Search Results

Search found 9318 results on 373 pages for 'django authentication'.

Page 15/373 | < Previous Page | 11 12 13 14 15 16 17 18 19 20 21 22  | Next Page >

  • Does this syntax for specifying Django conditional form display align with python/django convention?

    - by andy
    I asked a similar question on Stackoverflow and was told it was better asked here. So I'll ask it slightly rephrased. I am working on a Django project, part of which will become a distributable plugin that allows the python/django developer to specify conditional form field display logic in the form class or model class. I am trying to decide how the developer must specify that logic. Here's an example: class MyModel(models.Model): #these are some django model fields which will be used in a form yes_or_no = models.SomeField...choices are yes or no... why = models.SomeField...text, but only relevant if yes_or_no == yes... elaborate_even_more = models.SomeField...more text, just here so we can have multiple conditions #here i am inventing some syntax...i am looking for suggestions!! #this is one possibility why.show_if = ('yes_or_no','==','yes') elaborate_even_more.show_if = (('yes_or_no','==','yes'),('why','is not','None')) #help me choose a syntax that is *easy*...and Pythonic and...Djangonic...and that makes your fingers happy to type! #another alternative... conditions = {'why': ('yes_or_no','==','yes'), 'elaborate_even_more': (('yes_or_no','==','yes'),('why','is not','None')) } #or another alternative... """Showe the field whiche hath the name *why* only under that circumstance in whiche the field whiche hath the name *yes_or_no* hath the value *yes*, in strictest equality.""" etc... Those conditions will be eventually passed via django templates to some javascript that will show or hide form fields accordingly. Which of those options (or please propose a better option) aligns better with conventions such that it will be easiest for the python/django developer to use? Also are there other considerations that should impact what syntax I choose?

    Read the article

  • Rebuilding website from Django 0.96 to Django 1.2

    - by Neytiri
    I've got a website done in Django 0.96 (done in 2007), and now we are thinking about rebuilding it (not just migrating) for Django 1.2 . Can anyone point me to the new (and worth the while) widgets, plugins and other stuff for Django 1.2 (released in april 2010). I've heard of "South" and of a widget for debugging (can't remember the name), but I'm a little lost here.

    Read the article

  • Can django's auth_user.username be varchar(75)? How could that be done?

    - by perrierism
    Is there anything wrong with running alter table on auth_user to make username be varchar(75) so it can fit an email? What does that break if anything? If you were to change auth_user.username to be varchar(75) where would you need to modify django? Is it simply a matter of changing 30 to 75 in the source code?: username = models.CharField(_('username'), max_length=30, unique=True, help_text=_("Required. 30 characters or fewer. Letters, numbers and @/./+/-/_ characters")) Or is there other validation on this field that would have to be changed or any other repercussions to doing so? See comment discussion with bartek below regarding the reason for doing it.

    Read the article

  • Why use Django on Google App Engine?

    - by Travis Bradshaw
    When researching Google App Engine (GAE), it's clear that using Django is wildly popular for developing in Python on GAE. I've been scouring the web to find information on the costs and benefits of using Django, to find out why it's so popular. While I've been able to find a wide variety of sources on how to run Django on GAE and the various methods of doing so, I haven't found any comparative analysis on why Django is preferable to using the webapp framework provided by Google. To be clear, it's immediately apparent why using Django on GAE is useful for developers with an existing skillset in Django (a majority of Python web developers, no doubt) or existing code in Django (where using GAE is more of a porting exercise). My team, however, is evaluating GAE for use on an all-new project and our existing experience is with TurboGears, not Django. It's been quite difficult to determine why Django is beneficial to a development team when the BigTable libraries have replaced Django's ORM, sessions and authentication are necessarily changed, and Django's templating (if desirable) is available without using the entire Django stack. Finally, it's clear that using Django does have the advantage of providing an "exit strategy" if we later wanted to move away from GAE and need a platform to target for the exodus. I'd be extremely appreciative for help in pointing out why using Django is better than using webapp on GAE. I'm also completely inexperienced with Django, so elaboration on smaller features and/or conveniences that work on GAE are also valuable to me. Thanks in advance for your time!

    Read the article

  • Django vs GAE + Django vs GAE + other framework

    - by Ilian Iliev
    I`m looking for opinion which one is better for building web applications(web sites). I have some experience with Django, and some with Google App Engine and App-Engine-Patch for Django. And it seems to me that only Django is working faster than the GAE implementation. Is there some other frameworks that simplify the developments process, providing forms creating, user management, url resolving etc. Thanks in advance, Ilian Iliev P.S. I am also interested in GAE and webapp framework case

    Read the article

  • Google App Engine + Form Validation

    - by Iwona
    Hi, I would like to do google app engine form validation but I dont know how to do it? I tried like this: from google.appengine.ext.db import djangoforms from django import newforms as forms class SurveyForm(forms.Form): occupations_choices = ( ('1', ""), ('2', "Undergraduate student"), ('3', "Postgraduate student (MSc)"), ('4', "Postgraduate student (PhD)"), ('5', "Lab assistant"), ('6', "Technician"), ('7', "Lecturer"), ('8', "Other" ) ) howreach_choices = ( ('1', ""), ('2', "Typed the URL directly"), ('3', "Site is bookmarked"), ('4', "A search engine"), ('5', "A link from another site"), ('6', "From a book"), ('7', "Other") ) boxes_choices = ( ("des", "Website Design"), ("svr", "Web Server Administration"), ("com", "Electronic Commerce"), ("mkt", "Web Marketing/Advertising"), ("edu", "Web-Related Education") ) name = forms.CharField(label='Name', max_length=100, required=True) email = forms.EmailField(label='Your Email Address:') occupations = forms.ChoiceField(choices=occupations_choices, label='What is your occupation?') howreach = forms.ChoiceField(choices=howreach_choices, label='How did you reach this site?') # radio buttons 1-5 rating = forms.ChoiceField(choices=range(1,6), label='What is your occupation?', widget=forms.RadioSelect) boxes = forms.ChoiceField(choices=boxes_choices, label='Are you involved in any of the following? (check all that apply):', widget=forms.CheckboxInput) comment = forms.CharField(widget=forms.Textarea, required=False) And I wanted to display it like this: template_values = { 'url' : url, 'url_linktext' : url_linktext, 'userName' : userName, 'item1' : SurveyForm() } And I have this error message: Traceback (most recent call last): File "C:\Program Files\Google\google_appengine\google\appengine\ext\webapp_init_.py", line 515, in call handler.get(*groups) File "C:\Program Files\Google\google_appengine\demos\b00213576\main.py", line 144, in get self.response.out.write(template.render(path, template_values)) File "C:\Program Files\Google\google_appengine\google\appengine\ext\webapp\template.py", line 143, in render return t.render(Context(template_dict)) File "C:\Program Files\Google\google_appengine\google\appengine\ext\webapp\template.py", line 183, in wrap_render return orig_render(context) File "C:\Program Files\Google\google_appengine\lib\django\django\template_init_.py", line 168, in render return self.nodelist.render(context) File "C:\Program Files\Google\google_appengine\lib\django\django\template_init_.py", line 705, in render bits.append(self.render_node(node, context)) File "C:\Program Files\Google\google_appengine\lib\django\django\template_init_.py", line 718, in render_node return(node.render(context)) File "C:\Program Files\Google\google_appengine\lib\django\django\template\defaulttags.py", line 209, in render return self.nodelist_true.render(context) File "C:\Program Files\Google\google_appengine\lib\django\django\template_init_.py", line 705, in render bits.append(self.render_node(node, context)) File "C:\Program Files\Google\google_appengine\lib\django\django\template_init_.py", line 718, in render_node return(node.render(context)) File "C:\Program Files\Google\google_appengine\lib\django\django\template_init_.py", line 768, in render return self.encode_output(output) File "C:\Program Files\Google\google_appengine\lib\django\django\template_init_.py", line 757, in encode_output return str(output) File "C:\Program Files\Google\google_appengine\lib\django\django\newforms\util.py", line 26, in str return self.unicode().encode(settings.DEFAULT_CHARSET) File "C:\Program Files\Google\google_appengine\lib\django\django\newforms\forms.py", line 73, in unicode return self.as_table() File "C:\Program Files\Google\google_appengine\lib\django\django\newforms\forms.py", line 144, in as_table return self._html_output(u'%(label)s%(errors)s%(field)s%(help_text)s', u'%s', '', u'%s', False) File "C:\Program Files\Google\google_appengine\lib\django\django\newforms\forms.py", line 129, in _html_output output.append(normal_row % {'errors': bf_errors, 'label': label, 'field': unicode(bf), 'help_text': help_text}) File "C:\Program Files\Google\google_appengine\lib\django\django\newforms\forms.py", line 232, in unicode value = value.str() File "C:\Program Files\Google\google_appengine\lib\django\django\newforms\util.py", line 26, in str return self.unicode().encode(settings.DEFAULT_CHARSET) File "C:\Program Files\Google\google_appengine\lib\django\django\newforms\widgets.py", line 246, in unicode return u'\n%s\n' % u'\n'.join([u'%s' % w for w in self]) File "C:\Program Files\Google\google_appengine\lib\django\django\newforms\widgets.py", line 238, in iter yield RadioInput(self.name, self.value, self.attrs.copy(), choice, i) File "C:\Program Files\Google\google_appengine\lib\django\django\newforms\widgets.py", line 212, in init self.choice_value = smart_unicode(choice[0]) TypeError: 'int' object is unsubscriptable Do You have any idea how I can do this validation in different case? I have tried to do it using this kind of: class ItemUserAnswer(djangoforms.ModelForm): class Meta: model = UserAnswer But I dont know how to add extra labels to this form and it is displayed in one line. Do You have any suggestions? Thanks a lot as it making me crazy why it is still not working:/

    Read the article

  • Securing ASP.Net Pages - Forms Authentication - C# and .Net 4

    - by SAMIR BHOGAYTA
    ASP.Net has a built-in feature named Forms Authentication that allows a developer to easily secure certain areas of a web site. In this post I'm going to build a simple authentication sample using C# and ASP.Net 4.0 (still in beta as of the posting date). Security settings with ASP.Net is configured from within the web.config file. This is a standard ASCII file, with an XML format, that is located in the root of your web application. Here is a sample web.config file: configuration system.web authenticationmode="Forms" formsname="TestAuthCookie"loginUrl="login.aspx"timeout="30" credentialspasswordFormat="Clear" username="user1"password="pass1"/ username="user2"password="pass2"/ authorization denyusers="?"/ compilationtargetFramework="4.0"/ pagescontrolRenderingCompatibilityVersion="3.5"clientIDMode="AutoID"/ Here is the complete source of the sample login.aspx page: div Username: asp:TextBox ID="txtUsername" runat="server":TextBox Password: asp:TextBox ID="txtPassword" runat="server":TextBox asp:Button ID="Button1" runat="server" onclick="Button1_Click" Text="Login" / asp:Label ID="lblStatus" runat="server" Text="Please login":Label /div And here is the complete source of the login.aspx.cs file: using System; using System.Web.UI.WebControls; using System.Web.Security; public partial class Default3 : System.Web.UI.Page { protected void Button1_Click(object sender, EventArgs e) { if (FormsAuthentication.Authenticate(txtUsername.Text, txtPassword.Text)) { lblStatus.Text = ("Welcome " + txtUsername.Text); FormsAuthentication.RedirectFromLoginPage(txtUsername.Text, true); } else { lblStatus.Text = "Invalid login!"; } } }

    Read the article

  • Is this a secure solution for RESTful authentication?

    - by Chad Johnson
    I need to quickly implement a RESTful authentication system for my JavaScript application to use. I think I understand how it should work, but I just want to double check. Here's what I'm thinking -- what do you guys think? Database schema users id : integer first_name : varchar(50) last_name : varchar(50) password : varchar(32) (MD5 hashed) etc. user_authentications id : integer user_id : integer auth_token : varchar(32) (AES encrypted, with keys outside database) access_token : varchar(32) (AES encrypted, with keys outside database) active : boolean Steps The following happens over SSL. I'm using Sinatra for the API. JavaScript requests authentication via POST to /users/auth/token. The /users/auth/token API method generates an auth_token hash, creates a record in user_authentications, and returns auth_token. JavaScript hashes the user's password and then salts it with auth_token -- SHA(access_token + MD5(password)) POST the user's username and hashed+salted password to /users/auth/authenticate. The /users/auth/authenticate API method will verify that SHA(AES.decrypt(access_token) + user.password) == what was received via POST. The /users/auth/authenticate will generate, AES encrypt, store, and return an access token if verification is successful; otherwise, it will return 401 Unauthorized. For any future requests against the API, JavaScript will include access_token, and the API will find the user account based on that.

    Read the article

  • Squid 3 and Internet Explorer 11 with authentication

    - by StBlade
    Need some help. My college has up until now been running Squid 3 on Ubuntu 12.02 and now 14.04 successfully. That was till recently. Our WSUS server is dishing out updates to all our workstations of which Internet Explorer 11 is one of them. Now all of a sudden users do not need to authenticate via the squid proxy to be able to use the internet. This makes it rather difficult as I also use SARG to generate usage logs for all users each day. All our workstations also have Chrome on them, and Chrome authenticates fine via the Squid proxy. Doing a couple of Googles, I ran into and article, where someone made mention that Microsoft has deprecated digest and basic authentication from IE 11. Reason was given that Office 2013 was giving problems as it was not giving the popup screen for authentication when Office tries to download templates from the internet. I have run into this problem, but by setting those sites to not authenticate via squid fixed the problem. Has anyone else run into something similiar? Would changing to NTLM or Kereberos be a solution?

    Read the article

  • Authentication system brainstorm

    - by gansbrest
    Hi. We got multiple small websites (microsites) and one main high traffic one with big users base. Right now the requirement is to build authentication system which should allow users to loign with the same identity across the network. All website are running on different domains, powered by Drupal 6 CMS and have separate databases (so sharing tables with prefix is not an option + it creates a huge mess in the db). Here is the set of core requirements I came up with: Users should be able to login with the same credentials to all sites within the network User’s data sharing between Main site (storage) and all micro sites within the network Data synchronization across the network when user changes the data (update email or password for example) The login/registration process should be seamless and consistent Register on any of the sites across the network and use that identity to login later on. In the future there might be a need to add openid authentication options. Basically we are looking at something similar stackexchange does, but not sure if they have central users base on not. I was thinking about custom solution which will include 2 parts (modules), one will be stored on the Main site for users data storing and responding to requests from clients. Second part (module) will be placed on each microsite, which is going to send requests to the Master. Some kind of client - server setup. One of the complications I see right away is #3. Data Synhcronization across the network. I just don't want to reinvent the wheel and maybe some work is already done in this direction. Looking forward to your ideas on how to approach this project. EDIT: We use MySQL database

    Read the article

  • Password not working for sudo ("Authentication failure")

    - by Souta
    Before I mention anything further, DO NOT give me a response saying that terminal won't show password input. I'm AWARE of that. I'm typing my user password in (not a capslock issue), and for some reason it still says 'Authentication Failure'. Is there some other password (one I'm not aware of) I'm supposed to be using other than my user password? I've had this ubuntu before, on another hard drive and I didn't have this problem. (And it was the same ubuntu, ubuntu 12.04 LTS) ai@AiNekoYokai:~$ groups ai adm cdrom sudo dip plugdev lpadmin sambashare ai@AiNekoYokai:~$ lsb_release -rd Description: Ubuntu 12.04 LTS Release: 12.04 ai@AiNekoYokai:~$ pkexec cat /etc/sudoers # # This file MUST be edited with the 'visudo' command as root. # # Please consider adding local content in /etc/sudoers.d/ instead of # directly modifying this file. # # See the man page for details on how to write a sudoers file. # Defaults env_reset Defaults secure_path="/usr/local/sbin:/usr/local/bin:/usr/sbin:/usr/bin:/sbin:/bin" # Host alias specification # User alias specification # Cmnd alias specification # User privilege specification root ALL=(ALL:ALL) ALL # Members of the admin group may gain root privileges %admin ALL=(ALL) ALL # Allow members of group sudo to execute any command %sudo ALL=(ALL:ALL) ALL # See sudoers(5) for more information on "#include" directives: #includedir /etc/sudoers.d I can log in with my password, but it's not accepted as valid for authentication <-- That is pretty much my issue. (Although, I haven't gone into recovery mode.) I've ran: ai@AiNekoYokai:~$ ls /etc/sudoers.d README And also reinstalled sudo with: pkexec apt-get update pkexec apt-get --purge --reinstall install sudo pkexec usermod -a -G admin $USER <- Says admin does not exist su $USER <- worked for me, however, my password still does not do much (in sense of not working for other things) I changed my password with pkexec passwd $USER. I was able to change it no problem. gksudo xclock was something I was able to get into, no problem. (Clock showed) ai@AiNekoYokai:~$ gksudo xclock

    Read the article

  • Spring security ldap authentication with different ldap for authorities

    - by wuntee
    I am trying to set up an ldap authentication context where the authorities is a separate ldap instance (with the same principal name). I am having trouble setting up the authentication part, the logs dont show any search results for the following context. Can anyone see what I am doing wrong? <beans:bean id="ldapAuthProvider" class="org.springframework.security.ldap.authentication.LdapAuthenticationProvider"> <beans:constructor-arg> <beans:bean class="org.springframework.security.ldap.authentication.BindAuthenticator"> <beans:constructor-arg ref="adContextSource" /> <beans:property name="userSearch"> <beans:bean class="org.springframework.security.ldap.search.FilterBasedLdapUserSearch"> <beans:constructor-arg index="0" value=""/> <beans:constructor-arg index="1" value="(samaccountname={0})"/> <beans:constructor-arg index="2" ref="adContextSource" /> <beans:property name="searchSubtree" value="true" /> <beans:property name="returningAttributes"> <beans:list> <beans:value>DN</beans:value> </beans:list> </beans:property> </beans:bean> </beans:property> </beans:bean> </beans:constructor-arg> <beans:constructor-arg> <beans:bean class="org.springframework.security.ldap.userdetails.DefaultLdapAuthoritiesPopulator"> <beans:constructor-arg ref="cadaContextSource" /> <beans:constructor-arg value="ou=groups" /> <beans:property name="groupRoleAttribute" value="cn" /> </beans:bean> </beans:constructor-arg> </beans:bean> The logs simply show this when trying to authenticate: [DEBUG,UsernamePasswordAuthenticationFilter] Request is to process authentication [DEBUG,ProviderManager] Authentication attempt using org.springframework.security.ldap.authentication.LdapAuthenticationProvider [DEBUG,LdapAuthenticationProvider] Processing authentication request for user: wuntee [DEBUG,FilterBasedLdapUserSearch] Searching for user 'wuntee', with user search [ searchFilter: '(samaccountname={0})', searchBase: '', scope: subtree, searchTimeLimit: 0, derefLinkFlag: false ] [DEBUG,AbstractContextSource] Got Ldap context on server 'ldap://adapps.cable.comcast.com:3268/dc=comcast,dc=com/dc=comcast,dc=com' [DEBUG,XmlWebApplicationContext] Publishing event in Root WebApplicationContext: org.springframework.security.authentication.event.AuthenticationFailureServiceExceptionEvent[source=org.springframework.security.authentication.UsernamePasswordAuthenticationToken@b777617d: Principal: wuntee; Password: [PROTECTED]; Authenticated: false; Details: org.springframework.security.web.authentication.WebAuthenticationDetails@12afc: RemoteIpAddress: 127.0.0.1; SessionId: 191F70ED4E8351F8638868C34C6A076A; Not granted any authorities] [DEBUG,DefaultListableBeanFactory] Returning cached instance of singleton bean 'org.springframework.security.core.session.SessionRegistryImpl#0' [DEBUG,UsernamePasswordAuthenticationFilter] Authentication request failed: org.springframework.security.authentication.AuthenticationServiceException: Failed to parse DN; nested exception is org.springframework.ldap.core.TokenMgrError: Lexical error at line 1, column 21. Encountered: "=" (61), after : "" [DEBUG,UsernamePasswordAuthenticationFilter] Updated SecurityContextHolder to contain null Authentication [DEBUG,UsernamePasswordAuthenticationFilter] Delegating to authentication failure handlerorg.springframework.security.web.authentication.SimpleUrlAuthenticationFailureHandler@28651c

    Read the article

  • Django simple syndication example gives: ImportError, cannot import name Feed

    - by AP257
    I'm trying to set up the simple syndication example from the Django docs, in a working project. But I'm getting an ImportError, even though I'm sure I've copied the example exactly. Here's what I have in feeds.py: from django.contrib.syndication.views import Feed class LatestEntriesFeed(Feed): # etc And here's what I have in urls.py: from election.feeds import LatestEntriesFeed #... further down, at the appropriate line... # RSS feed (r'^feed/$', LatestEntriesFeed()), But Django says it can't import the Feed class from django.contrib.syndication.views: ImportError at /feed/ cannot import name Feed ....feeds.py in <module> from django.contrib.syndication.views import Feed Any ideas? I'm baffled!

    Read the article

  • url template tag in django template

    - by user192048
    guys: I was trying to use the url template tag in django, but no lucky, I defined my urls.py like this urlpatterns = patterns('', url(r'^analyse/$', views.home, name="home"), url(r'^analyse/index.html', views.index, name="index"), url(r'^analyse/setup.html', views.setup, name="setup"), url(r'^analyse/show.html', views.show, name="show"), url(r'^analyse/generate.html', views.generate, name="generate"), I defined the url pattern in my view like this {% url 'show'%} then I got this error message Caught an exception while rendering: Reverse for ''show'' with arguments '()' and keyword arguments '{}' not found. Original Traceback (most recent call last): File "/Library/Python/2.5/site-packages/django/template/debug.py", line 71, in render_node result = node.render(context) File "/Library/Python/2.5/site-packages/django/template/defaulttags.py", line 155, in render nodelist.append(node.render(context)) File "/Library/Python/2.5/site-packages/django/template/defaulttags.py", line 382, in render raise e NoReverseMatch: Reverse for ''show'' with arguments '()' and keyword arguments '{}' not found. I am wondering why django failed to render? what is the right way to define it in the tempalte?

    Read the article

  • Django syncdb not making tables for my app

    - by Rosarch
    It used to work, and now it doesn't. python manage.py syncdb no longer makes tables for my app. From settings.py: INSTALLED_APPS = ( 'django.contrib.auth', 'django.contrib.contenttypes', 'django.contrib.sessions', 'django.contrib.sites', 'mysite.myapp', 'django.contrib.admin', ) What could I be doing wrong? The break appeared to coincide with editing this model in models.py, but that could be total coincidence. I commented out the lines I changed, and it still doesn't work. class MyUser(models.Model): user = models.ForeignKey(User, unique=True) takingReqSets = models.ManyToManyField(RequirementSet, blank=True) takingTerms = models.ManyToManyField(Term, blank=True) takingCourses = models.ManyToManyField(Course, through=TakingCourse, blank=True) school = models.ForeignKey(School) # minCreditsPerTerm = models.IntegerField(blank=True) # maxCreditsPerTerm = models.IntegerField(blank=True) # optimalCreditsPerTerm = models.IntegerField(blank=True) UPDATE: When I run python manage.py loadddata initial_data, it gives an error: DeserializationError: Invalid model identifier: myapp.SomeModel Loading this data had worked fine before. This error is thrown on the very first data object in the data file.

    Read the article

  • Django ORM and PostgreSQL connection limits

    - by bennylope
    I'm running a Django project on Postgresql 8.1.21 (using Django 1.1.1, Python2.5, psycopg2, Apache2 with mod_wsgi 3.2). We've recently encountered this lovely error: OperationalError: FATAL: connection limit exceeded for non-superusers I'm not the first person to run up against this. There's a lot of discussion about this error, specifically with psycopg, but much of it centers on older versions of Django and/or offer solutions involving edits to code in Django itself. I've yet to find a succinct explanation of how to solve the problem of the Django ORM (or psycopg, whichever is really responsible, in this case) leaving open Postgre connections. Will simply adding connection.close() at the end of every view solve this problem? Better yet, has anyone conclusively solved this problem and kicked this error's ass?

    Read the article

  • View centric design with Django

    - by wishi_
    Hi! I'm relatively new to Django and I'm designing a website that primarily needs usability experience, speaking of optimized CSS, HTML5 and UI stuff. It's very easy to use Django for data/Model centric design. Just designing a couple of Python classes and ./manage.py syncdb - there's your Model. But I'm dealing with a significant amount of View centric challenges. (Different user classes, different tasks, different design challenges.) The official Django tutorial cursorily goes through using a "Template". Is there any Design centric guide for Django, or a set of Templates that are ready and useable? I don't want to start from scratch using JS, HTML5, Ajax and everything. From the Model layer perspective Django is very rapid and delivering a working base system. I wonder whether there's something like that for the Views.

    Read the article

  • django newbie question : cant start a new project

    - by Moayyad Yaghi
    hello . I'm totally new to django . and I'm using its documentation to get help on how to use it but seems like something is missing. i installed django using setup.py install command and i added the ( django/bin ) to system path variable but. i still cant start a new project i use the following syntax to start a project : django-admin.py startproject myNewProject but it says Type 'django-admin.py help' for usage. 1 do i miss anything ? thank u

    Read the article

  • Single Sign On with Forms Authentication

    - by Christo Fur
    I am trying to set up Single sign on for 2 websites that reside on the same domain e.g. http://mydomain (top level site that contains a forms-auth login page) http://mydomain/admin (seperately developed website residing in a Virtual Application within the parent website) Have read a few articles on Single Sign on e.g. http://www.codeproject.com/KB/aspnet/SingleSignon.aspx And they seem to suggest it is just a case of having the same machinekey section in each web.config so that the cookie encryprion and decryption is the same for each application I have set this up and I never get prompted for credentials in the sub-website (the virtual application) I always get prompted in the parent site. In addition to having the same machinekey I've also tried adding the same <authentication> and <authorisation> elements Any idea what I could be missing?

    Read the article

  • OpenId ASP MVC Authentication with long expiry

    - by Khash
    Stackoverflow uses OpenId as many other websites. However, I rarely need to provide my OpenId to Stackoverflow while with other OpenId enabled websites, I have to do it once a day or week. This suggests to me that the expiry of the session is with the website and not the OpenId provider. Looking at the DotNetOpenId code in ASP MVC, I can see that after a successful authentication by the OpenId provider FormsAuthentication.SetAuthCookie is called with the identifier and a boolean parameter to determine if the cookie should be persisted. How can I force this cookie to expire, say in 2020 instead of whatever the default value is.

    Read the article

  • Can the authentication box appear earlier after startup?

    - by John
    I'd expected the authentication "Enter your password" box to appear and need to be answered before any applications would run after startup - rather like Windows demands a password first - but it seems to be quite an unrushed process. CAN it be persuaded to get going more briskly ? (I'm usually about to respond to a new email before it interrupts me after starting Linux from scratch :) (I'm quite new to Linux: I'm on Ubuntu 12.04 LTS)

    Read the article

  • Ubuntu One Client 3.02 for windows - Authentication Failure signing in with existing account

    - by steigerj
    I have logged into ubuntu one using a browser successfully. But using the very same login email address and password in the windows client 3.02 gets me an 'authentication failed' message. I am 100% sure I used the same email address and password. My password does not contain any non-ascii characters. Someone suggested to use an older version of the client. Where could i possibly download a complete installer?

    Read the article

  • Django Form for date range

    - by gramware
    I am trying to come up with a form that lets the user select a date range to generate a web query in Django. I am having errors getting the date to filter with in my view, I am unable to strip the date. Here is my forms.py class ReportFiltersForm(forms.Form): start_date = forms.DateField(input_formats='%Y,%m,%d',widget=SelectDateWidget()) end_date = forms.DateField(input_formats='%Y,%m,%d',widget=SelectDateWidget()) And my view if request.method == 'POST': form = ReportFiltersForm(request.POST) sdy = request.POST['start_date_year'] sdm = request.POST['start_date_month'] sdd = request.POST['start_date_day'] edy = request.POST['end_date_year'] edm = request.POST['end_date_month'] edd = request.POST['end_date_day'] start_date= datetime.date(sdy, sdm, sdd) end_date= datetime.date(edy, edm,edd) Traceback Traceback (most recent call last): File "/usr/lib/python2.6/site-packages/django/core/servers/basehttp.py", line 651, in __call__ return self.application(environ, start_response) File "/usr/lib/python2.6/site-packages/django/core/handlers/wsgi.py", line 241, in __call__ response = self.get_response(request) File "/usr/lib/python2.6/site-packages/django/core/handlers/base.py", line 134, in get_response return self.handle_uncaught_exception(request, resolver, exc_info) File "/usr/lib/python2.6/site-packages/django/core/handlers/base.py", line 154, in handle_uncaught_exception return debug.technical_500_response(request, *exc_info) File "/usr/lib/python2.6/site-packages/django/core/handlers/base.py", line 92, in get_response response = callback(request, *callback_args, **callback_kwargs) File "/home/projects/acms/cms/views.py", line 470, in eventreports start_date= datetime.date(sdy, sdm, sdd) TypeError: an integer is required

    Read the article

< Previous Page | 11 12 13 14 15 16 17 18 19 20 21 22  | Next Page >