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  • Django Admin: OneToOne Relation as an Inline?

    - by Jim Robert
    I am putting together the admin for a satchmo application. Satchmo uses OneToOne relations to extend the base Product model, and I'd like to edit it all on one page. It is possible to have a OneToOne relation as an Inline? If not, what is the best way to add a few fields to a given page of my admin that will eventually be saved into the OneToOne relation? for example: class Product(models.Model): name = models.CharField(max_length=100) ... class MyProduct(models.Model): product = models.OneToOne(Product) ... I tried this for my admin but it does not work, and seems to expect a Foreign Key: class ProductInline(admin.StackedInline): model = Product fields = ('name',) class MyProductAdmin(admin.ModelAdmin): inlines = (AlbumProductInline,) admin.site.register(MyProduct, MyProductAdmin) Which throws this error: <class 'satchmo.product.models.Product'> has no ForeignKey to <class 'my_app.models.MyProduct'> Is the only way to do this a Custom Form? edit: Just tried the following code to add the fields directly... also does not work: class AlbumAdmin(admin.ModelAdmin): fields = ('product__name',)

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  • Linq to Entities and POCO foreign key relations mapping (1 to 0..1) problem

    - by brainnovative
    For my ASP.NET MVC 2 application I use Entity Framework 1.0 as my data access layer (repository). But I decided I want to return POCO. For the first time I have encountered a problem when I wanted to get a list of Brands with their optional logos. Here's what I did: public IQueryable<Model.Products.Brand> GetAll() { IQueryable<Model.Products.Brand> brands = from b in EntitiesCtx.Brands.Include("Logo") select new Model.Products.Brand() { BrandId = b.BrandId, Name = b.Name, Description = b.Description, IsActive = b.IsActive, Logo = /*b.Logo != null ? */new Model.Cms.Image() { ImageId = b.Logo.ImageId, Alt = b.Logo.Alt, Url = b.Logo.Url }/* : null*/ }; return brands; } You can see in the comments what I would like to achieve. It worked fine whenever a Brand had a Logo otherwise it through an exception that you can assign null to the non-nullable type int (for Id). My workaround was to use nullable in the POCO class but that's not natural - then I have to check not only if Logo is null in my Service layer or Controllers and Views but mostly for Logo.ImageId.HasValue. It's not justified to have a non null Logo property if the id is null. Can anyone think of a better solution?

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  • Django custom managers - how do I return only objects created by the logged-in user?

    - by Tom Tom
    I want to overwrite the custom objects model manager to only return objects a specific user created. Admin users should still return all objects using the objects model manager. Now I have found an approach that could work. They propose to create your own middleware looking like this: #### myproject/middleware/threadlocals.py try: from threading import local except ImportError: # Python 2.3 compatibility from django.utils._threading_local import local _thread_locals = local() def get_current_user(): return getattr(_thread_locals, 'user', None) class ThreadLocals(object): """Middleware that gets various objects from the request object and saves them in thread local storage.""" def process_request(self, request): _thread_locals.user = getattr(request, 'user', None) #### end And in the Custom manager you could call the get_current_user() method to return only objects a specific user created. class UserContactManager(models.Manager): def get_query_set(self): return super(UserContactManager, self).get_query_set().filter(creator=get_current_user()) Is this a good approach to this use-case? Will this work? Or is this like "using a sledgehammer to crack a nut" ? ;-) Just using: Contact.objects.filter(created_by= user) in each view doesn`t look very neat to me. EDIT Do not use this middleware approach !!! use the approach stated by Jack M. below After a while of testing this approach behaved pretty strange and with this approach you mix up a global-state with a current request. Use the approach presented below. It is really easy and no need to hack around with the middleware. create a custom manager in your model with a function that expects the current user or any other user as an input. #in your models.py class HourRecordManager(models.Manager): def for_user(self, user): return self.get_query_set().filter(created_by=user) class HourRecord(models.Model): #Managers objects = HourRecordManager() #in vour view you can call the manager like this and get returned only the objects from the currently logged-in user. hr_set = HourRecord.objects.for_user(request.user)

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  • Show models.ManyToManyField as inline, with the same form as models.ForeignKey inline

    - by Kristian
    I have a model similar to the following (simplified): models.py class Sample(models.Model): name=models.CharField(max_length=200) class Action(models.Model): samples=models.ManyToManyField(Sample) title=models.CharField(max_length=200) description=models.TextField() Now, if Action.samples would have been a ForeignKey instead of a ManyToManyField, when I display Action as a TabularInline in Sample in the Django Admin, I would get a number of rows, each containing a nice form to edit or add another Action. However; when I display the above as an inline using the following: class ActionInline(admin.TabularInline): model=Action.samples.through I get a select box listing all available actions, and not a nifty form to create a new Action. My question is really: How do I display the ManyToMany relation as an inline with a form to input information as described? In principle it should be possible since, from the Sample's point of view, the situation is identical in both cases; Each Sample has a list of Actions regardless if the relation is a ForeignKey or a ManyToManyRelation. Also; Through the Sample admin page, I never want to choose from existing Actions, only create new or edit old ones.

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  • Django User M2M relationship

    - by Antonio
    When trying to syncdb with the following models: class Contact(models.Model): user_from = models.ForeignKey(User,related_name='from_user') user_to = models.ForeignKey(User, related_name='to_user') class Meta: unique_together = (('user_from', 'user_to'),) User.add_to_class('following', models.ManyToManyField('self', through=Contact, related_name='followers', symmetrical=False)) I get the following error: Error: One or more models did not validate: auth.user: Accessor for m2m field 'following' clashes with related m2m field 'User.followers'. Add a related_name argument to the definition for 'following'. auth.user: Reverse query name for m2m field 'following' clashes with related m2m field 'User.followers'. Add a related_name argument to the definition for 'following'. auth.user: The model User has two manually-defined m2m relations through the model Contact, which is not permitted. Please consider using an extra field on your intermediary model instead. auth.user: Accessor for m2m field 'following' clashes with related m2m field 'User.followers'. Add a related_name argument to the definition for 'following'. auth.user: Reverse query name for m2m field 'following' clashes with related m2m field 'User.followers'. Add a related_name argument to the definition for 'following'.

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  • ASP.NET MVC TextBoxFor helper rendering empty when null

    - by mare
    I noticed that TextBoxFor helper renders empty if there is no model, like for instance when I have a CreateEdit ViewUserControl. When in Edit view fields are filled in, when in Create fields are empty but still rendered. The problem is TextBoxFor does not accept different Id for its name (the same as LabelFor and others, but for LabelFor I have custom Html helpers). So in some case we still have to use regular Html.TextBox helper. The problem is if I write this <%=Html.TextBox("postname", Model.PostCode.postname, new { @class = "postsDropDown" })%> an error occurs in Create view (obviously). So I have to do this: <% if (Model != null) %> <%=Html.TextBox("postname", Model.PostCode.postname, new { @class = "postsDropDown" })%> <% else %> <%=Html.TextBox("postname", null, new { @class = "postsDropDown" })%> Now that is something which I don't like anymore (the IF's). Is this the only way to do it? I know I could extend TextBoxFor helpers also but seems like so much trouble. In the end we will come to extending all of the "For" helpers but I think this should be done by ASP.NET MVC team already (built-in).

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  • The ViewData item that has the key 'MY KEY' is of type 'System.String' but must be of type 'IEnumerable<SelectListItem>'.

    - by JBibbs
    I am trying to populate a dropdown list from a database mapped with Linq 2 SQL, using ASP.NET MVC 2, and keep getting this error. I am so confused because I am declaring a variable with the type IEnumerable<SelectListItem> on the second line, but the error makes me think this is not the case. I feel like this should be very simple, but I am struggling. Any help is appreciated. Here are the interesting bits of my controller: public ActionResult Create() { var db = new DB(); IEnumerable<SelectListItem> basetypes = db.Basetypes.Select(b => new SelectListItem { Value = b.basetype, Text = b.basetype }); ViewData["basetype"] = basetypes; return View(); } And here are the interesting bits of my view: <div class="editor-label"> <%: Html.LabelFor(model => model.basetype) %> </div> <div class="editor-field"> <%: Html.DropDownList("basetype") %> <%: Html.ValidationMessageFor(model => model.basetype) %> </div> Here is the Post action when submitting the Form // POST: /Meals/Create [HttpPost] public ActionResult Create(Meal meal) { if (ModelState.IsValid) { try { // TODO: Add insert logic here var db = new DB(); db.Meals.InsertOnSubmit(meal); db.SubmitChanges(); return RedirectToAction("Index"); } catch { return View(meal); } } else { return View(meal); } } Thanks.

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  • Spring-json problem in Liferay with Spring 2.5

    - by Jesus Benito
    Hi all, I am trying to use the library spring-json.1.3.1 in a project that has been done with Liferay 5.1.2 which includes Spring 2.5. Following the project website instructions, I managed to make the request hit in my controller, but at the moment of returning the json object back through the modelAndView object it fails with the following error: java.lang.IllegalArgumentException at com.liferay.portlet.MimeResponseImpl.setContentType(MimeResponseImpl.java:162) I have checked Liferays source code, and it checks that contentType that its being set is in a harcoded list,if it not it will throw a IllegalArgumentException that it is exactly what os happening. This is my view resolver code: <bean id="xmlFileViewResolver" class="org.springframework.web.servlet.view.XmlViewResolver"> /WEB-INF/context/views.xml 1 My views.xml code: <beans> <bean name="jsonView" class="org.springframework.web.servlet.view.json.JsonView"/> And my controller: @SuppressWarnings("unchecked") @Override public ModelAndView handleRenderRequest(RenderRequest arg0, RenderResponse arg1) throws Exception { Map model = new HashMap(); model.put("firstname", "Peter"); model.put("secondname", "Schmitt"); return new ModelAndView("jsonView", model); } Any ideas?

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  • ASP.NET MVC: what mechanic returns ViewModel objects?

    - by Dr. Zim
    As I understand it, Domain Models are classes that only describe the data (aggregate roots). They are POCOs and do not reference outside libraries (nothing special). View models on the other hand are classes that contain domain model objects as well as all the interface specific objects like SelectList. A ViewModel includes using System.Web.Mvc;. A repository pulls data out of a database and feeds them to us through domain model objects. What mechanic or device creates the view model objects, populating them from a database? Would it be a factory that has database access? Would you bleed the view specific classes like System.Web.Mvc in to the Repository? Something else? For example, if you have a drop down list of cities, you would reference a SelectList object in the root of your View Model object, right next to your DomainModel reference: public class CustomerForm { public CustomerAddress address {get;set;} public SelectList cities {get;set;} } The cities should come from a database and be in the form of a select list object. The hope is that you don't create a special Repository method to extract out just the distinct cities, then create a redundant second SelectList object only so you have the right data types.

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  • Using Mapping Models to migrate between Core Data Object Models

    - by westsider
    I have a fairly simply scheme. Essentially, Run <-- Data (where a Run holds a data, e.g., Temperature, sampled from some sort of sensor). Now, it seems that sensors can have more than one measurement (e.g., Temperature and Humidity). So, a single Run could have multiple data samples. Hence, Run <-- Sample and Sample <-- Data. (And for simplicity I am leaving Run <-- Data in place, for now.) If I create a new mapping model, then things generally work - except that no new Samples are created, no relationships are established between Runs and Samples nor between Samples and Datas. I am trying to get mapping model to migrate my model but even the slightest change to the generated mapping model results in Cocoa error 134110. For example, if I take the "Sample" mapping (which has no Source) and set its Source to 'Run' (so that I can set Sample's inverse relationship 'run' appropriately) then the mapping changes its name to "RunToSample". There are two relationships handled in this mapping: data and run. The data property gets set automatically to FUNCTION($manager, "destinationInstancesForEntityMappingNamed:sourceInstances:" , "DataToData", $source.dataSet) Following this example, I set the run property to FUNCTION($manager, "destinationInstancesForEntityMappingNamed:sourceInstances:" , "RunToRun", $source) Similarly, I set the 'sample' property mapping in RunToRun to FUNCTION($manager, "destinationInstancesForEntityMappingNamed:sourceInstances:" , "RunToSample", $source) and the 'sample' property in DataToData to FUNCTION($manager, "destinationInstancesForEntityMappingNamed:sourceInstances:" , "RunToSample", $source.run) So, what, I wonder, is going wrong? I have tried various permutations, such as leaving the 'inverse' relationships unspecified. But I continue to get the same error (134110) regardless. I imagine that this is a lot easier than it seems and that I am missing some fundamental but minor piece. I have also tried subclassing NSEntityMigrationPolicy and overriding -createDestinationInstancesForSourceInstance: but these efforts have met with much the same results. Thanks in advance for any pointers or (relevant :-) advice.

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  • JPA 2 Criteria API: why is isNull being ignored when in conjunction with equal?

    - by Vítor Souza
    I have the following entity class (ID inherited from PersistentObjectSupport class): @Entity public class AmbulanceDeactivation extends PersistentObjectSupport implements Serializable { private static final long serialVersionUID = 1L; @Temporal(TemporalType.DATE) @NotNull private Date beginDate; @Temporal(TemporalType.DATE) private Date endDate; @Size(max = 250) private String reason; @ManyToOne @NotNull private Ambulance ambulance; /* Get/set methods, etc. */ } If I do the following query using the Criteria API: CriteriaBuilder cb = em.getCriteriaBuilder(); CriteriaQuery<AmbulanceDeactivation> cq = cb.createQuery(AmbulanceDeactivation.class); Root<AmbulanceDeactivation> root = cq.from(AmbulanceDeactivation.class); EntityType<AmbulanceDeactivation> model = root.getModel(); cq.where(cb.isNull(root.get(model.getSingularAttribute("endDate", Date.class)))); return em.createQuery(cq).getResultList(); I get the following SQL printed in the log: FINE: SELECT ID, REASON, ENDDATE, UUID, BEGINDATE, VERSION, AMBULANCE_ID FROM AMBULANCEDEACTIVATION WHERE (ENDDATE IS NULL) However, if I change the where() line in the previous code to this one: cq.where(cb.isNull(root.get(model.getSingularAttribute("endDate", Date.class))), cb.equal(root.get(model.getSingularAttribute("ambulance", Ambulance.class)), ambulance)); I get the following SQL: FINE: SELECT ID, REASON, ENDDATE, UUID, BEGINDATE, VERSION, AMBULANCE_ID FROM AMBULANCEDEACTIVATION WHERE (AMBULANCE_ID = ?) That is, the isNull criterion is totally ignored. It is as if it wasn't even there (if I provide only the equal criterion to the where() method I get the same SQL printed). Why is that? Is it a bug or am I missing something?

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  • how to do introspection in R (stat package)

    - by Lebron James
    Hi all, I am somewhat new to R, and i have this piece of code which generates a variable that i don't know the type for. Are there any introspection facility in R which will tell me which type this variable belongs to? The following illustrates the property of this variable: I am working on linear model selection, and the resource I have is lm result from another model. Now I want to retrieve the lm call by the command summary(model)$call so that I don't need to hardcode the model structure. However, since I have to change the dataset, I need to do a bit of modification on the "string", but apparently it is not a simple string. I wonder if there is any command similar to string.replace so that I can manipulate this variable from the variable $call. Thanks > str<-summary(rdnM)$call > str lm(formula = y ~ x1, data = rdndat) > str[1] lm() > str[2] y ~ x1() > str[3] rdndat() > str[3] <- data Warning message: In str[3] <- data : number of items to replace is not a multiple of replacement length > str lm(formula = y ~ x1, data = c(10, 20, 30, 40)) > str<-summary(rdnM)$call > str lm(formula = y ~ x1, data = rdndat) > str[3] <- 'data' > str lm(formula = y ~ x1, data = "data") > str<-summary(rdnM)$call > type str Error: unexpected symbol in "type str" >

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  • How do I get syncdb db_table and app_label to play nicely together

    - by Chris Heisel
    I've got a model that looks something like this: class HeiselFoo(models.Model): title = models.CharField(max_length=250) class Meta: """ Meta """ app_label = "Foos" db_table = u"medley_heiselfoo_heiselfoo" And whenever I run my test suite, I get an error because Django isn't creating the tables for that model. It appears to be an interaction between app_label and db_table -- as the test suite runs normally if db_table is set, but app_label isn't. Here's a link to the full source code: http://github.com/cmheisel/heiselfoo Here's the traceback from the test suite: E ====================================================================== ERROR: test_truth (heiselfoo.tests.HeiselFooTests) ---------------------------------------------------------------------- Traceback (most recent call last): File "/Users/chris/Code/heiselfoo/ve/lib/python2.6/site-packages/heiselfoo/tests.py", line 10, in test_truth f.save() File "/Users/chris/Code/heiselfoo/ve/lib/python2.6/site-packages/django/db/models/base.py", line 434, in save self.save_base(using=using, force_insert=force_insert, force_update=force_update) File "/Users/chris/Code/heiselfoo/ve/lib/python2.6/site-packages/django/db/models/base.py", line 527, in save_base result = manager._insert(values, return_id=update_pk, using=using) File "/Users/chris/Code/heiselfoo/ve/lib/python2.6/site-packages/django/db/models/manager.py", line 195, in _insert return insert_query(self.model, values, **kwargs) File "/Users/chris/Code/heiselfoo/ve/lib/python2.6/site-packages/django/db/models/query.py", line 1479, in insert_query return query.get_compiler(using=using).execute_sql(return_id) File "/Users/chris/Code/heiselfoo/ve/lib/python2.6/site-packages/django/db/models/sql/compiler.py", line 783, in execute_sql cursor = super(SQLInsertCompiler, self).execute_sql(None) File "/Users/chris/Code/heiselfoo/ve/lib/python2.6/site-packages/django/db/models/sql/compiler.py", line 727, in execute_sql cursor.execute(sql, params) File "/Users/chris/Code/heiselfoo/ve/lib/python2.6/site-packages/django/db/backends/sqlite3/base.py", line 200, in execute return Database.Cursor.execute(self, query, params) DatabaseError: no such table: medley_heiselfoo_heiselfoo ---------------------------------------------------------------------- Ran 1 test in 0.004s FAILED (errors=1) Creating test database 'default'... No fixtures found. medley_heiselfoo_heiselfoo Destroying test database 'default'...

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  • .NET Membership with Repository Pattern

    - by Zac
    My team is in the process of designing a domain model which will hide various different data sources behind a unified repository abstraction. One of the main drivers for this approach is the very high probability that these data sources will undergo significant change in the near future and we don't want to be re-writing business logic when this happens. One data source will be our membership database which was originally implemented using the default ASP.Net Membership Provider. The membership provider is tied to the System.Web.Security namespace but we have a design guideline requiring that our domain model layer is not dependent upon System.Web (or any other implementation/environment dependency) as it will be consumed in different environments - nor do we want our websites directly communicating with databases. I am considering what would be a good approach to reconciling the MembershipProvider approach with our abstracted n-tier architecture. My initial feeling is that we could create a "DomainMembershipProvider" which interacts with the domain model and then implement objects in the model which deal with the repository and handle validation/business logic. The repository would then implement data access using our (as-yet undecided) ORM/data access tool. Are there are any glaring holes in this approach - I haven't worked closely with the MembershipProvider class so may well be missing something. Alternatively, is there an approach that you think will better serve the requirements I described above? Thanks in advance for your thoughts and advice. Regards, Zac

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  • Project setup for an ADO.NET/WCF DataService

    - by Slauma
    I'd like to implement a ADO.NET/WCF DataService and I am wondering what's the best way to setup a project in VS2008 SP1 for this purpose. Currently I have an ASP.NET web application project (not of "WebSite" project type). The data access layer is an Entity model (EF version 1) with SQL Server database. I have the Entity Model in a separate DLL project and the web application project references to this assembly for all data accesses. The ADO.NET/WCF DataService needs to communicate with the Entity model/database as well. It has to be hosted on the same web server (IIS 7.5) together with the web application. Since the DataService is not directly related to that specific web application (though it will provide and modify data from/in the same database the web application uses as well) my basic idea was to separate the DataService in its own new project (which also references the Entity Model DLL). Now I have seen that there is no project type "ADO.NET/WCF DataService" in VS2008 SP1. It seems only possible to add a DataService as an element to other existing projects, for instance Web Application projects. Why isn't there a separate DataService project type? Does this mean now that I have to add the DataService as an element to my Web Application project? Or shall I create a new Web Application project and add a DataService to it? (I could delete the pregenerated default.aspx since I do not need any web pages in this project.) What's the best way? Thank you for suggestions in advance!

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  • Issue intercepting property in Silverlight application

    - by joblot
    I am using Ninject as DI container in a Silverlight application. Now I am extending the application to support interception and started integrating DynamicProxy2 extension for Ninject. I am trying to intercept call to properties on a ViewModel and ending up getting following exception: “Attempt to access the method failed: System.Reflection.Emit.DynamicMethod..ctor(System.String, System.Type, System.Type[], System.Reflection.Module, Boolean)” This exception is thrown when invocation.Proceed() method is called. I tried two implementations of the interceptor and they both fail public class NotifyPropertyChangedInterceptor: SimpleInterceptor { protected override void AfterInvoke(IInvocation invocation) { var model = (IAutoNotifyPropertyChanged)invocation.Request.Proxy; model.OnPropertyChanged(invocation.Request.Method.Name.Substring("set_".Length)); } } public class NotifyPropertyChangedInterceptor: IInterceptor { public void Intercept(IInvocation invocation) { invocation.Proceed(); var model = (IAutoNotifyPropertyChanged)invocation.Request.Proxy; model.OnPropertyChanged(invocation.Request.Method.Name.Substring("set_".Length)); } } I want to call OnPropertyChanged method on the ViewModel when property value is set. I am using Attribute based interception. [AttributeUsage(AttributeTargets.Property, AllowMultiple = false, Inherited = true)] public class NotifyPropertyChangedAttribute : InterceptAttribute { public override IInterceptor CreateInterceptor(IProxyRequest request) { if(request.Method.Name.StartsWith("set_")) return request.Context.Kernel.Get<NotifyPropertyChangedInterceptor>(); return null; } } I tested the implementation with a Console Application and it works alright. I also noted in Console Application as long as I had Ninject.Extensions.Interception.DynamicProxy2.dll in same folder as Ninject.dll I did not have to explicitly load DynamicProxy2Module into the Kernel, where as I had to explicitly load it for Silverlight application as follows: IKernel kernel = new StandardKernel(new DIModules(), new DynamicProxy2Module()); Could someone please help? Thanks

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  • Can't place a breakpoint in asp.net master page file

    - by Tony_Henrich
    I have an MVC web application. I get an "Object reference not set to an instance of an object" error in line 16 below. It's a master page file. When I try to place a breakpoint in that line or anywhere in the file, I get a "this is not a valid location for a breakpoint" error. I have clicked on every line and I can't place a single breakpoint. I do have lines which have code only. How do I place a breakpoint in this file? Note: I can place breakpoints in code files. In some other aspx files, I can place a breakpoint in some code lines and some not. Does the inline code have to be in a special format to place a breakpoint? Using VS 2010 in Windows 7 64bit. Code: Line 14: <div id="<%= Model.PageWidth %>" class="<%= Model.PageTemplate %>"> Line 15: <div id="hd"> Line 16: <h1><a href="/"><%= Model.Workspace.Title %></a></h1> Line 17: <h2><%= Model.Workspace.Subtitle %></h2> Line 18: </div>

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  • Add data to Django form class using modelformset_factory

    - by dean
    I have a problem where I need to display a lot of forms for detail data for a hierarchical data set. I want to display some relational fields as labels for the forms and I'm struggling with a way to do this in a more robust way. Here is the code... class Category(models.Model): name = models.CharField(max_length=160) class Item(models.Model): category = models.ForeignKey('Category') name = models.CharField(max_length=160) weight = models.IntegerField(default=0) class Meta: ordering = ('category','weight','name') class BudgetValue(models.Model): value = models.IntegerField() plan = models.ForeignKey('Plan') item = models.ForeignKey('Item') I use the modelformset_factory to create a formset of budgetvalue forms for a particular plan. What I'd like is item name and category name for each BudgetValue. When I iterate through the forms each one will be labeled properly. class BudgetValueForm(forms.ModelForm): item = forms.ModelChoiceField(queryset=Item.objects.all(),widget=forms.HiddenInput()) plan = forms.ModelChoiceField(queryset=Plan.objects.all(),widget=forms.HiddenInput()) category = "" < assign dynamically on form creation > item = "" < assign dynamically on form creation > class Meta: model = BudgetValue fields = ('item','plan','value') What I started out with is just creating a dictionary of budgetvalue.item.category.name, budgetvalue.item.name, and the form for each budget value. This gets passed to the template and I render it as I intended. I'm assuming that the ordering of the forms in the formset and the querset used to genererate the formset keep the budgetvalues in the same order and the dictionary is created correctly. That is the budgetvalue.item.name is associated with the correct form. This scares me and I'm thinking there has to be a better way. Any help would be greatly appreciated.

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  • Django form linking 2 models by many to many field.

    - by Ed
    I have two models: class Actor(models.Model): name = models.CharField(max_length=30, unique = True) event = models.ManyToManyField(Event, blank=True, null=True) class Event(models.Model): name = models.CharField(max_length=30, unique = True) long_description = models.TextField(blank=True, null=True) I want to create a form that allows me to identify the link between the two models when I add a new entry. This works: class ActorForm(forms.ModelForm): class Meta: model = Actor The form includes both name and event, allowing me to create a new Actor and simultaneous link it to an existing Event. On the flipside, class EventForm(forms.ModelForm): class Meta: model = Event This form does not include an actor association. So I am only able to create a new Event. I can't simultaneously link it to an existing Actor. I tried to create an inline formset: EventFormSet = forms.models.inlineformset_factory(Event, Actor, can_delete = False, extra = 2, form = ActorForm) but I get an error <'class ctg.dtb.models.Actor'> has no ForeignKey to <'class ctg.dtb.models.Event'> This isn't too surprising. The inlineformset worked for another set of models I had, but this is a different example. I think I'm going about it entirely wrong. Overall question: How can I create a form that allows me to create a new Event and link it to an existing Actor?

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  • .net mvc pass dictionary data from view to controller

    - by Wei Ma
    A while ago, I was trying to pass a dictionary data from my view to my controller. And I was able to do so after googling on the net(remember it was one of scott hanselman's posts). The solution I had was something like <%for(int index=0; index<Model.Count(); index++){ var property= Model.ElementAt(index);%> <input type="hidden" name="<%="properties["+index+"].Key"%>"/> <input type="hidden" name="<%="properties["+index+"].Value"%>"/> <%}%> public ActionResult Process(IDictionary<string,string> properties) { doSomething(); return View(); } The code worked for awhile and then I did some refactoring and got rid of this chunk of code. Today, I ran into a situation in which I would like to pass a dictionary again. But no matter how hard I try, the properties parameter received by the action was always null. I tried the above code and <%for(int index=0; index<Model.Count(); index++){ var property= Model.ElementAt(index);%> <input type="hidden" name="<%="properties.Keys["+index+"]"%>"/> <input type="hidden" name="<%="properties.Values["+index+"]"%>"/> <%}%> Neither code worked. I googled again but couldn't find the post that helped me before. Can someone point out what I did wrong? thanks a million.

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  • How to update QStandartItemModel without freezing the main UI

    - by user1044002
    I'm starting to learn PyQt4 and have been stuck on something for a long time now and can't figure it out myself: Here is the concept: There is a TreeView with custom QStandartItemModel, which gets rebuild every couple of seconds, and can have a lot (hundreds at least) of entries, there also will be additional delegates for the different columns etc. It's fairly complex and the building time for even plain model, without delegates, goes up to .3 sec, which makes the TreeView to freeze. Please advice me for the best approach on solving this. I was thing of somehow building the model in different thread, and eventually sending it to the TreeView, where it would just perform setModel() with the new one, but couldn't make that work. here is some code that may illustrate the problem a bit: from PyQt4.QtCore import * from PyQt4.QtGui import * import sys, os, re, time app = QApplication(sys.argv) REFRESH = 1 class Reloader_Thread(QThread): def __init__(self, parent = None): QThread.__init__(self, parent) self.loaders = ['\\', '--', '|', '/', '--'] self.emit(SIGNAL('refresh')) def run(self): format = '|%d/%b/%Y %H:%M:%S| ' while True: self.emit(SIGNAL('refresh')) self.sleep(REFRESH) class Model(QStandardItemModel): def __init__(self, viewer=None): QStandardItemModel.__init__(self,None) self.build() def build(self): stTime = time.clock() newRows = [] for r in range(1000): row = [] for c in range(12): item = QStandardItem('%s %02d%02d' % (time.strftime('%H"%M\'%S'), r,c)) row.append(item) newRows.append(row) eTime = time.clock() - stTime outStr = 'Build %03f' % eTime format = '|%d/%b/%Y %H:%M:%S| ' stTime = time.clock() self.beginRemoveRows(QModelIndex(), 0, self.rowCount()) self.removeRows(0, self.rowCount()) self.endRemoveRows() eTime = time.clock() - stTime outStr += ', Remove %03f' % eTime stTime = time.clock() numNew = len(newRows) for r in range(numNew): self.appendRow(newRows[r]) eTime = time.clock() - stTime outStr += ', Set %03f' % eTime self.emit(SIGNAL('status'), outStr) self.reset() w = QWidget() w.setGeometry(200,200,800,600) hb = QVBoxLayout(w) tv = QTreeView() tvm = Model(tv) tv.setModel(tvm) sb = QStatusBar() reloader = Reloader_Thread() tvm.connect(tvm, SIGNAL('status'), sb.showMessage) reloader.connect(reloader, SIGNAL('refresh'), tvm.build) reloader.start() hb.addWidget(tv) hb.addWidget(sb) w.show() app.setStyle('plastique') app.processEvents(QEventLoop.AllEvents) app.aboutToQuit.connect(reloader.quit) app.exec_()

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  • How to create a view to manage associations between HABTM models? (Rails)

    - by Chris Hart
    Hello, I am using Ruby on Rails and need to create a view that allows the creation of records through a HABTM relationship to another model. Specifically, I have the following models: Customer and ServiceOverride, and a join table customers_serviceoverrides. Using the customer view for create/update, I need to be able to create, update and delete ServiceOverrides and manage the attributes of the associated model(s) from the same view. Visually I'd prefer to have something like a plus/minus sign to add/delete service overrides, and each serviceoverride record has two string entities which need to be displayed and editable as well. However, if I could just get the code (a kind of nested form, I'm assuming?) working, I could work out the UI aspects. The models are pretty simple: class ServiceOverride < ActiveRecord::Base has_and_belongs_to_many :customers end class Customer < ActiveRecord::Base has_and_belongs_to_many :serviceoverrides end The closest thing I've found explaining this online is on this blog but it doesn't really address what I'm trying to do (both manage the linkages to the other model, and edit attributes of that model. Any help is appreciated. Thanks in advance. Chris

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  • KendoUI Mobile switch and datasource

    - by OnaBai
    I'm trying to have a list of items displayed using a listview, something like: <div data-role="view" data-model="my_model"> <ul data-role="listview" data-bind="source: ds" data-template="list-tmpl"></ul> </div> Where I have a view using a model called my_model and a listview where the source is bound to ds. My model is something like: var my_model = kendo.observable({ ds: new kendo.data.DataSource({ transport: { read: readData, update: updateData, create: updateData, remove: updateData }, pageSize: 10, schema: { model: { id: "id", fields: { id: { type: "number" }, name: { type: "string" }, active: { type: "boolean" } } } } }) }); Each item includes an id, a name (that is a string) and a boolean named active. The template used to render each element is: <script id="list-tmpl" type="text/kendo-tmpl"> <span>#= name # : #= active #</span> <input data-role="switch" data-bind="checked: active"/> </script> Where I display the name and (for debugging) the value of active. In addition, I render a switch bound to active. You should see something like: The problems observed are: If you click on a switch you will see that the value of active next to the name changes its value (as expected) but if then, you pick another switch, the value (neither next to name nor in the DataSource) is not updated (despite the value of the switch is correctly updated). The update handler in the DataSource is never invoked (not even for the first chosen switch and despite the DataSource for that first toggled switch is updated). You can check it in JSFiddle: http://jsfiddle.net/OnaBai/K7wEC/ How do I make that the DataSource gets updated and update handler invoked?

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  • Cannot install Visual Editor Plugin on Eclipse

    - by lyuba
    I try to follow the instructions from here to install a Visual editor pulgin for Eclipse: http://wiki.eclipse.org/VE/Update Both online and offline installations fails with the following mistake: Cannot complete request. Generating details. Here is the complete log: Cannot complete the install because of a conflicting dependency. Software being installed: Java EMF Model 1.4.0.v20090826-1446-7H-FPbAcggQleH8hJifHfUd (org.eclipse.jem.feature.group 1.4.0.v20090826-1446-7H-FPbAcggQleH8hJifHfUd) Software currently installed: Eclipse IDE for Java EE Developers 1.2.2.20100217-2310 (epp.package.jee 1.2.2.20100217-2310) Only one of the following can be installed at once: Java EMF Model BeanInfo (Introspection) Support 2.0.300.v200905030615 (org.eclipse.jem.beaninfo 2.0.300.v200905030615) Java EMF Model BeanInfo (Introspection) Support 2.0.300.R3_1_maintenance (org.eclipse.jem.beaninfo 2.0.300.R3_1_maintenance) Cannot satisfy dependency: From: Eclipse IDE for Java EE Developers 1.2.2.20100217-2310 (epp.package.jee 1.2.2.20100217-2310) To: org.eclipse.epp.package.jee.feature.feature.group [1.2.2.20100217-2310] Cannot satisfy dependency: From: Java EE IDE Feature 1.2.2.20100217-2310 (org.eclipse.epp.package.jee.feature.feature.group 1.2.2.20100217-2310) To: org.eclipse.jst.web_ui.feature.feature.group 0.0.0 Cannot satisfy dependency: From: Java EMF Model 1.4.0.v20090826-1446-7H-FPbAcggQleH8hJifHfUd (org.eclipse.jem.feature.group 1.4.0.v20090826-1446-7H-FPbAcggQleH8hJifHfUd) To: org.eclipse.jem.beaninfo [2.0.300.R3_1_maintenance] Cannot satisfy dependency: From: JST Web Core 3.1.1.v200908121609-7S7CFyvFIhIehVidwyfk0m (org.eclipse.jst.web_core.feature.feature.group 3.1.1.v200908121609-7S7CFyvFIhIehVidwyfk0m) To: org.eclipse.jem.beaninfo [2.0.300.v200905030615] Cannot satisfy dependency: From: JST Web Core 3.1.1.v200908121609-7S7CG-dFIhIeq7kV6qxaLD (org.eclipse.jst.web_core.feature.feature.group 3.1.1.v200908121609-7S7CG-dFIhIeq7kV6qxaLD) To: org.eclipse.jem.beaninfo [2.0.300.v200905030615] Cannot satisfy dependency: From: JST Web UI 3.1.1.v200908121609-7E77FBfDlwYa_9sdy2q77doi14gl (org.eclipse.jst.web_ui.feature.feature.group 3.1.1.v200908121609-7E77FBfDlwYa_9sdy2q77doi14gl) To: org.eclipse.jst.web_core.feature.feature.group [3.1.1.v200908121609-7S7CFyvFIhIehVidwyfk0m] Cannot satisfy dependency: From: JST Web UI 3.1.1.v200908121609-7E77FBiDlwYcICNdz-5z-9PGqZCy (org.eclipse.jst.web_ui.feature.feature.group 3.1.1.v200908121609-7E77FBiDlwYcICNdz-5z-9PGqZCy) To: org.eclipse.jst.web_core.feature.feature.group [3.1.1.v200908121609-7S7CG-dFIhIeq7kV6qxaLD] Has anybody encountered something like this? Appreciate your ideas!

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  • How to overload operator<< for qDebug

    - by iyo
    Hi, I'm trying to create more useful debug messages for my class where store data. My code is looking something like this #include <QAbstractTableModel> #include <QDebug> /** * Model for storing data. */ class DataModel : public QAbstractTableModel { // for debugging purposes friend QDebug & operator<< (const QDebug &d, DataModel model); //other stuff }; /** * Overloading operator for debugging purposes */ QDebug & operator<< (QDebug &d, DataModel model) { d << "Hello world!"; return d; } I expect qDebug() << model will print "Hello world!". However, there is alway something like "QAbstractTableModel(0x1c7e520)" on the output. Do you have any idea what's wrong?

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