I'm writing a program to check to see if a port is open in C. One line in particular copies one of the arguments to a char array. However, when I try to compile, it says:
error: incompatible types in
assignment
Heres the code. The error is on the
assignment of addr
#include <sys/socket.h>
#include <sys/time.h>
#include <sys/types.h>
#include <arpa/inet.h>
#include <netinet/in.h>
#include <errno.h>
#include <fcntl.h>
#include <stdio.h>
#include <netdb.h>
#include <stdlib.h>
#include <string.h>
#include <unistd.h>
int main(int argc, char **argv) {
u_short port; /* user specified port number */
char addr[1023]; /* will be a copy of the address entered by u */
struct sockaddr_in address; /* the libc network address data structure */
short int sock = -1; /* file descriptor for the network socket */
port = atoi(argv[1]);
addr = strncpy(addr, argv[2], 1023);
bzero((char *)&address, sizeof(address)); /* init addr struct */
address.sin_addr.s_addr = inet_addr(addr); /* assign the address */
address.sin_port = htons(port); /* translate int2port num */
sock = socket(AF_INET, SOCK_STREAM, 0);
if (connect(sock,(struct sockaddr *)&address,sizeof(address)) == 0) {
printf("%i is open\n", port);
}
if (errno == 113) {
fprintf(stderr, "Port not open!\n");
}
close(sock);
return 0;
}
I'm new to C, so I'm not sure why it would do this.
