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  • Safely escaping and reading back a file path in ruby

    - by user336851
    I need to save a few informations about some files. Nothing too fancy so I thought I would go with a simple one line per item text file. Something like this : # write io.print "%i %s %s\n" % [File.mtime(fname), fname, Digest::SHA1.file(fname).hexdigest] # read io.each do |line| mtime, name, hash = line.scanf "%i %s %s" end Of course this doesn't work because a file name can contain spaces (breaking scanf) and line breaks (breaking IO#each). The line break problem can be avoided by dropping the use of each and going with a bunch of gets(' ') while not io.eof? mtime = Time.at(io.gets(" ").to_i) name = io.gets " " hash = io.gets "\n" end Dealing with spaces in the names is another matter. Now we need to do some escaping. note : I like space as a record delimiter but I'd have no issue changing it for one easier to use. In the case of filenames though, the only one that could help is ascii nul "\0" but a nul delimited file isn't really a text file anymore... I initially had a wall of text detailing the iterations of my struggle to make a correct escaping function and its reciprocal but it was just boring and not really useful. I'll just give you the final result: def write_name(io, val) io << val.gsub(/([\\ ])/, "\\\\\\1") # yes that' 6 backslashes ! end def read_name(io) name, continued = "", true while continued continued = false name += io.gets(' ').gsub(/\\(.)/) do |c| if c=="\\\\" "\\" elsif c=="\\ " continued=true " " else raise "unexpected backslash escape : %p (%s %i)" % [c, io.path, io.pos] end end end return name.chomp(' ') end I'm not happy at all with read_name. Way too long and akward, I feel it shouldn't be that hard. While trying to make this work I tried to come up with other ways : the bittorrent encoded / php serialize way : prefix the file name with the length of the name then just io.read(name_len.to_i). It works but it's a real pita to edit the file by hand. At this point we're halfway to a binary format. String#inspect : This one looks expressly made for that purpose ! Except it seems like the only way to get the value back is through eval. I hate the idea of eval-ing a string I didn't generate from trusted data. So. Opinions ? Isn't there some lib which can do all this ? Am I missing something obvious ? How would you do that ?

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  • Haskell: Gluing a char and a list together?

    - by Vincent
    So I have this code here: toWords :: String - [a] toWords "" = [] toWords (nr1 : rest) | nr1 == ' ' = toWords rest | otherwise = nr1 : toWords rest The "toWords" function should simply remove all spaces and return a list with all the words. But I keep getting this error: test.hs:5:18: Couldn't match expected type a' against inferred typeChar' `a' is a rigid type variable bound by the type signature for `toWords' at test.hs:1:22 In the first argument of `(:)', namely `nr1' In the expression: nr1 : toWords rest In the definition of `toWords': toWords (nr1 : rest) | nr1 == ' ' = toWords rest | otherwise = nr1 : toWords rest Failed, modules loaded: none.

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  • How to remove/hide <div></div> tags only without the content?

    - by candies
    For example I have: <div id ="test">[the content here]</div> The content within the div tags will appear after I called the id of div using ajax. This is the code: function dinamic(add) { var kode = add.value; if (!kode) return; xmlhttp2.open('get', '../template/get_id.php?kode='+kode, true); xmlhttp2.onreadystatechange = function() { if ((xmlhttp2.readyState == 4) && (xmlhttp2.status == 200)) { var add = document.getElementById("test"); add.innerHTML = xmlhttp2.responseText; } return false; } xmlhttp2.send(null); } So it will appear <div id="test">A</div> I'd like to put the content of div - A into mysql query. $test = $_GET['test']; $query = "select * from example where category='$test'"; I've tried to make variable $test of the div id to get the content but result of the query in category is none. I tried again, I put the div in to the query $query = "select * from example where category='<div id=\"test\">A</div>'"; Yes, It works. But when I did query on navicat, no results I got because there's spaces between A that is <div> and </div>. How to remove/hide the div tags only so its only appear the content? > $query = "select * from example where category='A'"; < Edit: If I echo the query on firefox browser will say "$query = "select * from example where category='[space]A[space]'";" And look at the bug(I use firebug), it will say "$query = "select * from example where category='<div id="test">A</div>'";" So my guessing why can't get result after query on navicat is there's spaces between A([space]A[space]), just have no idea how to remove/hide the div tags, I want to get this result only "$query = "select * from example where category='A'";" Thanks.

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  • Split string in C every white space

    - by redsolja
    I want to write a program in C that displays each word of a whole sentence (taken as input) at a seperate line. This is what i have done so far: void manipulate(char *buffer); int get_words(char *buffer); int main(){ char buff[100]; printf("sizeof %d\nstrlen %d\n", sizeof(buff), strlen(buff)); // Debugging reasons bzero(buff, sizeof(buff)); printf("Give me the text:\n"); fgets(buff, sizeof(buff), stdin); manipulate(buff); return 0; } int get_words(char *buffer){ // Function that gets the word count, by counting the spaces. int count; int wordcount = 0; char ch; for (count = 0; count < strlen(buffer); count ++){ ch = buffer[count]; if((isblank(ch)) || (buffer[count] == '\0')){ // if the character is blank, or null byte add 1 to the wordcounter wordcount += 1; } } printf("%d\n\n", wordcount); return wordcount; } void manipulate(char *buffer){ int words = get_words(buffer); char *newbuff[words]; char *ptr; int count = 0; int count2 = 0; char ch = '\n'; ptr = buffer; bzero(newbuff, sizeof(newbuff)); for (count = 0; count < 100; count ++){ ch = buffer[count]; if (isblank(ch) || buffer[count] == '\0'){ buffer[count] = '\0'; if((newbuff[count2] = (char *)malloc(strlen(buffer))) == NULL) { printf("MALLOC ERROR!\n"); exit(-1); } strcpy(newbuff[count2], ptr); printf("\n%s\n",newbuff[count2]); ptr = &buffer[count + 1]; count2 ++; } } } Although the output is what i want, i have really many black spaces after the final word displayed, and the malloc() returns NULL so the MALLOC ERROR! is displayed in the end. I can understand that there is a mistake at my malloc() implementation but i do not know what it is. Is there another more elegant - generally better way to do it? Thanks in advance.

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  • Reading a line backwards

    - by Jimmy
    Hi, I'm using regular expression to count the total spaces in a line (first occurrence). match(/^\s*/)[0].length; However this reads it from the start to end, How can I read it from end to start. Thanks

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  • Using enums in Java across multiple classes

    - by Richard Mar.
    I have the following class: public class Card { public enum Suit { SPACES, HEARTS, DIAMONDS, CLUBS }; public Card(Suit nsuit, int nrank) { suit = nsuit; rank = nrank; } private Suit suit; private int rank; } I want to instantiate it in another class, but that class doesn't understand the Suit enum. Where should I put the enum to make it publicly visible?

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  • C#: How to replace "-" with " -" only when it's not preceded by "e"?

    - by MaDDoX
    I imagine I should use Regex for that but I still scratch my head a lot about it (and the only similar question I found wasn't exactly my case) so I decided to ask for help. This is the input and expected output: Input: "c-0.68219,-0.0478 -1.01455-0.0441 0.2321e-4,0.43212" Output:"c -0.68219,-0.0478 -1.01455 -0.0441 0.2321e-4,0.43212" Basically I need either commas or spaces as value separators, but I can't break the exponential index (e-4). Maybe do two successive replacements?

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  • Select fields containing at least one non-space alphanumeric character

    - by zzapper
    (Sorry I know this is an old chestnut; I have found similar answers here but not an exact answer) These are frequent hand written queries from a console so I is what I am looking for is the easiest thing to type SELECT * FROM tbl_loyalty_card WHERE CUSTOMER_ID REGEXP "[0-9A-Z]"; or SELECT * FROM tbl_loyalty_card WHERE LENGTH(CUSTOMER_ID) >0; -- could match spaces Do you have anything quicker to type even if it's QAD?

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  • Parsing Tabular cell data with space where there is td tag.

    - by Harikrishna
    I am parsing html tabular information with the help of the html agility pack. Now First I am finding the rows in that table like var rows = table.Descendants("tr"); then I find the cell data for each row like foreach(var row in rows) { string rowInnerText = row.InnerText; } That gives me the cell data.But with no spaces between them like NameAdressPhone No but I want the innertext like Name Address Phone No means where there is td tag I want to keep there one space between different column cell.

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  • How to change the separation character of Zend Url?

    - by koko
    I use Zend URL view helper for building my urls. Everythings works exactly as I'd like to, except one thing: The character used for replacing spaces in the url is a plus (+). I'd like it to be a 'min' (-). How can I change this? Example: Now: /nl/nieuws/bericht/3/title/nieuwe*+affiches Wish: /nl/nieuws/bericht/3/title/nieuwe-*affiches Thanks in advcance!

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  • DataGridView formatting

    - by Vadim
    I have a DGV with columns "code" and "name". Depends of lenght of a code I want to add tabulation to the "name" cells, to show structure of a data. Like that in this picture: How is it better to do? I think there is a better way then just loop for all rows and add spaces in front of names, right?

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  • how do I replace certain characters in a string?

    - by user296516
    Hi guys, Suppose I have a string like this SOMETHING [1000137c] SOMETHING = John Rogers III [SOMETHING] SOMETHING ELSE and I need to turn it into this SOMETHING [1000137c] SOMETHING = John_Rogers_III [SOMETHING] SOMETHING ELSE Therefor I need to replace spaces between words after "[1000137c] SOMETHING = " and before " [". How can I do that in php? Thanks!

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  • Getting a substring in Ruby by x number of chars

    - by wotaskd
    I'm trying to produce some Ruby code that will take a string and return a new one, with a number x number of characters removed from its end - these can be actual letters, numbers, spaces etc. Ex: given the following string a_string = "a1wer4zx" I need a simple way to get the same string, minus - say - the 3 last digits. In the case above, that would be "a1wer". The way I'm doing it right now seems very convoluted: an_array = a_string.split(//,(a_string.length-2)) an_array.pop new_string = an_array.join Any ideas?

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