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• Regular Expression: Match untill pattern is found

  - by ZafarYousafi

  Hi, I want to extract the status from the string untill I found a timespan. My input is something like "Something in start but not with this keyword of sure. STATUS: My Status Is Here Which can be anything but timespan 23:59:01 and so on. I want to extract the string after STATUS: untill 23:59:01 is found. How can i achieve this through regex. this 23:59:01 is a timespan and it is always in this format hh:mm:ss

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• Substitute all matches with values in Ruby regular expression

  - by Lewisham

  Hi all, I'm having a problem with getting a Ruby string substitution going. I'm writing a preprocessor for a limited language that I'm using, that doesn't natively support arrays, so I'm hacking in my own. I have a line: x[0] = x[1] & x[1] = x[2] I want to replace each instance with a reformatted version: x__0 = x__1 & x__1 = x__2 The line may include square brackets elsewhere. I've got a regex that will match the array use: array_usage = /(\w+)\[(\d+)\]/ but I can't figure out the Ruby construct to replace each instance one by one. I can't use .gsub() because that will match every instance on the line, and replace every array declaration with whatever the first one was. .scan() complains that the string is being modified if you try and use scan with a .sub()! inside a block. Any ideas would be appreciated!

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• Problem with changing td's html in JQuery.

  - by bugbug

  I want to change text in table td from 1,1,1 to 1,2,3 with following code, But it not seem to work. what is wrong in my code? This is my JavaScript function. function reorder(targetId){ var i = 1; jQuery.find(targetId).each(function(){ jQuery(this).attr("innerHTML", i); i ++; }); } My html code. <form> <input type="button" onClick="reorder('#index');" value="test"/> <table> <tr><td id="index">1</td></tr> <tr><td id="index">1</td></tr> <tr><td id="index">1</td></tr> </table> </form>

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• Django store regular expression in DB which then gets evaluated on page

  - by John

  Hi, I want to store a number of url patterns in my django model which a user can provide parameters to which will create a url. For example I might store these 3 urls in my db where %s is the variable parameter provided by the user: www.thisissomewebsite.com?param=%s www.anotherurl/%s/ www.lastexample.co.uk?param1=%s&fixedparam=2 As you can see from these examples the parameter can appear anywhere in the string and not in a fixed position. I have 2 models, one holds the urls and one holds the variables: class URLPatterns(models.Model): pattern = models.CharField(max_length=255) class URLVariables(models.Model): pattern = models.ForeignKey(URLPatterns) param = models.CharField(max_length=255) What would be the best way to generate these urls by replacing the %s with the variable in the database. would it just be a simple replace on the string e.g: urlvariable = URLVariable.objects.get(pk=1) pattern = url.pattern url = pattern.replace("%s", urlvariable.param) or is there a better way? Thanks

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• jQuery validation required( dependency-expression ) only 1 input validating

  - by user331884

  <script type="text/javascript"> $(function () { $("#form1").validate(); $("#survey1 .response").rules("add", { required: function () { return $('#choices').val() != '' } }); }); </script> <form id="form1" runat="server"> <div id="survey1"> <asp:DropDownList ID="choices" runat="server"> <asp:ListItem Value="">--Select--</asp:ListItem> <asp:ListItem>1</asp:ListItem> <asp:ListItem>2</asp:ListItem> </asp:DropDownList> <hr /> Response 1<br /> <asp:TextBox ID="TextBox1" runat="server" TextMode="MultiLine" Rows="6" CssClass="response"></asp:TextBox> <hr /> Response 2<br /> <asp:TextBox ID="TextBox2" runat="server" TextMode="MultiLine" Rows="6" CssClass="response"></asp:TextBox> </div></form> Only the first textbox gets validated. Am I missing something?

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• regular expression for decimal numbers?

  - by James123

  I need a validation regex for decimal. It should allow upto 5 digits after decimal. Allow: 1 1.0 12.0 12.01 123.01 1,123.01 1,123.013 21,123.01234 3,21,123.01234 How Can I do regex for this?

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• Expected Expression

  - by coffeeaddict

  I cannot figure out what I did or did not do here syntactically to cause this error. I don't see what's missing: function ShowWaitMessage(button) { var isValid; if (buttonSelected()) { showWaitMessage(button, "showMessage1"); isValid = true; } else { Page_ClientValidate(); if (Page_IsValid) { showWaitMessage(button, "showMessage2"); isValid = true; } } return isValid; }

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• PHP Regular expression flags

  - by incrediman

  Can someone explain what the 'e' flag does, or link me to somewhere that does? I couldn't find anything via google. Example: preg_replace("/a(b?)c/e", "search_foo_term('\$1')", $str);

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• Cadr of a list involving assoc function

  - by user3619045

  I have looked around on the net and cant find an answer to my query. I would really appreciate if someone could provide a good answer without down rating this post. In Lisp car, cdr are used on data mode like '(whatever here) which makes sense to me. Now, in the book Land of Lisp the author is explaining how to build a text engine and suddenly he uses the following description to make a function. (defun describe-location (location nodes) (cadr (assoc location nodes))) Can I ask why is he doing a cadr on a list and how come it provides a response and not an error? shouldn't it be a data mode i.e with a quote in front of the opening bracket '(whatever here)? and also why is he using assoc as in (assoc location nodes) and not (assoc 'garden *nodes*) Isn't the second correct way to use assoc ? I may be missing the big picture and as such would really appreciate someone explaining these key points please. Many thanks!

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• Regular Expression

  - by Blanca

  Hi! i would like to avoid texts like this one: height="49" with a regular expresion. I tought in .replaceAll("\s*="*"",""); (replaceAll is used as a method in a java class), but eclipse don't allowed me to do that. Any other suggestion?? tx!

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• Regular Expression Program

  - by david robers

  Hi I have the following text: SMWABCCA ABCCAEZZRHM NABCCAYJG XABCCA ABCCADK ABCCASKIYRH ABCCAKY PQABCCAK ABCCAKQ This method takes a regex in out by the user and SHOULD print out the Strings it applies to but seems to print out something completely different: private void matchIt(String regex) { Pattern p = Pattern.compile(regex); Matcher m = null; boolean found = false; for(int i = 0; i < data.length; i++){ m = p.matcher(data[i]); if(m.find()){ out.println(data[i]); found = true; } } if(!found){ out.println("Pattern Not Found"); } } When inputting "[C]" It outputs: SMWABCCA ABCCAEZZRHM NABCCAYJG XABCCA ABCCADK ABCCASKIYRH ABCCAKY PQABCCAK ABCCAKQ Any ideas why? I think I'm using m.find() improperly...

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• value of the expression in C#

  - by picnic4u

  what is out put of the following code int a=2,b=3,c=4; b=(c+2,a+4); Response.Write("Value of b= "+b);

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• dropping characters from regular expression groups

  - by tcurdt

  The goal: I want to convert a number from the format "10.234,56" to "10234.56" Using this simple approach almost gets us there /([\d\.]+),(\d\d)/ => '\1.\2' The problem is that the first group of the match (of course) still contains the '.' character. So questions are: Is it possible to exclude a character from the group somehow? How would you solve this with a single regexp (I know this is a trivial problem when not using a single regexp)

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• Turning logical expression around

  - by BluePrint

  I have the following code: bool s = true; for (...; ...; ...) { // code that defines A, B, C, D // and w, x, y, z if (!(A < w) && s == true) { s = false; } if (!(B < x) && s == true) { s = false; } if (!(C < y) && s == true) { s = false; } if (!(D < z) && s == true) { s = false; } } This code is working well. However, I want to, for several (unimportant) reasons, change the code so that I can initiate s = false; and set it to true inside the if-statement. It tried the following: bool s = false; for (...; ...; ...) { // code that defines A, B, C, D // and w, x, y, z if (A >= w && s == false) { s = true; } if (B >= x && s == false) { s = true; } if (C >= y && s == false) { s = true; } if (D >= z && s == false) { s = true; } } However, this is not working properly as the code above is working. I know thought wrong somewhere in the logic, but I can't figure out where. Does anbyone see my probably obvious error? EDIT: Added three more if-statemets. Missed them since they were commented away.

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• jquery: match regular expression

  - by teggy

  In the following: <span>This cost $15.99 per item</span> how do I return "$15.99" using jquery? The value can also be for example "$7".

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• regular expression - function body extracting

  - by Altariste

  Hi, In Python script,for every method definition in some C++ code of the form: return_value ClassName::MethodName(args) {MehodBody} ,I need to extract three parts: the class name, the method name and the method body for further processing. Finding and extracting the ClassName and MethodName is easy, but is there any simple way to extract the body of the method? With all possible '{' and '}' inside it? Or are regexes unsuitable for such task?

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• python and regular expression with unicode

  - by bsn

  I need to delete some unicode symbols from the string '?????? ??????? ???????????? ??????????' I know they exist here for sure. I try: re.sub('([\u064B-\u0652\u06D4\u0670\u0674\u06D5-\u06ED]+)', '', '?????? ??????? ???????????? ??????????') but it doesn't work. String stays the same. ant suggestion what i do wrong?

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• Why is writeSTRef faster than if expression?

  - by wenlong

  writeSTRef twice for each iteration fib3 :: Int -> Integer fib3 n = runST $ do a <- newSTRef 1 b <- newSTRef 1 replicateM_ (n-1) $ do !a' <- readSTRef a !b' <- readSTRef b writeSTRef a b' writeSTRef b $! a'+b' readSTRef b writeSTRef once for each iteration fib4 :: Int -> Integer fib4 n = runST $ do a <- newSTRef 1 b <- newSTRef 1 replicateM_ (n-1) $ do !a' <- readSTRef a !b' <- readSTRef b if a' > b' then writeSTRef b $! a'+b' else writeSTRef a $! a'+b' a'' <- readSTRef a b'' <- readSTRef b if a'' > b'' then return a'' else return b'' Benchmark, given n = 20000: benchmarking 20000/fib3 mean: 5.073608 ms, lb 5.071842 ms, ub 5.075466 ms, ci 0.950 std dev: 9.284321 us, lb 8.119454 us, ub 10.78107 us, ci 0.950 benchmarking 20000/fib4 mean: 5.384010 ms, lb 5.381876 ms, ub 5.386099 ms, ci 0.950 std dev: 10.85245 us, lb 9.510215 us, ub 12.65554 us, ci 0.950 fib3 is a bit faster than fib4.

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• C#: Using regular expression (Regex) to duplicate a specific character in a string

  - by user3703944

  Anyone know how to use regex to duplicate a specific character in a string? I have a path that is entered like this: C:/Example/example I would like to use regex (or any other method) to display it like this: C://Example//example Is it possible? This is where I'm getting the file path private void btnSearchImage_Click_1(object sender, EventArgs e) { OpenFileDialog ofd = new OpenFileDialog(); ofd.Filter = "Image Files(*.jpg; *.jpeg; *.gif; *.bmp)|*.jpg; *.jpeg; *.gif; *.bmp"; if (ofd.ShowDialog() == System.Windows.Forms.DialogResult.OK) { string filenName = ofd.FileName; pictureBox1.Image = new Bitmap(filenName); string path = filenName; txtimgPath.Text = path; } } Thanks

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• Regex if-else expression

  - by craig

  I'm trying to extract the # of minutes from a text field using Oracle's REGEXP_SUBSTR() function. Data: Treatment of PC7, PT1 on left. 15 min. 15 minutes. 15 minutes 15 mins. 15 mins 15 min. 15 min 15min 15 In each case, I'm hoping to extract the '15' part of the string. Attempts: \d+ gets all of the numeric values, including the '7' and '1', which is undesirable. (\d)+(?=\ ?min) get the '15' from all rows except the last. (?((\d)+(?=\ ?min))((\d)+(?=\ ?min))|\d+), an if-else statement, doesnt' match anything. What is wrong with my if-else statement?

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• Matching Word with regular expression

  - by lbar

  I have the following text file: ... "somewords MYWORD";123123123123 "someother MYWORDOTHER";456456456456 "somedifferent MYWORDDIFFERENT";789789789 ... i need to match the word MYWORD, MYWORDOTHER, MYWORDDIFFERENT and then substitute the space before this word with ";". Someone can figure out a regex? I have done something like that: +[^ ][^ ][^ ][^ ][^ ][^ ][^ ]"; but this works only with a specific word lenght. I need to modify to get any word of any leght. Any help? Thank you.

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• Regular Expression to match a string

  - by Adam Witko

  Hi, I've got two possible string inputs that my application will receive, and if it matches the following two strings, I need it regex.ismatch() to return true: "User * has logged out" "User * has joined" I'm not that good at regex and just can't figure out how to go about matching the above. Any help would be great!!!

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• Regular expression - skip string in quotes using sed

  - by milano

  I have string like this: "Some standard text CONST_INSIDE_QUOTES" blah blah CONST "There might be another quotes" The thing is, that i want to replace all constants in string with some text, but it mustn't be applied on constants inside text in quotes. I have this regex: sed "s/([A-Z][A-Z0-9_]*)([^a-z])/<span class=\"const\"\1<\/span\2/g" which of course works for all consts. Any ideas how to exclude its apply on quotes constants? Unfortunately sed only...

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• Regular expression help

  - by dmr

  I need to do a find and replace in Notepad of Err.Number, canBeAnything, canBeAnything, Err.Description (where canBeAnything is just what it says) with Err.Number, "canBeAnything", "canBeAnything", Err.Description (basically, put quotes around canBeAnything) I got as far as the find Err.Number, .+, .+, Err.Description But I'm stuck on the replace. Any suggestions?

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• What charectar range would this represent (regular expression)?

  - by Alex

  Recently I came across a character range that was the following: [/-+] My very simple question is, is this even a valid charectar range? If so, what range of charectars would it match?

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