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  • Finding out the windows group by virtue of which a user is able to access a database in sql server?

    - by Raghu Dodda
    There is a SQL Server 2005 database with mixed-mode authentication. Among others, we have the following logins on the server: our-domain\developers-group-1, and our-domain\developers-group-2 which are AD groups. The our-domain\developer-group-2 is added to the sysadmin role on the server, by virture of which all domain users of that group can access any database as SQL Server implictly maps the sysadmin role to the dbo user in each database. There are two users our-domain\good-user and our-domain\bad-user The issue is the following: Both the good-user and the bad-user have the exact same AD group memberships. They are both members of our-domain\developers-group-1 and our-domain\developers-group-2. The good-user is able to access all the databases, and the bad-user is not. The bad-user is able to login, but he is unable access any databases. By the way, I am the good-user. How do I go about finding out why? Here's what I tried so far: When I do print current_user, I get dbo When I do print system_user, I get my-domain\good-user When I do select * from fn_my_permissions(NULL, 'SERVER'), I see permissions. But if do execute as user='my-domain\good-user'; select * from fn_my_permissions(NULL, 'SERVER'), I dont see any permisisons. And When I do, execute as user='my-domain\bad-user'; select * from fn_my_permissions(NULL, 'SERVER'), I dont see any permisisons. Also, I was wondering if there is a sql command that will tell me, "hey! the current database user is able to access this database because he is a member such-and-such ad-group, which is a login that is mapped to such-and-such user in this database".

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  • sort surname in alphabet from file to file JAVA

    - by user577939
    hello all. I need some help. I have wrote this code and dont now how to sort surnames in alphabet from my file to other file. import java.io.; import java.util.; class Asmuo { String pavarde; String vardas; long buvLaikas; int atv1; int atv2; int atv3; } class Irasas { Asmuo duom; Irasas kitas; } class Sarasas { private Irasas p; Sarasas() { p = null; } Irasas itrauktiElementa(String pv, String v, long laikas, int d0, int d1, int d2) { String pvrd, vrd; int data0; int data1; int data2; long lks; lks = laikas; pvrd = pv; vrd = v; data0 = d0; data1 = d1; data2 = d2; Irasas r = new Irasas(); r.duom = new Asmuo(); uzpildymasDuomenimis(r, pvrd, vrd, lks, d0, d1, d2); r.kitas = p; p = r; return r; } void uzpildymasDuomenimis(Irasas r, String pv, String v, long laik, int d0, int d1, int d2) { r.duom.pavarde = pv; r.duom.vardas = v; r.duom.atv1 = d0; r.duom.buvLaikas = laik; r.duom.atv2 = d1; r.duom.atv3 = d2; } void spausdinti() { Irasas d = p; int i = 0; try { FileWriter fstream = new FileWriter("rez.txt"); BufferedWriter rez = new BufferedWriter(fstream); while (d != null) { System.out.println(d.duom.pavarde + " " + d.duom.vardas + " " + d.duom.buvLaikas + " " + d.duom.atv1 + " " + d.duom.atv2 + " " + d.duom.atv3); rez.write(d.duom.pavarde + " " + d.duom.vardas + " " + d.duom.buvLaikas + " " + d.duom.atv1 + " " + d.duom.atv2 + " " + d.duom.atv3 + "\n"); d = d.kitas; i++; } rez.close(); } catch (Exception e) { System.err.println("Error: " + e.getMessage()); } } } public class Gyventojai { public static void main(String args[]) { Sarasas sar = new Sarasas(); Calendar atv = Calendar.getInstance(); Calendar isv = Calendar.getInstance(); try { FileInputStream fstream = new FileInputStream("duom.txt"); DataInputStream in = new DataInputStream(fstream); BufferedReader br = new BufferedReader(new InputStreamReader(in)); String eil; while ((eil = br.readLine()) != null) { String[] cells = eil.split(" "); String pvrd = cells[0]; String vrd = cells[1]; atv.set(Integer.parseInt(cells[2]), Integer.parseInt(cells[3]), Integer.parseInt(cells[4])); isv.set(Integer.parseInt(cells[5]), Integer.parseInt(cells[6]), Integer.parseInt(cells[7])); long laik = (isv.getTimeInMillis() - atv.getTimeInMillis()) / (24 * 60 * 60 * 1000); int d0 = Integer.parseInt(cells[2]); int d1 = Integer.parseInt(cells[3]); int d2 = Integer.parseInt(cells[4]); sar.itrauktiElementa(pvrd, vrd, laik, d0, d1, d2); } in.close(); } catch (Exception e) { System.err.println("Error: " + e.getMessage()); } sar.spausdinti(); } }

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  • File Segmentation when trying to write in a file

    - by user1286390
    I am trying in C language to use the method of bisection to find the roots of some equation, however when I try to write every step of this process in a file I get the problem "Segmentation fault". This might be an idiot fault that I did, however I have been trying to solve this for a long time. I am compiling using gcc and that is the code: #include <stdio.h> #include <stdlib.h> #include <math.h> #define R 1.0 #define h 1.0 double function(double a); void attractor(double *a1, double *a2, double *epsilon); void attractor(double *a1, double *a2, double *epsilon) { FILE* bisection; double a2_copia, a3, fa1, fa2; bisection = fopen("bisection-part1.txt", "w"); fa1 = function(*a1); fa2 = function(*a2); if(function(*a1) - function(*a2) > 0.0) *epsilon = function(*a1) - function(*a2); else *epsilon = function(*a2) - function(*a1); fprintf(bisection, "a1 a2 fa1 fa2 epsilon\n"); a2_copia = 0.0; if(function(*a1) * function(*a2) < 0.0 && *epsilon >= 0.00001) { a3 = *a2 - (*a2 - *a1); a2_copia = *a2; *a2 = a3; if(function(*a1) - function(*a2) > 0.0) *epsilon = function(*a1) - function(*a2); else *epsilon = function(*a2) - function(*a1); if(function(*a1) * function(*a2) < 0.0 && *epsilon >= 0.00001) { fprintf(bisection, "%.4f %.4f %.4f %.4f %.4f\n", *a1, *a2, function(*a1), function(*a1), *epsilon); attractor(a1, a2, epsilon); } else { *a2 = a2_copia; *a1 = a3; if(function(*a1) - function(*a2) > 0) *epsilon = function(*a1) - function(*a2); else *epsilon = function(*a2) - function(*a1); if(function(*a1) * function(*a2) < 0.0 && *epsilon >= 0.00001) { fprintf(bisection, "%.4f %.4f %.4f %.4f %.4f\n", *a1, *a2, function(*a1), function(*a1), *epsilon); attractor(a1, a2, epsilon); } } } fa1 = function(*a1); fa2 = function(*a2); if(function(*a1) - function(*a2) > 0.0) *epsilon = function(*a1) - function(*a2); else *epsilon = function(*a2) - function(*a1); fprintf(bisection, "%.4f %.4f %.4f %.4f %.4f\n", a1, a2, fa1, fa2, epsilon); } double function(double a) { double fa; fa = (a * cosh(h / (2 * a))) - R; return fa; } int main() { double a1, a2, fa1, fa2, epsilon; a1 = 0.1; a2 = 0.5; fa1 = function(a1); fa2 = function(a2); if(fa1 - fa2 > 0.0) epsilon = fa1 - fa2; else epsilon = fa2 - fa1; if(epsilon >= 0.00001) { fa1 = function(a1); fa2 = function(a2); attractor(&a1, &a2, &epsilon); fa1 = function(a1); fa2 = function(a2); if(fa1 - fa2 > 0.0) epsilon = fa1 - fa2; else epsilon = fa2 - fa1; } if(epsilon < 0.0001) printf("Vanish at %f", a2); else printf("ERROR"); return 0; } Thanks anyway and sorry if this question is not suitable.

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  • Fixing corrupt files or corrupt file table on a USB drive?

    - by Kelsey
    I was doing a virus scan on an external USB drive while copying data over to it. While AVG was scanning my system got locked up I think due to the USB drive running out of space and it required a reboot. Since that time all data on the external drive is no longer accessible. I can see all the files in the root and directories but I cannot browse into any of them as Windows 7 gives an error stating they are corrupt. I think the file table or whatever it uses to store the index of what exists on the drive has been corrupted since it still shows the the drive as being almost full but everything I do a properties check on says it is 0 bytes. Does anyone know how to 'unlock' or recover this data? Is there a way to rebuild the file table somehow? Luckily I can recover this data from other sources as a last resort but I would like to fix this if possible. Any help would be appreciated. Thanks.

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  • Why Does DreamWeaver CS5 Discriminate between File Extensions, Even After Modding Mime Types!?

    - by Sam
    Hi folks, Even After I forced DreamWeaver CS5 to allow opening of .ast extensions as a MIME type of php5, which DreamWeaver now opens and colors correctly as described here, I still have trouble figuring out why it still discriminates between the two file extensions! Symptoms: External Files & Design View I have a file foo.php which php includes other files (e.g. the php-combined css.php and js.php). Now, when opening foo.php all functions work perfectly: the external (included) php files are all recognised correctly. However, when I change foo.php foo.ast, and open it again, It does not recognise the files extensions anymore in the top bar. Also, I lose the Design / Live View functionality.** When I change foo.ast to foo.php, all works again! Anyone any clues of why there remains a a difference between one and other extension? Note1: I have added the .ast extension to these four files, next to .php: 1 C:\Users\Sam\AppData\Local\VirtualStore\Program Files (x86)\Adobe\Adobe Dreamweaver CS5\configuration\DocumentTypes\MMDocumentTypes.xml 2 C:\Program Files (x86)\Adobe\Adobe Dreamweaver CS5\configuration\DocumentTypes\MMDocumentTypes.xml 3 C:\Users\Sam\AppData\Roaming\Adobe\Dreamweaver CS5\en_US\Configuration\Extensions.txt 4 C:\Program Files (x86)\Adobe\Adobe Dreamweaver CS5\configuration\Extensions.txt Note2: sometimes, even .php files do not want to show in design view or live view. Could this be caused by a corrupted installation?

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  • Is there a POSIX pathname that can't name a file?

    - by Charles Stewart
    Are there any legal paths in POSIX that cannot be associated with a file, regular or irregular? That is, for which test -e "$LEGITIMATEPOSIXPATHNAME" cannot succeed? Clarification #1: pathnames By "legal paths in POSIX", I mean ones that POSIX says are allowed, not ones that POSIX doesn't explicitly forbid. I've looked this up, and the are POSIX specification calls them character strings that: Use only characters from the portable filename character set [a-zA-Z0-9._-] (cf. http://www.opengroup.org/onlinepubs/009695399/basedefs/xbd_chap03.html#tag_03_276); Do not begin with -; and Have length between 1 and NAME_MAX, a number unspecified for POSIX that is not less than 14. POSIX also allows that filesystems will probably be more relaxed than this, but it forbids the characters NUL and / from appearing in filenames. Note that such a paradigmatically UNIX filename as lost+found isn't FPF, according to this def. There's another constant PATH_MAX, whose use needs no further explanation. The ideal answer will use FPFs, but I'm interested in any example with filenames that POSIX doesn't expressly forbid. Clarification #2: impossibility Obviously, pathnames normally could be bound to a file. But UNIX semantics will tell you that there are special places that couldn't normally have arbitrary files created, like in the /dev directory. Are any such special places stipulated in POSIX? That is what the question is getting after.

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  • Everyone can access my Windows 7 Homegroup file shares - Even Windows XP computers.

    - by adriangrigore
    Hi, I have 3 computers in my network, two running Windows 7 and one running Windows XP. I've set up a homegroup on both Windows 7 computers. Also, all computers are in the same Workgroup. The problem is that one of the Windows 7 computers makes all shares accessible to the entire Workgroup instead of just sharing to the Homegroup as it should be. I created the file share in Windows 7 via right-click in the explorer, then click on "Share For" - "Homegroup (Read/Write)" (translated from German, so the actual wording may be different). Also, when I look at the file sharing properties of that folder, Windows Explorer informs me that Users must have a valid account and password for this Computer to access drive shares. Unfortunately this is not true. Being in the same Workgroup is enough to get access. Homegroup restrictions work as expected on my other Windows 7 computer. When trying to browse those shares from the XP computer, I get a dialog asking for a login and password. What might cause homegroup restrictions to fail and how can I fix this?

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  • which is best smart automatic file replication solution for cloud storage based systems.

    - by TORr0t
    I am looking for a solution for a project i am working on. We are developing a websystem where people can upload their files and other people can download it. (similar to rapidshare.com model) Problem is, some files can be demanded much more than other files. The scenerio is like: I have uploaded my birthday video and shared it with all of my friend, I have uploaded it to myproject.com and it was stored in one of the cluster which has 100mbit connection. Problem is, once all of my friends want to download the file, they cant download it since the bottleneck here is 100mbit which is 15MB per second, but i got 1000 friends and they can only download 15KB per second. I am not taking into account that the hdd is serving same files. My network infrastrucre is as follows: 1 gbit server(client) and connected to 4 Nodes of storage servers that have 100mbit connection. 1gbit server can handle the 1000 users traffic if one of storage node can stream more than 15MB per second to my 1gbit (client) server and visitor will stream directly from client server instead of storage nodes. I can do it by replicating the file into 2 nodes. But i dont want to replicate all files uploadded to my network since it is costing much more. So i need a cloud based system, which will push the files into replicated nodes automatically when demanded to those files are high, and when the demand is low, they will delete from other nodes and it will stay in only 1 node. I have looked to gluster and asked in their irc channel that, gluster cant do such a thing. It is only able to replicate all the files or none of the files. But i need it the cluster software to do it automatically. Any solutions ? (instead of recommending me amazon s3) S

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  • What's a good solution for file-tagging in linux?

    - by julien
    I've been looking for a way to tag my files and search/filter them based on those tags. Here are my (updated) requirements : any file readable by the user can be tagged freely a user can search for files matching one or several tags files can be moved around without losing the previously associated tags the system could be backed up easily no dependencies on any desktop environment if any gui is involved, there must be a cli fallback I've been hoping for some basic filesystem & coreutils hackery to handle this, but I haven' thought about this hard enough yet. Meanwhile I'll review beagle and metatracker, which have been mentionned here, and see how they perform. Ok so beagle has huge gnome dependencies, and tracker is okish, but still has some dependencies I don't like... Been doing some more research, and the way to go could very well be extended file attributes. That's a native solution for most recent filesystems, but they aren't very well supported yet (most coreutils destroys them by default, cp for example needs the -a flag to preserve them). Would like to hear some thoughts on using them while I try my hand at some hacks myself, eventhough this might warrant a new question.

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  • Does anybody know of existing code to read a mork file (Thunderbird Address Book)?

    - by bruceatk
    I have the need to read the Thunderbird address book on the fly. It is stored in a file format called Mork. Not a pleasant file format to read. I found a 1999 article explaining the file format. I would love to know if someone already has gone through this process and could make the code available. I found mork.pl by Jamie Zawinski (he worked on Netscape Navigator), but I was hoping for a .NET solution. I'm hoping StackOverflow will come to the rescue, because this just seems like a waste of my time to write something to read this file format when it should be so simple. I love the comments that Jamie put in his perl script. Here is my favorite part: # Let me make it clear that McCusker is a complete barking lunatic. # This is just about the stupidest file format I've ever seen.

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  • replace file with hardlink to another file atomically

    - by Ben Clifford
    I have two directory entries, a and b. Before, a and b point to different inodes. Afterwards, I want b to point to the same inode as a does. I want this to be safe - by which I mean if I fail somewhere, b either points to its original inode or the a inode. most especially I don't want to end up with b disappearing. mv is atomic when overwriting. ln appears to not work when the destination already exists. so it looks like i can say: ln a tmp mv tmp b which in case of failure will leave a 'tmp' file around, which is undesirable but not a disaster. Is there a better way to do this? (what I'm actually trying to do is replace files that have identical content with a single inode containing that content, shared between all directory entries)

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  • Regex to match the first file in a rar archive file set in Python

    - by mridang
    I need to uncompress all the files in a directory and for this I need to find the first file in the set. I'm currently doing this using a bunch of if statements and loops. Can i do this this using regex? Here's a list of files that i need to match: yes.rar yes.part1.rar yes.part01.rar yes.part001.rar yes.r01 yes.r001 These should NOT be matched: no.part2.rar no.part02.rar no.part002.rar no.part011.rar no.r002 no.r02 I found a similar regex on this thread but it seems that Python doesn't support varible length lookarounds. A single line regex would be complicated but I'll document it well and it's not a problem. It's just one of those problems you beat your heap up, over. Thanks in advance guys. :)

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  • Parse HTML file to grab all ID and Classes for a CSS file

    - by iamfriendly
    Hey all, A short while ago, I'm fairly certain I came across an application (or perhaps a plugin for Coda - the IDE I use) which quickly parses a html document and then spits out all of the elements with IDs and Classes for me to use in a CSS file. Having fully 'got into' zen coding - using the wonderful TEA plugin for Coda, I'm now hot on the heels of this app/plugin again. I've tried and failed miserably at hunting through Google, but have come up completely empty handed. Does anyone know of anything which can do this? Happy New Year everyone!

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  • ACL actions tag cause 'roles resource tree' draw incorrectly in admin/system/permissions/roles

    - by latvian
    Hi, We created new action similar to 'hold', 'ship' and others in the 'sales_order/view' admin section that can be triggered by clicking at the button. Afterward, we added our new action to the ACL with the following code in config.xml: <acl> <resources> <admin> <children> <sales> <children> <order> <children> <actions translate="title"> <title>Actions</title> <children> <shipNew translate="title"><title>Ship Ups</title></shipNew> </children> </actions> </children> <sort_order>10</sort_order> </order> </children> </sales> </children> </admin> </resources> </acl> ACL functionality works, however, in the 'Resources Tree'(System/Permissions/Roles/Role Resources) our new action does never show up as selected(checked) even thou it is allowed for particular Role. I can see that from table 'admin_rule' with resource id for our new action that it is allowed, so it needs to be selected, but it is not. When trying to solve this issue i looked into the template(permissions/rolesedit.phtml) and I found that the 'resource tree' is draw with Javascript...thats where i got stock due to my limited knowledge in Javascript. Why the resource tree does not display our new ACL entry correctly, that is the check box is never checked? Thank You for helping margots

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  • How get file names using OpenFileDialog in .NET (1000+ file multiselect)

    - by Cole
    Maybe some of you have come across this before.... I am opening files for parsing. I'm using OpenFileDialog, of course, but i'm limited to a buffer of 2048 on the .FileNames string. Thus, I can only select a few hundred files. This is OK for most cases. However, fore example, I have in one case 1400 files to open. Do you know a way to do this with the open file dialog. I just want the string array of .FileNames, I pass that to parser class. I was also thinking of offering a FolderBrowserDialog option and then I'd use some other method to just loop through all the files in a directory, like the DirectoryInfo class. I'd do this as a last resort if I can't have an all in one solution.

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  • Non RBAC User Roles and Permissions System: checking the user's City

    - by micha12
    We are currently designing a User Roles and Permissions System in our web application (ASP.NET), and it seems that we have several cases that do no fit within the classical Role-Based Access Control (RBAC). I will post several questions, each devoted to a particular case, this being the first post. We have the following case: not to allow a user view a certain page if the user lives in a particular city. This is a simple case that is coded in the following way: if (User.City == “Moscow”) // Allow the user to view the page. else // Do not allow the user to view this page. Though this case is very simple and straightforward, it has nothing to do with the RBAC. On StackOverflow, someone called this an Attribute-based Access Control. Under the classical RBAC, it seems that this case should be designed like this: introduce a permission “City where the person lives”, this permission will have a property City. Then create a role, add a permission of type “City = Moscow” to it and the assign the role to the user. Looks extremely cumbersome. The question is whether it is acceptable to introduce such non-RBAC approaches to our permissions system – does that break the design or not? This might seem a primitive question, but we found that most applications use pure RBAC, and we started to think that we might be doing something wrong. Thank you.

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  • Replace string in one file with contents of a second file

    - by jag7720
    I have two files: fileA: date >> /root/kvno.out kvno serverXXX\$ >> /root/kvno.out fileB: foobar I need to create a new file, fileC, with the same contents as fileA, except with the string XXX being replaced with the contents of fileB: date >> /root/kvno.out kvno serverfoobar\$ >> /root/kvno.out I'd like to do this using sed. I tried some of the examples I found but I only get the contents of fileB in fileC.

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  • create and modify xml file using javascript (want to save xml file on client side)

    - by user201478
    Hi , How to save xml file on client side using javascript...? if (window.XMLHttpRequest) { xhttp = new XMLHttpRequest(); } else // Internet Explorer 5/6 { xhttp = new ActiveXObject("Microsoft.XMLHTTP"); } xhttp.open("GET", "User.xml", false); xhttp.send(""); xmlDoc = xhttp.responseXML; xmlDoc.getElementsByTagName("Username")[0].childNodes[0].nodeValue = 'asdasf'; xmlDoc.getElementsByTagName("password")[0].childNodes[0].nodeValue = 'asdAS'; xmlDoc.getElementsByTagName("UserId")[0].childNodes[0].nodeValue = '12'; xmlDoc.save("User.xml"); this is not working.. showing error as save is not a function. Thanks Suneetha.

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  • Providing File permissions in Installshield

    - by Pawan Kumar
    I have created an installer in Installshield X. I want to give 'write permissions' to few files when the installation is done in Non-Admin Windows accounts ( by default it will have only 'read' permission). If I select individual file and go to properties (inside Installshield),i have permissions tab where they have provided options like Domain , Readonly, Full Control, Modify etc. I have tested these options but it doesn't effect the msi file.(specific files doesn't have write permission). Is there something wrong I am doing? There is another way of doing this, writing the script Set objShell=CreateObject("WScript.Shell") installDir = Session.Property("INSTALLDIR.5A884667_3CC4_41EC_B0F2_BEEAB457BB8C") supportDir = Session.Property("SUPPORTDIR") length = Len(installDir) lastChar = Right(installDir, 1) if (lastChar = "\") Then installDir = Left(installDir, length - 1) end if 'MsgBox supportDir & "\setacl.exe """ & installDir & """ /dir /set S-1-5-32-545 /full /p:yes /sid /silent" objshell.Run supportDir & "\setacl.exe """ & installDir & """ /dir /set S-1-5-32-545 /full /p:yes /sid /silent",0,true Can someone please explain me what is going on here? those last set s-1-5-32-545. Thanks

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  • Blackberry JDE generating bad .jad file (does not match compiled .cod file)

    - by matkas
    I Have a BB application that gets compiled into 3 siblings cod file. ( actualy one cod fil contaning 3 sub cod files). app.cod |--app.cod |--app-1.cod |--app-2.cod which is normal. the jad refers to those 3 inner .cod files. Now I have add some feature to my app, it is getting a little bit bigger. the jad now refers to 4 inner .cod files. but there is still 3 inside the app.cod that is generated. so I now still have app.cod |--app.cod |--app-1.cod |--app-2.cod but with the jad refering to app.cod app-1.cod app-2.cod AND app-3.cod. what is wrong the my compiled program? is it a bug from the JDE? I am using JDE 4.5.

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  • How do I write to a file and print to a terminal cuncurrently in Unix?

    - by bias
    I have a little bash function to log my Macports outputs to a file (since installs often spew little tidbits that are easy to lose in terminal noise), then I just cat the file to the terminal: function porti { command sudo port install $@ >> $1.log 2>&1; cat $1.log } Is there a way to do this concurrently? I don't care about it being in Bash, that's just how I started it. BTW I pass $@ to install but only $1 for the file name so that I can do something like: porti git-gore +bash_completion and only get the file git-core.log however someone else might prefer to include variants in the file name ...

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  • Can .NET load and parse a properties file equivalent to Java Properties class?

    - by Tai Squared
    Is there an easy way in C# to read a properties file that has each property on a separate line followed by an equals sign and the value, such as the following: ServerName=prod-srv1 Port=8888 CustomProperty=Any value In Java, the Properties class handles this parsing easily: Properties myProperties=new Properties(); FileInputStream fis = new FileInputStream (new File("CustomProps.properties")); myProperties.load(fis); System.out.println(myProperties.getProperty("ServerName")); System.out.println(myProperties.getProperty("CustomProperty")); I can easily load the file in C# and parse each line, but is there a built in way to easily get a property without having to parse out the key name and equals sign myself? The C# information I have found seems to always favor XML, but this is an existing file that I don't control and I would prefer to keep it in the existing format as it will require more time to get another team to change it to XML than parsing the existing file.

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  • Why does eclipse break when the .project file is hidden?

    - by Tommy
    Why does eclipse break with the error "Could not write file: M:\workspaces\eclipse\project.project. M:\workspaces\eclipse\project.project (Access is denied)" when the .project file is hidden (on the Windows file system)? Note: This happens w/ other files as well. Steps to Reproduce: 1. Install the latest eclipse, I am using eclipse-jee-galileo-SR2-win32.zip. (Not sure if it happens in other versions) 2. Create a project. 3. Browse to the project in windows explorer, find the .project file. 4. Right click - properties 5. Under Attributes check hidden. 6. In eclipse, open the .project file, make a change and try to save. 7. After you get the error, uncheck the hidden box and save again.

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  • when using a FTPS connection to transfer a file, what is the difference between a 'Binary mode taran

    - by shaleen mohan
    I am using a FTPS connection to send a text file [this file will contain EDI(Electronic Data Interchange) information]to a mailbox INOVIS.I have configured the system to open a FTPS connection and using the PUT command I write the file to a folder on the FTP server. The problem is: what mode of file transfer should I use? How do I switch between modes? Moreover which mode is the 'best-practice' to use when transferring file over FTPS connection. If some one can provide me a small ftp script it would be helpful.

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  • Delphi: how to efficently read a big binary file, converting it to hexadecimal for passing it as a v

    - by user193655
    I need to convert a binary file (a zip file) into hexadecimal representation, to then send it to sql-server as a varbinary(max) function parameter. A full example (using a very small file!) is: 1) my file contains the following bits 000011110000111 2) I need a procedure to QUICKLY convert it to 0F0F 3) I will call a sql server function passing 0x0F0F as parameter The problem is that I have large files (up to 100MB, even if average file size is 100KB files are possible), so I need the fastest way to do this. Otherwise stated: I need to create the string '0x'+BinaryDataInHexadecimalRepresentation in the most efficient way. Related question: passing hexadecimal data to sql server

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