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  • Not Equal two Generic Lists

    - by David Johnson
    I have two generic lists, both containing different data, except 4 fields, which I want to compare to another list and find items that do not match in either list. I need to basically replace where it says equals below, with not equals! var unMatchedData = from liveLines in liveList join oldList in comapreSnapshotList on new {liveLines.ClientNo, liveLines.SequenceNo, liveLines.LineNo, liveLines.Text} equals new {oldList.ClientNo, oldList.SequenceNo, oldList.LineNo, oldList.Text} select new KNOWTXTS { ClientNo = liveLines.ClientNo, SequenceNo = liveLines.SequenceNo, LineNo = liveLines.LineNo, Text = liveLines.Text };

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  • classic asp comparison of comma seperated lists

    - by Reiwoldt
    Hello, I have two comma seperated lists:- 36,189,47,183,65,50 65, 50, 189, 47 the question is how to compare the two in classic ASP in order to identify and return any values that exist in list 1 but that don't exist in list 2 bearing in mind that associative arrays aren't available. e.g. in the above example I would need the return value to be 36,183 Thanks

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  • C# recursive programming with lists

    - by David Torrey
    I am working on a program where each item can hold an array of items (i'm making a menu, which has a tree-like structure) currently i have the items as a list, instead of an array, but I don't feel like I'm using it to its full potential to simplify code. I chose a list over a standard array because the interface (.add, .remove, etc...) makes a lot of sense. I have code to search through the structure and return the path of the name (i.e. Item.subitem.subsubitem.subsubsubitem). Below is my code: public class Item { //public Item[] subitem; <-- Array of Items public List<Item> subitem; // <-- List of Items public Color itemColor = Color.FromArgb(50,50,200); public Rectangle itemSize = new Rectangle(0,0,64,64); public Bitmap itemBitmap = null; public string itemName; public string LocateItem(string searchName) { string tItemName = null; //if the item name matches the search parameter, send it up) if (itemName == searchName) { return itemName; } if (subitem != null) { //spiral down a level foreach (Item tSearchItem in subitem) { tItemName = tSearchItem.LocateItem(searchName); if (tItemName != null) break; //exit for if item was found } } //do name logic (use index numbers) //if LocateItem of the subitems returned nothing and the current item is not a match, return null (not found) if (tItemName == null && itemName != searchName) { return null; } //if it's not the item being searched for and the search item was found, change the string and return it up if (tItemName != null && itemName != searchName) { tItemName.Insert(0, itemName + "."); //insert the parent name on the left --> TopItem.SubItem.SubSubItem.SubSubSubItem return tItemName; } //default not found return null; } } My question is if there is an easier way to do this with lists? I've been going back and forth in my head as to whether I should use lists or just an array. The only reason I have a list is so that I don't have to make code to resize the array each time I add or remove an item.

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  • How to remove certain lists from a list of lists using python?

    - by seaworthy
    I can not figure out why my code does not filter out lists from a predefined list. I am trying to remove specific list using the following code. data = [[1,1,1],[1,1,2],[1,2,1],[1,2,2],[2,1,1],[2,1,2],[2,2,1],[2,2,2]] data = [x for x in data if x[0] != 1 and x[1] != 1] print data My result: data = [[2, 2, 1], [2, 2, 2]] Expected result: data = [[1,2,1],[1,2,2],[2,1,1],[2,1,2],[2,2,1],[2,2,2]]

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  • Prolog returns Out = _G431 when it suppose to return a list of lists

    - by Mandah
    createSchedule([[math109]], fall, Out). [[cs485, cs485], [cs355, cs355, cs462, cs462, cs462], [cs345, cs345, cs352, cs352, cs352, cs362, cs362, cs362, cs396, cs396, cs396], [cs330, cs330, cs330], [cs255, cs255, cs255, cs268, cs268], [math114, cs245, cs245], [math112, cs145, cs146], [math109]] Out = _G431 this is what prolog returns and the list of lists is shown by using write(Out) in prolog. Any ideas why it is showing this? Thanks

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  • Trimming lists using a loop

    - by Vishal
    I have few lists like: a = [1, 2, 3, 4, 5] b = [4, 6, 5, 9, 2] c = [4, 7, 9, 1, 2] I want to trim all of them using a loop, instead of doing as below: a[-2:] b[-2:] c[-2:] I tried but got confused with pass by value or pass by reference fundamentals, looked into other questions as well but no help. Thanks

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  • error creating MS Exchange distribution list: Active directory response: 00000005: SecErr: DSID-031521D0

    - by BabakBani
    We've migrated a client from google apps to an MS Exchange 2010 SP2 on-premise setup. The setup /prepareAD went well, and the software was installed with the Administrator account. We've used the Exchange Management Console to setup mailboxes and had to google up the appropriate workarounds such as going into each users Advanced Security Settings and selecting "include inheritable permissions from this object's parents", and changing their logon-to from specific machines to "all computers" so that they can connect to Outlook Web Access, and in turn so their Outlook 2007-2010 clients can connect to Exchange. Sending and receiving emails are working well. Now that all this is in place, we can create Dynamic Distrubution Lists with no problem, but as soon as we try and create a DISTRIBUTION LIST, either in the EMC or the Exchange PowerShell, we get an error. As the error message in the powershell is more verbose, I include this if anyone can suggest how we remedy this: [PS] C:\Windows\system32new-DistributionGroup -Name 'projects' -SamAccountName 'projects' -Alias 'projects' Active Directory operation failed on DC.cppe.local. This error is not retriable. Additional information: Access is denied. Active directory response: 00000005: SecErr: DSID-031521D0, problem 4003 (INSUFF_ACCESS_RIGHTS), data 0 + CategoryInfo : NotSpecified: (0:Int32) [New-DistributionGroup], ADOperationException + FullyQualifiedErrorId : 1EA5CD3E,Microsoft.Exchange.Management.RecipientTasks.NewDistributionGroup

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  • Displaying music list using custom lists instead of array adapters

    - by Rahul Varma
    Hi, I have displayed the music list in a list view. The list is obtained from a website. I have done this using Arraylist. Now, i want to iterate the same program using custom lists and custom adapters instead of array list. The code i have written using array lists is... public class MusicListActivity extends Activity { MediaPlayer mp; File mediaFile; TextView tv; TextView albumtext; TextView artisttext; ArrayList<String> al=new ArrayList<String>(); //ArrayList<String> al=new ArrayList<String>(); ArrayList<String> node=new ArrayList<String>(); ArrayList<String> filepath=new ArrayList<String>(); ArrayList<String> imgal=new ArrayList<String>(); ArrayList<String> album=new ArrayList<String>(); ArrayList<String> artist=new ArrayList<String>(); ListView lv; Object[] webImgListObject; String[] stringArray; XMLRPCClient client; String loginsess; HashMap<?, ?> siteConn = null; //ImageView im; Bitmap img; String s; int d; int j; StreamingMediaPlayer sm; int start=0; Intent i; @Override protected void onCreate(Bundle savedInstanceState) { // TODO Auto-generated method stub super.onCreate(savedInstanceState); setContentView(R.layout.openadiuofile); lv=(ListView)findViewById(R.id.list1); al=getIntent().getStringArrayListExtra("titles"); //node=getIntent().getStringArrayListExtra("nodeid"); filepath=getIntent().getStringArrayListExtra("apath"); imgal=getIntent().getStringArrayListExtra("imgpath"); album=getIntent().getStringArrayListExtra("album"); artist=getIntent().getStringArrayListExtra("artist"); // ArrayAdapter<String> aa=new ArrayAdapter<String>(this,R.layout.row,R.id.text2,al); //lv.setAdapter(aa); try{ lv.setAdapter( new styleadapter(this,R.layout.row, R.id.text2,al)); }catch(Throwable e) { Log.e("openaudio error",""+e.toString()); goBlooey(e); } lv.setOnItemClickListener(new OnItemClickListener(){ @Override public void onItemClick(AdapterView<?> arg0, View arg1, int arg2, long arg3){ j=1; try{ d=arg2; String filep=filepath.get(d); String tit=al.get(d); String image=imgal.get(d); String singer=artist.get(d); String movie=album.get(d); sendpath(filep,tit,image,singer,movie); // getpath(n); }catch(Throwable t) { goBlooey(t); } } }); } @Override protected void onPause() { // TODO Auto-generated method stub super.onPause(); if(j==0) {i=new Intent(this,gorinkadashboard.class); startActivity(i);} } @Override protected void onResume() { // TODO Auto-generated method stub super.onResume(); j=0; } @Override public boolean onKeyDown(int keyCode, KeyEvent event) { if (keyCode==KeyEvent.KEYCODE_SEARCH) { Log.i("go","go"); return true; } return(super.onKeyDown(keyCode, event)); } public void sendpath(String n,String nn,String image,String singer,String movie) { Intent ii=new Intent(this,MusicPlayerActivity.class); ii.putExtra("path",n); ii.putExtra("titletxt",nn); //ii.putStringArrayListExtra("playpath",filepath); ii.putExtra("pos",d); ii.putExtra("image",image); ii.putStringArrayListExtra("imagepath",imgal); ii.putStringArrayListExtra("filepath", filepath); ii.putStringArrayListExtra("imgal", imgal); ii.putExtra("movie" ,movie ); ii.putExtra("singer",singer); ii.putStringArrayListExtra("album", album); ii.putStringArrayListExtra("artist",artist); ii.putStringArrayListExtra("tittlearray",al); startActivity(ii); } class styleadapter extends ArrayAdapter<String> { Context context=null; public styleadapter(Context context, int resource, int textViewResourceId, List<String> objects) { super(context, resource, textViewResourceId, objects); this.context=context; } @Override public View getView(int position, View convertView, ViewGroup parent) { final int i=position; LayoutInflater inflater = ((Activity) context).getLayoutInflater(); View v = inflater.inflate(R.layout.row, null); tv=(TextView)v.findViewById(R.id.text2); albumtext=(TextView)v.findViewById(R.id.text3); artisttext=(TextView)v.findViewById(R.id.text1); tv.setText(al.get(i)); albumtext.setText(album.get(i)); artisttext.setText(artist.get(i)); final ImageView im=(ImageView)v.findViewById(R.id.image); s="http://www.gorinka.com/"+imgal.get(i); // displyimg(s,v); // new imageloader(s,im); String imgPath=s; AsyncImageLoaderv asyncImageLoaderv=new AsyncImageLoaderv(); Bitmap cachedImage = asyncImageLoaderv.loadDrawable(imgPath, new AsyncImageLoaderv.ImageCallback() { public void imageLoaded(Bitmap imageDrawable, String imageUrl) { im.setImageBitmap(imageDrawable); } }); im.setImageBitmap(cachedImage); return v; } } public class imageloader implements Runnable{ private String ss; //private View v; //private View v2; private ImageView im; public imageloader(String s, ImageView im) { this.ss=s; //this.v2=v2; this.im=im; Thread thread = new Thread(this); thread.start(); } public void run(){ try { // URL url = new URL(ss); // URLConnection conn = url.openConnection(); // conn.connect(); HttpGet httpRequest = null; httpRequest = new HttpGet(ss); HttpClient httpclient = new DefaultHttpClient(); HttpResponse response = (HttpResponse) httpclient.execute(httpRequest); HttpEntity entity = response.getEntity(); BufferedHttpEntity bufHttpEntity = new BufferedHttpEntity(entity); InputStream is = bufHttpEntity.getContent(); // BufferedInputStream bis = new BufferedInputStream(is); Bitmap bm = BitmapFactory.decodeStream(is); Log.d("img","img"); // bis.close(); is.close(); im.setImageBitmap(bm); // im.forceLayout(); // v2.postInvalidate(); // v2.requestLayout(); } catch (Exception t) { Log.e("bitmap url", "Exception in updateStatus()", t); //goBlooey(t); // throw new RuntimeException(t); } } } private void goBlooey(Throwable t) { AlertDialog.Builder builder=new AlertDialog.Builder(this); builder .setTitle("Exception!") .setMessage(t.toString()) .setPositiveButton("OK", null) .show(); } } I have created the SongList.java, SongsAdapter.java and also SongsAdapterView.java. Their code is... public class SongsList { private String titleName; private String movieName; private String singerName; private String imagePath; private String mediaPath; // Constructor for the SongsList class public SongsList(String titleName, String movieName, String singerName,String imagePath,String mediaPath ) { super(); this.titleName = titleName; this.movieName = movieName; this.singerName = singerName; this.imagePath = imagePath; this.mediaPath = mediaPath; } public String gettitleName() { return titleName; } public void settitleName(String titleName) { this.titleName = titleName; } public String getmovieName() { return movieName; } public void setmovieName(String movieName) { this.movieName = movieName; } public String getsingerName() { return singerName; } public void setsingerName(String singerName) { this.singerName = singerName; } public String getimagePath() { return imagePath; } public void setimagePath(String imagePath) { this.imagePath = imagePath; } public String getmediaPath() { return mediaPath; } public void setmediaPath(String mediaPath) { this.mediaPath = mediaPath; } } public class SongsAdapter extends BaseAdapter{ private Context context; private List<SongsList> listSongs; public SongsAdapter(Context context, List<SongsList> listPhonebook){ this.context = context; this.listSongs = listSongs; } public int getCount() { return listSongs.size(); } public Object getItem(int position) { return listSongs.get(position); } public long getItemId(int position) { return position; } public View getView(int position, View view, ViewGroup viewGroup) { SongsList entry = listSongs.get(position); return new SongsAdapterView(context,entry); } } public SongsAdapterView(Context context, SongsList entry) { super(context); this.setOrientation(VERTICAL); this.setTag(entry); // TODO Auto-generated constructor stub View v = inflate(context, R.layout.row, null); TextView tvTitle = (TextView)v.findViewById(R.id.text2); tvTitle.setText(entry.gettitleName()); TextView tvMovie = (TextView)v.findViewById(R.id.text3); tvTitle.setText(entry.getmovieName()); TextView tvSinger = (TextView)v.findViewById(R.id.text1); tvTitle.setText(entry.getsingerName()); addView(v); } } Can anyone please tell me how to display the list using custom lists and custom adapters using the code above???

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  • Actionscript 3 and nested lists

    - by Hanpan
    Hi, I have the following code in my XML (EDIT:) which I am trying to show in a RichText using htmlText. <ul> <li>List Item 1 <ul> <li>List Item 2</li> </ul> </li> </ul> Unfortunately, Flash doesn't seem to support nested lists, and I am getting output which looks like this: List item 1 List item 2 Where I want the second ul to be indented further. Any ideas would be much appreciated! Cheers

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  • Python 3: unpack inner lists in list comprehension

    - by Beau Martínez
    I'm running the following code on a list of strings to return a list of its words: words = [re.split('\\s+', line) for line in lines] However, I end up getting something like: [['import', 're', ''], ['', ''], ['def', 'word_count(filename):', ''], ...] As opposed to the desired: ['import', 're', '', '', '', 'def', 'word_count(filename):', '', ...] How can I unpack the lists re.split('\\s+', line) produces in the above list comprehension? Naïvely, I tried using * but that doesn't work. (I'm looking for a simple and Pythonic way of doing; I was tempted to write a function but I'm sure the language accommodates for this issue.)

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  • python: how to convert list of lists into a single nested list

    - by Bhuski
    I have a python list of lists as shown below: mylist=[ [['orphan1', ['some value1']]], [['parent1', ['child1', ['child', ['some value2']]]]], [['parent1', ['child2', ['child', ['some value3']]]]] ] I need to convert the above list to some thing like this: result=[ ['orphan1', ['some value1']], ['parent1', ['child1', ['child', ['some value2']]], ['child2', ['child', ['some value3']]]] ] Kindly help me approach this problem. I have given only simple list. In actual scenario here, in my list, even grand parents/grand childs are there. How much ever deep the input nested list is, I need to convert it to a single nested list, with common list elements (parents and grand parents) appearing only once. (but the next to innermost list element('child' in above example) should appear as many times it occurs in the input list. I have been trying to do this last two days, but did not end up with working solution :(. I need to use the output in django template filter: unordered_list so that the resultant nested list appears as a nested unordered list in my html page ..

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  • JQuery - Ajax saving sortables in connected lists when sortable item is moved

    - by Ben Sinclair
    I have multiple JQuery sortable lists that connect with each other... They allow you to assign users to certain roles. Basically what I want to do is when a user is dragged from one list to another, I want JQuery to pick up the first list that the user was moved from so that I can send an AJAX request to delete it from that list in my database. I tried the following but every time you move the user over a list and haven't even dropped it within a list, it sends this request which means I'll be sending multiple AJAX requests... Does that make sense? $( ".selector" ).sortable({ out: function(event, ui) { ... } }); From my testing, I can use the following code to just update the list that user has been moved to so I've got the second half covered: $( ".selector" ).sortable({ receive: function(event, ui) { ... } }); Hopefully I am making sense :)

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  • Using ObjectBindingDatasource to bind to object exposing Lists, cant drag and drop fields onto repor

    - by SKM
    Hey Guys Ive used the ObjectBindingDatasource to bind to a class Ive called "ReportViewModel" which contains properties such as List Companies {get; set;} List Managers {get; set;} in its constructor Im just calling a method to populate with dummy data Managers = new ReportDataRepository().GetManagers(); Companies = new ReportDataReposiroty().GetCompanies(); ... When i create the new Datasource , it shows the ReportViewModel class with the Lists under it. I expand the Companies object and attempt draging and dropping fields onto the report designer and it works. Though doesnt allow me to drag and drop for any other List. Any guidance would be really appreciated.

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  • Objective C -- property lists or text files?

    - by William Jockusch
    I need to import a list of about 40,000 words into my Iphone app. The list will be the same every time the app starts. It seems that property lists and text files are reasonable options. Any reason to prefer one over the other? For reasons I don't understand, finder says the property list on my mac is 1MB, while the text file is only 328K. The property list is an NSMutableArray of NSMutableArrays of NSStrings. The text file is a plain txt file. But amount of time the app takes to start up is also important. If I read in a text file, my app would have to do some simple processing on it each time it starts. Thanks.

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  • Using Large Lists

    - by cam
    In an Outlook AddIn I'm working on, I use a list to grab all the messages in the current folder, then process them, then save them. First, I create a list of all messages, then I create another list from the list of messages, then finally I create a third list of messages that need to be moved. Essentially, they are all copies of eachother, and I made it this way to organize it. Would it increase performance if I used only one list? I thought lists were just references to the actual item.

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  • Turn a collection of headings, paragraphs and lists into one hyperlink

    - by Moak
    Is there a valid non js way to turn a collection of headings, paragraphs and lists into one url? (like in advertisements?) <a href="http://www.example.com" class="allclickable"> <h2>Fresh Bread</h2> <p>Delivered to your door</p> <ul> <li>Daily</li> <li>Fresh</li> <li>Bread</li> </ul> </a> This does not validate and I do want the href to be display as block element (so also the space around the text is clickable). Cheers

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  • Python sys.argv lists and indexes

    - by Fred Gerbig
    In the below code I understand that sys.argv uses lists, however I am not clear on how the index's are used here. def main(): if len(sys.argv) >= 2: name = sys.argv[1] else: name = 'World' print 'Hello', name if __name__ == '__main__': main() If I change name = sys.argv[1] to name = sys.argv[0] and type something for an argument it returns: Hello C:\Documents and Settings\fred\My Documents\Downloads\google-python-exercises \google-python-exercises\hello.py Which kind of make sense. Can someone explain how the 2 is used here: if len(sys.argv) >= 2: And how the 1 is used here: name = sys.argv[1]

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  • Algorithm - combine multiple lists, resulting in unique list and retaining order

    - by hitch
    I want to combine multiple lists of items into a single list, retaining the overall order requirements. i.e.: 1: A C E 2: D E 3: B A D result: B A C D E above, starting with list 1, we have ACE, we then know that D must come before E, and from list 3, we know that B must come before A, and D must come after B and A. If there are conflicting orderings, the first ordering should be used. i.e. 1: A C E 2: B D E 3: F D result: A C B D E F 3 conflicts with 2, therefore requirements for 2 will be used. If ordering requirements mean an item must come before or after another, it doesn't matter if it comes immediately before or after, or at the start or end of the list, as long as overall ordering is maintained. This is being developed using VB.Net, so a LINQy solution (or any .Net solution) would be nice - otherwise pointers for an approach would be good.

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  • Comparing two collection lists

    - by Eric
    I've been at this for few hors now and can't seem to find a solution. I have 2 invnetory lists, one a spreadsheet and the other data table. I need to match the spreadsheet agains the data table to find out if I have missing inventory. The spreadsheet should match with what I have in the db, ie the spreadsheet is like a master so when I have missing inventory in DB I need to add it an list and build a report. I thought by looping throught the spreadsheet and for each inventory in the spreadsheet loop through the data table I can achieve my goal but that proved to be wrong. Any ideas how I would do this? Thanks, Eric

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  • Splitting lists inside list haskell

    - by user3713267
    Hi I need to split list by an argument in Haskell. I found function like this group :: Int -> [a] -> [[a]] group _ [] = [] group n l | n > 0 = (take n l) : (group n (drop n l)) | otherwise = error "Negative n" But what if lists that I want to divide are contained by another list? For example group 3 [[1,2,3,4,5,6],[2,4,6,8,10,12]] should return [[[1,2,3],[4,5,6]],[[2,4,6],[8,10,12]]] Is there any way to do that ?

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  • Transform Two Lists into One Different List

    - by Ngu Soon Hui
    I have two lists of double List<double> X List<double> Y And I have a destination object: public class PointD { public double X {get;set;} public double Y {get;set;} } How to transform them into a single list? public static List<PointD> Transform(List<double> X, List<double> Y) { } All the errors checking must be there.

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  • python conditional list creation from 2D lists

    - by dls
    Say I've got a list of lists. Say the inner list of three elements in size and looks like this: ['apple', 'fruit', 1.23] The outer list looks like this data = [['apple', 'fruit', 1.23], ['pear', 'fruit', 2.34], ['lettuce', 'vegetable', 3.45]] I want to iterate through the outer list and cull data for a temporary list only in the case that element 1 matches some keyword (aka: 'fruit'). So, if I'm matching fruit, I would end up with this: tempList = [('apple', 1.23), ('pear', 2.34)] This is one way to accomplish this: tempList = [] for i in data: if i[1] == 'fruit': tempList.append(i[0], i[2]) is there some 'Pythonic' way to do this in fewer lines?

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  • Find common nodes from two linked lists using recursion

    - by Dan
    I have to write a method that returns a linked list with all the nodes that are common to two linked lists using recursion, without loops. For example, first list is 2 - 5 - 7 - 10 second list is 2 - 4 - 8 - 10 the list that would be returned is 2 - 10 I am getting nowhere with this.. What I have been think of was to check each value of the first list with each value of the second list recursively but the second list would then be cut by one node everytime and I cannot compare the next value in the first list with the the second list. I hope this makes sense... Can anyone help?

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  • Filter across 2 lists using LINQ

    - by Ajit Goel
    I have two lists: a. requestedAmenities b. units with amenities. I want to filter those units that have any one of the "requested amenities". I have tried to achieve the same result using foreach loops but I believe it should be much easier using LINQ. Can someone please help\advice? UnitAmenities unitSearchRequestAmenities = unitSearchRequest.Amenities; var exactMatchApartmentsFilteredByAmenities= new Units(); IEnumerable<string> requestAmenitiesIds = unitSearchRequestAmenities.Select(element => element.ID); foreach (var unitCounter in ExactMatchApartments) { IEnumerable<string> unitAmenities = unitCounter.Amenities.Select(element => element.ID); foreach (var requestAmenityId in requestAmenitiesIds) { foreach (var unitAmenity in unitAmenities) { if (requestAmenityId == unitAmenity) { exactMatchApartmentsFilteredByAmenities.Add(unitCounter); //break to the outmost foreach loop } } } }

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  • Intersection of two lists in Bash

    - by User1
    I'm trying to write a simple script that will list the contents found in two lists. To simplify, let's use ls as an example. Imagine "one" and "two" are directories. one=`ls one` two=`ls two` intersection $one $two I'm still quite green in bash, so feel free to correct how I am doing this. I just need some command that will print out all files in "one" and "two". They must exist in both. You might call this the "intersection" between "one" and "two".

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