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  • java: how to compress data into a String and uncompress data from the String

    - by Guillaume
    I want to put some compressed data into a remote repository. To put data on this repository I can only use a method that take the name of the resource and its content as a String. (like data.txt + "hello world"). The repository is moking a filesystem but is not, so I can not use File directly. I want to be able to do the following: client send to server a file 'data.txt' server compress 'data.txt' into data.zip server send to repository content of data.zip repository store data.zip client download from repository data.zip and his able to open it with its favorite zip tool I have tried a lots of compressing example found on the web but each time a send the data to the repository, my resulting zip file is corrupted. Here is a sample class, using the zip*stream and that emulate the repository showcasing my problem. The created zip file is working, but after its 'serialization' it's get corrupted. (the sample class use jakarta commons.io ) Many thanks for your help. package zip; import java.io.File; import java.io.FileInputStream; import java.io.FileOutputStream; import java.io.IOException; import java.io.InputStream; import java.util.zip.ZipEntry; import java.util.zip.ZipInputStream; import java.util.zip.ZipOutputStream; import org.apache.commons.io.FileUtils; /** * Date: May 19, 2010 - 6:13:07 PM * * @author Guillaume AME. */ public class ZipMe { public static void addOrUpdate(File zipFile, File ... files) throws IOException { File tempFile = File.createTempFile(zipFile.getName(), null); // delete it, otherwise you cannot rename your existing zip to it. tempFile.delete(); boolean renameOk = zipFile.renameTo(tempFile); if (!renameOk) { throw new RuntimeException("could not rename the file " + zipFile.getAbsolutePath() + " to " + tempFile.getAbsolutePath()); } byte[] buf = new byte[1024]; ZipInputStream zin = new ZipInputStream(new FileInputStream(tempFile)); ZipOutputStream out = new ZipOutputStream(new FileOutputStream(zipFile)); ZipEntry entry = zin.getNextEntry(); while (entry != null) { String name = entry.getName(); boolean notInFiles = true; for (File f : files) { if (f.getName().equals(name)) { notInFiles = false; break; } } if (notInFiles) { // Add ZIP entry to output stream. out.putNextEntry(new ZipEntry(name)); // Transfer bytes from the ZIP file to the output file int len; while ((len = zin.read(buf)) > 0) { out.write(buf, 0, len); } } entry = zin.getNextEntry(); } // Close the streams zin.close(); // Compress the files if (files != null) { for (File file : files) { InputStream in = new FileInputStream(file); // Add ZIP entry to output stream. out.putNextEntry(new ZipEntry(file.getName())); // Transfer bytes from the file to the ZIP file int len; while ((len = in.read(buf)) > 0) { out.write(buf, 0, len); } // Complete the entry out.closeEntry(); in.close(); } // Complete the ZIP file } tempFile.delete(); out.close(); } public static void main(String[] args) throws IOException { final String zipArchivePath = "c:/temp/archive.zip"; final String tempFilePath = "c:/temp/data.txt"; final String resultZipFile = "c:/temp/resultingArchive.zip"; File zipArchive = new File(zipArchivePath); FileUtils.touch(zipArchive); File tempFile = new File(tempFilePath); FileUtils.writeStringToFile(tempFile, "hello world"); addOrUpdate(zipArchive, tempFile); //archive.zip exists and contains a compressed data.txt that can be read using winrar //now simulate writing of the zip into a in memory cache String archiveText = FileUtils.readFileToString(zipArchive); FileUtils.writeStringToFile(new File(resultZipFile), archiveText); //resultingArchive.zip exists, contains a compressed data.txt, but it can not //be read using winrar: CRC failed in data.txt. The file is corrupt } }

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  • Why am I getting 404 in Django?

    - by alex
    After installing this python Django module: http://code.google.com/p/django-compress/wiki/Installation I am getting 404's in my media static files. This Django module is supposed to "compress" the javascript/css files. That's why I'm getting 404 I guess. The problem is, I don't want this anymore. And when I installed this program, I did "python setup.py install" How do I install it? I just want to revert it back to normal so I don't get any 404 errors.

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  • Why is my GZipStream not writeable?

    - by Ozzah
    I have some GZ compressed resources in my program and I need to be able to write them out to temporary files for use. I wrote the following function to write the files out and return true on success or false on failure. In addition, I've put a try/catch in there which shows a MessageBox in the event of an error: private static bool extractCompressedResource(byte[] resource, string path) { try { using (MemoryStream ms = new MemoryStream(resource)) { using (FileStream fs = new FileStream(path, FileMode.Create, FileAccess.ReadWrite)) { using (GZipStream zs = new GZipStream(fs, CompressionMode.Decompress)) { ms.CopyTo(zs); // Throws exception zs.Close(); ms.Close(); } } } } catch (Exception ex) { MessageBox.Show(ex.Message); // Stream is not writeable return false; } return true; } I've put a comment on the line which throws the exception. If I put a breakpoint on that line and take a look inside the GZipStream then I can see that it's not writeable (which is what's causing the problem). Am I doing something wrong, or is this a limitation of the GZipStream class?

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  • mysql image disable print download

    - by Vish
    Hi, We use a Flex AIR client and a WAMP server. Tiff images are stored in MySQL. Currently, I can download the image from AIR client and it prompts for a download dialog. Things are fine till this point. We got a new requirement. Requirement is that only some users can print the image which gets downloaded. For other users, they should not be able to print the tiff image. Wondering how to accomplish this. One idea, not sure if its efficient, is to convert the image requested to pdf at the server side, disable print option there(hope there are API's available) and send back the pdf. Please let me know btter ideas. Also, is there a way to prevent file download dialog from popping up everytime the file is requested for download? Can we just get the file stream to the client and manipulate it to open with a particular viewer or write it to pdf... Please help.

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  • How to decompress/inflate an XML response from ASP

    - by krisg
    Can anyone provide some insight into how i'd go about decompressing an XML response in classic ASP. We've been handed some code and asked to get it working: Set oXMLHttp = Server.CreateObject("MSXML2.ServerXMLHTTP") URL = HttpServer + re_domain + ".do;jsessionid=" + ue_session + "?" + data oXMLHttp.setTimeouts 5000, 60000, 1200000, 1200000 oXMLHttp.open "GET", URL, false oXMLHttp.setRequestHeader "Accept-Encoding", "gzip" oXMLHttp.send() if oXMLHttp.status = 200 Then if oXMLHttp.responseText = "" then htmlrequest_get = "Empty Response from Server" else htmlrequest_get = oXMLHttp.responseText end if else ... Apparently now that the response is compressed using gzip, we have to un-compress the XML response before we can start to work with the data. How should i go about this?

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  • java: how to get a string representation of a compressed byte array ?

    - by Guillaume
    I want to put some compressed data into a remote repository. To put data on this repository I can only use a method that take the name of the resource and its content as a String. (like data.txt + "hello world"). The repository is moking a filesystem but is not, so I can not use File directly. I want to be able to do the following: client send to server a file 'data.txt' server compress 'data.txt' into a compressed file 'data.zip' server send a string representation of data.zip to the repository repository store data.zip client download from repository data.zip and his able to open it with its favorite zip tool The problem arise at step 3 when I try to get a string representation of my compressed file. Here is a sample class, using the zip*stream and that emulate the repository showcasing my problem. The created zip file is working, but after its 'serialization' it's get corrupted. (the sample class use jakarta commons.io ) Many thanks for your help. package zip; import java.io.File; import java.io.FileInputStream; import java.io.FileOutputStream; import java.io.IOException; import java.io.InputStream; import java.util.zip.ZipEntry; import java.util.zip.ZipInputStream; import java.util.zip.ZipOutputStream; import org.apache.commons.io.FileUtils; /** * Date: May 19, 2010 - 6:13:07 PM * * @author Guillaume AME. */ public class ZipMe { public static void addOrUpdate(File zipFile, File ... files) throws IOException { File tempFile = File.createTempFile(zipFile.getName(), null); // delete it, otherwise you cannot rename your existing zip to it. tempFile.delete(); boolean renameOk = zipFile.renameTo(tempFile); if (!renameOk) { throw new RuntimeException("could not rename the file " + zipFile.getAbsolutePath() + " to " + tempFile.getAbsolutePath()); } byte[] buf = new byte[1024]; ZipInputStream zin = new ZipInputStream(new FileInputStream(tempFile)); ZipOutputStream out = new ZipOutputStream(new FileOutputStream(zipFile)); ZipEntry entry = zin.getNextEntry(); while (entry != null) { String name = entry.getName(); boolean notInFiles = true; for (File f : files) { if (f.getName().equals(name)) { notInFiles = false; break; } } if (notInFiles) { // Add ZIP entry to output stream. out.putNextEntry(new ZipEntry(name)); // Transfer bytes from the ZIP file to the output file int len; while ((len = zin.read(buf)) > 0) { out.write(buf, 0, len); } } entry = zin.getNextEntry(); } // Close the streams zin.close(); // Compress the files if (files != null) { for (File file : files) { InputStream in = new FileInputStream(file); // Add ZIP entry to output stream. out.putNextEntry(new ZipEntry(file.getName())); // Transfer bytes from the file to the ZIP file int len; while ((len = in.read(buf)) > 0) { out.write(buf, 0, len); } // Complete the entry out.closeEntry(); in.close(); } // Complete the ZIP file } tempFile.delete(); out.close(); } public static void main(String[] args) throws IOException { final String zipArchivePath = "c:/temp/archive.zip"; final String tempFilePath = "c:/temp/data.txt"; final String resultZipFile = "c:/temp/resultingArchive.zip"; File zipArchive = new File(zipArchivePath); FileUtils.touch(zipArchive); File tempFile = new File(tempFilePath); FileUtils.writeStringToFile(tempFile, "hello world"); addOrUpdate(zipArchive, tempFile); //archive.zip exists and contains a compressed data.txt that can be read using winrar //now simulate writing of the zip into a in memory cache String archiveText = FileUtils.readFileToString(zipArchive); FileUtils.writeStringToFile(new File(resultZipFile), archiveText); //resultingArchive.zip exists, contains a compressed data.txt, but it can not //be read using winrar: CRC failed in data.txt. The file is corrupt } }

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  • webcam refreshing image in iframe not working IE

    - by Nix
    I'm trying to show images from this webcam http://regacam.usz.ch/cgi-bin/guestimage.html on an html page by putting an iframe in pointing to another page that has an image tag in it. But it isn't working in IE (I just see a little cross where the image should be), Firefox is ok. Here the page with the image in: <html> <head> <meta http-euqiv="refresh" content="5"> </head> <body> <img src="http://regacam.usz.ch/cgi-bin/faststream.jpg?stream=full&fps=0.01667&rand=295543" width="200" height="150"/> </body> <html> and the iframe: <div id="rightcontainer"> <iframe id="rightframe" src="zurich.html" name="content" frameborder="0"></iframe> </div> I tried a different webcam elsewhere and that works ok in both browsers. Is there something odd about the one in my example? I got the link in src by right-clicking and copying the image location - is that the right way to go about it?

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  • Multi-part gzip file random access (in Java)

    - by toluju
    This may fall in the realm of "not really feasible" or "not really worth the effort" but here goes. I'm trying to randomly access records stored inside a multi-part gzip file. Specifically, the files I'm interested in are compressed Heretrix Arc files. (In case you aren't familiar with multi-part gzip files, the gzip spec allows multiple gzip streams to be concatenated in a single gzip file. They do not share any dictionary information, it is simple binary appending.) I'm thinking it should be possible to do this by seeking to a certain offset within the file, then scan for the gzip magic header bytes (i.e. 0x1f8b, as per the RFC), and attempt to read the gzip stream from the following bytes. The problem with this approach is that those same bytes can appear inside the actual data as well, so seeking for those bytes can lead to an invalid position to start reading a gzip stream from. Is there a better way to handle random access, given that the record offsets aren't known a priori?

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  • how to tile 3D mesh with image brush in XAML

    - by MC9000
    I have a 2D square in a ViewPort3D that I want to do a tiling of an image (like a checkerboard or flooring with "tiles" effect). I've created an image brush (the image is 50x50 pixels, the surface 250x550 pixels) and a viewport (trying to follow MS's site - though their example is for 2D), but only 1 of the colors in the "tile" image shows up and no tiling is seen. I can't find a single example on the Internet and MS's site has no info (that I can find) on 3D XAML anywhere, so I'm stumped as how to actually do this. <Viewport3D> <Viewport3D.Camera> <PerspectiveCamera Position="125,790,120" LookDirection="0,-.7,-0.25" UpDirection="0,0,1" /> </Viewport3D.Camera> <ModelVisual3D> <ModelVisual3D.Content> <Model3DGroup> <AmbientLight Color="white" /> <GeometryModel3D> <GeometryModel3D.Geometry> <MeshGeometry3D Positions="0,0,0 250,0,0 250,550,0 0,550,0 " TriangleIndices="0 1 3 1 2 3 "/> </GeometryModel3D.Geometry> <GeometryModel3D.Material> <DiffuseMaterial> <DiffuseMaterial.Brush> <ImageBrush ViewportUnits="Absolute" TileMode="Tile" ImageSource="testsquare.gif" Viewport="0,0,50,50" Stretch="None" ViewboxUnits="Absolute" /> </DiffuseMaterial.Brush> </DiffuseMaterial> </GeometryModel3D.Material> </GeometryModel3D> </Model3DGroup> </ModelVisual3D.Content> </ModelVisual3D> </Viewport3D>

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  • Cursor image to the center on mouseout

    - by Milla
    Hi all! I'm a real noobie with flash and I was wondering if somebody could help me with this one. I have this actionsript 3 code, where the cursor image "ball_mc" follows the mouse's position with a slight delay: stage.addEventListener(Event.ENTER_FRAME,followBall); function followBall(event:Event):void { var dx:int = ball_mc.x - mouseX; var dy:int = ball_mc.y - mouseY; ball_mc.x -= dx / 5; ball_mc.y -= dy /5; } 1) How can I get the cursor image automatically return to the center of the stage on mouseout? As of now, it stays at the position where the mouse leaves the stage. 2) How can I reverse the movement of the mouse? So that when I, for example, move mouse to the right, the cursor image would move to the left? And when moving the mouse up, the image would go down. The stage is 800 x 250 pixels, in case that makes any difference.

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  • Efficiently storing a list of prime numbers

    - by eSKay
    This article says: Every prime number can be expressed as 30k±1, 30k±7, 30k±11, or 30k±13 for some k. That means we can use eight bits per thirty numbers to store all the primes; a million primes can be compressed to 33,334 bytes "That means we can use eight bits per thirty numbers to store all the primes" This "eight bits per thirty numbers" would be for k, correct? But each k value will not necessarily take-up just one bit. Shouldn't it be eight k values instead? "a million primes can be compressed to 33,334 bytes" I am not sure how this is true. We need to indicate two things: VALUE of k (can be arbitrarily large) STATE from one of the eight states (-13,-11,-7,-1,1,7,11,13) I am not following how 33,334 bytes was arrived at, but I can say one thing: as the prime numbers become larger and larger in value, we will need more space to store the value of k. How, then can we fix it at 33,334 bytes?

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  • Compressing xls content with apache deflate module

    - by Clinton Bosch
    I am trying to compress an excel spreadsheet being sent from my application using apache deflate module. I have added the following line to the my sites-enabled file: AddOutputFilterByType DEFLATE text/html text/plain text/xml text/css text/javascript application/excel But is seems to make the response data bigger??? Using firebug, without the module I downloaded the xls spreadsheet from the application and it downloaded 100Kb of data, the file size once on the filesystem was also 100Kb as expected. Once I enabled the deflate module as described above and repeated the process, the amount of data downloaded was 295Kb?? but the file was still only 100Kb once save on the filesystem. As an experiment I manually gzipped the saved xls file and it compressed to 20Kb. What am I doing wrong here? Using deflate (Firebug output): 200 OK xxxxxxx.co.za 293 KB 4.43s ParamsHeadersPostPutResponseCacheHTML Response Headers Date Tue, 03 Nov 2009 13:01:43 GMT Server Apache/2.2.4 (Ubuntu) mod_jk/1.2.23 PHP/5.2.3-1ubuntu6.4 mod_ssl/2.2.4 OpenSSL/0.9.8e Content-Disposition attachment; filename="Employee List.xls" Vary Accept-Encoding Content-Encoding gzip Content-Type application/excel Without deflate (Firebug output): 200 OK xxxxxxxx.co.za 100 KB 3.46s ParamsHeadersPostPutResponseCacheHTML Response Headers Date Tue, 03 Nov 2009 13:06:00 GMT Server Apache/2.2.4 (Ubuntu) mod_jk/1.2.23 PHP/5.2.3-1ubuntu6.4 mod_ssl/2.2.4 OpenSSL/0.9.8e Content-Disposition attachment; filename="Employee List.xls" Content-Length 102912 Content-Type application/excel

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  • How do I compute the approximate entropy of a bit string?

    - by dreeves
    Is there a standard way to do this? Googling -- "approximate entropy" bits -- uncovers multiple academic papers but I'd like to just find a chunk of pseudocode defining the approximate entropy for a given bit string of arbitrary length. (In case this is easier said than done and it depends on the application, my application involves 16,320 bits of encrypted data (cyphertext). But encrypted as a puzzle and not meant to be impossible to crack. I thought I'd first check the entropy but couldn't easily find a good definition of such. So it seemed like a question that ought to be on StackOverflow! Ideas for where to begin with de-cyphering 16k random-seeming bits are also welcome...) See also this related question: http://stackoverflow.com/questions/510412/what-is-the-computer-science-definition-of-entropy

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  • Compressibility Example

    - by user285726
    From my algorithms textbook: The annual county horse race is bringing in three thoroughbreds who have never competed against one another. Excited, you study their past 200 races and summarize these as prob- ability distributions over four outcomes: first (“first place”), second, third, and other. Outcome Aurora Whirlwind Phantasm 0.15 0.30 0.20 first 0.10 0.05 0.30 second 0.70 0.25 0.30 third 0.05 0.40 0.20 other Which horse is the most predictable? One quantitative approach to this question is to look at compressibility. Write down the history of each horse as a string of 200 values (first, second, third, other). The total number of bits needed to encode these track- record strings can then be computed using Huffman’s algorithm. This works out to 290 bits for Aurora, 380 for Whirlwind, and 420 for Phantasm (check it!). Aurora has the shortest encoding and is therefore in a strong sense the most predictable. How did they get 420 for Phantasm? I keep getting 400 bytes, as so: Combine first, other = 0.4, combine second, third = 0.6. End up with 2 bits encoding each position. Is there something I've misunderstood about the Huffman encoding algorithm? Textbook available here: http://www.cs.berkeley.edu/~vazirani/algorithms.html (page 156).

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  • Manual alternative to mod_deflate

    - by Bobby Jack
    Say I don't have mod_deflate compiled into apache, and I don't feel like recompiling right now. What are the downsides to a manual approach, e.g. something like: AddEncoding x-gzip .gz RewriteCond %{HTTP_ACCEPT_ENCODING} gzip RewriteRule ^/css/styles.css$ /css/styles.css.gz (Note: I'm aware that the specifics of that RewriteCond need to be tweaked slightly)

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  • Updating gzip library in jre

    - by Sarmun
    Is there a way to update gzip library that JRE uses? There is a bug in gzip library that is used by latest JRE, and it has been fixed in later version of gzip library, so I would like to make latest JRE work by updating just gzip.

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  • How do you get Lighttpd to compress CodeIgniter's "clean urls"?

    - by ocdcoder
    I was looking at PageSpeed on my test website and noticed that Lighttpd wasn't compressing my HTML (but was compressing my javascript and css files). I'm assuming this is because I'm using CodeIgniter and it's clean url system and since the requests don't have file extensions, Lighttpd doesn't have the rule to compress it. That being the case, how do I get Lighttpd to compress my HTML? Is this something I shouldn't be doing? Or something I need to specially configure Lighttpd for?

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  • Random access gzip stream

    - by jkff
    I'd like to be able to do random access into a gzipped file. I can afford to do some preprocessing on it (say, build some kind of index), provided that the result of the preprocessing is much smaller than the file itself. Any advice? My thoughts were: Hack on an existing gzip implementation and serialize its decompressor state every, say, 1 megabyte of compressed data. Then to do random access, deserialize the decompressor state and read from the megabyte boundary. This seems hard, especially since I'm working with Java and I couldn't find a pure-java gzip implementation :( Re-compress the file in chunks of 1Mb and do same as above. This has the disadvantage of doubling the required disk space. Write a simple parser of the gzip format that doesn't do any decompressing and only detects and indexes block boundaries (if there even are any blocks: I haven't yet read the gzip format description)

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  • Oracle output: cursor, file, or very long string?

    - by Klay
    First, the setup: I have a table in an Oracle10g database with spatial columns. I need to be able to pass in a spatial reference so that I can reproject the geometry into an arbitrary coordinate system. Ultimately, I need to compress the results of this projection to a zip file and make it available for download through a Silverlight project. I would really appreciate ideas as to the best way to accomplish this. In the examples below, the SRID is the Spatial reference ID integer used to convert the geometric points into a new coordinate system. In particular, I can see a couple of possibilities. There are many more, but this is an idea of how I'm thinking: a) Pass SRID to a dynamic view -- perform projection, output a cursor -- send cursor to UTL_COMPRESS -- write output to a file (somehow) -- send URL to Silverlight app b) Use SRID to call Oracle function from Silverlight app -- perform projection, output a string -- build strings into a file -- compress file using SharpZipLib library in .NET -- send bytestream back to Silverlight app I've done the first two steps of b), and the conversion of 100 points took about 7 seconds, which is unacceptably slow. I'm hoping it would be faster doing the processing totally in Oracle. If anyone can see potential problems with either way of doing this, or can suggest a better way, it would be very helpful. Thanks!

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  • Compile/use unrar C++ source for iphone app?

    - by greypoint
    Writing an app that will include the ability to decompress zip and rar files. I think I'm OK on how to handle the .zips but .rars seem a little more trouble. I noticed that rarlabs has source available but it's C++. Is there a way to compile, wrap or otherwise use this code within an iPhone app? Reference: http://www.rarlab.com/rar_add.htm Open to alternate suggestions on how to handle .rar files as well. I'm still pretty much a newbie so please explain in small words :)

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  • Very basic question about Hadoop and compressed input files

    - by Luis Sisamon
    I have started to look into Hadoop. If my understanding is right i could process a very big file and it would get split over different nodes, however if the file is compressed then the file could not be split and wold need to be processed by a single node (effectively destroying the advantage of running a mapreduce ver a cluster of parallel machines). My question is, assuming the above is correct, is it possible to split a large file manually in fixed-size chunks, or daily chunks, compress them and then pass a list of compressed input files to perform a mapreduce?

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  • is jQuery 1.4.2 compatible with Closure Compiler?

    - by Mohammad
    According to the official release statement version 1.4 has been re-written to be compressed with Closure Compiler yet when I use the online version of closure compiler I get 130 warnings. This is the code I use. // ==ClosureCompiler== // @compilation_level ADVANCED_OPTIMIZATIONS // @output_file_name default.js // @code_url http://ajax.googleapis.com/ajax/libs/jquery/1.4.2/jquery.js // ==/ClosureCompiler== And as far as I know you get the real benefit of Closure Compiler if you include the library with your code also, so it removes the unused functions. Yet my testing show that I can't get any further than compressing the library itself.. What am I doing wrong? Any kind of insight will be much appreciated.

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