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  • ASP.NET MVC 2 - ViewModel Prefix

    - by Cosmo
    I want to use RenderPartial twice in my view with different models associated. The problem is that some properties are present in both models (nickname, password). They have no prefix, so even the id's or names are equal in the output. Now, if I have model errors for nickname or password, both fields get highlighted. Main View: <div> <% Html.RenderPartial("Register", Model.RegisterModel); %> </div> <div> <% Html.RenderPartial("Login", Model.LoginModel); %> </div> Login PartialView: <% using (Html.BeginForm("Login", "Member")) { %> <fieldset> <legend>Login</legend> <p> <%= Html.LabelFor(x => x.Nickname) %> <%= Html.TextBoxFor(x => x.Nickname) %> </p> <p> <%= Html.LabelFor(x => x.Password) %> <%= Html.PasswordFor(x => x.Password) %> </p> <input type="submit" value="Login" /> </fieldset> <% } % Register PartialView: <% using (Html.BeginForm("Register", "Member")) { %> <fieldset> <legend>Register</legend> <p> <%= Html.LabelFor(x => x.Nickname) %> <%= Html.TextBoxFor(x => x.Nickname) %> </p> <p> <%= Html.LabelFor(x => x.Email) %> <%= Html.TextBoxFor(x => x.Email) %> </p> <p> <%= Html.LabelFor(x => x.Password) %> <%= Html.PasswordFor(x => x.Password) %> </p> <p> <%= Html.LabelFor(x => x.PasswordRepeat) %> <%= Html.PasswordFor(x => x.PasswordRepeat) %> </p> <input type="submit" value="Register" /> </fieldset> <% } % How can I change this?

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  • How to read registry correctly for multiple values in c?

    - by kampi
    Hi! I created a .dll which should work like the RunAs command. The only difference is, that it should read from registry. My problem is, that i need to reed 3 values from the registry, but i can't. It reads the first, than it fails at the second one (Password) with error code 2, which means "The system cannot find the file specified". If i query only for domain and username then it is ok, if i query only for password then it it still succeeds, but if i want to query all three then it fails. Can someone tell me, what i am doing wrong? Heres my code: HKEY hKey = 0; DWORD dwType = REG_SZ; DWORD dwBufSize = sizeof(buf); TCHAR szMsg [MAX_PATH + 32]; HANDLE handle; LPVOID lpMsgBuf; if( RegOpenKeyEx( HKEY_CURRENT_USER, TEXT("SOFTWARE\\Kampi Corporation\\RunAs!"), 0, KEY_QUERY_VALUE, &hKey ) == ERROR_SUCCESS ) { if( RegQueryValueEx( hKey, TEXT("Username"), 0, &dwType, (LPBYTE)buf, &dwBufSize ) == ERROR_SUCCESS ) { memset( szMsg, 0, sizeof( szMsg ) ); wsprintf ( szMsg, _T("%s"), buf ); mbstowcs( wuser, szMsg, 255 ); RegCloseKey( hKey ); } else { MessageBox ( pCmdInfo->hwnd, "Can not query for Username key value!", _T("RunAs!"), MB_ICONERROR ); RegCloseKey( hKey ); return -1; } } else { CSimpleShlExt::showerror( GetLastError(), pCmdInfo->hwnd, "RegOpenKeyEx failed for Username with error code :: " ); return -1; } if( RegOpenKeyEx( HKEY_CURRENT_USER, TEXT("SOFTWARE\\Kampi Corporation\\RunAs!"), 0, KEY_QUERY_VALUE ,&hKey ) == ERROR_SUCCESS ) { if( RegQueryValueEx( hKey, TEXT("Password"), 0, &dwType, (LPBYTE)buf, &dwBufSize ) == ERROR_SUCCESS ) { memset( szMsg, 0, sizeof( szMsg ) ); wsprintf ( szMsg, _T("%s"), buf ); mbstowcs( wpass, szMsg, 255 ); RegCloseKey( hKey ); } else { char test[200]; sprintf(test,"Can not query for Password key value! EC: %d",GetLastError() ); MessageBox ( pCmdInfo->hwnd, test, _T("RunAs!"), MB_ICONERROR ); RegCloseKey( hKey ); return -1; } } else { CSimpleShlExt::showerror( GetLastError(), pCmdInfo->hwnd, "RegOpenKeyEx failed for Password with error code :: " ); return -1; } if( RegOpenKeyEx( HKEY_CURRENT_USER, TEXT("SOFTWARE\\Kampi Corporation\\RunAs!"), 0, KEY_QUERY_VALUE ,&hKey ) == ERROR_SUCCESS ) { if( RegQueryValueEx( hKey, TEXT("Domain"), 0, &dwType, (LPBYTE)buf, &dwBufSize ) == ERROR_SUCCESS ) { memset( szMsg, 0, sizeof( szMsg ) ); wsprintf ( szMsg, _T("%s"), buf ); mbstowcs( wdomain, szMsg, 255 ); RegCloseKey( hKey ); } else { char test[200]; sprintf(test,"Can not query for Password key value! EC: %d",GetLastError() ); MessageBox ( pCmdInfo->hwnd, test, _T("RunAs!"), MB_ICONERROR ); RegCloseKey( hKey ); return -1; } } else { CSimpleShlExt::showerror( GetLastError(), pCmdInfo->hwnd, "RegOpenKeyEx failed for Domain with error code :: " ); return -1; }

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  • Is this PHP/MySQL login script secure?

    - by NightMICU
    Greetings, A site I designed was compromised today, working on damage control at the moment. Two user accounts, including the primary administrator, were accessed without authorization. Please take a look at the log-in script that was in use, any insight on security holes would be appreciated. I am not sure if this was an SQL injection or possibly breach on a computer that had been used to access this area in the past. Thanks <?php //Start session session_start(); //Include DB config require_once('config.php'); //Error message array $errmsg_arr = array(); $errflag = false; //Connect to mysql server $link = mysql_connect(DB_HOST, DB_USER, DB_PASSWORD); if(!$link) { die('Failed to connect to server: ' . mysql_error()); } //Select database $db = mysql_select_db(DB_DATABASE); if(!$db) { die("Unable to select database"); } //Function to sanitize values received from the form. Prevents SQL injection function clean($str) { $str = @trim($str); if(get_magic_quotes_gpc()) { $str = stripslashes($str); } return mysql_real_escape_string($str); } //Sanitize the POST values $login = clean($_POST['login']); $password = clean($_POST['password']); //Input Validations if($login == '') { $errmsg_arr[] = 'Login ID missing'; $errflag = true; } if($password == '') { $errmsg_arr[] = 'Password missing'; $errflag = true; } //If there are input validations, redirect back to the login form if($errflag) { $_SESSION['ERRMSG_ARR'] = $errmsg_arr; session_write_close(); header("location: http://tapp-essexvfd.org/admin/index.php"); exit(); } //Create query $qry="SELECT * FROM user_control WHERE username='$login' AND password='".md5($_POST['password'])."'"; $result=mysql_query($qry); //Check whether the query was successful or not if($result) { if(mysql_num_rows($result) == 1) { //Login Successful session_regenerate_id(); //Collect details about user and assign session details $member = mysql_fetch_assoc($result); $_SESSION['SESS_MEMBER_ID'] = $member['user_id']; $_SESSION['SESS_USERNAME'] = $member['username']; $_SESSION['SESS_FIRST_NAME'] = $member['name_f']; $_SESSION['SESS_LAST_NAME'] = $member['name_l']; $_SESSION['SESS_STATUS'] = $member['status']; $_SESSION['SESS_LEVEL'] = $member['level']; //Get Last Login $_SESSION['SESS_LAST_LOGIN'] = $member['lastLogin']; //Set Last Login info $qry = "UPDATE user_control SET lastLogin = DATE_ADD(NOW(), INTERVAL 1 HOUR) WHERE user_id = $member[user_id]"; $login = mysql_query($qry) or die(mysql_error()); session_write_close(); if ($member['level'] != "3" || $member['status'] == "Suspended") { header("location: http://members.tapp-essexvfd.org"); //CHANGE!!! } else { header("location: http://tapp-essexvfd.org/admin/admin_main.php"); } exit(); }else { //Login failed header("location: http://tapp-essexvfd.org/admin/index.php"); exit(); } }else { die("Query failed"); } ?>

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  • Android: HttpURLConnection not working properly

    - by giorgiline
    I'm trying to get the cookies from a website after sending user credentials through a POST Request an it seems that it doesn't work in android this way. ¿Am I doing something bad?. Please help. I've searched here in different posts but there's no useful answer. It's curious that this run in a desktop Java implementation it works perfect but it crashes in Android platform. And it is exactly the same code, specifically when calling HttpURLConnection.getHeaderFields(), it also happens with other member methods. It's a simple code and I don't know why the hell isn't working. DESKTOP CODE: This goes just in the main() HttpURLConnection connection = null; OutputStream out = null; try { URL url = new URL("http://www.XXXXXXXX.php"); String charset = "UTF-8"; String postback = "1"; String user = "XXXXXXXXX"; String password = "XXXXXXXX"; String rememberme = "on"; String query = String.format("postback=%s&user=%s&password=%s&rememberme=%s" , URLEncoder.encode(postback, charset) , URLEncoder.encode(user,charset) , URLEncoder.encode(password, charset) , URLEncoder.encode(rememberme, charset)); connection = (HttpURLConnection)url.openConnection(); connection.setRequestMethod("POST"); connection.setRequestProperty("Accept-Charset", charset); connection.setDoOutput(true); connection.setFixedLengthStreamingMode(query.length()); out = connection.getOutputStream (); out.write(query.getBytes(charset)); if (connection.getHeaderFields() == null){ System.out.println("Header null"); }else{ for (String cookie: connection.getHeaderFields().get("Set-Cookie")){ System.out.println(cookie.split(";", 2)[0]); } } } catch (IOException e){ e.printStackTrace(); } finally { try { out.close();} catch (IOException e) { e.printStackTrace();} connection.disconnect(); } So the output is: login_key=20ad8177db4eca3f057c14a64bafc2c9 FASID=cabf20cc471fcacacdc7dc7e83768880 track=30c8183e4ebbe8b3a57b583166326c77 client-data=%7B%22ism%22%3Afalse%2C%22showm%22%3Afalse%2C%22ts%22%3A1349189669%7D ANDROID CODE: This goes inside doInBackground AsyncTask body HttpURLConnection connection = null; OutputStream out = null; try { URL url = new URL("http://www.XXXXXXXXXXXXXX.php"); String charset = "UTF-8"; String postback = "1"; String user = "XXXXXXXXX"; String password = "XXXXXXXX"; String rememberme = "on"; String query = String.format("postback=%s&user=%s&password=%s&rememberme=%s" , URLEncoder.encode(postback, charset) , URLEncoder.encode(user,charset) , URLEncoder.encode(password, charset) , URLEncoder.encode(rememberme, charset)); connection = (HttpURLConnection)url.openConnection(); connection.setRequestMethod("POST"); connection.setRequestProperty("Accept-Charset", charset); connection.setDoOutput(true); connection.setFixedLengthStreamingMode(query.length()); out = connection.getOutputStream (); out.write(query.getBytes(charset)); if (connection.getHeaderFields() == null){ Log.v(TAG, "Header null"); }else{ for (String cookie: connection.getHeaderFields().get("Set-Cookie")){ Log.v(TAG, cookie.split(";", 2)[0]); } } } catch (IOException e){ e.printStackTrace(); } finally { try { out.close();} catch (IOException e) { e.printStackTrace();} connection.disconnect(); } And here there is no output, it seems that connection.getHeaderFields() doesn't return result. It takes al least 30 seconds to show the Log: 10-02 16:56:25.918: V/class com.giorgi.myproject.activities.HomeActivity(2596): Header null

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  • Using jQuery to call a web service

    - by Matt
    I have created a web service which takes a username and password as parameters and returns a list of children in JSON (the user is a Social Worker). The web service is hosted locally with IIS7. I am attempting to access the web service using javascript/jquery because it will eventually need to run as a mobile app. I'm not really experienced with web services, or javascript for that matter, but the following two links seemed to point me in the right direction: http://williamsportwebdeveloper.com/cgi/wp/?p=494 http://encosia.com/using-jquery-to-consume-aspnet-json-web-services/ This is my html page: <%@ Page Title="" Language="C#" MasterPageFile="~/MasterPage.Master" AutoEventWireup="true" CodeBehind="TestWebService.aspx.cs" Inherits="Sponsor_A_Child.TestWebService" %> <asp:Content ID="Content1" ContentPlaceHolderID="stylesPlaceHolder" runat="server"> <script type="text/javascript" src="Scripts/jquery-1.7.1.js"> $(document).ready(function () { }); function LoginClientClick() { $("#query_results").empty(); $("#query_results").append('<table id="ResultsTable" class="ChildrenTable"><tr><th>Child_ID</th><th>Child_Name</th><th>Child_Surname</th></tr>'); $.ajax({ type: "POST", contentType: "application/json; charset=utf-8", url: "http://localhost/PhoneWebServices/GetChildren.asmx/GetMyChildren", data: '{ "email" : "' + $("#EmailBox").val() + '", "password": "' + $("#PasswordBox").val() + '" }', dataType: "json", success: function (msg) { var c = eval(msg.d); alert("" + c); for (var i in c) { $("#ResultsTable tr:last").after("<tr><td>" + c[i][0] + "</td><td>" + c[i][1] + "</td><td>" + c[i][2] + "</td></tr>"); } } }); } </script> </asp:Content> <asp:Content ID="Content2" ContentPlaceHolderID="contentPlaceHolder" runat="server"> <div id="LoginDiv"> Email: <input id="EmailBox" type="text" /><br /> Password: <input id="PasswordBox" type="password" /><br /> <input id="LoginButton" type="button" value="Submit" onclick="LoginClientClick()" /> </div> <div id="query_results"> </div> </asp:Content> And this is my web service code: [WebMethod (Description="Returns the list of children for whom the social worker is responsible.")] public String GetMyChildren(String email,String password) { DataSet MyChildren=new DataSet(); int ID=SocialWorkerLogin(email, password); if (ID > 0) { MyChildren = FillChildrenTable(ID); } MyChildren.DataSetName = "My Children"; //To prevent 'DataTable name not set' error string[][] JaggedArray = new string[MyChildren.Tables[0].Rows.Count][]; int i = 0; foreach (DataRow rs in MyChildren.Tables[0].Rows) { JaggedArray[i] = new string[] { rs["Child_ID"].ToString(), rs["Child_Name"].ToString(), rs["Child_Surname"].ToString() }; i = i + 1; } // Return JSON data JavaScriptSerializer js = new JavaScriptSerializer(); string strJSON = js.Serialize(JaggedArray); return strJSON; } I followed the examples in the provided links, but when I press submit, only the table headers appear but not the list of children. When I test the web service on it's own though, it does return a JSON string so that part seems to be working. Any help is greatly appreciated :)

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  • php curl http 405 error mind body online api

    - by K_G
    I am trying to connect to the Mind Body Online API (their forum is down currently, so I came here). Below is the code I am using. I am receiving this: SERVER ERROR 405 - HTTP verb used to access this page is not allowed. The page you are looking for cannot be displayed because an invalid method (HTTP verb) was used to attempt to access. code: //Data, connection, auth $soapUrl = "http://clients.mindbodyonline.com/api/0_5"; // xml post structure $xml_post_string = '<?xml version="1.0" encoding="utf-8"?> <soapenv:Envelope xmlns:soapenv="http://schemas.xmlsoap.org/soap/envelope/" xmlns="http://clients.mindbodyonline.com/api/0_5"> <soapenv:Header/> <soapenv:Body> <GetClasses> <Request> <SourceCredentials> <SourceName>username</SourceName> <Password>password</Password> <SiteIDs> <int>site id</int> </SiteIDs> </SourceCredentials> <UserCredentials> <Username>username</Username> <Password>password</Password> <SiteIDs> <int></int> </SiteIDs> </UserCredentials> <Fields> <string>Classes.Resource</string> </Fields> <XMLDetail>Basic</XMLDetail> <PageSize>10</PageSize> <CurrentPageIndex>0</CurrentPageIndex> </Request> </GetClasses> </soapenv:Body> </soapenv:Envelope>'; $headers = array( "Content-type: text/xml;charset=\"utf-8\"", "Accept: text/xml", "Cache-Control: no-cache", "Pragma: no-cache", "SOAPAction: http://clients.mindbodyonline.com/api/0_5", "Content-length: ".strlen($xml_post_string), ); //SOAPAction: your op URL $url = $soapUrl; // PHP cURL for https connection with auth $ch = curl_init(); curl_setopt($ch, CURLOPT_URL, $url); curl_setopt($ch, CURLOPT_RETURNTRANSFER, true); curl_setopt($ch, CURLOPT_HTTPAUTH, CURLAUTH_ANY); curl_setopt($ch, CURLOPT_TIMEOUT, 10); curl_setopt($ch, CURLOPT_POST, true); curl_setopt($ch, CURLOPT_POSTFIELDS, $xml_post_string); // the SOAP request curl_setopt($ch, CURLOPT_HTTPHEADER, $headers); // converting $response = curl_exec($ch); curl_close($ch); var_dump($response); // converting //$response1 = str_replace("<soap:Body>","",$response); //$response2 = str_replace("</soap:Body>","",$response1); // convertingc to XML //$parser = simplexml_load_string($response2); // user $parser to get your data out of XML response and to display it. Any help would be great and if anyone has any experience working with their API, my first time ;) Here is the post on stack I am going off of: SOAP request in PHP

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  • upload video to youtube via iphone application ----ServiceForbiddenException

    - by user577670
    Hey,I use GData try to upload my video to youtube, but meet these error: serviceBase:<GDataServiceGoogleYouTube: 0x2435f0> objectFetcher:<GDataHTTPUploadFetcher: 0x26dca0> failedWithStatus:403 data:<errors xmlns='http://schemas.google.com/g/2005'> <error> <domain>GData</domain> <code>ServiceForbiddenException</code> <internalReason>Currently authenticated user does not have write access to desrender&apos;s videos.</internalReason> </error> </errors> * is my youtube account. Following is the code: - (GDataServiceGoogleYouTube *)youTubeService { static GDataServiceGoogleYouTube* service = nil; if (!service) { service = [[GDataServiceGoogleYouTube alloc] init]; [service setShouldCacheDatedData:YES]; [service setServiceShouldFollowNextLinks:YES]; [service setIsServiceRetryEnabled:YES]; } // update the username/password each time the service is requested NSString *username = [mUsernameField text]; NSString *password = [mPasswordField text]; if ([username length] > 0 && [password length] > 0) { [service setUserCredentialsWithUsername:username password:password]; } else { // fetch unauthenticated [service setUserCredentialsWithUsername:nil password:nil]; } NSString *devKey = [mDeveloperKeyField text]; [service setYouTubeDeveloperKey:devKey]; return service; } - (IBAction)uploadPressed:(id)sender { NSString *devKey = [mDeveloperKeyField text]; GDataServiceGoogleYouTube *service = [self youTubeService]; [service setYouTubeDeveloperKey:devKey]; NSString *username = [mUsernameField text]; NSString *clientID = [mClientIDField text]; NSURL *url = [GDataServiceGoogleYouTube youTubeUploadURLForUserID:username clientID:clientID]; // load the file data NSString *path = [[NSBundle mainBundle] pathForResource:@"YouTubeTest" ofType:@"m4v"]; NSData *data = [NSData dataWithContentsOfFile:path]; NSString *filename = [path lastPathComponent]; // gather all the metadata needed for the mediaGroup NSString *titleStr = [mTitleField text]; GDataMediaTitle *title = [GDataMediaTitle textConstructWithString:titleStr]; NSString *categoryStr = [mCategoryField text]; GDataMediaCategory *category = [GDataMediaCategory mediaCategoryWithString:categoryStr]; [category setScheme:kGDataSchemeYouTubeCategory]; NSString *descStr = [mDescriptionField text]; GDataMediaDescription *desc = [GDataMediaDescription textConstructWithString:descStr]; NSString *keywordsStr = [mKeywordsField text]; GDataMediaKeywords *keywords = [GDataMediaKeywords keywordsWithString:keywordsStr]; BOOL isPrivate = mIsPrivate; GDataYouTubeMediaGroup *mediaGroup = [GDataYouTubeMediaGroup mediaGroup]; [mediaGroup setMediaTitle:title]; [mediaGroup setMediaDescription:desc]; [mediaGroup addMediaCategory:category]; [mediaGroup setMediaKeywords:keywords]; [mediaGroup setIsPrivate:isPrivate]; NSString *mimeType = [GDataUtilities MIMETypeForFileAtPath:path defaultMIMEType:@"video/mp4"]; // create the upload entry with the mediaGroup and the file data GDataEntryYouTubeUpload *entry; entry = [GDataEntryYouTubeUpload uploadEntryWithMediaGroup:mediaGroup data:data MIMEType:mimeType slug:filename]; SEL progressSel = @selector(ticket:hasDeliveredByteCount:ofTotalByteCount:); [service setServiceUploadProgressSelector:progressSel]; GDataServiceTicket *ticket; ticket = [service fetchEntryByInsertingEntry:entry forFeedURL:url delegate:self didFinishSelector:@selector(uploadTicket:finishedWithEntry:error:)]; [self setUploadTicket:ticket]; } It almost same as GData's YouTubeSample.. Someone help me!!!!

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  • ASP.Net MVC 2 is it possible to get the same instance of model(with slight changes) in HttpPost meth

    - by jjjjj
    Hi I have a complex entity User: public class User : BaseEntity { public virtual Taxi Taxi { get; set; } --> That is why i call it "complex" public virtual string Login { get; set; } public virtual string Password { get; set; } } where Taxi is a parent of User (Taxi has-many Users): public class Taxi : BaseEntity { public virtual string Name { get; set; } public virtual string ClientIp { get; set; } } BaseEntity consists of public virtual int Id { get; private set; } The problem occurs while trying to edit User [Authorize] public ActionResult ChangeAccountInfo() { var user = UserRepository.GetUser(User.Identity.Name); return View(user); } My ChangeAccountInfo.aspx <fieldset> <legend>Fields</legend> <% %> <div class="editor-label"> <%: Html.LabelFor(model => model.Login) %> </div> <div class="editor-field"> <%: Html.TextBoxFor(model => model.Login) %> <%: Html.ValidationMessageFor(model => model.Login) %> </div> <div class="editor-label"> <%: Html.LabelFor(model => model.Password) %> </div> <div class="editor-field"> <%: Html.TextBoxFor(model => model.Password) %> <%: Html.ValidationMessageFor(model => model.Password) %> </div> <div class="editor-field"> <%: Html.HiddenFor(model => model.Taxi.Name)%> </div> <p> <input type="submit" value="Save" /> </p> </fieldset> Post changes: [Authorize] [HttpPost] public ActionResult ChangeAccountInfo(User model) { if (ModelState.IsValid) { UserRepository.UpdateUser(model); return RedirectToAction("ChangeAccountInfoSuccess", "Account"); } return View(model); } But, the (User model) parameter has User.Id == 0 -- User entity had 5 before edit User.Login == "my new login" User.Password == "my new password" User.Taxi.Id == 0 -- User.Taxi entity had 3 before edit User.Taxi.Name == "old hidden name" User.Taxi.ClientIp == null -- User entity had 192.168.0.1 before edit Q: Is it possible not to mark all the fields of an entity (that should be in my UpdateUser) with tag "hidden" but still have them unchanged in my HttpPost method? e.g. not User.Taxi.ClientIp = null, but User.Taxi.ClientIp = 192.168.0.1 I'm using nhibernate, if it matters.

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  • Java, LDAP: Make it not ignore blank passwords?

    - by Steve
    I'm maintaining some legacy Java LDAP code. I know next to nothing about LDAP. The program below basically just sends the userid and password to the LDAP server, receives notification back if the credentials are good. If so, it prints out the LDAP attributes received from the LDAP server, if not it prints out an exception. All works well if a bad password is given. An "invalid credentials" exception gets thrown. However, if a blank password is sent to the LDAP Server, authentication will still happen, LDAP attributes will still be returned. Is this unhappy situation due to the LDAP server allowing blank passwords, or does the code below need to be adjusted such a blank password will get fed to the LDAP server in such a way so it will get rejected? I do have data validation in place. I took it off in a testing environment to solve another issue and noticed this problem. I would prefer not to have this problem underneath the data validation. Thanks much in advance for any information import javax.naming.*; import javax.naming.directory.*; import java.util.*; import java.sql.*; public class LDAPTEST { public static void main(String args[]) { String lcf = "com.sun.jndi.ldap.LdapCtxFactory"; String ldapurl = "ldaps://ldap-cit.smew.acme.com:636/o=acme.com"; String loginid = "George.Jetson"; String password = ""; DirContext ctx = null; Hashtable env = new Hashtable(); Attributes attr = null; Attributes resultsAttrs = null; SearchResult result = null; NamingEnumeration results = null; int iResults = 0; int iAttributes = 0; env.put(Context.INITIAL_CONTEXT_FACTORY, lcf); env.put(Context.PROVIDER_URL, ldapurl); env.put(Context.SECURITY_PROTOCOL, "ssl"); env.put(Context.SECURITY_AUTHENTICATION, "simple"); env.put(Context.SECURITY_PRINCIPAL, "uid=" + loginid + ",ou=People,o=acme.com"); env.put(Context.SECURITY_CREDENTIALS, password); try { ctx = new InitialDirContext(env); attr = new BasicAttributes(true); attr.put(new BasicAttribute("uid",loginid)); results = ctx.search("ou=People",attr); while (results.hasMore()) { result = (SearchResult)results.next(); resultsAttrs = result.getAttributes(); for (NamingEnumeration enumAttributes = resultsAttrs.getAll(); enumAttributes.hasMore();) { Attribute a = (Attribute)enumAttributes.next(); System.out.println("attribute: " + a.getID() + " : " + a.get().toString()); iAttributes++; }// end for loop iResults++; }// end while loop System.out.println("Records == " + iResults + " Attributes: " + iAttributes); }// end try catch (Exception e) { e.printStackTrace(); } }// end function main() }// end class LDAPTEST

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  • User welcome message in php

    - by user225269
    How do I create a user welcome message in php. So that the user who has been logged on will be able to see his username. I have this code, but it doesn't seem to work. <?php $con = mysql_connect("localhost","root","nitoryolai123$%^"); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("school", $con); $result = mysql_query("SELECT * FROM users WHERE Username='$username'"); while($row = mysql_fetch_array($result)) { echo $row['Username']; echo "<br />"; } ?> I'm trying to make use of the data that is inputted in this login form: <form name="form1" method="post" action="verifylogin.php"> <td> <table border="0" cellpadding="3" cellspacing="1" bgcolor=""> <tr> <td colspan="16" height="25" style="background:#5C915C; color:white; border:white 1px solid; text-align: left"><strong><font size="2">Login User</strong></td> </tr> <tr> <td width="30" height="35"><font size="2">Username:</td> <td width="30"><input name="myusername" type="text" id="idnum" maxlength="5"></td> </tr> <tr> <td width="30" height="35" ><font size="2">Password:</td> <td width="30"><input name="mypassword" type="password" id="lname" maxlength="15"></td> </tr> <td align="right" width="30"><td align="right" width="30"><input type="submit" name="Submit" value="Submit" /></td> <td align="right" width="30"><input type="reset" name="Reset" value="Reset"></td></td> </tr> </form> But this, verifylogin.php, seems to be in the way. <?php $host="localhost"; $username="root"; $password="nitoryolai123$%^"; $db_name="school"; $tbl_name="users"; mysql_connect("$host", "$username", "$password")or die("cannot connect"); mysql_select_db("$db_name")or die("cannot select DB"); $myusername=$_POST['myusername']; $mypassword=$_POST['mypassword']; $myusername = stripslashes($myusername); $mypassword = stripslashes($mypassword); $myusername = mysql_real_escape_string($myusername); $mypassword = mysql_real_escape_string($mypassword); $sql="SELECT * FROM $tbl_name WHERE username='$myusername' and password='$mypassword'"; $result=mysql_query($sql); $count=mysql_num_rows($result); if($count==1){ session_register("myusername"); session_register("mypassword"); header("location:userpage.php"); } else { echo "Wrong Username or Password"; } ?> How do I do it? I always get this error when I run it: Notice: Undefined variable: username in C:\wamp\www\exp\userpage.php on line 53 Can you recommend of an easier on how I can achieve the same thing?

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  • How can i clear a SQLite database each time i start my app

    - by AndroidUser99
    Hi, i want that each time i start my app my SQLite database get's cleaned for this, i need to make a method on my class MyDBAdapter.java code examples are welcome, i have no idea how to do it this is the dbadapter/helper i'm using: public class MyDbAdapter { private static final String TAG = "NotesDbAdapter"; private DatabaseHelper mDbHelper; private SQLiteDatabase mDb; private static final String DATABASE_NAME = "gpslocdb"; private static final String PERMISSION_TABLE_CREATE = "CREATE TABLE permission ( fk_email1 varchar, fk_email2 varchar, validated tinyint, hour1 time default '08:00:00', hour2 time default '20:00:00', date1 date, date2 date, weekend tinyint default '0', fk_type varchar, PRIMARY KEY (fk_email1,fk_email2))"; private static final String USER_TABLE_CREATE = "CREATE TABLE user ( email varchar, password varchar, fullName varchar, mobilePhone varchar, mobileOperatingSystem varchar, PRIMARY KEY (email))"; private static final int DATABASE_VERSION = 2; private final Context mCtx; private static class DatabaseHelper extends SQLiteOpenHelper { DatabaseHelper(Context context) { super(context, DATABASE_NAME, null, DATABASE_VERSION); } @Override public void onCreate(SQLiteDatabase db) { db.execSQL(PERMISSION_TABLE_CREATE); db.execSQL(USER_TABLE_CREATE); } @Override public void onUpgrade(SQLiteDatabase db, int oldVersion, int newVersion) { db.execSQL("DROP TABLE IF EXISTS user"); db.execSQL("DROP TABLE IF EXISTS permission"); onCreate(db); } } /** * Constructor - takes the context to allow the database to be * opened/created * * @param ctx the Context within which to work */ public MyDbAdapter(Context ctx) { this.mCtx = ctx; } /** * Open the database. If it cannot be opened, try to create a new * instance of the database. If it cannot be created, throw an exception to * signal the failure * * @return this (self reference, allowing this to be chained in an * initialization call) * @throws SQLException if the database could be neither opened or created */ public MyDbAdapter open() throws SQLException { mDbHelper = new DatabaseHelper(mCtx); mDb = mDbHelper.getWritableDatabase(); return this; } public void close() { mDbHelper.close(); } public long createUser(String email, String password, String fullName, String mobilePhone, String mobileOperatingSystem) { ContentValues initialValues = new ContentValues(); initialValues.put("email",email); initialValues.put("password",password); initialValues.put("fullName",fullName); initialValues.put("mobilePhone",mobilePhone); initialValues.put("mobileOperatingSystem",mobileOperatingSystem); return mDb.insert("user", null, initialValues); } public Cursor fetchAllUsers() { return mDb.query("user", new String[] {"email", "password", "fullName", "mobilePhone", "mobileOperatingSystem"}, null, null, null, null, null); } public Cursor fetchUser(String email) throws SQLException { Cursor mCursor = mDb.query(true, "user", new String[] {"email", "password", "fullName", "mobilePhone", "mobileOperatingSystem"} , "email" + "=" + email, null, null, null, null, null); if (mCursor != null) { mCursor.moveToFirst(); } return mCursor; } public List<Friend> retrieveAllUsers() { List <Friend> friends=new ArrayList<Friend>(); Cursor result=fetchAllUsers(); if( result.moveToFirst() ){ do{ //note.getString(note.getColumnIndexOrThrow(NotesDbAdapter.KEY_TITLE))); friends.add(new Friend(result.getString(result.getColumnIndexOrThrow("email")), "","","","")); }while( result.moveToNext() ); } return friends; } }

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  • Samba smbtree No output; failed to retrieve share list

    - by TomKat
    I'm using Ubuntu 12.10 on two machines, one laptop & one desktop. Faced the same problem when I used 12.04. When I try connecting to the other machine using 'Connect to Server', I give the correct user & workgroup details, but the system displays 'failed to retrieve server list' I've tried editing /etc/samba/smb.conf file to: name resolve order = lmhosts host wins bcast I also added the other machine to /etc/hosts But, nothing worked. The output of smbtree is naveen@tomkat:~$ smbtree Enter naveen's password: naveen@tomkat:~$ Used sources to solve problem myself: "Failed to retrieve share list from server" error when browsing a share with Nautilus http://ubuntuforums.org/showthread.php?t=1114038 All help will be appreciated. Thanks. UPDATE: After 'purging' samba and all its components (incl all config files), and reinstall, sharing workes in one direction (from Laptop to Desktop) but when I attempt to use the Desktop as server, same problem is still faced. UPDATE 2 dpkg -l|grep samba output: naveen@tomkat:~$ sudo dpkg -l|grep samba [sudo] password for naveen: ii libcrypt-smbhash-perl 0.12-3 all generate LM/NT hash of a password for samba ii samba 2:3.6.6-3ubuntu5 i386 SMB/CIFS file, print, and login server for Unix ii samba-common 2:3.6.6-3ubuntu5 all common files used by both the Samba server and client ii samba-common-bin 2:3.6.6-3ubuntu5 i386 common files used by both the Samba server and client

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  • Tomcat6 Manager Webapp is 404 on apt-get install on Ubuntu 10.10

    - by Noel
    http://localhost:8080/manager/html gives a 404 error on apt-get install of tomcat6 (6.0.28 on JVM 1.6.0_20-b20 on 2.6.35-27-generic amd64). http://localhost:8080/host-manager/html works. Lists one Host name, localhost. Installed tomcat6-admin with apt-get. $ ls dpkg -l | grep -i tomcat6-admin ii tomcat6-admin 6.0.28-2ubuntu1.1 Servlet and JSP engine -- admin web applications $ cat /usr/share/tomcat6/conf/tomcat-users.xml <tomcat-users> <role rolename="admin"/> <role rolename="manager" /> <user username="tomcatuser" password="Password1" roles="admin,manager"/> </tomcat-users> $ cat /usr/share/tomcat6/conf/Catalina/localhost/manager.xml <Context path="/manager" docBase="/usr/share/tomcat6-admin/manager" antiResourceLocking="false" privileged="true" /> <role name="manager" /> <user name="manager" password="Password1" roles="manager" /> <user name="tomcatuser" password="Password1" roles="manager" /> Those two files are the only documentation I've seen on how to setup the Manager webapp, and they seem to be compliant with the requirements.

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  • Tomcat6 Manager Webapp returns a 404

    - by Noel
    http://localhost:8080/manager/html gives a 404 error on apt-get install of tomcat6 (6.0.28 on JVM 1.6.0_20-b20 on 2.6.35-27-generic amd64). http://localhost:8080/host-manager/html works. Lists one Host name, localhost. Installed tomcat6-admin with apt-get. ls dpkg -l | grep -i tomcat6-admin ii tomcat6-admin 6.0.28-2ubuntu1.1 Servlet and JSP engine -- admin web applications $ cat /usr/share/tomcat6/conf/tomcat-users.xml <tomcat-users> <role rolename="admin"/> <role rolename="manager" /> <user username="tomcatuser" password="Password1" roles="admin,manager"/> </tomcat-users> cat /usr/share/tomcat6/conf/Catalina/localhost/manager.xml <Context path="/manager" docBase="/usr/share/tomcat6-admin/manager" antiResourceLocking="false" privileged="true" /> <role name="manager" /> <user name="manager" password="Password1" roles="manager" /> <user name="tomcatuser" password="Password1" roles="manager" /> Those two files are the only documentation I've seen on how to setup the Manager webapp, and they seem to be compliant with the requirements.

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  • Uploading documents to WSS (Windows Sharepoint Services) using SSIS

    - by Randy Aldrich Paulo
    Recently I was tasked to create an SSIS application that will query a database, split the results with certain criteria and create CSV file for every result and upload the file to a Sharepoint Document Library site. I've search the web and compiled the steps I've taken to build the solution. Summary: A) Create a proxy class of WSS Copy.asmx. B) Create a wrapper class for the proxy class and add a mechanism to check if the file is existing and delete method. C) Create an SSIS and call the wrapper class to transfer the files.   A) Creating Proxy Class 1) Go to Visual Studio Command Prompt type wsdl http://[sharepoint site]/_vti_bin/Copy.asmx this will generate the proxy class (Copy.cs) that will be added to the solution. 2) Add Copy.cs to solution and create another constructor for Copy() that will accept additional parameters url, userName, password and domain.   public Copy(string url, string userName, string password, string domain) { this.Url = url; this.Credentials = new System.Net.NetworkCredential(userName, password, domain); } 3) Add a namespace.     B) Wrapper Class Create a C# new library that references the Proxy Class.         C) Create SSIS SSIS solution is composed of:   1) Execute SQL Task, returns a single column rows containing the criteria. 2) Foreach Loop Container - loops per result from query (SQL Task) and creates a CSV file on a certain folder. 3) Script Task - calls the wrapper class to upload CSV files located on a certain folder to targer WSS Document Library Note: I've created another overload of CopyFiles that accepts a Directory Info instead of file location that loops thru the contents of the folder. Designer View Variable View

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  • Securing ASP.Net Pages - Forms Authentication - C# and .Net 4

    - by SAMIR BHOGAYTA
    ASP.Net has a built-in feature named Forms Authentication that allows a developer to easily secure certain areas of a web site. In this post I'm going to build a simple authentication sample using C# and ASP.Net 4.0 (still in beta as of the posting date). Security settings with ASP.Net is configured from within the web.config file. This is a standard ASCII file, with an XML format, that is located in the root of your web application. Here is a sample web.config file: configuration system.web authenticationmode="Forms" formsname="TestAuthCookie"loginUrl="login.aspx"timeout="30" credentialspasswordFormat="Clear" username="user1"password="pass1"/ username="user2"password="pass2"/ authorization denyusers="?"/ compilationtargetFramework="4.0"/ pagescontrolRenderingCompatibilityVersion="3.5"clientIDMode="AutoID"/ Here is the complete source of the sample login.aspx page: div Username: asp:TextBox ID="txtUsername" runat="server":TextBox Password: asp:TextBox ID="txtPassword" runat="server":TextBox asp:Button ID="Button1" runat="server" onclick="Button1_Click" Text="Login" / asp:Label ID="lblStatus" runat="server" Text="Please login":Label /div And here is the complete source of the login.aspx.cs file: using System; using System.Web.UI.WebControls; using System.Web.Security; public partial class Default3 : System.Web.UI.Page { protected void Button1_Click(object sender, EventArgs e) { if (FormsAuthentication.Authenticate(txtUsername.Text, txtPassword.Text)) { lblStatus.Text = ("Welcome " + txtUsername.Text); FormsAuthentication.RedirectFromLoginPage(txtUsername.Text, true); } else { lblStatus.Text = "Invalid login!"; } } }

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  • Connecting MS SQL using freetds and unixodbc: isql - no default driver specified

    - by Dejan
    I am trying to connect to the MS SQL database using freetds and unixodbc. I have read various guides how to do it, but no one works fine for me. When I try to connect to the database using isql tool, I get the following error: $ isql -v TS username password [IM002][unixODBC][Driver Manager]Data source name not found, and no default driver specified [ISQL]ERROR: Could not SQLConnect Have anybody already successfully established the connection to the MS SQL database using freetds and unixodbc on Ubuntu 12.04? I would really appreciate some help. Below is the procedure I used to configure the freetds and unixodbc. Thanks for your help in advance! Procedure First, I have installed the following packages sudo apt-get unixodbc unixodbc-dev freetds-dev tdsodbc and configured freetds as follows: --- /etc/freetds/freetds.conf --- [TS] host = SERVER port = 1433 tds version = 7.0 client charset = UTF-8 Using tsql tool I can successfully connect to the database by executing tsql -S TS -U username -P password As I need an odbc connection I configured odbcinst.ini as follows: --- /etc/odbcinst.ini --- [FreeTDS] Description = FreeTDS Driver = /usr/lib/x86_64-linux-gnu/odbc/libtdsodbc.so Setup = /usr/lib/x86_64-linux-gnu/odbc/libtdsS.so FileUsage = 1 CPTimeout = CPResuse = client charset = utf-8 and odbc.ini as follows: --- /etc/odbc.ini --- [TS] Description = "test" Driver = FreeTDS Servername = SERVER Server = SERVER Port = 1433 Database = DBNAME Trace = No Trying to connect to the database using isql tool with such a configuration results the following error: $ isql -v TS username password [IM002][unixODBC][Driver Manager]Data source name not found, and no default driver specified [ISQL]ERROR: Could not SQLConnect

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  • C# Simple Twitter Update

    - by mroberts
    For what it's worth a simple twitter update. 1: using System; 2: using System.IO; 3: using System.Net; 4: using System.Text; 5:   6: namespace Server.Actions 7: { 8: public class TwitterUpdate 9: { 10: public string Body { get; set; } 11: public string Login { get; set; } 12: public string Password { get; set; } 13:   14: public override void Execute() 15: { 16: try 17: { 18: //encode user name and password 19: string creds = Convert.ToBase64String(Encoding.ASCII.GetBytes(string.Format("{0}:{1}", this.Login, this.Password))); 20:   21: //encode tweet 22: byte[] tweet = Encoding.ASCII.GetBytes("status=" + this.Body); 23:   24: //setup request 25: HttpWebRequest request = (HttpWebRequest)WebRequest.Create("http://twitter.com/statuses/update.xml"); 26: request.Method = "POST"; 27: request.ServicePoint.Expect100Continue = false; 28: request.Headers.Add("Authorization", string.Format("Basic {0}", creds)); 29: request.ContentType = "application/x-www-form-urlencoded"; 30: request.ContentLength = tweet.Length; 31:   32: //write to stream 33: Stream reqStream = request.GetRequestStream(); 34: reqStream.Write(tweet, 0, tweet.Length); 35: reqStream.Close(); 36:   37: //check response 38: HttpWebResponse response = (HttpWebResponse)request.GetResponse(); 39:   40: //... 41: } 42: catch (Exception e) 43: { 44: //... 45: } 46: } 47: } 48: }   BTW, this is my first blog post.  Nothing earth shattering, I admit, but I needed to figure out how to post formatted code.  In the past I’ve used Alex Gorbatchev’s Syntax Highlighter with great success, but here at GWB I couldn’t get it to work. Windows Live Writer though, being a stand alone writer, worked with no problems.  For now, that’s what I’ll use.

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  • BI Applications 7.9.6.3 and EBS 12.1.3 Vision: Integrated Demo Environments

    - by Mike.Hallett(at)Oracle-BI&EPM
    If you need a combined BI-Applications + eBusiness Suite Applications demonstration environment, or for proof of concept work for your customers, then these versions of images on Oracle Virtual Box are now available for partners to download and use.  To get access to these images, Partners must be OPN members, specialised in OBI or BI-Apps.   This is an integrated Demo/Test Drive/POC/Self Enablement environment including two separate images (in English) representing the entire Oracle Stack – Applications, Middleware, Database, Operating System and Virtual Machine. Minimum Hardware requirements for each image to run separately 4GB RAM Minimum Hardware requirements for both images to run concurrently 8GB RAM Dual CPU 64 bit OS   BI Applications 7.9.6.3 Linux based and running on Oracle Virtual Box and compatible with OVM Image Content: BI Application Analytics demo data extracted from EBS 12.1.3 Vision for Financials and HR using EBS 12.1.3 Vision (image supplied) Built Integration to EBS 12.1.3 Vision image (provided). Fully functional BI Applications 7.9.6.3 software install and configuration Image can be connected to load any data from any other compatible source system. BI Apps Demo data is based on OOTB EBS Vision 12.1.3 Configured to run BI Apps data load for all other modules of EBS 12.1.3 Vision. Includes OBIEE Sample demonstration content Documented scripts for running presentations, demonstrations and Test Drives Image Size: 34GB zip, 84GB unzip.  Min Hardware 4GB RAM         EBS Vision 12.1.3 Linux based and running on Oracle Virtual Box and compatible with OVM Image Content: eBusiness Suite (EBS) Applications Vision 12.1.3 Standard Vision instance with all given setups, configurations and data Source system for BI Apps 7.9.6.3 Image Size: 76GB zip, 300GB unzip.  Min Hardware 4GB RAM Distribution: The Virtual Box images are posted on an external FTP server @ BI Applications 7.9.6.3 EBS12.1.3   To download, Partners need to request the current password to access the images.  To request the current ftp.oracle.com password and the password required to unzip the images, please email Marek Winiarski   Support Contact =  Marek Winiarski: Oracle Partner Solution Consultant

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  • Screen lock broken when using separate x screens

    - by Wolf
    For some reason, the screen lock appears to be broken when I use separate x screens (it works fine if I use twin view or just one monitor, though). If I wait for the screen to lock (or if I tell it to lock), it fades to black, showing only the mouse cursor. However, when I move the mouse to bring up the password prompt, nothing happens, the screens remain completely blank. Furthermore, it would appear that the screen lock never activated in the first place, for two reasons: one, if I blindly enter my password and press enter, nothing happens; and two, if I press ctrl+alt+delete and then enter it logs me out (which shouldn't happen if the password prompt is there, right), losing any progress I have on any of the open programs (meaning, not a very friendly option for a programmer ;) ). So yeah, does anyone know why this is happening, and how to fix it? Thanks! Notes: I am using Ubuntu 11.10 64 bit. I am using gnome-classic, but the same problem occurs when I use unity. I do not have xscreensaver, nor do I have any screen savers running (except, I guess for the default blank one).

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  • ASP.NET 4 Hosting :: How to set up Forms Authentication for your ASP.NET web site

    - by mbridge
    Please follow this steps: 1. Log in to your Control Panel. 2. From the menu, select Databases ? SQL Server 2008. 3. Click the Create User button. 4. Enter a user name and password and click Save. In this demonstration, the user name is dotnetuser and the password is dotnetuserpass. 5. Click the Create Database button. 6. Enter a database name and grant access to the user you created above and click Save. In this demonstration the database is called DotNetAuthentication. 7. Locate and run the ASP.NET SQL Server Setup Wizard. This file is located in your .NET framework directory and is named aspnet_regsql.exe (example: C:\Windows\Microsoft.NET\Framework64\v4.0.30319\aspnet_regsql.exe). 8. Click Next and choose Configure SQL Server for application services. 9. Click Next and enter the server name and database log in credentials. The server name is the web site pointer address to where your application will be published and the log in credentials are the SQL server user name and password created earlier. 10. Click Next twice and the wizard will take a moment to complete the scripting actions that populate the new database with all the objects necessary to configure the ASP.NET provider.  Once complete, click Finish to close the wizard. 11. Finally, modify the web.config file in your ASP.NET web application to use the database you created.

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  • Entity Object Based on PL/SQL

    - by Manoj Madhusoodanan
    This blog describes how to create a PL/SQL based Entity Object.Oracle application has number of APIs and each API will perform numerous number of tasks.We can create PL/SQL based EO which will directly invoke the PL/SQL stored procedure from the EO. Here I am demonstrating using a standard API FND_USER_PKG.CREATEUSER.This API has x_user_name and x_owner as mandatory parameter.My task is to create a user through OAF page which will accept User Name and Password. Following steps needs to be performed to achieve the above scenario. 1) Create FndUserEO as follows Include all the API parameters and WHO columns in the EO. Make UserName and EncryptedUserPassword ( Here I am not using Encrypted Password. The column name is same as table column so I am keeping the same) column as mandatory. Generate VO. 2) Edit FndUserEOImpl and add the following 3) Attach FndUserVO to AM 4) Create the UI 5) Deploy following files to middle tier and restart the server.  Entity Object: xxcust.oracle.apps.fnd.user.schema.server.FndUserEO.xml xxcust.oracle.apps.fnd.user.schema.server.FndUserEOImpl.java View Object: xxcust.oracle.apps.fnd.user.server.FndUserVO.xml xxcust.oracle.apps.fnd.user.server.FndUserVOImpl.javaUser Interface: xxcust.oracle.apps.fnd.user.webui.CreateFndUserCO.java xxcust.oracle.apps.fnd.user.webui.CreateFndUserPG.xmlYou can test by giving User Name and Password.

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  • Database Replication check script not running

    - by Tarun
    I'm trying to create a Database Replication checking script but I'm getting error while executing it. Here is the script #!/bin/bash PATH=/usr/local/sbin:/usr/local/bin:/usr/sbin:/usr/bin:/sbin:/bin export PATH #Server Name Server="Test Server" #My Sql Username and Password User=root Password="a" #Maximum Slave Time Delay Delay="60" #File Path to store error and email the same Log_File=/tmp/replicationcheck.txt #Email Settings Subject="$Server Replication Error" Sender_Name=TestServer Recipients="[email protected]" #Mail Alert Function mailalert(){ sendmail -F $Sender_Name -it <<END_MESSAGE To: $Recipients Subject: $Subject $Message_Replication_Error `/bin/cat $Log_File` END_MESSAGE } #Show Slave Status Show_Slave_Status=`echo "show slave status \G;" | mysql -u $User -p$Password 2>&1` #Getting list of queries in mysql $Show_Slave_Status | grep "Last_" > $Log_File #Check if slave running $Show_Slave_Status | grep "Slave_IO_Running: No" if [ "$?" -eq "0" ]; then Message_Replication_Error="$Server Replication error please check. The Slave_IO_Running state is No." mailalert exit 1 else $Show_Slave_Status | grep "Slave_IO_Running: Connecting" if [ "$?" -eq "0" ]; then Message_Replication_Error="$Server Replication error please check. The Slave_IO_Running state is Connecting." mailalert exit 1 fi fi #Check if replication delayed Seconds_Behind_Master=$Show_Slave_Status | grep "Seconds_Behind_Master" | awk -F": " {' print $2 '} if [ "$Seconds_Behind_Master" -ge "$Delay" ]; then Message_Replication_Error="Replication Delayed by $Seconds_Behind_Master." mailalert else if [ "$Seconds_Behind_Master" = "NULL" ]; then Message_Replication_Error="$Server Replication error please check. The Seconds_Behind_Master state is NULL." mailalert fi fi

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  • Can't ssh to instance

    - by megas
    I have a linode instance, I was successfully connecting to it via ssh. But I've decided to rebuild my instance and then I can not connect to that instance via ssh. The linode works correctly because I can get access via Lish (lonode ssh) I've tried to clear known_hosts with: ssh-keygen -R 212.71.xxx.xx But I still getting message: ssh [email protected] -v OpenSSH_5.9p1 Debian-5ubuntu1.1, OpenSSL 1.0.1 14 Mar 2012 debug1: Reading configuration data /etc/ssh/ssh_config debug1: /etc/ssh/ssh_config line 19: Applying options for * debug1: Connecting to 212.71.238.74 [212.71.238.74] port 22. debug1: Connection established. debug1: identity file /home/megas/.ssh/id_rsa type 1 debug1: Checking blacklist file /usr/share/ssh/blacklist.RSA-2048 debug1: Checking blacklist file /etc/ssh/blacklist.RSA-2048 debug1: identity file /home/megas/.ssh/id_rsa-cert type -1 debug1: identity file /home/megas/.ssh/id_dsa type -1 debug1: identity file /home/megas/.ssh/id_dsa-cert type -1 debug1: identity file /home/megas/.ssh/id_ecdsa type -1 debug1: identity file /home/megas/.ssh/id_ecdsa-cert type -1 debug1: Remote protocol version 2.0, remote software version OpenSSH_5.9p1 Debian-5ubuntu1.1 debug1: match: OpenSSH_5.9p1 Debian-5ubuntu1.1 pat OpenSSH* debug1: Enabling compatibility mode for protocol 2.0 debug1: Local version string SSH-2.0-OpenSSH_5.9p1 Debian-5ubuntu1.1 debug1: SSH2_MSG_KEXINIT sent debug1: SSH2_MSG_KEXINIT received debug1: kex: server->client aes128-ctr hmac-md5 none debug1: kex: client->server aes128-ctr hmac-md5 none debug1: sending SSH2_MSG_KEX_ECDH_INIT debug1: expecting SSH2_MSG_KEX_ECDH_REPLY debug1: Server host key: ECDSA c5:c3:a7:c0:5a:25:a1:64:c4:04:0c:42:bb:46:f6:96 debug1: Host '212.71.238.74' is known and matches the ECDSA host key. debug1: Found key in /home/megas/.ssh/known_hosts:1 debug1: ssh_ecdsa_verify: signature correct debug1: SSH2_MSG_NEWKEYS sent debug1: expecting SSH2_MSG_NEWKEYS debug1: SSH2_MSG_NEWKEYS received debug1: Roaming not allowed by server debug1: SSH2_MSG_SERVICE_REQUEST sent debug1: SSH2_MSG_SERVICE_ACCEPT received debug1: Authentications that can continue: publickey,password debug1: Next authentication method: publickey debug1: Offering RSA public key: /home/megas/.ssh/id_rsa debug1: Authentications that can continue: publickey,password debug1: Trying private key: /home/megas/.ssh/id_dsa debug1: Trying private key: /home/megas/.ssh/id_ecdsa debug1: No more authentication methods to try. Permission denied (publickey,password). How to resolve this problem? Thanks

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  • reinstalling phpmyadmin

    - by explorex
    EDIT:: installed mysql-server but no phpmyadmin (since phpmyadmin was installed before mysql, that resulted an error). How to reinstall phpmyadmin with database (there is no phpmyadmin datbase)? unstalling it and reinstalling it didn't help. i was trying to install phpmyadmin (and zend framework) through synaptic manager but in the middle i was prompted for password i thought it was phpmyadmin password and i proceeded but i got error and i aborted. and then again i tried to reinstall, it reinstalled but i am not getting phpmyadmin. EDIT::The following is invalid so please don't bother apache is running but mysql is not some of it's characteristics are: santosh@explorer:~$ mysql ERROR 2002 (HY000): Can't connect to local MySQL server through socket '/var/run/mysqld/mysqld.sock' (2) santosh@explorer:~$ sudo apt-get install mysql-server E: Could not get lock /var/lib/dpkg/lock - open (11: Resource temporarily unavailable) E: Unable to lock the administration directory (/var/lib/dpkg/), is another process using it? Should i be asking this question here or stackoverflow? UPDATES:: after restarting my computer santosh@explorer:~$ sudo service mysql start [sudo] password for santosh: mysql: unrecognized service UPDATES:: santosh@explorer:~$ sudo apt-get install mysql Reading package lists... Done Building dependency tree Reading state information... Done E: Unable to locate package mysql

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