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• What is the maximum number of virtualhosts Apache can handle?

  - by FractalizeR

  Hello. What is the maximum number of VirtualHosts Apache can handle on a single machine (I don't mean anything related to load, let's suppose it's irrelevant for the question). And we take only Apache without any proxifying things like nginx. I am asking because on one forum one guy reported that his Apache works unstable with the number of sites more than 400 on a single machine. If you have a config, that handles more than 400, please tell me here. Thanks.

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• Windows Server 2008 Scheduled Tasks not running - 0x80041323 - Reduce Number of tasks running in the specified context?

  - by Mayb2Moro

  I am getting the following problem on a number of windows 2008 servers. 0x80041323 Task Scheduler failed to start task \Reporting" in TaskEngine "S-1-5-18:NT AUTHORITY\System:Service:" for user "NT AUTHORITY\System". User Action: Reduce the number of tasks running in the specified user context. I've done lots of research around the web but have been unable to come up with a working answer. I have found some information suggesting increasing a value in the registry key "TasksInMemoryQueue" which I have done, but even setting this as high as 500 has not helped. I have rebooted the server after setting this value. The server does run a high volume of Scheduled tasks, there could be 150 or so running at any one time, but certainly not 500. The scheduled tasks are all running under the system user. Does anyone have any ideas?

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• How to increase the number of items in the "recent" folder in Windows 7?

  - by netvope

  Windows 7 keeps a list of recently used files in C:\Users\<username>\AppData\Roaming\Microsoft\Windows\Recent. Based on my observation, it keeps 10 items for each file extension. So when you So open 11 .txt files in a row, the 2nd to the 11th items will stay in that Recent folder, but the first one will be gone. My question is: How to keep an unlimited number of items in that Recent folder? Note: Increasing the per-application recent items (e.g. as in http://www.mydigitallife.info/2009/05/21/change-increase-or-decrease-number-of-recent-or-frequent-items-displayed-in-windows-7-taskbar-jump-list/ ) has no effect on the per-user Recent item folder that I'm concerning.

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• Is there a limit for the number of files in a directory on an SD card?

  - by jamesh

  I have a project written for Android devices. It generates a large number of files, each day. These are all text files and images. The app uses a database to reference these files. The app is supposed to clear up these files after a little use (perhaps after a few days), but this process may or may not be working. This is not the subject of this question. Due to a historic accident, the organization of the files are somewhat naive: everything is in the same directory; a .hidden directory which contains a zero byte .nomedia file to prevent the MediaScanner indexing it. Today, I am seeing an error reported: java.io.IOException: Cannot create: /sdcard/.hidden/file-4200.html at java.io.File.createNewFile(File.java:1263) Regarding the sdcard, I see it has plenty of storage left, but counting $ cd /Volumes/NO_NAME/.hidden $ ls | wc -w 9058 Deleting a number of files seems to have allowed the file creation for today to proceed. Regrettably, I did not try touching a new file to try and reproduce the error on a commandline; I also deleted several hundred files rather than a handful. However, my question is: are there hard limits on filesize or number of files in a directory? am I even on the right track here? Nota Bene: The SD card is as-is - i.e. I haven't formatted it, so I would guess it would be a FAT-* format. The FAT-32 format has hard limits of filesize of 2GB (well above the filesizes I am dealing with) and a limit of number of files in the root directory. I am definitely not writing files in the root directory.

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• How does a client find the port number of a server?

  - by Jonathan

  Hello all, I am currently learning about basic networking in java. I have been playing around with the server and client relationship between two of my computers. However, I cannot figure out how distributed programs (say, a videogame), can not only find the 'host' computer, but also the port number on which the server is running in order to create a Socket between the two computers. The only way I really see to create a Socket is with an already known IP Address, and with a known port number. How do you search a LAN network for another computer (host) searching for clients? How do you determine what port the server is located on without 'pinging' all available ports for a response (which, I understand, is bad form... Something about 'server attack'...)? In such a situation as a video game, there can be any number of computers on the same network, and any number of them might be attempting to host, or otherwise running the application. Any other important information, or perhaps reference to a more detailed tutorial than the one I am using, regarding making connections on so very little information on the client side would be appreciated. Many thanks, Jonathan

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• How to know the number of CPUs and spec for each CPU/Core in Ubuntu Karmic?

  - by Viet

  How to know the number of CPUs and spec for each CPU/Core in Ubuntu Karmic?

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• Why does my C++ LinkedList method print out the last word more than once?

  - by Anthony Glyadchenko

  When I call the cmremoveNode method in my LinkedList from outside code, I get an EXC_BAD_ACCESS. FIXED: But now the last word using the following test code gets repeated twice: #include <iostream> #include "LinkedList.h" using namespace std; int main (int argc, char * const argv[]) { ctlinkList linkMe; linkMe.cminsertNode("The"); linkMe.cminsertNode("Cat"); linkMe.cminsertNode("Dog"); linkMe.cminsertNode("Cow"); linkMe.cminsertNode("Ran"); linkMe.cminsertNode("Pig"); linkMe.cminsertNode("Away"); linkMe.cmlistList(); cout << endl; linkMe.cmremoveNode("The"); linkMe.cmremoveNode("Cow"); linkMe.cmremoveNode("Away"); linkMe.cmlistList(); return 0; } LinkedList code: /* * LinkedList.h * Lab 6 * * Created by Anthony Glyadchenko on 3/22/10. * Copyright 2010 __MyCompanyName__. All rights reserved. * */ #include <stdio.h> #include <iostream> #include <fstream> #include <iomanip> using namespace std; class ctNode { friend class ctlinkList ; // friend class allowed to access private data private: string sfileWord ; // used to allocate and store input word int iwordCnt ; // number of word occurrances ctNode* ctpnext ; // point of Type Node, points to next link list element }; class ctlinkList { private: ctNode* ctphead ; // initialized by constructor public: ctlinkList () { ctphead = NULL ; } ctNode* gethead () { return ctphead ; } string cminsertNode (string svalue) { ctNode* ctptmpHead = ctphead ; if ( ctphead == NULL ) { // allocate new and set head ctptmpHead = ctphead = new ctNode ; ctphead -> ctpnext = NULL ; ctphead -> sfileWord = svalue ; } else { //find last ctnode do { if ( ctptmpHead -> ctpnext != NULL ) ctptmpHead = ctptmpHead -> ctpnext ; } while ( ctptmpHead -> ctpnext != NULL ) ; // fall thru found last node ctptmpHead -> ctpnext = new ctNode ; ctptmpHead = ctptmpHead -> ctpnext ; ctptmpHead -> ctpnext = NULL; ctptmpHead -> sfileWord = svalue ; } return ctptmpHead -> sfileWord ; } string cmreturnNode (string svalue) { return NULL; } string cmremoveNode (string svalue) { int counter = 0; ctNode *tmpHead = ctphead; if (ctphead == NULL) return NULL; while (tmpHead->sfileWord != svalue && tmpHead->ctpnext != NULL){ tmpHead = tmpHead->ctpnext; counter++; } do{ tmpHead->sfileWord = tmpHead->ctpnext->sfileWord; tmpHead = tmpHead->ctpnext; } while (tmpHead->ctpnext != NULL); return tmpHead->sfileWord; } string cmlistList () { string tempList; ctNode *tmpHead = ctphead; if (ctphead == NULL){ return NULL; } else{ while (tmpHead != NULL){ cout << tmpHead->sfileWord << " "; tempList += tmpHead->sfileWord; tmpHead = tmpHead -> ctpnext; } } return tempList; } }; Why is this happening?

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• (Oracle) How get total number of results when using a pagination query?

  - by BestPractices

  I am using Oracle 10g and the following paradigm to get a page of 15 results as a time (so that when the user is looking at page 2 of a search result, they see records 16-30). select * from ( select rownum rnum, a.* from (my_query) a where rownum <= 30 ) where rnum > 15; Right now I'm having to run a separate SQL statement to do a "select count" on "my_query" in order to get the total number of results for my_query (so that I can show it to the user and use it to figure out total number of pages, etc). Is there any way to get the total number of results without doing this via a second query, i.e. by getting it from above query? I've tried adding "max(rownum)", but it doesn't seem to work (I get an error [ORA-01747] that seems to indicate it doesnt like me having the keyword rownum in the group by). My rationale for wanting to get this from the original query rather than doing it in a separate SQL statement is that "my_query" is an expensive query so I'd rather not run it twice (once to get the count, and once to get the page of data) if I dont have to; but whatever solution I can come up with to get the number of results from within a single query (and at the same time get the page of data I need) should not add much if any additional overhead, if possible. Please advise. Here is exactly what I'm trying to do for which I receive an ORA-01747 error because I believe it doesnt like me having ROWNUM in the group by. Note, If there is another solution that doesnt use max(ROWNUM), but something else, that is perfectly fine too. This solution was my first thought as to what might work. SELECT * FROM (SELECT r.*, ROWNUM RNUM, max(ROWNUM) FROM (SELECT t0.ABC_SEQ_ID AS c0, t0.FIRST_NAME, t0.LAST_NAME, t1.SCORE FROM ABC t0, XYZ t1 WHERE (t0.XYZ_ID = 751) AND t0.XYZ_ID = t1.XYZ_ID ORDER BY t0.RANK ASC) r WHERE ROWNUM <= 30 GROUP BY r.*, ROWNUM) WHERE RNUM > 15

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• In Varnish, is it normal for the number of freed bytes to be 60% of those allocated?

  - by user331397

  I have an installation of Varnish 3.02 on an Amazon EC2 Medium Linux instance in front of two relatively low-traffic websites. After an uptime of 2 hours, there are 3400 objects in the cache. Using varnishstat, I checked the variables SMA.s0.c_bytes and SMA.s0.c_freed, which I assume correspond to the total number of bytes allocated since startup and the number freed, respectively. No objects should have had time to expire during these two hours, but still about 60% of the memory allocated since startup (330MB out of 560MB) has already been freed. Do you know if this is normal? If not, do you know what kind of configuration could be wrong?

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• How can I lookup data about a book from its barcode number?

  - by Joel Spolsky

  I'm building the world's simplest library application. All I want to be able to do is scan in a book's UPC (barcode) using a typical scanner (which just types the numbers of the barcode into a field) and then use it to look up data about the book... at a minimum, title, author, year published, and either the Dewey Decimal or Library of Congress catalog number. The goal is to print out a tiny sticker ("spine label") with the card catalog number that I can stick on the spine of the book, and then I can sort the books by card catalog number on the shelves in our company library. That way books on similar subjects will tend to be near each other, for example, if you know you're looking for a book about accounting, all you have to do is find SOME book about accounting and you'll see the other half dozen that we have right next to it which makes it convenient to browse the library. There seem to be lots of web APIs to do this, including Amazon and the Library of Congress. But those are all extremely confusing to me. What I really just want is a single higher level function that takes a UPC barcode number and returns some basic data about the book.

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• Count the Number of Characters in a Full FIle Path?

  - by Richie086

  I need to be able to count the number of characters in a full path to a file in windows. How I am currently accomplishing this task is as follows: Open a command prompt cd to the directory in question (for example c:\CruiseControl\ProjectArtifacts\ProjectName) type the following command dir /s /b output.csv Open the resulting output.csv file in excel. use the =LEN() function in excel to count the number of characters per row as listed in the output.csv file. Does anyone know of an explorer shell extension, or some 3rd party tool that could preform this function without me having to manipulate the output from dir in excel? Is there some easier way to go about doing this? The root of the issue I am having is the ~260 character file path limit in Windows. I am trying to analyze which paths are approx ~260 characters so I can shorten them to avoid getting this error.

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• PL-SQL - Two statements with begin and end, run fine seperately but not together?

  - by Twiss

  Hi all, Just wondering if anyone can help with this, I have two PLSQL statements for altering tables (adding extra fields) and they are as follows: -- Make GC_NAB field for Next Action By Dropdown begin if 'VARCHAR2' = 'NUMBER' and length('VARCHAR2')>0 and length('')>0 then execute immediate 'alter table "SERVICEMAIL6"."ETD_GUESTCARE" add(GC_NAB VARCHAR2(10, ))'; elsif ('VARCHAR2' = 'NUMBER' and length('VARCHAR2')>0 and length('')=0) or 'VARCHAR2' = 'VARCHAR2' then execute immediate 'alter table "SERVICEMAIL6"."ETD_GUESTCARE" add(GC_NAB VARCHAR2(10))'; else execute immediate 'alter table "SERVICEMAIL6"."ETD_GUESTCARE" add(GC_NAB VARCHAR2)'; end if; commit; end; -- Make GC_NABID field for Next Action By Dropdown begin if 'NUMBER' = 'NUMBER' and length('NUMBER')>0 and length('')>0 then execute immediate 'alter table "SERVICEMAIL6"."ETD_GUESTCARE" add(GC_NABID NUMBER(, ))'; elsif ('NUMBER' = 'NUMBER' and length('NUMBER')>0 and length('')=0) or 'NUMBER' = 'VARCHAR2' then execute immediate 'alter table "SERVICEMAIL6"."ETD_GUESTCARE" add(GC_NABID NUMBER())'; else execute immediate 'alter table "SERVICEMAIL6"."ETD_GUESTCARE" add(GC_NABID NUMBER)'; end if; commit; end; When I run these two queries seperately, no problems. However, when run together as shown above, Oracle gives me an error when it starts the second statement: Error report: ORA-06550: line 15, column 1: PLS-00103: Encountered the symbol "BEGIN" 06550. 00000 - "line %s, column %s:\n%s" *Cause: Usually a PL/SQL compilation error. *Action: I'm assuming that this means the first statement is not terminated properly... is there anything I should put inbetween the statements to make it work properly? Thanks in advance everyone!

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• Capture the build number for a remote-triggered Hudson job?

  - by EMiller

  I have a very simple inhouse web app from which certain Hudson builds (on another server) can be triggered remotely. I have no problem triggering the builds, but I don't know how to capture the associated build number for later reference. I'm using the buildWithParameters trigger, and the actual result of that call is just a mess of HTML - I don't believe it gives me back the build number. I started down the path of pulling the whole build list for the job (via the api), and then attempting to reconcile that list against my records - but that's much more complicated than I'd like it to be. I also considered sleeping for a few seconds after launching the job, and then grabbing the latestBuild from the Hudson api - but I'm sure that's going to go wrong at some point (someone will fire off two jobs quickly, and I'll get the association wrong).

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• error in assigning a const character to an unsigned char array in C++

  - by mekasperasky

  #include <iostream> #include <fstream> #include <cstring> using namespace std; typedef unsigned long int WORD; /* Should be 32-bit = 4 bytes */ #define w 32 /* word size in bits */ #define r 12 /* number of rounds */ #define b 16 /* number of bytes in key */ #define c 4 /* number words in key */ /* c = max(1,ceil(8*b/w)) */ #define t 26 /* size of table S = 2*(r+1) words */ WORD S [t],L[c]; /* expanded key table */ WORD P = 0xb7e15163, Q = 0x9e3779b9; /* magic constants */ /* Rotation operators. x must be unsigned, to get logical right shift*/ #define ROTL(x,y) (((x)<<(y&(w-1))) | ((x)>>(w-(y&(w-1))))) #define ROTR(x,y) (((x)>>(y&(w-1))) | ((x)<<(w-(y&(w-1))))) void RC5_DECRYPT(WORD *ct, WORD *pt) /* 2 WORD input ct/output pt */ { WORD i, B=ct[1], A=ct[0]; for (i=r; i>0; i--) { B = ROTR(B-S [2*i+1],A)^A; A = ROTR(A-S [2*i],B)^B; } pt [1] = B-S [1] ;pt [0] = A-S [0]; } void RC5_SETUP(unsigned char *K) /* secret input key K 0...b-1] */ { WORD i, j, k, u=w/8, A, B, L [c]; /* Initialize L, then S, then mix key into S */ for (i=b-1,L[c-1]=0; i!=-1; i--) L[i/u] = (L[i/u]<<8)+K[ i]; for (S [0]=P,i=1; i<t; i++) S [i] = S [i-1]+Q; for (A=B=i=j=k=0; k<3*t; k++,i=(i+1)%t,j=(j+1)%c) /* 3*t > 3*c */ { A = S[i] = ROTL(S [i]+(A+B),3); B = L[j] = ROTL(L[j]+(A+B),(A+B)); } } void printword(WORD A) { WORD k; for (k=0 ;k<w; k+=8) printf("%02.2lX",(A>>k)&0xFF); } int main() { WORD i, j, k, pt [2], pt2 [2], ct [2] = {0,0}; unsigned char key[b]; ofstream out("cpt.txt"); ifstream in("key.txt"); if(!in) { cout << "Cannot open file.\n"; return 1; } if(!out) { cout << "Cannot open file.\n"; return 1; } key="111111000001111"; RC5_SETUP(key); ct[0]=2185970173; ct[1]=3384368406; for (i=1;i<2;i++) { RC5_DECRYPT(ct,pt2); printf("\n plaintext "); printword(pt [0]); printword(pt[1]); } return 0; } When I compile this code, I get two warnings and also an error saying that I can't assign a char value to my character array. Why is that?

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• error in assigning a const character to a usigned char array in C++

  - by mekasperasky

  #include <iostream> #include <fstream> #include <cstring> using namespace std; typedef unsigned long int WORD; /* Should be 32-bit = 4 bytes */ #define w 32 /* word size in bits */ #define r 12 /* number of rounds */ #define b 16 /* number of bytes in key */ #define c 4 /* number words in key */ /* c = max(1,ceil(8*b/w)) */ #define t 26 /* size of table S = 2*(r+1) words */ WORD S [t],L[c]; /* expanded key table */ WORD P = 0xb7e15163, Q = 0x9e3779b9; /* magic constants */ /* Rotation operators. x must be unsigned, to get logical right shift*/ #define ROTL(x,y) (((x)<<(y&(w-1))) | ((x)>>(w-(y&(w-1))))) #define ROTR(x,y) (((x)>>(y&(w-1))) | ((x)<<(w-(y&(w-1))))) void RC5_DECRYPT(WORD *ct, WORD *pt) /* 2 WORD input ct/output pt */ { WORD i, B=ct[1], A=ct[0]; for (i=r; i>0; i--) { B = ROTR(B-S [2*i+1],A)^A; A = ROTR(A-S [2*i],B)^B; } pt [1] = B-S [1] ;pt [0] = A-S [0]; } void RC5_SETUP(unsigned char *K) /* secret input key K 0...b-1] */ { WORD i, j, k, u=w/8, A, B, L [c]; /* Initialize L, then S, then mix key into S */ for (i=b-1,L[c-1]=0; i!=-1; i--) L[i/u] = (L[i/u]<<8)+K[ i]; for (S [0]=P,i=1; i<t; i++) S [i] = S [i-1]+Q; for (A=B=i=j=k=0; k<3*t; k++,i=(i+1)%t,j=(j+1)%c) /* 3*t > 3*c */ { A = S[i] = ROTL(S [i]+(A+B),3); B = L[j] = ROTL(L[j]+(A+B),(A+B)); } } void printword(WORD A) { WORD k; for (k=0 ;k<w; k+=8) printf("%02.2lX",(A>>k)&0xFF); } int main() { WORD i, j, k, pt [2], pt2 [2], ct [2] = {0,0}; unsigned char key[b]; ofstream out("cpt.txt"); ifstream in("key.txt"); if(!in) { cout << "Cannot open file.\n"; return 1; } if(!out) { cout << "Cannot open file.\n"; return 1; } key="111111000001111"; RC5_SETUP(key); ct[0]=2185970173; ct[1]=3384368406; for (i=1;i<2;i++) { RC5_DECRYPT(ct,pt2); printf("\n plaintext "); printword(pt [0]); printword(pt[1]); } return 0; } when i run this code i get two warnings and also an error saying that i cant assign a char value to my character array . Why is that ?

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• Is there a maximum number of input controls that can be used on an HTML form?

  - by Rich

  I have an ambitious requirement for an asp.net 2.0 web page that contains a table (gridview), and each row in the grid contains 6 select (dropdown) controls for data entry. The number of rows that will be displayed is dependent upon the user's search parameters, which are specified in another area of the page. Unfortunately, with the default (and even basic) search parameters specified, the grid could contain several hundred rows. I've noticed that the browser, in this case IE8, starts behaving rather erratically once I reach a large number of rows -- no documented evidence for the number of rows where this begins to be a problem. For example, trying to view the source of the page results in a message from IE stating that there was a problem with the page that forced the browser to reload it, and I never get the source. Obviously the page loads and renders rather slowly also. I know that my solution is probably going to involve paging the gridview such that it only displays 20 or so rows per page, and I'll have to write code to handle the saving of changes in the dropdown values when the user changes pages. I can probably turn off viewstate on the gridview also. However, the question I really want to pose is this -- has anyone seen a documented rule indicating the maximum number of input controls that an HTML browser form is supposed to be able to contain? I could not find anything on the Internet after doing a search, and I suspect the answer may be whatever the browser can handle based on the machine configuration it is running on. Any rules of thumb you use? Thanks for any suggestions. Rich

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• multiplying all elements in an array by an outside number?

  - by prodo

  I need to multiple all the values in an array by 3000 which in turn would create a new array that I will use to subtract from another array. I've tried to create a separate method that would do that for me but all I got back in the multiplied array was a bunch of numbers and symbols strangely? here is the code that I wrote public static void main(String[] args) { int numberOfTaxpayers = Integer.parseInt(JOptionPane.showInputDialog("Enter how many users you would like to calculate taxes for: "); int[] usernumChild = new int[numberOfTaxPayers]; for (int i = 0; i < usernumChild.length; i++) { usernumChild[i] = Integer.parseInt(JOptionPane.showInputDialog("Enter number of children for user "+ (i+1) +": ")); }//this for loop finds out the number of children per user so we can later multiply each input by 3000 to create an array that determine dependency exemption for each user int[] depndExemp = multiply(usernumChild, 3000);//this was the calling of the multiply method... somewhere here is the error!! }//end main method public static int[] multiply(int[] children, int number) { int array[] = new int[children.length]; for( int i = 0; i < children.length; i++) { children[i] = children[i] * number; }//end for return array; }//this is the method that I was shown in a previous post on how to create return an array in this the dependency exemption array but when I tested this by printing out the dependency array all I received were a jumble of wrong numbers.

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• Find existence of number in a sorted list in constant time? (Interview question)

  - by Rich

  I'm studying for upcoming interviews and have encountered this question several times (written verbatim) Find or determine non existence of a number in a sorted list of N numbers where the numbers range over M, M N and N large enough to span multiple disks. Algorithm to beat O(log n); bonus points for constant time algorithm. First of all, I'm not sure if this is a question with a real solution. My colleagues and I have mused over this problem for weeks and it seems ill formed (of course, just because we can't think of a solution doesn't mean there isn't one). A few questions I would have asked the interviewer are: Are there repeats in the sorted list? What's the relationship to the number of disks and N? One approach I considered was to binary search the min/max of each disk to determine the disk that should hold that number, if it exists, then binary search on the disk itself. Of course this is only an order of magnitude speedup if the number of disks is large and you also have a sorted list of disks. I think this would yield some sort of O(log log n) time. As for the M N hint, perhaps if you know how many numbers are on a disk and what the range is, you could use the pigeonhole principle to rule out some cases some of the time, but I can't figure out an order of magnitude improvement. Also, "bonus points for constant time algorithm" makes me a bit suspicious. Any thoughts, solutions, or relevant history of this problem?

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• SEM & Adwords: How many click without a sale before i should pause a keyword

  - by Thomas Jönsson

  I wonder how many clicks I optimally should let pass through every new keyword I try in Adwords before I find out that it's not making a profit and it should be paused! It's actually four question. 1: At which likelihood percentile should I pause a word? 2: How many clicks should I let through before I pause a word for those word which do not generate any lead? 3: How many clicks should I let through after one sale to consider the word not to be profitable? 4: Does the likelihood of the word becoming profitable affect the above? Conditions: -The clicks is normally distributed. (correct?) -A CR of 1% is break even, everything above is profit (1 sale/100 clicks=break even) Cost per Click(cpc) = 4$ -Marginal (profit per sale) = 400$ -Paybacktime = 1 year -Average click per word = 0,333 per day (121 + 2/3 per year) Exampel: After 1 click and no sale the keyword still has a high probability to be profitable. After 500 clicks and no sale it has almost no likelihood to not be profitable and should probably be paused. Thanks in advance!

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• How to Extract the images from the doc file without Having Microsoft office ?

  - by Anirudha

  Originally posted on: http://geekswithblogs.net/anirugu/archive/2013/06/29/how-to-extract-the-images-from-the-doc-file-without.aspxMany time we got the doc file who have some images. We need to try to extract them in Microsoft word which come with Windows 7 (not Microsoft office word). Looking to this article http://www.techrepublic.com/blog/itdojo/save-images-in-microsoft-word-documents-as-separate-files/135 This article is only useful when you have Microsoft word installed. Now if I don’t have Microsoft office then what ? No problem, here is a trick. when you open the doc file in Word  then select the image and right click on image and choose cut. open the Microsoft paint. paste them here. Without clicking anywhere click on crop icon on toolbar.   Now you got your image in the same size as you have in word file. Don’t worry about Image format. Microsoft paint have support for save them in PNG format.

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• Software for a online collaborative bi/tri lingual dictionary [closed]

  - by user537488

  I am looking for a software which I can host in popular and general shared web hosting services(online softwares like wordpress, meidawiki, drupal etc.) which can do the following- allow users to create account allow users or anons to add words to the dictionary (there will be English as base language and other languages) easier way to import all the words from English dictionary users should be able to write the that language equivalent of the English word Every word should have it's own address and page like www.namesomething.com/word/en/software will contain the word software and the other language word for it search should be faster and should find nearer results it's should be able to list related words like if the user is looking at "software" then other words from s like "softcopy" etc should appear alphabetically in that page Any one should be able to comment on the word which is not seen in the main page but other page similar to the talk page in the wiki any one should be able to contribute clean interface unlike wiki (media wiki and all other) just for words only I tried media wiki and other wiki software but it overloaded and unclean. I am looking for interface similar to oed.com but clean, minimal as we are not going to have such more information. Just words in English and it's other language equivalent. Here we are talking about a language which has not yet been in the Internet. It's should be collaborative.

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• Creating foreign words' learning site with memory technique (Web 2.0)? Will it work?

  - by Michal P.

  I would like to earn a little money for realizing a good, simple project. My idea is to build a website for learning of chosen by me language (for users knowing English) using mnemonics. Users would be encourage to enter English words with translation to another language and describing the way, how to remember a foreign language word (an association link). Example: if I choose learning Spanish for people who knows English well, it would look like that: every user would be encourage to enter a way to remember a chosen by him/her Spanish word. So he/she would enter to the dictionary (my site database) ,e.g., English word: beach - playa (Spanish word). Then he/she would describe the method to remember Spanish word, e.g., "Image that U r on the beach and U play volleyball" - we have the word play and recall playa (mnemonics). I would like to give possibility of pic hotlinks, encourage for fun or little shocking memory links which is -- in the art of memory -- good. I would choose a language to take a niche of Google Search. The big question is if I don't lose my time on it?? (Maybe I need to find prototype way to check that idea?)

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• usb mouse/keyboard doesn't work with 3.11.0-12-generic kernel

  - by x-yuri

  I can't use my usb keyboard/mouse after upgrade from raring to saucy. The keyboard works in grub menu and if I boot with the previous kernel version (3.8.0-31-generic). My new kernel version is 3.11.0-12-generic. I've got Mad Catz R.A.T.7 wired USB mouse, Canyon CNL-MBMSO02 wired usb mouse and Logitech diNovo Edge wireless keyboard, connected to computer through Logitech Unifying Receiver. Using PS/2 keyboard I've managed to get some information. dmesg says: [ 0.166273] ACPI: bus type USB registered [ 0.166273] usbcore: registered new interface driver usbfs [ 0.166273] usbcore: registered new interface driver hub [ 0.166273] usbcore: registered new device driver usb ... [ 3.534226] ehci_hcd: USB 2.0 'Enhanced' Host Controller (EHCI) Driver [ 3.534228] ehci-pci: EHCI PCI platform driver [ 3.534291] ehci-pci 0000:00:1a.7: setting latency timer to 64 [ 3.534299] ehci-pci 0000:00:1a.7: EHCI Host Controller [ 3.534304] ehci-pci 0000:00:1a.7: new USB bus registered, assigned bus number 1 [ 3.534315] ehci-pci 0000:00:1a.7: debug port 1 [ 3.538218] ehci-pci 0000:00:1a.7: cache line size of 64 is not supported [ 3.538231] ehci-pci 0000:00:1a.7: irq 18, io mem 0xd3325400 [ 3.548017] ehci-pci 0000:00:1a.7: USB 2.0 started, EHCI 1.00 [ 3.548042] usb usb1: New USB device found, idVendor=1d6b, idProduct=0002 [ 3.548045] usb usb1: New USB device strings: Mfr=3, Product=2, SerialNumber=1 [ 3.548048] usb usb1: Product: EHCI Host Controller [ 3.548050] usb usb1: Manufacturer: Linux 3.11.0-12-generic ehci_hcd [ 3.548053] usb usb1: SerialNumber: 0000:00:1a.7 [ 3.548155] hub 1-0:1.0: USB hub found [ 3.548159] hub 1-0:1.0: 6 ports detected [ 3.548311] ehci-pci 0000:00:1d.7: setting latency timer to 64 [ 3.548319] ehci-pci 0000:00:1d.7: EHCI Host Controller [ 3.548323] ehci-pci 0000:00:1d.7: new USB bus registered, assigned bus number 2 [ 3.548333] ehci-pci 0000:00:1d.7: debug port 1 [ 3.552228] ehci-pci 0000:00:1d.7: cache line size of 64 is not supported [ 3.552239] ehci-pci 0000:00:1d.7: irq 23, io mem 0xd3325000 [ 3.564014] ehci-pci 0000:00:1d.7: USB 2.0 started, EHCI 1.00 [ 3.564044] usb usb2: New USB device found, idVendor=1d6b, idProduct=0002 [ 3.564047] usb usb2: New USB device strings: Mfr=3, Product=2, SerialNumber=1 [ 3.564050] usb usb2: Product: EHCI Host Controller [ 3.564052] usb usb2: Manufacturer: Linux 3.11.0-12-generic ehci_hcd [ 3.564056] usb usb2: SerialNumber: 0000:00:1d.7 [ 3.564163] hub 2-0:1.0: USB hub found [ 3.564167] hub 2-0:1.0: 6 ports detected [ 3.564274] ehci-platform: EHCI generic platform driver [ 3.564280] ohci_hcd: USB 1.1 'Open' Host Controller (OHCI) Driver [ 3.564281] ohci-platform: OHCI generic platform driver [ 3.564287] uhci_hcd: USB Universal Host Controller Interface driver [ 3.564345] uhci_hcd 0000:00:1a.0: setting latency timer to 64 [ 3.564347] uhci_hcd 0000:00:1a.0: UHCI Host Controller [ 3.564352] uhci_hcd 0000:00:1a.0: new USB bus registered, assigned bus number 3 [ 3.564378] uhci_hcd 0000:00:1a.0: irq 16, io base 0x0000f0c0 [ 3.564402] usb usb3: New USB device found, idVendor=1d6b, idProduct=0001 [ 3.564404] usb usb3: New USB device strings: Mfr=3, Product=2, SerialNumber=1 [ 3.564406] usb usb3: Product: UHCI Host Controller [ 3.564408] usb usb3: Manufacturer: Linux 3.11.0-12-generic uhci_hcd [ 3.564410] usb usb3: SerialNumber: 0000:00:1a.0 [ 3.564478] hub 3-0:1.0: USB hub found [ 3.564482] hub 3-0:1.0: 2 ports detected [ 3.564589] uhci_hcd 0000:00:1a.1: setting latency timer to 64 [ 3.564592] uhci_hcd 0000:00:1a.1: UHCI Host Controller [ 3.564597] uhci_hcd 0000:00:1a.1: new USB bus registered, assigned bus number 4 [ 3.564623] uhci_hcd 0000:00:1a.1: irq 21, io base 0x0000f0a0 [ 3.564647] usb usb4: New USB device found, idVendor=1d6b, idProduct=0001 [ 3.564649] usb usb4: New USB device strings: Mfr=3, Product=2, SerialNumber=1 [ 3.564651] usb usb4: Product: UHCI Host Controller [ 3.564653] usb usb4: Manufacturer: Linux 3.11.0-12-generic uhci_hcd [ 3.564654] usb usb4: SerialNumber: 0000:00:1a.1 [ 3.564727] hub 4-0:1.0: USB hub found [ 3.564730] hub 4-0:1.0: 2 ports detected [ 3.564834] uhci_hcd 0000:00:1a.2: setting latency timer to 64 [ 3.564837] uhci_hcd 0000:00:1a.2: UHCI Host Controller [ 3.564843] uhci_hcd 0000:00:1a.2: new USB bus registered, assigned bus number 5 [ 3.564863] uhci_hcd 0000:00:1a.2: irq 18, io base 0x0000f080 [ 3.564885] usb usb5: New USB device found, idVendor=1d6b, idProduct=0001 [ 3.564887] usb usb5: New USB device strings: Mfr=3, Product=2, SerialNumber=1 [ 3.564889] usb usb5: Product: UHCI Host Controller [ 3.564891] usb usb5: Manufacturer: Linux 3.11.0-12-generic uhci_hcd [ 3.564892] usb usb5: SerialNumber: 0000:00:1a.2 [ 3.564962] hub 5-0:1.0: USB hub found [ 3.564966] hub 5-0:1.0: 2 ports detected [ 3.565073] uhci_hcd 0000:00:1d.0: setting latency timer to 64 [ 3.565076] uhci_hcd 0000:00:1d.0: UHCI Host Controller [ 3.565081] uhci_hcd 0000:00:1d.0: new USB bus registered, assigned bus number 6 [ 3.565101] uhci_hcd 0000:00:1d.0: irq 23, io base 0x0000f060 [ 3.565124] usb usb6: New USB device found, idVendor=1d6b, idProduct=0001 [ 3.565127] usb usb6: New USB device strings: Mfr=3, Product=2, SerialNumber=1 [ 3.565128] usb usb6: Product: UHCI Host Controller [ 3.565130] usb usb6: Manufacturer: Linux 3.11.0-12-generic uhci_hcd [ 3.565132] usb usb6: SerialNumber: 0000:00:1d.0 [ 3.565195] hub 6-0:1.0: USB hub found [ 3.565198] hub 6-0:1.0: 2 ports detected [ 3.565303] uhci_hcd 0000:00:1d.1: setting latency timer to 64 [ 3.565306] uhci_hcd 0000:00:1d.1: UHCI Host Controller [ 3.565310] uhci_hcd 0000:00:1d.1: new USB bus registered, assigned bus number 7 [ 3.565329] uhci_hcd 0000:00:1d.1: irq 19, io base 0x0000f040 [ 3.565352] usb usb7: New USB device found, idVendor=1d6b, idProduct=0001 [ 3.565354] usb usb7: New USB device strings: Mfr=3, Product=2, SerialNumber=1 [ 3.565356] usb usb7: Product: UHCI Host Controller [ 3.565358] usb usb7: Manufacturer: Linux 3.11.0-12-generic uhci_hcd [ 3.565359] usb usb7: SerialNumber: 0000:00:1d.1 [ 3.565424] hub 7-0:1.0: USB hub found [ 3.565427] hub 7-0:1.0: 2 ports detected [ 3.565534] uhci_hcd 0000:00:1d.2: setting latency timer to 64 [ 3.565537] uhci_hcd 0000:00:1d.2: UHCI Host Controller [ 3.565541] uhci_hcd 0000:00:1d.2: new USB bus registered, assigned bus number 8 [ 3.565560] uhci_hcd 0000:00:1d.2: irq 18, io base 0x0000f020 [ 3.565584] usb usb8: New USB device found, idVendor=1d6b, idProduct=0001 [ 3.565587] usb usb8: New USB device strings: Mfr=3, Product=2, SerialNumber=1 [ 3.565588] usb usb8: Product: UHCI Host Controller [ 3.565590] usb usb8: Manufacturer: Linux 3.11.0-12-generic uhci_hcd [ 3.565592] usb usb8: SerialNumber: 0000:00:1d.2 [ 3.565658] hub 8-0:1.0: USB hub found [ 3.565661] hub 8-0:1.0: 2 ports detected ... [ 4.120014] usb 2-3: new high-speed USB device number 2 using ehci-pci ... [ 4.468908] usb 2-3: New USB device found, idVendor=046d, idProduct=0825 [ 4.468912] usb 2-3: New USB device strings: Mfr=0, Product=0, SerialNumber=2 [ 4.468914] usb 2-3: SerialNumber: AF582E10 ... [ 5.284019] usb 5-2: new full-speed USB device number 2 using uhci_hcd [ 5.465903] usb 5-2: New USB device found, idVendor=046d, idProduct=0b04 [ 5.465908] usb 5-2: New USB device strings: Mfr=1, Product=2, SerialNumber=0 [ 5.465911] usb 5-2: Product: Logitech BT Mini-Receiver [ 5.465914] usb 5-2: Manufacturer: Logitech [ 5.468948] hub 5-2:1.0: USB hub found [ 5.470898] hub 5-2:1.0: 3 ports detected [ 5.476096] Switched to clocksource tsc [ 5.712099] usb 7-2: new full-speed USB device number 2 using uhci_hcd [ 5.896366] usb 7-2: New USB device found, idVendor=046d, idProduct=c52b [ 5.896370] usb 7-2: New USB device strings: Mfr=1, Product=2, SerialNumber=0 [ 5.896372] usb 7-2: Product: USB Receiver [ 5.896374] usb 7-2: Manufacturer: Logitech [ 6.140016] usb 8-1: new full-speed USB device number 2 using uhci_hcd [ 6.324597] usb 8-1: New USB device found, idVendor=0738, idProduct=1708 [ 6.324603] usb 8-1: New USB device strings: Mfr=1, Product=2, SerialNumber=0 [ 6.324605] usb 8-1: Product: Mad Catz R.A.T.7 Mouse [ 6.324608] usb 8-1: Manufacturer: Mad Catz [ 6.564012] usb 8-2: new low-speed USB device number 3 using uhci_hcd [ 6.746602] usb 8-2: New USB device found, idVendor=1d57, idProduct=0010 [ 6.746608] usb 8-2: New USB device strings: Mfr=1, Product=2, SerialNumber=0 [ 6.746610] usb 8-2: Product: usb mouse with wheel [ 6.746613] usb 8-2: Manufacturer: HID-Compliant Mouse [ 7.337898] usb 5-2.2: new full-speed USB device number 3 using uhci_hcd [ 7.490902] usb 5-2.2: New USB device found, idVendor=046d, idProduct=c713 [ 7.490907] usb 5-2.2: New USB device strings: Mfr=1, Product=2, SerialNumber=3 [ 7.490910] usb 5-2.2: Product: Logitech BT Mini-Receiver [ 7.490913] usb 5-2.2: Manufacturer: Logitech [ 7.490915] usb 5-2.2: SerialNumber: 001F203BD6A7 [ 7.569898] usb 5-2.3: new full-speed USB device number 4 using uhci_hcd [ 7.722901] usb 5-2.3: New USB device found, idVendor=046d, idProduct=c714 [ 7.722906] usb 5-2.3: New USB device strings: Mfr=1, Product=2, SerialNumber=3 [ 7.722909] usb 5-2.3: Product: Logitech BT Mini-Receiver [ 7.722911] usb 5-2.3: Manufacturer: Logitech [ 7.722913] usb 5-2.3: SerialNumber: 001F203BD6A7 lsusb (more output): Bus 002 Device 002: ID 046d:0825 Logitech, Inc. Webcam C270 Bus 002 Device 001: ID 1d6b:0002 Linux Foundation 2.0 root hub Bus 008 Device 003: ID 1d57:0010 Xenta Bus 008 Device 002: ID 0738:1708 Mad Catz, Inc. Bus 008 Device 001: ID 1d6b:0001 Linux Foundation 1.1 root hub Bus 007 Device 002: ID 046d:c52b Logitech, Inc. Unifying Receiver Bus 007 Device 001: ID 1d6b:0001 Linux Foundation 1.1 root hub Bus 006 Device 001: ID 1d6b:0001 Linux Foundation 1.1 root hub Bus 001 Device 001: ID 1d6b:0002 Linux Foundation 2.0 root hub Bus 005 Device 004: ID 046d:c714 Logitech, Inc. diNovo Edge Keyboard Bus 005 Device 003: ID 046d:c713 Logitech, Inc. Bus 005 Device 002: ID 046d:0b04 Logitech, Inc. Bus 005 Device 001: ID 1d6b:0001 Linux Foundation 1.1 root hub Bus 004 Device 001: ID 1d6b:0001 Linux Foundation 1.1 root hub Bus 003 Device 001: ID 1d6b:0001 Linux Foundation 1.1 root hub More background. Before that I had a problem with logging in to GNOME. During which I upgraded all the packages at one point (apt-get upgrade) and it stopped booting at all (it didn't get to login screen). Then I fixed PATH issue and now I've got this usb-not-working issue. I tried reinstalling kernel, to no effect. Is there anything else I can do to fix or diagnose the problem?

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• Have you used the ExecutionValue and ExecValueVariable properties?

  The ExecutionValue execution value property and it’s friend ExecValueVariable are a much undervalued feature of SSIS, and many people I talk to are not even aware of their existence, so I thought I’d try and raise their profile a bit. The ExecutionValue property is defined on the base object Task, so all tasks have it available, but it is up to the task developer to do something useful with it. The basic idea behind it is that it allows the task to return something useful and interesting about what it has performed, in addition to the standard success or failure result. The best example perhaps is the Execute SQL Task which uses the ExecutionValue property to return the number of rows affected by the SQL statement(s). This is a very useful feature, something people often want to capture into a variable, and start using the result set options to do. Unfortunately we cannot read the value of a task property at runtime from within a SSIS package, so the ExecutionValue property on its own is a bit of a let down, but enter the ExecValueVariable and we have the perfect marriage. The ExecValueVariable is another property exposed through the task (TaskHost), which lets us select a SSIS package variable. What happens now is that when the task sets the ExecutionValue, the interesting value is copied into the variable we set on the ExecValueVariable property, and a variable is something we can access and do something with. So put simply if the ExecutionValue property value is of interest, make sure you create yourself a package variable and set the name as the ExecValueVariable. Have  look at the 3 step guide below: 1 Configure your task as normal, for example the Execute SQL Task, which here calls a stored procedure to do some updates. 2 Create variable of a suitable type to match the ExecutionValue, an integer is used to match the result we want to capture, the number of rows. 3 Set the ExecValueVariable for the task, just select the variable we created in step 2. You need to do this in Properties grid for the task (Short-cut key, select the task and press F4) Now when we execute the sample task above, our variable UpdateQueueRowCount will get the number of rows we updated in our Execute SQL Task. I’ve tried to collate a list of tasks that return something useful via the ExecutionValue and ExecValueVariable mechanism, but the documentation isn’t always great. Task ExecutionValue Description Execute SQL Task Returns the number of rows affected by the SQL statement or statements. File System Task Returns the number of successful operations performed by the task. File Watcher Task Returns the full path of the file found Transfer Error Messages Task Returns the number of error messages that have been transferred Transfer Jobs Task Returns the number of jobs that are transferred Transfer Logins Task Returns the number of logins transferred Transfer Master Stored Procedures Task Returns the number of stored procedures transferred Transfer SQL Server Objects Task Returns the number of objects transferred WMI Data Reader Task Returns an object that contains the results of the task. Not exactly clear, but I assume it depends on the WMI query used.

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• Is this an effective monetization method for an Android game? [on hold]

  - by Matthew Page

  The short version: I plan to make an Android puzzle game where the user tries to get 3-6 numbers to their predetermined goal numbers. The free version of the app will have three predetermined levels (easy, medium, hard). The full version ($0.99, probably) will have a level generator where there will be unlimited easy, medium, or hard levels, as well as a custom difficulty option where users can set specific vales to the number of numbers to equate to their goal, the number of buttons to use, etc. Users will also have the option to get a one-time "hint" for a fee of $0.49, or unlimited hints for a one-time fee of $2.99. The long version: Mechanics of Game and Victory The application is a number puzzle. When the user begins a new game, depending on the input by the user, between 3 and 6 numbers show up on the top of the screen, and between 3 and 6 buttons show up on the bottom of the screen. The buttons all have two options: to increase every number the same way, or decrease every number the same way. The buttons either use addition / subtraction, multiplication / division, or exponents / roots, all depending on the number displayed on the button. Addition buttons are green, multiplication buttons are blue, and exponential buttons are red. The user wins when all of the numbers displayed on the screen equate to their goal number, displayed below each number. Monetization If the user is playing the full (priced) version of the app, upon the start of the game, the user will be confronted with a dialogue asking for the number of buttons and the number of numbers to equate in the game. Then, based on the user input, a random puzzle will be generated. If the user is playing the free version of the app, the user will be asked to either play an “easy”, “hard”, or “expert” puzzle. A pre-determined puzzle from each category will be used in the game. If the user has played that puzzle before, a dialogue will show saying this to the user and advertising the full version of the app. The full version of the app will also be advertised upon the successful or in successful completion of a puzzle. Upon exiting this advertisement, another full screen advertisement will appear from a third party. Also, the solution to the puzzle should be stored by the program, and if the user pays a small fee, he/she can see a hint to the solution to the program. In the free version of the app, the user may use their first hint for free. Also, the user can use unlimited hints for a slightly larger fee. Is this an effective monetization method?

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