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  • Classic asp comparison of comma separated lists

    - by Reiwoldt
    Hello, I have two comma separated lists:- 36,189,47,183,65,50 65,50,189,47 The question is how to compare the two in classic ASP in order to identify and return any values that exist in list 1 but that don't exist in list 2 bearing in mind that associative arrays aren't available. E.g., in the above example I would need the return value to be 36,183 Thanks

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  • Append to list of lists

    - by Joel
    Hello, I am trying to build a list of lists using the following code: list=3*[[]] Now I am trying to append a string to the list in position 0: list[0].append("hello") However, instead of receiving the list [ ["hello"] , [], [] ] I am receiving the list: [ ["hello"] ,["hello"] , ["hello"] ] Am I missing something? Thanks, Joel

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  • create a dict of lists from a string

    - by Chris Card
    I want to convert a string such as 'a=b,a=c,a=d,b=e' into a dict of lists {'a': ['b', 'c', 'd'], 'b': ['e']} in Python 2.6. My current solution is this: def merge(d1, d2): for k, v in d2.items(): if k in d1: if type(d1[k]) != type(list()): d1[k] = list(d1[k]) d1[k].append(v) else: d1[k] = list(v) return d1 record = 'a=b,a=c,a=d,b=e' print reduce(merge, map(dict,[[x.split('=')] for x in record.split(',')])) which I'm sure is unnecessarily complicated. Any better solutions?

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  • in Python find number of same elements in 2 lists

    - by John
    Hi, In Python if I have 2 lists say: l1 = ['a', 'b', 'c', 'd'] l2 = ['c', 'd', 'e'] is there a way to find out how many elements they have the same. In the case about it would be 2 (c and d) I know I could just do a nested loop but is there not a built in function like in php with the array_intersect function Thanks

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  • Need to try and count repeated lists within a list

    - by user1828603
    Im trying to count how many repeated lists there are inside a list. But it doesnt work the same way I could count repeated elements in just a list. Im fairly new to python, so apologies if it sounds too easy. this is what i did x= [["coffee", "cola", "juice" "tea" ],["coffee", "cola", "juice" "tea"] ["cola", "coffee", "juice" "tea" ]] dictt= {} for item in x: dictt[item]= dictt.get(item, 0) +1 return(dictt)

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  • Join a list of lists together into 1 list in Python

    - by dotty
    Hay All. I have a list which consists of many lists, here is an example [ [Obj, Obj, Obj, Obj], [Obj], [Obj], [ [Obj,Obj], [Obj,Obj,Obj] ] ] Is there a way to join all these items together as 1 list, so the output will be something like [Obj,Obj,Obj,Obj,Obj,Obj,Obj,Obj,Obj,Obj,Obj] Thanks

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  • Web Programming language for very large lists?

    - by behrk2
    Hello, In your experience, what is the best web programming language used to handle sorting and comparison of very large lists (ie tens of thousands of email addresses)? I am most familiar with PHP. I think that it could get the job done, but I'm unsure of other languages and if there might be a bettor suitor. Thanks!

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  • intiating lists in the constructor's initialization list

    - by bks
    i just moved from C to C++, and now work with lists. i have a class called "message", and i need to have a class called "line", which should have a list of messages in its properties. as i learned, the object's properties should be initialized in the constructor's initialization list, and i had the "urge" to initialize the messages list in addition to the rest of the properties (some strings and doubles). is that "urge" justified? does the list need to be initialized? thank you in advance

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  • MongoDB lists with paginations?

    - by Timmy
    for documents with lists with pagination, is it better to embed or use reference? im reading the custom type "SONManipulator" and it appears to transform every thing on retrieval, even the sub docs. i want to keep the list in the document sorted, should this impact anything?

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  • How does Python store lists internally?

    - by Mike Cooper
    How are lists in python stored internally? Is it an array? A linked list? Something else? Or does the interpreter guess at the right structure for each instance based on length, etc. If the question is implementation dependent, what about the classic CPython?

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  • Not Equal two Generic Lists

    - by David Johnson
    I have two generic lists, both containing different data, except 4 fields, which I want to compare to another list and find items that do not match in either list. I need to basically replace where it says equals below, with not equals! var unMatchedData = from liveLines in liveList join oldList in comapreSnapshotList on new {liveLines.ClientNo, liveLines.SequenceNo, liveLines.LineNo, liveLines.Text} equals new {oldList.ClientNo, oldList.SequenceNo, oldList.LineNo, oldList.Text} select new KNOWTXTS { ClientNo = liveLines.ClientNo, SequenceNo = liveLines.SequenceNo, LineNo = liveLines.LineNo, Text = liveLines.Text };

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  • classic asp comparison of comma seperated lists

    - by Reiwoldt
    Hello, I have two comma seperated lists:- 36,189,47,183,65,50 65, 50, 189, 47 the question is how to compare the two in classic ASP in order to identify and return any values that exist in list 1 but that don't exist in list 2 bearing in mind that associative arrays aren't available. e.g. in the above example I would need the return value to be 36,183 Thanks

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  • C# recursive programming with lists

    - by David Torrey
    I am working on a program where each item can hold an array of items (i'm making a menu, which has a tree-like structure) currently i have the items as a list, instead of an array, but I don't feel like I'm using it to its full potential to simplify code. I chose a list over a standard array because the interface (.add, .remove, etc...) makes a lot of sense. I have code to search through the structure and return the path of the name (i.e. Item.subitem.subsubitem.subsubsubitem). Below is my code: public class Item { //public Item[] subitem; <-- Array of Items public List<Item> subitem; // <-- List of Items public Color itemColor = Color.FromArgb(50,50,200); public Rectangle itemSize = new Rectangle(0,0,64,64); public Bitmap itemBitmap = null; public string itemName; public string LocateItem(string searchName) { string tItemName = null; //if the item name matches the search parameter, send it up) if (itemName == searchName) { return itemName; } if (subitem != null) { //spiral down a level foreach (Item tSearchItem in subitem) { tItemName = tSearchItem.LocateItem(searchName); if (tItemName != null) break; //exit for if item was found } } //do name logic (use index numbers) //if LocateItem of the subitems returned nothing and the current item is not a match, return null (not found) if (tItemName == null && itemName != searchName) { return null; } //if it's not the item being searched for and the search item was found, change the string and return it up if (tItemName != null && itemName != searchName) { tItemName.Insert(0, itemName + "."); //insert the parent name on the left --> TopItem.SubItem.SubSubItem.SubSubSubItem return tItemName; } //default not found return null; } } My question is if there is an easier way to do this with lists? I've been going back and forth in my head as to whether I should use lists or just an array. The only reason I have a list is so that I don't have to make code to resize the array each time I add or remove an item.

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  • How to remove certain lists from a list of lists using python?

    - by seaworthy
    I can not figure out why my code does not filter out lists from a predefined list. I am trying to remove specific list using the following code. data = [[1,1,1],[1,1,2],[1,2,1],[1,2,2],[2,1,1],[2,1,2],[2,2,1],[2,2,2]] data = [x for x in data if x[0] != 1 and x[1] != 1] print data My result: data = [[2, 2, 1], [2, 2, 2]] Expected result: data = [[1,2,1],[1,2,2],[2,1,1],[2,1,2],[2,2,1],[2,2,2]]

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  • Prolog returns Out = _G431 when it suppose to return a list of lists

    - by Mandah
    createSchedule([[math109]], fall, Out). [[cs485, cs485], [cs355, cs355, cs462, cs462, cs462], [cs345, cs345, cs352, cs352, cs352, cs362, cs362, cs362, cs396, cs396, cs396], [cs330, cs330, cs330], [cs255, cs255, cs255, cs268, cs268], [math114, cs245, cs245], [math112, cs145, cs146], [math109]] Out = _G431 this is what prolog returns and the list of lists is shown by using write(Out) in prolog. Any ideas why it is showing this? Thanks

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  • Trimming lists using a loop

    - by Vishal
    I have few lists like: a = [1, 2, 3, 4, 5] b = [4, 6, 5, 9, 2] c = [4, 7, 9, 1, 2] I want to trim all of them using a loop, instead of doing as below: a[-2:] b[-2:] c[-2:] I tried but got confused with pass by value or pass by reference fundamentals, looked into other questions as well but no help. Thanks

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  • error creating MS Exchange distribution list: Active directory response: 00000005: SecErr: DSID-031521D0

    - by BabakBani
    We've migrated a client from google apps to an MS Exchange 2010 SP2 on-premise setup. The setup /prepareAD went well, and the software was installed with the Administrator account. We've used the Exchange Management Console to setup mailboxes and had to google up the appropriate workarounds such as going into each users Advanced Security Settings and selecting "include inheritable permissions from this object's parents", and changing their logon-to from specific machines to "all computers" so that they can connect to Outlook Web Access, and in turn so their Outlook 2007-2010 clients can connect to Exchange. Sending and receiving emails are working well. Now that all this is in place, we can create Dynamic Distrubution Lists with no problem, but as soon as we try and create a DISTRIBUTION LIST, either in the EMC or the Exchange PowerShell, we get an error. As the error message in the powershell is more verbose, I include this if anyone can suggest how we remedy this: [PS] C:\Windows\system32new-DistributionGroup -Name 'projects' -SamAccountName 'projects' -Alias 'projects' Active Directory operation failed on DC.cppe.local. This error is not retriable. Additional information: Access is denied. Active directory response: 00000005: SecErr: DSID-031521D0, problem 4003 (INSUFF_ACCESS_RIGHTS), data 0 + CategoryInfo : NotSpecified: (0:Int32) [New-DistributionGroup], ADOperationException + FullyQualifiedErrorId : 1EA5CD3E,Microsoft.Exchange.Management.RecipientTasks.NewDistributionGroup

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  • Displaying music list using custom lists instead of array adapters

    - by Rahul Varma
    Hi, I have displayed the music list in a list view. The list is obtained from a website. I have done this using Arraylist. Now, i want to iterate the same program using custom lists and custom adapters instead of array list. The code i have written using array lists is... public class MusicListActivity extends Activity { MediaPlayer mp; File mediaFile; TextView tv; TextView albumtext; TextView artisttext; ArrayList<String> al=new ArrayList<String>(); //ArrayList<String> al=new ArrayList<String>(); ArrayList<String> node=new ArrayList<String>(); ArrayList<String> filepath=new ArrayList<String>(); ArrayList<String> imgal=new ArrayList<String>(); ArrayList<String> album=new ArrayList<String>(); ArrayList<String> artist=new ArrayList<String>(); ListView lv; Object[] webImgListObject; String[] stringArray; XMLRPCClient client; String loginsess; HashMap<?, ?> siteConn = null; //ImageView im; Bitmap img; String s; int d; int j; StreamingMediaPlayer sm; int start=0; Intent i; @Override protected void onCreate(Bundle savedInstanceState) { // TODO Auto-generated method stub super.onCreate(savedInstanceState); setContentView(R.layout.openadiuofile); lv=(ListView)findViewById(R.id.list1); al=getIntent().getStringArrayListExtra("titles"); //node=getIntent().getStringArrayListExtra("nodeid"); filepath=getIntent().getStringArrayListExtra("apath"); imgal=getIntent().getStringArrayListExtra("imgpath"); album=getIntent().getStringArrayListExtra("album"); artist=getIntent().getStringArrayListExtra("artist"); // ArrayAdapter<String> aa=new ArrayAdapter<String>(this,R.layout.row,R.id.text2,al); //lv.setAdapter(aa); try{ lv.setAdapter( new styleadapter(this,R.layout.row, R.id.text2,al)); }catch(Throwable e) { Log.e("openaudio error",""+e.toString()); goBlooey(e); } lv.setOnItemClickListener(new OnItemClickListener(){ @Override public void onItemClick(AdapterView<?> arg0, View arg1, int arg2, long arg3){ j=1; try{ d=arg2; String filep=filepath.get(d); String tit=al.get(d); String image=imgal.get(d); String singer=artist.get(d); String movie=album.get(d); sendpath(filep,tit,image,singer,movie); // getpath(n); }catch(Throwable t) { goBlooey(t); } } }); } @Override protected void onPause() { // TODO Auto-generated method stub super.onPause(); if(j==0) {i=new Intent(this,gorinkadashboard.class); startActivity(i);} } @Override protected void onResume() { // TODO Auto-generated method stub super.onResume(); j=0; } @Override public boolean onKeyDown(int keyCode, KeyEvent event) { if (keyCode==KeyEvent.KEYCODE_SEARCH) { Log.i("go","go"); return true; } return(super.onKeyDown(keyCode, event)); } public void sendpath(String n,String nn,String image,String singer,String movie) { Intent ii=new Intent(this,MusicPlayerActivity.class); ii.putExtra("path",n); ii.putExtra("titletxt",nn); //ii.putStringArrayListExtra("playpath",filepath); ii.putExtra("pos",d); ii.putExtra("image",image); ii.putStringArrayListExtra("imagepath",imgal); ii.putStringArrayListExtra("filepath", filepath); ii.putStringArrayListExtra("imgal", imgal); ii.putExtra("movie" ,movie ); ii.putExtra("singer",singer); ii.putStringArrayListExtra("album", album); ii.putStringArrayListExtra("artist",artist); ii.putStringArrayListExtra("tittlearray",al); startActivity(ii); } class styleadapter extends ArrayAdapter<String> { Context context=null; public styleadapter(Context context, int resource, int textViewResourceId, List<String> objects) { super(context, resource, textViewResourceId, objects); this.context=context; } @Override public View getView(int position, View convertView, ViewGroup parent) { final int i=position; LayoutInflater inflater = ((Activity) context).getLayoutInflater(); View v = inflater.inflate(R.layout.row, null); tv=(TextView)v.findViewById(R.id.text2); albumtext=(TextView)v.findViewById(R.id.text3); artisttext=(TextView)v.findViewById(R.id.text1); tv.setText(al.get(i)); albumtext.setText(album.get(i)); artisttext.setText(artist.get(i)); final ImageView im=(ImageView)v.findViewById(R.id.image); s="http://www.gorinka.com/"+imgal.get(i); // displyimg(s,v); // new imageloader(s,im); String imgPath=s; AsyncImageLoaderv asyncImageLoaderv=new AsyncImageLoaderv(); Bitmap cachedImage = asyncImageLoaderv.loadDrawable(imgPath, new AsyncImageLoaderv.ImageCallback() { public void imageLoaded(Bitmap imageDrawable, String imageUrl) { im.setImageBitmap(imageDrawable); } }); im.setImageBitmap(cachedImage); return v; } } public class imageloader implements Runnable{ private String ss; //private View v; //private View v2; private ImageView im; public imageloader(String s, ImageView im) { this.ss=s; //this.v2=v2; this.im=im; Thread thread = new Thread(this); thread.start(); } public void run(){ try { // URL url = new URL(ss); // URLConnection conn = url.openConnection(); // conn.connect(); HttpGet httpRequest = null; httpRequest = new HttpGet(ss); HttpClient httpclient = new DefaultHttpClient(); HttpResponse response = (HttpResponse) httpclient.execute(httpRequest); HttpEntity entity = response.getEntity(); BufferedHttpEntity bufHttpEntity = new BufferedHttpEntity(entity); InputStream is = bufHttpEntity.getContent(); // BufferedInputStream bis = new BufferedInputStream(is); Bitmap bm = BitmapFactory.decodeStream(is); Log.d("img","img"); // bis.close(); is.close(); im.setImageBitmap(bm); // im.forceLayout(); // v2.postInvalidate(); // v2.requestLayout(); } catch (Exception t) { Log.e("bitmap url", "Exception in updateStatus()", t); //goBlooey(t); // throw new RuntimeException(t); } } } private void goBlooey(Throwable t) { AlertDialog.Builder builder=new AlertDialog.Builder(this); builder .setTitle("Exception!") .setMessage(t.toString()) .setPositiveButton("OK", null) .show(); } } I have created the SongList.java, SongsAdapter.java and also SongsAdapterView.java. Their code is... public class SongsList { private String titleName; private String movieName; private String singerName; private String imagePath; private String mediaPath; // Constructor for the SongsList class public SongsList(String titleName, String movieName, String singerName,String imagePath,String mediaPath ) { super(); this.titleName = titleName; this.movieName = movieName; this.singerName = singerName; this.imagePath = imagePath; this.mediaPath = mediaPath; } public String gettitleName() { return titleName; } public void settitleName(String titleName) { this.titleName = titleName; } public String getmovieName() { return movieName; } public void setmovieName(String movieName) { this.movieName = movieName; } public String getsingerName() { return singerName; } public void setsingerName(String singerName) { this.singerName = singerName; } public String getimagePath() { return imagePath; } public void setimagePath(String imagePath) { this.imagePath = imagePath; } public String getmediaPath() { return mediaPath; } public void setmediaPath(String mediaPath) { this.mediaPath = mediaPath; } } public class SongsAdapter extends BaseAdapter{ private Context context; private List<SongsList> listSongs; public SongsAdapter(Context context, List<SongsList> listPhonebook){ this.context = context; this.listSongs = listSongs; } public int getCount() { return listSongs.size(); } public Object getItem(int position) { return listSongs.get(position); } public long getItemId(int position) { return position; } public View getView(int position, View view, ViewGroup viewGroup) { SongsList entry = listSongs.get(position); return new SongsAdapterView(context,entry); } } public SongsAdapterView(Context context, SongsList entry) { super(context); this.setOrientation(VERTICAL); this.setTag(entry); // TODO Auto-generated constructor stub View v = inflate(context, R.layout.row, null); TextView tvTitle = (TextView)v.findViewById(R.id.text2); tvTitle.setText(entry.gettitleName()); TextView tvMovie = (TextView)v.findViewById(R.id.text3); tvTitle.setText(entry.getmovieName()); TextView tvSinger = (TextView)v.findViewById(R.id.text1); tvTitle.setText(entry.getsingerName()); addView(v); } } Can anyone please tell me how to display the list using custom lists and custom adapters using the code above???

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  • Actionscript 3 and nested lists

    - by Hanpan
    Hi, I have the following code in my XML (EDIT:) which I am trying to show in a RichText using htmlText. <ul> <li>List Item 1 <ul> <li>List Item 2</li> </ul> </li> </ul> Unfortunately, Flash doesn't seem to support nested lists, and I am getting output which looks like this: List item 1 List item 2 Where I want the second ul to be indented further. Any ideas would be much appreciated! Cheers

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  • Python 3: unpack inner lists in list comprehension

    - by Beau Martínez
    I'm running the following code on a list of strings to return a list of its words: words = [re.split('\\s+', line) for line in lines] However, I end up getting something like: [['import', 're', ''], ['', ''], ['def', 'word_count(filename):', ''], ...] As opposed to the desired: ['import', 're', '', '', '', 'def', 'word_count(filename):', '', ...] How can I unpack the lists re.split('\\s+', line) produces in the above list comprehension? Naïvely, I tried using * but that doesn't work. (I'm looking for a simple and Pythonic way of doing; I was tempted to write a function but I'm sure the language accommodates for this issue.)

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  • python: how to convert list of lists into a single nested list

    - by Bhuski
    I have a python list of lists as shown below: mylist=[ [['orphan1', ['some value1']]], [['parent1', ['child1', ['child', ['some value2']]]]], [['parent1', ['child2', ['child', ['some value3']]]]] ] I need to convert the above list to some thing like this: result=[ ['orphan1', ['some value1']], ['parent1', ['child1', ['child', ['some value2']]], ['child2', ['child', ['some value3']]]] ] Kindly help me approach this problem. I have given only simple list. In actual scenario here, in my list, even grand parents/grand childs are there. How much ever deep the input nested list is, I need to convert it to a single nested list, with common list elements (parents and grand parents) appearing only once. (but the next to innermost list element('child' in above example) should appear as many times it occurs in the input list. I have been trying to do this last two days, but did not end up with working solution :(. I need to use the output in django template filter: unordered_list so that the resultant nested list appears as a nested unordered list in my html page ..

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