones
    Hi there, I have a slight problem. I am using a working script (works on my testing account - shared server) to send a mail through PHP using the mail() function. I just got a dedicated server, and I haven't been able to get the function to work. I've spent the last 10 or so hours reading various documentations on BIND (for the SPF record), dovecot, sendmail and postfix trying various things to get this to work. There is clearly something that I am missing. So we know the PHP code works fine. All the headers are fine everything. We know this as it's a direct copy from my testing account. So the problem must arise somewhere in the server config. The path to sendmail is correct, and sendmail is (apparently) working fine. I've set up the script to now deliver "Sent" or "Error" based on the boolean result from the PHP mail() function. That is: if(mail($blah,$blah,$blah,$blah,$blah)) { echo "Sent"; } else { echo "Error";} And the result ALWAYS comes up as "Sent" - however, the email never arrives. Can someone suggest things to check, as I'm completely new to this (24 hours or so!). Thanks in advance. Ryan

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  • posting a variable with jquery and receiving it on other page

    - by Billa
    I want to post a varible "id" to a page. I'm trying following code, but I cant get the id value, it says "undefined". function box(){ var id=$(this).attr("id"); $("#votebox").slideDown("slow"); $("#flash").fadeIn("slow"); $.ajax({ type: "POST", //I want to post the "id" to the rating page. data: "id="+$(this).attr("id"), url: "rating.php", success: function(html){ $("#flash").fadeOut("slow"); $("#content").html(html); } }); } This function is called in following code. In the following code too, the id is posted to the page "votes.php", and it works fine, but in the above code when I'm trying to post the id to the rating.php page, it does not send. $(function(){ $("a.vote_up").click(function(){ the_id = $(this).attr('id'); $("span#votes_count"+the_id).fadeOut("fast"); $.ajax({ type: "POST", data: "action=vote_up&id="+$(this).attr("id"), url: "votes.php", success: function(msg) { $("span#votes_up"+the_id).fadeOut(); $("span#votes_up"+the_id).html(msg); $("span#votes_up"+the_id).fadeIn(); var that = this; box.call(that); } }); }); }); rating.php <? $id = $_POST['id']; echo $id; ?> The html part is: <a href='javascript:;' class='vote_up' id='<?php echo $row['id']; ?>'>Vote Up!</a> I'll appriciate any help.

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  • CodeIgniter: problem using foreach in view

    - by krike
    I have a model and controller who gets some data from my database and returns the following array Array ( [2010] => Array ( [year] => 2010 [months] => Array ( [0] => stdClass Object ( [sales] => 2 [month] => Apr ) [1] => stdClass Object ( [sales] => 1 [month] => Nov ) ) ) [2011] => Array ( [year] => 2011 [months] => Array ( [0] => stdClass Object ( [sales] => 1 [month] => Nov ) ) ) ) It shows exactly what it should show but the key's have different names so I have no idea on how to loop through the years using foreach in my view. Arrays is something I'm not that good at yet :( this is the controller if you need to know: function analytics() { $this->load->model('admin_model'); $analytics = $this->admin_model->Analytics(); foreach ($analytics as $a): $data[$a->year]['year'] = $a->year; $data[$a->year]['months'] = $this->admin_model->AnalyticsMonth($a->year); endforeach; echo"<pre style='text-align:left;'>"; print_r($data); echo"</pre>"; $data['main_content'] = 'analytics'; $this->load->view('template_admin', $data); }//end of function categories()

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  • Send file FTP over SSL with custom port number

    - by JM4
    I have asked the question before but in a different manner. I am trying taking form data, compiling into a temporary CSV file and trying to send over to a client via FTP over SSL (this is the only route I am interested in hearing solutions for unless there is a workaround to doing this, I cannot make changes). I have tried the following: ftp_connect - nothing happens, the page just times out ftp_ssl_connect - nothing happens, the page just times out curl library - same thing, given URL it also gives error. I am given the following information: FTPS Server IP Address TCP Port (1234) Username Password Data Directory to dump file FTP Mode: Passive very, very basic code (which I believe should initiate a connection at minimum): Code: <?php $ftp_server = "00.000.00.000"; //masked for security $ftp_port = "1234"; // masked but not 990 $ftp_user_name = "username"; $ftp_user_pass = "password"; // set up basic ssl connection $conn_id = ftp_ssl_connect($ftp_server, $ftp_port, "20"); // login with username and password $login_result = ftp_login($conn_id, $ftp_user_name, $ftp_user_pass); echo ftp_pwd($conn_id); // / echo "hello"; // close the ssl connection ftp_close($conn_id); ?> When I run this over a SmartFTP client, everything works just fine. I just can't get it to work using PHP (which is a necessity). Has anybody had success doing this in the past? I would be very interested to hear your approach.

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  • Check if date is allowed weekday in php?

    - by moogeek
    Hello! I'm stuck with a problem how to check if a specific date is within allowed weekdays array in php. For example, function dateIsAllowedWeekday($_date,$_allowed) { if ((isDate($_date)) && (($_allowed!="null") && ($_allowed!=null))){ $allowed_weekdays=json_decode($_allowed); $weekdays=array(); foreach($allowed_weekdays as $wd){ $weekday=date("l",date("w",strtotime($wd))); array_push($weekdays,$weekday); } if(in_array(date("l",strtotime($_date)),$weekdays)){return TRUE;} else {return FALSE;} } else {return FALSE;} } ///////////////////////////// $date="21.05.2010"; $wd="[0,1,2]"; if(dateIsAllowedWeekday($date,$wd)){echo "$date is within $wd weekday values!";} else{echo "$date isn't within $wd weekday values!"} I have input dates formatted as "d.m.Y" and an array returned from database with weekday numbers (formatted as 'Numeric representation of the day of the week') like [0,1,2] - (Sunday,Monday,Tuesday). The returned string from database can be "null", so i check it too. Them, the isDate function checks whether date is a date and it is ok. I want to check if my date, for example 21.05.2010 is an allowed weekday in this array. My function always returns TRUE and somehow weekday is always 'Thursday' and i don't know why... Is there any other ways to check this or what can be my error in the code above? thx

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  • Getting the last User ID in Zend Framework

    - by Ryan Murphy
    Using MySQL query browser, I manually made a table called users and input some date in the fields. I set the primary key to id and set it to auto increment. There are 3 rows, the highest id is 3. I then made the following class in the method directory to call upon the data in the table etc. class Application_Model_DbTable_User extends Zend_Db_Table_Abstract { protected $_name = 'user'; public function getLatestUserId() { $id = $this->getAdapter()->lastInsertId(); return $id; } } In the controller I do the following which gets the value generated by the method and lets the view access it: $usersDbModel = new Application_Model_DbTable_User(); $lastUserId = $usersDbModel->getLatestUserId(); $this->view->lastUserId = $lastUserId; In the view I then echo it to display it to the user: echo $this->lastUserId; However, even though my last id in the users table is 3. It displays 0. I have also tried: public function getLatestUserId() { $sql = 'SELECT max(id) FROM user'; $query = $this->query($sql); $result = $query->fetchAll(); return $result; } But this just throws out a server error. What have I done wrong? Am I missing something? Is there another way of doing this?

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  • Yii Framework Tutorial - file not found

    - by Heshan Perera
    I am in the process of learning the Yii Framework. I have been following this Tutorial. I have followed all the steps and have by index page loading. In my index.php page I point to two other pages located in protected/views/message The following is the code in my index.php located in the message folder mentioned above. <html> <body> <h1>Welcome</h1> <p> To view our message go to... <?php echo CHtml::link('Here', '/message/show')?> </p> <p> To edit our message go to... <?php echo CHtml::link('Here', '/message/edit')?> </p> </body> </html> "message" is the ID I gave when generating the model and controller through the yii shell application. The problem is, after the above page loads, and I click on any one of the above URLs, it points to "localhost:8080/message/show" and "localhost:8080/message/edit" , whereas the real location of these files is "localhost:8080/test/protected/views/message/..." What could I be doing wrong ?

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  • Magento help with creating model in custom class

    - by dardub
    I'm trying to add some custom filter methods to my magento module. I though it would be simple but I can't figure out why it's not working. My model which extends the catalog/product class contains this: public function filterProdType($prod_id) { $this->addAttributeToFilter('attribute_set_id', $prod_id); } Then in my template I have this: $collection = Mage::getModel('configurator/product')->getCollection()->addAttributeToSelect('*'); $collection->filterProdType(50)->addAttributeToFilter('type_id', 'bundle'); foreach ($collection as $item){ echo $item->getName() . ', '; } Just to try things out. But I don't get any results, no error, and it doesn't finish rendering the page (missing footer). When I do this instead, it works: $collection = Mage::getModel('configurator/product')->getCollection()->addAttributeToSelect('*'); $collection->addAttributeToFilter('attribute_set_id', 50)->addAttributeToFilter('type_id', 'bundle'); foreach ($collection as $item){ echo $item->getName() . ', '; } I'm just wondering what I'm missing. UPDATE: I didn't realize error reporting was turned off, after turning it on I get the error: Fatal error: Call to undefined method Mage_Catalog_Model_Resource_Eav_Mysql4_Product_Collection::filterProdType() I assumed after instantiating $collection using my custom model, it would find my new method.

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  • HTML relative links on various domains

    - by Adam Kiss
    I have quickie: When you code/develop themes, how do you link to various files in your html/css code? Example: We at our firm use mostly <base target="http://whatever"> in our main template and then just <img src="./images/file.png"> in our html, "/category/page" as links and something alike in our css. However, when testing on different machines, we use ip address rather than localhost on main dev station of coder, so all base links don't work (because localhost goes to viewing machine, not coder's, in our network). Same thing happens when updating pages - on dev server, we have to edit base target, so browsing site won't take us to live site - this part is actually rather simple PHP (if ... echo else echo something else), but it still not solve problem of more coding-testing problems. So, my question is, how do YOU solve it? How do you use relative links, which basically don't care for what domain is the page on and don't care for url rewrite? (because ../images/ is different for / and different for /something/somethingElse/page)?

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  • How to inject php code from database into php script ?

    - by luxquarta
    I want to store php code inside my database and then use it into my script. class A { public function getName() { return "lux"; } } // instantiates a new A $a = new A(); Inside my database there is data like "hello {$a->getName()}, how are you ?" In my php code I load the data into a variable $string $string = load_data_from_db(); echo $string; // echoes hello {$a->getName()}, how are you ? So now $string contains "hello {$a-getName()}, how are you ?" {$a-getName()} still being un-interpretated Question: I can't find how to write the rest of the code so that {$a-getName()} gets interpretated "into hello lux, how are you". Can someone help ? $new_string = ?????? echo $new_string; //echoes hello lux, how are you ? Is there a solution with eval() ? (please no debate about evil eval ;)) Or any other solution ?

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  • How to disable a checkbox based on date using php?

    - by udaya
    I have iterated a table based on my query result... I have a column lastDate it contains a date value like 01/24/2010... Now i have to check the date value with the current date if currentdate is less than or equal to lastDate i have to enable the checkbox else disable it..... Any suggestion how it can be done in php... Here is my code <? if(isset($comment)) { echo '<tr><td class=table_label colspan=5>'.$comment.'</td></tr>'; } ?> <td align="center" class="table_label" id="txtsubdat"> <? $dd=$row['dDate']; if($dd=='') { } else { $str = $dd; $dd = strtotime ( $str ); echo date ( 'm/d/Y' , $dd ); } ?> </td> <td align="center"> <input type="checkbox" name="group" id="group" value="<?=$row['dAssignment_id']?>" onclick="checkdisplay(this);"> </td> <? } ?>

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  • PHP unlink OR rewrite own/current file by itself

    - by Email
    Hi Task: Cut or erase a file after first walk-through. i have an install file called "index.php" which creates another php file. <? /* here some code*/ $fh = fopen($myFile, 'w') or die("can't open file"); $stringData = "<?php \n echo 'hallo, *very very long text*'; \n ?>"; fwrite($fh, $stringData); /*herecut"/ /*here some code */ after the creation of the new file this file is called and i intent to erase the filecreation call since it is very long and only needed on first install. i therefor add to the above code echo 'hallo, *very very long text*'; \n ***$new= file_get_contents('index.php'); \n $findme = 'habanot'; $pos = strpos($new, $findme); if ($pos === false) { $marker='herecut';\n $new=strstr($new,$marker);\n $new='<?php \n /*habanot*/\n'.$new;\n $fh = fopen('index.php', 'w') or die 'cant open file'); $stringData = $new; fwrite($fh, $stringData); fclose($fh);*** ?>"; fwrite($fh, $stringData);]} Isnt there an easier way or a function to modify the current file or even "self destroy" a file after first call? Regards

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  • Cache layer for MVC - Model or controller?

    - by Industrial
    Hi everyone, I am having some second thoughts about where to implement the caching part. Where is the most appropriate place to implement it, you think? Inside every model, or in the controller? Approach 1 (psuedo-code): // mycontroller.php MyController extends Controller_class { function index () { $data = $this->model->getData(); echo $data; } } // myModel.php MyModel extends Model_Class{ function getData() { $data = memcached->get('data'); if (!$data) { $query->SQL_QUERY("Do query!"); } return $data; } } Approach 2: // mycontroller.php MyController extends Controller_class { function index () { $dataArray = $this->memcached->getMulti('data','data2'); foreach ($dataArray as $key) { if (!$key) { $data = $this->model->getData(); $this->memcached->set($key, $data); } } echo $data; } } // myModel.php MyModel extends Model_Class{ function getData() { $query->SQL_QUERY("Do query!"); return $data; } } Thoughts: Approach 1: No multiget/multi-set. If a high number of keys would be returned, overhead would be caused. Easier to maintain, all database/cache handling is in each model Approach 2: Better performancewise - multiset/multiget is used More code required Harder to maintain Tell me what you think!

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  • Load PHP function with jQuery Ajax

    - by brandon14_99
    I have a file which is loaded at the top of my document, which is called Videos.php. Inside that file are several functions, such as getYoutubeVideos. On some pages, I need to call upon that function several times (up to 50), and it of course creates major lag on load times. So I have been trying to figure out how to call that function in, only when it is need (when someone clicks the show videos button). I have very little experience with jQuery's ajax abilities. I would like the ajax call to be made inside of something like this: jQuery('a[rel=VideoPreview1).click(function(){ jQuery ("a[rel=VideoPreview1]").hide(); jQuery ("a[rel=HideVideoPreview1]").show(); jQuery ("#VideoPreview1").show(); //AJAX STUFF HERE preventDefault(); }); Ok I have created this based on the responses, but it is still not working: jQuery Code: jQuery(document).ready(function(){ jQuery("a[rel=VideoPreview5]").click(function(){ jQuery("a[rel=VideoPreview5]").hide(); jQuery("a[rel=HideVideoPreview5]").show(); jQuery.post("/Classes/Video.php", {action: "getYoutubeVideos", artist: "Train", track: "Hey, Soul Sister"}, function(data){ jQuery("#VideoPreview5").html(data); }, 'json'); jQuery("#VideoPreview5").show(); preventDefault(); }); jQuery("a[rel=HideVideoPreview5]").click(function(){ jQuery("a[rel=VideoPreview5]").show(); jQuery("a[rel=HideVideoPreview5]").hide(); jQuery("#VideoPreview5").hide(); preventDefault(); }); }); And the PHP code: $Action = isset($_POST['action']); $Artist = isset($_POST['artist']); $Track = isset($_POST['track']); if($Action == 'getYoutubeVideos') { echo 'where are the videos'; echo json_encode(getYoutubeVideos($Artist.' '.$Track, 1, 5, 'relevance')); }

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  • Problem with checkboxes, sql select statements & php

    - by smokey20
    I am trying to display some rows from a database table based on choices submitted by the user. Here is my form code <form action="choice.php" method="POST" > <input type="checkbox" name="variable[]" value="Apple">Apple <input type="checkbox" name="variable[]" value="Banana">Banana <input type="checkbox" name="variable[]" value="Orange">Orange <input type="checkbox" name="variable[]" value="Melon">Melon <input type="checkbox" name="variable[]" value="Blackberry">Blackberry From what I understand I am placing the values of these into an array called variable. Two of my columns are called receipe name and ingredients(each field under ingredients can store a number of fruits). What I would like to do is, if a number of checkboxes are selected then the receipe name/s is displayed. Here is my php code. <?php // Make a MySQL Connection mysql_connect("localhost", "*****", "*****") or die(mysql_error()); mysql_select_db("****") or die(mysql_error()); $variable=$_POST['variable']; foreach ($variable as $variablename) { echo "$variablename is checked"; } $query = "SELECT receipename FROM fruit WHERE $variable like ingredients"; $row = mysql_fetch_assoc($result); foreach ($_POST['variabble'] as $ingredients) echo $row[$ingredients] . '<br/>'; ?> I am very new to php and just wish to display the data, I do not need to perform any actions on it. I have tried many select statements but I cannot get any results to display. My db connection is fine and it does print out what variables are checked. Many thanks in advance.

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  • Making a Function-Activated Link Appear Without Having to Refresh Browser

    - by John
    Hello, I'm trying to use the code below to make the <a href='http://www...com/.../footervote.php'>Vote</a> link appear if a user logs in and a user shows up in the function getEditorsList(). The vote link only appears if the browser is refreshed. Any idea how I could make the vote link appear without having to refresh the browser? Thanks in advance, John index.php: <?php require_once "header.php"; //content include "login.php"; // more content require_once "footer.php"; ?> In header.php: <?php error_reporting(0); session_start(); require_once ('db_connect.inc.php'); require_once ("function.inc.php"); $seed="0dAfghRqSTgx"; $domain = "...com"; $editors = getEditorsList(); foreach($editors as $editor) { $editorids[] = $editor['loginid']; } if(in_array($_SESSION['loginid'], $editorids)) { echo "<div class='footervote'><a href='http://www...com/.../footervote.php'>Vote</a></div>"; } ?> login.php: <?php if (!isLoggedIn()) { if (isset($_POST['cmdlogin'])) { if (checkLogin($_POST['username'], $_POST['password'])) { show_userbox(); } else { echo "Incorrect Login information !"; show_loginform(); } } else { show_loginform(); } } else { show_userbox(); } ?>

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  • Increase and decrease row value by 1 in MySQL

    - by Elliott
    Hi I have a MySQL database table "points" the user can click a button and a point should be removed from their account, the button they pressed has an ID of another user, therefore their account must increase by one. I have it working in jQuery and checked the varibles/posts in Firebug, and it does send the correct data, such as: userid= 1 posterid = 4 I think the problem is with my PHP page: <?php include ('../functions.php'); $userid=mysql_real_escape_string($_POST['user_id']); $posterid=mysql_real_escape_string($_POST['poster_id']); if (loggedin()) { include ('../connection.php'); $query1 = "UPDATE `points` SET `points` = `points` - 1 WHERE `userID` = '$userid'"; $result1=mysql_query($query1); $query2 = "UPDATE `points` SET `points` = `points` + 1 WHERE `userID` = '$posterid'"; $result2=mysql_query($query2); if ($result1 && result2) { echo "Successful"; return 1; } else { echo mysql_error(); return 0; } } ?> Any ideas? Thanks :)

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  • minifying final html output using regex with codeigniter

    - by Aman
    Google pages suggest you to minify html i.e. remove all the un-necessary spaces. Codeigniter does have feature of giziping output or it can be done via .htaccess. But still I also would like to remove un-necessary spaces from final html output as well. I played a bit with this peace of code to do it, and it seem to work. This does indeed result in html that is without excess spaces and removes other tab formatting. class Welcome extends CI_Controller { function _output() { echo preg_replace('!\s+!', ' ', $output); } function index(){ ... } } Now the problem with this is there may be tag like <pre>,<textarea>, etc.. which may have space in it and regx should remove them. So, how do I remove excess space from final html, without effecting spaces or formatting for these certain tags using regx? Thanks to @Alan Moore got the answer, this worked for me echo preg_replace('#(?ix)(?>[^\S ]\s*|\s{2,})(?=(?:(?:[^<]++|<(?!/?(?:textarea|pre)\b))*+)(?:<(?>textarea|pre)\b|\z))#', ' ', $output); @ridgerunner here did very good job of analyzing this regx, ended up using his solution. Cheers to ridgerunner.

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  • gevent urllib is slow

    - by djay
    I've created a set of demos of a TCP server however my gevent examples are noticely slower. I'm sure must be how I compiled gevent but can't work out the problem. I'm using OSX leopard using fink compiled python 2.6 and 2.7. I've tried both the stable gevent and gevent 1.0b1 and it acts the same. The echo takes 5 seconds to respond, where the other examples take <1sec. If I remove the urllib call then the problem goes away. I put all the code in https://github.com/djay/geventechodemo To run the examples I'm using zc.buildout so to build $ python2.7 bootstrap.py $ bin/buildout To run the gevent example: $ bin/py geventecho3.py & [1] 80790 waiting for connection... $ telnet localhost 8080 Trying 127.0.0.1... ...connected from: ('127.0.0.1', 56588) Connected to localhost. Escape character is '^]'. hello echo: avast This will take 3-4 seconds to respond on my system. However the twisted example $ bin/py threadecho2.py or the twisted example $ bin/py twistedecho2.py Is less than 1s. Any idea what I'm doing wrong?

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  • How do I use curl to display a table on a page?

    - by user272899
    I want to use curl to retrieve a table from an external page. So far my code retrieves all data from the page. I have read that using preg_match or preg_replace is the way to go about it. This is my code so far: <?php $ch = curl_init() or die(curl_error()); curl_setopt($ch, CURLOPT_URL,"http://www.megaupload.com/?d=XE30L1GA&w=631&h=392"); curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1); $data1=curl_exec($ch) or die(curl_error()); echo "<font color=black face=verdana size=3>".$data1."</font>"; echo curl_error($ch); curl_close($ch); ?> This is the data I want to retrieve from the page: <FORM method="POST" id="captchaform"> <INPUT type="hidden" name="captchacode" value="1a589e0a53c54f937eb8"> <INPUT type="hidden" name="megavar" value="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"> <TR> <TD>Enter this </TD> <TD width="100" align="center" height="40"><img src="http://wwwq32.megaupload.com/gencap.php?23243f17c2404dd4.gif" border="0" alt=""></TD> <TD> here:</TD> <TD><input type="text" name="captcha" id="captchafield" maxlength="4" style="border:solid 1px; border-color:#C4C4C4; background-color:#F9F9F9; width:50px; height:25px;"></TD> </TR> </FORM>

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