negative number - Page 131

best practice - loging events (general) and changes (database)

- by b0x0rz

need help with logging all activities on a site as well as database changes. requirements: * should be in database * should be easily searchable by initiator (user name / session id), event (activity type) and event parameters i can think of a database design but either it involves a lot of tables (one per event) so i can log each of the parameters of an event in a separate field OR it involves one table with generic fields (7 int numeric and 7 text types) and log everything in one table with event type field determining what parameter got written where (and hoping that i don't need more than 7 fields of a certain type, or 8 or 9 or whatever number i choose)... example of entries (the usual things): [username] login failed @datetime [username] login successful @datetime [username] changed password @datetime, estimated security of password [low/ok/high/perfect] @datetime [username] clicked result [result number] [result id] after searching for [search string] and got [number of results] @datetime [username] clicked result [result number] [result id] after searching for [search string] and got [number of results] @datetime [username] changed profile name from [old name] to [new name] @datetime [username] verified name with [credit card type] credit card @datetime datbase table [table name] purged of old entries @datetime etc... so anyone dealt with this before? any best practices / links you can share? i've seen it done with the generic solution mentioned above, but somehow that goes against what i learned from database design, but as you can see the sheer number of events that need to be trackable (each user will be able to see this info) is giving me headaches, BUT i do LOVE the one event per table solution more than the generic one. any thoughts? edit: also, is there maybe an authoritative list of such (likely) events somewhere? thnx stack overflow says: the question you're asking appears subjective and is likely to be closed. my answer: probably is subjective, but it is directly related to my issue i have with designing a database / writing my code, so i'd welcome any help. also i tried narrowing down the ideas to 2 so hopefully one of these will prevail, unless there already is an established solution for these kinds of things.

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help with mysql triggers (checking values before insert)

- by user332817

hi I'm quite new to mysql and I'm trying to figure out how to use triggers. what I'm trying to do: I have 2 tables, max and sub_max, when I insert a new row to sub_max I want to check if the SUM of the values with the same foreign_key as the new row are less than the value in the max table. I think this sounds confusing so here are my tables: CREATE TABLE max( number INT , MaxAmount integer NOT NULL) CREATE TABLE sub_max( sub_number INT , sub_MaxAmount integer NOT NULL, number INT, FOREIGN KEY ( number ) REFERENCES max( number )) and here is my code for the trigger, I know the syntax is off but this is the best I could do from looking up tutorials. CREATE TRIGGER maxallowed after insert on submax FOR EACH ROW BEGIN DECLARE submax integer; DECLARE maxmax integer; submax = select sum(sub_MaxAmount) from sub_max where sub_number = new.sub_number; submax = submax + new. sub_MaxAmount; maxmax = select MaxAmount from max where number = new.number ; if max>maxmax rollback? END I wanted to know if I'm doing this remotely correctly. Thanks in advance.

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Naive Bayesian classification (spam filtering) - Doubt in one calculation? Which one is right? Plz c

- by Microkernel

Hi guys, I am implementing Naive Bayesian classifier for spam filtering. I have doubt on some calculation. Please clarify me what to do. Here is my question. In this method, you have to calculate P(S|W) - Probability that Message is spam given word W occurs in it. P(W|S) - Probability that word W occurs in a spam message. P(W|H) - Probability that word W occurs in a Ham message. So to calculate P(W|S), should I do (1) (Number of times W occuring in spam)/(total number of times W occurs in all the messages) OR (2) (Number of times word W occurs in Spam)/(Total number of words in the spam message) So, to calculate P(W|S), should I do (1) or (2)? (I thought it to be (2), but I am not sure, so plz clarify me) I am refering http://en.wikipedia.org/wiki/Bayesian_spam_filtering for the info by the way. I got to complete the implementation by this weekend :( Thanks and regards, MicroKernel :) @sth: Hmm... Shouldn't repeated occurrence of word 'W' increase a message's spam score? In the your approach it wouldn't, right?. Lets take a scenario and discuss... Lets say, we have 100 training messages, out of which 50 are spam and 50 are Ham. and say word_count of each message = 100. And lets say, in spam messages word W occurs 5 times in each message and word W occurs 1 time in Ham message. So total number of times W occuring in all the spam message = 5*50 = 250 times. And total number of times W occuring in all Ham messages = 1*50 = 50 times. Total occurance of W in all of the training messages = (250+50) = 300 times. So, in this scenario, how do u calculate P(W|S) and P(W|H) ? Naturally we should expect, P(W|S) P(W|H)??? right. Please share your thought...

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Array: Recursive problem cracked me up

- by VaioIsBorn

An array of integers A[i] (i 1) is defined in the following way: an element A[k] ( k 1) is the smallest number greater than A[k-1] such that the sum of its digits is equal to the sum of the digits of the number 4* A[k-1] . You need to write a program that calculates the N th number in this array based on the given first element A[1] . INPUT: In one line of standard input there are two numbers seperated with a single space: A[1] (1 <= A[1] <= 100) and N (1 <= N <= 10000). OUTPUT: The standard output should only contain a single integer A[N] , the Nth number of the defined sequence. Input: 7 4 Output: 79 Explanation: Elements of the array are as follows: 7, 19, 49, 79... and the 4th element is solution. I tried solving this by coding a separate function that for a given number A[k] calculates the sum of it's digits and finds the smallest number greater than A[k-1] as it says in the problem, but with no success. The first testing failed because of a memory limit, the second testing failed because of a time limit, and now i don't have any possible idea how to solve this. One friend suggested recursion, but i don't know how to set that. Anyone who can help me in any way please write, also suggest some ideas about using recursion/DP for solving this problem. Thanks.

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Why can't decimal numbers be represented exactly in binary?

- by Barry Brown

There have been several questions posted to SO about floating-point representation. For example, the decimal number 0.1 doesn't have an exact binary representation, so it's dangerous to use the == operator to compare it to another floating-point number. I understand the principles behind floating-point representation. What I don't understand is why, from a mathematical perspective, are the numbers to the right of the decimal point any more "special" that the ones to the left? For example, the number 61.0 has an exact binary representation because the integral portion of any number is always exact. But the number 6.10 is not exact. All I did was move the decimal one place and suddenly I've gone from Exactopia to Inexactville. Mathematically, there should be no intrinsic difference between the two numbers -- they're just numbers. By contrast, if I move the decimal one place in the other direction to produce the number 610, I'm still in Exactopia. I can keep going in that direction (6100, 610000000, 610000000000000) and they're still exact, exact, exact. But as soon as the decimal crosses some threshold, the numbers are no longer exact. What's going on? Edit: to clarify, I want to stay away from discussion about industry-standard representations, such as IEEE, and stick with what I believe is the mathematically "pure" way. In base 10, the positional values are: ... 1000 100 10 1 1/10 1/100 ... In binary, they would be: ... 8 4 2 1 1/2 1/4 1/8 ... There are also no arbitrary limits placed on these numbers. The positions increase indefinitely to the left and to the right.

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C/C++ Control Structure Limitations?

- by STingRaySC

I have heard of a limitation in VC++ (not sure which version) on the number of nested if statements (somewhere in the ballpark of 300). The code was of the form: if (a) ... else if (b) ... else if (c) ... ... I was surprised to find out there is a limit to this sort of thing, and that the limit is so small. I'm not looking for comments about coding practice and why to avoid this sort of thing altogether. Here's a list of things that I'd imagine could have some limitation: Number of functions in a scope (global, class, or namespace). Number of expressions in a single statement (e.g., compound conditionals). Number of cases in a switch. Number of parameters to a function. Number of classes in a single hierarchy (either inheritance or containment). What other control structures/language features have limits such as this? Do the language standards say anything about these limits (perhaps minimum requirements for an implementation)? Has anyone run into a particular language limitation like this with a particular compiler/implementation? EDIT: Please note that the above form of if statements is indeed "nested." It is equivalent to: if (a) { //... } else { if (b) { //... } else { if (c) { //... } else { //... } } }

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How to properly translate the "var" result of a lambda expression to a concrete type?

- by CrimsonX

So I'm trying to learn more about lambda expressions. I read this question on stackoverflow, concurred with the chosen answer, and have attempted to implement the algorithm using a console app in C# using a simple LINQ expression. My question is: how do I translate the "var result" of the lambda expression into a usable object that I can then print the result? I would also appreciate an in-depth explanation of what is happening when I declare the outer => outer.Value.Frequency (I've read numerous explanations of lambda expressions but additional clarification would help) C# //Input : {5, 13, 6, 5, 13, 7, 8, 6, 5} //Output : {5, 5, 5, 13, 13, 6, 6, 7, 8} //The question is to arrange the numbers in the array in decreasing order of their frequency, preserving the order of their occurrence. //If there is a tie, like in this example between 13 and 6, then the number occurring first in the input array would come first in the output array. List<int> input = new List<int>(); input.Add(5); input.Add(13); input.Add(6); input.Add(5); input.Add(13); input.Add(7); input.Add(8); input.Add(6); input.Add(5); Dictionary<int, FrequencyAndValue> dictionary = new Dictionary<int, FrequencyAndValue>(); foreach (int number in input) { if (!dictionary.ContainsKey(number)) { dictionary.Add(number, new FrequencyAndValue(1, number) ); } else { dictionary[number].Frequency++; } } var result = dictionary.OrderByDescending(outer => outer.Value.Frequency); // How to translate the result into something I can print??

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Java ternary operator and boxing Integer/int?

- by Markus

I tripped across a really strange NullPointerException the other day caused by an unexpected type-cast in the ternary operator. Given this (useless exemplary) function: Integer getNumber() { return null; } I was expecting the following two code segments to be exactly identical after compilation: Integer number; if (condition) { number = getNumber(); } else { number = 0; } vs. Integer number = (condition) ? getNumber() : 0; . Turns out, if condition is true, the if-statement works fine, while the ternary opration in the second code segment throws a NullPointerException. It seems as though the ternary operation has decided to type-cast both choices to int before auto-boxing the result back into an Integer!?! In fact, if I explicitly cast the 0 to Integer, the exception goes away. In other words: Integer number = (condition) ? getNumber() : 0; is not the same as: Integer number = (condition) ? getNumber() : (Integer) 0; . So, it seems that there is a byte-code difference between the ternary operator and an equivalent if-else-statement (something I didn't expect). Which raises three questions: Why is there a difference? Is this a bug in the ternary implementation or is there a reason for the type cast? Given there is a difference, is the ternary operation more or less performant than an equivalent if-statement (I know, the difference can't be huge, but still)?

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Insert and delete SIM contacs working but it needs to be phone restart to update the changes

- by girishgm08

Hi All, I am able to insert the contacts into SIM card and delete from it. But it needs to be phone restart to update the changes. The below is the code woks for delete the conatcs, Uri simUri = Uri.parse("content://icc/adn"); Cursor cur = context.getContentResolver().query(simUri, null, null, null, null); prn("Number of SIM Contacts are.."+cur.getCount()); int row =0; while(cur.moveToNext()){ String name = cur.getString(cur.getColumnIndex("name")); prn("Name..."+name); String data = cur.getString(cur.getColumnIndex("number")); if(!data.equals("")) prn("Number.."+data); String where = null; if(!name.equals("") && !data.equals("")){ where = "tag =" + name + "AND" + "number =" +data; } else if(name.equals("") && !data.equals("")){ where = "number ="+data; } else { where = "tag ="+name+ "AND" +"number="+null; } context.getContentResolver().delete(simUri, where, null); row++; } prn(row+" are deleted"); cur.close(); cur = null; Please look into this issue and give suggestions on this. Thanks, Girish G M

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MySQL Paritioning performance

- by Imran Pathan

Measured performance on key partitioned tables and normal tables separately. But we couldn't find any performance improvement with partitioning. Queries are pruned. Using MySQL 5.1.47 on RHEL 4. Table details: UserUsage - Will have entries for user mobile number and data usage for each date. Mobile number and Date as PRI KEY. UserProfile - Queries prev table and stores summary for each mobile number. Mobile number PRI KEY. CREATE TABLE `UserUsage` ( `Msisdn` decimal(20,0) NOT NULL, `Date` date NOT NULL, . . PRIMARY KEY USING BTREE (`Msisdn`,`Date`) ) ENGINE=InnoDB DEFAULT CHARSET=latin1 PARTITION BY KEY(Msisdn) PARTITIONS 50; CREATE TABLE `UserProfile` ( `Msisdn` decimal(20,0) NOT NULL, . . PRIMARY KEY (`Msisdn`) ) ENGINE=InnoDB DEFAULT CHARSET=latin1 PARTITION BY KEY(Msisdn) PARTITIONS 50; Second table is updated by query select and order by date in first table in a perl program, query is select * from UserUsage where Msisdn=number order by Date desc limit 7 [Process data in perl] update UserProfile values(....) where Msisdn=number explain partition for select, shows row being scanned in a particular partition only. Is something wrong with partition design or queries as partitioning is taking almost same or more time compared to normal tables?

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Animate and form rows, arrays, AS3

- by VideoDnd

Question How can I animate and form rows together? Explanation One 'for loop' is for animation, the other 'for loop' is for making rows. I want to understand how to use arrays and create a row of sprite animations. 'for loop' for animation //FRAMES ARRAY //THIS SETS UP MY ANIMATION FOR TIMER EVENT var frames:Array = [ new Frame1(), new Frame2(), new Frame3(), new Frame4(), new Frame5(), new Frame6(), new Frame7(), new Frame8(), new Frame9(), new Frame0(), ]; for each (var frame:Sprite in frames) { addChild(frame); } 'for loop' for rows //THIS MAKES A ROW OF DISPLAY OBJECTS var numberOfClips:Number = 11; var xStart:Number = 0; var yStart:Number = 0; var xVal:Number = xStart; var xOffset:Number = 2; for (var $:Number=0; $<numberOfClips; $++) { //DUDE ARRAY var dude:Array = frames; dude.y = yStart +11; dude.x = xVal +55; xVal = dude.x + dude.width + this.xOffset; } timer var timer:Timer = new Timer(100); timer.addEventListener(TimerEvent.TIMER, countdown); function countdown(event:TimerEvent) { var currentFrame:int = timer.currentCount % frames.length; for (var i:int = 0; i < frames.length; ++i) { frames[i].visible = (i == currentFrame); } } timer.start(); counter experiment My new class I'm working on loops through 10 different display objects that are numbers. For those following, I'm trying to make something like NumbersView.

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Generating report with MySQL and Rails - how?

- by Arywista

Here is my data model from my application: id :integer(4) not null, primary key spam :boolean(1) not null duplicate :boolean(1) not null ignore :boolean(1) not null brand_id :integer(4) not null attitude :string not null posted_at :datetime not null Attitude could have 3 states: negative, positive, neutral. I want to generate resultset in table, this way, for each day between start and end date: date | total | positive | neutral | negative 2009-10-10 | 12 | 4 | 7 | 1 (...) 2009-10-30 | 5 | 2 | 1 | 1 And ignore all records which have: duplicate = true ignore = true spam = true How it's could be done?

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Knowing which annotation is selected and accessing properties of it.

- by kevin Mendoza

So far my program can display a database of custom annotation views. Eventually I want my program to be able to display extra information after a button on the annotation bubble is clicked. Each element in the database has a unique entry Number, so I thought it would be a good idea to add this entry number as a property of the custom annotation. The problem I am having is that after the button is clicked and the program switches to a new view I am unable to retrieve the entry number of the annotation I selected. Below is the code that assigns the entry Number property to the annotation: for (id mine in mines) { workingCoordinate.latitude = [[mine latitudeInitial] doubleValue]; workingCoordinate.longitude = [[mine longitudeInitial] doubleValue]; iProspectAnnotation *tempMine = [[iProspectAnnotation alloc] initWithCoordinate:workingCoordinate]; [tempMine setTitle:[mine mineName]]; [tempMine setAnnotationEntryNumber:[mine entryNumber]]; } [mines dealloc]; When the button on an annotation is selected, this is the code that initializes the new view: - (void)mapView:(MKMapView *)mapView annotationView:(MKAnnotationView *)view calloutAccessoryControlTapped:(UIControl *)control { mineInformationController *controller = [[mineInformationController alloc] initWithNibName:@"mineInformationController" bundle:nil]; controller.modalTransitionStyle = UIModalTransitionStyleCrossDissolve; [self presentModalViewController:controller animated:YES]; [controller release]; } and lastly is my attempt at retrieving the entryNumber property from the new view so that I can compare it to the mines database and retrieve more information on the array element. iProspectFresno_LiteAppDelegate *appDelegate = (iProspectFresno_LiteAppDelegate *)[[UIApplication sharedApplication] delegate]; NSMutableArray* mines = [[NSMutableArray alloc] initWithArray:(NSMutableArray *)appDelegate.mines]; for(id mine in mines) { if ([[mine entryNumber] isEqualToNumber: /*the entry Number of the selected annotation*/]) { /* display the information in the mine object */ } } So how do I access this entry number property in this new view controller?

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how do I get the program to Know which annotation is selected and be able to access properties of it

- by kevin Mendoza

So far my program can display a database of custom annotation views. Eventually I want my program to be able to display extra information after a button on the annotation bubble is clicked. Each element in the database has a unique entry Number, so I thought it would be a good idea to add this entry number as a property of the custom annotation. The problem I am having is that after the button is clicked and the program switches to a new view I am unable to retrieve the entry number of the annotation I selected. Below is the code that assigns the entry Number property to the annotation: for (id mine in mines) { workingCoordinate.latitude = [[mine latitudeInitial] doubleValue]; workingCoordinate.longitude = [[mine longitudeInitial] doubleValue]; iProspectAnnotation *tempMine = [[iProspectAnnotation alloc] initWithCoordinate:workingCoordinate]; [tempMine setTitle:[mine mineName]]; [tempMine setAnnotationEntryNumber:[mine entryNumber]]; } [mines dealloc]; When the button on an annotation is selected, this is the code that initializes the new view: - (void)mapView:(MKMapView *)mapView annotationView:(MKAnnotationView *)view calloutAccessoryControlTapped:(UIControl *)control { mineInformationController *controller = [[mineInformationController alloc] initWithNibName:@"mineInformationController" bundle:nil]; controller.modalTransitionStyle = UIModalTransitionStyleCrossDissolve; [self presentModalViewController:controller animated:YES]; [controller release]; } and lastly is my attempt at retrieving the entryNumber property from the new view so that I can compare it to the mines database and retrieve more information on the array element. iProspectFresno_LiteAppDelegate *appDelegate = (iProspectFresno_LiteAppDelegate *)[[UIApplication sharedApplication] delegate]; NSMutableArray* mines = [[NSMutableArray alloc] initWithArray:(NSMutableArray *)appDelegate.mines]; for(id mine in mines) { if ([[mine entryNumber] isEqualToNumber: /*the entry Number of the selected annotation*/]) { /* display the information in the mine object */ } } So how do I access this entry number property in this new view controller?

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How do I do a count on that meet a specific condition, dependent on several has_many relationships i

- by Angela

I have a Model Campaign. A Campaign has many Events. Each Event has an attribute :days. A Campaign also has_many Contacts. Each Contact as a :date_entered attribute. The from_today(contact,event) method returns a number, which is the number of days from the contact's :date_entered till today minus the event's :days. In other words, a positive number shows the number of days from today till the :days of the event is elapsed. If it is negative, if means that the number of days that has elapsed since the :date_entered is greater than the :days attribute of an event. In other words, the event is overdue. What I would like to be able to do is do campaign.overdue and this would result in a total number of contacts that have an overdue event. It shouldn't count multiple events for a single contact, just one contact. How do I do that? It seems like I would need to cycle through all the events for every contact and keep a counter but I'm assuming that there is a better way.

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How does retiming work in systolic arrays?

- by Andriyev

How does retiming work in systolic arrays (used in signal processors)? I read that there is some notion of negative delay which is used, but how can a delay be negative and if that is just an abstraction then how does it help?

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How to detect a sign change for elements in a numpy array

- by cb160

I have a numpy array with positive and negative values in. a = array([1,1,-1,-2,-3,4,5]) I want to create another array which contains a value at each index where a sign change occurs (For example, if the current element is positive and the previous element is negative and vice versa). For the array above, I would expect to get the following result array([0,0,1,0,0,1,0]) Alternatively, a list of the positions in the array where the sign changes occur or list of booleans instead of 0's and 1's is fine.

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PHP's page generation time takes 0.01s. 1/0.01 = 100; however i'm having problems reaching that number of request per seconds. Why?

- by cedivad

On average, my PHP page generation time is 10ms. So i should be able to execute 100 requests one after the other one (using a single core on the server, since that php is not multithreaded). However, i'm having problems reaching 50 pages per seconds. As of now i do 25 on avg., with a medium load. The application is really light, it consist in a read (<5KB) from a pool of SSDs, some read queries solved by indexes. Where should i look to solve this bottleneck?

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What is a more "ruby way" to write this code?

- by steadfastbuck

This was a homework assignment for my students (I am a teaching assistant) in c and I am trying to learn Ruby, so I thought I would code it up. The goal is to read integers from a redirected file and print some simple information. The first line in the file is the number of elements, and then each integer resides on its own line. This code works (although perhaps inefficiently), but how can I make the code more Ruby-like? #!/usr/bin/ruby -w # first line is number of inputs (Don't need it) num_inputs = STDIN.gets.to_i # read inputs as ints h = Hash.new STDIN.each do |n| n = n.to_i h[n] = 1 unless h[n] and h[n] += 1 end # find smallest mode h.sort.each do |k,v| break puts "Mode is: #{k}", "\n" if v == h.values.max end # mode unique? v = h.values.sort print "Mode is unique: " puts v.pop == v.pop, "\n" # print number of singleton odds, # odd elems repeated odd number times in desc order # even singletons in desc order odd_once = 0 odd = Array.new even = Array.new h.each_pair do |k, v| odd_once += 1 if v == 1 and k.odd? odd << k if v.odd? even << k if v == 1 and k.even? end puts "Number of elements with an odd value that appear only once: #{odd_once}", "\n" puts "Elements repeated an odd number of times:" puts odd.sort.reverse, "\n" puts "Elements with an even value that appear exactly once:" puts even.sort.reverse, "\n" # print fib numbers in the hash class Fixnum def is_fib? l, h = 0, 1 while h <= self return true if h == self l, h = h, l+h end end end puts "Fibonacci numbers:" h.keys.sort.each do |n| puts n if n.is_fib? end

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dividing two array elements

- by pradeep

main() { int prime_array[2339],prime1_count=0,mul1_count=0; int i, prime, lim_up, lim_low, n,j=0; int mul,count=0; int mul_count[65026]={0},number[7096]; printf("\n ENTER THE LOWER LIMIT…: "); scanf("%d", &lim_low); printf("\n ENTER THE UPPER LIMIT…: "); scanf("%d", &lim_up); for(n=lim_low+1; n<lim_up; n++) { prime = 1; for(i=2; i<n; i++) if(n%i == 0) { prime = 0; break; } if(prime) { prime_array[j]=n; j++; } } for(i=1;i<=255;i++) { for(j=1;j<=255;j++) { mul = j*i; mul_count[mul]++; } } for(i=1;i<=65025;i++) if( mul_count[i]!=2 && mul_count[i]!=0 ) { number[count]=i; count++; } for(prime1_count=0;prime1_count<2339;prime1_count++) { printf("\nprime number used is:%d",prime_array[prime1_count]); for(mul1_count=0;mul1_count<7096;mul1_count++) { printf("\n%d\t",number[mul1_count] % prime_array[prime1_count]); } } } I want to find the modulus of (number[mul1_count] % prime_array[prime1_count] ), but the output which I get is wrong. What is the mistake here. The prime number should be in the range 40000 to 65025. What changes should i make here?

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How to account for non-prime numbers 0 and 1 in java?

- by shady

I'm not sure if this is the right place to be asking this, but I've been searching for a solution for this on my own for quite some time, so hopefully I've come to the right place. When calculating prime numbers, the starting number that each number has to be divisible by is 2 to be a non-prime number. In my java program, I want to include all the non-prime numbers in the range from 0 to a certain number, so how do I include 0 and 1? Should I just have separate if and else-if statements for 0 and 1 that state that they are not prime numbers? I think that maybe 0 and 1 should be included in the java for loop, but I don't know how to go about doing that. for (int i = 2; i < num; i++){ if (num % i == 0){ System.out.println(i + " is not a prime number. "); } else{ System.out.println(i + " is a prime number. "); } }

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selected option not clearing from memory android

- by user2980560

I have a small random number spinner that when you click gives a random number. I am having two problems. The first is when the main activity loads it displays a random number on the screen without the random number spinner being clicked. I am unsure what to set to false to keep it from opening with the main activity. The second problem is that when you select an option from the spinner it does not clear. Meaning that If you click on option D6 or D20 then you can not click on the same option again until selecting the other option first. Essentially the selection does not clear out of memory after the random number is selected. Here is the random number code public void onItemSelected(AdapterView<?> parent, View view, int pos, long id) { Random rand = new Random(); int roll; // An item was selected. if (spinner1.getSelectedItemPosition()==0) { roll = rand.nextInt(6)+1; } else { roll = rand.nextInt(20)+1; } // Put the result into a string. String text = "You rolled a " + roll; // Build a dialog box and with the result string and a single button AlertDialog.Builder builder = new AlertDialog.Builder(this); builder.setMessage(text).setCancelable(false) .setPositiveButton("OK", new DialogInterface.OnClickListener() { public void onClick(DialogInterface dialog, int id) { // do things when the user clicks ok. } }); AlertDialog alert = builder.create(); // Show the dialog box. alert.show(); }

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Know more about Cache Buffer Handle

- by Liu Maclean(???)

??????«latch free:cache buffer handles???SQL????»?????cache buffer handle latch?????,?????????: “?????pin?buffer header???????buffer handle,??buffer handle?????????cache buffer handles?,??????cache buffer handles??????,???????cache???buffer handles,?????(reserved set)?????????????_db_handles_cached(???5)???,?????????????????SQL??????????????????????,????pin??????,????????handle,?????????5?cached buffer handles???handle????????????????,Oracle?????????????????pin?”????“?buffer,????????????????handle???db_block_buffers/processes,????_cursor_db_buffers_pinned???????cache buffer handles?????,??????,????????????SQL,????cache?buffer handles?????????,??????????????,???????????/?????” ????T.ASKMACLEAN.COM????,??????cache Buffer handle?????: cache buffer handle ??: ------------------------------ | Buffer state object | ------------------------------ | Place to hang the buffer | ------------------------------ | Consistent Get? | ------------------------------ | Proc Owning SO | ------------------------------ | Flags(RIR) | ------------------------------ ???? cache buffer handle SO: 70000046fdfe530, type: 24, owner: 70000041b018630, flag: INIT/-/-/0×00(buffer) (CR) PR: 70000048e92d148 FLG: 0×500000lock rls: 0, class bit: 0kcbbfbp: [BH: 7000001c7f069b0, LINK: 70000046fdfe570]where: kdswh02: kdsgrp, why: 0BH (7000001c7f069b0) file#: 12 rdba: 0×03061612 (12/398866) class: 1 ba: 7000001c70ee000set: 75 blksize: 8192 bsi: 0 set-flg: 0 pwbcnt: 0dbwrid: 2 obj: 66209 objn: 48710 tsn: 6 afn: 12hash: [700000485f12138,700000485f12138] lru: [70000025af67790,700000132f69ee0]lru-flags: hot_bufferckptq: [NULL] fileq: [NULL] objq: [700000114f5dd10,70000028bf5d620]use: [70000046fdfe570,70000046fdfe570] wait: [NULL]st: SCURRENT md: SHR tch: 0flags: affinity_lockLRBA: [0x0.0.0] HSCN: [0xffff.ffffffff] HSUB: [65535]where: kdswh02: kdsgrp, why: 0 # Example:# (buffer) (CR) PR: 37290 FLG: 0# kcbbfbp : [BH: befd8, LINK: 7836c] (WAITING) Buffer handle (X$KCBBF) kernel cache, buffer buffer_handles Query x$kcbbf – lists all the buffer handles ???? _db_handles System-wide simultaneous buffer operations ,no of buffer handles_db_handles_cached Buffer handles cached each process , no of processes default 5_cursor_db_buffers_pinned additional number of buffers a cursor can pin at once_session_kept_cursor_pins Number of cursors pins to keep in a session When a buffer is pinned it is attached to buffer state object. ??? ???????? cache buffer handles latch ? buffer pin???: SESSION A : SQL> select * from v$version; BANNER ---------------------------------------------------------------- Oracle Database 10g Enterprise Edition Release 10.2.0.5.0 - 64bi PL/SQL Release 10.2.0.5.0 - Production CORE 10.2.0.5.0 Production TNS for Linux: Version 10.2.0.5.0 - Production NLSRTL Version 10.2.0.5.0 - Production SQL> create table test_cbc_handle(t1 int); Table created. SQL> insert into test_cbc_handle values(1); 1 row created. SQL> commit; Commit complete. SQL> select rowid from test_cbc_handle; ROWID ------------------ AAANO6AABAAAQZSAAA SQL> select * from test_cbc_handle where rowid='AAANO6AABAAAQZSAAA'; T1 ---------- 1 SQL> select addr,name from v$latch_parent where name='cache buffer handles'; ADDR NAME ---------------- -------------------------------------------------- 00000000600140A8 cache buffer handles SQL> select to_number('00000000600140A8','xxxxxxxxxxxxxxxxxxxx') from dual; TO_NUMBER('00000000600140A8','XXXXXXXXXXXXXXXXXXXX') ---------------------------------------------------- 1610694824 ??cache buffer handles????parent latch ??? child latch ???SESSION A hold ??????cache buffer handles parent latch ???? oradebug call kslgetl ??, kslgetl?oracle??get latch??? SQL> oradebug setmypid; Statement processed. SQL> oradebug call kslgetl 1610694824 1; Function returned 1 ?????SESSION B ???: SQL> select * from v$latchholder; PID SID LADDR NAME GETS ---------- ---------- ---------------- ---------------------------------------------------------------- ---------- 15 141 00000000600140A8 cache buffer handles 119 cache buffer handles latch ???session A hold??,????????acquire cache buffer handle latch SQL> select * from test_cbc_handle where rowid='AAANO6AABAAAQZSAAA'; T1 ---------- 1 ?????Server Process?????? read buffer, ????????"_db_handles_cached", ??process?cache 5? cache buffer handle ??"_db_handles_cached"=0,?process????5????cache buffer handle , ???? process ???pin buffer,???hold cache buffer handle latch??????cache buffer handle SQL> alter system set "_db_handles_cached"=0 scope=spfile; System altered. ????? shutdown immediate; startup; session A: SQL> oradebug setmypid; Statement processed. SQL> oradebug call kslgetl 1610694824 1; Function returned 1 session B: select * from test_cbc_handle where rowid='AAANO6AABAAAQZSAAA'; session B hang!! WHY? SQL> oradebug setmypid; Statement processed. SQL> oradebug dump systemstate 266; Statement processed. SO: 0x11b30b7b0, type: 2, owner: (nil), flag: INIT/-/-/0x00 (process) Oracle pid=22, calls cur/top: (nil)/0x11b453c38, flag: (0) - int error: 0, call error: 0, sess error: 0, txn error 0 (post info) last post received: 0 0 0 last post received-location: No post last process to post me: none last post sent: 0 0 0 last post sent-location: No post last process posted by me: none (latch info) wait_event=0 bits=8 holding (efd=4) 600140a8 cache buffer handles level=3 SO: 0x11b305810, type: 2, owner: (nil), flag: INIT/-/-/0x00 (process) Oracle pid=10, calls cur/top: 0x11b455ac0/0x11b450a58, flag: (0) - int error: 0, call error: 0, sess error: 0, txn error 0 (post info) last post received: 0 0 0 last post received-location: No post last process to post me: none last post sent: 0 0 0 last post sent-location: No post last process posted by me: none (latch info) wait_event=0 bits=2 Location from where call was made: kcbzgs: waiting for 600140a8 cache buffer handles level=3 FBD93353:000019F0 10 162 10005 1 KSL WAIT BEG [latch: cache buffer handles] 1610694824/0x600140a8 125/0x7d 0/0x0 FF936584:00002761 10 144 10005 1 KSL WAIT BEG [latch: cache buffer handles] 1610694824/0x600140a8 125/0x7d 0/0x0 PID=22 holding ??cache buffer handles latch PID=10 ?? cache buffer handles latch, ????"_db_handles_cached"=0 ?? process??????cache buffer handles ??systemstate???? kcbbfbp cache buffer handle??, ?? "_db_handles_cached"=0 ? cache buffer handles latch?hold ?? ????cache buffer handles latch , ??? buffer?pin?????????? session A exit session B: SQL> select * from v$latchholder; no rows selected SQL> insert into test_cbc_handle values(2); 1 row created. SQL> commit; Commit complete. SQL> SQL> select t1,rowid from test_cbc_handle; T1 ROWID ---------- ------------------ 1 AAANPAAABAAAQZSAAA 2 AAANPAAABAAAQZSAAB SQL> select spid,pid from v$process where addr = ( select paddr from v$session where sid=(select distinct sid from v$mystat)); SPID PID ------------ ---------- 19251 10 ? GDB ? SPID=19215 ?debug , ?? kcbrls ????breakpoint ??? ????release buffer [oracle@vrh8 ~]$ gdb $ORACLE_HOME/bin/oracle 19251 GNU gdb (GDB) Red Hat Enterprise Linux (7.0.1-37.el5) Copyright (C) 2009 Free Software Foundation, Inc. License GPLv3+: GNU GPL version 3 or later <http://gnu.org/licenses/gpl.html> This is free software: you are free to change and redistribute it. There is NO WARRANTY, to the extent permitted by law. Type "show copying" and "show warranty" for details. This GDB was configured as "x86_64-redhat-linux-gnu". For bug reporting instructions, please see: <http://www.gnu.org/software/gdb/bugs/>... Reading symbols from /s01/oracle/product/10.2.0.5/db_1/bin/oracle...(no debugging symbols found)...done. Attaching to program: /s01/oracle/product/10.2.0.5/db_1/bin/oracle, process 19251 Reading symbols from /s01/oracle/product/10.2.0.5/db_1/lib/libskgxp10.so...(no debugging symbols found)...done. Loaded symbols for /s01/oracle/product/10.2.0.5/db_1/lib/libskgxp10.so Reading symbols from /s01/oracle/product/10.2.0.5/db_1/lib/libhasgen10.so...(no debugging symbols found)...done. Loaded symbols for /s01/oracle/product/10.2.0.5/db_1/lib/libhasgen10.so Reading symbols from /s01/oracle/product/10.2.0.5/db_1/lib/libskgxn2.so...(no debugging symbols found)...done. Loaded symbols for /s01/oracle/product/10.2.0.5/db_1/lib/libskgxn2.so Reading symbols from /s01/oracle/product/10.2.0.5/db_1/lib/libocr10.so...(no debugging symbols found)...done. Loaded symbols for /s01/oracle/product/10.2.0.5/db_1/lib/libocr10.so Reading symbols from /s01/oracle/product/10.2.0.5/db_1/lib/libocrb10.so...(no debugging symbols found)...done. Loaded symbols for /s01/oracle/product/10.2.0.5/db_1/lib/libocrb10.so Reading symbols from /s01/oracle/product/10.2.0.5/db_1/lib/libocrutl10.so...(no debugging symbols found)...done. Loaded symbols for /s01/oracle/product/10.2.0.5/db_1/lib/libocrutl10.so Reading symbols from /s01/oracle/product/10.2.0.5/db_1/lib/libjox10.so...(no debugging symbols found)...done. Loaded symbols for /s01/oracle/product/10.2.0.5/db_1/lib/libjox10.so Reading symbols from /s01/oracle/product/10.2.0.5/db_1/lib/libclsra10.so...(no debugging symbols found)...done. Loaded symbols for /s01/oracle/product/10.2.0.5/db_1/lib/libclsra10.so Reading symbols from /s01/oracle/product/10.2.0.5/db_1/lib/libdbcfg10.so...(no debugging symbols found)...done. Loaded symbols for /s01/oracle/product/10.2.0.5/db_1/lib/libdbcfg10.so Reading symbols from /s01/oracle/product/10.2.0.5/db_1/lib/libnnz10.so...(no debugging symbols found)...done. Loaded symbols for /s01/oracle/product/10.2.0.5/db_1/lib/libnnz10.so Reading symbols from /usr/lib64/libaio.so.1...(no debugging symbols found)...done. Loaded symbols for /usr/lib64/libaio.so.1 Reading symbols from /lib64/libdl.so.2...(no debugging symbols found)...done. Loaded symbols for /lib64/libdl.so.2 Reading symbols from /lib64/libm.so.6...(no debugging symbols found)...done. Loaded symbols for /lib64/libm.so.6 Reading symbols from /lib64/libpthread.so.0...(no debugging symbols found)...done. [Thread debugging using libthread_db enabled] Loaded symbols for /lib64/libpthread.so.0 Reading symbols from /lib64/libnsl.so.1...(no debugging symbols found)...done. Loaded symbols for /lib64/libnsl.so.1 Reading symbols from /lib64/libc.so.6...(no debugging symbols found)...done. Loaded symbols for /lib64/libc.so.6 Reading symbols from /lib64/ld-linux-x86-64.so.2...(no debugging symbols found)...done. Loaded symbols for /lib64/ld-linux-x86-64.so.2 Reading symbols from /lib64/libnss_files.so.2...(no debugging symbols found)...done. Loaded symbols for /lib64/libnss_files.so.2 0x00000035c000d940 in __read_nocancel () from /lib64/libpthread.so.0 (gdb) break kcbrls Breakpoint 1 at 0x10e5d24 session B: select * from test_cbc_handle where rowid='AAANPAAABAAAQZSAAA'; select hang !! GDB (gdb) c Continuing. Breakpoint 1, 0x00000000010e5d24 in kcbrls () (gdb) bt #0 0x00000000010e5d24 in kcbrls () #1 0x0000000002e87d25 in qertbFetchByUserRowID () #2 0x00000000030c62b8 in opifch2 () #3 0x00000000032327f0 in kpoal8 () #4 0x00000000013b7c10 in opiodr () #5 0x0000000003c3c9da in ttcpip () #6 0x00000000013b3144 in opitsk () #7 0x00000000013b60ec in opiino () #8 0x00000000013b7c10 in opiodr () #9 0x00000000013a92f8 in opidrv () #10 0x0000000001fa3936 in sou2o () #11 0x000000000072d40b in opimai_real () #12 0x000000000072d35c in main () SQL> oradebug setmypid; Statement processed. SQL> oradebug dump systemstate 266; Statement processed. ?????? kcbbfbp buffer cache handle ? SO state object ? BH BUFFER HEADER link??? ---------------------------------------- SO: 0x11b452348, type: 3, owner: 0x11b305810, flag: INIT/-/-/0x00 (call) sess: cur 11b41bd18, rec 0, usr 11b41bd18; depth: 0 ---------------------------------------- SO: 0x1182dc750, type: 24, owner: 0x11b452348, flag: INIT/-/-/0x00 (buffer) (CR) PR: 0x11b305810 FLG: 0x108000 class bit: (nil) kcbbfbp: [BH: 0xf2fc69f8, LINK: 0x1182dc790] where: kdswh05: kdsgrp, why: 0 BH (0xf2fc69f8) file#: 1 rdba: 0x00410652 (1/67154) class: 1 ba: 0xf297c000 set: 3 blksize: 8192 bsi: 0 set-flg: 2 pwbcnt: 272 dbwrid: 0 obj: 54208 objn: 54202 tsn: 0 afn: 1 hash: [f2fc47f8,1181f3038] lru: [f2fc6b88,f2fc6968] obj-flags: object_ckpt_list ckptq: [1182ecf38,1182ecf38] fileq: [1182ecf58,1182ecf58] objq: [108712a28,108712a28] use: [1182dc790,1182dc790] wait: [NULL] st: XCURRENT md: SHR tch: 12 flags: buffer_dirty gotten_in_current_mode block_written_once redo_since_read LRBA: [0xc7.73b.0] HSCN: [0x0.1cbe52] HSUB: [1] Using State Objects ---------------------------------------- SO: 0x1182dc750, type: 24, owner: 0x11b452348, flag: INIT/-/-/0x00 (buffer) (CR) PR: 0x11b305810 FLG: 0x108000 class bit: (nil) kcbbfbp: [BH: 0xf2fc69f8, LINK: 0x1182dc790] where: kdswh05: kdsgrp, why: 0 buffer tsn: 0 rdba: 0x00410652 (1/67154) scn: 0x0000.001cbe52 seq: 0x01 flg: 0x02 tail: 0xbe520601 frmt: 0x02 chkval: 0x0000 type: 0x06=trans data tab 0, row 0, @0x1f9a tl: 6 fb: --H-FL-- lb: 0x0 cc: 1 col 0: [ 2] c1 02 tab 0, row 1, @0x1f94 tl: 6 fb: --H-FL-- lb: 0x2 cc: 1 col 0: [ 2] c1 15 end_of_block_dump (buffer) (CR) PR: 0x11b305810 FLG: 0x108000 st: XCURRENT md: SHR tch: 12 ? buffer header?status= XCURRENT mode=KCBMSHARE KCBMSHR current share ????? x$kcbbf ????? cache buffer handle SQL> select distinct KCBBPBH from x$kcbbf ; KCBBPBH ---------------- 00 00000000F2FC69F8 ==>0xf2fc69f8 SQL> select * from x$kcbbf where kcbbpbh='00000000F2FC69F8'; ADDR INDX INST_ID KCBBFSO_TYP KCBBFSO_FLG KCBBFSO_OWN ---------------- ---------- ---------- ----------- ----------- ---------------- KCBBFFLG KCBBFCR KCBBFCM KCBBFMBR KCBBPBH ---------- ---------- ---------- ---------------- ---------------- KCBBPBF X0KCBBPBH X0KCBBPBF X1KCBBPBH ---------------- ---------------- ---------------- ---------------- X1KCBBPBF KCBBFBH KCBBFWHR KCBBFWHY ---------------- ---------------- ---------- ---------- 00000001182DC750 748 1 24 1 000000011B452348 1081344 1 0 00 00000000F2FC69F8 00000001182DC750 00 00000001182DC750 00 00000001182DC7F8 00 583 0 SQL> desc x$kcbbf; Name Null? Type ----------------------------------------- -------- ---------------------------- ADDR RAW(8) INDX NUMBER INST_ID NUMBER KCBBFSO_TYP NUMBER KCBBFSO_FLG NUMBER KCBBFSO_OWN RAW(8) KCBBFFLG NUMBER KCBBFCR NUMBER KCBBFCM NUMBER KCBBFMBR RAW(8) KCBBPBH RAW(8) KCBBPBF RAW(8) X0KCBBPBH RAW(8) X0KCBBPBF RAW(8) X1KCBBPBH RAW(8) X1KCBBPBF RAW(8) KCBBFBH RAW(8) KCBBFWHR NUMBER KCBBFWHY NUMBER gdb ?? ?process??????kcbrls release buffer? ???cache buffer handle??? SQL> select distinct KCBBPBH from x$kcbbf ; KCBBPBH ---------------- 00

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SharePoint 2010 – SQL Server has an unsupported version 10.0.2531.0

- by Jeff Widmer

I am trying to perform a database attach upgrade to SharePoint Foundation 2010. At this point I am trying to attach the content database to a Web application by using Windows Powershell: Mount-SPContentDatabase -Name <DatabaseName> -DatabaseServer <ServerName> -WebApplication <URL> [-Updateuserexperience] I am following the directions from this TechNet article: Attach databases and upgrade to SharePoint Foundation 2010. When I go to mount the content database I am receiving this error: Mount-SPContentDatabase : Could not connect to [DATABASE_SERVER] using integrated security: SQL server at [DATABASE_SERVER] has an unsupported version 10.0.2531.0. Please refer to “http://go.microsoft.com/fwlink/?LinkId=165761” for information on the minimum required SQL Server versions and how to download them. At first this did not make sense because the default SharePoint Foundation 2010 website was running just fine. But then I realized that the default SharePoint Foundation site runs off of SQL Server Express and that I had just installed SQL Server Web Edition (since the database is greater than 4GB) and restored the database to this version of SQL Server. Checking the documentation link above I see that SharePoint Server 2010 requires a 64-bit edition of SQL Server with the minimum required SQL Server versions as follows: SQL Server 2008 Express Edition Service Pack 1, version number 10.0.2531 SQL Server 2005 Service Pack 3 cumulative update package 3, version number 9.00.4220.00 SQL Server 2008 Service Pack 1 cumulative update package 2, version number 10.00.2714.00 The version of SQL Server 2008 Web Edition with Service Pack 1 (the version I installed on this machine) is 10.0.2531.0. SELECT @@VERSION: Microsoft SQL Server 2008 (SP1) - 10.0.2531.0 (X64) Mar 29 2009 10:11:52 Copyright (c) 1988-2008 Microsoft Corporation Web Edition (64-bit) on Windows NT 6.1 <X64> (Build 7600: ) (VM) But I had to read the article several times since the minimum version number for SQL Server Express is 10.0.2531.0. At first I thought I was good with the version of SQL Server 2008 Web that I had installed, also 10.0.2531.0. But then I read further to see that there is a cumulative update (hotfix) for SQL Server 2008 SP1 (NOT the Express edition) that is required for SharePoint 2010 and will bump the version number to 10.0.2714.00. So the solution was to install the Cumulative update package 2 for SQL Server 2008 Service Pack 1 on my SQL Server 2008 Web Edition to allow SharePoint 2010 to work with SQL Server 2008 (other than the SQL Server 2008 Express version). SELECT @@VERSION (After installing Cumulative update package 2): Microsoft SQL Server 2008 (SP1) - 10.0.2714.0 (X64) May 14 2009 16:08:52 Copyright (c) 1988-2008 Microsoft Corporation Web Edition (64-bit) on Windows NT 6.1 <X64> (Build 7600: ) (VM)

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SQL SERVER – When are Statistics Updated – What triggers Statistics to Update

- by pinaldave

If you are an SQL Server Consultant/Trainer involved with Performance Tuning and Query Optimization, I am sure you have faced the following questions many times. When is statistics updated? What is the interval of Statistics update? What is the algorithm behind update statistics? These are the puzzling questions and more. I searched the Internet as well many official MS documents in order to find answers. All of them have provided almost similar algorithm. However, at many places, I have seen a bit of variation in algorithm as well. I have finally compiled the list of various algorithms and decided to share what was the most common “factor” in all of them. I would like to ask for your suggestions as whether following the details, when Statistics is updated, are accurate or not. I will update this blog post with accurate information after receiving your ideas. The answer I have found here is when statistics are expired and not when they are automatically updated. I need your help here to answer when they are updated. Permanent table If the table has no rows, statistics is updated when there is a single change in table. If the number of rows in a table is less than 500, statistics is updated for every 500 changes in table. If the number of rows in table is more than 500, statistics is updated for every 500+20% of rows changes in table. Temporary table If the table has no rows, statistics is updated when there is a single change in table. If the number of rows in table is less than 6, statistics is updated for every 6 changes in table. If the number of rows in table is less than 500, statistics is updated for every 500 changes in table. If the number of rows in table is more than 500, statistics is updated for every 500+20% of rows changes in table. Table variable There is no statistics for Table Variables. If you want to read further about statistics, I suggest that you read the white paper Statistics Used by the Query Optimizer in Microsoft SQL Server 2008. Let me know your opinions about statistics, as well as if there is any update in the above algorithm. Reference: Pinal Dave (http://blog.SQLAuthority.com) Filed under: Pinal Dave, Readers Question, SQL, SQL Authority, SQL Optimization, SQL Performance, SQL Query, SQL Server, SQL Tips and Tricks, T SQL, Technology Tagged: SQL Statistics

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