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  • Template function overloading with identical signatures, why does this work?

    - by user1843978
    Minimal program: #include <stdio.h> #include <type_traits> template<typename S, typename T> int foo(typename T::type s) { return 1; } template<typename S, typename T> int foo(S s) { return 2; } int main(int argc, char* argv[]) { int x = 3; printf("%d\n", foo<int, std::enable_if<true, int>>(x)); return 0; } output: 1 Why doesn't this give a compile error? When the template code is generated, wouldn't the functions int foo(typename T::type search) and int foo(S& search) have the same signature? If you change the template function signatures a little bit, it still works (as I would expect given the example above): template<typename S, typename T> void foo(typename T::type s) { printf("a\n"); } template<typename S, typename T> void foo(S s) { printf("b\n"); } Yet this doesn't and yet the only difference is that one has an int signature and the other is defined by the first template parameter. template<typename T> void foo(typename T::type s) { printf("a\n"); } template<typename T> void foo(int s) { printf("b\n"); } I'm using code similar to this for a project I'm working on and I'm afraid that there's a subtly to the language that I'm not understanding that will cause some undefined behavior in certain cases. I should also mention that it does compile on both Clang and in VS11 so I don't think it's just a compiler bug.

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  • Will the template argument's destructor to a templated class be called on deletion?

    - by Mutmansky
    If you have a templated base class as in the following example: class A{ A(); virtual ~A(); }; template <class T> class B : public T { B(); virtual ~B(); }; typedef B<A> C; class D : public C { D(); virtual ~D(); }; When you delete an instance of D, will the destructor of A be called? I'll probably create a test program to find out what happens, but just thinking about it, I wasn't sure what should happen.

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  • C++ require that one template type is derived from the other

    - by Will
    In a comparison operator: template<class R1, class R2> bool operator==(Manager<R1> m1, Manager<R2> m2) { return p1.internal_field == p2.internal_field; } Is there any way I could enforce that R1 and R2 must have a supertype or subtype relation? That is, I'd like to allow either R1 to be derived from R2, or R2 to be derived from R1, but disallow the comparison if R1 and R2 are unrelated types.

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  • error - inherited class field undeclared according to g++

    - by infoholic_anonymous
    I have a code that has the following logic. g++ gives me the error that I have not declared n in my iterator2. What could be wrong? template <typename T> class List{ template <typename TT> class Node; Node<T> *head; /* (...) */ template <bool D> class iterator1{ protected: Node<T> n; public: iterator1( Node<T> *nn ) { n = nn } /* (...) */ }; template <bool D> class iterator2 : public iterator1<D>{ public: iterator2( Node<T> *nn ) : iterator1<D>( nn ) {} void fun( Node<T> *nn ) { n = nn; } /* (...) */ }; }; EDIT : I attach the actual header file. iterator1 would be iterable_frame and iterator2 - switchable_frame. #ifndef LST_H #define LST_H template <typename T> class List { public: template <typename TT> class Node; private: Node<T> *head; public: List() { head = new Node<T>; } ~List() { empty_list(); delete head; } List( const List &l ); inline bool is_empty() const { return head->next[0] == head; } void empty_list(); template <bool DIM> class iterable_frame { protected: Node<T> *head; Node<T> **caret; public: iterable_frame( const List &l ) { head = *(caret = &l.head); } iterable_frame( const iterable_frame &i ) { head = *(caret = i.caret); } ~iterable_frame() {} /* (...) - a few methods follow */ template <bool _DIM> friend class supervised_frame; }; template <bool DIM> class switchable_frame : public iterable_frame<DIM> { Node<T> *main_head; public: switchable_frame( const List& l ) : iterable_frame<DIM>(l) { main_head = head; } inline bool next_frame() { caret = &head->next[!DIM]; head = *caret; return head != main_head; } }; template <bool DIM> class supervised_frame { iterable_frame<DIM> sentinels; iterable_frame<DIM> cells; public: supervised_frame( const List &l ) : sentinels(l), cells(l) {} ~supervised_frame() {} /* (...) - a few methods follow */ }; template <typename TT> class Node { unsigned index[2]; TT num; Node<TT> *next[2]; public: Node( unsigned x = 0, unsigned y = 0 ) { index[0]=x; index[1]=y; next[0] = this; next[1] = this; } Node( unsigned x, unsigned y, TT d ) { index[0]=x; index[1]=y; num=d; next[0] = this; next[1] = this; } Node( const Node &n ) { index[0] = n.index[0]; index[1] = n.index[1]; num = n.num; next[0] = next[1] = this; } ~Node() {} friend class List; }; }; #include "List.cpp" #endif the exact error log is the following: In file included from main.cpp:1: List.h: In member function ‘bool List<T>::switchable_frame<DIM>::next_frame()’: List.h:77: error: ‘caret’ was not declared in this scope

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  • C++ "delayed" template argument

    - by aaa
    hello. Is there direct way to do the following: template < class > struct f {}; template < class F > void function() { F<int>(); //for example // ? F template <int>(); } function < f >(); I have workaround by using extra class around template struct. I am wondering if it's possible to do so directly. Thanks

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  • How can data templates in generic.xaml get applied automatically?

    - by Thiado de Arruda
    I have a custom control that has a ContentPresenter that will have an arbitrary object set as it content. This object does not have any constraint on its type, so I want this control to display its content based on any data templates defined by application or by data templates defined in Generic.xaml. If in a application I define some data template(without a key because I want it to be applied automatically to objects of that type) and I use the custom control bound to an object of that type, the data template gets applied automatically. But I have some data templates defined for some types in the generic.xaml where I define the custom control style, and these templates are not getting applied automatically. Here is the generic.xaml : If I set an object of type 'PredefinedType' as the content in the contentpresenter, the data template does not get applied. However, If it works if I define the data template in the app.xaml for the application thats using the custom control. Does someone got a clue? I really cant assume that the user of the control will define this data template, so I need some way to tie it up with the custom control.

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  • Unresolved import: models

    - by Timmy O' Tool
    Hi! I'm doing my VERY first project using python/django/eclipse/pydev following this guide http://docs.djangoproject.com/en/dev/intro/tutorial01/ My only addition is the use of Eclipse/pydev. I'm getting many errors related to "Unresolved imports". I can remove the errors using "remove error markers" and my site runs perfect (I can browse it) but I want to get rid definitively of this problem since errors appear again after I removed them. Any ideas?

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  • How to browse .rst files ?

    - by Eric
    In many django projects, in the docs directory I can see *.rst files : What is the best way to browse them (without using a text editor of course) ? Is that possible to generate HTML ?

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  • Why can't my Apache see my media folder?

    - by alex
    Alias /media/ /home/matt/repos/hello/media <Directory /home/matt/repos/hello/media> Options -Indexes Order deny,allow Allow from all </Directory> WSGIScriptAlias / /home/matt/repos/hello/wsgi/django.wsgi /media is my directory. When I go to mydomain.com/media/, it says 403 Forbidden. And, the rest of my site doesn't work because all static files are 404s. Why? Edit: hello is my project folder

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  • Is there a wysiwyg editor for restructured text?

    - by dar
    Is there a wysiwyg editor for the web, like tinymce or wmd, which can produce restructured text? I'm looking for something which can be integrated with django. I would like to use rst instead of markdown because I need to convert the content entered to pdf and do some layout specific things which make rst look like a better choice.

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  • Getting a Jabber status via Python

    - by Teegijee
    I'm developing a website using the Django framework, and I need to retrieve Jabber (okay, Google Talk) statuses for a user. Most of the Jabber python libraries seem like an incredible amount of overkill (and overhead) for a simple task. Is there any simple way to do this? I know very little about XMPP/Jabber, though of course I'm willing to learn. Do you need to be an authenticated and "friended" user to retrieve another user's status?

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  • Testing Python Decorators?

    - by Jama22
    I'm writing some unit tests for a Django project, and I was wondering if its possible (or necessary?) to test some of the decorators that I wrote for it. Here is an example of a decorator that I wrote: class login_required(object): def __init__(self, f): self.f = f def __call__(self, *args): request = args[0] if request.user and request.user.is_authenticated(): return self.f(*args) return redirect('/login')

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  • (O)Auth with ExtJS

    - by TheShow
    Hi, today i tried to get django-piston and ExtJS working. I used the ExtJS restful example and the piston example to create a little restful webapp. Everything works fine except the authentication. Whats the best way to get Basic/Digest/OAuth authentication working with ExtJS? Atm I'm not sure where to set the Username/Password. Thanks

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  • bundles in java?

    - by fayer
    in symfony 2.0 and django there are bundles that contain everything for a feature (html, css, js, img, php/python). so if you want to delete one feature, you basically just delete that bundle and unregister it from "main". are there java frameworks for this too? or is it different in java cause java is a compiling language. thanks

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  • psycopg2 on cygwin: no such process

    - by Jerry
    I am trying to install postgrepsql to cygwin on a windows 7 machine and want it to work with django. After built and installed postgrepsql in cygwin, I built and installed psycopg2 in cygwin as well and got no error, but when use it in python with cygwin, I got the "no such process" error: import psycopg2 Traceback (most recent call last): File "", line 1, in File "/usr/lib/python2.5/site-packages/psycopg2/init.py", line 60, in from _psycopg import BINARY, NUMBER, STRING, DATETIME, ROWID ImportError: No such process any clues? Thanks! Jerry

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  • python Socket.IO client for sending broadcast messages to TornadIO2 server

    - by Alp
    I am building a realtime web application. I want to be able to send broadcast messages from the server-side implementation of my python application. Here is the setup: socketio.js on the client-side TornadIO2 server as Socket.IO server python on the server-side (Django framework) I can succesfully send socket.io messages from the client to the server. The server handles these and can send a response. In the following i will describe how i did that. Current Setup and Code First, we need to define a Connection which handles socket.io events: class BaseConnection(tornadio2.SocketConnection): def on_message(self, message): pass # will be run if client uses socket.emit('connect', username) @event def connect(self, username): # send answer to client which will be handled by socket.on('log', function) self.emit('log', 'hello ' + username) Starting the server is done by a Django management custom method: class Command(BaseCommand): args = '' help = 'Starts the TornadIO2 server for handling socket.io connections' def handle(self, *args, **kwargs): autoreload.main(self.run, args, kwargs) def run(self, *args, **kwargs): port = settings.SOCKETIO_PORT router = tornadio2.TornadioRouter(BaseConnection) application = tornado.web.Application( router.urls, socket_io_port = port ) print 'Starting socket.io server on port %s' % port server = SocketServer(application) Very well, the server runs now. Let's add the client code: <script type="text/javascript"> var sio = io.connect('localhost:9000'); sio.on('connect', function(data) { console.log('connected'); sio.emit('connect', '{{ user.username }}'); }); sio.on('log', function(data) { console.log("log: " + data); }); </script> Obviously, {{ user.username }} will be replaced by the username of the currently logged in user, in this example the username is "alp". Now, every time the page gets refreshed, the console output is: connected log: hello alp Therefore, invoking messages and sending responses works. But now comes the tricky part. Problems The response "hello alp" is sent only to the invoker of the socket.io message. I want to broadcast a message to all connected clients, so that they can be informed in realtime if a new user joins the party (for example in a chat application). So, here are my questions: How can i send a broadcast message to all connected clients? How can i send a broadcast message to multiple connected clients that are subscribed on a specific channel? How can i send a broadcast message anywhere in my python code (outside of the BaseConnection class)? Would this require some sort of Socket.IO client for python or is this builtin with TornadIO2? All these broadcasts should be done in a reliable way, so i guess websockets are the best choice. But i am open to all good solutions.

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  • Comparing two large sets of attributes

    - by andyashton
    Suppose you have a Django view that has two functions: The first function renders some XML using a XSLT stylesheet and produces a div with 1000 subelements like this: <div id="myText"> <p id="p1"><a class="note-p1" href="#" style="display:none" target="bot">?</a></strong>Lorem ipsum</p> <p id="p2"><a class="note-p2" href="#" style="display:none" target="bot">?</a></strong>Foo bar</p> <p id="p3"><a class="note-p3" href="#" style="display:none" target="bot">?</a></strong>Chocolate peanut butter</p> (etc for 1000 lines) <p id="p1000"><a class="note-p1000" href="#" style="display:none" target="bot">?</a></strong>Go Yankees!</p> </div> The second function renders another XML document using another stylesheet to produce a div like this: <div id="myNotes"> <p id="n1"><cite class="note-p1"><sup>1</sup><span>Trololo</span></cite></p> <p id="n2"><cite class="note-p1"><sup>2</sup><span>Trololo</span></cite></p> <p id="n3"><cite class="note-p2"><sup>3</sup><span>lololo</span></cite></p> (etc for n lines) <p id="n"><cite class="note-p885"><sup>n</sup><span>lololo</span></cite></p> </div> I need to see which elements in #myText have classes that match elements in #myNotes, and display them. I can do this using the following jQuery: $('#myText').find('a').each(function() { var $anchor = $(this); $('#myNotes').find('cite').each(function() { if($(this).attr('class') == $anchor.attr('class')) { $anchor.show(); }); }); However this is incredibly slow and inefficient for a large number of comparisons. What is the fastest/most efficient way to do this - is there a jQuery/js method that is reasonable for a large number of items? Or do I need to reengineer the Django code to do the work before passing it to the template?

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  • Simplejson dumps char \

    - by Monty
    Hi! Im programming with django and i need to serialize an object to a string, but i need to get the string \/ serialized. An example: simplejson.dumps({'id' : 'root\/leaf'}) I need an output like this: '{"id": "root\/leaf"}' but i get this: '{"id": "root\\\\leaf"}' Thank you!! PD: Sorry for my english :-P

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