Search Results

Search found 70390 results on 2816 pages for 'file upload'.

Page 124/2816 | < Previous Page | 120 121 122 123 124 125 126 127 128 129 130 131  | Next Page >

  • PHP resizing PNGs results in corrupted files

    - by Robert
    I have a PHP script that resizes .jpg, .gif, and .png files to a bounding box. $max_width = 500; $max_height = 600; $filetype = $_FILES["file"]["type"]; $source_pic = "img/" . $idnum; if($filetype == "image/jpeg") { $src = imagecreatefromjpeg($source_pic); } else if($filetype == "image/png") { $src = imagecreatefrompng($source_pic); } else if($filetype == "image/gif") { $src = imagecreatefromgif($source_pic); } list($width,$height)=getimagesize($source_pic); $x_ratio = $max_width / $width; $y_ratio = $max_height / $height; if( ($width <= $max_width) && ($height <= $max_height) ) { $tn_width = $width; $tn_height = $height; } else if (($x_ratio * $height) < $max_height) { $tn_height = ceil($x_ratio * $height); $tn_width = $max_width; } else { $tn_width = ceil($y_ratio * $width); $tn_height = $max_height; } $tmp = imagecreatetruecolor($tn_width,$tn_height); imagecopyresampled($tmp,$src,0,0,0,0,$tn_width, $tn_height,$width,$height); $destination_pic = "img/thumbs/" . $idnum . "thumb"; if($filetype == "image/jpeg") { imagejpeg($tmp,$destination_pic,80); } else if($filetype == "image/png") { imagepng($tmp,$destination_pic,80); } else if($filetype == "image/gif") { imagegif($tmp,$destination_pic,80); } imagedestroy($src); imagedestroy($tmp); The script works fine with jpeg and gif but when running on a png the file will be corrupted. Is there anything special I need to use when working with a png? I have never worked with this sort of thing in PHP so I'm not very familiar with it.

    Read the article

  • Reading and writing to files simultaneously?

    - by vipersnake005
    Moved the question here. Suppose, I want to store 1,000,000,000 integers and cannot use my memory. I would use a file(which can easily handle so much data ). How can I let it read and write and the same time. Using fstream file("file.txt', ios::out | ios::in ); doesn't create a file, in the first place. But supposing the file exists, I am unable to use to do reading and writing simultaneously. WHat I mean is this : Let the contents of the file be 111111 Then if I run : - #include <fstream> #include <iostream> using namespace std; int main() { fstream file("file.txt",ios:in|ios::out); char x; while( file>>x) { file<<'0'; } return 0; } Shouldn't the file's contents now be 101010 ? Read one character and then overwrite the next one with 0 ? Or incase the entire contents were read at once into some buffer, should there not be atleast one 0 in the file ? 1111110 ? But the contents remain unaltered. Please explain. Thank you.

    Read the article

  • Windows 7: Can't see ISO file in C:\

    - by cbp
    I used DVD shrink to create an ISO file and saved it into C:\ The ISO file is visible with some programs but not with others. The file is not hidden as far as I am aware. But it cannot be seen by Windows Explorer, DVD Decrypter or a bunch of other programs. If I search for the file using Windows 7's Start Menu search tool, I can see the file and I can right click and select Properties. The Properties window appears OK, but if I try to change tabs on the property window, I receive an error message as though the file is not there. DVD Shrink can still open the file OK. I can also find the file using Agent Ransack (a file searching tool), but then I cannot open it. What gives?

    Read the article

  • optimizing file share performance on Win2k8?

    - by Kirk Marple
    We have a case where we're accessing a RAID array (drive E:) on a Windows Server 2008 SP2 x86 box. (Recently installed, nothing other than SQL Server 2005 on the server.) In one scenario, when directly accessing it (E:\folder\file.xxx) we get 45MBps throughput to a video file. If we access the same file on the same array, but through UNC path (\server\folder\file.xxx) we get about 23MBps throughput with the exact same test. Obviously the second test is going through more layers of the stack, but that's a major performance hit. What tuning should we be looking at for making the UNC path be closer in performance to the direct access case? Thanks, Kirk (corrected: it is CIFS not SMB, but generalized title to 'file share'.) (additional info: this happens during the read from a single file, not an issue across multiple connections. the file is on the local machine, but exposed via file share. so client and file server are both same Windows 2008 server.)

    Read the article

  • undelete big files - mission impossible?

    - by johnrembo
    Hi, I've accidentaly deleted outlook.pst (6.7GB) file, while there was only 400MB free space left on primary NTFS partition (winxp). I've tried several recovery tools to get this file back. "Ontrack Easy Recovery Pro" found 0 pst files (complete scan mode), while "Recover My Files" in sector scan mode found 5 pst's, but 4 of them of sizes from 3 to 28 KB, while the 5th one - 1Gb. I've managed to succesfuly recover 1Gb pst file, which was 1 year old copy (the one used after the latest windows reinstall). Now, I'm frustrated and confused Why 1 year old file was succesfuly recovered if there were only 400MB left on primary partition? Where's 6.7GB file gone? I did some reading (i.e. here), and it seems that there's almost no probability to retrieve the file I'm looking for, but wait - none of recovery tools i've used found zero-sized pst file, moreover - if due to fragmentation a file might be corrupted - we could use scanpst.exe to fix some errors and survive with 10 or 100 emails missing - whatever. Could you please recommend some more sophisticated recovery tools for this particular task? Appretiate your help - thanks in advance

    Read the article

  • Is it possible to download extremely large files intelligently or in parts via SSH from Linux to Windows?

    - by Andrew
    I have a ~35 GB file on a remote Linux Ubuntu server. Locally, I am running Windows XP, so I am connecting to the remote Linux server using SSH (specifically, I am using a Windows program called SSH Secure Shell Client version 3.3.2). Although my broadband internet connection is quite good, my download of the large file often fails with a Connection Lost error message. I am not sure, but I think that it fails because perhaps my internet connection goes out for a second or two every several hours. Since the file is so large, downloading it may take 4.5 to 5 hours, and perhaps the internet connection goes out for a second or two during that long time. I think this because I have successfully downloaded files of this size using the same internet connection and the same SSH software on the same computer. In other words, sometimes I get lucky and the download finishes before the internet connection drops for a second. Is there any way that I can download the file in an intelligent way -- whereby the operating system or software "knows" where it left off and can resume from the last point if a break in the internet connection occurs? Perhaps it is possible to download the file in sections? Although I do not know if I can conveniently split my file into multiple files -- I think this would be very difficult, since the file is binary and is not human-readable. As it is now, if the entire ~35 GB file download doesn't finish before the break in the connection, then I have to start the download over and overwrite the ~5-20 GB chunk that was downloaded locally so far. Do you have any advice? Thanks.

    Read the article

  • Command line switching

    - by Larry
    I have read through some suggestions but I am just not technical enough to get this I think. I am a CAD designer and each file has 5 files associated with it. I have 3 sets of 5 files, and each set needs to go into its own zip file, placed on a separate server. For example: "C:\Program Files\7-zip\7z.exe" a file1.zip "O:\server2\map files\BC\BC.d*"-0 "C:\Program Files\7-zip\7z.exe" a file2.zip "O:\server2\map files\BC\ON.d*"-0 "C:\Program Files\7-zip\7z.exe" a file3.zip "O:\server2\map files\BC\AB.d*"-0 and I am in directory "S:\server\map files\provinces" (for example). These lines run within an existing batch file and by the time it reaches the 3 lines above, it's in the S: directory sample above. So it's looking on my pc for the 7-zip program, creating 3 zip file names which it does, but places those zip files on a separate server which it doesn't and the first zip file also includes all the other 10 files, the second zip file the same plus the first zip file, and the third the same with the other two zip files making me think the code isn't recognizing the part after file1.zip where I am trying to tell it what files to include and where to place the zip files. Ultimately, I want to either have the system create a new zip file if the old one was deleted, or copy the new files into the existing zip and overwrite any older files, and for these zip files to be placed in a separate location which is where we share our files with other personnel from within our company. The S: drive is for all originals, and O: is for sharing. Is there a list of all switching options with many different samples?

    Read the article

  • how to write or what is the concept behind the file unlocker program

    - by Jach Many
    Recently i was trying to delete a file thinking that i had closed the program which is manipulating the file but it did not delete because the program was still running. I misunderstood that file as an unwanted file. So i used the file unlocker program to find which process is manipulating that file. That program really worked well by showing the process which was handling that file. and that file was http://download.cnet.com/Unlocker/3000-2248_4-10493998.html. What i want to know is i would like to write a program in win32 C or .net to mimic the same process. Just to find which process is handling which file. and if possible to close it. Or i want to know the concept behind that. I know this cannot be explained in a few paragraphs yet if i could get some references or external links to references then that could be nice.

    Read the article

  • c# Uploading files to ftp server

    - by etarvt
    Hi there, I have a problem with uploading files to ftp server. I have a few buttons. Every button uploads different files to the ftp. The first time when a button is clicked the file is uploaded successfully, but the second and later tries fail. It gives me "The operation has timed out". When I close the site and then open it again I can upload again only one file. I am sure that I can override files on the ftp. Here's the code: protected void btn_export_OnClick(object sender, EventArgs e) { Stream stream = new MemoryStream(); stream.Position = 0; // fill the stream bool res = this.UploadFile(stream, "test.csv", "dir"); stream.Close(); } private bool UploadFile(Stream stream, string filename, string ftp_dir) { stream.Seek(0, SeekOrigin.Begin); string uri = String.Format("ftp://{0}/{1}/{2}", "host", ftp_dir, filename); try { FtpWebRequest reqFTP = (FtpWebRequest)FtpWebRequest.Create(new Uri(uri)); reqFTP.Credentials = new NetworkCredential("user", "pass"); reqFTP.Method = WebRequestMethods.Ftp.UploadFile; reqFTP.KeepAlive = false; reqFTP.UseBinary = true; reqFTP.UsePassive = true; reqFTP.ContentLength = stream.Length; reqFTP.EnableSsl = true; // it's FTPES type of ftp int buffLen = 2048; byte[] buff = new byte[buffLen]; int contentLen; try { Stream ftpStream = reqFTP.GetRequestStream(); contentLen = stream.Read(buff, 0, buffLen); while (contentLen != 0) { ftpStream.Write(buff, 0, contentLen); contentLen = stream.Read(buff, 0, buffLen); } ftpStream.Flush(); ftpStream.Close(); } catch (Exception exc) { this.lbl_error.Text = "Error:<br />" + exc.Message; this.lbl_error.Visible = true; return false; } } catch (Exception exc) { this.lbl_error.Text = "Error:<br />" + exc.Message; this.lbl_error.Visible = true; return false; } return true; } Does anyone have idea what may cause this strange behaviour? I think I'm closing all streams accurately. Could this be related with the ftp server settings? The admin said that the ftp handshake never happened second time.

    Read the article

  • Pass string between two threads in java

    - by geeta
    I have to search a string in a file and write the matched lines to another file. I have a thread to read a file and a thread to write a file. I want to send the stringBuffer from read thread to write thread. Please help me to pass this. I amm getting null value passed. write thread: class OutputThread extends Thread{ /****************** Writes the line with search string to the output file *************/ Thread runner1,runner; File Out_File; public OutputThread() { } public OutputThread(Thread runner,File Out_File) { runner1 = new Thread(this,"writeThread"); // (1) Create a new thread. this.Out_File=Out_File; this.runner=runner; runner1.start(); // (2) Start the thread. } public void run() { try{ BufferedWriter bufferedWriter=new BufferedWriter(new FileWriter(Out_File,true)); System.out.println("inside write"); synchronized(runner){ System.out.println("inside wait"); runner.wait(); } System.out.println("outside wait"); // bufferedWriter.write(line.toString()); Buffer Buf = new Buffer(); bufferedWriter.write(Buf.buffers); System.out.println(Buf.buffers); bufferedWriter.flush(); } catch(Exception e){ System.out.println(e); e.printStackTrace(); } } } Read Thraed: class FileThread extends Thread{ Thread runner; File dir; String search_string,stats; File Out_File,final_output; StringBuffer sb = new StringBuffer(); public FileThread() { } public FileThread(CountDownLatch latch,String threadName,File dir,String search_string,File Out_File,File final_output,String stats) { runner = new Thread(this, threadName); // (1) Create a new thread. this.dir=dir; this.search_string=search_string; this.Out_File=Out_File; this.stats=stats; this.final_output=final_output; this.latch=latch; runner.start(); // (2) Start the thread. } public void run() { try{ Enumeration entries; ZipFile zipFile; String source_file_name = dir.toString(); File Source_file = dir; String extension; OutputThread out = new OutputThread(runner,Out_File); int dotPos = source_file_name.lastIndexOf("."); extension = source_file_name.substring(dotPos+1); if(extension.equals("zip")) { zipFile = new ZipFile(source_file_name); entries = zipFile.entries(); while(entries.hasMoreElements()) { ZipEntry entry = (ZipEntry)entries.nextElement(); if(entry.isDirectory()) { (new File(entry.getName())).mkdir(); continue; } searchString(runner,entry.getName(),new BufferedInputStream(zipFile.getInputStream(entry)),Out_File,final_output,search_string,stats); } zipFile.close(); } else { searchString(runner,Source_file.toString(),new BufferedInputStream(new FileInputStream(Source_file)),Out_File,final_output,search_string,stats); } } catch(Exception e){ System.out.println(e); e.printStackTrace(); } } /********* Reads the Input Files and Searches for the String ******************************/ public void searchString(Thread runner,String Source_File,BufferedInputStream in,File output_file,File final_output,String search,String stats) { int count = 0; int countw = 0; int countl=0; String s; String[] str; String newLine = System.getProperty("line.separator"); try { BufferedReader br2 = new BufferedReader(new InputStreamReader(in)); //OutputFile outfile = new OutputFile(); BufferedWriter bufferedWriter = new BufferedWriter(new FileWriter(output_file,true)); Buffer Buf = new Buffer(); //StringBuffer sb = new StringBuffer(); StringBuffer sb1 = new StringBuffer(); while((s = br2.readLine()) != null ) { str = s.split(search); count = str.length-1; countw += count; if(s.contains(search)){ countl++; sb.append(s); sb.append(newLine); } if(countl%100==0) { System.out.println("inside count"); Buf.setBuffers(sb.toString()); sb.delete(0,sb.length()); System.out.println("outside notify"); synchronized(runner) { runner.notify(); } //outfile.WriteFile(sb,bufferedWriter); //sb.delete(0,sb.length()); } } } synchronized(runner) { runner.notify(); } br2.close(); in.close(); if(countw == 0) { System.out.println("Input File : "+Source_File ); System.out.println("Word not found"); System.exit(0); } else { System.out.println("Input File : "+Source_File ); System.out.println("Matched word count : "+countw ); System.out.println("Lines with Search String : "+countl); System.out.println("Output File : "+output_file.toString()); System.out.println(); } } catch(Exception e){ System.out.println(e); e.printStackTrace(); } } }

    Read the article

  • Java Client-Server problem when sending multiple files

    - by Jim
    Client public void transferImage() { File file = new File(ServerStats.clientFolder); String[] files = file.list(); int numFiles = files.length; boolean done = false; BufferedInputStream bis; BufferedOutputStream bos; int num; byte[] byteArray; long count; long len; Socket socket = null ; while (!done){ try{ socket = new Socket(ServerStats.imgServerName,ServerStats.imgServerPort) ; InputStream inStream = socket.getInputStream() ; OutputStream outStream = socket.getOutputStream() ; System.out.println("Connected to : " + ServerStats.imgServerName); BufferedReader inm = new BufferedReader(new InputStreamReader(inStream)); PrintWriter out = new PrintWriter(outStream, true /* autoFlush */); for (int itor = 0; itor < numFiles; itor++) { String fileName = files[itor]; System.out.println("transfer: " + fileName); File sentFile = new File(fileName); len = sentFile.length(); len++; System.out.println(len); out.println(len); out.println(sentFile); //SENDFILE bis = new BufferedInputStream(new FileInputStream(fileName)); bos = new BufferedOutputStream(socket.getOutputStream( )); byteArray = new byte[1000000]; count = 0; while ( count < len ){ num = bis.read(byteArray); bos.write(byteArray,0,num); count++; } bos.close(); bis.close(); System.out.println("file done: " + itor); } done = true; }catch (Exception e) { System.err.println(e) ; } } } Server public static void main(String[] args) { BufferedInputStream bis; BufferedOutputStream bos; int num; File file = new File(ServerStats.serverFolder); if (!(file.exists())){ file.mkdir(); } try { int i = 1; ServerSocket socket = new ServerSocket(ServerStats.imgServerPort); Socket incoming = socket.accept(); System.out.println("Spawning " + i); try { try{ if (!(file.exists())){ file.mkdir(); } InputStream inStream = incoming.getInputStream(); OutputStream outStream = incoming.getOutputStream(); BufferedReader inm = new BufferedReader(new InputStreamReader(inStream)); PrintWriter out = new PrintWriter(outStream, true /* autoFlush */); String length2 = inm.readLine(); System.out.println(length2); String filename = inm.readLine(); System.out.println("Filename = " + filename); out.println("ACK: Filename received = " + filename); //RECIEVE and WRITE FILE byte[] receivedData = new byte[1000000]; bis = new BufferedInputStream(incoming.getInputStream()); bos = new BufferedOutputStream(new FileOutputStream(ServerStats.serverFolder + "/" + filename)); long length = (long)Integer.parseInt(length2); length++; long counter = 0; while (counter < length){ num = bis.read(receivedData); bos.write(receivedData,0,num); counter ++; } System.out.println(counter); bos.close(); bis.close(); File receivedFile = new File(filename); long receivedLen = receivedFile.length(); out.println("ACK: Length of received file = " + receivedLen); } finally { incoming.close(); } } catch (IOException e){ e.printStackTrace(); } } catch (IOException e1){ e1.printStackTrace(); } } The code is some I found, and I have slightly modified it, but I am having problems transferring multiple images over the server. Output on Client: run ServerQueue.Client Connected to : localhost transfer: Picture 012.jpg 1312743 java.lang.ArrayIndexOutOfBoundsException Connected to : localhost transfer: Picture 012.jpg 1312743 Cant seem to get it to transfer multiple images. But bothsides I think crash or something because the file never finishes transfering

    Read the article

  • ruby on rails photo upload problem

    - by dodo00700
    Hallo rails version 2.3.5 I'm learning rails and I run into a problem. I'm doing some nesting forms from the railscasts tutorials. I changed the text area into a data field to upload photos and everything is working. Now i have to display the uploaded pictures and i simply can't do it. I Tried everything I could find on the net but nothing worked. PROBLEM I have the Article controller which handles the article CRUD. inside the article new form there is nested a form for uploading images. article controller def code_image @image_data = Photo.find(params[:id]) @image = @image_data.binary_data send_data(@image, :type => @image_data.content_type, :filename => @image_data.filename, :disposition => 'inline') end photo model def image_file=(input_data) self.filename = input_data.original_filename self.content_type = input_data.content_type.chomp self.binary_data = input_data.read end articles/show.html.erb <%=h @article.title %> <%=h @article.body %> <% for photos in @article.photos %> <%= image_tag(url_for({:action => 'code_image', :id => @article.photos.id})) -%> <% end %> articles/_formnew.html.erb <% form_for (:article, @article, :url => {:action=>'create'}, :html=> {:multipart=>true}) do |f| %> <%= f.error_messages % <%= f.label :title %><br /> <%= f.text_field :title %><br /><br /> <%= f.label :body %><br /> <%= f.text_area :body, :style => 'width: 600px;' %><br /><br /> <% f.fields_for :photos do |builder|%> <%= builder.label :content, "Photo"%><br /> <%= builder.file_field :image_file %><br /> <% end %> <br /> <%= f.submit "Create" %> <% end % Thanks

    Read the article

  • Upload picture directly to the server

    - by Rajeev
    In the following link http://www.tuttoaster.com/create-a-camera-application-in-flash-using-actionscript-3/ how to make the picture upload directly to the server after taking a picture from webcam package { import flash.display.Sprite; import flash.media.Camera; import flash.media.Video; import flash.display.BitmapData; import flash.display.Bitmap; import flash.events.MouseEvent; import flash.net.FileReference; import flash.utils.ByteArray; import com.adobe.images.JPGEncoder; public class caml extends Sprite { private var camera:Camera = Camera.getCamera(); private var video:Video = new Video(); private var bmd:BitmapData = new BitmapData(320,240); private var bmp:Bitmap; private var fileReference:FileReference = new FileReference(); private var byteArray:ByteArray; private var jpg:JPGEncoder = new JPGEncoder(); public function caml() { saveButton.visible = false; discardButton.visible = false; saveButton.addEventListener(MouseEvent.MOUSE_UP, saveImage); discardButton.addEventListener(MouseEvent.MOUSE_UP, discard); capture.addEventListener(MouseEvent.MOUSE_UP, captureImage); if (camera != null) { video.smoothing = true; video.attachCamera(camera); video.x = 140; video.y = 40; addChild(video); } else { trace("No Camera Detected"); } } private function captureImage(e:MouseEvent):void { bmd.draw(video); bmp = new Bitmap(bmd); bmp.x = 140; bmp.y = 40; addChild(bmp); capture.visible = false; saveButton.visible = true; discardButton.visible = true; } private function saveImage(e:MouseEvent):void { byteArray = jpg.encode(bmd); fileReference.save(byteArray, "Image.jpg"); removeChild(bmp); saveButton.visible = false; discardButton.visible = false; capture.visible = true; } private function discard(e:MouseEvent):void { removeChild(bmp); saveButton.visible = false; discardButton.visible = false; capture.visible = true; } } }

    Read the article

  • Save Files Directly from Your Browser to the Cloud in Chrome and Iron

    - by Asian Angel
    Are you looking for a quicker, easier way to upload files you find while browsing to your favorite cloud services? Skip saving files to your hard-drive and transfer them directly from your browser to your accounts using the Cloud Save extension. You can see the cloud services currently supported in the screenshot above and more are being added all the time. So if your favorite is not listed yet just keep checking in at the extension’s homepage. Cloud Save [Google Chrome Extensions] Latest Features How-To Geek ETC How to Get Amazing Color from Photos in Photoshop, GIMP, and Paint.NET Learn To Adjust Contrast Like a Pro in Photoshop, GIMP, and Paint.NET Have You Ever Wondered How Your Operating System Got Its Name? Should You Delete Windows 7 Service Pack Backup Files to Save Space? What Can Super Mario Teach Us About Graphics Technology? Windows 7 Service Pack 1 is Released: But Should You Install It? Save Files Directly from Your Browser to the Cloud in Chrome and Iron The Steve Jobs Chronicles – Charlie and the Apple Factory [Video] Google Chrome Updates; Faster, Cleaner Menus, Encrypted Password Syncing, and More Glowing Chess Set Combines LEDs, Chess, and DIY Electronics Fun Peaceful Alpine River on a Sunny Day [Wallpaper] Fast Society Creates Mini and Mobile Temporary Social Networks

    Read the article

  • Java Fx Data bind not working with File Read

    - by rjha94
    Hi I am using a very simple JavaFx client to upload files. I read the file in chunks of 1 MB (using Byte Buffer) and upload using multi part POST to a PHP script. I want to update the progress bar of my client to show progress after each chunk is uploaded. The calculations for upload progress look correct but the progress bar is not updated. I am using bind keyword. I am no JavaFx expert and I am hoping some one can point out my mistake. I am writing this client to fix the issues posted here (http://stackoverflow.com/questions/2447837/upload-1gb-files-using-chunking-in-php) /* * Main.fx * * Created on Mar 16, 2010, 1:58:32 PM */ package webgloo; import javafx.stage.Stage; import javafx.scene.Scene; import javafx.scene.layout.VBox; import javafx.geometry.VPos; import javafx.scene.control.Button; import javafx.scene.control.Label; import javafx.scene.layout.HBox; import javafx.scene.layout.LayoutInfo; import javafx.scene.text.Font; import javafx.scene.control.ProgressBar; import java.io.FileInputStream; /** * @author rajeev jha */ var totalBytes:Float = 1; var bytesWritten:Float = 0; var progressUpload:Float; var uploadURI = "http://www.test1.com/test/receiver.php"; var postMax = 1024000 ; function uploadFile(inputFile: java.io.File) { totalBytes = inputFile.length(); bytesWritten = 1; println("To-Upload - {totalBytes}"); var is = new FileInputStream(inputFile); var fc = is.getChannel(); //1 MB byte buffer var chunkCount = 0; var bb = java.nio.ByteBuffer.allocate(postMax); while(fc.read(bb) >= 0){ println("loop:start"); bb.flip(); var limit = bb.limit(); var bytes = GigaFileUploader.getBufferBytes(bb.array(), limit); var content = GigaFileUploader.createPostContent(inputFile.getName(), bytes); GigaFileUploader.upload(uploadURI, content); bytesWritten = bytesWritten + limit ; progressUpload = 1.0 * bytesWritten / totalBytes ; println("Progress is - {progressUpload}"); chunkCount++; bb.clear(); println("loop:end"); } } var label = Label { font: Font { size: 12 } text: bind "Uploaded - {bytesWritten * 100 / (totalBytes)}%" layoutInfo: LayoutInfo { vpos: VPos.CENTER maxWidth: 120 minWidth: 120 width: 120 height: 30 } } def jFileChooser = new javax.swing.JFileChooser(); jFileChooser.setApproveButtonText("Upload"); var button = Button { text: "Upload" layoutInfo: LayoutInfo { width: 100 height: 30 } action: function () { var outputFile = jFileChooser.showOpenDialog(null); if (outputFile == javax.swing.JFileChooser.APPROVE_OPTION) { uploadFile(jFileChooser.getSelectedFile()); } } } var hBox = HBox { spacing: 10 content: [label, button] } var progressBar = ProgressBar { progress: bind progressUpload layoutInfo: LayoutInfo { width: 240 height: 30 } } var vBox = VBox { spacing: 10 content: [hBox, progressBar] layoutX: 10 layoutY: 10 } Stage { title: "Upload File" width: 270 height: 120 scene: Scene { content: [vBox] } resizable: false }

    Read the article

  • Sorted list of file names in a folder in VBA?

    - by Karsten W.
    Is there a way to get a sorted list of file names of a folder in VBA? Up to now, I arrived at Dim fso As Object Dim objFolder As Object Dim objFileList As Object Dim vFile As Variant Dim sFolder As String sFolder = "C:\Docs" Set fso = CreateObject("Scripting.FileSystemObject") Set objFolder = fso.GetFolder(sFolder) Set objFileList = objFolder.Files For Each vFile In objFileList ' do something ' Next vFile but it is crucial to be sure the processing order of the for loop is determined by the file names... Any help appreciated!

    Read the article

  • Linking the Linker script file to source code

    - by user304097
    Hello , I am new to GNU compiler. I have a C source code file which contains some structures and variables in which I need to place certain variables at a particular locations. So, I have written a linker script file and used the __ attribute__("SECTION") at variable declaration, in C source code. I am using a GNU compiler (cygwin) to compile the source code and creating a .hex file using -objcopy option, but I am not getting how to link my linker script file at compilation to relocate the variables accordingly. I am attaching the linker script file and the C source file for the reference. Please help me link the linker script file to my source code, while creating the .hex file using GNU. /*linker script file*/ /*defining memory regions*/ MEMORY { base_table_ram : org = 0x00700000, len = 0x00000100 /*base table area for BASE table*/ mem2 : org =0x00800200, len = 0x00000300 /* other structure variables*/ } /*Sections directive definitions*/ SECTIONS { BASE_TABLE : { } > base_table_ram GROUP : { .text : { } { *(SEG_HEADER) } .data : { } { *(SEG_HEADER) } .bss : { } { *(SEG_HEADER) } } > mem2 } C source code: const UINT8 un8_Offset_1 __attribute__((section("BASE_TABLE"))) = 0x1A; const UINT8 un8_Offset_2 __attribute__((section("BASE_TABLE"))) = 0x2A; const UINT8 un8_Offset_3 __attribute__((section("BASE_TABLE"))) = 0x3A; const UINT8 un8_Offset_4 __attribute__((section("BASE_TABLE"))) = 0x4A; const UINT8 un8_Offset_5 __attribute__((section("BASE_TABLE"))) = 0x5A; const UINT8 un8_Offset_6 __attribute__((section("SEG_HEADER"))) = 0x6A; My intention is to place the variables of section "BASE_TABLE" at the address defined i the linker script file and the remaining variables at the "SEG_HEADER" defined in the linker script file above. But after compilation when I look in to the .hex file the different section variables are located in different hex records, located at an address of 0x00, not the one given in linker script file . Please help me in linking the linker script file to source code. Are there any command line options to link the linker script file, if any plese provide me with the info how to use the options. Thanks in advance, SureshDN.

    Read the article

  • How to add the time stamp to the log file

    - by swati
    ello Everyone, I am new to using apache logger . I have downloaded the log4j-xx and i have the following text configuration file Set root logger level to DEBUG and its only appender to mainFormat. log4j.rootLogger = TRACE, mainFormat, FILE mainFormat is set to be a ConsoleAppender. log4j.appender.mainFormat=org.apache.log4j.ConsoleAppender mainFormat uses PatternLayout. log4j.appender.mainFormat.layout=org.apache.log4j.PatternLayout log4j.appender.mainFormat.layout.ConversionPattern=%d [%t] %-5p %c - %m%n File makes a file of the output. log4j.appender.FILE=org.apache.log4j.FileAppender log4j.appender.FILE.File=log4j_HAPR001_OutputFile.log log4j.appender.FILE.layout=org.apache.log4j.PatternLayout log4j.appender.FILE.layout.ConversionPattern=%d [%t] %-5p %c - %m%n i use the above config file to create the log file. Now i wanted to add the current time stamp to the log file. Is there any way to do this. If yes can some one please give me the instructions how to do. Thanks in advance.

    Read the article

  • A Python Wrapper for Shutterfly. Uploading an Image

    - by iJames
    I'm working on a Django app in which I want to order prints through Shutterfly's Open API: http://www.shutterfly.com/documentation/start.sfly So far I've been able to build the appropriate POSTs and GETs using the modules and suggested code snippets including httplib, httplib2, urllib, urllib2, mimetype, etc. But I'm stuck on the image uploading when placing an order (the ordering process is not the same process as uploading images to albums which I haven't tried.) From what I can tell, I'm supposed to basically create the multipart form data by concatenating the HTTP request body together with the binary data of the image. I take the strings: --myuniqueboundary1273149960.175.1 Content-Disposition: form-data; name="AuthenticationID" auniqueauthenticationid --myuniqueboundary1273149960.175.1 Content-Disposition: file; name="Image.Data"; filename="1_41_orig.jpg" Content-Type: image/jpeg and I put this data into it and end with the final boundary: ...\xb5|\xf88\x1dj\t@\xd9\'\x1f\xc6j\x88{\x8a\xc0\x18\x8eGaJG\x03\xe9J-\xd8\x96[\x91T\xc3\x0eTu\xf4\xaa\xa5Ty\x80\x01\x8c\x9f\xe9Z\xad\x8cg\xba# g\x18\xe2\xaa:\x829\x02\xb4["\x17Q\xe7\x801\xea?\xad7j\xfd\xa2\xdf\x81\xd2\x84D\xb6)\xa8\xcb\xc8O\\\x9a\xaf(\x1cqM\x98\x8d*\xb8\'h\xc8+\x8e:u\xaa\xf3*\x9b\x95\x05F8\xedN%\xcb\xe1B2\xa9~Tw\xedF\xc4\xfe\xe8\xfc\xa9\x983\xff\xd9... That ends up making it look like this (when I use print to debug): ... --myuniqueboundary1273149960.175.1 Content-Disposition: file; name="Image.Data"; filename="1_41_orig.jpg" Content-Type: image/jpeg ????q?ExifMM* ? ??(1?2?<??i?b?NIKON CORPORATIONNIKON D40HHQuickTime 7.62009:02:17 13:05:25Mac OS X 10.5.6%??????"?'??0220?????? ???? ? ?|_???,b???50??5 ... --myuniqueboundary1273149960.175.1-- My code for grabbing the binary data is pretty much this: filedata = open('myjpegfile.jpeg','rb').read() Which I then add to the rest of the body. I've see something like this code everywhere. I'm then using this to post the full request (with the headers too): response = urllib2.urlopen(request).read() This seems to me to be the standard way that form POSTS with files happens. Am I missing something here? At some point I might be able to make this into a library worth posting up on github, but this problem has stopped me cold in my tracks. Thanks for any insight!

    Read the article

  • Sending Email with attachment, sends a blank file.

    - by pankaj
    I am using this code: File myDir = new File(getApplicationContext().getFilesDir().getAbsolutePath()); try { Log.i("CSV Testing ", "CSV file creating"); FileWriter fw = new FileWriter(myDir + "/myfile.csv"); // // write data to file // Log.i("CSV Testing ", "CSV file created and your data has been saved"); // Process for sending email with CSV file File CSVFile = new File(myDir,"myfile.csv"); if(CSVFile.exists()) { Log.i("CSV FILE", "CSV file exists"); } else { Log.i("CSV FILE", "CSV file not exists"); } Log.i("SEND EMAIL TESTING", "Email sending"); Intent emailIntent = new Intent(android.content.Intent.ACTION_SEND); emailIntent.setType("text/csv"); emailIntent .putExtra(android.content.Intent.EXTRA_EMAIL, new String[]{"myemailid"}); emailIntent .putExtra(android.content.Intent.EXTRA_SUBJECT, "my subject"); emailIntent .putExtra(android.content.Intent.EXTRA_TEXT, "_____________\n Regards \n Pankaj \n ____________ "); emailIntent.putExtra(Intent.EXTRA_STREAM, Uri.parse("file://" + CSVFile.getAbsolutePath())); emailIntent.setType("message/rfc822"); // Shows all application that supports SEND activity try { startActivity(Intent.createChooser(emailIntent, "Send mail...")); } catch (android.content.ActivityNotFoundException ex) { showMSG("There are no email clients installed."); } Log.i("SEND EMAIL TESTING", "Email sent"); } catch (FileNotFoundException e) { Log.i("ExportCSV Exception", e.toString()); } catch (IOException e) { Log.i("ExportCSV Exception", e.toString()); } But it sends myfile.csv as a blank file. I checked it from file explorer, where myfile.csv is not blank and contains right data. How can I solve this?

    Read the article

  • PHP Mcrypt - Encrypting / Decrypting file

    - by whitman6732
    Trying to write a couple of functions that will encrypt or decrypt a file and am using the class found here to try and accomplish this: http://www.itnewb.com/v/PHP-Encryption-Decryption-Using-the-MCrypt-Library-libmcrypt The encryption function below seems to work, in that it appears to encrypt the file and place it in the intended directory. I'm trying to decrypt the file now, and it just dies with the message "Failed to complete decryption" (which is coded in there...) There's nothing in the php error logs, so I'm not sure why it's failing, but as mcrypt is entirely new to me, I'm more than inclined to believe I'm doing something wrong here... Here are the functions: //ENCRYPT FILE function encryptFile() { global $cryptastic; $pass = PGPPASS; $salt = PGPSALT; $key = $cryptastic->pbkdf2($pass, $salt, 1000, 32) or die("Failed to generate secret key."); if ($handle = opendir(PATH.'/ftpd')) { while (false !== ($file = readdir($handle))) { if ($file != "." && $file != "..") { $newfile = PATH.'/encrypted/'.$file.'.txt'; $msg = file_get_contents(PATH.'/ftpd/'.$file); $encrypted = $cryptastic->encrypt($msg, $key) or die("Failed to complete encryption."); $nfile = fopen($newfile, 'w'); fwrite($nfile, $encrypted); fclose($nfile); unlink(PATH.'/ftpd/'.$file); } } closedir($handle); } //DECRYPT FILE function inFTP() { global $cryptastic; $pass = PGPPASS; $salt = PGPSALT; $key = $cryptastic->pbkdf2($pass, $salt, 1000, 32) or die("Failed to generate secret key."); if ($handle = opendir(PATH.'/encrypted')) { while (false !== ($file = readdir($handle))) { if ($file != "." && $file != "..") { $newfile = PATH.'/decrypted/'.$file; $msg = PATH.'/encrypted/'.$file; $decrypted = $cryptastic->decrypt($msg, $key) or die("Failed to complete decryption."); $nfile = fopen($newfile, 'w'); fwrite($nfile, $decrypted); fclose($nfile); //unlink(PATH.'/encrypted/'.$file); } } closedir($handle); } //$crypt->decrypt($file); }

    Read the article

< Previous Page | 120 121 122 123 124 125 126 127 128 129 130 131  | Next Page >