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  • php dom problem

    - by Guru
    hello I'm new to PHP programming and I migrated from ASP .net to PHP.. I have a div just like below <div id="mydiv"></div> what I wanted to do is just to change the text and html content(like some name or any data in it) in it. What I imagine is just like mydiv=innertext="some value"; Thanks, GURU

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  • Weird text addition in PHP

    - by Patrick Gates
    I have a form posting data to a php page. Then I have the PHP page echoing the data aswell as posting it to twitter. Whenever In a word with an apostrophe it adds a back-slash right before it. So I type in "I'm going to the park" it echos "I\'m going to the park" what's going on and how do I fix it? Thanx :)

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  • PHP not outputting errors?

    - by Rob
    My webpage is putting out a 500 Internal Server Error. I've turned on E_ALL for error reporting in the php.ini, and restarted the httpd. I've even used error_reporting(E_ALL) and error_reporting(-1) but still no luck. Any suggestions? OS: CentOS5.5 PHP: 5.2.6 HTTPD: Apache/2.2.3

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  • Can I use PHP for a mobi site?

    - by kielie
    Hi guys, I have been doing some research on mobile websites, and thus far it seems to me that PHP is not supported by most handsets. I am trying to create multiple form's that lead up to a auto email response, which would be fairly simple if I could use PHP. Is there any other way of achieving this?

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  • php/ldap - bind fails but errorno doesn't execute

    - by user240907
    I am trying to connect to ldap with a php web application. If the username/password is correct everything works fine however if the username/password is incorrect I get the following error: PHP Warning: ldap_bind() [function.ldap-bind]: Unable to bind to server: Invalid credentials for some reason I am not able to look at the errorno or the state of the bind variable afterwards to print the appopriate user friendly error message. any ideas?

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  • php with oracle 9i

    - by php_oracle
    Hi everyone, I am new in php with oracle. Trying to connect with oracle by php. But have no success. I have installed xammp since i had to work with mysql. And now i have to use oracle 9i (9.2.0.6). Now if i use -- oci_connect(username, password, servicename) -- It says undefined function oci_connect(); Can any one tell how to configure xammpp for oracle? Thanks in advance

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  • PHP 'instanceof' failing with class constant

    - by Nathan Loding
    I'm working on a framework that I'm trying to type as strongly as I possibly can. (I'm working within PHP and taking some of the ideas that I like from C# and trying to utilize them within this framework.) I'm creating a Collection class that is a collection of domain entities/objects. It's kinda modeled after the List<T> object in .Net. I've run into an obstacle that is preventing me from typing this class. If I have a UserCollection, it should only allow User objects into it. If I have a PostCollection, it should only allow Post objects. All Collections in this framework need to have certain basic functions, such as add, remove, iterate. I created an interface, but found that I couldn't do the following: interface ICollection { public function add($obj) } class PostCollection implements ICollection { public function add(Post $obj) {} } This broke it's compliance with the interface. But I can't have the interface strongly typed because then all Collections are of the same type. So I attempted the following: interface ICollection { public function add($obj) } abstract class Collection implements ICollection { const type = 'null'; } class PostCollection { const type = 'Post'; public function add($obj) { if(!($obj instanceof self::type)) { throw new UhOhException(); } } } When I attempt to run this code, I get syntax error, unexpected T_STRING, expecting T_VARIABLE or '$' on the instanceof statement. A little research into the issue and it looks like the root of the cause is that $obj instanceof self is valid to test against the class. It appears that PHP doesn't process the entire self::type constant statement in the expression. Adding parentheses around the self::type variable threw an error regarding an unexpected '('. An obvious workaround is to not make the type variable a constant. The expression $obj instanceof $this->type works just fine (if $type is declared as a variable, of course). I'm hoping that there's a way to avoid that, as I'd like to define the value as a constant to avoid any possible change in the variable later. Any thoughts on how I can achieve this, or have I take PHP to it's limit in this regard? Is there a way of "escaping" or encapsulating self::this so that PHP won't die when processing it?

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  • PHP Doesn't Display Errors or Warnings.

    - by David
    I don't know how php.ini was configured since I don't have access to it. But on top of my php code file I have error_reporting(E_ALL); ini_set('display_errors', '1'); But still, if there is an error, e.g. missing a ")", the page is blank. It is so painful to debug without error message. Why were the errors not shown?

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  • Writing direct to disk with php

    - by Jurander
    I would like to create an upload script that doesn't fall under the php upload limit. There might be an occasion where I need to upload a 2GB, or larger file and I don't want to have to change the whole server execution to above 32MB. Is there a way to write direct to disk from php? What method might you propose someone would use to accomplish this? I have read around stack overflow but haven't quite found what I am looking to do.

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  • .htaccess makes php files downloadable

    - by arik-so
    I have an .htaccess file with following content: AddHandler x-httpd-php5 .php For some reason, whenever I upload it to the server, Firefox then wants to download PHP files instead of showing them, I think the Apache server has some error. What's wrong? Thanks in advance ^^

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  • PHP, Ajax, and the lifespan of the request

    - by Dave
    I was wondering about the lifespan of a PHP script when called via Ajax. Assume that there is a long-running (i.e. 30 seconds) PHP script on a server and that page is loaded via Ajax. Before the script completes, the user closes the browser. Does the script continue running to completion, is it terminated, or is this a function of the server itself (I'm running Apache fwiw). Thanks for any help.

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  • Good Training Sources for OOP PHP, Anyone ?

    - by Codex73
    Hey Guys. I will like to see if everybody could share any good training sources on OOP on PHP language. Good Training Sources for OOP (Object Oriented Programming) PHP, anyone ? I've seen numerous tutorials, mostly superficial, some of them bad. Please share anything good either commercial or free, Video or Written.

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  • POST request from Python to PHP

    - by RainbowHat
    Python params = urllib.parse.urlencode({'spam': '1', 'eggs': '2', 'bacon': '3'}) binary_data = params.encode('utf-8') reg = urllib.request.Request("http://www.abc.com/abc/smart/ap/request/",binary_data) reg.add_header('Content-Type','application/x-www-form-urlencoded') f = urllib.request.urlopen(reg) print(f.read()) PHP if($_SERVER['REQUEST_METHOD'] == 'POST') { //parse_str($_SERVER['QUERY_STRING']); var_dump($_SERVER['QUERY_STRING']); } When i try print binary_data , it does show the parameter but by the time it reaches the PHP , i see nothing. Any idea?

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  • Beginner PHP Question

    - by user317128
    I am working on an example from a php book and am getting an error on line 8 with this code <?php $agent = getenv("HTTP_USER_AGENT"); if (preg_match("/MSIE/i", "$agent")); { $result = "You are using Microsoft Internet Explorer"; } else if (preg_match("/Mozilla/i", "$agent")); { $result = "You are using Mozilla firefox"; } else {$result = "you are using $agent"; } echo $result; ?>

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  • accessing php javascript object in asp.net user control

    - by Khushi
    Hi, I have a website in php which is using 4 frames(top, left, middle and right). The middle frame contains the web user control coded in asp.net. Now, in the right frame( which is coded in php ) some javascript contains the id of the items selected in right frame. I need to get those ids to the middle frame on asp.net user control. How can i do this?

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  • opening and viewing a file in php

    - by Christian Burgos
    how do i open/view for editing an uploaded file in php? i have tried this but it doesn't open the file. $my_file = 'file.txt'; $handle = fopen($my_file, 'r'); $data = fread($handle,filesize($my_file)); i've also tried this but it wont work. $my_file = 'file.txt'; $handle = fopen($my_file, 'w') or die('Cannot open file: '.$my_file); $data = 'This is the data'; fwrite($handle, $data); what i have in mind is like when you want to view an uploaded resume,documents or any other ms office files like .docx,.xls,.pptx and be able to edit them, save and close the said file. edit: latest tried code... <?php // Connects to your Database include "configdb.php"; //Retrieves data from MySQL $data = mysql_query("SELECT * FROM employees") or die(mysql_error()); //Puts it into an array while($info = mysql_fetch_array( $data )) { //Outputs the image and other data //Echo "<img src=localhost/uploadfile/images".$info['photo'] ."> <br>"; Echo "<b>Name:</b> ".$info['name'] . "<br> "; Echo "<b>Email:</b> ".$info['email'] . " <br>"; Echo "<b>Phone:</b> ".$info['phone'] . " <hr>"; //$file=fopen("uploadfile/images/".$info['photo'],"r+"); $file=fopen("Applications/XAMPP/xamppfiles/htdocs/uploadfile/images/file.odt","r") or exit("unable to open file");; } ?> i am getting the error: Warning: fopen(Applications/XAMPP/xamppfiles/htdocs/uploadfile/images/file.odt): failed to open stream: No such file or directory in /Applications/XAMPP/xamppfiles/htdocs/uploadfile/view.php on line 17 unable to open file the file is in that folder, i don't know it wont find it.

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  • PHP Menu Items Count then add under more button

    - by Adrian M.
    Hello, I use the bellow code to load the main menu elements from some CMS, the present code is perfect except that it loads ALL the main items on a single line of menu - which will make the width of it unusable in any centered design (under 1000px).. I want to change this script so after 15 main elements will add a "MORE" button under which the rest of the main menu items will show as sub-items of this "MORE" button (they will not have their own sub-items as the first 15 do).. How can I do it? Thanks! <?php require_once( '../../../inc/header.inc.php' ); require_once( DIRECTORY_PATH_INC . 'membership_levels.inc.php' ); require_once( DIRECTORY_PATH_ROOT . "templates/tmpl_{$tmpl}/scripts/TemplMenu.php" ); class SimpleMenu extends TemplMenu { function getCode() { $this->iElementsCntInLine = 100; $this->getMenuInfo(); $this->genTopItems(); return $this->sCode; } function genTopItem($sText, $sLink, $sTarget, $sOnclick, $bActive, $iItemID, $isBold = false, $sPicture = '') { $sActiveStyle = ($bActive) ? ' id="tm_active"' : ''; if (!$bActive) { $sAlt= $sOnclick ? ( ' alt="' . $sOnclick . '"' ) : ''; $sTarget = $sTarget ? ( ' target="_parent"' ) : ''; } $sLink = (strpos($sLink, 'http://') === false && !strlen($sOnclick)) ? $this->sSiteUrl . $sLink : $sLink; $sSubMenu = $this->getAllSubMenus($iItemID); $sImgTabStyle = $sPictureRep = ''; if ($isBold && $sPicture != '') { $sPicturePath = getTemplateIcon($sPicture); $sPictureRep = "<img src='{$sPicturePath}' style='vertical-align:middle;width:16px;height:16px;' />"; $sText = '&nbsp;'; $sImgTabStyle = 'style="width:38px;"'; } $sMainSubs = ($sSubMenu=='') ? '' : " {$sSubMenu} </a>"; $this->sCode .= " <li><a href='{$sLink}' {$sOnclick} target='_parent'>{$sPictureRep}{$sText}</a> <div id='submenu'> <ul> <li>{$sMainSubs}</li> </ul> </div> </li> "; } } $objMenu = new SimpleMenu(); echo "<ul id='ddmenu'>"; echo $objMenu->getCode(); echo "</ul>"; ?>

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  • PHP object class variable

    - by mck89
    I have built a class in PHP and I must declare a class variable as an object. Everytime I want to declare an empty object I use: $var=new stdClass; But if I use it to declare a class variable as class foo { var $bar=new stdClass; } a parse error occurs. Is there a way to do this or must I declare the class variable as an object in the constructor function? PS: I'm using PHP 4.

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