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  • How to display strings in activity 3 from activity 1, 2? [migrated]

    - by user107160
    I need to get strings values from two different activities say activity1 and activity2, each activity should have maximum 4 edittext field..so totally eight fields should be displayed orderly in activity3. I have tried the code which is not displaying in the activity3. Look at code, Activity1 String namef = fname.getText().toString(); Intent first = new Intent(AssessmentActivity.this, Second.class); first.putExtra("list1", namef); startActivity(first); String namel = lname.getText().toString(); Intent second = new Intent(AssessmentActivity.this, Second.class); second.putExtra("list2", namel); startActivity(second); String phone = mob.getText().toString(); Intent third = new Intent(AssessmentActivity.this, Second.class); third.putExtra("list3", phone); startActivity(third); String mailid = email.getText().toString(); Intent fourth = new Intent(AssessmentActivity.this, Second.class); fourth.putExtra("list4", mailid); startActivity(fourth); Activity2 String cont = addr.getText().toString(); Intent fifth = new Intent(Second.this, Third.class); fifth.putExtra("list5", cont); startActivity(fifth); String db = dob.getText().toString(); Intent sixth = new Intent(Second.this, Third.class); sixth.putExtra("list6", db); startActivity(sixth); String nation = citizen.getText().toString(); Intent Seventh = new Intent(Second.this, Third.class); Seventh.putExtra("list7", nation); startActivity(Seventh); String subject = course.getText().toString(); Intent Eight = new Intent(Second.this, Third.class); Eight.putExtra("list8", subject); startActivity(Eight); *Activity3* TextView first = (TextView)findViewById(R.id.textView2); String fieldone = getIntent().getStringExtra("list1" ); first.setText(fieldone); TextView second = (TextView)findViewById(R.id.textView3); String fieldtwo = getIntent().getStringExtra("list2" ); second.setText(fieldtwo); TextView third = (TextView)findViewById(R.id.textView4); String fieldthree = getIntent().getStringExtra("list3" ); third.setText(fieldthree); TextView fourth = (TextView)findViewById(R.id.textView5); String fieldfour = getIntent().getStringExtra("list4" ); fourth.setText(fieldfour); TextView fifth = (TextView)findViewById(R.id.textView6); String fieldfive = getIntent().getStringExtra("list5" ); fifth.setText(fieldfive); TextView sixth = (TextView)findViewById(R.id.textView7); String fieldsix = getIntent().getStringExtra("list6" ); sixth.setText(fieldsix); TextView seventh = (TextView)findViewById(R.id.textView8); String fieldseven = getIntent().getStringExtra("list7" ); seventh.setText(fieldseven); TextView eight = (TextView)findViewById(R.id.textView3); String fieldeight = getIntent().getStringExtra("list8"); eight.setText(fieldeight);

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  • How to reduce iOS AVPlayer start delay

    - by Bernt Habermeier
    Note, for the below question: All assets are local on the device -- no network streaming is taking place. The videos contain audio tracks. I'm working on an iOS application that requires playing video files with minimum delay to start the video clip in question. Unfortunately we do not know what specific video clip is next until we actually need to start it up. Specifically: When one video clip is playing, we will know what the next set of (roughly) 10 video clips are, but we don't know which one exactly, until it comes time to 'immediately' play the next clip. What I've done to look at actual start delays is to call addBoundaryTimeObserverForTimes on the video player, with a time period of one millisecond to see when the video actually started to play, and I take the difference of that time stamp with the first place in the code that indicates which asset to start playing. From what I've seen thus-far, I have found that using the combination of AVAsset loading, and then creating an AVPlayerItem from that once it's ready, and then waiting for AVPlayerStatusReadyToPlay before I call play, tends to take between 1 and 3 seconds to start the clip. I've since switched to what I think is roughly equivalent: calling [AVPlayerItem playerItemWithURL:] and waiting for AVPlayerItemStatusReadyToPlay to play. Roughly same performance. One thing I'm observing is that the first AVPlayer item load is slower than the rest. Seems one idea is to pre-flight the AVPlayer with a short / empty asset before trying to play the first video might be of good general practice. [http://stackoverflow.com/questions/900461/slow-start-for-avaudioplayer-the-first-time-a-sound-is-played] I'd love to get the video start times down as much as possible, and have some ideas of things to experiment with, but would like some guidance from anyone that might be able to help. Update: idea 7, below, as-implemented yields switching times of around 500 ms. This is an improvement, but it it'd be nice to get this even faster. Idea 1: Use N AVPlayers (won't work) Using ~ 10 AVPPlayer objects and start-and-pause all ~ 10 clips, and once we know which one we really need, switch to, and un-pause the correct AVPlayer, and start all over again for the next cycle. I don't think this works, because I've read there is roughly a limit of 4 active AVPlayer's in iOS. There was someone asking about this on StackOverflow here, and found out about the 4 AVPlayer limit: fast-switching-between-videos-using-avfoundation Idea 2: Use AVQueuePlayer (won't work) I don't believe that shoving 10 AVPlayerItems into an AVQueuePlayer would pre-load them all for seamless start. AVQueuePlayer is a queue, and I think it really only makes the next video in the queue ready for immediate playback. I don't know which one out of ~10 videos we do want to play back, until it's time to start that one. ios-avplayer-video-preloading Idea 3: Load, Play, and retain AVPlayerItems in background (not 100% sure yet -- but not looking good) I'm looking at if there is any benefit to load and play the first second of each video clip in the background (suppress video and audio output), and keep a reference to each AVPlayerItem, and when we know which item needs to be played for real, swap that one in, and swap the background AVPlayer with the active one. Rinse and Repeat. The theory would be that recently played AVPlayer/AVPlayerItem's may still hold some prepared resources which would make subsequent playback faster. So far, I have not seen benefits from this, but I might not have the AVPlayerLayer setup correctly for the background. I doubt this will really improve things from what I've seen. Idea 4: Use a different file format -- maybe one that is faster to load? I'm currently using .m4v's (video-MPEG4) H.264 format. I have not played around with other formats, but it may well be that some formats are faster to decode / get ready than others. Possible still using video-MPEG4 but with a different codec, or maybe quicktime? Maybe a lossless video format where decoding / setup is faster? Idea 5: Combination of lossless video format + AVQueuePlayer If there is a video format that is fast to load, but maybe where the file size is insane, one idea might be to pre-prepare the first 10 seconds of each video clip with a version that is boated but faster to load, but back that up with an asset that is encoded in H.264. Use an AVQueuePlayer, and add the first 10 seconds in the uncompressed file format, and follow that up with one that is in H.264 which gets up to 10 seconds of prepare/preload time. So I'd get 'the best' of both worlds: fast start times, but also benefits from a more compact format. Idea 6: Use a non-standard AVPlayer / write my own / use someone else's Given my needs, maybe I can't use AVPlayer, but have to resort to AVAssetReader, and decode the first few seconds (possibly write raw file to disk), and when it comes to playback, make use of the raw format to play it back fast. Seems like a huge project to me, and if I go about it in a naive way, it's unclear / unlikely to even work better. Each decoded and uncompressed video frame is 2.25 MB. Naively speaking -- if we go with ~ 30 fps for the video, I'd end up with ~60 MB/s read-from-disk requirement, which is probably impossible / pushing it. Obviously we'd have to do some level of image compression (perhaps native openGL/es compression formats via PVRTC)... but that's kind crazy. Maybe there is a library out there that I can use? Idea 7: Combine everything into a single movie asset, and seekToTime One idea that might be easier than some of the above, is to combine everything into a single movie, and use seekToTime. The thing is that we'd be jumping all around the place. Essentially random access into the movie. I think this may actually work out okay: avplayer-movie-playing-lag-in-ios5 Which approach do you think would be best? So far, I've not made that much progress in terms of reducing the lag.

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  • How can we copy the column data of one datatable to another,even if there is different column names

    - by Harikrishna
    I have two datatables. First is DataTable NameAdressPhones = new DataTable(); with Three columns Name,Adress and PhoneNo.But I want only two columns Name and Adress data so I am copy those columns (with data) to the new datatable DataTable NameAdress = new DataTable(); For that I do foreach (DataRow sourcerow in NameAdressPhones.Rows) { DataRow destRow = NameAdress.NewRow(); foreach (string colname in columns) { destRow[colname] = sourcerow[colname]; } NameAdress.Rows.Add(destRow); } Now I clear every time the NameAdressPhones(first) datatable when there are new records in the table.And every time there will be same no of columns but column name will be different like Nm instead of Name,Add instead of Address.Now problem is second datatable have already column names Name and Address and now I want to copy the columns data of Nm and Add to the second datatabel but the column names are different to the second datatable.So even If there is different column names I want to copy Nm column data of first datatable to the column Name of second datatable and column Add data of first datatable to column Address of second datatable.

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  • Problem with adding Appendix in Latex

    - by Andrew
    Hi all, I tried the first time to add an appendix to my thesis, here are the commands that I used. \appendix \chapter{Appendices} \input{appendix} The output looks than as follows: Appendix A Appendices A.1 My first appendix ..... It does not look to bad, but what is irritating is the Appendices entry after Appendix A. Is there any possibilty I could get rid of it? If I try the following commands: \appendix \input{appendix} The output looks than as follows: .1 My first appendix ... Also not how it is intended. Ideally, it would look like this here: Appendix A A.1 My first appendix ..... Any idea how to do that? Andrew

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  • Issue with dynamic array Queue data structure with void pointer

    - by Nazgulled
    Hi, Maybe there's no way to solve this the way I'd like it but I don't know everything so I better ask... I've implemented a simple Queue with a dynamic array so the user can initialize with whatever number of items it wants. I'm also trying to use a void pointer as to allow any data type, but that's the problem. Here's my code: typedef void * QueueValue; typedef struct sQueueItem { QueueValue value; } QueueItem; typedef struct sQueue { QueueItem *items; int first; int last; int size; int count; } Queue; void queueInitialize(Queue **queue, size_t size) { *queue = xmalloc(sizeof(Queue)); QueueItem *items = xmalloc(sizeof(QueueItem) * size); (*queue)->items = items; (*queue)->first = 0; (*queue)->last = 0; (*queue)->size = size; (*queue)->count = 0; } Bool queuePush(Queue * const queue, QueueValue value, size_t val_sz) { if(isNull(queue) || isFull(queue)) return FALSE; queue->items[queue->last].value = xmalloc(val_sz); memcpy(queue->items[queue->last].value, value, val_sz); queue->last = (queue->last+1) % queue->size; queue->count += 1; return TRUE; } Bool queuePop(Queue * const queue, QueueValue *value) { if(isEmpty(queue)) return FALSE; *value = queue->items[queue->first].value; free(queue->items[queue->first].value); queue->first = (queue->first+1) % queue->size; queue->count -= 1; return TRUE; } The problem lies on the queuePop function. When I call it, I lose the value because I free it right away. I can't seem to solve this dilemma. I want my library to be generic and modular. The user should not care about allocating and freeing memory, that's the library's job. How can the user still get the value from queuePop and let the library handle all memory allocs/frees?

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  • RadComboBox Just Freezes

    - by ProfK
    I have two examples now, my first two, where a place a RadComboBox on a web form, and populate it, but it won't drop down. I first picked this up on a big web application project, and then on a simple little web site project, for investigating this. In my sample project, it is the only control on the page besides the ScriptManager, and there are rows in the data source, and it does display the first row, but it just doesn't drop down. Any ideas on this? BTW, this is theh first time I've restored this project onto a new XP machine, where I previously was working on a Vista machine that died.

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  • Decompiling a *.DLL to assembly for .net in delphi 4

    - by Lex Dean
    I love my Delphi 4 but at the same time I see the need to talk to windows .net This is a recompiled dll that I found on sourceforge.net/projects/delphinet/ (DelphiNet03.zip) by some nice people that fund the dll from some were. The real answer is to make this dll so that fits into Delphi as true Delphi code, and not a dll clip on. So we can make objects that use dot net in Delphi. Because I’m not an assembly freak, I’m freaking out a little with a wee sweek for help! 1/ How do I link the asm code with the data info at the bottom of this code. Can some one show me which calls to look for to make this link to data. 2/ I need to find the beginning of all the procedures and functions, but I cannot find a ‘RET’ statement. And what line is the beginning statement in this code. 3/ How do I identify were the jump statements go to, put them into Delphi format In this code it looks I can do:- jle 402890h \1000:00402854 7e3a add [eax], al \1000:00402856 0000 …………………………………………….. or ch, [edi+3eh] \1000:0040288d 0a6f3e xrefs first: 1000:00402854 number : 1 \; add [eax], al \1000:00402890 0000 //******************************* jle @@21 \\1000:00402854 7e3a add [eax], al \\1000:00402856 0000 …………………………………………….. or ch, [edi+3eh] \1000:0040288d 0a6f3e xrefs first: 1000:00402854 number : 1 \; @@21 add [eax], al \1000:00402890 0000 Is that a correct conversion. I think a xrefs first: 1000:004021d1 number : 1 is the best to follow 4/ I need a good reference on 8086 up assembly code that I can print out and get to learn properly. I found this asm decomplier of http://www.cronos.cc/ that is so similar to Delphi that it only needs a little more convertion to get it into Delphi asm I think. It’s only taken me 3 hours to get the file into TMemo and to write a few lines to chop the line over in a stream and reload the memo. Help please Email: [email protected] xrefs first: 1000:004041ae number : 1 \\; dd 4190h \\1000:00402000 90410000 dd 00h \\1000:00402004 00000000 dec eax \\1000:00402008 48 add [eax], al \\1000:00402009 0000 add [edx], al \\1000:0040200b 0002 add [eax], al \\1000:0040200d 0000 add [eax-2bffffd2h], al \\1000:0040200f 00802e0000d4 adc al, [eax] \\1000:00402015 1200 add [ecx], al \\1000:00402017 0001 add [eax], al \\1000:00402019 0000 add [eax], al \\1000:0040201b 0000 add [eax], al \\1000:0040201d 0000 add [eax], al \\1000:0040201f 0000 add [eax], al \\1000:00402021 0000 add [eax], al \\1000:00402023 0000 add [eax], al \\1000:00402025 0000 add [eax], al \\1000:00402027 0000 add [eax], al \\1000:00402029 0000 add [eax], al \\1000:0040202b 0000 add [eax], al \\1000:0040202d 0000 add [eax], al \\1000:0040202f 0000 add [eax], al \\1000:00402031 0000 add [eax], al \\1000:00402033 0000 add [eax], al \\1000:00402035 0000 add [eax], al \\1000:00402037 0000 add [eax], al \\1000:00402039 0000 add [eax], al \\1000:0040203b 0000 add [eax], al \\1000:0040203d 0000 add [eax], al \\1000:0040203f 0000 add [eax], al \\1000:00402041 0000 add [eax], al \\1000:00402043 0000 add [eax], al \\1000:00402045 0000 add [eax], al \\1000:00402047 0000 add [eax], al \\1000:00402049 0000 add [eax], al \\1000:0040204b 0000 add [eax], al \\1000:0040204d 0000 add [ebx], dl \\1000:0040204f 0013 xor [eax+eax], al \\1000:00402051 300400 or al, [ecx] \\1000:00402054 0a01 add [eax], al \\1000:00402056 0000 add [eax], eax \\1000:00402058 0100 add [ecx], dl \\1000:0040205a 0011 push cs \\1000:0040205c 0e add al, 50h \\1000:0040205d 0450 mov gs, [ecx+05h] \\1000:0040205f 8e6905 push eax \\1000:00402062 50 mov gs, [ecx+2eh] \\1000:00402063 8e692e add eax, f938h \\1000:00402066 0538f90000 add [ebx], al \\1000:0040206b 0003 jc 402070h \\1000:0040206d 7201 add [eax], al \\1000:0040206f 0000 jo 40209bh \\1000:00402071 7028 add al, [eax] \\1000:00402073 0200 add [edx], cl \\1000:00402075 000a sub eax, 36f0408h \\1000:00402077 2d08046f03 add [eax], al \\1000:0040207c 0000 or ch, [ebx] \\1000:0040207e 0a2b push es \\1000:00402080 06 add al, 6fh \\1000:00402081 046f add al, 00h \\1000:00402083 0400 add [edx], cl \\1000:00402085 000a adc eax, [edi] \\1000:00402087 1307 push ss \\1000:00402089 16 adc ecx, [eax] \\1000:0040208a 1308 cmp cl, cl \\1000:0040208c 38c9 add [eax], al \\1000:0040208e 0000 add [ecx], dl \\1000:00402090 0011 pop es \\1000:00402092 07 adc [eax], ecx \\1000:00402093 1108 callf 056f:060a9a08h \\1000:00402095 9a0a066f05 add [eax], al \\1000:0040209a 0000 or cl, [ebx] \\1000:0040209c 0a0b push es \\1000:0040209e 06 outsd \\1000:0040209f 6f push es \\1000:004020a0 06 add [eax], al \\1000:004020a1 0000 or al, [ebx] \\1000:004020a3 0a03 sub [edx], al \\1000:004020a5 2802 add [eax], al \\1000:004020a7 0000 or bh, [ecx] \\1000:004020a9 0a39 movsd \\1000:004020ab a5 add [eax], al \\1000:004020ac 0000 add [edi], al \\1000:004020ae 0007 mov gs, [ecx+0eh] \\1000:004020b0 8e690e add al, 50h \\1000:004020b3 0450 mov gs, [ecx+40h] \\1000:004020b5 8e6940 cwde \\1000:004020b8 98 add [eax], al \\1000:004020b9 0000 add [edi], dl \\1000:004020bb 0017 or al, 16h \\1000:004020bd 0c16 or eax, 9072b2bh \\1000:004020bf 0d2b2b0709 callf 0000:076f9a09h \\1000:004020c4 9a6f070000 or ch, [edi+08h] \\1000:004020c9 0a6f08 add [eax], al \\1000:004020cc 0000 or ch, [eax+ebx] \\1000:004020ce 0a2c18 push cs \\1000:004020d1 0e add al, 50h \\1000:004020d2 0450 or [edx+d72h], ebx \\1000:004020d4 099a720d0000 jo 402104h \\1000:004020da 7028 or [eax], eax \\1000:004020dc 0900 add [edx], cl \\1000:004020de 000a add dl, cs:[esi] \\1000:004020e0 2e0216 or al, 08h \\1000:004020e3 0c08 sub eax, 90c2b02h \\1000:004020e5 2d022b0c09 pop ss \\1000:004020ea 17 pop eax \\1000:004020eb 58 or eax, 50040e09h \\1000:004020ec 0d090e0450 mov gs, [ecx+32h] \\1000:004020f1 8e6932 int 08h \\1000:004020f4 cd08 sub al, 5ch \\1000:004020f6 2c5c push ss \\1000:004020f8 16 adc eax, [ebx+ebp] \\1000:004020f9 13042b dec esi \\1000:004020fc 4e push cs \\1000:004020fd 0e add al, 50h \\1000:004020fe 0450 adc [edx+ebx*4], eax \\1000:00402100 11049a jc 402112h \\1000:00402103 720d add [eax], al \\1000:00402105 0000 jo 402131h \\1000:00402107 7028 or [eax], eax \\1000:00402109 0900 add [edx], cl \\1000:0040210b 000a xor esi, [esi] \\1000:0040210d 3336 pop es \\1000:0040210f 07 adc [edx+ebx*4], eax \\1000:00402110 11049a outsd \\1000:00402113 6f pop es \\1000:00402114 07 add [eax], al \\1000:00402115 0000 or ch, [edi+0ah] \\1000:00402117 0a6f0a add [eax], al \\1000:0040211a 0000 or dl, [ebx] \\1000:0040211c 0a13 push es \\1000:0040211e 06 add eax, 9a041150h \\1000:0040211f 055011049a sub [ebx], cl \\1000:00402124 280b add [eax], al \\1000:00402126 0000 or dl, [edx] \\1000:00402128 0a12 push es \\1000:0040212a 06 adc al, [c28h] \\1000:0040212b 1205280c0000 xrefs first: 1000:00402107 number : 1 \\; or ch, [edx+eax] \\1000:00402131 0a2c02 sub ebx, [esi] \\1000:00402134 2b1e push cs \\1000:00402136 0e add al, 50h \\1000:00402137 0450 adc [edi+eax], eax \\1000:00402139 110407 adc [edx+ebx*4], eax \\1000:0040213c 11049a outsd \\1000:0040213f 6f pop es \\1000:00402140 07 add [eax], al \\1000:00402141 0000 or ah, [edx+58170411h] \\1000:00402143 0aa211041758 adc eax, [ecx+edx] \\1000:00402149 130411 add al, 0eh \\1000:0040214c 040e add al, 50h \\1000:0040214e 0450 mov gs, [ecx+32h] \\1000:00402150 8e6932 test eax, 58170811h \\1000:00402153 a911081758 adc ecx, [eax] \\1000:00402158 1308 adc [eax], ecx \\1000:0040215a 1108 adc [edi], eax \\1000:0040215c 1107 mov gs, [ecx+3fh] \\1000:0040215e 8e693f sub al, ffh \\1000:00402161 2cff db ff \\1000:00402163 ff jmp [edx] \\1000:00402164 ff2a add [eax], al \\1000:00402166 0000 adc esi, [eax] \\1000:00402168 1330 add eax, 8100h \\1000:0040216a 0500810000 add [edx], al \\1000:0040216f 0002 add [eax], al \\1000:00402171 0000 adc [edx+esi*2], eax \\1000:00402173 110472 xor eax, [eax] \\1000:00402176 3300 add [eax+28h], dh \\1000:00402178 007028 add al, [eax] \\1000:0040217b 0200 add [edx], cl \\1000:0040217d 000a sub al, 09h \\1000:0040217f 2c09 add ebp, [eax] \\1000:00402181 0328 or eax, a0a0000h \\1000:00402183 0d00000a0a sub eax, [edi] \\1000:00402188 2b07 add al, 28h \\1000:0040218a 0428 push cs \\1000:0040218c 0e add [eax], al \\1000:0040218d 0000 or cl, [edx] \\1000:0040218f 0a0a push es \\1000:00402191 06 add eax, f6f1717h \\1000:00402192 0517176f0f add [eax], al \\1000:00402197 0000 or cl, [ebx] \\1000:00402199 0a0b push ss \\1000:0040219b 16 lea eax, [edx] \\1000:0040219c 8d02 add [eax], al \\1000:0040219e 0000 add [esi+ecx], ecx \\1000:004021a0 010c0e add al, 2ch \\1000:004021a3 042c push cs \\1000:004021a5 260e add al, 8eh \\1000:004021a7 048e c160d imul edi, [eax+28dh], d160c01h \\1000:004021a9 69b88d020000010c sub edx, [eax] \\1000:004021b3 2b10 or [ecx], cl \\1000:004021b5 0809 push cs \\1000:004021b7 0e add al, 09h \\1000:004021b8 0409 callf 0000:106f9a09h \\1000:004021ba 9a6f100000 or ah, [edx+d581709h] \\1000:004021bf 0aa20917580d or [esi], ecx \\1000:004021c5 090e add al, 8eh \\1000:004021c7 048e imul esi, [edx], 17202e9h \\1000:004021c9 6932e9027201 add [eax], al \\1000:004021cf 0000 jo 4021dah \\1000:004021d1 7007 db 0f \\1000:004021d3 0f add al, 12h \\1000:004021d4 0412 add ch, [eax] \\1000:004021d6 0228 add [eax], eax \\1000:004021d8 0100 xrefs first: 1000:004021d1 number : 1 \\; add [esi], al \\1000:004021da 0006 pop es \\1000:004021dc 07 or [edi+11h], ch \\1000:004021dd 086f11 add [eax], al \\1000:004021e0 0000 or dl, [ebx] \\1000:004021e2 0a13 add al, 11h \\1000:004021e4 0411 add al, 0eh \\1000:004021e6 040e add al, 6fh \\1000:004021e8 046f adc al, [eax] \\1000:004021ea 1200 add [edx], cl \\1000:004021ec 000a adc eax, [511002bh] \\1000:004021ee 13052b001105 sub al, [eax] \\1000:004021f4 2a00 add [eax], al \\1000:004021f6 0000 adc esi, [eax] \\1000:004021f8 1330 add eax, 4e00h \\1000:004021fa 05004e0000 add [ebx], al \\1000:004021ff 0003 add [eax], al \\1000:00402201 0000 adc [ebx], eax \\1000:00402203 1103 outsd \\1000:00402205 6f adc [eax], al \\1000:00402206 1000 add [edx], cl \\1000:00402208 000a or al, [8db8698eh] \\1000:0040220a 0a058e69b88d add al, [eax] \\1000:00402210 0200 add [ecx], al \\1000:00402212 0001 or edx, [esi] \\1000:00402214 0b16 or al, 2bh \\1000:00402216 0c2b db 0f \\1000:00402218 0f pop es \\1000:00402219 07 or [106f9a08h], al \\1000:0040221a 0805089a6f10 add [eax], al \\1000:00402220 0000 or ah, [edx+c581708h] \\1000:00402222 0aa20817580c or [eb32698eh], al \\1000:00402228 08058e6932eb add al, [esi+eax] \\1000:0040222e 020406 lsl edx, [edx] \\1000:00402231 0f0312 add [eax], ebp \\1000:00402234 0128 add [eax], eax \\1000:00402236 0100 add [esi], al \\1000:00402238 0006 push es \\1000:0040223a 06 add al, 07h \\1000:0040223b 0407 outsd \\1000:0040223d 6f adc eax, [eax] \\1000:0040223e 1300 add [edx], cl \\1000:00402240 000a or eax, 6f050309h \\1000:00402242 0d0903056f adc al, 00h \\1000:00402247 1400 add [edx], cl \\1000:00402249 000a adc eax, [ebx+ebp] \\1000:0040224b 13042b add [ecx], dl \\1000:0040224e 0011 add al, 2ah \\1000:00402250 042a add [eax], al \\1000:00402252 0000 adc esi, [eax] \\1000:00402254 1330 add eax, 7600h \\1000:00402256 0500760000 add [eax+eax], al \\1000:0040225b 000400 add [ecx], dl \\1000:0040225e 0011 add al, 72h \\1000:00402260 0472 xor eax, [eax] \\1000:00402262 3300 add [eax+28h], dh \\1000:00402264 007028 add al, [eax] \\1000:00402267 0200 add [edx], cl \\1000:00402269 000a sub al, 09h \\1000:0040226b 2c09 add ebp, [eax] \\1000:0040226d 0328 or eax, a0a0000h \\1000:0040226f 0d00000a0a sub eax, [edi] \\1000:00402274 2b07 add al, 28h \\1000:00402276 0428 push cs \\1000:00402278 0e add [eax], al \\1000:00402279 0000 or cl, [edx] \\1000:0040227b 0a0a push es \\1000:0040227d 06 add eax, f6f1717h \\1000:0040227e 0517176f0f add [eax], al \\1000:00402283 0000 or cl, [ebx] \\1000:00402285 0a0b push cs \\1000:00402287 0e add eax, 8db8698eh \\1000:00402288 058e69b88d add al, [eax] \\1000:0040228d 0200 add [ecx], al \\1000:0040228f 0001 or al, 16h \\1000:00402291 0c16 or eax, 908102bh \\1000:00402293 0d2b100809 push cs \\1000:00402298 0e add eax, 106f9a09h \\1000:00402299 05099a6f10 add [eax], al \\1000:0040229e 0000 or ah, [edx+d581709h] \\1000:004022a0 0aa20917580d or [esi], ecx \\1000:004022a6 090e add eax, e932698eh \\1000:004022a8 058e6932e9 add cl, [esi] \\1000:004022ad 020e add al, 07h \\1000:004022af 0407 db 0f \\1000:004022b1 0f add eax, 1280212h \\1000:004022b2 0512022801 add [eax], al \\1000:004022b7 0000 push es \\1000:004022b9 06 pop es \\1000:004022ba 07 push cs \\1000:004022bb 0e add al, 08h \\1000:004022bc 0408 outsd \\1000:004022be 6f adc eax, [eax] \\1000:004022bf 1300 add [edx], cl \\1000:004022c1 000a adc eax, [ecx+edx] \\1000:004022c3 130411 add al, 14h \\1000:004022c6 0414 push cs \\1000:004022c8 0e add eax, 146fh \\1000:004022c9 056f140000 or dl, [ebx] \\1000:004022ce 0a13 add eax, 511002bh \\1000:004022d0 052b001105 sub al, [eax] \\1000:004022d5 2a00 add [ebx], dl \\1000:004022d7 0013 xor [eax+eax], al \\1000:004022d9 300400 jbe 4022deh \\1000:004022dc 7600 xrefs first: 1000:004022dc number : 1 \\; add fs:[esi+45h], cl \\1000:004034fc 64004e45 push esp \\1000:00403500 54 dec ecx \\1000:00403501 49 xrefs first: 1000:004034b2 number : 1 \\; outsb \\1000:00403502 6e jbe 403574h \\1000:00403503 766f imul esp, [ebp+43h], 6ch \\1000:00403505 6b65436c popad \\1000:00403509 61 jnc 40357fh \\1000:0040350a 7373 dec ebp \\1000:0040350c 4d jz 403578h \\1000:0040350d 657468 outsd \\1000:00403510 6f add fs:[esi+45h], cl \\1000:00403511 64004e45 push esp \\1000:00403515 54 push ebx \\1000:00403516 53 jz 40355fh \\1000:00403517 657445 outsb \\1000:0040351a 6e jnz 40358ah \\1000:0040351b 756d push esi \\1000:0040351d 56 xrefs first: 1000:004034b7 number : 1 \\; popad \\1000:0040351e 61 insb \\1000:0040351f 6c jnz 403587h \\1000:00403520 7565 add [esi+45h], cl \\1000:00403522 004e45 push esp \\1000:00403525 54 inc edi \\1000:00403526 47 db 65 ;'e' \\1000:00403527 65 xrefs first: 1000:004034be number : 1 \\; db 74 ;'t' \\1000:00403528 74 db 50 ;'p' \\1000:00403529 50 db 72 ;'r' \\1000:0040352a 72 db 6f ;'o' \\1000:0040352b 6f db 70 ;'p' \\1000:0040352c 70 db 65 ;'e' \\1000:0040352d 65 db 72 ;'r' \\1000:0040352e 72 db 74 ;'t' \\1000:0040352f 74 db 79 ;'y' \\1000:00403530 79 db 00 \\1000:00403531 00 db 4e ;'n' \\1000:00403532 4e db 45 ;'e' \\1000:00403533 45 db 54 ;'t' \\1000:00403534 54 db 47 ;'g' \\1000:00403535 47 db 65 ;'e' \\1000:00403536 65 db 74 ;'t' \\1000:00403537 74 db 46 ;'f' \\1000:00403538 46 db 69 ;'i' \\1000:00403539 69 db 65 ;'e' \\1000:0040353a 65 db 6c ;'l' \\1000:0040353b 6c db 64 ;'d' \\1000:0040353c 64 db 00 \\1000:0040353d 00 could not fit the rest in because of Stack overflow limitions

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  • "wait_fences: failed to receive reply: 10004003"?

    - by Michael
    I get this cryptic error the first time (and only the first time) my view is loaded due to the following line of code: - (void)viewWillAppear:(BOOL)animated { [textField becomeFirstResponder]; } There is a noticeable (~3 – 4 second, even on the simulator) delay due to this that makes my app feel unresponsive. Does anyone know how to fix this? I can't find any documentation on it on Apple's site, or any solutions here or on Google. Strangely, the opposite situation happens if I put the line in -viewDidAppear: instead of -viewWillAppear:; that is, instead of printing the error only the first time the keyboard is shown and never again, the error is not printed the first time but every time after. This is causing a major headache for me.

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  • Getting ActiveRecord (Rails) to_xml to use xsi:nil and xsi:type instead of nil and type

    - by nbeyer
    The default behavior of XML serialization (to_xml) for ActiveRecord objects will emit 'type' and 'nil' attributes that are similar to XML Schema Instance attributes, but aren't set in a XML Namespace. For example, a model might produce an output like this: <user> <username nil="true" /> <first-name type="string">Name</first-name> </user> Is there anyway to get to_xml to utilize the XML Schema Instance namespace and prefix the attributes and the values? Using the above example, I'd like to produce the following: <user xmlns:xsi="http://www.w3.org/1999/XMLSchema-instance" xmlns:xs="http://www.w3.org/1999/XMLSchema"> <username xsi:nil="true" /> <first-name xsi:type="xs:string">Name</first-name> </user>

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  • Application with two UITabBarControls

    - by kovpas
    Hello, I want to create an app, whith the following structure: UITabBarController ..UINavigationController ....UITabBarController So, in other words, I want to load first UITabbarController as my main ViewController, that appears on application start, in its' first tab there's a UINavigationController with a table, which shows another UITabBarController by pressing on a table cell. I started Tab Based application, set first tab to UINavigationController, and its ViewController to my TableViewController. I also created second UITabBarController in Interface Builder. Created a separate class for this controller. Everything works fine at start - my first UITabBarController is shown perfectly, but when I'm trying to push my second UITabBarController, using my UINavigationController, it looks like nothing is loaded from a .xib file - there are just an empty TabBar and NavigationBar pushed. Seems, that something is wrong with an architecture, but I can't figure out the problem. Thanks in advance and I'm sorry for my poor English. Please let me know if something is not clear, I'll try to rephrase it :).

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  • JSF: How to get the selected item from selectOneMenu if its rendering is dynamic?

    - by Dzmitry Zhaleznichenka
    At my view I have two menus that I want to make dependent, namely, if first menu holds values "render second menu" and "don't render second menu", I want second menu to be rendered only if user selects "render second menu" option in the first menu. After second menu renders at the same page as the first one, user has to select current item from it, fill another fields and submit the form to store values in database. Both the lists of options are static, they are obtained from the database once and stay the same. My problem is I always get null as a value of the selected item from second menu. How to get a proper value? The sample code of view that holds problematic elements is: <h:selectOneMenu id="renderSecond" value="#{Bean.renderSecondValue}" valueChangeListener="#{Bean.updateDependentMenus}" immediate="true" onchange="this.form.submit();" > <f:selectItems value="#{Bean.typesOfRendering}" /> </h:selectOneMenu><br /> <h:selectOneMenu id="iWillReturnYouZeroAnyway" value="#{Bean.currentItem}" rendered="#{Bean.rendered}" > <f:selectItems value="#{Bean.items}" /> </h:selectOneMenu><br /> <h:commandButton action="#{Bean.store}" value="#Store" /> However, if I remove "rendered" attribute from the second menu, everything works properly, except for displaying the menu for all the time that I try to prevent, so I suggest the problem is in behavior of dynamic rendering. The initial value of isRendered is false because the default item in first menu is "don't render second menu". When I change value in first menu and update isRendered with valueChangeListener, the second menu displays but it doesn't initialize currentItem while submitting. Some code from my backing bean is below: public void updateDependentMenus(ValueChangeEvent value) { String newValue = (String) value.getNewValue(); if ("render second menu" == newValue){ isRendered = true; } else { isRendered = false; } } public String store(){ System.out.println(currentItem); return "stored"; }

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  • Make list from two database items

    - by unnamet
    I want to make a list from some data that I have in my database. The first two sets of data in my database are first name and last name. I want my list to show both first and last name instead of now where it only shows the first name. How do I do that? My code looks like this: private void fillData() { Cursor contactCursor = mDbHelper.fetchAllReminders(); startManagingCursor(contactCursor); String[] from = new String[]{DbAdapter.KEY_FIRST}; int[] to = new int[]{R.id.contactlist}; SimpleCursorAdapter contacts = new SimpleCursorAdapter(this, R.layout.list, contactCursor, from, to); setListAdapter(contacts); }

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  • How to count each digit in a range of integers?

    - by Carlos Gutiérrez
    Imagine you sell those metallic digits used to number houses, locker doors, hotel rooms, etc. You need to find how many of each digit to ship when your customer needs to number doors/houses: 1 to 100 51 to 300 1 to 2,000 with zeros to the left The obvious solution is to do a loop from the first to the last number, convert the counter to a string with or without zeros to the left, extract each digit and use it as an index to increment an array of 10 integers. I wonder if there is a better way to solve this, without having to loop through the entire integers range. Solutions in any language or pseudocode are welcome. Edit: Answers review John at CashCommons and Wayne Conrad comment that my current approach is good and fast enough. Let me use a silly analogy: If you were given the task of counting the squares in a chess board in less than 1 minute, you could finish the task by counting the squares one by one, but a better solution is to count the sides and do a multiplication, because you later may be asked to count the tiles in a building. Alex Reisner points to a very interesting mathematical law that, unfortunately, doesn’t seem to be relevant to this problem. Andres suggests the same algorithm I’m using, but extracting digits with %10 operations instead of substrings. John at CashCommons and phord propose pre-calculating the digits required and storing them in a lookup table or, for raw speed, an array. This could be a good solution if we had an absolute, unmovable, set in stone, maximum integer value. I’ve never seen one of those. High-Performance Mark and strainer computed the needed digits for various ranges. The result for one millon seems to indicate there is a proportion, but the results for other number show different proportions. strainer found some formulas that may be used to count digit for number which are a power of ten. Robert Harvey had a very interesting experience posting the question at MathOverflow. One of the math guys wrote a solution using mathematical notation. Aaronaught developed and tested a solution using mathematics. After posting it he reviewed the formulas originated from Math Overflow and found a flaw in it (point to Stackoverflow :). noahlavine developed an algorithm and presented it in pseudocode. A new solution After reading all the answers, and doing some experiments, I found that for a range of integer from 1 to 10n-1: For digits 1 to 9, n*10(n-1) pieces are needed For digit 0, if not using leading zeros, n*10n-1 - ((10n-1) / 9) are needed For digit 0, if using leading zeros, n*10n-1 - n are needed The first formula was found by strainer (and probably by others), and I found the other two by trial and error (but they may be included in other answers). For example, if n = 6, range is 1 to 999,999: For digits 1 to 9 we need 6*105 = 600,000 of each one For digit 0, without leading zeros, we need 6*105 – (106-1)/9 = 600,000 - 111,111 = 488,889 For digit 0, with leading zeros, we need 6*105 – 6 = 599,994 These numbers can be checked using High-Performance Mark results. Using these formulas, I improved the original algorithm. It still loops from the first to the last number in the range of integers, but, if it finds a number which is a power of ten, it uses the formulas to add to the digits count the quantity for a full range of 1 to 9 or 1 to 99 or 1 to 999 etc. Here's the algorithm in pseudocode: integer First,Last //First and last number in the range integer Number //Current number in the loop integer Power //Power is the n in 10^n in the formulas integer Nines //Nines is the resut of 10^n - 1, 10^5 - 1 = 99999 integer Prefix //First digits in a number. For 14,200, prefix is 142 array 0..9 Digits //Will hold the count for all the digits FOR Number = First TO Last CALL TallyDigitsForOneNumber WITH Number,1 //Tally the count of each digit //in the number, increment by 1 //Start of optimization. Comments are for Number = 1,000 and Last = 8,000. Power = Zeros at the end of number //For 1,000, Power = 3 IF Power 0 //The number ends in 0 00 000 etc Nines = 10^Power-1 //Nines = 10^3 - 1 = 1000 - 1 = 999 IF Number+Nines <= Last //If 1,000+999 < 8,000, add a full set Digits[0-9] += Power*10^(Power-1) //Add 3*10^(3-1) = 300 to digits 0 to 9 Digits[0] -= -Power //Adjust digit 0 (leading zeros formula) Prefix = First digits of Number //For 1000, prefix is 1 CALL TallyDigitsForOneNumber WITH Prefix,Nines //Tally the count of each //digit in prefix, //increment by 999 Number += Nines //Increment the loop counter 999 cycles ENDIF ENDIF //End of optimization ENDFOR SUBROUTINE TallyDigitsForOneNumber PARAMS Number,Count REPEAT Digits [ Number % 10 ] += Count Number = Number / 10 UNTIL Number = 0 For example, for range 786 to 3,021, the counter will be incremented: By 1 from 786 to 790 (5 cycles) By 9 from 790 to 799 (1 cycle) By 1 from 799 to 800 By 99 from 800 to 899 By 1 from 899 to 900 By 99 from 900 to 999 By 1 from 999 to 1000 By 999 from 1000 to 1999 By 1 from 1999 to 2000 By 999 from 2000 to 2999 By 1 from 2999 to 3000 By 1 from 3000 to 3010 (10 cycles) By 9 from 3010 to 3019 (1 cycle) By 1 from 3019 to 3021 (2 cycles) Total: 28 cycles Without optimization: 2,235 cycles Note that this algorithm solves the problem without leading zeros. To use it with leading zeros, I used a hack: If range 700 to 1,000 with leading zeros is needed, use the algorithm for 10,700 to 11,000 and then substract 1,000 - 700 = 300 from the count of digit 1. Benchmark and Source code I tested the original approach, the same approach using %10 and the new solution for some large ranges, with these results: Original 104.78 seconds With %10 83.66 With Powers of Ten 0.07 A screenshot of the benchmark application: If you would like to see the full source code or run the benchmark, use these links: Complete Source code (in Clarion): http://sca.mx/ftp/countdigits.txt Compilable project and win32 exe: http://sca.mx/ftp/countdigits.zip Accepted answer noahlavine solution may be correct, but l just couldn’t follow the pseudo code, I think there are some details missing or not completely explained. Aaronaught solution seems to be correct, but the code is just too complex for my taste. I accepted strainer’s answer, because his line of thought guided me to develop this new solution.

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  • FBConnect for iPhone: sessionDidNotLogin, sessionDidLogout, session didLogin not called the second t

    - by Irene
    My problem is very similar to this question, however I am posting a new one, as the answer to the aforementioned does not seem to solve my problem. I have a multiview application - the first view is where the user logs in to Facebook, and the second where he picks an image and uploads it there. The first time the app runs, everything works fine, however if I return to the login view and press logout, then any calls to sessionDidNotLogin, sessionDidLogout or session didLogin don't seem to work. I found out that the first time, if I NSLog(@"%@",session.delegates); I have 2; my LoginViewController and the FBLoginButton. However, apart from that first time, the same log prints only the LoginViewController and not the FBLoginButton. I guess this is connected somehow, but I don't know how to solve it. Do I have to manually add the FBLoginButton to the session delegates, or I'm doing something else wrong here? Thank you for any help/suggestion.

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  • VBA-Sorting the data in a listbox, sort works but data in listbox not changed

    - by Mike Clemens
    A listbox is passed, the data placed in an array, the array is sort and then the data is placed back in the listbox. The part that does work is putting the data back in the listbox. Its like the listbox is being passed by value instead of by ref. Here's the sub that does the sort and the line of code that calls the sort sub. Private Sub SortListBox(ByRef LB As MSForms.ListBox) Dim First As Integer Dim Last As Integer Dim NumItems As Integer Dim i As Integer Dim j As Integer Dim Temp As String Dim TempArray() As Variant ReDim TempArray(LB.ListCount) First = LBound(TempArray) ' this works correctly Last = UBound(TempArray) - 1 ' this works correctly For i = First To Last TempArray(i) = LB.List(i) ' this works correctly Next i For i = First To Last For j = i + 1 To Last If TempArray(i) > TempArray(j) Then Temp = TempArray(j) TempArray(j) = TempArray(i) TempArray(i) = Temp End If Next j Next i ! data is now sorted LB.Clear ! this doesn't clear the items in the listbox For i = First To Last LB.AddItem TempArray(i) ! this doesn't work either Next i End Sub Private Sub InitializeForm() ' There's code here to put data in the list box Call SortListBox(FieldSelect.CompleteList) End Sub Thanks for your help.

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  • Polynomial division overloading operator (solved)

    - by Vlad
    Ok. here's the operations i successfully code so far thank's to your help: Adittion: polinom operator+(const polinom& P) const { polinom Result; constIter i = poly.begin(), j = P.poly.begin(); while (i != poly.end() && j != P.poly.end()) { //logic while both iterators are valid if (i->pow > j->pow) { //if the current term's degree of the first polynomial is bigger Result.insert(i->coef, i->pow); i++; } else if (j->pow > i->pow) { // if the other polynomial's term degree is bigger Result.insert(j->coef, j->pow); j++; } else { // if both are equal Result.insert(i->coef + j->coef, i->pow); i++; j++; } } //handle the remaining items in each list //note: at least one will be equal to end(), but that loop will simply be skipped while (i != poly.end()) { Result.insert(i->coef, i->pow); ++i; } while (j != P.poly.end()) { Result.insert(j->coef, j->pow); ++j; } return Result; } Subtraction: polinom operator-(const polinom& P) const //fixed prototype re. const-correctness { polinom Result; constIter i = poly.begin(), j = P.poly.begin(); while (i != poly.end() && j != P.poly.end()) { //logic while both iterators are valid if (i->pow > j->pow) { //if the current term's degree of the first polynomial is bigger Result.insert(-(i->coef), i->pow); i++; } else if (j->pow > i->pow) { // if the other polynomial's term degree is bigger Result.insert(-(j->coef), j->pow); j++; } else { // if both are equal Result.insert(i->coef - j->coef, i->pow); i++; j++; } } //handle the remaining items in each list //note: at least one will be equal to end(), but that loop will simply be skipped while (i != poly.end()) { Result.insert(i->coef, i->pow); ++i; } while (j != P.poly.end()) { Result.insert(j->coef, j->pow); ++j; } return Result; } Multiplication: polinom operator*(const polinom& P) const { polinom Result; constIter i, j, lastItem = Result.poly.end(); Iter it1, it2, first, last; int nr_matches; for (i = poly.begin() ; i != poly.end(); i++) { for (j = P.poly.begin(); j != P.poly.end(); j++) Result.insert(i->coef * j->coef, i->pow + j->pow); } Result.poly.sort(SortDescending()); lastItem--; while (true) { nr_matches = 0; for (it1 = Result.poly.begin(); it1 != lastItem; it1++) { first = it1; last = it1; first++; for (it2 = first; it2 != Result.poly.end(); it2++) { if (it2->pow == it1->pow) { it1->coef += it2->coef; nr_matches++; } } nr_matches++; do { last++; nr_matches--; } while (nr_matches != 0); Result.poly.erase(first, last); } if (nr_matches == 0) break; } return Result; } Division(Edited): polinom operator/(const polinom& P) const { polinom Result, temp2; polinom temp = *this; Iter i = temp.poly.begin(); constIter j = P.poly.begin(); int resultSize = 0; if (temp.poly.size() < 2) { if (i->pow >= j->pow) { Result.insert(i->coef / j->coef, i->pow - j->pow); temp = temp - Result * P; } else { Result.insert(0, 0); } } else { while (true) { if (i->pow >= j->pow) { Result.insert(i->coef / j->coef, i->pow - j->pow); if (Result.poly.size() < 2) temp2 = Result; else { temp2 = Result; resultSize = Result.poly.size(); for (int k = 1 ; k != resultSize; k++) temp2.poly.pop_front(); } temp = temp - temp2 * P; } else break; } } return Result; } }; The first three are working correctly but division doesn't as it seems the program is in a infinite loop. Final Update After listening to Dave, I finally made it by overloading both / and & to return the quotient and the remainder so thanks a lot everyone for your help and especially you Dave for your great idea! P.S. If anyone wants for me to post these 2 overloaded operator please ask it by commenting on my post (and maybe give a vote up for everyone involved).

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  • Jquery runtime error: object expected

    - by Joris
    The Jquery script that controls my tabcontainer gives an "object expected" runtime error. I honestly can't find the reason why: $(document).ready(function() { //When page loads... $(".tab_content").hide(); //Hide all content $("ul.tabs li:first").addClass("active").show(); //Activate first tab $(".tab_content:first").show(); //Show first tab content //On Click Event $("ul.tabs li").click(function() { $("ul.tabs li").removeClass("active"); //Remove any "active" class $(this).addClass("active"); //Add "active" class to selected tab $(".tab_content").hide(); //Hide all tab content var activeTab = $(this).find("a").attr("href"); //Find the href attribute value to identify the active tab + content $(activeTab).fadeIn(); //Fade in the active ID content return false; }); }); Has it something to do with the stylesheet?

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  • Programmatically controlling a Dojo Accordion

    - by prule
    I have a dijit.layout.AccordionContainer on my page which is defined in the html and created when dojo parses the page on load. Then, as the user interacts with the page I use Ajax to retrieve data and programmatically populate the container (removing existing items first). To illustrate my issue simply, here is some code that doesn't work: function doit() { var accordion = dijit.byId("accordionShell"); accordion.getChildren().each(function(item) { accordion.removeChild(item); }); for (i = 1; i < 5; i++) { var d = new dijit.layout.AccordionPane({title:'hello', content:'world'}); accordion.addChild(d); } } This fails, because only the first item in the accordian is visible. I think the others actually exist, but they are not visible so you can't do anything. I've managed to get around it by: Always ensuring there is 1 item in the accordian (so I never remove the first child) Call accordian.layout() after changing the contents So, this code "works" as long as you always want to see the first item, and don't actually expand any but the first one: function doit() { var accordion = dijit.byId("accordionShell"); var i = 0; accordion.getChildren().each(function(item) { if (i > 0) accordion.removeChild(item); i++; }); for (i = 1; i < 5; i++) { var d = new dijit.layout.AccordionPane({title:'hello', content:'world'}); accordion.addChild(d); } accordion.layout(); } I am using Dojo 1.2.0 - Anyone know what I am doing wrong?

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  • iphone SDK Keyboard problem

    - by Elishiah
    I have a login view controller that has a button and a UI text view that becomes the first responder. When the button is clicked it loads the forgot view controller and a new UI textview becomes the first responder. When I dissmis the modal view controller the keyboard also gets dismissed and when I load the forgot view controller again the keyboard will not pop up as the first responder. (IBAction) backBeg: (id) sender{ [self dismissModalViewControllerAnimated:YES]; }

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  • Validation Summary for Collections

    - by Myster
    Hi All, EDIT: upgraded this question to MVC 2.0 With asp.net MVC 2.0 is there an existing method of creating Validation Summary that makes sense for models containing collections? If not I can create my own validation summary Example Model: public class GroupDetailsViewModel { public string GroupName { get; set; } public int NumberOfPeople { get; set; } public List<Person> People{ get; set; } } public class Person { [Required(ErrorMessage = "Please enter your Email Address")] [RegularExpression(@"^([a-zA-Z0-9_\-\.]+)@((\[[0-9]{1,3}\.[0-9]{1,3}\.[0-9]{1,3}\.)|(([a-zA-Z0-9\-]+\.)+))([a-zA-Z]{2,4}|[0-9]{1,3})(\]?)$", ErrorMessage = "Please enter a valid Email Address")] public string EmailAddress { get; set; } [Required(ErrorMessage = "Please enter your Phone Number")] public string Phone { get; set; } [Required(ErrorMessage = "Please enter your First Name")] public string FirstName { get; set; } [Required(ErrorMessage = "Please enter your Last Name")] public string LastName { get; set; } } The existing summary <%=Html.ValidationSummary %> if nothing is entered looks like this. The following error(s) must be corrected before proceeding to the next step * Please enter your Email Address * Please enter your Phone Number * Please enter your First Name * Please enter your Last Name * Please enter your Email Address * Please enter your Phone Number * Please enter your First Name * Please enter your Last Name The design calls for headings to be inserted like this: The following error(s) must be corrected before proceeding to the next step Person 1 * Please enter your Email Address * Please enter your Phone Number * Please enter your First Name * Please enter your Last Name Person 2 * Please enter your Email Address * Please enter your Phone Number * Please enter your First Name * Please enter your Last Name

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  • How do I sort an array of Person Objects by using compareto()?

    - by Adam
    Here is my code: > import java.util.Scanner; import java.util.Arrays; /** This class tests the Person class. */ public class PersonDemo { public static void main(String[] args) { int count = 0; Scanner in = new Scanner(System.in); boolean more = false; Person first = null; Person last = null; while (more) { System.out.println( "Please enter the person's name or a blank line to quit"); String name = in.nextLine(); if (name.equals("")) more = false; else { Person p = new Person(name); //new person object created with inputted name Person[] people = new Person[10]; //new array of 10 person objects people[count] = p; //declare person object with index of variable count as the new person object first = people[count]; // I have no idea what to do here. This is where I'm stuck. last = people[count]; // I can't figure out what to do with this either. first.compareTo(p); //call compareTo method on first and new person object last.compareTo(p); //call compareTo method on last and new person object count++; // increase count variable } } System.out.println("First: " + first.toString()); System.out.println("Last: " + last.toString()); } } And the Person class: /** A person with a name. */ public class Person implements Comparable { /** * Constructs a Person with a name. * @param aName the person's name */ public Person(String aName) { name = aName; } public String getName() { return name; } @Override public int compareTo(Object otherObject) { Person other = (Person)otherObject; if (name.compareTo(other.name) < 0) return -1; if (name.compareTo(other.name) > 0) return 1; return 0; } /** Returns a string representation of the object. @return name of Person */ public String toString() { return "[name=" + name + "]"; } private String name; }

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  • How to get form elements from one form to another form in drupal

    - by ugesh.gali
    I have two forms in drupal and the form values is stores in DB.The first form contanins some fields related to company by default like id conpany,name etc.The second form consists of attributes .If I add attributes to the second form the attribute field should be visible in first form. Ex If i add loaction or any other field it should visible in first form as location field.

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  • Linq Query Performance , comparing Compiled query vs Non-Compiled.

    - by AG.
    Hello Guys, I was wondering if i extract the common where clause query into a common expression would it make my query much faster, if i have say something like 10 linq queries on a collection with exact same 1st part of the where clause. I have done a small example to explain a bit more . public class Person { public string First { get; set; } public string Last { get; set; } public int Age { get; set; } public String Born { get; set; } public string Living { get; set; } } public sealed class PersonDetails : List<Person> { } PersonDetails d = new PersonDetails(); d.Add(new Person() {Age = 29, Born = "Timbuk Tu", First = "Joe", Last = "Bloggs", Living = "London"}); d.Add(new Person() { Age = 29, Born = "Timbuk Tu", First = "Foo", Last = "Bar", Living = "NewYork" }); Expression<Func<Person, bool>> exp = (a) => a.Age == 29; Func<Person, bool> commonQuery = exp.Compile(); var lx = from y in d where commonQuery.Invoke(y) && y.Living == "London" select y; var bx = from y in d where y.Age == 29 && y.Living == "NewYork" select y; Console.WriteLine("All Details {0}, {1}, {2}, {3}, {4}", lx.Single().Age, lx.Single().First , lx.Single().Last, lx.Single().Living, lx.Single().Born ); Console.WriteLine("All Details {0}, {1}, {2}, {3}, {4}", bx.Single().Age, bx.Single().First, bx.Single().Last, bx.Single().Living, bx.Single().Born); So can some of the guru's here give me some advice if it would be a good practice to write query like var lx = "Linq Expression " or var bx = "Linq Expression" ? Any inputs would be highly appreciated. Thanks, AG

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  • Binary Cosine Cofficient

    - by hairyyak
    I was given the following forumulae for calculating this sim=|QnD| / v|Q|v|D| I went ahed and implemented a class to compare strings consisting of a series of words #pragma once #include <vector> #include <string> #include <iostream> #include <vector> using namespace std; class StringSet { public: StringSet(void); StringSet( const string the_strings[], const int no_of_strings); ~StringSet(void); StringSet( const vector<string> the_strings); void add_string( const string the_string); bool remove_string( const string the_string); void clear_set(void); int no_of_strings(void) const; friend ostream& operator <<(ostream& outs, StringSet& the_strings); friend StringSet operator *(const StringSet& first, const StringSet& second); friend StringSet operator +(const StringSet& first, const StringSet& second); double binary_coefficient( const StringSet& the_second_set); private: vector<string> set; }; #include "StdAfx.h" #include "StringSet.h" #include <iterator> #include <algorithm> #include <stdexcept> #include <iostream> #include <cmath> StringSet::StringSet(void) { } StringSet::~StringSet(void) { } StringSet::StringSet( const vector<string> the_strings) { set = the_strings; } StringSet::StringSet( const string the_strings[], const int no_of_strings) { copy( the_strings, &the_strings[no_of_strings], back_inserter(set)); } void StringSet::add_string( const string the_string) { try { if( find( set.begin(), set.end(), the_string) == set.end()) { set.push_back(the_string); } else { //String is already in the set. throw domain_error("String is already in the set"); } } catch( domain_error e) { cout << e.what(); exit(1); } } bool StringSet::remove_string( const string the_string) { //Found the occurrence of the string. return it an iterator pointing to it. vector<string>::iterator iter; if( ( iter = find( set.begin(), set.end(), the_string) ) != set.end()) { set.erase(iter); return true; } return false; } void StringSet::clear_set(void) { set.clear(); } int StringSet::no_of_strings(void) const { return set.size(); } ostream& operator <<(ostream& outs, StringSet& the_strings) { vector<string>::const_iterator const_iter = the_strings.set.begin(); for( ; const_iter != the_strings.set.end(); const_iter++) { cout << *const_iter << " "; } cout << endl; return outs; } //This function returns the union of the two string sets. StringSet operator *(const StringSet& first, const StringSet& second) { vector<string> new_string_set; new_string_set = first.set; for( unsigned int i = 0; i < second.set.size(); i++) { vector<string>::const_iterator const_iter = find(new_string_set.begin(), new_string_set.end(), second.set[i]); //String is new - include it. if( const_iter == new_string_set.end() ) { new_string_set.push_back(second.set[i]); } } StringSet the_set(new_string_set); return the_set; } //This method returns the intersection of the two string sets. StringSet operator +(const StringSet& first, const StringSet& second) { //For each string in the first string look though the second and see if //there is a matching pair, in which case include the string in the set. vector<string> new_string_set; vector<string>::const_iterator const_iter = first.set.begin(); for ( ; const_iter != first.set.end(); ++const_iter) { //Then search through the entire second string to see if //there is a duplicate. vector<string>::const_iterator const_iter2 = second.set.begin(); for( ; const_iter2 != second.set.end(); const_iter2++) { if( *const_iter == *const_iter2 ) { new_string_set.push_back(*const_iter); } } } StringSet new_set(new_string_set); return new_set; } double StringSet::binary_coefficient( const StringSet& the_second_set) { double coefficient; StringSet intersection = the_second_set + set; coefficient = intersection.no_of_strings() / sqrt((double) no_of_strings()) * sqrt((double)the_second_set.no_of_strings()); return coefficient; } However when I try and calculate the coefficient using the following main function: // Exercise13.cpp : main project file. #include "stdafx.h" #include <boost/regex.hpp> #include "StringSet.h" using namespace System; using namespace System::Runtime::InteropServices; using namespace boost; //This function takes as input a string, which //is then broken down into a series of words //where the punctuaction is ignored. StringSet break_string( const string the_string) { regex re; cmatch matches; StringSet words; string search_pattern = "\\b(\\w)+\\b"; try { // Assign the regular expression for parsing. re = search_pattern; } catch( regex_error& e) { cout << search_pattern << " is not a valid regular expression: \"" << e.what() << "\"" << endl; exit(1); } sregex_token_iterator p(the_string.begin(), the_string.end(), re, 0); sregex_token_iterator end; for( ; p != end; ++p) { string new_string(p->first, p->second); String^ copy_han = gcnew String(new_string.c_str()); String^ copy_han2 = copy_han->ToLower(); char* str2 = (char*)(void*)Marshal::StringToHGlobalAnsi(copy_han2); string new_string2(str2); words.add_string(new_string2); } return words; } int main(array<System::String ^> ^args) { StringSet words = break_string("Here is a string, with some; words"); StringSet words2 = break_string("There is another string,"); cout << words.binary_coefficient(words2); return 0; } I get an index which is 1.5116 rather than a value from 0 to 1. Does anybody have a clue why this is the case? Any help would be appreciated.

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  • jqgrid ASP.NET MVC -- getting data right for the grid.

    - by SamM09
    Here is my dilemma, I have not been able to manipulate my data to a form fitting to jqgrid standards. This is my first time using the jqgrid and I've spent a lot of time reading up on it. My js code is as follows: jQuery("#list").jqGrid({ url: '/Home/ListContacts/', dataType: "json", contentType: "application/json; charset=utf-8", mtype: 'POST', colNames: ['First Name', 'MI', 'Last Name'], colModel: [ { name: 'First Name', index: 'FName', width: 40, align: 'left' }, { name: 'MI', index: 'MInitial', width: 40, align: 'left' }, { name: 'Last Name', index: 'LName', width: 400, align: 'left'}], pager: jQuery('#pager'), rowNum: 10, rowList: [5, 10, 20, 50], sortname: 'Id', sortorder: "desc", repeatitems: false, viewrecords: true, imgpath: '/scripts/themes/basic/images', caption: 'My first grid' }); }); what im getting from the database: [["4","Jenna","Mccarthy"],["56","wer","weoiru"]] Now correct me if I am wrong, but the index: in my colModel refers to the column names in my database right? Could someone point to a reference that is straight forward or just start me off with this I would be most grateful.

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