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  • django forms in diferent contexts

    - by z3a
    I'm in a middle of a problem, I have a url like /account/login that displays a login form. I need to include this form in another template that have a different url. I tried to use {%include%} but this don't work, the form is not shown. Any one have a clue about this??

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  • Django unable to update model

    - by user292652
    i have the following function to override the default save function in a model match def save(self, *args, **kwargs): if self.Match_Status == "F": Team.objects.filter(pk=self.Team_one.id).update(Played=F('Played')+1) Team.objects.filter(pk=self.Team_two.id).update(Played=F('Played')+1) if self.Winner !="": Team.objects.filter(pk=self.Winner.id).update(Win=F('Win')+1, Points=F('Points')+3) else: return if self.Match_Status == "D": Team.objects.filter(pk=self.Team_one.id).update(Played=F('Played')+1, Draw = F('Draw')+1, Points=F('Points')+1) Team.objects.filter(pk=self.Team_two.id).update(Played=F('Played')+1, Draw = F('Draw')+1, Points=F('Points')+1) super(Match, self).save(*args, **kwargs) I am able to save the match model just fine but Team model does not seem to be updating at all and no error is being thrown. am i missing some thing here ?

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  • How to display total record count against models in django admin

    - by Rog
    Is there a neat way to make the record/object count for a model appear on the main model list in the admin module? I have found techniques for showing counts of related objects within sets in the list_display page (and I can see the total in the pagination section at the bottom of the same), but haven't come across a neat way to show the record count at the model list level.

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  • Django: How to set default language in admin on login

    - by lazerscience
    I'm saving an user's default language in his user profile and on login I want to set the admin's default language to it. One possibility I was thinking of is using a middleware, but I think if I do it on process_request I will not see an user object there since this is processed AFTER the middleware, so I could only set it after the next request! Any solutions are highly appreciated!

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  • Manually listing objects in Django (problem with field ordering)

    - by Chris
    I'm having some trouble figuring out the best/Djangoic way to do this. I'm creating something like an interactive textbook. It has modules, which are more or less like chapters. Each module page needs to list the topics in that module, grouped into sections. My question is how I can ensure that they list in the correct order in the template? Specifically: 1) How to ensure the sections appear in the correct order? 2) How to ensure the topics appear in the correct order in the section? I imagine I could add a field to each model purely for the sake of ordering, but the problem with that is that a topic might appear in different modules, and in whatever section they are in there they would again have to be ordered somehow. I would probably give up and do it all manually were it not for the fact that I need to have the Topic as object in the template (or view) so I can mark it up according to how the user has labeled it. So I suppose my question is really to do with whether I should create the contents pages manually, or whether there is a way of ordering the query results in a way I haven't thought of. Thanks for your help!

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  • Django many to many annotations and filters

    - by dl8
    So I have two models, Person and Film where they're in a many to many relationship. My goal is to grab a film, and output the persons that have also appeared in at least 10 films. For example I can get the count individually by: >>> Person.objects.get(short__istartswith = "Matt Damon").film_set.count() 71 However, if I try to filter all the actors of a particular film out: >>> Film.objects.get(name__istartswith="Saving Private Ryan").actors.all().annotate(film_count=Count('film')).filter(film_count__gte=10) [] it returns an empty set since if I manually look at everyone's film_count it's 1, even though an actor such as Matt Damon (as seen above) has been in 71 films in my db. As you can see with this query, the annotation doesn't work: >>> Film.objects.get(name__istartswith="Saving Private Ryan").actors.all().annotate(film_count=Count('film'))[0].film_count 1 >>> Film.objects.get(name__istartswith="Saving Private Ryan").actors.all().annotate(film_count=Count('film'))[0].film_set.count() 7 and I can't seem to figure out a way to filter it by the film_set.count()

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  • Django templates check condition

    - by Hulk
    If there are are no values in the table how can should the code be to indicate no name found else show the drop down box in the below code {% for name in dict.names %} <option value="{{name.id}}" {% for selected_id in selected_name %}{% ifequal name.id selected_id %} {{ selected }} {% endifequal %} {% endfor %}>{{name.firstname}}</option>{% endfor %} </select> Thanks..

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  • Django - calling full_clean() inside of clean() equivalent?

    - by orokusaki
    For transaction purposes, I need all field validations to run before clean() is done. Is this possible? My thinking is this: @transaction.commit_on_success def clean(self): # Some fun stuff here. self.full_clean() # I know this isn't correct, but it illustrates my point. but obviously that's not correct, because it would be recursive. Is there a way to make sure that everything that full_clean() does is done inside clean()?

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  • Time based movement Vs Frame rate based movement?

    - by sil3nt
    Hello there, I'm new to Game programmming and SDL, and I have been following Lazyfoo's SDL tutorials. My question is related to time based motion and frame rate based motion, basically which is better or appropriate depending on situations?. Could you give me an example where each of these methods are used?. Another question I have is that, in lazyfoo's two Motion tutorials (FPS based and time based) The time based method showed a much smoother animation while the Frame rate based one was a little hiccupy, meaning you could clearly see the gap between the previous location of the dot and its current position when you compare the two programs. As beginner which method should I stick to?(all I want is smooth animations).

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  • Debugging "Premature end of script headers" - WSGI/Django [migrated]

    - by Marcin
    I have recently deployed an app to a shared host (webfaction), and for no apparent reason, my site will not load at all (it worked until today). It is a django app, but the django.log is not even created; the only clue is that in one of the logs, I get the error message: "Premature end of script headers", identifying my wsgi file as the source. I've tried to add logging to my wsgi file, but I can't find any log created for it. Is there any recommended way to debug this error? I am on the point of tearing my hair out. My WSGI file: import os import sys from django.core.handlers.wsgi import WSGIHandler import logging logger = logging.getLogger(__name__) os.environ['DJANGO_SETTINGS_MODULE'] = 'settings' os.environ['CELERY_LOADER'] = 'django' virtenv = os.path.expanduser("~/webapps/django/oneclickcosvirt/") activate_this = virtenv + "bin/activate_this.py" execfile(activate_this, dict(__file__=activate_this)) # if 'VIRTUAL_ENV' not in os.environ: # os.environ['VIRTUAL_ENV'] = virtenv sys.path.append(os.path.dirname(virtenv+'oneclickcos/')) logger.debug('About to run WSGIHandler') try: application = WSGIHandler() except (Exception,), e: logger.debug('Exception starting wsgihandler: %s' % e) raise e

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  • Disabling email-style usernames in Django 1.2 with django-registration

    - by shacker
    Django 1.2 allows usernames to take the form of an email address. Changed in Django 1.2: Usernames may now contain @, +, . and - characters I know that's a much-requested feature, but what if you don't want the new behavior? It makes for messy usernames in profile URLs and seems to break django-registration (if a user registers an account with an email-style username, the link in the django-registration activation email returns 404). Does anyone have a recipe for restoring the old behavior and disabling email-style usernames?

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  • MultiWidget in MultiWidget how to compress the first one?

    - by sacabuche
    I have two MultiWidget one inside the other, but the problem is that the MultiWidget contained don't return compress, how do i do to get the right value from the first widget? In this case from SplitTimeWidget class SplitTimeWidget(forms.MultiWidget): """ Widget written to split widget into hours and minutes. """ def __init__(self, attrs=None): widgets = ( forms.Select(attrs=attrs, choices=([(hour,hour) for hour in range(0,24)])), forms.Select(attrs=attrs, choices=([(minute, str(minute).zfill(2)) for minute in range(0,60)])), ) super(SplitTimeWidget, self).__init__(widgets, attrs) def decompress(self, value): if value: return [value.hour, value.minute] return [None, None] class DateTimeSelectWidget (forms.MultiWidget): """ A widget that splits date into Date and Hours, minutes, seconds with selects """ date_format = DateInput.format def __init__(self, attrs=None, date_format=None): if date_format: self.date_format = date_format #if time_format: # self.time_format = time_format hours = [(hour,str(hour)+' h') for hour in range(0,24)] minutes = [(minute,minute) for minute in range(0,60)] seconds = minutes #not used always in 0s widgets = ( DateInput(attrs=attrs, format=self.date_format), SplitTimeWidget(attrs=attrs), ) super(DateTimeSelectWidget,self).__init__(widgets, attrs) def decompress(self, value): if value: return [value.date(), value.time()] else: [None, None, None]

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  • Drupal Views display newest content per taxonomy limit to one node

    - by digital
    Hi, I want to create a view where all 5 of my taxonomy terms are displayed and it then displays the latest node published but this is limited by 1. For Example: Tax Term 1 Latest node published Tax Term 2 Latest node published etc etc Currently I'm grouping by taxonomy term so it's displaying all nodes published then sorted by published date desc. I can't quite figure out how to limit the nodes to only show one item per taxonomy term. Any help would be greatly appreciated.

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  • Component based game engine issue

    - by Mathias Hölzl
    We are just switching from a hierarchy based game engine to a component based game engine. My problem is that when I load a model which has has a hierarchy of meshes and the way I understand is that a entity in a component based system can not have multiple components of the same type, but I need a "meshComponent" for each mesh in a model. So how could I solve this problem. On this side they implemented a Component based game engine: http://cowboyprogramming.com/2007/01/05/evolve-your-heirachy/

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  • Does Django cache url regex patterns somehow?

    - by Emre Sevinç
    I'm a Django newbie who needs help: Even though I change some urls in my urls.py I keep on getting the same error message from Django. Here is the relevant line from my settings.py: ROOT_URLCONF = 'mydjango.urls' Here is my urls.py: from django.conf.urls.defaults import * # Uncomment the next two lines to enable the admin: from django.contrib import admin admin.autodiscover() urlpatterns = patterns('', # Example: # (r'^mydjango/', include('mydjango.foo.urls')), # Uncomment the admin/doc line below and add 'django.contrib.admindocs' # to INSTALLED_APPS to enable admin documentation: #(r'^admin/doc/', include(django.contrib.admindocs.urls)), # (r'^polls/', include('mydjango.polls.urls')), (r'^$', 'mydjango.polls.views.homepage'), (r'^polls/$', 'mydjango.polls.views.index'), (r'^polls/(?P<poll_id>\d+)/$', 'mydjango.polls.views.detail'), (r'^polls/(?P<poll_id>\d+)/results/$', 'mydjango.polls.views.results'), (r'^polls/(?P<poll_id>\d+)/vote/$', 'mydjango.polls.views.vote'), (r'^polls/randomTest1/', 'mydjango.polls.views.randomTest1'), (r'^admin/', include(admin.site.urls)), ) So I expect that whenever I visit http://mydjango.yafz.org/polls/randomTest1/ the mydjango.polls.views.randomTest1 function should run because in my polls/views.py I have the relevant function: def randomTest1(request): # mainText = request.POST['mainText'] return HttpResponse("Default random test") However I keep on getting the following error message: Page not found (404) Request Method: GET Request URL: http://mydjango.yafz.org/polls/randomTest1 Using the URLconf defined in mydjango.urls, Django tried these URL patterns, in this order: 1. ^$ 2. ^polls/$ 3. ^polls/(?P<poll_id>\d+)/$ 4. ^polls/(?P<poll_id>\d+)/results/$ 5. ^polls/(?P<poll_id>\d+)/vote/$ 6. ^admin/ 7. ^polls/randomTest/$ The current URL, polls/randomTest1, didn't match any of these. I'm surprised because again and again I check urls.py and there is no ^polls/randomTest/$ in it, but there is ^polls/randomTest1/' It seems like Django is somehow storing the previous contents of urls.py and I just don't know how to make my latest changes effective. Any ideas? Why do I keep on seeing some old version of regexes when I try to load that page even though I changed my urls.py?

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  • force delete row on django app after migration

    - by unsorted
    After a migration with south, I ended up deleting a column. Now the current data in one of my tables is screwed up and I want to delete it, but attempts to delete just result in an error: >>> d = Degree.objects.all() >>> d.delete() Traceback (most recent call last): File "<console>", line 1, in <module> File "C:\Python26\lib\site-packages\django\db\models\query.py", line 440, in d elete for i, obj in izip(xrange(CHUNK_SIZE), del_itr): File "C:\Python26\lib\site-packages\django\db\models\query.py", line 106, in _ result_iter self._fill_cache() File "C:\Python26\lib\site-packages\django\db\models\query.py", line 760, in _ fill_cache self._result_cache.append(self._iter.next()) File "C:\Python26\lib\site-packages\django\db\models\query.py", line 269, in i terator for row in compiler.results_iter(): File "C:\Python26\lib\site-packages\django\db\models\sql\compiler.py", line 67 2, in results_iter for rows in self.execute_sql(MULTI): File "C:\Python26\lib\site-packages\django\db\models\sql\compiler.py", line 72 7, in execute_sql cursor.execute(sql, params) File "C:\Python26\lib\site-packages\django\db\backends\util.py", line 15, in e xecute return self.cursor.execute(sql, params) File "C:\Python26\lib\site-packages\django\db\backends\sqlite3\base.py", line 200, in execute return Database.Cursor.execute(self, query, params) DatabaseError: no such column: students_degree.abbrev >>> Is there a simple way to just force a delete? Do I drop the table and then rerun manage.py schemamigration to recreate the table in south?

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  • 2-step user registration with Django

    - by David S
    I'm creating a website with Django and want a fairly common 2-step user registration. What I mean by this is that the user fills in the some basic user information + some application specific information (sort of like a coupon value). Upon submit, an email is sent to ensure email address is valid. This email should contain a link to click on to "finish" the registration. When the link is clicked, the user is marked as validated and they are directed to a new page to complete optional "user profile" type information. So, pretty basic stuff. I have done some research and found django-registration by James Bennett. I do know who James is and have seen him at PyCons and DjanoCons in the past. There is obviously very few people in the world that know Django better than James (so, I know the quality of the code/app is good). But, it almost seems like a bit of over kill. I've read through the docs and was a bit confused (maybe I'm just being a bit dense today). I believe that if I do use django-registration, I will need to have some custom forms, etc. Is there anything else out there I should evaluate? Or are there any good tutorials or videos on using django-registration? I've done a bit of googling, but haven't found anything. But, I suspect that it might be a case of a lot of very common words that don't really find what you are looking for (django user registration tutorial/example). Or is just a case where it would be just about as easy to build your own solution with Django forms, etc? Here is the tech stack I'm using: Python 2.7.2 Django 1.3.1 PostgreSQL 9.1 psycopg2 2.4.1 Twitter Bootstrap 2.0.2

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  • error in implementing static files in django

    - by POOJA GUPTA
    my settings.py file:- STATIC_ROOT = '/home/pooja/Desktop/static/' # URL prefix for static files. STATIC_URL = '/static/' # Additional locations of static files STATICFILES_DIRS = ( '/home/pooja/Desktop/mysite/search/static', ) my urls.py file:- from django.conf.urls import patterns, include, url from django.contrib.staticfiles.urls import staticfiles_urlpatterns from django.contrib import admin admin.autodiscover() urlpatterns = patterns('', url(r'^search/$','search.views.front_page'), url(r'^admin/', include(admin.site.urls)), ) urlpatterns += staticfiles_urlpatterns() I have created an app using django which seraches the keywords in 10 xml documents and then return their frequency count displayed as graphical representation and list of filenames and their respective counts.Now the list has filenames hyperlinked, I want to display them on the django server when user clicks them , for that I have used static files provision in django. Hyperlinking has been done in this manner: <ul> {% for l in list1 %} <li><a href="{{STATIC_URL}}static/{{l.file_name}}">{{l.file_name}}</a{{l.frequency_count</li> {% endfor %} </ul> Now when I run my app on the server, everything is running fine but as soon as I click on the filename, it gives me this error : Using the URLconf defined in mysite.urls, Django tried these URL patterns, in this order: ^search/$ ^admin/ ^static\/(?P<path>.*)$ The current URL, search/static/books.xml, didn't match any of these. I don't know why this error is coming, because I have followed the steps required to achieve this. I have posted my urls.py file and it is showing error in that only. I'm new to django , so Please help

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  • How to make a model instance read-only after saving it once?

    - by Ryszard Szopa
    One of the functionalities in a Django project I am writing is sending a newsletter. I have a model, Newsletter and a function, send_newsletter, which I have registered to listen to Newsletter's post_save signal. When the newsletter object is saved via the admin interface, send_newsletter checks if created is True, and if yes it actually sends the mail. However, it doesn't make much sense to edit a newsletter that has already been sent, for the obvious reasons. Is there a way of making the Newsletter object read-only once it has been saved? Edit: I know I can override the save method of the object to raise an error or do nothin if the object existed. However, I don't see the point of doing that. As for the former, I don't know where to catch that error and how to communicate the user the fact that the object wasn't saved. As for the latter, giving the user false feedback (the admin interface saying that the save succeded) doesn't seem like a Good Thing. What I really want is allow the user to use the Admin interface to write the newsletter and send it, and then browse the newsletters that have already been sent. I would like the admin interface to show the data for sent newsletters in an non-editable input box, without the "Save" button. Alternatively I would like the "Save" button to be inactive.

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  • django internationalization doesn't work

    - by xRobot
    I have: * created translation strings in the template and in the application view. * run this command: django-admin.py makemessages -l it and the file it/LC_MESSAGES/django.po has been created * translated strings in the django.po file. * run this command: django-admin.py compilemessages and I receive: processing file django.po in /home/jobber/Desktop/library/books/locale/it/LC_MESSAGES * set this in settings.py: LANGUAGE_CODE = 'it' TEMPLATE_CONTEXT_PROCESSORS = ( "django.core.context_processors.auth", "django.core.context_processors.debug", "django.core.context_processors.i18n", "django.core.context_processors.media", ) USE_I18N = True MIDDLEWARE_CLASSES = ( 'django.middleware.common.CommonMiddleware', 'django.middleware.locale.LocaleMiddleware', 'django.contrib.sessions.middleware.SessionMiddleware', 'django.contrib.auth.middleware.AuthenticationMiddleware', ) but.... translation doesn't work !! I always see english text. Why ?

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  • How to add manytomany field to flatpage admin

    - by valya
    Hello! I have a site with Flatpages, and now I need to be able to add galleries (Gallery model) to the page. This is going to be ManyToManyField, so there is no need to change the flatpages table. But I still can't define ManyToManyField in proxy class. I can define ManyToManyField in Gallery model, but it isn't comfortable for the client. How can I change FlatPage Admin to add a ManyToManyField from Galleries model?

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