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  • Auto populate input based on file name with AngularJS

    - by LouieV
    I am playing around with AngularJS and have not been able to solve this problem. I have a view that has a form to upload a file to a node server. So far I have manage to do this using some directives and a service. I allow the user to send a custom name to the POST data if they desire. What I wan to accomplish is that when the user selects a file the filename models auto populates. My view looks like: <div> <input file-model="phpFile" type="file"> <input name="filename" type="text" ng-model="filename"> <button ng-click="send()">send</button> </div> file-model is my directive that allows the file to be assigned to a scope. myApp.directive('fileModel', ['$parse', function($parse) { return { restrict: 'A', link: function(scope, element, attrs) { var model = $parse.(attrs.fileModel); var modelSetter = model.assign; element.bind('change', function() { scope.$apply(function() { modelSetter(scope, element[0].files[0]); }); }); } }]); The service: myApp.service('fileUpload', ['$http', function($http){ this.uploadFileToUrl = function(file, uploadUrl, optionals) { var fd = new FormData(); fd.append('file', file); for (var key in file) { fd.append(key, file[key]); } for(var i = 0; i < optionals.length; i++){ fd.append(optionals[i].name, optionals[i].data); } }); }]); Here as you can see I pass the file, append its properties, and append any optional properties. In the controller is where I am having the troubles. I have tried $watch and using the file-model but I get the same error either way. myApp.controller('AddCtrl', function($scope, $location, PEberry, fileUpload){ //$scope.$watch(function() { // return $scope.phpFile; //},function(newValue, oldValue) { // $scope.filename = $scope.phpFile.name; //}, true); // if ($scope.phpFiles) { // $scope.filename = $scope.phpFiles.name; // } $scope.send = function() { var uploadUrl = "/files"; var file = $scope.phpFile; //var opts = [{ name: "uname", data: file.name }] fileUpload.uploadFileToUrl(file, uploadUrl); }; }); Thank you for your help!

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  • How do I turn an array of bytes back into a file and open it automatically with C#?

    - by Ace Grace
    Hi, I am writing some code to add file attachments into an application I am building. I have add & Remove working but I don't know where to start to implement open. I have an array of bytes (from a table field) and I don't know how to make it automatically open e.g. If I have an array of bytes which is a PDF, how do I get my app to automatically open Acrobat or whatever the currently assigned application for the extension is using C#?

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  • PHP mini-server download resulme-error! Resource id # 4

    - by snikolov
    <?php $httpsock = @socket_create_listen("9090"); if (!$httpsock) { print "Socket creation failed!\n"; exit; } while (1) { $client = socket_accept($httpsock); $input = trim(socket_read ($client, 4096)); $input = explode(" ", $input); $range = $input[12]; $input = $input[1]; $fileinfo = pathinfo($input); switch ($fileinfo['extension']) { default: $mime = "text/html"; } if ($input == "/") { $input = "index.html"; } $input = ".$input"; if (file_exists($input) && is_readable($input)) { echo "Serving $input\n"; $contents = file_get_contents($input); $output = "HTTP/1.0 200 OK\r\nServer: APatchyServer\r\nConnection: close\r\nContent-Type: $mime\r\n\r\n$contents"; } else { //$contents = "The file you requested doesn't exist. Sorry!"; //$output = "HTTP/1.0 404 OBJECT NOT FOUND\r\nServer: BabyHTTP\r\nConnection: close\r\nContent-Type: text/html\r\n\r\n$contents"; if(isset($range)) { list($a, $range) = explode("=",$range); str_replace($range, "-", $range); $size2 = $size-1; $new_length = $size-$range; $output = "HTTP/1.1 206 Partial Content\r\n"; $output .= "Content-Length: $new_length\r\n"; $output .= "Content-Range: bytes $range$size2/$size\r\n"; } else { $size2=$size-1; $output .= "Content-Length: $new_length\r\n"; } $chunksize = 1*(1024*1024); $bytes_send = 0; $file = "a.mp3"; $filesize = filesize($file); if ($file = fopen($file, 'r')) { if(isset($range)) $output = 'HTTP/1.0 200 OK\r\n'; $output .= "Content-type: application/octet-stream\r\n"; $output .= "Content-Length: $filesize\r\n"; $output .= 'Content-Disposition: attachment; filename="'.$file.'"\r\n'; $output .= "Accept-Ranges: bytes\r\n"; $output .= "Cache-Control: private\n\n"; fseek($file, $range); $download_rate = 1000; while(!feof($file) and (connection_status()==0)) { $var_stat = fread($file, round($download_rate *1024)); $output .= $var_stat;//echo($buffer); // is also possible flush(); sleep(1);//// decrease download speed } fclose($file); } /** $filename = "dada"; $file = fopen($filename, 'r'); $filesize = filesize($filename); $buffer = fread($file, $filesize); $send = array("Output"=>$buffer,"filesize"=>$filesize,"filename"=>$filename); $file = $send['filename']; */ //@ob_end_clean(); // $output .= "Content-Transfer-Encoding: binary"; //$output .= "Connection: Keep-Alive\r\n"; } socket_write($client, $output); socket_close ($client); } socket_close ($httpsock); Hey guys, I haved create a miniwebserver downloader. It can download files from your server. However, I am unable to resume my download when I download the file – I get Resource id # 4 – and I also can't resume the download. I would like to know how I can monitor and record the client output and how much bandwidth he has downloaded. Perl has something like this, but it's hardcore; if possible, kindly provide me with some pointers thank you :)

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  • Ruby: output not saved to file

    - by Sophie
    I'm trying to give a file as input, have it changed within the program, and save the result to a file that is output. But the output file is the same as the input file. :/ Total n00b question, but what am I doing wrong?: puts "Reading Celsius temperature value from data file..." num = File.read("temperature.dat") celsius = num.to_i farenheit = (celsius * 9/5) + 32 puts "Saving result to output file 'faren_temp.out'" fh = File.new("faren_temp.out", "w") fh.puts farenheit fh.close

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  • JQuery Modal Boxes and Iframe

    - by Ólafur Waage
    I've been using Simple Modal and i feel it doesn't live up to what i need at the moment. Is there a Modal Box that supports loading external files and allows those external files to close the modal box and redirect the parent page to some url. An example of what i want to do. You have a list of users, you could click "Add user" and a Modal Box with the form pops up, you fill that in and submit it. That would close the box and reload the user list page so you would see the user in the list. Then you could click "Edit user" and a Modal Box with the user info filled in the form fields would pop up and you could edit, submit and it would close and refresh. I know this can be done if i have the user info form as a hidden div for each user but this will not scale well and it is a lot of overhead data. I found some code about this on Google Code but just can't get it to work (possibly different simple modal version I am willing to change to another modal box tool also. UPDATE: Do either Thickbox or Fancybox support being closed from a child IFrame element?

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  • Facebook Feed Dialog Returns API Error Code: 191

    - by Kris
    In my Facebook App I'll always get the following error : An error occurred. Please try again later. API Error Code: 191 API Error Description: The specified URL is not owned by the application Error Message: redirect_uri is not owned by the application. I just want to feed a post via button my code is function postToFeed() { // calling the API ... var obj = { method: 'feed', link: 'https://mydomain.com/', picture: 'https://mydomain.com/img/feed.png', name: 'BLABLADialog', caption: 'UeberschriftBLABLA', description: 'DescriptionBLABLA', show_error: true }; function callback(response) { document.getElementById('msg').innerHTML = "Post ID: " + response['post_id']; } FB.ui(obj, callback); } my Canvas-URL is "http://mydomain.com/" my Secure Canvas-URL is "https://mydomain.com/" my Tab-URL is "https://mydomain.com/tab.php" my Secure Tab-URL is "https://mydomain.com/tab.php" my Website with Facebook Login SITE URL is "https://mydomain.com/" so what I am doing wrong ?

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  • Usable mainmenu when sheet is shown

    - by neoneye
    How does one react to menuitems that are clicked via mouse or invoked via keyboard, e.g: CMD+Q ? [NSApp beginSheet:my_sheet ...arguments... ]; /* The sheet is now shown and the mainmenu isn't usable. How does one make it usable? */ [NSApp endSheet:my_sheet returnCode:0];

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  • Delphi - How to prevent Forms/MsgBoxes to move under prior form?

    - by durumdara
    Hi! Many times we experienced after Windows 98 era that some dialogs are lost their Z-Order, and moved back to prior form. For example: Dialog1.ShowModal; Dialog1.OnClickButton() : ShowMessage('anything'); When MessageBox appears, sometimes not got focus, it is moved under Dialog1. The users confused on it, because they are say: application freezed!!! But if they are uses AltTab to move another app and back, the focus return to the MessageBox, and it will be the foreground Window. We experienced this with ShowMessage, MessageBox, normal forms, QuickReport forms also. Is anyone knows about this? Is it Windows bug? How to prevent it? How to catch this? Thanks for your help: dd

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  • Spring Security 3.0- Customise basic http Authentication Dialog

    - by gav
    Rather than reading; A user name and password are being requested by http://localhost:8080. The site says: "Spring Security Application" I want to change the prompt, or at least change what the "site says". Does anyone know how to do this via resources.xml? In my Grails App Spring configuration, my current version is as follows; <?xml version="1.0" encoding="UTF-8"?> <beans:beans xmlns="http://www.springframework.org/schema/security" xmlns:beans="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.0.xsd http://www.springframework.org/schema/security http://www.springframework.org/schema/security/spring-security-3.0.xsd"> <http auto-config="true" use-expressions="true"> <http-basic/> <intercept-url pattern="/**" access="isAuthenticated()" /> </http> <authentication-manager alias="authenticationManager"> <authentication-provider> <user-service> <user name="admin" password="admin" authorities="ROLE_ADMIN"/> </user-service> </authentication-provider> </authentication-manager> </beans:beans>

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  • Symfony and uploadify

    - by Thomas
    Hi! I want to use uploadify with Symfony 1.4, but so far I couldn't. Uploadify loads correctly, I choose my files, it says that the files were successfully uploaded, but the are nowhere. (I'm doing this on localhost) Is there anybody who met this problem before? Thanks, Tom $file = $request->getParameter('file'); $filename = sha1($file->getOriginalName()).$file->getExtension($file->getOriginalExtension()); $file->save(sfConfig::get('sf_upload_dir').'/'.$filename);

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  • Is there any Prototype Javascript function similar to Jquery Live to trace dynamic dom elements?

    - by Wbdvlpr
    Hi Event.observe(window,"load",function() { $$(".elem_classs").findAll(function(node){ return node.getAttribute('title'); }).each(function(node){ new Tooltip(node,node.title); node.removeAttribute("title"); }); }); Using above method, I can retrieve all elements having ".elem_class" and apply some javascript functions on them. But I have a modal/popup box which has some elements also having ".elem_class" and these dont get in the scope of findAll/each as they are loaded into the dom thru ajax. How do I apply the same to dynamically loaded elements as well? I am using Prototype Library. (I have used JQuery's Live function which keeps track of all future elements, but need to achieve something similar using Prototype) Thanks.

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  • Two Problems I'm having with UIButton and UIView.

    - by Andy
    Hi all, I haven't been programming on the iPhone for very long, but I'm picking it up slowly by googling problems I get. Unfortunately I haven't been able to find an answer for these. I have started a new View-based application in Xcode 3.2.2 and immediately added the following files: myUIView.m and myUIView.h, which are subclasses of UIView. In Interface Builder, I set the subclass of the default UIView to be myUIView. I made a button in the drawRect method. Problem one: The title of the button only appears AFTER I click the screen, why? Problem two: I want the button to produce the modalview - is this possible? The code is as follow: #import "myUIView.h" @implementation myUIView - (void)drawRect:(CGRect)rect { // Drawing code button = [UIButton buttonWithType:UIButtonTypeRoundedRect]; button.frame = CGRectMake(0,0,100,100); [button setTitle:@"butty" forState:UIControlStateNormal]; [button addTarget:self action:@selector(buttonPressed:) forControlEvents:UIControlEventTouchUpInside]; [self addSubview:button]; } -(void)buttonPressed:(id)sender{ NSLog(@"Button pressed"); //present modal view somehow..? } I can't see how to post attachments, but if anyone thinks it will help I can upload the source. Many thanks, Andy

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  • DialogBox in Win32 - Prevent multiple instance

    - by UK
    Hello all, I have a program which creates DialogBox window when user clicks the menu item from tray icon, case ID_OPTIONS: DialogBox ( GetModuleHandle ( NULL ), MAKEINTRESOURCE ( IDD_SETUP_DIALOG ), hWnd, reinterpret_cast<DLGPROC>(SetupDlgProc) ); return 0; But the problem here is everytime when users clicks item from tray , a new instance of the dialogbox appears. Is there anyway to prevent this multiple instance ? BTW, my SetupDlgProc looks like this, BOOL CALLBACK SetupDlgProc ( HWND hwnd, UINT Message, WPARAM wParam, LPARAM lParam ) { switch ( Message ) { case WM_INITDIALOG: ... } } Thanks for your help.

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  • java bubblesort with acm dialog

    - by qzar
    Hi, the program gives following exception: Exception in thread "main" java.lang.NullPointerException at myclasses.BubbleSort.run(BubbleSort.java:42) at acm.program.Program.runHook(Program.java:1519) at acm.program.Program.startRun(Program.java:1508) at acm.program.Program.start(Program.java:729) at myclasses.BubbleSort.main(BubbleSort.java:49) what is wrong? thank you very much! package myclasses; import acm.program.DialogProgram; public class BubbleSort extends DialogProgram { int[] array; public int[] getArray() { return array; } public void setArray(int[] array) { this.array = array; } void swap(int firstPos, int secondPos) { int temp = array[firstPos]; array[firstPos] = array[secondPos]; array[secondPos] = temp; } public void bubblesort() { int i, j, k; for (i = 1; i < array.length; i++) { j = i; k = array[i]; while (j > 0 && array[j - 1] > k) { array[j] = array[j - 1]; --j; } array[j] = k; } } public void run() { BubbleSort a = new BubbleSort(); a.setArray(new int[] {1, 3, 5, 7, 6, 2}); a.bubblesort(); StringBuffer sb = new StringBuffer(a.array.length * 2); for (int i = 0; i < getArray().length; i++) sb.append(getArray()[i]).append(" "); println(sb); } public static void main(String[] args) { new BubbleSort().start(args); } }

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  • Is there an "are you sure" for stored procedure execution? :)

    - by Swoosh
    I have a stored procedure which is doing a lot of delete. Hundreds of thousands of records. It is not going to be runnable from the application, but still, i am concerned, that one of my clients accidentally runs it (i had problems earlier due to their "curiosity") :D Yes. there are backups and stuff like that, but I was thinking .... not to scare them ... is there a way to ask the user "are you sure?" before executing it? :) thanks

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  • How to bring a modal to the front of the page using bootstrap?

    - by sharataka
    I am trying to implement a modal using bootstrap. When I click on the button the screen fades and the modal appears, but it appears behind the images in and is unreadable for the user. How do I bring the modal forward? <div class ="container-fluid"> <div class = "row-fluid"> <div class = "span2"> <!-- Modal --> <div class="modal hide fade" id="myModal"> <div class="modal-header"> <a class="close" data-dismiss="modal">×</a> <h3>Modal header</h3> </div> <div class="modal-body"> <p>One fine body…</p> </div> <div class="modal-footer"> <a href="#" class="btn">Close</a> <a href="#" class="btn btn-primary">Save changes</a> </div> </div> <a data-toggle="modal" href="#myModal" class="btn btn-primary">Launch demo modal</a> </div> <div class = "span8"> #a lot of images in this div </div> </div> </div>

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  • Uploading multiple files using Spring MVC 3.0.2 after HiddenHttpMethodFilter has been enabled

    - by Tiny
    I'm using Spring version 3.0.2. I need to upload multiple files using the multiple="multiple" attribute of a file browser such as, <input type="file" id="myFile" name="myFile" multiple="multiple"/> (and not using multiple file browsers something like the one stated by this answer, it indeed works I tried). Although no versions of Internet Explorer supports this approach unless an appropriate jQuery plugin/widget is used, I don't care about it right now (since most other browsers support this). This works fine with commons fileupload but in addition to using RequestMethod.POST and RequestMethod.GET methods, I also want to use other request methods supported and suggested by Spring like RequestMethod.PUT and RequestMethod.DELETE in their own appropriate places. For this to be so, I have configured Spring with HiddenHttpMethodFilter which goes fine as this question indicates. but it can upload only one file at a time even though multiple files in the file browser are chosen. In the Spring controller class, a method is mapped as follows. @RequestMapping(method={RequestMethod.POST}, value={"admin_side/Temp"}) public String onSubmit(@RequestParam("myFile") List<MultipartFile> files, @ModelAttribute("tempBean") TempBean tempBean, BindingResult error, Map model, HttpServletRequest request, HttpServletResponse response) throws IOException, FileUploadException { for(MultipartFile file:files) { System.out.println(file.getOriginalFilename()); } } Even with the request parameter @RequestParam("myFile") List<MultipartFile> files which is a List of type MultipartFile (it can always have only one file at a time). I could find a strategy which is likely to work with multiple files on this blog. I have gone through it carefully. The solution below the section SOLUTION 2 – USE THE RAW REQUEST says, If however the client insists on using the same form input name such as ‘files[]‘ or ‘files’ and then populating that name with multiple files then a small hack is necessary as follows. As noted above Spring 2.5 throws an exception if it detects the same form input name of type file more than once. CommonsFileUploadSupport – the class which throws that exception is not final and the method which throws that exception is protected so using the wonders of inheritance and subclassing one can simply fix/modify the logic a little bit as follows. The change I’ve made is literally one word representing one method invocation which enables us to have multiple files incoming under the same form input name. It attempts to override the method protected MultipartParsingResult parseFileItems(List fileItems, String encoding) {} of the abstract class CommonsFileUploadSupport by extending the class CommonsMultipartResolver such as, package multipartResolver; import java.io.UnsupportedEncodingException; import java.util.HashMap; import java.util.Iterator; import java.util.List; import java.util.Map; import javax.servlet.ServletContext; import org.apache.commons.fileupload.FileItem; import org.springframework.util.StringUtils; import org.springframework.web.multipart.MultipartException; import org.springframework.web.multipart.MultipartFile; import org.springframework.web.multipart.commons.CommonsMultipartFile; import org.springframework.web.multipart.commons.CommonsMultipartResolver; final public class MultiCommonsMultipartResolver extends CommonsMultipartResolver { public MultiCommonsMultipartResolver() { } public MultiCommonsMultipartResolver(ServletContext servletContext) { super(servletContext); } @Override @SuppressWarnings("unchecked") protected MultipartParsingResult parseFileItems(List fileItems, String encoding) { Map<String, MultipartFile> multipartFiles = new HashMap<String, MultipartFile>(); Map multipartParameters = new HashMap(); // Extract multipart files and multipart parameters. for (Iterator it = fileItems.iterator(); it.hasNext();) { FileItem fileItem = (FileItem) it.next(); if (fileItem.isFormField()) { String value = null; if (encoding != null) { try { value = fileItem.getString(encoding); } catch (UnsupportedEncodingException ex) { if (logger.isWarnEnabled()) { logger.warn("Could not decode multipart item '" + fileItem.getFieldName() + "' with encoding '" + encoding + "': using platform default"); } value = fileItem.getString(); } } else { value = fileItem.getString(); } String[] curParam = (String[]) multipartParameters.get(fileItem.getFieldName()); if (curParam == null) { // simple form field multipartParameters.put(fileItem.getFieldName(), new String[] { value }); } else { // array of simple form fields String[] newParam = StringUtils.addStringToArray(curParam, value); multipartParameters.put(fileItem.getFieldName(), newParam); } } else { // multipart file field CommonsMultipartFile file = new CommonsMultipartFile(fileItem); if (multipartFiles.put(fileItem.getName(), file) != null) { throw new MultipartException("Multiple files for field name [" + file.getName() + "] found - not supported by MultipartResolver"); } if (logger.isDebugEnabled()) { logger.debug("Found multipart file [" + file.getName() + "] of size " + file.getSize() + " bytes with original filename [" + file.getOriginalFilename() + "], stored " + file.getStorageDescription()); } } } return new MultipartParsingResult(multipartFiles, multipartParameters); } } What happens is that the last line in the method parseFileItems() (the return statement) i.e. return new MultipartParsingResult(multipartFiles, multipartParameters); causes a compile-time error because the first parameter multipartFiles is a type of Map implemented by HashMap but in reality, it requires a parameter of type MultiValueMap<String, MultipartFile> It is a constructor of a static class inside the abstract class CommonsFileUploadSupport, public abstract class CommonsFileUploadSupport { protected static class MultipartParsingResult { public MultipartParsingResult(MultiValueMap<String, MultipartFile> mpFiles, Map<String, String[]> mpParams) { } } } The reason might be - this solution is about the Spring version 2.5 and I'm using the Spring version 3.0.2 which might be inappropriate for this version. I however tried to replace the Map with MultiValueMap in various ways such as the one shown in the following segment of code, MultiValueMap<String, MultipartFile>mul=new LinkedMultiValueMap<String, MultipartFile>(); for(Entry<String, MultipartFile>entry:multipartFiles.entrySet()) { mul.add(entry.getKey(), entry.getValue()); } return new MultipartParsingResult(mul, multipartParameters); but no success. I'm not sure how to replace Map with MultiValueMap and even doing so could work either. After doing this, the browser shows the Http response, HTTP Status 400 - type Status report message description The request sent by the client was syntactically incorrect (). Apache Tomcat/6.0.26 I have tried to shorten the question as possible as I could and I haven't included unnecessary code. How could be made it possible to upload multiple files after Spring has been configured with HiddenHttpMethodFilter? That blog indicates that It is a long standing, high priority bug. If there is no solution regarding the version 3.0.2 (3 or higher) then I have to disable Spring support forever and continue to use commons-fileupolad as suggested by the third solution on that blog omitting the PUT, DELETE and other request methods forever. Just curiously waiting for a solution and/or suggestion. Very little changes to the code in the parseFileItems() method inside the class MultiCommonsMultipartResolver might make it to upload multiple files but I couldn't succeed in my attempts (again with the Spring version 3.0.2 (3 or higher)).

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