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  • "Invalid Handle Object" when plotting 2 figures Matlab

    - by pinnacler
    I'm having a difficult time understanding the paradigm of Matlab classes vs compared to c++. I wrote code the other day, and I thought it should work. It did not... until I added <handle after the classdef. So I have two classes, landmarks and robot, both are called from within the simulation class. This is the main loop of obj.simulation.animate() and it works, until I try to plot two things at once. DATA.path is a record of all the places a robot has been on the map, and it's updated every time the position is updated. When I try to plot it, by uncommenting the two marked lines below, I get this error: ??? Error using == set Invalid handle object. Error in == simulationsimulation.animate at 45 set(l.lm,'XData',obj.landmarks.apparentPositions(:,1),'YData',obj.landmarks.apparentPositions(:,2)); %INITIALIZE GLOBALS global DATA XX XX = [obj.robot.x ; obj.robot.y]; DATA.i=1; DATA.path = XX; %Setup Plots fig=figure; xlabel('meters'), ylabel('meters') set(fig, 'name', 'Phil''s AWESOME 80''s Robot Simulator') xymax = obj.landmarks.mapSize*3; xymin = -(obj.landmarks.mapSize*3); l.lm=scatter([0],[0],'b+'); %"UNCOMMENT ME"l.pth= plot(0,0,'k.','markersize',2,'erasemode','background'); % vehicle path axis([xymin xymax xymin xymax]); %Simulation Loop for n = 1:720, %Calculate and Set Heading/Location XX = [obj.robot.x;obj.robot.y]; store_data(XX); if n == 120, DATA.path end %Update Position headingChange = navigate(n); obj.robot.updatePosition(headingChange); obj.landmarks.updatePerspective(obj.robot.heading, obj.robot.x, obj.robot.y); %Animate %"UNCOMMENT ME" set(l.pth, 'xdata', DATA.path(1,1:DATA.i), 'ydata', DATA.path(2,1:DATA.i)); set(l.lm,'XData',obj.landmarks.apparentPositions(:,1),'YData',obj.landmarks.apparentPositions(:,2)); rectangle('Position',[-2,-2,4,4]); drawnow This is the classdef for landmarks classdef landmarks <handle properties fixedPositions; %# positions in a fixed coordinate system. [ x, y ] mapSize; %Map Size. Value is side of square x; y; heading; headingChange; end properties (Dependent) apparentPositions end methods function obj = landmarks(mapSize, numberOfTrees) obj.mapSize = mapSize; obj.fixedPositions = obj.mapSize * rand([numberOfTrees, 2]) .* sign(rand([numberOfTrees, 2]) - 0.5); end function apparent = get.apparentPositions(obj) currentPosition = [obj.x ; obj.y]; apparent = bsxfun(@minus,(obj.fixedPositions)',currentPosition)'; apparent = ([cosd(obj.heading) -sind(obj.heading) ; sind(obj.heading) cosd(obj.heading)] * (apparent)')'; end function updatePerspective(obj,tempHeading,tempX,tempY) obj.heading = tempHeading; obj.x = tempX; obj.y = tempY; end end end To me, this is how I understand things. I created a figure l.lm that has about 100 xy points. I can rotate this figure by using set(l.lm,'XData',obj.landmarks.apparentPositions(:,1),'YData',obj.landmarks.apparentPositions(:,2)); When I do that, things work. When I try to plot a second group of XY points, stored in DATA.path, it craps out and I can't figure out why.

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  • Matlab Image watermarking question , using both SVD and DWT

    - by Georgek
    Hello all . here is a code that i got over the net ,and it is supposed to embed a watermark of size(50*20) called _copyright.bmp in the Code below . the size of the cover object is (512*512), it is called _lena_std_bw.bmp.What we did here is we did DWT2 2 times for the image , when we reached our second dwt2 cA2 size is 128*128. You should notice that the blocksize and it equals 4, it is used to determine the max msg size based on cA2 according to the following code:max_message=RcA2*CcA2/(blocksize^2). in our current case max_message would equal 128*128/(4^2)=1024. i want to embed a bigger watermark in the 2nd dwt2 and lets say the size of that watermark is 400*10(i can change the dimension using MS PAINT), what i have to do is change the size of the blocksize to 2. so max_message=4096.Matlab gives me 3 errors and they are : ??? Error using == plus Matrix dimensions must agree. Error in == idwt2 at 93 x = upsconv2(a,{Lo_R,Lo_R},sx,dwtEXTM,shift)+ ... % Approximation. Error in == two_dwt_svd_low_low at 88 CAA1 = idwt2(cA22,cH2,cV2,cD2,'haar',[RcA1,CcA1]); The origional Code is (the origional code where blocksize =4): %This algorithm makes DWT for the whole image and after that make DWT for %cH1 and make SVD for cH2 and embed the watermark in every level after SVD %(1) -------------- Embed Watermark ------------------------------------ %Add the watermar W to original image I and give the watermarked image in J %-------------------------------------------------------------------------- % set the gain factor for embeding and threshold for evaluation clc; clear all; close all; % save start time start_time=cputime; % set the value of threshold and alpha thresh=.5; alpha =0.01; % read in the cover object file_name='_lena_std_bw.bmp'; cover_object=double(imread(file_name)); % determine size of watermarked image Mc=size(cover_object,1); %Height Nc=size(cover_object,2); %Width % read in the message image and reshape it into a vector file_name='_copyright.bmp'; message=double(imread(file_name)); T=message; Mm=size(message,1); %Height Nm=size(message,2); %Width % perform 1-level DWT for the whole cover image [cA1,cH1,cV1,cD1] = dwt2(cover_object,'haar'); % determine the size of cA1 [RcA1 CcA1]=size(cA1) % perform 2-level DWT for cA1 [cA2,cH2,cV2,cD2] = dwt2(cA1,'haar'); % determine the size of cA2 [RcA2 CcA2]=size(cA2) % set the value of blocksize blocksize=4 % reshape the watermark to a vector message_vector=round(reshape(message,Mm*Nm,1)./256); W=message_vector; % determine maximum message size based on cA2, and blocksize max_message=RcA2*CcA2/(blocksize^2) % check that the message isn't too large for cover if (length(message) max_message) error('Message too large to fit in Cover Object') end %----------------------- process the image in blocks ---------------------- x=1; y=1; for (kk = 1:length(message_vector)) [cA2u cA2s cA2v]=svd(cA2(y:y+blocksize-1,x:x+blocksize-1)); % if message bit contains zero, modify S of the original image if (message_vector(kk) == 0) cA2s = cA2s*(1 + alpha); % otherwise mask is filled with zeros else cA2s=cA2s; end cA22(y:y+blocksize-1,x:x+blocksize-1)=cA2u*cA2s*cA2v; % move to next block of mask along x; If at end of row, move to next row if (x+blocksize) >= CcA2 x=1; y=y+blocksize; else x=x+blocksize; end end % perform IDWT CAA1 = idwt2(cA22,cH2,cV2,cD2,'haar',[RcA1,CcA1]); watermarked_image= idwt2(CAA1,cH1,cV1,cD1,'haar',[Mc,Nc]); % convert back to uint8 watermarked_image_uint8=uint8(watermarked_image); % write watermarked Image to file imwrite(watermarked_image_uint8,'dwt_watermarked.bmp','bmp'); % display watermarked image figure(1) imshow(watermarked_image_uint8,[]) title('Watermarked Image') %(2) ---------------------------------------------------------------------- %---------- Extract Watermark from attacked watermarked image ------------- %-------------------------------------------------------------------------- % read in the watermarked object file_name='dwt_watermarked.bmp'; watermarked_image=double(imread(file_name)); % determine size of watermarked image Mw=size(watermarked_image,1); %Height Nw=size(watermarked_image,2); %Width % perform 1-level DWT for the whole watermarked image [ca1,ch1,cv1,cd1] = dwt2(watermarked_image,'haar'); % determine the size of ca1 [Rca1 Cca1]=size(ca1); % perform 2-level DWT for ca1 [ca2,ch2,cv2,cd2] = dwt2(ca1,'haar'); % determine the size of ca2 [Rca2 Cca2]=size(ca2); % process the image in blocks % for each block get a bit for message x=1; y=1; for (kk = 1:length(message_vector)) % sets correlation to 1 when patterns are identical to avoid /0 errors % otherwise calcluate difference between the cover image and the % watermarked image [cA2u cA2s cA2v]=svd(cA2(y:y+blocksize-1,x:x+blocksize-1)); [ca2u1 ca2s1 ca2v1]=svd(ca2(y:y+blocksize-1,x:x+blocksize-1)); correlation(kk)=diag(ca2s1-cA2s)'*diag(ca2s1-cA2s)/(alpha*alpha)/(diag(cA2s)*diag(cA2s)); % move on to next block. At and of row move to next row if (x+blocksize) >= Cca2 x=1; y=y+blocksize; else x=x+blocksize; end end % if correlation exceeds average correlation correlation(kk)=correlation(kk)+mean(correlation(1:Mm*Nm)); for kk = 1:length(correlation) if (correlation(kk) > thresh*alpha);%thresh*mean(correlation(1:Mo*No))) message_vector(kk)=0; end end % reshape the message vector and display recovered watermark. figure(2) message=reshape(message_vector(1:Mm*Nm),Mm,Nm); imshow(message,[]) title('Recovered Watermark') % display processing time elapsed_time=cputime-start_time, please do help,its my graduation project and i have been trying this code for along time but failed miserable. Thanks in advance

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  • C# Toolbox: Debug-able, Self-Installable Windows Service Template Redux

    - by James Michael Hare
    I had written a pair of posts before about creating a debug-able and self-installing windows service template in C#.  This is a template I began creating to ease creating windows services and to take some of the mundane tasks out of the coding effort.  The original posts were here: C# Windows Services (1 of 2) - Debug-able Windows Services C# Windows Services (2 of 2) - Self-Installing Windows Services But at the time, though I gave the code samples I didn't have a downloadable for of the template on the blog.  After getting many requests for the actual source, I zipped it up and am posting it with this blog entry.  Click on the link below to download the archive.  The password on the archive is, imaginatively enough, password.  Hope you enjoy and please feel free to comment and suggest changes! Debug-able, Self-Installing Windows Service Template download Enjoy! Tweet Technorati Tags: C#,Windows Service,Toolbox

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  • Learning Blend with .toolbox (Silverlight TV #29)

    In this episode, Arturo Toledo demonstrates all of the new content he and his colleagues have created to teach you to design and develop with Expression Blend and Silverlight. He shows off some really cool samples, all of which you can download and do yourself through hands on-labs. Arturo walks through the .toolbox site and shows the numerous learning materials, videos, demos, and hands-on labs. If you have been looking for a comprehensive set of self-paced learning materials focused on designing ...Did you know that DotNetSlackers also publishes .net articles written by top known .net Authors? We already have over 80 articles in several categories including Silverlight. Take a look: here.

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  • Telerik Q1 2010 Release Enhances Productivity Throughout .NET Toolbox

    Entire product portfolio now supports Microsoft Visual Studio 2010 RC Waltham, MA, March 10, 2010 Telerik, a leading vendor of development tools and user interface components for .NET, announced today their Q1 2010 release, consisting of a complete update of the Telerik .NET developer toolbox and the official release of Telerik Extensions for ASP.NET MVC and JustCode. This release is further marked by significant performance innovations in the companys Silverlight and WPF UI controls, full support...Did you know that DotNetSlackers also publishes .net articles written by top known .net Authors? We already have over 80 articles in several categories including Silverlight. Take a look: here.

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  • Telerik Q1 2010 Release Enhances Productivity Throughout .NET Toolbox

    Entire product portfolio now supports Microsoft Visual Studio 2010 RC Waltham, MA, March 10, 2010 Telerik, a leading vendor of development tools and user interface components for .NET, announced today their Q1 2010 release, consisting of a complete update of the Telerik .NET developer toolbox and the official release of Telerik Extensions for ASP.NET MVC and JustCode. This release is further marked by significant performance innovations in the companys Silverlight and WPF UI controls, full support...Did you know that DotNetSlackers also publishes .net articles written by top known .net Authors? We already have over 80 articles in several categories including Silverlight. Take a look: here.

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  • Installing a VADTools design component into your 3CX Voice Application Designer toolbox

    - by ParadigmShift
    The 3CX Voice Application Designer is an innovative tool for creating IVR (Interactive Voice Response) Applications, or Voice Applications.  It is a familiar drag-and-drop experience that Visual Studio developers will get the hang of pretty quick. Additionally, there are new 3rd party components released by BlueVoice, that are distributed though www.UtahVoIPStore.com I thought I’d post a quick introduction to it, by showing how to install a component into you designer tool box.  In this example I am using the CommandLine component, which lets you call the command line from your voice application. First, copy the ZIP file that came with your component to the root folder of your VAD project. Now extract the zip file into the root directory. The component will be in the root directory and the Libraries directory will have a new DLL file. Open your VAD project and right-click on the project in project explorer to add the new component to your project. Navigate to the root folder of your project and select the new component. The component is now ready for you to use in your toolbox.

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  • Matlab matrix replacement assignment gives error

    - by Gulcan
    Hello, when i tried to update some part of a matrix, i got the following error message: ??? Assignment has fewer non-singleton rhs dimensions than non-singleton subscripts My code tries to update some values of a matrix that represent a binary image. My code is as follows: outImage(3:5,2:4,1) = max(imBinary(3:5,2:4,1)); When I delete last parameter (1), this time I get the same error. I guess there is a mismatch between dimensions but I could not get it. outImage is a new object that is created at that time (I tried to create it before, but nothing changed). What may be wrong? Thanks in advance, Gulcan

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  • MATLAB matrix replacement assignment gives error

    - by Gulcan
    I tried to update some part of a matrix, I got the following error message: ??? Assignment has fewer non-singleton rhs dimensions than non-singleton subscripts My code tries to update some values of a matrix that represent a binary image. My code is as follows: outImage(3:5,2:4,1) = max(imBinary(3:5,2:4,1)); When I delete last parameter (1), this time I get the same error. I guess there is a mismatch between dimensions but I could not get it. outImage is a new object that is created at that time (I tried to create it before, but nothing changed). What may be wrong?

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  • Octave / Matlab: How to plot the roots of a polynomial

    - by Tom
    Hi everyone, Im trying to plot the roots of a polynomial, and i just cant get it. First i create my polynomial p5 = [1 0 0 0 0 -1] %x^5 - 1 r5 = roots(p5) stem (p5) Im using the stem function, but I would like to remove the stems, and just get the circle around the roots. Is this possible, is stem the right command? Thanks in advance, PS: This is not homework, but very close, will tag it if requested.

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  • memory not freed in matlab?

    - by noam
    I am running a script that animates a plot (simulation of a water flow). After a while, I kill the loop by doing ctrl-c. After doing this several times I get the error: ??? Error: Out of memory. And after I start receiving that error, every call to my script will generate it. Now, it happens before anything inside the function that I am calling is executed, i.e even if I add the line a=1 as the first line of the function I am calling, I still get the error and no printout, so the code inside the function doesn't even get executed. What could be causing this?

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  • Matlab multiple graph types inside one graph

    - by mirekys
    Hi, I have a task to draw electrostatic field between two electrodes( at given sizes and shape ), what i have now is that i draw the electrodes with area plot (area(elect_x,elect_y)) the graph looks like this: ------------------.--- |.. .---. |.. |...| |.. .----....| |.. |........| |.. ---------------------- and now i would need to draw inside this probably a mesh, showing the field. Is there any way to do it, or i´m on a wrong way? Thank you very much for every guide

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  • Finding edge and corner values of an image in matlab

    - by James
    Hi, this problem links to two other questions i've asked on here. I am tracing the outline of an image and plotting this to a dxf file. I would like to use the bwboundaries function to find the coordinates of the edges of the image, find the corner coordinates using the cornermetric function and then remove any edge coordinates that are not a corner. The important thing I need to be able to do is keep the order of the corner elements obtained from bwboundaries, so that the section traces properly. The dxf function I have that draws from the coordinates draws lines between coordinates that are next to each other, so the line has to be drawn "around" the section rather than straight between the corner points. The reason I am doing this is because there are less coordinates obtained this way, so it is easier to amend the dxf file (as there are less points to manipulate). The code I have so far is: %# Shape to be traced bw = zeros(200); bw(20:40,20:180) = 1; bw(20:180,90:110) = 1; bw(140:180,20:185) = 1; %# Boundary Finding Section [Boundary] = bwboundaries(bw); %Traces the boundary of each section figure, imshow(bw); hold on; colors=['b' 'g' 'r' 'c' 'm' 'y']; for k=1:length(Boundary) perim = Boundary{k}; %Obtains perimeter coordinates (as a 2D matrix) from the cell array cidx = mod(k,length(colors))+1;% Obtains colours for the plot plot(perim(:,2), perim(:,1),... colors(cidx),'LineWidth',2); end Coordmat = cell2mat(Boundary) %Converts the traced regions to a matrix X = Coordmat(:,1) Y = Coordmat(:,2) % This gives the edge coordinates in matrix form %% Corner Finding Section (from Jonas' answer to a previous question %# get corners cornerProbability = cornermetric(bw); cornerIdx = find(cornerProbability==max(cornerProbability(:))); %# Label the image. bwlabel puts 1 for the first feature, 2 for the second, etc. %# Since concave corners are placed just outside the feature, grow the features %# a little before labeling bw2 = imdilate(bw,ones(3)); labeledImage = bwlabel(bw2); %# read the feature number associated with the corner cornerLabels = labeledImage(cornerIdx); %# find all corners that are associated with feature 1 corners_1 = cornerIdx(cornerLabels==1) [Xcorners, Ycorners] = ind2sub(200,corners_1) % Convert subscripts The code I have is, to give a matrix Xfin for the final x coordinates (which are on the edge AND at a corner. Xfin = zeros(length(X),1) for i = Xcorners XFin(i) = Xcorners if i~= Xcorners XFin(i) = [] end end However, this does not work correctly, because the values in the solution are sorted into order, and only one of each value remains. As I said, I would like the corner elements to be in the same order as obtained from bwboundaries, to allow the image to trace properly. Thanks

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  • Matlab: convert global coordinates to figure coordinates

    - by noam
    If I get coordinates via coords = get(0,'PointerLocation'); How can I convert them into points gotten via ginput? i.e, I would like to get the same values from coords = get(0,'PointerLocation'); coords=someConversion(coords); As I would have gotten by calling coords=ginput(1); And clicking inside the figure in the same spot as the mouse was in the previous bit of code.

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  • SOM Algorithm Matlab HELP

    - by Tim
    I'm trying to pass a txt file to som_read_data from a GUI......i created a function that takes a txt file from the GUI and then passes it to som_read_data..but i'm getting some errors...here are a list of some of the errors.....any one with ideas? ??? Error using ==> ftell Invalid file identifier. Use fopen to generate a valid file identifier. Error in ==> som_read_data at 169 fpos1 = ftell(fid); c1 = 0; % read first non-comment line Error in ==> prog_som at 3 sD = som_read_data(m);

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  • Plotting multi-colored line in Matlab

    - by Jonas
    I would like to plot a line with two-color dashes, say red-blue-red-blue-... I know I could do it like this: plot([1,2],[1,2],'r'), hold on, plot([1,2],[1,2],'--b') However, since I need to be able to move the line, among others, it should only have a single handle. How could I do this?

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  • Matlab - plot multiple data sets on a scatter plot

    - by Mark
    Hey all, I have 2 sets of data (Ax, Ay; Bx, By) - I'd like to plot both of these data sets on a scatter plot with different colors, but can't seem to get it to work because it seems scatter() does not work like plot(). Is it possible to do this? I've tried... scatter(Ax, Ay, 'g', Bx, By, 'b') And scatter(Ax, Ay, 'g') scatter(Bx, By, 'b') The first way returns an error. The latter only plots the Bx/By data. Many thanks!

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  • How to setup matlab for parallel processing on Amazon EC2?

    - by JohnIdol
    I just setup a Extra Large Heavy Computation EC2 instance to throw it at my Genetic Algorithms problem, hoping to speed up things. This instance has 8 Intel Xeon processors (around 2.4Ghz each) and 7 Gigs of RAM. On my machine I have an Intel Core Duo, and matlab is able to work with my two cores just fine. On the EC2 instance though, matlab only is capable of detecting 1 out of 8 processors. Obviously the difference is that I have my 2 cores on a single processor, while the EC2 instance has 8 distinct processors. My question is, how do I get matlab to work with those 8 processors? I found this paper, but it seems related to setting up matlab with multiple EC2 instances, which is not my problem. Any help appreciated!

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  • What is the fastest way to unzip textfiles in Matlab during a function?

    - by Paul
    Hello all, I would like to scan text of textfiles in Matlab with the textscan function. Before I can open the textfile with fid = fopen('C:\path'), I need to unzip the files first. The files have the extension: *.gz There are thousands of files which I need to analyze and high performance is important. I have two ideas: (1) Use an external program an call it from the command line in Matlab (2) Use a Matlab 'zip'toolbox. I have heard of gunzip, but don't know about its performance. Does anyone knows a way to unzip these files as quick as possible from within Matlab? Thanks!

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  • Matlab - binary vector with high concentration of 1s (or 0s)

    - by JohnIdol
    What's the best way to generate a number X of random binary vectors of size N with concentration of 1s (or, simmetrically, of 0s) that spans from very low to very high? Using randint or unidrnd (as in this question) will generate binary vectors with uniform distributions, which is not what I need in this case. Any help appreciated!

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  • MATLAB: vectorized array creation from a list of start/end indices

    - by merv
    I have a two-column matrix M that contains the start/end indices of a bunch of intervals: startInd EndInd 1 3 6 10 12 12 15 16 How can I generate a vector of all the interval indices: v = [1 2 3 6 7 8 9 10 12 15 16]; I'm doing the above using loops, but I'm wondering if there's a more elegant vectorized solution? v = []; for i=1:size(M,1) v = [v M(i,1):M(i,2)]; end

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  • Numerical Integration of a vector in matlab?

    - by clowny
    Hello all! Well i have an issue. I have a vector of 358 numbers. I'd like to make a numerical integration of this vector, but i don't know the function of this one. I found that we can use trapz or quad, but i don't really understand how to integrate without the function. Thanx for any help!

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  • Replace empty cells with logical 0's before cell2mat in MATLAB

    - by Doresoom
    I've got a cell array of empty cells and ones that I want to convert to a logical array, where the empty cells are zeros. When I use cell2mat, the empty cells are ignored, and I end up with a matrix of solely 1's, with no reference to the previous index they held. Is there a way to perform this operation without using loops? Example code: for n=1:5 %generate sample cell array mycellarray{n}=1; end mycellarray{2}=[] %remove one value for testing Things I've tried: mylogicalarray=logical(cell2mat(mycellarray)); which results in [1,1,1,1], not [1,0,1,1,1]. for n=1:length(mycellarray) if isempty(mycellarray{n}) mycellarray{n}=0; end end mylogicalarray=logical(cell2mat(mycellarray)); which works, but uses loops.

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  • Matlab Simulink: Transfer Function

    - by stanigator
    I am trying to model a transfer function block for let's say 1/(s+1). I am having a hard time coming up with proper search terms for it, hence having trouble finding out how I can achieve this on the Internet. What is the easiest way to implement a block for a transfer function in Simulink? Thanks in advance.

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  • Typecast to an int in Octave/Matlab

    - by Leif Andersen
    I need to call the index of a matrix made using the linspace command, and based on somde data taken from an oscilloscope. Because of this, the data inputed is a double. However, I can't really call: Time[V0Found] where V0Found is something like 5.2 however, taking index 5 is close enough, so I need to drop the decimal. I used this equation to drop the decimal: V0FoundDec = V0Found - mod(V0Found,1) Time[V0FoundDec] However, eve though that drops the decimal, octave still complains about it. So, what can I do to typecast it to an int? Thank you.

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