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  • Adding the sum of numbers using a loop statement

    - by Deonna
    I need serious help dividing the positive numbers and the negative numbers. I am to accumulate the total of the negative values and separately accumulate the total of the positive values. After the loop, you are then to display the sum of the negative values and the sum of the positive values. The data is suppose to look like this: -2.3 -1.9 -1.5 -1.1 -0.7 -0.3 0.1 0.5 0.9 1.3 1.7 2.1 2.5 2.9 Sum of negative values: -7.8 Sum of positive values: 12 So far I have this: int main () { int num, num2, num3, num4, num5, sum, count, sum1; int tempVariable = 0; int numCount = 100; int newlineCount = 0, newlineCount1 = 0; float numCount1 = -2.3; while (numCount <= 150) { cout << numCount << " "; numCount += 2; newlineCount ++; if(newlineCount == 6) { cout<< " " << endl; newlineCount = 0; } } **cout << "" << endl; while (numCount1 <=2.9 ) { cout << numCount1 << " "; numCount1 += 0.4; newlineCount1 ++; } while ( newlineCount1 <= 0 && newlineCount >= -2.3 ); cout << "The sum is " << newlineCount1 << endl;** return 0; }

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  • scheme basic loop

    - by utku
    I'm trying to write a scheme func that behaves in a way similar to a loop. (loop min max func) This loop should perform the func between the range min and max (integers) -- one of an example like this (loop 3 6 (lambda (x) (display (* x x)) (newline))) 9 16 25 36 and I define the function as ( define ( loop min max fn) (cond ((>= max min) ( ( fn min ) ( loop (+ min 1 ) max fn) ) ) ) ) when I run the code I get the result then an error occur. I couldn't handle this error. (loop 3 6 (lambda (x) (display(* x x))(newline))) 9 16 25 36 Backtrace: In standard input: 41: 0* [loop 3 6 #] In utku1.scheme: 9: 1 (cond ((= max min) ((fn min) (loop # max fn)))) 10: 2 [# ... 10: 3* [loop 4 6 #] 9: 4 (cond ((= max min) ((fn min) (loop # max fn)))) 10: 5 [# ... 10: 6* [loop 5 6 #] 9: 7 (cond ((= max min) ((fn min) (loop # max fn)))) 10: 8 [# ... 10: 9* [loop 6 6 #] 9: 10 (cond ((= max min) ((fn min) (loop # max fn)))) 10: 11 [# #] utku1.scheme:10:31: In expression ((fn min) (loop # max ...)): utku1.scheme:10:31: Wrong type to apply: #<unspecified> ABORT: (misc-error)

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  • While loop in foreach loop not looping correctly

    - by tominated
    I'm trying to make a very basic php ORM as for a school project. I have got almost everything working, but I'm trying to map results to an array. Here's a snippet of code to hopefully assist my explanation. $results = array(); foreach($this->columns as $column){ $current = array(); while($row = mysql_fetch_array($this->results)){ $current[] = $row[$column]; print_r($current); echo '<br><br>'; } $results[$column] = $current; } print_r($results); return mysql_fetch_array($this->results); This works, but the while loop only works on the first column. The print_r($results); shows the following: Array ( [testID] => Array ( [0] => 1 [1] => 2 ) [testName] => Array ( ) [testData] => Array ( ) ) Can anybody shed some light? Thanks in advance!

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  • loop html table using jquery and for loop (not for each)

    - by Mandeep Singh
    I have a HTML table <table id="mytab"> <thead> <th>col1</th> <th>col2</th> </thead> <tbody> <tr> <td>1</td> <td>2</td> </tr> <tr> <td>11</td> <td>22</td> </tbody> </table> and i am writing the jquery function function LoopTable() { $row = $('#mytab tbody >tr"); //here I have successfully find all the rows. //now i want to loop on rows and find each column row for (var i=0; i<$rows.length; i++) { //need something here to find col data } what I should use to have column values from row

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  • Creating new image in a loop using OpenCV

    - by user565415
    I am programing some image conversion code with OpenCV and I don't know how can I create image memory buffer to load image on every iteration. I have number of iteration (maxImNumber) and I have an input image. In every loop program must create image that is resized and modified input image. Here is some basic code (concept). for (int imageIndex = 0; imageIndex < maxImNumber; imageIndex++){ cvCopy(inputImage, images[imageIndex], 0); cvReleaseImage(&inputImage); images[imageIndex+1] = cvCreateImage(cvSize((image[imageIndex]->width)/2, image[imageIndex]->height), IPL_DEPTH_8U, 1); for (i=1; i < image[imageIndex]->height; i++) { index = 0; // for(j=0; j < image[imageIndex]->width ; j=j+2){ // doing some basic matematical operation on image content and store it to new image images[imageIndex+1][i][index] = (image[imageIndex][i][j] + image[imageIndex][i][j+2])/2; index++ } } inputImage = cvCreateImage(cvSize((image[imageIndex+1]->width), image[imageIndex]->height), IPL_DEPTH_8U, 1); cvCopy(images[imageIndex+1], inputImage, 0); } Can somebody, please, explain how can I create this image buffer (images[]) and allocate memory for it. Also how can I access any image in this buffer? Thank you very much in advance!

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  • SQL SERVER – Running Multiple Batch Files Together in Parallel

    - by pinaldave
    Recently I was preparing a demo for my next technical session, I had to do run a SQL code in parallel. I decided to use Batch File to run the code. I am not the best guy to with command shell so I did it with following setup. Code of tsql.sql SELECT 1 ColumnName Code of command.bat sqlcmd -S . -i tsql.sql timeout 100 Code of  AllBatch.bat start cmd.exe /C “command.bat” start cmd.exe /C “command.bat” start cmd.exe /C “command.bat” Now I ran AllBatch.bat and it run all the three files in parallel and simulated my needed scenario. I believe there should be simpler way using power-shell. Anybody want to come up with equivalent code which is improvement to this code? Reference: Pinal Dave (http://blog.SQLAuthority.com) Filed under: Pinal Dave, PostADay, SQL, SQL Authority, SQL Query, SQL Scripts, SQL Server, SQL Tips and Tricks, SQL Utility, T SQL, Technology

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  • Links from UK TechDays 2010 sessions on Entity Framework, Parallel Programming and Azure

    - by Eric Nelson
    [I will do some longer posts around my sessions when I get back from holiday next week] Big thanks to all those who attended my 3 sessions at TechDays this week (April 13th and 14th, 2010). I really enjoyed both days and watched some great session – my personal fave being the Silverlight/Expression session by my friend and colleague Mike Taulty. The following links should help get you up and running on each of the technologies. Entity Framework 4 Entity Framework 4 Resources http://bit.ly/ef4resources Entity Framework Team Blog http://blogs.msdn.com/adonet Entity Framework Design Blog http://blogs.msdn.com/efdesign/ Parallel Programming Parallel Computing Developer Center http://msdn.com/concurrency Code samples http://code.msdn.microsoft.com/ParExtSamples Managed Team Blog http://blogs.msdn.com/pfxteam Tools Team Blog http://blogs.msdn.com/visualizeparallel My code samples http://gist.github.com/364522  And PDC 2009 session recordings to watch: Windows Azure Platform UK Site http://bit.ly/landazure UK Community http://bit.ly/ukazure (http://ukazure.ning.com ) Feedback www.mygreatwindowsazureidea.com Azure Diagnostics Manager - A client for Windows Azure Diagnostics Cloud Storage Studio - A client for Windows Azure Storage SQL Azure Migration Wizard http://sqlazuremw.codeplex.com

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  • Graphic card for parallel programming vs traditional methods

    - by Sambatyon
    With a simple search in amazon one can see that the modern approach for parallel programming is to use your graphic card. However I am still a little bit skeptical about it. My last computer has an 8 core CPU which I need is enough for basic all my parallel needs, if I need more I will probably use MPI through a network using my old machines. All in all, Why and/or when should I use CUDA or another method which uses my graphic card instead of traditional methods like pthreads, java threads, boost threads or the new C++ 11 threads? What about using processes?

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  • Infinite loop when using fscanf

    - by user1409641
    I wrote this simple program in C, because I'm studying FILES right now at University. I take a txt file with a list of the results of the last race so my program will show the data formatted as I want. Here's my code: /* Esercizio file Motogp */ #include <stdio.h> #define SIZE 20 int main () { int pos, punt, num; float kmh; char nome[SIZE+1], cognome[SIZE+1], moto[SIZE+1]; char naz[SIZE+1], nome_file[SIZE+1]; FILE *fp; printf ("Inserisci il nome del file da aprire: "); gets (nome_file); fp = fopen (nome_file, "r"); if (fopen == NULL) printf ("Errore nell' apertura del file %s\n", nome_file); else { while (fscanf (fp, "%d %d %d %s %s %s %s %.2f", &pos, &punt, &num, nome, cognome, naz, moto, &kmh) != EOF ) { printf ("Posizione di arrivo: %d\n", pos); printf ("Punteggio: %d\n", punt); printf ("Numero pilota: %d\n", num); printf ("Nome pilota: %s\n", nome); printf ("Cognome pilota: %s\n", cognome); printf ("Nazione: %s\n", naz); printf ("Moto: %s\n", moto); printf ("Media Kmh: %d\n\n", kmh); } } fclose(fp); return 0; } and there's my txt file: 1 25 99 Jorge LORENZO SPA Yamaha 164.4 2 20 26 Dani PEDROSA SPA Honda 164.1 3 16 4 Andrea DOVIZIOSO ITA Yamaha 163.8 4 13 1 Casey STONER AUS Honda 163.8 5 11 35 Cal CRUTCHLOW GBR Yamaha 163.6 6 10 19 Alvaro BAUTISTA SPA Honda 163.5 7 9 46 Valentino ROSSI ITA Ducati 163.3 8 8 6 Stefan BRADL GER Honda 162.9 9 7 69 Nicky HAYDEN USA Ducati 162.5 10 6 11 Ben SPIES USA Yamaha 162.3 11 5 8 Hector BARBERA SPA Ducati 162.1 12 4 17 Karel ABRAHAM CZE Ducati 160.9 13 3 41 Aleix ESPARGARO SPA ART 160.2 14 2 51 Michele PIRRO ITA FTR 160.1 15 1 14 Randy DE PUNIET FRA ART 160.0 16 0 77 James ELLISON GBR ART 159.9 17 0 54 Mattia PASINI ITA ART 159.4 18 0 68 Yonny HERNANDEZ COL BQR 159.4 19 0 9 Danilo PETRUCCI ITA Ioda 158.2 20 0 22 Ivan SILVA SPA BQR 158.2 When I run my program, it return me an infinite loop of the first one. Why? Is there another function to read those data?

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  • ForEach loop: Output something different on every second result

    - by Wade D Ouellet
    I have two for each loops and I am trying to output something different for each second result: foreach ($wppost as $wp) { $wp_title = $wp->post_title; $wp_date = strtotime($wp->post_date); $wp_slug = $wp->post_name; $wp_id = $wp->ID; // Start Permalink Template $wp_showurl = $wp_url; $wp_showurl = str_replace("%year%", date('Y', $wp_date), $wp_showurl); $wp_showurl = str_replace("%monthnum%", date('m', $wp_date), $wp_showurl); $wp_showurl = str_replace("%day%", date('d', $wp_date), $wp_showurl); $wp_showurl = str_replace("%hour%", date('H', $wp_date), $wp_showurl); $wp_showurl = str_replace("%minute%", date('i', $wp_date), $wp_showurl); $wp_showurl = str_replace("%second%", date('s', $wp_date), $wp_showurl); $wp_showurl = str_replace("%postname%", $wp_slug, $wp_showurl); $wp_showurl = str_replace("%post_id%", $wp_id, $wp_showurl); // Stop Permalink Template $wp_posturl = $blog_address . $wp_showurl; echo '<li><a href="'.$wp_posturl.'" title="'.$wp_title.'">'.$wp_title.'</a></li>'; } For this one I want it to echo li class="even" instead of just li for each second result. I think this will have to be changed to a for loop to accomplished this but I am not sure how that is done without breaking it. Exact same for this one: if(is_array($commenters)) { foreach ($commenters as $k) { ?><li><?php if($ns_options["make_links"] == 1) { $url = ns_get_user_url($k->poster_id); if(trim($url) != '') { echo "<a href='" . $url . "'>"; } } if($ns_options["make_links"] == 2) { $url = ns_get_user_profile($k->poster_id); echo "<a href='" . $url . "'>"; } $name = $bbdb->get_var(" SELECT user_login FROM $bbdb->users WHERE ID = $k->poster_id"); echo ns_substr_ellipse($name, $ns_options["name_limit"]); if(trim($url) != '' && $ns_options["make_links"] == 1) { echo "</a>"; } if($ns_options["make_links"] == 2) { echo "</a>"; } if ($ns_options["show_posts"] == 1) { echo " (" . $k->num_posts . ")\n"; } echo $ns_options["end_html"] . "\n"; unset($url); } } else { ?></li><?php } Thanks, Wade

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  • For loop from assembly to C

    - by FranXh
    I have a bomb project where I need to defuse certain phases by finding "pas phrases" that will defuse the bomb. Right now I have been working with phase_2, for which the assembly code is shown below. Phase_2 requires as an input 6 numbers, which I need to find in order to defuse this phase. I analyzed this assembly, and I came up with the C code below, that covers lines from 40101c to 401044. It is basically a for loop that makes sure that elements t[0]==t[3], t[1]==t[4] and t[2]==t[5] that the user inputs, are equal. According to my logic, the user can input any 6 numbers as long as the above condition is satisfied. Say 1, 2, 3, 1, 2, 3 would be a valid "pas phrase". However this solution does not convince me for some reason. Am I doing something wrong? 0000000000400ffc <phase_2>: 400ffc: 48 89 5c 24 e0 mov %rbx,-0x20(%rsp) 401001: 48 89 6c 24 e8 mov %rbp,-0x18(%rsp) 401006: 4c 89 64 24 f0 mov %r12,-0x10(%rsp) 40100b: 4c 89 6c 24 f8 mov %r13,-0x8(%rsp) 401010: 48 83 ec 48 sub $0x48,%rsp 401014: 48 89 e6 mov %rsp,%rsi 401017: e8 65 0a 00 00 callq 401a81 <read_six_numbers> 40101c: 48 89 e5 mov %rsp,%rbp 40101f: 4c 8d 6c 24 0c lea 0xc(%rsp),%r13 401024: 41 bc 00 00 00 00 mov $0x0,%r12d 40102a: 48 89 eb mov %rbp,%rbx 40102d: 8b 45 0c mov 0xc(%rbp),%eax 401030: 39 45 00 cmp %eax,0x0(%rbp) 401033: 74 05 je 40103a <phase_2+0x3e> 401035: e8 2d 09 00 00 callq 401967 <_GLOBAL_RESET_> 40103a: 44 03 23 add (%rbx),%r12d 40103d: 48 83 c5 04 add $0x4,%rbp 401041: 4c 39 ed cmp %r13,%rbp 401044: 75 e4 jne 40102a <phase_2+0x2e> 401046: 45 85 e4 test %r12d,%r12d 401049: 75 05 jne 401050 <phase_2+0x54> 40104b: e8 17 09 00 00 callq 401967 <_GLOBAL_RESET_> 401050: 48 8b 5c 24 28 mov 0x28(%rsp),%rbx 401055: 48 8b 6c 24 30 mov 0x30(%rsp),%rbp 40105a: 4c 8b 64 24 38 mov 0x38(%rsp),%r12 40105f: 4c 8b 6c 24 40 mov 0x40(%rsp),%r13 401064: 48 83 c4 48 add $0x48,%rsp 401068: c3 for (int i=0; i<3; i++){ if(t[i] != t[i+3]){ explode(); } }

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  • Why wont my while loop take new input (c++)

    - by Van
    I've written a program to get a string input from a user and parse it into tokens and move a robot according to the input. My problem is trying to issue more than one command. The code looks like: void Navigator::manualDrive() { const int bufSize = 42; char uinput[bufSize]; char delim[] = " "; char *token; while(true) { Navigator::parseInstruction(uinput); } } /* parseInstruction(char *c) -- parses cstring instructions received * and moves robot accordingly */ void Navigator::parseInstruction(char * c) { const int bufSize = 42; char uinput[bufSize]; char delim[] = " "; char *token; cout << "Enter your directions below: \n"; cin.ignore(); cin.getline (uinput, bufSize); token=strtok(uinput, delim); if(strcmp("forward", token) == 0) { int inches; token = strtok(NULL, delim); inches = atoi (token); Navigator::travel(inches); } if(strcmp("back",token) == 0) { int inches; token = strtok(NULL, delim); inches = atoi (token); double value = fabs(0.0735 * fabs(inches) - 0.0550); myRobot.backward(1/*speed*/, value/*time*/); } if(strcmp("turn",token) == 0) { int degrees; token = strtok(NULL, delim); if(strcmp("left",token) == 0) { token = strtok(uinput, delim); degrees = atoi (token); double value = fabs(0.0041 * degrees - 0.0523); myRobot.turnLeft(1/*speed*/, value/*time*/); } } if(strcmp("turn",token) == 0) { int degrees; token = strtok(NULL, delim); if(strcmp("right",token) == 0) { token = strtok(uinput, delim); degrees = atoi (token); double value = fabs(0.0041 * degrees - 0.0523); myRobot.turnRight(1/*speed*/, value/*time*/); } } if(strcmp("stop",token) == 0) { myRobot.motors(0,0); } } In the function manualDrive I have a while loop calling the function parseInstruction infinitely. The program outputs "Enter your directions below: " When I give the program instructions it executes them, and then it outputs "enter your directions below: " again and when I input my directions again it does not execute them and outputs "Enter your directions below: " instead. I'm sure this is a very simple fix I'm just very new to c++. So if you could please help me out and tell me why the program only takes the first set of directions. thanks

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  • Why wont my while loop wont take new input (c++)

    - by Van
    I've written a program to get a string input from a user and parse it into tokens and move a robot according to the input. My problem is trying to issue more than one command. The code looks like: void Navigator::manualDrive() { const int bufSize = 42; char uinput[bufSize]; char delim[] = " "; char *token; while(true) { Navigator::parseInstruction(uinput); } } /* parseInstruction(char *c) -- parses cstring instructions received * and moves robot accordingly */ void Navigator::parseInstruction(char * c) { const int bufSize = 42; char uinput[bufSize]; char delim[] = " "; char *token; cout << "Enter your directions below: \n"; cin.ignore(); cin.getline (uinput, bufSize); token=strtok(uinput, delim); if(strcmp("forward", token) == 0) { int inches; token = strtok(NULL, delim); inches = atoi (token); Navigator::travel(inches); } if(strcmp("back",token) == 0) { int inches; token = strtok(NULL, delim); inches = atoi (token); double value = fabs(0.0735 * fabs(inches) - 0.0550); myRobot.backward(1/*speed*/, value/*time*/); } if(strcmp("turn",token) == 0) { int degrees; token = strtok(NULL, delim); if(strcmp("left",token) == 0) { token = strtok(uinput, delim); degrees = atoi (token); double value = fabs(0.0041 * degrees - 0.0523); myRobot.turnLeft(1/*speed*/, value/*time*/); } } if(strcmp("turn",token) == 0) { int degrees; token = strtok(NULL, delim); if(strcmp("right",token) == 0) { token = strtok(uinput, delim); degrees = atoi (token); double value = fabs(0.0041 * degrees - 0.0523); myRobot.turnRight(1/*speed*/, value/*time*/); } } if(strcmp("stop",token) == 0) { myRobot.motors(0,0); } } In the function manualDrive I have a while loop calling the function parseInstruction infinitely. The program outputs "Enter your directions below: " When I give the program instructions it executes them, and then it outputs "enter your directions below: " again and when I input my directions again it does not execute them and outputs "Enter your directions below: " instead. I'm sure this is a very simple fix I'm just very new to c++. So if you could please help me out and tell me why the program only takes the first set of directions. thanks

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  • C++: Trouble with Pointers, loop variables, and structs

    - by Rosarch
    Consider the following example: #include <iostream> #include <sstream> #include <vector> #include <wchar.h> #include <stdlib.h> using namespace std; struct odp { int f; wchar_t* pstr; }; int main() { vector<odp> vec; ostringstream ss; wchar_t base[5]; wcscpy_s(base, L"1234"); for (int i = 0; i < 4; i++) { odp foo; foo.f = i; wchar_t loopStr[1]; foo.pstr = loopStr; // wchar_t* = wchar_t ? Why does this work? foo.pstr[0] = base[i]; vec.push_back(foo); } for (vector<odp>::iterator iter = vec.begin(); iter != vec.end(); iter++) { cout << "Vec contains: " << iter->f << ", " << *(iter->pstr) << endl; } } This produces: Vec contains: 0, 52 Vec contains: 1, 52 Vec contains: 2, 52 Vec contains: 3, 52 I would hope that each time, iter->f and iter->pstr would yield a different result. Unfortunately, iter->pstr is always the same. My suspicion is that each time through the loop, a new loopStr is created. Instead of copying it into the struct, I'm only copying a pointer. The location that the pointer writes to is getting overwritten. How can I avoid this? Is it possible to solve this problem without allocating memory on the heap?

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  • javascript won't execute nested for loop

    - by mcdwight6
    thanks in advance for all your help! i'm fairly new to javascript, but i have a fairly strong background in java, so i thought i would try it out on this project i'm working on. essentially, what i'm trying to do is read data from an xml file and create the html code for the page i'm making. i used the script from w3schools found here. I've altered it and gotten it to pull the data from my own xml and even to do the more basic generation of the html code i need. Here's the html i'm using inside <script> tags: var s = swDoc.getElementsByTagName("planet"); var plShowsArr = s[i].getElementsByTagName("show"); var plGamesArr = s[i].getElementsByTagName("videoGame"); for (i=0;i<s.length;i++) { // test section all works document.write("<div><table border = \"1\">"); document.write("<tr><td>"+ s[i].getElementsByTagName("showText")[0].childNodes[0].nodeValue + "</td><td>" + s[i].getElementsByTagName("showUrl")[0].childNodes[0].nodeValue + "</td></tr>"); document.write("<tr><td>" + s[i].getElementsByTagName("gameText")[0].childNodes[0].nodeValue + "</td><td>" + s[i].getElementsByTagName("gameUrl")[0].childNodes[0].nodeValue + "</td></tr>"); document.write("</tr></table></div>"); // end test section document.write("<div class=\"appearances-row\"><ol class=\"shows\">shows list"); for(j=0;j<plShows.length;j++){ document.write("nested for"); var showUrl = s[i].getElementsByTagName("showUrl")[j].childNodes[0].nodeValue; var showText = s[i].getElementByTagName("showText")[j].childNodes[0].nodeValue; document.write("<li><a href=\""+showUrl+"\">"+showText+"</a></li>"); } the code breaks at the nested for loop at the end, where it finished the document.write and prints "shows list" to the page, but then never gets to the document.write inside. if it helps, the xml contains a list of planets from the star wars universe organized like this: <planets> <planet> <planetName>planet</planetName> <description>some text</description> <appearances> <show> <showUrl>url</showUrl> <showText>hyperlink text</showText> </show> <videoGame> <gameUrl>url</gameUrl> <gameText>hyperlink text</gameText> </videoGame> </appearances> <locationsOfInterest> <location>location name</location> </locationsOfInterest> <famousCharactersRelatedTo> <character>a character</character> </famousCharactersRelatedTo> <externalLinks> <link> <linkUrl>url</linkUrl> <linkText>hyperlink text</linkText> </link> </externalLinks> </planet>

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  • ASM programming, how to use loop?

    - by chris
    Hello. Im first time here.I am a college student. I've created a simple program by using assembly language. And im wondering if i can use loop method to run it almost samething as what it does below the program i posted. and im also eager to find someome who i can talk through MSN messanger so i can ask you questions right away.(if possible) ok thank you .MODEL small .STACK 400h .data prompt db 10,13,'Please enter a 3 digit number, example 100:',10,13,'$' ;10,13 cause to go to next line first_digit db 0d second_digit db 0d third_digit db 0d Not_prime db 10,13,'This number is not prime!',10,13,'$' prime db 10,13,'This number is prime!',10,13,'$' question db 10,13,'Do you want to contine Y/N $' counter dw 0d number dw 0d half dw ? .code Start: mov ax, @data ;establish access to the data segment mov ds, ax mov number, 0d LetsRoll: mov dx, offset prompt ; print the string (please enter a 3 digit...) mov ah, 9h int 21h ;execute ;read FIRST DIGIT mov ah, 1d ;bios code for read a keystroke int 21h ;call bios, it is understood that the ascii code will be returned in al mov first_digit, al ;may as well save a copy sub al, 30h ;Convert code to an actual integer cbw ;CONVERT BYTE TO WORD. This takes whatever number is in al and ;extends it to ax, doubling its size from 8 bits to 16 bits ;The first digit now occupies all of ax as an integer mov cx, 100d ;This is so we can calculate 100*1st digit +10*2nd digit + 3rd digit mul cx ;start to accumulate the 3 digit number in the variable imul cx ;it is understood that the other operand is ax ;AND that the result will use both dx::ax ;but we understand that dx will contain only leading zeros add number, ax ;save ;variable <number> now contains 1st digit * 10 ;---------------------------------------------------------------------- ;read SECOND DIGIT, multiply by 10 and add in mov ah, 1d ;bios code for read a keystroke int 21h ;call bios, it is understood that the ascii code will be returned in al mov second_digit, al ;may as well save a copy sub al, 30h ;Convert code to an actual integer cbw ;CONVERT BYTE TO WORD. This takes whatever number is in al and ;extends it to ax, boubling its size from 8 bits to 16 bits ;The first digit now occupies all of ax as an integer mov cx, 10d ;continue to accumulate the 3 digit number in the variable mul cx ;it is understood that the other operand is ax, containing first digit ;AND that the result will use both dx::ax ;but we understand that dx will contain only leading zeros. Ignore them add number, ax ;save -- nearly finished ;variable <number> now contains 1st digit * 100 + second digit * 10 ;---------------------------------------------------------------------- ;read THIRD DIGIT, add it in (no multiplication this time) mov ah, 1d ;bios code for read a keystroke int 21h ;call bios, it is understood that the ascii code will be returned in al mov third_digit, al ;may as well save a copy sub al, 30h ;Convert code to an actual integer cbw ;CONVERT BYTE TO WORD. This takes whatever number is in al and ;extends it to ax, boubling its size from 8 bits to 16 bits ;The first digit now occupies all of ax as an integer add number, ax ;Both my variable number and ax are 16 bits, so equal size mov ax, number ;copy contents of number to ax mov cx, 2h div cx ;Divide by cx mov half, ax ;copy the contents of ax to half mov cx, 2h; mov ax, number; ;copy numbers to ax xor dx, dx ;flush dx jmp prime_check ;jump to prime check print_question: mov dx, offset question ;print string (do you want to continue Y/N?) mov ah, 9h int 21h ;execute mov ah, 1h int 21h ;execute cmp al, 4eh ;compare je Exit ;jump to exit cmp al, 6eh ;compare je Exit ;jump to exit cmp al, 59h ;compare je Start ;jump to start cmp al, 79h ;compare je Start ;jump to start prime_check: div cx; ;Divide by cx cmp dx, 0h ;reset the value of dx je print_not_prime ;jump to not prime xor dx, dx; ;flush dx mov ax, number ;copy the contents of number to ax cmp cx, half ;compare half with cx je print_prime ;jump to print prime section inc cx; ;increment cx by one jmp prime_check ;repeat the prime check print_prime: mov dx, offset prime ;print string (this number is prime!) mov ah, 9h int 21h ;execute jmp print_question ;jumps to question (do you want to continue Y/N?) this is for repeat print_not_prime: mov dx, offset Not_prime ;print string (this number is not prime!) mov ah, 9h int 21h ;execute jmp print_question ;jumps to question (do you want to continue Y/N?) this is for repeat Exit: mov ah, 4ch int 21h ;execute exit END Start

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  • Java style FOR loop in a clojure interpeter ?

    - by Kevin
    I have a basic interpreter in clojure. Now i need to implement for (initialisation; finish-test; loop-update) { statements } inside my interpreter. I will attach my interpreter code I got so far. Any help is appreciated. Interpreter (declare interpret make-env) ;; (def do-trace false) ;; ;; simple utilities (def third ; return third item in a list (fn [a-list] (second (rest a-list)))) (def fourth ; return fourth item in a list (fn [a-list] (third (rest a-list)))) (def run ; make it easy to test the interpreter (fn [e] (println "Processing: " e) (println "=> " (interpret e (make-env))))) ;; for the environment (def make-env (fn [] '())) (def add-var (fn [env var val] (cons (list var val) env))) (def lookup-var (fn [env var] (cond (empty? env) 'error (= (first (first env)) var) (second (first env)) :else (lookup-var (rest env) var)))) ;; -- define numbers (def is-number? (fn [expn] (number? expn))) (def interpret-number (fn [expn env] expn)) ;; -- define symbols (def is-symbol? (fn [expn] (symbol? expn))) (def interpret-symbol (fn [expn env] (lookup-var env expn))) ;; -- define boolean (def is-boolean? (fn [expn] (or (= expn 'true) (= expn 'false)))) (def interpret-boolean (fn [expn env] expn)) ;; -- define functions (def is-function? (fn [expn] (and (list? expn) (= 3 (count expn)) (= 'lambda (first expn))))) (def interpret-function (fn [expn env] expn)) ;; -- define addition (def is-plus? (fn [expn] (and (list? expn) (= 3 (count expn)) (= '+ (first expn))))) (def interpret-plus (fn [expn env] (+ (interpret (second expn) env) (interpret (third expn) env)))) ;; -- define subtraction (def is-minus? (fn [expn] (and (list? expn) (= 3 (count expn)) (= '- (first expn))))) (def interpret-minus (fn [expn env] (- (interpret (second expn) env) (interpret (third expn) env)))) ;; -- define multiplication (def is-times? (fn [expn] (and (list? expn) (= 3 (count expn)) (= '* (first expn))))) (def interpret-times (fn [expn env] (* (interpret (second expn) env) (interpret (third expn) env)))) ;; -- define division (def is-divides? (fn [expn] (and (list? expn) (= 3 (count expn)) (= '/ (first expn))))) (def interpret-divides (fn [expn env] (/ (interpret (second expn) env) (interpret (third expn) env)))) ;; -- define equals test (def is-equals? (fn [expn] (and (list? expn) (= 3 (count expn)) (= '= (first expn))))) (def interpret-equals (fn [expn env] (= (interpret (second expn) env) (interpret (third expn) env)))) ;; -- define greater-than test (def is-greater-than? (fn [expn] (and (list? expn) (= 3 (count expn)) (= '> (first expn))))) (def interpret-greater-than (fn [expn env] (> (interpret (second expn) env) (interpret (third expn) env)))) ;; -- define not (def is-not? (fn [expn] (and (list? expn) (= 2 (count expn)) (= 'not (first expn))))) (def interpret-not (fn [expn env] (not (interpret (second expn) env)))) ;; -- define or (def is-or? (fn [expn] (and (list? expn) (= 3 (count expn)) (= 'or (first expn))))) (def interpret-or (fn [expn env] (or (interpret (second expn) env) (interpret (third expn) env)))) ;; -- define and (def is-and? (fn [expn] (and (list? expn) (= 3 (count expn)) (= 'and (first expn))))) (def interpret-and (fn [expn env] (and (interpret (second expn) env) (interpret (third expn) env)))) ;; -- define with (def is-with? (fn [expn] (and (list? expn) (= 3 (count expn)) (= 'with (first expn))))) (def interpret-with (fn [expn env] (interpret (third expn) (add-var env (first (second expn)) (interpret (second (second expn)) env))))) ;; -- define if (def is-if? (fn [expn] (and (list? expn) (= 4 (count expn)) (= 'if (first expn))))) (def interpret-if (fn [expn env] (cond (interpret (second expn) env) (interpret (third expn) env) :else (interpret (fourth expn) env)))) ;; -- define function-application (def is-function-application? (fn [expn env] (and (list? expn) (= 2 (count expn)) (is-function? (interpret (first expn) env))))) (def interpret-function-application (fn [expn env] (let [function (interpret (first expn) env)] (interpret (third function) (add-var env (first (second function)) (interpret (second expn) env)))))) ;; the interpreter itself (def interpret (fn [expn env] (cond do-trace (println "Interpret is processing: " expn)) (cond ; basic values (is-number? expn) (interpret-number expn env) (is-symbol? expn) (interpret-symbol expn env) (is-boolean? expn) (interpret-boolean expn env) (is-function? expn) (interpret-function expn env) ; built-in functions (is-plus? expn) (interpret-plus expn env) (is-minus? expn) (interpret-minus expn env) (is-times? expn) (interpret-times expn env) (is-divides? expn) (interpret-divides expn env) (is-equals? expn) (interpret-equals expn env) (is-greater-than? expn) (interpret-greater-than expn env) (is-not? expn) (interpret-not expn env) (is-or? expn) (interpret-or expn env) (is-and? expn) (interpret-and expn env) ; special syntax (is-with? expn) (interpret-with expn env) (is-if? expn) (interpret-if expn env) ; functions (is-function-application? expn env) (interpret-function-application expn env) :else 'error)))

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  • perl multiple tasks problem

    - by Alice Wozownik
    I have finished my earlier multithreaded program that uses perl threads and it works on my system. The problem is that on some systems that it needs to run on, thread support is not compiled into perl and I cannot install additional packages. I therefore need to use something other than threads, and I am moving my code to using fork(). This works on my windows system in starting the subtasks. A few problems: How to determine when the child process exits? I created new threads when the thread count was below a certain value, I need to keep track of how many threads are running. For processes, how do I know when one exits so I can keep track of how many exist at the time, incrementing a counter when one is created and decrementing when one exits? Is file I/O using handles obtained with OPEN when opened by the parent process safe in the child process? I need to append to a file for each of the child processes, is this safe on unix as well. Is there any alternative to fork and threads? I tried use Parallel::ForkManager, but that isn't installed on my system (use Parallel::ForkManager; gave an error) and I absolutely require that my perl script work on all unix/windows systems without installing any additional modules.

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  • Does JavaScript's for in loop iterate over methods?

    - by hekevintran
    In an article on yuiblog Douglas Crockford says that the for in statement will iterate over the methods of an object. Why does the following code not produce ["a", "b", "c", "d", "toString"]? Aren't .toString() and other methods members of my_obj? Object.prototype.toString = function(){return 'abc'} Object.prototype.d = 4; my_obj = { 'a':1, 'b':2, 'c':3 } a = [] for (var key in my_obj) { a.push(key) } console.log(a) // prints ["a", "b", "c", "d"]

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  • Back button loop with IFRAMES

    - by Tim Jackson
    In my (school) website we use Iframes to display class blogs (on blogger). This works well EXCEPT if the user then clicks on (say) a photo inside the iframe. Blogger (in this case) then displays the photo in the whole browser window and the back button loops; that is if the back button is hit, the browser (IE, FF, Chrome) stays on the same page. The only way out is for the user to jump back two pages (which many of our users don't know how to do). I've read a lot of posts on back buttons and iframes and there doesn't appear to be a simple solution. Bear in mind that I don't have control over the iframe content (so no embedded back buttons in the frame are possible). Ideas anyone?

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  • Walk/loop through an XSL key: how?

    - by krisvandenbergh
    Is there a way to walk-through a key and output all the values it contains? I though of it this way: <xsl:for-each select="key('kElement', '.')"> <li><xsl:value-of select="." /></li> </xsl:for-each> However, this does not work. I simply want to list all the values in a key for testing purposes. The question is simply: how can this be done?

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