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  • Upload image from URL to FTP server using PHP

    - by user1807556
    I want to upload a picture from another site to my FTP server using PHP. Example: File to upload("http://page.mi.fu-berlin.de/krudolph/stuff/stackoverflow.png") FTP-path("pictures/") This is what I've already tried: 1 $image = file_get_contents("http://img.youtube.com/vi/Rz8KW4Tveps/1.jpg"); file_put_contents("imgfolder/imgID.jpg", $image); 2 copy('http://img.youtube.com/vi/Rz8KW4Tveps/1.jpg', 'imgfolder/imgID.jpg'); 3 <?php set_time_limit (24 * 60 * 60); if (!isset($_POST['submit'])) die(); $file = fopen ($url, "rb"); if ($file) { $newf = fopen ($newfname, "wb"); if ($newf) while(!feof($file)) { fwrite($newf, fread($file, 1024 * 2000 ), 1024 * 2000 ); } } if ($file) { fclose($file); } if ($newf) { fclose($newf); } ?> 4 http://www.teckdevil.com/php-server-to-server-transfer-script-to-remotely-transfer-files/ 5 (kinda the same as first linked) Download files directly to my server # I don't get any errors when I'm running the scripts and I have chmod the directory to 777.

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  • Getting document.getElementsByName from another page PHP/javascript

    - by DarkN3ss
    so i have been looking around on how to do this but with no success. Im trying to get the value of the name test from an external website <input type="hidden" name="test" value="ThisIsAValue" /> But so far i have only found how to get the value of that with an ID <input type="hidden" id="test" name="test" value="ThisIsAValue" autocomplete="off" /> but I need to try find it without a ID is my problem. And this is an example on how to get it from the ID <?php $doc = new DomDocument; $doc->validateOnParse = true; $doc->loadHtml(file_get_contents('http://example.com/bla.php')); var_dump($doc->getElementById('test')); ?> And i have found how to get it from name and NOT ID on the same page <script> function getElements() { var test = document.getElementsByName("test")[0].value; alert(test); } </script> But again I dont know how to get the value of it by name from an external page eg "http://example.com/bla.php", any help? Thanks

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  • PHP cookies in a session handler

    - by steve
    I have run into a very interesting problem trying to debug my custom php session handler. For some reason unknown to me I can set cookies all the way through the session handler right up until the very start of the write function. As far as I know session handler calls go in this order. open - read - write - close The open function sets a cookie just fine. function open($save_path,$session_name) { require_once('database.php'); require_once('websiteinfo.php'); mysql_connect($sqllocation,$sql_session_user,$sql_session_pass); @mysql_select_db($sql_default_db); date_default_timezone_set('America/Los_Angeles'); setcookie("test","test"); return TRUE; } The read function can set a cookie right up until the very moment it returns a value. function read($session_id) { $time = time(); $query = "SELECT * FROM 'sessions' WHERE 'expires' > '$time'"; $query_result = mysql_query($query); $data = ''; /* fetch the array and start sifting through it */ while($session_array = mysql_fetch_array($query_result)) { /* strip the slashes from the session array */ $session_array = $this->strip($session_array); /* authenticate the user and if so return the session data */ if($this->auth_check($session_array,$session_id)) { $data = $session_array['data']; } } setcookie("testcookie1","value1",time()+1000,'/'); return $data; } The very first line of the write function is setting another cookie and it cannot because the headers are already sent. Any ideas anyone? Thanks in advance

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  • PHP header() redirect not working after shortening URL using bit.ly

    - by Fabian Kreiser
    Hi, I have a problem with php header redirect. I already spent hours trying to fix it. The problem doesn't occur when the bit.ly api is not used in the script, I have no clue why. <?php if (strlen($_GET['url']) > 26) { $shortenedURL = $_GET['url']; if (isset($_GET['login']) && isset($_GET['apikey'])) { $shortenedURL = file_get_contents('http://api.bit.ly/v3/shorten?format=txt&login='.urlencode($_GET['login']).'&apiKey='.$_GET['apikey'].'&uri='.urlencode($_GET['url'])); } else { $shortenedURL = file_get_contents('http://icbrd.net/shorten.php?longurl='.$_GET['url']); } if (strlen($shortenedURL) > 0) { header( 'Location: icebird://compose?status='.$shortenedURL.'%20' ); exit(); } else { header( 'Location: icebird://compose?status='.$_GET['url'].'%20' ); exit(); } } else { header( 'Location: icebird://compose?status='.$_GET['url'].'%20' ); exit(); } ?> I hope you can help me, as this is driving me crazy. Regards

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  • in_array() - help on what specifically would return true

    - by Kerri
    I am using in_array, and I'm trying to use it in a way where it will only return true if it's an exact match of one of the objects in the array, not just if it's "in" the array. e.g. 1. $sample_array = array('123', '234', '345'); 2. $sample_array = array('23', '34', '45'); in_array('23', $sample_array); In the above example, I would only want version 2 to return true, because it has the exact string, '23'. Version 1 returns true as well though, because the array contains instances of the string '23'. How would I get this to work so that only version 2 returns true? Am I even using the right function?

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  • designing solution to dynamically load class

    - by dot
    Background Information I have a web app that allows end users to connect to ssh-enabled devices and manipulate them. Right now, i only support one version of firmware. The logic is something like this: user clicks on a button to run some command on device. web application looks up the class name containing the correct ssh interface for the device, using the device's model name. (because the number of hardware models is so small, i have a list that's hardcoded in my web app) web app creates a new ssh object using the class loaded in step 2. ssh command is run and session closed. command results displayed on web page. This all works fine. Now the end user wants me to be able to support multiple versions of firmware. But the catch is, they don't want to have to document the firmware version anywhere becuase the amount of overhead this will create in maintaining the system database. In other words, I can't look up the firmware version based on the device. The good news is that it sounds like at most, I'll have to support two different versions of firmware per device. One option is to name the the classes like this: deviceX.1.php deviceX.2.php deviceY.1.php deviceY.2.php where "X" and "Y" represent the model names, and 1 and 2 represent the firmware versions. When a user runs a command, I will first try it with one of the class files, if it fails, i can try with the second. I think always try the newer version of firmware first... so let's say in the above example, I would load deviceX.2.php before deviceX.1.php. This will work, but it's not very efficient. But I can't think of another way around this. Any suggestions?

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  • Warning ,i can not solving in PHP code

    - by user318068
    hi , in code there Warning Warning: mysql_fetch_array() expects parameter 1 to be resource, string given in C:\xampp\htdocs\Join.php on line 69 but i can not solving where exactly can you help me where the error in this code . <?php 51. include("connect.php"); 53. $email = mysql_query("select MemberEmail from members where MemberID= '$id' "); 54. while ($row = mysql_fetch_array($email)) 55. { 57. $memEmail=$row['MemberEmail']; } 62. $sql = mysql_query("select * from ninvite where recieverMemberEmail ='$memEmail' and viwed= '0' order by RoomID desc"); 64. $num =mysql_num_rows($sql); 67. if ($sql and $num >0 ) { 69. while($row=mysql_fetch_array($sql)) { 71. $sender=$row['SenderMemberID']; 73. $room=$row['RoomID']; 77. $sql2 =mysql_query("select MemberName from members where MemberID ='$sender' "); 78. $sql1 =mysql_query("select RoomName,RoomLogo from rooms where RoomID ='$room' "); 79. while($row=mysql_fetch_array($sql2)) { $mem =$row['MemberName']; } 84. while($rows=mysql_fetch_array($sql1)) { $Ro =$rows['RoomName']; $logo = $rows['RoomLogo']; } 89. ?> Thanks alot

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  • PHP include taking too long

    - by wxiiir
    I have a php file with around 100mb which is full of arrays (only arrays). I've made a script that includes this file (for processing), first it exhausted the default Xampp 128mb memory limit, i've raised it to 1024mb but it just takes forever and doesn't do anything. I'm sure the problem is being created by the sheer size of the file because i've tried removing all lines of code and just leaving the include and an echo for me to know when it finishes executing, and it does the same thing (which is taking forever), i've also tried to run the 100mb file in separate and same thing again. A 10mb file is taking forever as well but a similar 1mb file is almost instantly read and executed so the problem must be more than just the file size. I was avoiding using c++ for a simple project as this and would rather not to as php is easier for me and the task that will be executed doesn't need to benefit from the added speed that it would have if it had been done in c++ but if i have no luck in solving this problem i guess i'll have to. EDIT Reasons for not using a database: 1-Whoever made it didn't used a database and it will be pretty hard to store this in an organized database if i'm not able to do something with it first, like just reading it, copying parts from it or putting in memory or something. 2-I don't have experience working with databases as pretty much all stuff i've ever done in php didn't needed large amounts of stored data, 50kb at best, if i was thinking about a big project or huge chunks of data as this one, i definitely would, but i didn't made this mess to start with and now i have to undo it. 3-The logic for having to store a small portion of data like 10mb in hard drive when now every computer has pretty much enough ram to fit the whole OS in it is pretty much incomprehensible unless someone gives a good explanation about it, if i had to access a lot of said files simultaneously i would understand but like i said, this is a simple project, this is the only file that will be accessed at a given time this isn't even to make some kind of website, it's to run a few times and be done with it.

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  • php facebook delete feeds

    - by meAtStackOverflow
    Hi there, I have manage to grab all the photos posted to my app wall. Now I am trying to add a function to my facebook app where it will delete all the feeds posted on the wall. <?php include_once 'facebook.php'; include_once 'config.php'; $feed = $facebook->api('/me/feed'); foreach($feed['data'] as $feeds) { echo "Feeds secion", "<br />"; echo $feeds["picture"], "<br />"; echo "<img src='{$feeds['picture']}' />", "<br />"; $target_path = "uploads/"; $target_path = $target_path . basename($feeds["picture"]); $content = file_get_contents($feeds["picture"]); file_put_contents($target_path, $content); } ? This is how i grab the photos and push them into my server. Please guide me on how i could delete all the feeds. I have went through some online examples but i could not figure out how to go about doing it. I kept receving errors. Thanks!

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  • PHP transfer files from server to server in LAN

    - by cheapez
    So, I have 5-6 pages of requirements. I'm trying to build this application in PHP based on the requirements. I want to transfer files from one server to the other server in LAN, and then send a shell command to the other server to find out if the file has been transferred successfully. In php, I can transfer files using FTP, and send shell commands using SSH. Using the methods above, I will need to open connection to the server first, but I don't know the ftp server name, domain name, ip address, or anything like that. I only know the the server ID (I'm not sure what this ID is, but I guess it is like the computer's name). An example of the server ID is: "c23bap234" How do I open a connection with just that server ID? These servers are in the same building, have LAN connection, don't have connection to the outside world. These machines have PHP, Apache, ... installed. If my post doesn't make sense to you, it's because I'm a learner. I hope someone can help me on this. Thanks in advance.

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  • Assign a static function to a variable in PHP

    - by Felipe Almeida
    I would like to assign a static function to a variable so that I can send it around as a parameter. For example: class Foo{ private static function privateStaticFunction($arg1,$arg2){ //compute stuff on the args } public static function publicStaticFunction($foo,$bar){ //works $var = function(){ //do stuff }; //also works $var = function($someArg,$someArg2){ //do stuff }; //Fatal error: Undefined class constant 'privateStaticFunction' $var = self::privateStaticMethod; //same error $var = Foo::privateStaticFunction; //compiles, but errors when I try to run $var() somewhere else, as expected //Fatal error: Call to private method Foo::privateStaticMethod() from context '' $var = function(){ return Foo::privateStaticMethod(); }; } } I've tried a few more variations but none of them worked. I don't even expect this sort of functional hacking to work with PHP but hey, who knows? Is it possible to do that in PHP or will I need to come up with some hack using eval? P.S.: LawnGnome on ##php mentioned something about it being possible to do what I want using array('Foo','privateStaticMethod') but I didn't understand what he meant and I didn't press him further as he looked busy.

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  • PHP: Need a double check on an error in this small code

    - by Josh K
    I have this simple Select box that is suppose to store the selected value in a hidden input, which can then be used for POST (I am doing it this way to use data from disabled drop down menus) <body> <?php $Z = $_POST[hdn]; ?> <form id="form1" name="form1" method="post" action="test.php"> <select name="whatever" id="whatever" onchange="document.getElementById('hdn').value = this.value"> <option value="1">1Value</option> <option value="2">2Value</option> <option value="3">3Value</option> <option value="4">4Value</option> </select> <input type="hidden" name ='hdn' id="hdn" /> <input type="submit" id='submit' /> <?php echo "<p>".$Z."</p>"; ?> </form> </body> The echo call works for the last 3 options (2,3,4) but if I select the first one it doesnt output anything, and even if i change first one it still doesnt output anything. Can someone explain to me whats going on, I think it might be a syntax issue.

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  • pascal triangle in php (anything wrong with this solution?) [migrated]

    - by zhenka
    I saw that one of the interview questions could be building a pascal triangle. Is there anything wrong with this particular solution I came up with? function pascal_r($r){ $local = array(); if($r == 1){ return array(array(1)); } else { $previous = pascal_r($r - 1); array_push($local, 1); for($i = 0; $i < $r - 2 && $r > 2; $i++){ array_push($local, $previous[$r-2][$i] + $previous[$r-2][$i + 1]); } array_push($local, 1); } array_push($previous, $local); return $previous; } print_r(pascal_r(100));

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  • PHP download page: file_exists() returns true, but browser returns 'page not found'

    - by Chris
    I'm using PHP for a file download page. Here's a snippet of the problem code: if (file_exists($attachment_location)) { header($_SERVER["SERVER_PROTOCOL"] . " 200 OK"); header("Cache-Control: public"); // needed for i.e. header("Content-Type: application/zip"); header("Content-Transfer-Encoding: Binary"); header("Content-Length:".filesize($attachment_location)); header("Content-Disposition: attachment; filename=file.zip"); readfile($attachment_location); die("Hooray"); } else { die("Error: File not found."); } This code works absolutely fine when testing locally, but after deploying to the live server the browser returns a 'Page not found' error. I thought it might be an .htaccess issue, but all .htaccess files on the live server are identical to their local counterparts. My next guess would be the live server's PHP configuration, but I have no idea what PHP setting might cause this behaviour. The file_exists() function always returns true - I've checked this on the live server and it's always correctly picking up the file, its size etc., so it does have a handle on the file. It just won't perform the download! The main site is a Wordpress site, but this code isn't part of a Wordpress page - it's in a standalone directory within the site root. UPDATE: is_file() and is_readable() are both returning true for the file, so that's not the problem. The specific line that is causing the problem is: readfile($attachment_location) Everything up until that point is super happy.

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  • Changing PHP variable from an <a href=""> link

    - by aener
    I'm making a site using divs. I have one across the top with a row of links which I want to change what's in the main window. I would prefer to keep strictly to PHP and HTML and use a full page refresh as I am comfortable with them at current, rather than using an Ajax refresh as I don't have any knowledge of Ajax. I don't want to use iframes. I thought the best way to do this would be as follows: <div id="top"> <a href="news.html">News</a> </div> <div id="main"> <?php include($page); ?> </div> What I need is a way of changing the $page variable upon clicking the link. If this means changing the variable and then reloading the page then so be it. A command following the logic of: <a href="news.html" action="<?php $page="news.html"; ?>">News</a> would be ideal! I thought about using a form, but it seems there should be an easier way.

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  • Using AJAX to POST data to PHP database, then refresh

    - by cb74656
    Currently I have a button: <ul> <li><button onclick="display('1')">1</button></li> <li><button onclick="display('2')">2</button></li> <li><button onclick="display('3')">3</button></li> </ul> That when pressed, calls a javascript function, and displays PHP based on which button is pressed using AJAX. I figured this out all on my own. The AJAX gets a PHP file with a postgres query that outputs a table of data to a div. Now I want to be able to add, via form, new data and have it refresh (without reloading the page, yannknow?). I've tried a couple of things, and have hit roadblocks every time. My initial idea was to have the form submit the data using a javascript function and AJAX, then call my "display()" function after the query to reload the content. I just can't figure it out using GoogleFu. Based on my current idea, I'd like help with the following: How do I pass the form data to a javascript function. How do I use POST to pass that data to PHP using AJAX? I'm super new to javascript and AJAX. I've looked into jquery as it seems like that's the way to go, but I can't figure it out. If there's a better way to do this, I'm open to suggestions. Please forgive any misuse of nomenclature. EDIT: Once I solve this problem..., I'll have all the tools needed to finish the project preliminarily.

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  • Notification 7 Days Before Payment PHP No Error Message

    - by user1858672
    So I have PHP script running on cron daily. It is suppose to check the date and send an email if it is 7 days before any payments as a reminder. I haven't used PHP in a long time so sorry if the way I did it was ridiculous or something. Thanks a lot. I would say what the problem is but I don't get any error message or anything.. <?php mysqli_connect("xxxxxx", "xxxxxxx", "xxxxxxxxx") or die(mysqli_error()); mysqli_select_db("xxxxxxxxx") or die(mysqli_error()); //Retrieve original payment dates and enter them into an array $result = mysqli_query("SELECT DateCreated FROM UserTable"); $payment_dates = mysqli_fetch_array($result); //Puts original payment date into month-day format $md_payment_dates = substr($payment_dates, 5); //Gets todays date in m-d format and adds 7 days to it $due_date = mktime(0, 0, 0, date("m"), date("d")+7); //Checks if any payment days match today's date. If there are none it script will stop. if (count(preg_grep($due_date, $md_payment_dates)) > 0) { //Retrieves usernames of users that have an invoice due. $users_to_pay = mysqli_fetch_array("SELECT Username IN UserTable WHERE DateCreated = $date"); //Notifies you via email $to = "[email protected]"; $subject = "7 Day Payment Reminder"; $message = "Hi, <br /> The following owe a payment in 7 days : " + $users_to_pay ".<br/> Their payments are due on " + $md_payment_dates " of this year."; mail($to, $subject, $message); exit(); }else{ exit(); } ?>

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  • How can I add one line into all php files' beginning?

    - by Tom
    So, ok. I have many php files and one index.php file. All files can't work without index.php file, because I include them in index.php. For example. if somebody click Contact us the URL will become smth like index.php?id=contact and I use $_GET['id'] to include contacts.php file. But, if somebody find the file's path, for example /system/files/contacts.php I don't want that that file would be executed. So, I figured out that I can add before including any files in index.php line like this $check_hacker = 1 and use if in every files beginning like this if($check_hacker <> 1) die();. So, how can I do it without opening all files and adding this line to each of them? Is it possible? Because I actually have many .php files. And maybe there is other way to do disable watching separate file? Any ideas? Thank you.

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  • Building html structure in php or javascript?

    - by Adam
    I've been doing a lot of ajax calls and using the returned data to build html with javascript. However, I've noticed some people are returning the constructed html in the ajax calls since they're doing it all in php. What is the preferred method? I have a bunch of stuff already using javascript, so I guess I would prefer not changing everything to use just php. But, I'm assuming php would be more "secure."? The following is what I've been doing: $main_frag = $("<div class='order-container'/>"); $contact_frag = $("<div class='group'><div class='line-data'>Name: "+data.name+"</div><div class='line-data'>Email: "+data.email+"</div><div class='line-data'>Phone: "+data.phone+"</div></div>"); $address_frag = $("<div class='group'><div class='line-data'>Address 1: "+data.address_one+"</div><div class='line-data'>Address 2: "+address2+"</div><div class='line-data'>City: "+data.city+"</div><div class='line-data'>Province: "+data.province+"</div><div class='line-data'>Postal Code: "+data.postal+"</div></div>"); etc.. I just want to hear the opinions of the community.

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  • detect click on submit button in PHP

    - by Remus Rigo
    hi all I have a php file that contains a form (witch contains 2 input boxes and a submit button) for updating a contact. I managed to fill the fields with the contact's data, but I can't detect if the submit button is clicked form looks like this echo "<form action=Contact.php><table>". "<tr><td>First Name</td><td><input type=text size=75% name=FirstName value='".$row['FirstName']."'></td></tr>". "<tr><td>Last Name</td><td><input type=text size=75% name=LastName value='".$row['LastName']."'></td></tr>". "<tr><td colspan=2><input type=submit name=UpdateContact value=Update></td></tr>". "</table></form>"; this code should output a "clicked" message if the button is clicked if (isset($_POST['UpdateContact'])) { echo "<p>clicked"; } else { echo "<p>not clicked"; } can anyone help me out or tell me what i've done wrong (I want from the same php file to fill the contact's data in a from and to update the database)

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  • PHP session token can be used multipletimes?

    - by kornesh
    I got page A which is a normal HTML page and page which is an AJAX response page. And I want to prevent CSRF attacks by tokens. Lets say I use this method for an autocomplete form, is it possible to use same token multiple times (of course the session is only set one time) because i tired this method but the validation keep failing after the first suggestion (obviously the token has changed, somehow) page A <?php session_start(); $token = md5(uniqid(rand(), TRUE)); $_SESSION['token'] = $token; ?> <input id="token" value="<?php echo $token; ?>" type="hidden"></input> <input id="autocomplete" placeholder="Type something"></input> .... The form is autosubmitted every time theres a change using Jquery. page B <?php session_start(); if($_REQUEST['token'] == $_SESSION['token']){ echo 'Im working fine'; } ?>

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  • Load the <?php the_permalink(); ?> with an ajax loader

    - by fxg
    I´m working on a wordpress template. I´m trying to load the single.php of a post using ajax. I´m doing all the load thru a loader.js file that has this: // load single project page $("#project_slider").live("click", function(){ $("#content").hide(); $("#content").load("<?php the_permalink(); ?>", function(){ $(this).fadeIn("slow"); }); }); The problem is that I can´t just put on the .load because it doesn´t works. this is the markup: <div id="project_page" class="item"> <a href="#"> <img src="<?php the_field('artworks_thumbnail'); ?>" alt="" width="240" height="173"> </a> <div class="art_title"> <p>SWEET LIFE</p> </div> <div class="mask"></div> </div> How can I add the permalink via the loader.js?

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  • How to separate date in php

    - by user225269
    I want to be able to separate the birthday from the mysql data into day, year and month. Using the 3 textbox in html. How do I separate it? I'm trying to think of what can I do with the code below to show the result that I want: Here's the html form with the php code: $idnum = mysql_real_escape_string($_POST['idnum']); mysql_select_db("school", $con); $result = mysql_query("SELECT * FROM student WHERE IDNO='$idnum'"); $month = mysql_real_escape_string($_POST['mm']); ?> <?php while ( $row = mysql_fetch_array($result) ) { ?> <tr> <td width="30" height="35"><font size="2">Month:</td> <td width="30"><input name="mo" type="text" id="mo" onkeypress="return handleEnter(this, event)" value="<?php echo $month = explode("-",$row['BIRTHDAY']);?>"> As you can see the column is the mysql database is called BIRTHDAY. With this format: YYYY-MM-DD How do I do it. So that the data from the single column will be divided into three parts? Please help thanks,

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  • Jquery - $.(post) data response not consistent with PHP

    - by Sasha
    Jquery code: var code = $('#code'), id = $('input[name=id]').val(), url = '<?php echo base_url() ?>mali_oglasi/mgl_check_paid'; code.on('focusout', function(){ var code_value = $(this).val(); if(code_value.length != 16 ) { if ($('p[role=code_msg]').length != 0 ) $('p[role=code_msg]').remove() ; code.after('<p role=code_msg>Pogrešan kod je unešen.</p>'); } else { if ($('p[role=code_msg]').length != 0 ) $('p[role=code_msg]').remove() ; $.post(url, {id : id, code : code_value}, function(data){ if(data != 'TRUE'){ code.after('<p role=code_msg>Uneti kod je neispravan.</p>'); } else { code.after('<p role=code_msg>Status malog oglasa je promenjen.</p>'); code.after(create_image()); code.remove(); } }); } }); PHP (Codeigniter) code: function mgl_check_paid() { $code = $this->input->post('code'); $id = $this->input->post('id'); echo ($this->mgl->mgl_check_paid($code, $id)) ? 'TRUE' : 'FALSE'; } Problem is following: When code is sent and if it is correct, PHP part will echo TRUE, and JS will execute ELSE part (after post), but for some reason it is not doing that (it is executing the first part of the statment)? What is wrong with this code?

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  • PHP - Undefined index error

    - by user1815290
    This is my form with a file input field named "photo": <form action = "spremi-film.php" method = "POST" enctype = "multipart/form-data"> <div class="grid_2">Naslov:</div> <div class="grid_10"><input type="text" name="naslov" value="" /></div> <div class="grid_2">Žanr: </div> <div class="grid_10"><?php izborZanra(); ?></div> <div class="grid_2">Godina: </div> <div class="grid_10"><?php izborGodine(); ?></div> <div class="grid_2">Trajanje:</div> <div class="grid_10"><input type="text" name="trajanje" value="" /></div> <div class="grid_2">Izbor slike:</div> <!--<input type="hidden" name="MAX_FILE_SIZE" value="30000" />--> <div class="grid_10"><input type="file" name="photo" /></div> <div class="grid_12"><input type="submit" value="SPREMI" /></div> </form> After that i put this code: $uploaddir = '/slike'; $uploadfile = $uploaddir . basename($_FILES['photo']['name']); //echo '<pre>'; if(move_uploaded_file($_FILES['photo']['tmp_name'], $uploadfile)) { echo 'Slika je uspješno spremljena!'; } else { echo 'Slika nije spremljena!'; } //print_r($_FILES); //echo '</pre>'; When i run this i have an undefined index: photo notice in my browser. Help, please.

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