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  • Save File Contents to Variable in Python3.3 [migrated]

    - by Neo_Programmer
    I have a Python3.3 script that seems to not work. The script will search for an XML pattern and then print the results to the screen. I am using Ubuntu 12.10 (AMD64) and python3.3. I prefer to use regex with XML, so please disregard this unconventional form of programming. #!/usr/bin/python3.3 import io, re openfile = open('./temp/xaiml/temp_db1.xaiml', 'r') TEMPDB = openfile.read() OUTPUT = print(''.join(re.findall('<cgy><prn>.*_.*<\/prn>.*<\/cgy>', TEMPDB, flags=re.I)))

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  • Text Classification Implementation

    - by Hearty
    I've been trying to implement a text classification system. It needs to read a text file, and extract the words and the word frequency. So far, I've been planning to parse the words, put them in a dictionary and save it to an XML file. I am using C++/CLI. Is this a good implementation or is there a simpler or better implementation? May be related question (some code implementation): http://stackoverflow.com/questions/10631309/save-dictionary-to-xml-file

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  • How to add an XML parameter to a stored procedure in C#?

    - by salvationishere
    I am developing a C# web application in VS 2008 which interacts with my Adventureworks database in my SQL Server 2008. Now I am trying to add new records to one of the tables which has an XML column in it. How do I do this? This is the error I'm getting: System.Data.SqlClient.SqlException was caught Message="XML Validation: Text node is not allowed at this location, the type was defined with element only content or with simple content. Location: /" Source=".Net SqlClient Data Provider" ErrorCode=-2146232060 Class=16 LineNumber=22 Number=6909 Procedure="AppendDataC" Server="." State=1 StackTrace: at System.Data.SqlClient.SqlConnection.OnError(SqlException exception, Boolean breakConnection) at System.Data.SqlClient.SqlInternalConnection.OnError(SqlException exception, Boolean breakConnection) at System.Data.SqlClient.TdsParser.ThrowExceptionAndWarning(TdsParserStateObject stateObj) at System.Data.SqlClient.TdsParser.Run(RunBehavior runBehavior, SqlCommand cmdHandler, SqlDataReader dataStream, BulkCopySimpleResultSet bulkCopyHandler, TdsParserStateObject stateObj) at System.Data.SqlClient.SqlCommand.FinishExecuteReader(SqlDataReader ds, RunBehavior runBehavior, String resetOptionsString) at System.Data.SqlClient.SqlCommand.RunExecuteReaderTds(CommandBehavior cmdBehavior, RunBehavior runBehavior, Boolean returnStream, Boolean async) at System.Data.SqlClient.SqlCommand.RunExecuteReader(CommandBehavior cmdBehavior, RunBehavior runBehavior, Boolean returnStream, String method, DbAsyncResult result) at System.Data.SqlClient.SqlCommand.InternalExecuteNonQuery(DbAsyncResult result, String methodName, Boolean sendToPipe) at System.Data.SqlClient.SqlCommand.ExecuteNonQuery() at ADONET_namespace.ADONET_methods.AppendDataC(DataRow d, Hashtable ht) in C:\Documents and Settings\Admin\My Documents\Visual Studio 2008\Projects\AddFileToSQL\AddFileToSQL\ADONET methods.cs:line 212 InnerException: And this is a portion of my code in C#: try { SqlConnection conn2 = new SqlConnection(connString); SqlCommand cmd = conn2.CreateCommand(); cmd.CommandText = "dbo.AppendDataC"; cmd.CommandType = CommandType.StoredProcedure; cmd.Connection = conn2; ... sqlParam10.SqlDbType = SqlDbType.VarChar; SqlParameter sqlParam11 = cmd.Parameters.AddWithValue("@" + ht["@col11"], d[10]); sqlParam11.SqlDbType = SqlDbType.VarChar; SqlParameter sqlParam12 = cmd.Parameters.AddWithValue("@" + ht["@col12"], d[11]); sqlParam12.SqlDbType = SqlDbType.Xml; ... conn2.Open(); cmd.ExecuteNonQuery(); //This is the line it fails on and then jumps //to the Catch statement conn2.Close(); errorMsg = "The Person.Contact table was successfully updated!"; } catch (Exception ex) { Right now in my text input MDF file I have the XML parameter as: '<Products><id>3</id><id>6</id><id>15</id></Products>' Is this valid format for XML?

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  • Validate an Xml file against a DTD with a proxy. C# 2.0

    - by Chris Dunaway
    I have looked at many examples for validating an XML file against a DTD, but have not found one that allows me to use a proxy. I have a cXml file as follows (abbreviated for display) which I wish to validate: <?xml version="1.0" encoding="utf-8"?> <!DOCTYPE cXML SYSTEM "http://xml.cxml.org/schemas/cXML/1.2.018/InvoiceDetail.dtd"> <cXML payloadID="123456" timestamp="2009-12-10T10:05:30-06:00"> <!-- content snipped --> </cXML> I am trying to create a simple C# program to validate the xml against the DTD. I have tried code such as the following but cannot figure out how to get it to use a proxy: private static bool isValid = false; static void Main(string[] args) { try { XmlTextReader r = new XmlTextReader(args[0]); XmlReaderSettings settings = new XmlReaderSettings(); XmlDocument doc = new XmlDocument(); settings.ProhibitDtd = false; settings.ValidationType = ValidationType.DTD; settings.ValidationEventHandler += new ValidationEventHandler(v_ValidationEventHandler); XmlReader validator = XmlReader.Create(r, settings); while (validator.Read()) ; validator.Close(); // Check whether the document is valid or invalid. if (isValid) Console.WriteLine("Document is valid"); else Console.WriteLine("Document is invalid"); } catch (Exception ex) { Console.WriteLine(ex.ToString()); } } static void v_ValidationEventHandler(object sender, ValidationEventArgs e) { isValid = false; Console.WriteLine("Validation event\n" + e.Message); } The exception I receive is System.Net.WebException: The remote server returned an error: (407) Proxy Authentication Required. which occurs on the line while (validator.Read()) ; I know I can validate against a DTD locally, but I don't want to change the xml DOCTYPE since that is what the final form needs to be (this app is solely for diagnostic purposes). For more information about the cXML spec, you can go to cxml.org. I appreciate any assistance. Thanks

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  • What is the problems for my xml file format ?

    - by python
    <? $xml="<?xml version='1.0' encoding='UTF-8' standalone='no'?> <Document> <pain.001.001.02> <books> <book> <qty>12</qty> <title>C++</title> </book> <book> <qty>21</qty> <title>PHP</title> </book> </books> <books> <book> <qty>25</qty> <title>Java</title> </book> <book> <qty>32</qty> <title>Python</title> </book> <book> <qty>22</qty> <title>History</title> </book> </books> </pain.001.001.02> </Document> "; $doc = new DOMDOcument; $doc->loadxml($xml); $xpath = new DOMXpath($doc); $arr = array( array( '12;C++', '21;PHP'), array( '25;Java', '32;Python' ) ); # Remove elements based on qty and title foreach($arr as $items) { foreach($items as $item) { list($qty, $title) = explode(';', $item); foreach($xpath->query('//pain.001.001.02/books/book[title="'.$title.'"][qty="'.$qty.'"]') as $book) { $book->parentNode->removeChild($book); } } } # Remove empty <books> foreach($xpath->query('pain.001.001.02/books[count(book)=0]') as $empty) { $empty->parentNode->removeChild($empty); } header('Content-type: text/xml'); echo $doc->savexml(); ?> If I put <Document> in the xml document , get the expected result BUT If change <Document> to <Document xmlns="urn:iso:std:iso:20022:tech:xsd:pain.001.001.02"> get UNEXPECTED RESULT? Do you have any idea? thanks

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  • In .NET Xml Serialization, is it possible to serialize a class with an enum property with different

    - by Lasse V. Karlsen
    I have a class, containing a list property, where the list contains objects that has an enum property. When I serialize this, it looks like this: <?xml version="1.0" encoding="ibm850"?> <test> <events> <test-event type="changing" /> <test-event type="changed" /> </events> </test> Is it possible, through attributes, or similar, to get the Xml to look like this? <?xml version="1.0" encoding="ibm850"?> <test> <events> <changing /> <changed /> </events> </test> Basically, use the property value of the enum as a way to determine the tag-name? Is using a class hierarchy (ie. creating subclasses instead of using the property value) the only way? Edit: After testing, it seems even a class-hierarchy won't actually work. If there is a way to structure the classes to get the output I want, even with sub-classes, that is also an acceptable answer. Here's a sample program that will output the above Xml (remember to hit Ctrl+F5 to run in Visual Studio, otherwise the program window will close immediately): using System; using System.Collections.Generic; using System.Xml.Serialization; namespace ConsoleApplication18 { public enum TestEventTypes { [XmlEnum("changing")] Changing, [XmlEnum("changed")] Changed } [XmlType("test-event")] public class TestEvent { [XmlAttribute("type")] public TestEventTypes Type { get; set; } } [XmlType("test")] public class Test { private List<TestEvent> _Events = new List<TestEvent>(); [XmlArray("events")] public List<TestEvent> Events { get { return _Events; } } } class Program { static void Main(string[] args) { Test test = new Test(); test.Events.Add(new TestEvent { Type = TestEventTypes.Changing }); test.Events.Add(new TestEvent { Type = TestEventTypes.Changed }); XmlSerializer serializer = new XmlSerializer(typeof(Test)); XmlSerializerNamespaces ns = new XmlSerializerNamespaces(); ns.Add("", ""); serializer.Serialize(Console.Out, test, ns); } } }

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  • How to set up default schema name in JPA configuration?

    - by Roman
    I found that in hibernate config file we could set up parameter hibernate.default_schema: <hibernate-configuration> <session-factory> ... <property name="hibernate.default_schema">myschema</property> ... </session-factory> </hibernate-configuration> Now I'm using JPA and I want to do the same. Otherwise I have to add parameter schema to each @Table annotation like: @Entity @Table (name = "projectcategory", schema = "SCHEMANAME") public class Category implements Serializable { ... } As I understand this parameter should be somewhere in this part of configuration: <bean id="domainEntityManagerFactory" class="org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean"> <property name="persistenceUnitName" value="JiraManager"/> <property name="dataSource" ref="domainDataSource"/> <property name="jpaVendorAdapter"> <bean class="org.springframework.orm.jpa.vendor.HibernateJpaVendorAdapter"> <property name="generateDdl" value="false"/> <property name="showSql" value="false"/> <property name="databasePlatform" value="${hibernate.dialect}"/> </bean> </property> </bean> <bean id="domainDataSource" class="com.mchange.v2.c3p0.ComboPooledDataSource" destroy-method="close"> <property name="driverClass" value="${db.driver}" /> <property name="jdbcUrl" value="${datasource.url}" /> <property name="user" value="${datasource.username}" /> <property name="password" value="${datasource.password}" /> <property name="initialPoolSize" value="5"/> <property name="minPoolSize" value="5"/> <property name="maxPoolSize" value="15"/> <property name="checkoutTimeout" value="10000"/> <property name="maxStatements" value="150"/> <property name="testConnectionOnCheckin" value="true"/> <property name="idleConnectionTestPeriod" value="50"/> </bean> ... but I can't find its name in google. Any ideas?

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  • Is there any better IDOMImplementation other than MSXML?

    - by Chau Chee Yang
    There are 3 IDOMImplementation available in Delphi: MSXML Xerces XML ADOM XML v4 MSXML is the default IDOMImplementation. My test is count the time need to load a 10MB xml file. I use a Delphi unit generated from a XSD using XML data binding to load the xml file. This unit has 3 common function: function Getmenubar(Doc: IXMLDocument): IXMLMenubarType; function Loadmenubar(const FileName: WideString): IXMLMenubarType; function Newmenubar: IXMLMenubarType; I learn from the web that some comment that MSXML's overhead is high that it doesn't perform if compare to other XML parser. However, my study shows that MSXML is the best among others. Xerces XML 2nd and ADOM XML v4 the worst: MSXML - 0.6410 seconds Xerces XML - 2.4220 seconds ADOM XML v4 - 67.50 seconds I also come across with OmniXML that claim to have much better performance compare to MSXML but I never success using it with the unit generated by XML data binding. Is there any other vendor that implement IDOMImplementation of Delphi that work much better than MSXML? I am using Delphi 2010 and Windows 7.

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  • How to add DOCTYPE and xml processing instructions when marshalling with JAXB?

    - by Juha Syrjälä
    I am marshalling (serializing) JAXB beans to output stream. How can I add DOCTYPE declaration and xml processing instructions to ouput? I am doing currently marshalling like this: JAXBContext jaxbContext = JAXBContext.newInstance("com.example.package"); Marshaller marshaller = jaxbContext.createMarshaller(); marshaller.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT, Boolean.TRUE); SchemaFactory schemaFactory = SchemaFactory.newInstance("http://www.w3.org/2001/XMLSchema"); Schema schema = schemaFactory.newSchema(schemaSource); marshaller.setSchema(schema); marshaller.marshal(object, output); I'd like have output that looks something like this: <?xml version="1.0" encoding="UTF-8"?> <!DOCTYPE Something SYSTEM "some.dtd"> <?xml-stylesheet type="text/xsl" href="some.xsl"?> JAXB bean are generated code so I don't want to change them. There are some undocumented tricks to add the xml processing instructions and doctype. But what is the preferred or right way to do this?

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  • externalizing junit stub objects.

    - by Ajay
    Hi!    In my project we created stub files for testing junits in java(factories) itself. However, we have to externalize these stubs. After seeing a number of serializers/deserializers, we settled on using XStream to serialize and deserialize these stub objects. XStream works like a charm. Its pretty good at what it claims to be. Previously, we had a single factory class say AFactory which produced all the stubs needed for testing different test cases. Now when externalizing each of the stub generated, we hit a road block. We had to create 1 xml file for each stub produced by the factory. For example, public final class AFactory{ public static A createStub1(){ /*Code here */} public static A createStub2(){ /*Code here */} public static A createStub3(){ /*Code here */} } Now, when trying to move this stubs to external files, we had to create 1 xml file for each stub created(A-stub1.xml, A-stub2.xml and A-stub3.xml). The problem with this approach is that, it leads to proliferation of xml stub files. I was thinking, how about keeping all the stubs related to a single bean class in a single xml file. <?xml version="1.0"?> <stubs class="A"> <stub id="stub1"> <!-- Here comes the externalized xml stub representation --> </stub> <stub id="stub2"> </stub> </stubs> Is there a framework which allows you keep all the stub in xml representation in a single xml file as above ? Or What do you guys suggest should be the right approach to adhere to ?

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  • Accessing an object's fields without an active session

    - by Dave
    I'm using Hibernate 4.0.1.Final. Is it possible to access an object's fields if that object has been loaded via the org.hibernate.Session.load(Class clazz, Serializable id) method and there is no active session? I use this code to access an object by id … protected Object find(Class clazz, Serializable id) { Object obj = null; try { startOperation(); obj = session.load(clazz, id); tx.commit(); } catch (HibernateException e) { handleException(e); } finally { session.close(); } return obj; } but if I have that object without an active session, like with this code … final Organization foundOrg = orgDao.findById(org.getOrganizationId()); System.out.println(foundOrg.getName()); I get this error on the "System.out" line … org.hibernate.LazyInitializationException: could not initialize proxy - no Session at org.hibernate.proxy.AbstractLazyInitializer.initialize(AbstractLazyInitializer.java:149) at org.hibernate.proxy.AbstractLazyInitializer.getImplementation(AbstractLazyInitializer.java:195) at org.hibernate.proxy.pojo.javassist.JavassistLazyInitializer.invoke(JavassistLazyInitializer.java:185) at org.myco.myproject.orgsclient.model.Organization_$$_javassist_0.getName(Organization_$$_javassist_0.java) at org.myco.myproject.orgsclient.dao.OrganizationDAOTest.testInsertSchool(OrganizationDAOTest.java:43) at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method) at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:39) at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:25) at java.lang.reflect.Method.invoke(Method.java:597) at org.junit.runners.model.FrameworkMethod$1.runReflectiveCall(FrameworkMethod.java:44) at org.junit.internal.runners.model.ReflectiveCallable.run(ReflectiveCallable.java:15) at org.junit.runners.model.FrameworkMethod.invokeExplosively(FrameworkMethod.java:41) at org.junit.internal.runners.statements.InvokeMethod.evaluate(InvokeMethod.java:20) at org.junit.internal.runners.statements.RunBefores.evaluate(RunBefores.java:28) at org.junit.runners.BlockJUnit4ClassRunner.runChild(BlockJUnit4ClassRunner.java:76) at org.junit.runners.BlockJUnit4ClassRunner.runChild(BlockJUnit4ClassRunner.java:50) at org.junit.runners.ParentRunner$3.run(ParentRunner.java:193) at org.junit.runners.ParentRunner$1.schedule(ParentRunner.java:52) at org.junit.runners.ParentRunner.runChildren(ParentRunner.java:191) at org.junit.runners.ParentRunner.access$000(ParentRunner.java:42) at org.junit.runners.ParentRunner$2.evaluate(ParentRunner.java:184) at org.junit.runners.ParentRunner.run(ParentRunner.java:236) at org.eclipse.jdt.internal.junit4.runner.JUnit4TestReference.run(JUnit4TestReference.java:50) at org.eclipse.jdt.internal.junit.runner.TestExecution.run(TestExecution.java:38) at org.eclipse.jdt.internal.junit.runner.RemoteTestRunner.runTests(RemoteTestRunner.java:467) at org.eclipse.jdt.internal.junit.runner.RemoteTestRunner.runTests(RemoteTestRunner.java:683) at org.eclipse.jdt.internal.junit.runner.RemoteTestRunner.run(RemoteTestRunner.java:390) at org.eclipse.jdt.internal.junit.runner.RemoteTestRunner.main(RemoteTestRunner.java:197)

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  • How to register a custom type in Hibernate using org.springframework.orm.hibernate4.LocalSessionFactoryBean

    - by Luis
    I'm migrating from hibernate 3 to hibernate 4, In hibernate 3 the way I was registering a custom type was: public class AnnotationSessionFactoryBean extends org.springframework.orm.hibernate3.annotation.AnnotationSessionFactoryBean { private Collection<? extends BasicType> customTypes; public Collection<? extends BasicType> getCustomTypes() { return customTypes; } public void setCustomTypes(Collection<? extends BasicType> customTypes) { this.customTypes = customTypes; } @Override protected Configuration newConfiguration() throws HibernateException { Configuration configuration = super.newConfiguration(); if (CollectionUtils.hasEntries(customTypes)) { for (BasicType customType:customTypes) { configuration.registerTypeOverride(customType); } } return configuration; }} I'm now trying to do the same operation but using hibernate 4, my question is how is the best way to do this? since I dont have access do change configuration when using "org.springframework.orm.hibernate4.LocalSessionFactoryBean" instead of "org.springframework.orm.hibernate3.annotation.AnnotationSessionFactoryBean". Thanks

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  • How to create an XML document from a .NET object?

    - by JL
    I have the following variable that accepts a file name: var xtr = new XmlTextReader(xmlFileName) { WhitespaceHandling = WhitespaceHandling.None }; var xd = new XmlDocument(); xd.Load(xtr); I would like to change it so that I can pass in an object. I don't want to have to serialize the object to file first. Is this possible? Update: My original intentions were to take an xml document, merge some xslt (stored in a file), then output and return html... like this: public string TransformXml(string xmlFileName, string xslFileName) { var xtr = new XmlTextReader(xmlFileName) { WhitespaceHandling = WhitespaceHandling.None }; var xd = new XmlDocument(); xd.Load(xtr); var xslt = new System.Xml.Xsl.XslCompiledTransform(); xslt.Load(xslFileName); var stm = new MemoryStream(); xslt.Transform(xd, null, stm); stm.Position = 1; var sr = new StreamReader(stm); xtr.Close(); return sr.ReadToEnd(); } In the above code I am reading in the xml from a file. Now what I would like to do is just work with the object, before it was serialized to the file. So let me illustrate my problem using code public string TransformXMLFromObject(myObjType myobj , string xsltFileName) { // Notice the xslt stays the same. // Its in these next few lines that I can't figure out how to load the xml document (xd) from an object, and not from a file.... var xtr = new XmlTextReader(xmlFileName) { WhitespaceHandling = WhitespaceHandling.None }; var xd = new XmlDocument(); xd.Load(xtr); }

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  • what does mean "SQL Error: 30000, SQLState: XSAI3" ?

    - by phmr
    I'm using javadb/derbydb 10.5.3.0 with hibernate 3.5-Final I get this error at the end of EM initialisation : 4427 [SwingWorker-pool-1-thread-1] WARN org.hibernate.util.JDBCExceptionReporter - SQL Error: 30000, SQLState: XSAI3 4427 [SwingWorker-pool-1-thread-1] ERROR org.hibernate.util.JDBCExceptionReporter - Feature not implemented. SQL Error 30000 doesn't seem to be documented http://developers.sun.com/docs/javadb/10.3.3.0/ref/ref-single.html#rrefexcept71493

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  • Set the property hibernate.dialect error message

    - by user281180
    I am having the following error when configuring mvc3 and Nhibernate. Can anyone guide me what I have missed please. the dialect was not set. Set the property hibernate.dialect. Description: An unhandled exception occurred during the execution of the current web request. Please review the stack trace for more information about the error and where it originated in the code. Exception Details: NHibernate.HibernateException: The dialect was not set. Set the property hibernate.dialect. Source Error: Line 16: { Line 17: NHibernate.Cfg.Configuration configuration = new NHibernate.Cfg.Configuration(); Line 18: configuration.AddAssembly(System.Reflection.Assembly.GetExecutingAssembly()); Line 19: sessionFactory = configuration.BuildSessionFactory(); Line 20: } My web.config is as follows: <configSections> <section name="cachingConfiguration"type="Microsoft.Practices.EnterpriseLibrary.Caching.Configuration.CacheManagerSettings,Microsoft.Practices.EnterpriseLibrary.Caching"/> <section name="log4net"type="log4net.Config.Log4NetConfigurationSectionHandler,log4net"/> <section name="hibernate-configuration"type="NHibernate.Cfg.ConfigurationSectionHandler, NHibernate"/ <appSettings> <add key="BusinessObjectAssemblies" value="Keeper.API"></add> <add key="ConnectionString" value="Server=localhost\SQLSERVER2005;Database=KeeperDev;User=test;Pwd=test;"></add> <add key="ClientValidationEnabled" value="true"/> <add key="UnobtrusiveJavaScriptEnabled" value="true"/> </appSettings> <hibernate-configuration xmlns="urn:nhibernate-configuration-2.2"> <session-factory> <property name="dialect">NHibernate.Dialect.MsSql2000Dialect</property> <property name="connection.provider">NHibernate.Connection.DriverConnectionProvider</property> <property name="connection.connection_string">Server=localhost\SQLServer2005;Database=KeeperDev;User=test;Pwd=test;</property> <property name="proxyfactory.factory_class">NHibernate.ByteCode.Castle.ProxyFactoryFactory, NHibernate.ByteCode.Castle</property> </session-factory> </hibernate-configuration>

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  • Multi-level shop, xml or sql. best practice?

    - by danrichardson
    Hello, i have a general "best practice" question regarding building a multi-level shop, which i hope doesn't get marked down/deleted as i personally think it's quite a good "subjective" question. I am a developer in charge (in most part) of maintaining and evolving a cms system and associated front-end functionality. Over the past half year i have developed a multiple level shop system so that an infinite level of categories may exist down into a product level and all works fine. However over the last week or so i have questioned by own methods in front-end development and the best way to show the multi-level data structure. I currently use a sql server database (2000) and pull out all the shop levels and then process them into an enumerable typed list with child enumerable typed lists, so that all levels are sorted. This in my head seems quite process heavy, but we're not talking about thousands of rows, generally only 1-500 rows maybe. I have been toying with the idea recently of storing the structure in an XML document (as well as the database) and then sending last modified headers when serving/requesting the document for, which would then be processed as/when nessecary with an xsl(t) document - which would be processed server side. This is quite a handy, reusable method of storing the data but does it have more overheads in the fact im opening and closing files? And also the xml will require a bit of processing to pull out blocks of xml if for instance i wanted to show two level mid way through the tree for a side menu. I use the above method for sitemap purposes so there is currently already code i have built which does what i require, but unsure what the best process is to go about. Maybe a hybrid method which pulls out the data, sorts it and then makes an xml document/stream (XDocument/XmlDocument) for xsl processing is a good way? - This is the way i currently make the cms work for the shop. So really (and thanks for sticking with me on this), i am just wandering which methods other people use or recommend as being the best/most logical way of doing things. Thanks Dan

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  • XML: what processing rules apply for values intertwined with tags?

    - by iCE-9
    I've started working on a simple XML pull-parser, and as I've just defuzzed my mind on what's correct syntax in XML with regards to certain characters/sequences, ignorable whitespace and such (thank you, http://www.w3schools.com/xml/xml_elements.asp), I realized that I still don't know squat about what can be sketched up as the following case (which Validome finds well-formed very much; note that I only want to use xml files for data storage, no entities, DTD or Schemas needed): <bookstore> <book id="1"> <author>Kurt Vonnegut Jr.</author> <title>Slapstick</title> </book> We drop a pie here. <book id="2">Who cares anyway? <author>Stephen King</author> <title>The Green Mile</title> </book> And another one here. <book id="3"> <author>Next one</author> <title>This time with its own title</title> </book> </bookstore> "We drop a pie here." and "And another one here." are values of the 'bookstore' element. "Who cares anyway?" is a value related to the second 'book' element. How are these processed, if at all? Will "We drop a pie here." and "Another one here." be concatenated to form one value for the 'bookstore' element, or are they treated separately, stored somewhere, affecting the outcome of the parsing of the element they belong to, or...?

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  • how to use a generated dbml classes to deserialize xml via linq?

    - by Eelco Meuter
    Hi, I have a complex data structure, which I boiled down in a dbml file with one class and 6 one-to-many relations. This data must also be read via xml. The xml structure is something like: <table id=1> <column 1></column 1> <column n></column n> <m-n table x> <column 1></column 1> </m-n table x> </table> where the tag <m-n table x> is one of the six related tables. The idea is to generate an xsd based upon the dbml, which I can use to create and validate a xml. This xml can hopefully deserialized into the dbml classes. The question is: Can this be done? If so, how do I generate the xsd. I use a sql server express 2008 r2 as backend. Thanks in advance for your time!

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  • What to pass to UserType, BlobType.setPreparedStatement session parameter

    - by dlots
    http://blog.xebia.com/2009/11/09/understanding-and-writing-hibernate-user-types/ I am attempting to defined a customer serialization UserType that mimics, the XStreamUserType referenced and provided here: http://code.google.com/p/aphillips/source/browse/commons-hibernate-usertype/trunk/src/main/java/com/qrmedia/commons/persistence/hibernate/usertype/XStreamableUserType.java My serializer outputs a bytearray that should presumably written to a Blob. I was going to do: public class CustomSerUserType extends DirtyCheckableUserType { protected SerA ser=F.g(SerA.class); public Class<Object> returnedClass() { return Object.class; } public int[] sqlTypes() { return new int[] {Types.BLOB}; } public Object nullSafeGet(ResultSet resultSet,String[] names,Object owner) throws HibernateException,SQLException { if() } public void nullSafeSet(PreparedStatement preparedStatement,Object value,int index) throws HibernateException,SQLException { BlobType.nullSafeSet(preparedStatement,ser.ser(value),index); } } Unfortunetly, the BlobType.nullSafeSet method requires the session. So how does one define a UserType that gets access to a servlet requests session? EDIT: There is a discussion of the issue here and it doesn't appear there is a solution: Best way to implement a Hibernate UserType after deprecations?

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  • How to convert source code to a xml based representation of the ast?

    - by autobiographer
    i wanna get a xml representation of the ast of java and c code. 3 months ago, i asked this question yet but the solutions weren't comfortable for me srcml seems to be a good solution for this problem but it does not support line numbers and columns but i need that feature. about elsa: cite: "There is ongoing effort to export the Elsa AST as an XML document; we expect to be able to advertise this in the next public release." dms... didn't understand that. especially for java, there is javaml which supports line numbers. but the sourceforge page doesn't list any files. question: there's software available which supports conversion of ast into xml which supports line numbers (and columns) [especially for java and c/c++]? is there an alternative to javaml and srcml? ps: i don't wanne have parser generators. i hope to find a tool which can be used on the console typing: ./my-xml-generator Test.java [or something like that]... or a java implementation would be great too.

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  • Does Hibernate create tables in the database automatically.

    - by theJava
    http://www.vaannila.com/spring/spring-hibernate-integration-1.html Upon reading this tutorial, they have not mentioned anything over creating tables in the DB. Does the Hibernate handle it automatically by creating tables and fields once i specify them. Here is my beans configuration. <?xml version="1.0" encoding="UTF-8"?> <beans xmlns="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:p="http://www.springframework.org/schema/p" xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans.xsd"> <bean id="viewResolver" class="org.springframework.web.servlet.view.InternalResourceViewResolver" p:prefix="/WEB-INF/jsp/" p:suffix=".jsp" /> <bean id="myDataSource" class="org.apache.commons.dbcp.BasicDataSource" destroy-method="close"> <property name="driverClassName" value="com.mysql.jdbc.Driver"/> <property name="url" value="jdbc:mysql://127.0.0.1:3306/spring"/> <property name="username" value="monwwty"/> <property name="password" value="www"/> </bean> <bean id="mySessionFactory" class="org.springframework.orm.hibernate3.annotation.AnnotationSessionFactoryBean"> <property name="dataSource" ref="myDataSource" /> <property name="annotatedClasses"> <list> <value>uk.co.vinoth.spring.domain.User</value> </list> </property> <property name="hibernateProperties"> <props> <prop key="hibernate.dialect">org.hibernate.dialect.MySQLDialect</prop> <prop key="hibernate.show_sql">true</prop> <prop key="hibernate.hbm2ddl.auto">create</prop> </props> </property> </bean> <bean id="myUserDAO" class="uk.co.vinoth.spring.dao.UserDAOImpl"> <property name="sessionFactory" ref="mySessionFactory"/> </bean> <bean name="/user/*.htm" class="uk.co.vinoth.spring.web.UserController" > <property name="userDAO" ref="myUserDAO" /> </bean> </beans>

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  • Is there a way to parse XML via SAX/DOM with line numbers available per node.

    - by Chris
    I already have written a DOM parser for a large XML document format that contains a number of items that can be used to automatically generate Java code. This is limited to small expressions that are then merged into a dynamically generated Java source file. So far - so good. Everything works. BUT - I wish to be able to embed the line number of the XML node where the Java code was included from (so that if the configuration contains uncompilable code, each method will have a pointer to the source XML document and the line number for ease of debugging). I don't require the line number at parse-time and I don't need to validate the XML Source Document and throw an error at a particular line number. I need to be able to access the line number for each node and attribute in my DOM or per SAX event. Any suggestions on how I might be able to achieve this? P.S. Also, I read the StAX has a method to obtain line number whilst parsing, but ideally I would like to achieve the same result with regular SAX/DOM processing in Java 4/5 rather than become a Java 6+ application or take on extra .jar files.

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  • How to generate XML from an Excel VBA macro?

    - by SuperNES
    So, I've got a bunch of content that was delivered to us in the form of Excel spreadsheets. I need to take that content and push it into another system. The other system takes its input from an XML file. I could do all of this by hand (and trust me, management has no problem making me do that!), but I'm hoping there's an easy way to write an Excel macro that would generate the XML I need instead. This seems like a better solution to me, as this is a job that will need to be repeated regularly (we'll be getting a LOT of content in Excel sheets) and it just makes sense to have a batch tool that does it for us. However, I've never experimented with generating XML from Excel spreadsheets before. I have a little VBA knowledge but I'm a newbie to XML. I guess my problem in Googling this is that I don't even know what to Google for. Can anyone give me a little direction to get me started? Does my idea sound like the right way to approach this problem, or am I overlooking something obvious? Thanks StackOverflow!

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  • java.sql.SQLException: No suitable driver found for jdbc:db2:

    - by Celia
    Im using hibernate to connect to my DB2 database. I got java.sql.SQLException: No suitable driver found for jdbc:db2://ldild4268.mycompany.com:55000/myDB. I have db2jcc.jar, db2jcc_javax.jar, db2jcc_license_cu.jar, db2policy.jar, db2ggjava.jar and db2umplugin.jar added into my Java Build Path. I am able to connect to my database through SQuirrel. database.properties: jdbc.driverClassName=com.ibm.db2.jcc.DB2Driver jdbc.url=jdbc:db2://ldild4268.mycompany.com:55000/myDB jdbc.username=uname jdbc.password=pwd datasource.xml: <bean class="org.springframework.beans.factory.config.PropertyPlaceholderConfigurer"> <property name="location"> <value>/WEB-INF/database.properties</value> </property> </bean> <bean id="dataSource" class="org.springframework.jdbc.datasource.DriverManagerDataSource"> <property name="driverClassName" value="${jdbc.driverClassName}" /> <property name="url" value="${jdbc.url}" /> <property name="username" value="${jdbc.username}" /> <property name="password" value="${jdbc.password}" /> </bean> hibernate.xml: <bean id="sessionFactory" class="org.springframework.orm.hibernate3.LocalSessionFactoryBean"> <property name="dataSource"> <ref bean="dataSource" /> </property> <property name="hibernateProperties"> <props> <prop key="hibernate.dialect">org.hibernate.dialect.DB2Dialect</prop> <prop key="hibernate.show_sql">true</prop> </props> </property> <property name="mappingResources"> <list> <value>/myModel.hbm.xml</value> </list> </property> </bean> myModel.hbm.xml: <hibernate-mapping> <class name="com.myCompany.model.myModel" table="table1" catalog=""> <composite-id> <key-property name="key1" column="key1" length="10"/> <key-property name="key2" column="key2" length="19"/> </composite-id> <property name="name" type="string"> <column name="Name" length="50"/> </property> </class> </hibernate-mapping> myModelDaoImpl: @Repository("myModelDao") public class myModelDaoImpl extends PortfolioHibernateDaoSupport implements myModelDao{ private SessionFactory sessionFactory; public List<Date> getKey1() { return this.sessionFactory.getCurrentSession() .createQuery("select pn.key1 from com.myCompany.model.myModel pn") .list(); } public String getPs() { String query = "select pn.name from com.myCompany.model.myModel pn where pn.key1='2011-09-30' and pn.key2=1049764"; List list = getHibernateTemplate().find(query); } } also, the method getKey1 throws nullPointer exception. How can I use createquery instead of hibernateTemplate? Thanks in advance!

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  • How to create XSD schema from XML with this kind of structure (in .net)?

    - by Mr. Brownstone
    Here's the problem: my input is XML file that looks something like: <BaseEntityClassInfo> <item> <key>BaseEntityClassInfo.SomeField</key> <value>valueData1</value> </item> <item> <key>BaseEntityClassInfo.AdditionalDataClass.SomeOtherField</key> <value>valueData2</value> </item> <item> <key>BaseEntityClassInfo.AdditionalDataClass.AnotherClassInfo.DisplayedText</key> <value>valueData3</value> </item> ... ... </BaseEntityClassInfo> The <key> element somehow describes entity classes fields and relationships (used in some other app that I don't have access to) and the <value> stores the actual data that I need. My goal is to programatically generate a typed Dataset from this XML that could then be used for creating reports. I thought of building some XSD schema from input XML file first and then use this schema to generate Dataset but I'm not sure how to do that. The problem is that I don't want all data in one table, I need several tables with relationships based on the <key> value so I guess I need to infer relational structure from XML <key> data in some way. So what do you think? How could this be done and what would be the best approach? Any advice, ideas, suggestions would be appreciated!

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